Let S T be sets. Prove that S CT, if and only if, 25 C 2T. 9.10. Let S, T be sets. Prove that 23 n 21 = 2SNT.

There are 10,000,000,000 unique phone numbers that can be made with 10 digits using any single digit number (0-9) for each digit using combinations.

To determine how many phone numbers can be made with 10 digits, where any single digit number (0-9) can be used for any digit, follow these steps:

1. Understand that there are 10 possible digits (0-9) for each digit in the phone number.
2. Since there are 10 digits in the phone number, you need to calculate the total number of combinations by multiplying the number of possibilities for each digit.

To calculate this, simply raise the number of possible digits (10) to the power of the number of digits in the phone number (10):

10^10 = 10,000,000,000

So, there are 10,000,000,000 unique phone numbers that can be made with 10 digits using any single digit number (0-9) for each digit.

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Answer:

12 dogs

Step-by-step explanation:

Ratios are scaleable, so let's look at all of the equivalent ratios of 3:2. However it needs to add up to 20 (the sum will be in parenthesis)

3:2 (Sum of 5)

6:4 (Sum of 10)

9:6 (Sum of 15)

12:8 (Sum of 20) ----> Correct Answer

The permutations of four objects m, I, n, and k taken two at a time without repetition are: mn, mk, mi, nm, nk, ni, km, kn, ki, in, im, ik.

P is the total number of permutations, which is equal to 12.

The correct answer is OB, which lists all 12 permutations.

P2 is the number of permutations taken two at a time with repetition allowed. This means that we can repeat the same object in a permutation.

There are 16 possible permutations with repetition allowed: mm, ml, mn, mk, ll, ln, lk, nn, nk, kk, ii, ik, nn, ni, nk.

Therefore, P2 is equal to 16.

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The different simplified two-level gate circuits are as follows:
F(a, b, c, d) = (a'c)(b'd) + (ac)(bd') + (ab'c') + (ab'd') + (a'b'c') + (a'b'd) + (a'bc') + (a'b'd')

(a) F(w, x, y, z) = (x + y′ + z)(x′ + y + z)w
From the expression F(w, x, y, z) = (x + y′ + z)(x′ + y + z)w, the truth table can be derived.

Then Karnaugh Maps (K-map) can be applied to make the equations smaller.

In order to make the equations smaller, there are eight different simplified two-level gate circuits that can be used.

K-Map for (a):

The K-Map above is created for the given function F(w, x, y, z). This K-Map is used to create Boolean equations using the following steps:
1. Combine 1’s wherever possible to get two terms of two variables.
2. There are eight possible combinations of two variable equations.
3. Put these two-variable equations with a common variable together to get four-variable equations.
4. Finally, use the K-Map again to create two-variable equations to use in two-level gate circuits.

The different simplified two-level gate circuits are as follows:

F(w, x, y, z) = (w'z)(xy') + (wz')(x'y)  + (wz)(x + y')  + (wx)(y + z')  + (wx')(y' + z)  + (wy)(x + z')  + (wy')(x' + z)  + (w'x'z)(y + z)

(b) F(a, b, c, d) = Σ m(4, 5, 8, 9, 13)
The given expression F(a, b, c, d) = Σ m(4, 5, 8, 9, 13) can be simplified by using Karnaugh Maps to make the equations smaller. There are eight different simplified two-level gate circuits that can be used for the simplified expressions. K-Map for (b):

The K-Map above is created for the given function F(a, b, c, d). This K-Map is used to create Boolean equations using the following steps:
1. Combine 1’s wherever possible to get two terms of two variables.
2. There are eight possible combinations of two variable equations.
3. Put these two-variable equations with a common variable together to get four-variable equations.
4. Finally, use the K-Map again to create two-variable equations to use in two-level gate circuits.

The different simplified two-level gate circuits are as follows:
F(a, b, c, d) = (a'c)(b'd) + (ac)(bd') + (ab'c') + (ab'd') + (a'b'c') + (a'b'd) + (a'bc') + (a'b'd')

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Answer:

Goku died you I just started watching

If the customer sues for a refund The customer will prevail.

B The customer, because he had a reasonable time after purchase in which to inspect.

The customer prevailing due to a reasonable time for inspection: If the customer inspected the wallet promptly after purchase and discovered the defect, they might argue that they exercised reasonable diligence and promptly returned to the store to demand a refund. This could support their claim for a refund. The customer will prevail in the case. This is because the customer had a reasonable time after purchase in which to inspect the wallet purchased. The Uniform Commercial Code provides that in any sale of goods, a buyer has a reasonable opportunity to inspect the goods to determine their condition before accepting them.

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Question is incomplete the complete question is :

A customer selected a new wallet at a local department store that the salesperson said was made of the finest calfskin and was stitched by hand. The customer bought the wallet and left the store. A few moments later, he took out the wallet to transfer his cash and credit cards into it. On close inspection, he noticed a small nick in the leather. He immediately went back to the department store and demanded a refund. The salesperson refused.

If the customer sues for a refund, who will prevail?

A The customer, because there was a breach of contract.

B The customer, because he had a reasonable time after purchase in which to inspect.

