inventory items that are purchased by your company. Classify them using ABC Analysis and mention the criteria chosen for the classification. The assignment must include the calculations, charts with proper justifications. (subject - production planning and control) PPC.

Answer:

Step-by-step explanation:

The slopes of both those lines are the same so there is no solution. Use slope triangles to find out the slope. They are both 1/4.

A. No solution

y = 1/4x+5

x - 4y = 4

You can simplify the second equation into y = 1/4x - 1

Since these equations both have the same slope, they are parallel. When two lines are parallel, they have no solutions.

Answer:

Volume of right rectangular prism = 3.75 in³

Step-by-step explanation:

Given:

First side of rectangular prism = 2 inches

Second side of rectangular prism = 1\(\frac{1}{2}\) = 1.5 inches

Third side of rectangular prism = 1\(\frac{1}{4}\) = 1.25 inches

Find:

Volume of right rectangular prism:

Computation:

\(Volume\ of\ right\ rectangular\ prism=lbh\\\\Volume\ of\ right\ rectangular\ prism=(2)(1.5)(1.25)\\\\ Volume\ of\ right\ rectangular\ prism= 3.75 in^3\)

Answer:

(6,2)

Step-by-step explanation:

Answer:

square root 162

Step-by-step explanation:

Answer:

\(9 \sqrt{2 } \)

Probability = required outcome / all possible outcome

Total number of balls = 5+ 3+4 = 12

a) number of red ball = 4

p( red gum ball) = 4/12 = 1/3

b)

number of green ball = 5

p(green ball) = 5/12

p(not green ball) = 1- 5/12

=12-5 /12

=7/12

You are correct, P(red) = P(green) = 0.25.

The intermediate step  in the form ( x + a ) ^2 = b (x+a)  2 =b as a result of completing the square  of x² - 4x = 45 is (x- 2)² = 49

How to determine the intermediate step?

The equation is given as:

x² - 4x = 45

Take the coefficient of x

k = -4

Divide by 2

k/2 = -2

Square both sides

(k/2)^2 = 4

Add 4 to both sides of x² - 4x = 45

x² - 4x + 4= 45 + 4

This gives

x² - 4x + 4= 49

Express as perfect square

(x- 2)² = 49

Hence, the intermediate step of x² - 4x = 45 is (x- 2)² = 49

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Answer: 9:51

Step-by-step explanation:

Answer:

D 3^3 *3^-7

Step-by-step explanation:

1/27 = 1/3^3 = 3^-3

When multiplying with the same base, add the exponents

A 3^1 * 3^-10  = 3^-9

B 3^-1 * 3^10 = 3^9

C 3^-4 * 3^7 = 3^3

D 3^3 *3^-7 = 3^-3

Answer: B'(-4, -4)

Given : A(1, 2), B(-1, -1), C(0, -2)

"Focusing on B coordinates"

If the points are dilated with a scale factor of 4

Then new coordinates : (-1, -1) × 4 = B'(-4, -4)

Answer:

B' = (-4, -4)

Step-by-step explanation:

Dilation:  A type of transformation that makes the pre-image larger or smaller without changing its shape.

Center of a dilation:  a fixed point about which all points are dilated.

Given:

For dilation when the center of dilation is the origin (0, 0), simply multiply the coordinates of the vertices of the pre-image by the given scale factor to find the image under dilation:

Therefore:

A' = (1 x 4, 2 x 4) = (4, 8)

B' = (-1 x 4, -1 x 4) = (-4, -4)

C' = (0 x 4, -2 x 4) = (0, -8)

Given:

A homogeneous system of linear equations Ax= 0 is given.

If the determinant of A is 0 then Ax = 0 has infinitely many solutions.

If the determinant is zero that means the matrix A is not invertible.

That implies there exists a non zero x such that Ax=0 that is,

Then by linearity of A, every scalar multiple of x is mapped to zero by A.

Therefore, the system yields an infinite number of solutions.

Therefore, the statement is a true statement.

