Justin is making a snack. He toasts a piece of bread and spreads peanut butter and jelly on it. Then he cuts an apple into several slices and adds these to his plate. Next, Justin mixes a scoop of lemonade powder into a glass of water, mixes it, and adds ice.

How many chemical changes occurred in this scenario?

one
two
three
four

Answer:

displacement rxn takes place

Explanation:

Zn +FeCl2 → ZnCl2 +Fe

In a case whereby the fish in the lake at the local park are dying so, a professor from the local college comes to investigate, and first she measures the amount dissolved oxygen because she wants to check the possibility of eutrophication.

Harmful algal blooms, dead zones, and fish kills are the results of a process known as eutrophication. Basically, eutrophication occurs when the environment becomes enriched with nutrients, increasing the amount of plant and algae growth to estuaries and coastal waters.

Eutrophication is a process of pollution that occurs when a lake or stream becomes over-rich in plant nutrient, as a consequence of it becomes overgrown in algae and other aquatic plants. Due to this plants die and decompose. In decomposing of the plants, it robs the water of oxygen and the lake, river or stream becomes lifeless.

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Answer:

A

Explanation:

Cuz that's the answer for your question

Precipitate refers to a solid that develops from solution during a chemical process.

A solid that is distinct from any of the reactants is referred to as a precipitate. An insoluble product may arise when solutions containing ionic chemicals are combined.

Combination, disintegration, solitary, dual, and combustion are the five fundamental kinds of chemical processes. You may classify a reaction into one of these groups by looking at the reactants and products. Several categories will apply to some reactions.

When pieces of two ionic compounds are swapped, creating two new compounds, this reaction is known as a double replacement reaction (also known as a double displacement, swap, or metathesis reaction).

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The rate law that is consistent with the proposed mechanism is [-d[H₂]/dt = k[H₂][ICl].

The sum of the two processes produces the overall reaction, which is:

H₂(g) + 2ICl(g) → 2HCl(g) + I₂(g)

We must take into account the rate-determining step, which is the step with the slowest rate, in order to derive the rate law for the total reaction. It is step 1 in this instance.

H₂(g) + ICl(g) → HI(g) + HCl(g) is the rate-determining step (g)

This step's rate rule is-d[H₂]/dt = k[H₂][ICl]

[ICl]

We can assume that the concentration of HI is always in equilibrium with the concentrations of H₂ and ICl because step 2 is quick.

Therefore, -d[H₂]/dt = k[H₂][ICl] is the rate law for the entire reaction.

Therefore,  [-d[H₂]/dt = k[H₂][ICl] is the rate law that is consistent with the hypothesized mechanism.

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Answer:

780 watts

Explanation:

formula to find power when given amps and voltage

P = A x V

=6.50a x 120V

= 780 W (watts)

The amount of heat needed to increase the temperature of a metal's unit mass by one degree is known as its specific heat.

Thus, It is a measurement of the thermal energy storage capacity of the metal molecules at the molecular level and specific heat.

The atomic structure of the metal, its atomic weight, temperature, phase, and impurities are only a few of the variables that have an impact on this number and Specific heat.

Every metal has a different specific heat. It is possible for metals with the same elemental structure to have varying values. The atomic structure, mass, temperature, and presence of impurities in the metal, among other things, all have an impact on the specific heat value in specific heat.

Thus, The amount of heat needed to increase the temperature of a metal's unit mass by one degree is known as its specific heat.

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Electrical energy is changed into mechanical energy which takes place when the cook uses the blender. So, the correct option is B.

Electrical energy is defined as the energy related to the forces on electrically-charged particles and the motion of those particles whose energy is supplied by a combination of current and electric potential that is delivered by a circuit.

Electrical energy is present all around us in many different forms, where some of the best examples of electrical energy are using car battery electrical energy in electrical systems, wall outlet to transfer electrical energy to charge our phones, and our muscles that uses electrical energy to contract and relax. Electrical energy is changed into mechanical energy which takes place when the cook uses the blender.

