Answer:
No
Step-by-step explanation:
12ab + 18a
_________________________
a(16b + 24)
use the distributive property
16ab + 24a is not equal to 12ab + 18a
Hope this helped! Have a nice day! Plz mark as brainliest!!!
-XxDeathshotxX
the administration team compiled test results for those who had been tested for strep throat in a random sample of 400 sick patients who had been tested. the following relative frequency table shows the data. positive negative total has the flu 54% 6% 60% does not have the flu 8% 32% 40% total 62% 38% 100% based on the data, what is the ratio of false positives to true positives? 6 over 32 8 over 6 8 over 54
The ratio of false positives to true positives is 8 over 54.
According to the Question
Results of a strep throat test performed on a sample of 400 ill people are displayed in the table's data. People who have the flu and those who don't are separated into two categories. The patients are then separated into groups based on whether they tested positive or negative for strep throat within each of these categories.
We must first define what a true positive and a false positive are in order to calculate the ratio of false positives to true positives. A patient who tests positive for strep throat but does not actually have the illness is said to have a false positive. The 8% of patients in this instance who tested positive for strep throat but did not have the flu would fall under that category. A patient who tests positive for strep throat and truly has the illness is said to have a true positive. That would be the 54% of patients who tested positive for both the flu and strep throat in this instance.
We divide the percentage of false positives (8%) by the percentage of true positives (54%), which gives us the ratio of false positives to true positives.
As a result, the ratio becomes 8% / 54%, or 8/54.
It's critical to remember that this ratio is dependent on the sample and test performed and may not be the same for different populations or testing methodologies.
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Volume of a cube (cm') = width (cm) x height (cm) x length (cm). 1.1) Using the equation above, determine the volume of a cube that measures 3 cm wide, 3 cm tall, and 3 cm long. 1.2) Let's say this cube is made out of ice and has a mass of 24.76 grams (g). What is this ice cube's density? 1.3) The density of liquid water is slightly higher than that of frozen water ice. Liquid water's density at standard pressures and temperatures is 1.00 grams per cubic centimeter (g/cm'). Given that density, what is the mass of a cube of water measuring 3 cm wide, 3 cm tall, and 3 cm long? 1.4) Compare the weight of the water you calculated in question 1.3 with the weight of the ice of the same volume given in question 1.2. Which is heavier, the liquid water or the ice? Notice that the cube of water is the same size (or volume) as the cube of ice. 1.5) You know that ice floats on water. Explain why.
1.1) The volume of the cube is 27 cubic centimeters. 1.2)the density of the ice cube is approximately 0.917 grams per cubic centimeter (g/cm³).
1.3) the mass of the water cube is 27 grams. 1.4) the weight of the water and the ice would be the same under the same conditions. 1.5)In simpler terms, ice floats on water because it is lighter (less dense) than the water, allowing it to displace an amount of water equal to its weight and float on the surface.
1.1) The volume of the cube can be calculated using the equation: Volume = width x height x length. In this case, the cube measures 3 cm wide, 3 cm tall, and 3 cm long, so the volume is:
Volume = 3 cm x 3 cm x 3 cm = 27 cm³.
Therefore, the volume of the cube is 27 cubic centimeters.
1.2) Density is defined as mass divided by volume. The mass of the ice cube is given as 24.76 grams, and we already determined the volume to be 27 cm³. Therefore, the density of the ice cube is:
Density = Mass / Volume = 24.76 g / 27 cm³ ≈ 0.917 g/cm³.
Therefore, the density of the ice cube is approximately 0.917 grams per cubic centimeter (g/cm³).
1.3) The volume of the water cube is the same as the ice cube, which is 27 cm³. Given the density of liquid water as 1.00 g/cm³, we can calculate the mass of the water cube using the equation:
Mass = Density x Volume = 1.00 g/cm³ x 27 cm³ = 27 grams.
Therefore, the mass of the water cube is 27 grams.
1.4) The weight of an object depends on both its mass and the acceleration due to gravity. Since the volume of the water cube and the ice cube is the same (27 cm³), and the mass of the water cube (27 grams) is equal to the mass of the ice cube (24.76 grams), their weights would also be equal when measured in the same gravitational field.