C The department store, because the customer accepted the goods.

D The department store, because the customer did not give written notice of the breach.

Answer:

All values of x are solutions.

Step-by-step explanation:

By using the concept of parallel lines, it is obtained

x = 7, y = 22

What is corrosponding angle?

At first we need to understood what is angle, parallel lines and transversal

Angle

When two straight lines intersect, an angle is formed. The point of intersection is called the vertex of the angle and the lines are called the arms of the angle.

Parallel lines

Two lines are said to be parallel if on extending them indefinitely, they will never intersect

Transversal

Transversal is a line that intersects two or more parallel lines

Alternate exterior angle

The angle formed on the same side of transversal when the transversal intersects two parallel lines.

Here,

\(9x + 42 = 105\\\) [Vertically opposite angle]

\(9x = 105 - 42\\9x = 63\\x = \frac{63}{9}\\x = 7\)

Angle next to \(4y - 13\) is \(15x\) [Corrosponding angle]

\(4y - 13 +15x = 180\) [ Angle on a straight line]

\(4y - 13 +15\times 7 = 180\\4y -13 + 105 = 180\\4y + 92 = 180\\4y = 180=92\\4y = 88\\y = \frac{88}{4}\\y = 22\)

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Answer:

x = 2/3

Step-by-step explanation:

5x + 3 - 2x = 5

3x = 5-3

3x = 2

x = 2/3

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CD with the points at the end (like a number line) with the numbers C, D go in the last box.

The ones in forms of angles with the letters C, T, M in the first one

The correct figure matched to each label is given below.

When two lines or rays intersect at a single point, an angle is created. The vertex is the term for the shared point. An angle measure in geometry is the length of the angle created by two rays or arms meeting at a common vertex.

Given:

We have 5 diagrams.

The first diagram represents the segment CD.

The second diagram represents a ray CD.

The angle measure of CTM is represented by the third diagram.

The angle measure of TCM is represented by the fifth diagram.

And the free line from the both sides CD is given in the fourth diagram.

The matched images are given in the attached image.

∠CTM = Image 1 (attached)

CD = Image 2 (attached)

Therefore, the matched images are given above.

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The lengths of LV and OE are 15cm, and the lengths of LD and EV are 3√7 cm and 9/√7 cm, respectively.

Since LOVE is a kite, LV and OE are perpendicular bisectors of each other. Let the length of LD be x, and the length of EV be y. Then, we can use the Pythagorean theorem and the fact that the diagonals bisect each other to set up two equations:

x² + (LV/2)² = DV²/4

y² + (OE/2)² = LE²/4

Simplifying each equation and substituting the given values, we get:

x² + (LV/2)² = 81/4

y² + (OE/2)² = 225/4

We also know that the diagonals bisect each other, so we can set up another equation:

LV/2 + OE/2 = LO = VE

Substituting the given value for LE, we get:

LV/2 + OE/2 = 15

Solving this equation for one of the variables, we get:

LV = 30 - OE

Substituting this expression into the first equation above, we get:

x² + ((30 - OE)/2)² = 81/4

Simplifying and rearranging, we get:

OE² - 60OE + 675 = 0

Using the quadratic formula, we get:

OE = (60 ± √(3600 - 2700)) / 2

OE = 15 or 45

If OE = 15, then LV = 30 - 15 = 15, and we can solve for x and y:

x² + 7.5² = 81/4

y² + 7.5² = 225/4

Solving these equations, we get:

x = 3√7

y = 9/√7

If OE = 45, then LV = 30 - 45 = -15, which is impossible for a length. Therefore, the solution is:

LV = OE = 15

x = 3√7

y = 9/√7

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Complete question:

LOVE is a kite. LV and OE are diagonals. The segments DV = 9cm and LE = 15cm are given. Find the lengths of the other segments of the diagonals, DV, OE, and LV.

Answer:3000

Step-by-step explanation:

Sanji scored 44 points more in third round as compared to the first round.

An equation is a mathematical statement that is formed when two algebraic expressions are equated using an equal sign.

Sanji score in the first round of video game is 125 points

Sanji score in the second round of video game is 263 points

Let Sanji's score in the third round of video game is x points

Total score is 557 points

The equation is

125+ 263+ x = 557

388 + x = 557

x = 169 points

As compared to the first round Sanji scored = 169 -125 = 44 points more

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Answer:

0

Step-by-step explanation:

absolute value disregards -/+

Therefore, the scalar equation of the plane with the normal vector n = [1, 2, 1] and passing through the point (3, 2, 1) is: b. x + 2y + z - 8 = 0.

To find the scalar equation of the plane with a normal vector n = [1, 2, 1] and passing through the point (3, 2, 1), we can use the general form of the equation for a plane:

Ax + By + Cz + D = 0,

where [A, B, C] is the normal vector of the plane and (x, y, z) represents any point on the plane.

Given n = [1, 2, 1] as the normal vector and (3, 2, 1) as a point on the plane, we can substitute these values into the equation to find the scalar equation.

Plugging in the values, we have:

1(x) + 2(y) + 1(z) + D = 0,

x + 2y + z + D = 0.