Therefore, the correct option is B.

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The moles of water produced from 3.07 mol of H2O2 are 64.47 moles. Answer: 64.47

Part A Given the following decomposition reaction, calculate the moles of water produced from 3.07 mol of

H2O2.2 H2O2(1) → 42 H2O(l) + O2(g)

Molar ratio between H2O2 and

H2O is 2:42 or 1:21.

Therefore, moles of water produced from 3.07 mol of H2O2 is:

Moles of water produced = Moles of H2O2 × 21/1 = 3.07 × 21 = 64.47 (approx)

Therefore, the moles of water produced from 3.07 mol of H2O2 are 64.47 moles.

Answer: 64.47

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Expressing the answer with the appropriate units, we have:

3.07 moles of water.

Moles of water: Moles of a substance are a measure of the amount of that substance present. It is a unit used in chemistry to quantify the number of particles (atoms, molecules, or ions) in a sample.

The balanced equation for the decomposition reaction of hydrogen peroxide \(\rm(H_2O_2)\) is: \(\rm\[2H_2O_2(\ell) \rightarrow 2H_2O(\ell) + O_2(g)\]\)

According to the stoichiometry of the reaction, for every 2 moles of \(H_2O_2}\) consumed, 2 moles of \(H_2O\) are produced.

To calculate the moles of water \((H_2O)\) produced from 3.07 moles of \(H_2O_2\), we can set up a ratio: (3.07 moles \(\rm H_2O_2\)) x (2 moles \(\rm H_2O_\) / 2 moles \(\rm H_2O_2\)) = 3.07 moles \(\rm H_2O\)

Therefore, from 3.07 moles of \(\rm H_2O_2\), 3.07 moles of \(\rm H_2O\) are produced.

Thus, Expressing the answer with the appropriate units, we have:

3.07 moles of water.

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Sucrose and other simple sugars may dissolve in water because they are polar molecules with an unequal charge distribution. Water is also quite polar, capable of forming weak, temporary connections with other polar compounds.

Salt dissolves into ions, with Na being positively charged and CL being negatively charged. Because water is highly polar (parts of the molecule are negatively charged while others are positively charged), the sodium ions are surrounded by water molecules, with the negatively charged component of the water molecules surrounding the NA ion. The Cl ion experiences the inverse effect.

A solution's solute and solvent are two different types of substances that can dissolve one another. Different solvents have different levels of solubility for different solutes. For instance, sugar is far more soluble in water than salt. Even sugar, though, has a limit on how much may dissolve.

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Answer:  Salt's ions and sugar's polar bonds are both attracted to the polar water molecules.

Explanation:

this statement is true

Answer:

Hope it helps u

Answer:

thermal shock

Explanation:

the temperatures inside the glass jar should have continued to increase over time. Internal stresses due to uneven heating. This is also known as “thermal shock”.

In general, the thicker the glass, the more prone it will be to breaking due to the immediate differences in temperature across the thickness of glass.

Borosilicate glass is more tolerant of this, as it has a higher elasticity than standard silicon glass.

You may also note that laboratory test tubes and flasks are made with thinner walls, and of borosilicate glass, when designated for heating.

Answer:

answer is 18g

Explanation:

acording to mass formula

mass=concentration x volume

Answer:

They typically use solar powered batteries

Explanation:

When 5.0 mL of 4.00×10⁻³ M AgNO₃ is added to 5.0 mL of 2.80×10⁻³ M K₂CrO₄, there is a stoichiometric excess of Ag⁺ ions.