Therefore, the weight of the water and the ice would be the same under the same conditions.
1.5) Ice floats on water because it is less dense than liquid water. The density of ice is lower than the density of water because the water molecules in the solid ice are arranged in a specific lattice structure with open spaces. This arrangement causes ice to have a lower density compared to liquid water, where the molecules are closer together.
When ice is placed in water, the denser water molecules exert an upward buoyant force on the less dense ice, causing it to float. The buoyant force is the result of the pressure difference between the top and bottom surfaces of the submerged object.
In simpler terms, ice floats on water because it is lighter (less dense) than the water, allowing it to displace an amount of water equal to its weight and float on the surface.
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Un frutero ha comprado 165kg de manzanas a 2 € el kilo; se le han estropeado 15 kg y el resto los vende a 4 € el kilo. ¿ Cuánto ha ganado? ( 1,25p)
Answer:
€270
Step-by-step explanation:
If a fruit vendor has bought 165kg of apples at € 2 per kilo, the total amount spent is expressed as;
Cost price = 165 * 2 = €330
If 15kg spoilt, the amount of fruit remaining will be 165 - 15 = 150kg
If he rests he sells for € 4 per kilo, then;
Selling price = 150 * 4 = €600
Amount earned = €600 - €330
Amount earned = €270
Note: Triangle may not be drawn to scale.Suppose a=48 and b=55 and c=73.Find an exact value (report answer as a fraction): sin(B)=cos(B)=tan(B)=sec(B)=csc(B)=cot(B)=
From the drawing above :
• Sin (B) = opp/hyp = (b /c )= 55/73
,• Cos (B) = adj / hyp =(a/c ) = 48 /73
,• Tan(B) = opp/adj = (b/ a) = 55/48
Suppose y, ... Yn ~ N(u,02), with y known. Use the non-informative prior p(02) « 1/02. Obtain the sampling distribution (likelihood) and the posterior distribution.
To obtain the sampling distribution (likelihood) and the posterior distribution for this scenario, we can use Bayesian inference.
The sampling distribution (likelihood) can be represented as:
p(y|u,02) = (1/sqrt(2*pi*02)^n) * exp(-(1/(2*02)) * sum((yi-u)^2))
where y is the observed data, u is the mean of the normal distribution, and 02 is the variance of the normal distribution.
The non-informative prior for 02 can be represented as:
p(02) « 1/02
Using Bayes' theorem, we can obtain the posterior distribution:
p(u,02|y) = p(y|u,02) * p(02) / p(y)
where p(y) is the marginal likelihood. To simplify the calculation, we can integrate out u from the joint distribution:
p(02|y) = (p(y|02) * p(02)) / p(y)
where p(y|02) is the marginal likelihood for 02:
p(y|02) = (1/sqrt(2*pi*02)^n) * exp(-(n-1)/2)
We can then obtain the posterior distribution for 02:
p(02|y) « 1/02 * exp(-(n-1)/2)
This is a gamma distribution with shape parameter (n-1)/2 and scale parameter 1/2. Therefore, the posterior distribution for 02 is:
02|y ~ Gamma((n-1)/2, 1/2)
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a smartphone was purposefully dropped from a height of 10 meters to test its durability from external physical impact. it will be damaged 100% of the time, but the damage can occur in different parts of the phone. it has been shown that 76% of the damages occur in the glass screen, while the other 24% occur in the battery. a number of smartphones were tested and the tests were independent. find the probability that the first time you observe a battery damage is during the third trial or later.
Answer:
what the quistion?
Step-by-step explanation:
sry i cant spell
The probability that the first time a battery damage is observed is during the third trial or later is 42.74%.
To solve this problem, we can use the geometric distribution, which models the number of trials until the first success in a sequence of independent trials. In this case, the probability of success is 0.24 (the probability of a battery damage) and the probability of failure is 0.76 (the probability of a glass screen damage).
The probability of observing a battery damage for the first time on the third trial or later can be calculated as the complement of the probability of observing a battery damage on the first or second trial.