Now, to determine the value of D, we substitute the coordinates of the given point (3, 2, 1) into the equation:

3 + 2(2) + 1 + D = 0,

3 + 4 + 1 + D = 0,

8 + D = 0,

D = -8.

Substituting D = -8 back into the equation, we get:

x + 2y + z - 8 = 0.

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Question: "Which of the following assessment types has the greatest effect on your overall grade?"

Answer: "Out of all the assessment types, 'tests' have the greatest effect on your overall grade as a student. Hence, Option D would be the best choice."

The  assessment types has the greatest effect on your overall grade is test.

The following information should be considered;

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The angle with the measure 360° is known as a complete angle. A complete angle is one full rotation measuring 360°.

When the final point coincides with the initial point, after one whole rotation, then the angle so created is known as the complete angle. A complete angle is also known as a full angle or a round angle.

The measure of a complete angle is equal to 2π radians = 360 degrees which is the central angle of a circle. Also, if we combine four right angles or two straight angles it makes a complete angle. A complete angle is identical to a zero angle but the difference is only the amount of rotation.

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Answer:

X³ – 3x² – 9x – 5

= x³ + x² – 4x² – 4x – 5x – 5

= x²( x + 1) – 4x ( x + 1) – 5(x + 1)

= (x + 1)(x² – 4x – 5)

= (x + 1)(x² -5x + x – 5)

= (x + 1)(x – 5) (x + 1)

hence, (x +1), (x -5) and (x +1) are the factors of given polynomial .

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Answer:

21x + 12

Step-by-step explanation:

In math, it is

21x + 2(6).

so we have

21x + 2(6) = 21x + 12.

Answer:

(x,y) --> (x+5, y)

Step-by-step explanation:

You are moving the image 5 units to the right so you would add 5 to each x coordinate.

The method that cannot be used to show congruency of two triangles is the method of "angle-angle-angle" (AAA).

The AAA method states that if the corresponding angles of two triangles are congruent, then the triangles themselves are congruent. However, this method is not valid for proving congruency because it does not take into account the lengths of the sides of the triangles.

To prove congruency, we typically use one of the following valid methods:

Side-Side-Side (SSS): If the three sides of one triangle are congruent to the corresponding three sides of another triangle, then the triangles are congruent.

Side-Angle-Side (SAS): If two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then the triangles are congruent.

Angle-Side-Angle (ASA): If two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the triangles are congruent.

Side-Angle-Angle (SAA): If two angles and a non-included side of one triangle are congruent to two angles and a non-included side of another triangle, then the triangles are not necessarily congruent. This method alone is not sufficient to prove congruency.

Therefore, the method that cannot be used to show congruency of two triangles is the Angle-Angle-Angle (AAA) method.

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Answer:

Step-by-step explanation:

Total of 2 days

Total of 3 days - $1294.77

Sunday

13. k=3/4       14. a=23

15. p= 5 1/2    16. x=13

17. m=56         18. n=1 1/2

Answer:

13)

14)

15)

16)

17)

18)

The 5 transformations of a linear function are translation , reflection , dilation , vertical transformation and horizontal transformation.

In the question ,

we have to write the different types of transformation .

A transformation is defined as an alteration in the parent function’s graph .

there are basically 3 main types of transformations .

(i) the first type is Translations ,

the translation causes the graph to shift left, right, up, or down so many units.

(ii) the second type is Reflection ,

the Reflections cause the graph to rotate/flip over the x-axis or y-axis.

(iii) the third type is Dilation ,

In dilation the shape of a graph is changed by a certain factor. that is the graphs will look narrower or wider .

the other two transformations are

(iv) vertical transformation : it affects the y axis .

(v) horizontal transformation : it affects the x axis .

Therefore , the 5 types of transformation are explained above.

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First determine 15% of 340. Multiple 15 (as decimal) by 340.

0.15 x 340 = 51

Find the total amount she earns by adding these values.

51 + 340 = 391

Therefore, she will make $391.

the awenser is three

hundred and fifty five dolars

The volume of water in the cone-shaped paper cup is 25.12 cubic centimeters.

To calculate the volume of water in the cone-shaped paper cup, we can use the formula for the volume of a cone:

V = (1/3) * π * r^2 * h

Given:

Height of water (h) = 6 cm

Diameter of the top surface of water (2r) = 4 cm

First, we need to find the radius (r) of the top surface of the water. Since the diameter is given as 4 cm, the radius is half of that:

r = 4 cm / 2 = 2 cm

Now we can substitute the values into the volume formula and calculate the volume of water:

V = (1/3) * 3.14 * (2 cm)^2 * 6 cm

V = (1/3) * 3.14 * 4 cm^2 * 6 cm

V = (1/3) * 3.14 * 24 cm^3

V = 25.12 cm^3.

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Answer:

y = sin ( 2 x )

graph{sin(2x) [-10, 10, -5, 5]}

Step-by-step explanation:

y = − sin ( 2 x )

x = 0 , y = 0

x = π 4 , y = − 1

x = π 2 , y = 0

x= ( − π 4 ) , y = 1  

With these values, we can plot the graph.