The reaction between AgNO₃ and K₂CrO₄ produces Ag₂CrO₄, and the balanced equation is:

2 AgNO₃ + K₂CrO₄ → Ag₂CrO₄ + 2 KNO₃

From the balanced equation, we can see that the mole ratio of AgNO₃ to K₂CrO₄ is 2:1. Now let's calculate the moles of each reactant:

Moles of AgNO₃ = (5.0 mL) × (4.00×10⁻³ mol/L) = 2.00×10⁻² mol
Moles of K₂CrO₄ = (5.0 mL) × (2.80×10⁻³ mol/L) = 1.40×10⁻² mol

Now, divide the moles of each reactant by their stoichiometric coefficients:

AgNO₃: (2.00×10⁻² mol) / 2 = 1.00×10⁻² mol
K₂CrO₄: (1.40×10⁻² mol) / 1 = 1.40×10⁻² mol

Since the value for AgNO₃ (1.00×10⁻² mol) is less than the value for K₂CrO₄ (1.40×10⁻² mol), AgNO₃ is the limiting reactant and K₂CrO₄ is in stoichiometric excess. Therefore, Ag⁺ ions are in stoichiometric excess.

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The correct formula of the molecule is C4H9O2.

The model of a compound is a representation of the molecule. It gives us an idea of what the molecule looks like as well as its molecular formula.

Looking at the structure of the compound as shown in the model in the question, the correct formula of the molecule is C4H9O2.

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Answer:C4H9O2.

Explanation:

An indicator is added during an acid-base titration to visually indicate the endpoint of the titration. The endpoint is the point at which the acid and base have completely reacted with each other in stoichiometric amounts, resulting in a neutral solution.

During the titration, the acid and base are gradually added to each other until the endpoint is reached. At this point, the indicator changes color, indicating that the neutralization reaction is complete and the titration can be stopped.

The purpose of adding an indicator is to make it easier to determine the endpoint of the titration. Without an indicator, it can be difficult to determine when the neutralization reaction is complete. The indicator changes color at or very near the endpoint, providing a clear visual signal that the reaction is complete.

Different indicators are used depending on the type of acid-base titration being performed. For example, phenolphthalein is commonly used as an indicator in acid-base titrations because it changes color in the pH range of 8.2 to 10, which is near the endpoint of many acid-base titrations.

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At a neutral pH, aluminum hydroxide, Al(OH)₃, will precipitate out of solution.

Neutral pH is a measure of acidity or alkalinity in a solution, where the pH value is equal to 7.0. This means that the concentration of hydrogen ions in the solution is equal to the concentration of hydroxide ions. Solutions at neutral pH are neither acidic nor basic. Examples of neutral solutions include pure water, blood, and milk.

This is because the reaction between the hydroxide and aluminum ions produces an insoluble compound which will fall out of solution. Additionally, the aluminum ions, Al³⁺, will also precipitate out of solution. Other aluminum-containing compounds, such as Al(H2O)⁶³⁺ and Al(H₂O)₂(OH)⁴⁻, will remain in solution.

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The boiling point of the sucrose solution would be 3.68 °C compared to the boiling point of pure water.

The boiling point of a solution depends on the concentration of solute particles in the solution, which affects the colligative properties of the solution, such as boiling point elevation.

To calculate the boiling point elevation, we can use the following formula;

ΔTb = Kbm

where ΔTb is the boiling point elevation, Kb is the molal boiling point constant for water (which is a constant value), and bm is the molality of the solution, which is the amount of solute (in moles) per kilogram of solvent.

First, let's calculate the molality of the solution;

moles of sucrose = mass of sucrose / molar mass of sucrose

moles of sucrose = 739 g / 342.3 g/mol (molar mass of sucrose)

Next, let's convert the mass of water to kilograms:

mass of water = 0.300 kg

Now, we can calculate the molality of the solution;

bm = moles of sucrose / mass of water

Plugging in the values;

moles of sucrose = 739 g / 342.3 g/mol ≈ 2.158 mol

mass of water = 0.300 kg

bm = 2.158 mol / 0.300 kg ≈ 7.193 mol/kg

Next, we need to determine the molal boiling point constant (Kb) for water. The molal boiling point constant for water is approximately 0.512 °C kg/mol.