The probability of observing a battery damage on the first trial is 0.24, and the probability of observing a battery damage on the second trial is (0.76)(0.24) = 0.1824 (the probability of no battery damage on the first trial times the probability of battery damage on the second trial). Therefore, the probability of observing a battery damage for the first time on the third trial or later is 1 - 0.24 - 0.1824 = 0.5776.
However, the question asks for the probability of observing a battery damage for the first time on the third trial or later, which means we need to take into account the fact that we may have observed a battery damage before the third trial. Therefore, we need to adjust our calculation by subtracting the probability of observing a battery damage for the first time on the first or second trial from our previous result.
The probability of observing a battery damage for the first time on the first or second trial is 0.24 + 0.1824 = 0.4224. Therefore, the probability of observing a battery damage for the first time on the third trial or later is 0.5776 - 0.4224 = 0.1552 or 15.52%.
Therefore, the probability that the first time a battery damage is observed is during the third trial or later is 42.74%
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Which equation gives the length of an arc, s, intersected by a central angle of 3 radians in a circle with a radius of 4 in.?
s = three-fourths
s = four-thirds
s = 4 + 3
s = 4 times 3
The length of an arc, s, intersected by a central angle of 3 radians in a circle with a radius of 4 in. is s = three-fourths inches.
What is the length of an arc?The length of the arc is the distance between the two points lying on a curve.
We know that the 2 radian is 360°, therefore, it will cover the complete circumference of the circle. Now, calculating the value of 1 radian,
\(2\pi\) \(radian=2\pi r\)
\(1\) \(radian=\frac{2\pi r}{2\pi }\)
\(1\) \(radian=r\)
As we know the value of 1 radian, therefore, to find the value of 3 radians simply multiply it by 3,
\(1\) \(radian=r\)
\(3\) \(radian=3*r\)
\(3\) \(radian=3r\)
We know the value of the radius of the circle, therefore,
\(3\) \(radian=3r\)
\(3\) \(radian=3*4\) \(in.\)
Hence, the length of an arc, s, intersected by a central angle of 3 radians in a circle with a radius of 4 in. is s = three-fourths inches.
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Answer:
ANSWER IS D ON EDGE 23'
Step-by-step explanation:
GUY ABOVE IS WRONG THE ANSWER IS s=4x3
can someone please help with this geometry
Answer:
∠ABD = 19.5°
∠ABE = 160.5°
Step-by-step explanation:
Given angle ABC = 39° and its bisector BD, you want the measures of angle ABD and ABE, its supplement.
Angle bisectorAn angle bisector divides an angle into two equal parts, each with half the measure of the whole.
∠ABD = 1/2∠ABC
∠ABD = 1/2(39°)
∠ABD = 19.5°
Linear pairThe angles of a linear pair are supplementary: they total 180°. Angles ABD and ABE form a linear pair.
∠ABE = 180° -∠ABD
∠ABE = 180° -19.5°
∠ABE = 160.5°
Derive the general solution form for the recurrence tn = 120,-2 - 166n-3 + 2" Show your work (all steps: the associated homogeneous equation, the characteristic polynomial and its roots, the general solution of the homogeneous equation, computing a particular solution, the general solution of the non-homogeneous equation.) a
The general solution form for the recurrence tn = 120,-2 - 166n-3 + 2.
Given a recurrence relation tn = 120,-2 - 166n-3 + 2 we have to derive the general solution form for the recurrence sequence.
We have the recurrence relation tn = 120,-2 - 166n-3 + 2
We need to find the solution for the recurrence relation.
Associated Homogeneous Equation: First, we need to find the associated homogeneous equation.
tn = -166n-3 …..(i)
The characteristic equation is given by the following:tn = arn. Where ‘a’ is a constant.
We have tn = -166n-3..... (from equation i)ar^n = -166n-3
Let's assume r³ = t.
Then equation i becomes ar^3 = -166(r³) - 3ar^3 + 166 = 0ar³ = 166
Hence r = ±31.10.3587Complex roots: α + iβ, α - iβ
Characteristics Polynomial:
So, the characteristic polynomial becomes(r - 31)(r + 31)(r - 10.3587 - 1.7503i)(r - 10.3587 + 1.7503i) = 0
The general solution of the Homogeneous equation:
Now we have to find the general solution of the homogeneous equation.
tn = C1(-31)n + C2(31)n + C3 (10.3587 + 1.7503i)n + C4(10.3587 - 1.7503i)
nWhere C1, C2, C3, C4 are constants.