Answer:

31.42

Step-by-step explanation:

equation for solving is C= π d

circumference is  π x diameter

so therefore the new equation is π x 10

3.14 (π) x 10 (d) = 31.42

To find the distance traveled by the car in the time interval from t = 0 to t = 9 seconds, we need to integrate the velocity function over that interval.

The velocity function is given by \(\(v(t) = 3t \sqrt{81 - t^2}\).\)

To find the distance traveled, we integrate the absolute value of the velocity function over the interval [0, 9]:

\(\[\text{{Distance}} = \int_{{0}}^{{9}} |v(t)| \, dt\]\)

Since the velocity function \(\(v(t)\)\) is non-negative over the interval [0, 9], we can simply integrate the velocity function from 0 to 9:

\(\[\text{{Distance}} = \int_{{0}}^{{9}} v(t) \, dt\]\)

Let's calculate the distance traveled:

\(\[\text{{Distance}} = \int_{{0}}^{{9}} 3t \sqrt{81 - t^2} \, dt\]\)

We can simplify this integral using a substitution. Let's substitute \(\(u = 81 - t^2\) and \(du = -2t \, dt\). When \(t = 0\), \(u = 81\), and when \(t = 9\), \(u = 0\)\). The integral becomes:

\(\[\text{{Distance}} = \int_{{81}}^{{0}} -\frac{3}{2} \sqrt{u} \, du\]\)

Now we can evaluate the integral:

\(\[\text{{Distance}} = -\frac{3}{2} \int_{{81}}^{{0}} \sqrt{u} \, du\]\)

We can reverse the limits of integration and change the sign:

\(\[\text{{Distance}} = \frac{3}{2} \int_{{0}}^{{81}} \sqrt{u} \, du\]\)

Integrating \(\(\sqrt{u}\) with respect to \(u\)\) gives us:

\(\[\text{{Distance}} = \frac{3}{2} \left[ \frac{2}{3} u^{3/2} \right]_{{0}}^{{81}}\]\)

Evaluating the integral at the limits:

\(\[\text{{Distance}} = \frac{3}{2} \left[ \frac{2}{3} (81)^{3/2} - \frac{2}{3} (0)^{3/2} \right]\]\)

Simplifying:

\(\[\text{{Distance}} = \frac{3}{2} \left( \frac{2}{3} \cdot 81^{3/2} - 0 \right)\]\)

\(\[\text{{Distance}} = 3 \cdot 81^{3/2}\]\)

Evaluating the expression:

\(\[\text{{Distance}} = 3 \cdot 9^3 = 3 \cdot 729 = 2187 \text{{ ft}}\]\)

Therefore, the distance traveled by the car in the 9 seconds from t = 0 to t = 9 is 2187 ft.

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Answer:

2/5

Step-by-step explanation:

This is because the whole wall is 5/5 (5/5 = 1 whole).

5/5 - 3/5 = 2/5

When we add or subtract like fractions, we ignore the same denominator, and just add or subtract the numerator.

Hope this helps.

A differential equation with some initial conditions is used to solve an initial value problem.

The required particular solution is given by the relation:

\($4y^{(3/2)} = 9e^{(-2x/3)} + 23\)

An initial value problem in multivariable calculus is an ordinary differential equation with an initial condition that specifies the value of the unknown function at a given point in the domain. In physics or other sciences, modeling a system frequently entails solving an initial value problem.

Let the given equation be \($y^{1/2} dy\ dx y^{3/2} = 1\), y(0) = 9

\($(\sqrt{y } ) y^{\prime}+\sqrt{(y^3\right\left) }=1\) …..(1)

Divide the given equation (1)  by \($\sqrt{ y} $\)  giving

\($y^{\prime}+y=y^{(-1 / 2)} \ldots(2)$\), which is in Bernoulli's form.

Put \($u=y^{(1+1 / 2)}=y^{(3 / 2)}$\)

Then \($(3 / 2) y^{(1 / 2)} \cdot y^{\prime}=u^{\prime}$\).