Finally, we can calculate the boiling point elevation;

ΔTb = Kb × bm

ΔTb = 0.512 °C kg/mol × 7.193 mol/kg

≈ 3.68 °C

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In the strong acid–strong base titration, the ph is 7.0.

Titration of a solid acid with a solid base is the best of the four sorts of titrations because it includes a solid acid and solid base that totally separate in water, in this manner coming about in a solid acid-strong base neutralization reaction. This titration requires the utilization of a buret to apportion a solid base into a holder of , or vice-versa strong acid , in arrange to decide the proportionality point. The reason for a strong acid-strong base titration is to decide the concentration of the acidic solution by titrating it with a fundamental solution of known concentration, or vice-versa until neutralization happens. As both the acid and base are solid (tall values of Ka and Kb), they will both completely separate, which suggests all the atoms of acid or base will be totally partitioned into ions. At the proportionality point, rise to sums of H+ and OH- particles will combine to create H2O, coming about in a pH of 7.0 , neutral. The pH at the comparability point for this titration will continuously be 7.0.

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Answer:

HC2H3O2(I) + O2(g) ---> H2O(I) + CO2(g) ΔH= -72.35 kJ

Explanation:

We know that 5.0 g of acetic acid will contain, 5.0g/60 g/mol = 0.083 moles of acetic acid

Now from the reaction equation;

1 mole of acetic acid evolved -871.7 KJ of heat

0.083 moles of acetic acid will evolve 0.083 * -871.7 = -72.35 KJ

For 5.0 g of acetic acid, we can write;

HC2H3O2(I) + O2(g) ---> H2O(I) + CO2(g) ΔH= -72.35 kJ

Answer:

D. Moving north at 40 km/hr

Explanation:

velocity is just speed of something in a given direction

Answer:

B. The rock gained mass because new rock formed around

the edge.

26 °C /

80 °F

Rock sample

Answer:

Explanation:

B. The rock gained mass because new rock formed around the edge

26 °C

80 °F

Answer:

Explanation:

as we know in a face-centered unit each atom give1/2 a portion at the face

and fully atom involvement at center therefore  

1/2( total face of cube )+ 1(centre)

1/2 ×6 + 1

3+ 1

4 atoms per cell

The refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.

To calculate the kilowatt-hours (kWh) of electric energy used by the refrigerator in 30 days, we need to multiply the power rating by the total running time.

Given:

Power rating of the refrigerator = 500 W

Running time per day = 12 hours

Number of days = 30

First, we need to convert the power rating from watts to kilowatts:

Power rating = 500 W / 1000 = 0.5 kW

Next, we calculate the total energy used in kilowatt-hours (kWh) over the 30-day period:

Energy used = Power rating × Running time × Number of days

Energy used = 0.5 kW × 12 hours/day × 30 days

Energy used = 180 kWh

Therefore, the refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.

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Answer: type the compound into your search bar then it should tell you what it is for 3. you should look up "what is the formula for -----" same thing for #4

Explanation:

Answer:

2.a.  germanium tetrahydride

2.b. dinitrogen tetrabromide

2.c. diphosphorus pentasulfide

2.d. selenium dioxide

2.e. nitrogen trihydride

2.f. silicon dioxide

3.a. PO3

3.b. SiCl4

3.c. N2O5

3.e. N2O4

3.f. CO

4.a CO2

4.b. SF6

4.c. N2Cl4

4.d. CI4

4.e. PF5

4.f. P2O5

****All numbers are subscripts, please do not write them as is, but to the bottom right of them like shown in the options from question 2.

Explanation:

To name covalent compounds (NM+NM), we use prefixes.

To name covalent compounds goes as follows:

First, name the first element in the formula the normal name it has (ex. Nitrogen, Oxygen). If the first element is present more than once shown by a subscript, use a prefix that will indicate how many there are present (ex. mono, di, tri).

Next, name the second element in the compound using prefixes aswell if present more than once. These elements though, will end with -ide instead of their original name (ex. monoxide, dibromide, trichloride).