Computing a Particular Solution:
Now we have to compute the particular solution.
tn = 120-2 - 166n-3 + 2
Here the constant term is (120-2) + 2 = 122.
The solution of the recurrence relation is:tn = A122Where A is the constant.
The General Solution of Non-Homogeneous Equation:
The general solution of the non-homogeneous equation is given bytn = C1(-31)n + C2(31)n + C3 (10.3587 + 1.7503i)n + C4(10.3587 - 1.7503i)n + A122
Hence, we have derived the general solution form for the recurrence tn = 120,-2 - 166n-3 + 2.
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Can someone help me with this please
Answer: get smart bro
you would know it if you was smart
Step-by-step explanation:
you wont do your work, you always cheat, and you don't listen to the teacher
you need to find the answer out on your own.
P.S. i hope you have a good day :)
prove the property of indicator function:
In 14k = I=11Ak = min{IA₁, A₂,..., I An} Ak
(introduction to probability theory)
reference theory:
Given the universal set Q and A CO. Define the point function IA : Q → R with IA(W) = 1, if w EA = 0, if w E A complement The function IA is called the indicator function or characteristic function of the set A. Sometimes the indicator function IA is written as I(A)
Let Q be the universal set and A₁, A₂, ..., Aₙ be subsets of Q. The indicator function IA(W) is defined as 1 if w ∈ A and 0 if w ∉ A. We want to prove the property: I(A₁ ∩ A₂ ∩ ... ∩ Aₙ) = min{IA₁, IA₂, ..., IAₙ}.
To prove the property of the indicator function, we need to show that I(A₁ ∩ A₂ ∩ ... ∩ Aₙ) = min{IA₁, IA₂, ..., IAₙ}.
Let's consider an arbitrary point w in the universal set Q. We can break down the proof into two cases:
1. If w ∈ A₁ ∩ A₂ ∩ ... ∩ Aₙ:
In this case, w belongs to the intersection of all the sets A₁, A₂, ..., Aₙ. Therefore, IA₁(w) = IA₂(w) = ... = IAₙ(w) = 1. Hence, the minimum value among IA₁, IA₂, ..., IAₙ is 1. Therefore, min{IA₁, IA₂, ..., IAₙ}(w) = 1. On the other hand, I(A₁ ∩ A₂ ∩ ... ∩ Aₙ)(w) is also equal to 1 since w belongs to the intersection. Thus, min{IA₁, IA₂, ..., IAₙ}(w) = I(A₁ ∩ A₂ ∩ ... ∩ Aₙ)(w).
2. If w ∉ A₁ ∩ A₂ ∩ ... ∩ Aₙ:
In this case, w does not belong to the intersection of the sets A₁, A₂, ..., Aₙ. Therefore, at least one of the indicator functions, say IAₖ(w), is 0. Thus, min{IA₁, IA₂, ..., IAₙ}(w) = 0. On the other hand, I(A₁ ∩ A₂ ∩ ... ∩ Aₙ)(w) is also equal to 0 since w does not belong to the intersection. Hence, min{IA₁, IA₂, ..., IAₙ}(w) = I(A₁ ∩ A₂ ∩ ... ∩ Aₙ)(w).
Since the property holds for all points w in the universal set Q, we can conclude that I(A₁ ∩ A₂ ∩ ... ∩ Aₙ) = min{IA₁, IA₂, ..., IAₙ}.
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1 Fifty-five students, 4 teachers, and 3
parent helpers will go on a trip to a
planetarium this Friday. If each student
brings $12 and each adult brings $22, how
much money will they bring all together?
For my little cousin
Teresa is maintaining a camp fire. She can keep the fire burning for 4 hours with 6 logs. She wants to know how
many logs (g) she needs to keep the fire burning for 18 hours. She assumes all logs are the same.
How many logs does Teresa need to maintain the fire for 18 hours?
Answer:
27
Step-by-step explanation:
6/4 = 1.5
1.5 * 18 = 27
What is 845 divided by 21
Answer: 40.2
Step-by-step explanation:
Answer:
40 remainder 5
Step-by-step explanation:
"Solving an integer programming problem by rounding off answers obtained by solving it as a linear programming problem, we find that The values of decision variables obtained by rounding off is always sub-optimal The values of decision variables obtained by rounding off might violate some constraints. The values of decision variables obtained by rounding off are always very close to the optimal valuesNone of the above.
I understand that you want to know the consequences of rounding off answers when solving an integer programming problem by treating it as a linear programming problem. Here's my explanation:
When you solve an integer programming problem as a linear programming problem and then round off the answers, you may encounter the following issues:
1. The values of decision variables obtained by rounding off might be sub-optimal: Rounding off can lead to a solution that is not the true optimal integer solution, as linear programming allows fractional values that might not be feasible in the integer problem.
2. The values of decision variables obtained by rounding off might violate some constraints: Rounding off can result in values that do not satisfy the integer constraints, which could render the solution infeasible for the original integer problem.
3. The values of decision variables obtained by rounding off are not always very close to the optimal values: Although it is possible for the rounded solution to be close to the optimal integer solution, there is no guarantee that this will be the case, as the linear relaxation might lead to significantly different values.
In summary, when solving an integer programming problem by treating it as a linear programming problem and rounding off the answers, you might encounter sub-optimal solutions, constraint violations, and values that are not very close to the true optimal integer values.
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Hard question: there are many partially mixed strategy Nash equilibria here. Try to think of when players are indifferent between their strategies. In each of the following games, find all the pure and mixed strategy Nash equilibria. Golden Balls Player 2 Split Player 1 Split 50,50 Steal 100,0 Steal 0,100 0,0
in the Golden Balls game, there is only one pure strategy Nash equilibrium, which is (Split, Split).
In the Golden Balls game, there are two players, Player 1 and Player 2. Each player can choose to either "Split" or "Steal." The payoffs for each possible combination of actions are as follows:
If both players choose Split, they both receive a payoff of 50.
If Player 1 chooses Steal and Player 2 chooses Split, Player 1 receives 100, and Player 2 receives 0.
If Player 1 chooses Split and Player 2 chooses Steal, Player 1 receives 0, and Player 2 receives 100.
If both players choose Steal, they both receive a payoff of 0.
To find all the pure strategy Nash equilibria, we need to identify any strategies where neither player has an incentive to deviate unilaterally.
Pure Strategy Nash Equilibria:
(Split, Split): This is a pure strategy Nash equilibrium because if both players choose Split, neither player can improve their payoff by unilaterally changing their strategy to Steal.
Now let's consider mixed strategy Nash equilibria, where players randomize between their available strategies.
Mixed Strategy Nash Equilibrium:
To find the mixed strategy Nash equilibrium, we need to examine whether there exists a probability distribution over strategies that maximizes the expected payoff for each player, given the other player's strategy.
In this case, there is no mixed strategy Nash equilibrium since Player 2's expected payoff from choosing Split is always lower than the expected payoff from choosing Steal, regardless of the probabilities assigned to each strategy by Player 1. Similarly, Player 1's expected payoff from choosing Split is always lower than the expected payoff from choosing Steal, regardless of the probabilities assigned to each strategy by Player 2.
Therefore, in the Golden Balls game, there is only one pure strategy Nash equilibrium, which is (Split, Split).
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express the limit as a definite integral on the given interval. lim n → [infinity] n ∑ i = 1 cos x i x i δ x , [ 3 π , 5 π ]
The given limit can be expressed as the definite integral ∫[3π, 5π] cos(x) dx over the interval [3π, 5π].
To express the limit as a definite integral, we can rewrite the sum as a Riemann sum and take the limit as n approaches infinity.
The given sum can be written as:
lim(n → ∞) [Σ(i = 1 to n) cos(xi) Δxi],
where Δxi = (b - a) / n is the width of each subinterval, xi is a sample point in the i-th subinterval, and [a, b] is the interval [3π, 5π].
To express the limit as a definite integral, we can rewrite the sum using the definite integral notation:
lim(n → ∞) [Σ(i = 1 to n) cos(xi) Δxi] = ∫[3π, 5π] cos(x) dx,
where dx represents an infinitesimally small change in x. By taking the limit as n approaches infinity, the sum converges to the definite integral.
Therefore, the given limit can be expressed as the definite integral ∫[3π, 5π] cos(x) dx over the interval [3π, 5π].
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Solve 3x > 174, and use the interactive number line tool to graph the solution. What is true about the graph? Check all that apply.
There is an open circle at 58.
There is a closed circle at 58.
There is an open circle at 174.
There is a closed circle at 174.
The arrow points right.
The arrow points left.
Answer:
there is an open circle at 58
the arrow points right
Step-by-step explanation:
3x>174/:3
x>58 we have a strict x more than 58 that's why it's an open circle and right because x is more, but not less
Multiplying binomials using area model.
Answer:
4x²+35x+24
Step-by-step explanation:
FOIL the binomials and simplify
4x^2 + 35x + 24
That's all I know.
Please see the image below(math)
Answer:
21
Step-by-step explanation:
If a line parallel to one side of a triangle intersects the other two sides of the triangle, then the line divides these two sides proportionally.
AD AH
----- = ---------
AB AH +y
3 9
---- = ------
10 9+y
Using cross products:
3(9+y) = 9*10
27+3y = 90
3y = 90-27
3y =63
y = 63/3
y = 21
Answer:
y = 21
Step-by-step explanation:
According to the Side Splitter Theorem, if a line parallel to one side of a triangle intersects the other two sides, then this line divides those two sides proportionally.
Therefore, according to the Side Splitter Theorem:
\(\boxed{\sf AD : DB = AH : HC}\)
From inspection of the given triangle, the lengths of the line segments are:
AD = 3DB = 7AH = 9HC = yTo find the value of y, substitute the given line segment lengths into the proportion and solve for y:
\(\begin{aligned}\sf AD : DB &=\sf AH : HC\\\\3:7&=9:y\\\\\dfrac{3}{7}&=\dfrac{9}{y}\\\\3 \cdot y&=9 \cdot 7\\\\3y&=63\\\\\dfrac{3y}{3}&=\dfrac{63}{3}\\\\y&=21\end{aligned}\)
Therefore, the value of y is 21.
7b-3b+4 please help me with this
Answer:
4b+4
Step-by-step explanation:
7b-3b = 4b and then you cant do anything with the four so your answer should be 4b+4!
If the lateral area of a square pyramid is 800 in² and the slant
height is 16 in, what is the length of the base edge?
a 30 in
b 25 in
C 21 in
d 32 in
Answer:
b. 25 in
Step-by-step explanation:
the lateral area is the area of the outside walls (not including the base area).
on a square pyramid there are 4 such outside walls in the form of triangles.
so, each such triangle has an area of 800/4 = 200 in².
the area of a triangle is
baseline × height / 2
the slant height is the height of a wall triangle (not the inner height of the pyramid).
a base edge is nothing else but the baseline of such a wall triangle.
so, we have
200 = baseline × 16 / 2 = baseline × 8
baseline = 200/8 = 25 in
Alex wrote checks on Tuesday for $35 and $40. He also made a deposit in his checking account of $170. Find the overall change in the amount in his checking account.
Answer: He retrieved 75$ from his account then he put back 170$ so +75 and -170 so in total the answer would be 245$
Answer: He would have $100 in his bank account from the information provided .
Using Joe’s triangle what is the slope of the graph
Answer:
The slope is 2.
Step-by-step explanation:
You can take the second plotted point of the graph. (2,4)
Since slope is y/x, the equation is 4/2.
4/2=2
Find the equilibrium price and quantity for each of the following pairs of demand and supply functions. a. Q=10-2P b. Q=1640-30P C. Q = 200 -0.2P Q² =5+3P Q² = 1100+30P Q² = 110+0.3P Q² = 5000+ 0.
The equilibrium price and quantity for each pair of demand and supply functions are as follows:
a. Q = 10 - 2P
To find the equilibrium, we set the quantity demanded equal to the quantity supplied:
10 - 2P = P
By solving this equation, we can determine the equilibrium price and quantity. Simplifying the equation, we get:
10 = 3P
P = 10/3 ≈ 3.33
Substituting the equilibrium price back into the demand or supply function, we can find the equilibrium quantity:
Q = 10 - 2(10/3) = 10/3 ≈ 3.33
Therefore, the equilibrium price is approximately $3.33, and the equilibrium quantity is also approximately 3.33 units.
b. Q = 1640 - 30P
Setting the quantity demanded equal to the quantity supplied:
1640 - 30P = P
Simplifying the equation, we have:
1640 = 31P
P = 1640/31 ≈ 52.90
Substituting the equilibrium price back into the demand or supply function:
Q = 1640 - 30(1640/31) ≈ 51.61
Hence, the equilibrium price is approximately $52.90, and the equilibrium quantity is approximately 51.61 units.
In summary, for the demand and supply functions given:
a. The equilibrium price is approximately $3.33, and the equilibrium quantity is approximately 3.33 units.
b. The equilibrium price is approximately $52.90, and the equilibrium quantity is approximately 51.61 units.
In the first paragraph, we summarize the steps taken to determine the equilibrium price and quantity for each pair of demand and supply functions. We set the quantity demanded equal to the quantity supplied and solve the resulting equations to find the equilibrium price. Substituting the equilibrium price back into either the demand or supply function allows us to calculate the equilibrium quantity.
In the second paragraph, we provide the specific calculations for each pair of functions. For example, in case a, we set Q = 10 - 2P equal to P and solve for P, which gives us P ≈ 3.33. Substituting this value into the demand or supply function, we find the equilibrium quantity to be approximately 3.33 units. We follow a similar process for case b, setting Q = 1640 - 30P equal to P, solving for P to find P ≈ 52.90, and substituting this value back into the function to determine the equilibrium quantity of approximately 51.61 units.
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Once again i need help its worth 90 points so id say its worth it
Answer:
EXPLANATION BELOW
Step-by-step explanation:
7 | 0, 4, 8
8 | 0, 8, 9
9 | 5
10 | 1, 9
11 | 6, 7
hope this helps!! you basically just divide the number into two-
what is x (its a parralleligram)
Check the picture below.
Fâ-statistics computed using maximum likelihoodâ estimators:
A.
can be used to test joint hypotheses.
B.
do not follow the standard F distribution.
C.
are not meaningful since the entire regression R² concept is hard to apply in this situation.
D.
cannot be used to test joint hypotheses.
A. can be used to test joint hypotheses.
In statistical analysis, F-statistics are used to compare the fit of two nested models, typically to test joint hypotheses. Maximum likelihood estimators are a popular method for estimating the parameters of a statistical model by maximizing the likelihood function. They are widely used in various fields due to their desirable properties, such as being consistent and asymptotically efficient.
When F-statistics are computed using maximum likelihood estimators, they can still be employed to test joint hypotheses. This involves comparing the difference in the log-likelihoods between two nested models, one being a restricted model and the other being an unrestricted model. The test statistic, in this case, follows an F distribution under the null hypothesis, which states that the restrictions imposed on the model are valid.
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Last Wednesday, students could choose ham or turkey sandwiches for lunch. The cafeteria made 100 sandwiches in all, 85% of which were turkey. How many turkey sandwiches did the cafeteria make?
Answer:
85 Turkey sandwiches
Step-by-step explanation:
85% of 100 is 85
That means that the remaining 15% or 15 sandwiches that were made were ham.
Caroline leaves her house and walks north 6 blocks. She turns and heads east 8 blocks until she reaches mattie’s house. What is the shortest distance between caroline’s and mattie’s houses?.
The shortest distance between Caroline's and Mattie's houses is 10 blocks .
In the question ,
it is given that,
Caroline leaves her house and walks 6 blocks ,
let the point where she starts be A , and the point where she ends be B .
So the distance AB = 6 blocks .
then she turns east and heads to 8 blocks to reach Mattie's house ,
let the point where she stops be C ,
So, the distance BC = 8 blocks ,
the shortest distance(AC) between Caroline and Mattie house can be calculated using the Pythagoras Theorem
AB + BC = AC
6 + 8 = AC
AC = 64 + 36
AC = 100
AC = 10
Therefore , The shortest distance between Caroline's and Mattie's houses is 10 blocks .
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