Multiply (2) by \($\sqrt{ } y$\) and we get

\(y^{(1 / 2)} y^{\prime}+y^{(3 / 2)}=1\)

(2/3) \(u^{\prime}+u=1$\) or \($u^{\prime}+(3 / 2) y=3 / 2$\),

which is a first order linear equation with an integrating factor

exp[Int{(2/3)dx}] = exp(2x/3) and a general solution is

\(u. $e^{(2 x / 3)}=(3 / 2) \ln \[\left[e^{(2 x / 3)} d x\right]+c\right.$\)  or

\(\mathrm{y}^{(3 / 2)} \cdot \mathrm{e}^{(2x / 3)}=(9 / 4) \mathrm{e}^{(2x / 3)}+{c}\)

To obtain the particular solution satisfying y(0) = 4,

put x = 0, y = 4, then

8 = (9/4) + c

c = (23/4)

Hence, the required particular solution is given by the relation:

\($4y^{(3/2)} = 9e^{(-2x/3)} + 23\)

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Answer:

x=4

Step-by-step explanation:

9=1/4 (6x+12)

Multiply each side by 4

4*9 =4*1/4 (6x+12)

36 =  (6x+12)

Subtract 12 from each side

36-12 = 6x+12-12

24 = 6x

Divide each side by 6

24/6 = 6x/6

4 =x

Answer:

\(26.666666667\)

Step-by-step explanation:

To find the volume of a pyramid, you can use the formula:

Volume = (1/3) * base area * height

If the base is a rectangle, the base area is calculated by multiplying the length by the width.

Let's call the original length "L", the original width "W", and the original height "H".

The volume of the original pyramid is:

(1/3) * L * W * H = 40 cubic inches

If the length of the base is doubled, the new length is 2L.

The width is tripled, so the new width is 3W.

The height is increased by 50%, so the new height is 1.5H.

The volume of the new pyramid is:

(1/3) * (2L) * (3W) * (1.5H) = (2/3) * L * W * H = (2/3) * 40 cubic inches = 26.666666667 cubic inches.

So the volume of the new pyramid is approximately 26.666666667 cubic inches.

Answer:

2/10 of a foot long.

Step-by-step explanation:

Answer:

The first fish was 1/3 of a foot longer.

mark me brainlest

Step-by-step explanation:

1/2=3/6

3/6>1/6

3/6-1/6=2/6

2/6 / 2/2

1/3

Answer:

(gOh)(x) on edg 2020

Step-by-step explanation:

Answer:

x+7=12

Step-by-step explanation:

x+7=12

   -7 -7

it depends what the number is

Answer:

50

Step-by-step explanation:

20 divided by the percent value as a decimal 0.4 is 50

It is critical to open a compass with over half the way in order for the arcs formed to meet for perpendicular bisector.

A perpendicular bisector would be a line that cuts a line segment in half and forms a 90-degree angle at the intersection point. In other words, a perpendicular bisector separates a line segment now at midpoint, forming a 90-degree angle.

Now, consider an example;

When you wish to build a perpendicular line on a line segment, like line AB, you do the following;

A line AB appears to be bisected perpendicularly as a result. The arcs would not have met if the compass is opened less than half way down line AB.

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Answer:

-2x² - 8x + 15 = 0

Step-by-step explanation:

Given the following algebraic expression;

x² – 7x + 5

-3x² - x + 10

To add the equation together;

x² – 7x + 5 + (-3x² - x + 10) = 0

x² – 7x + 5 - 3x² - x + 10 = 0

Collecting like terms, we have;

(x² - 3x²) - (7x + x) + (5 + 10) = 0

-2x² - 8x + 15 = 0

To find the area of the region enclosed by the astroid curve, we can use the Green's Theorem area formula:

Area of R = 1/2 ∫(C) x dy - y dx,

where C is the curve that encloses the region R.

The parametric equation of the astroid curve is given by r(t) = (-3cos^3(t))i + (-3sin^3(t))j, where 0 ≤ t ≤ 2π.

To apply the Green's Theorem, we need to find the derivatives of x and y with respect to t:

dx/dt = d/dt(-3cos^3(t)) = 9cos^2(t)sin(t),

dy/dt = d/dt(-3sin^3(t)) = -9sin^2(t)cos(t).

Now we can calculate the area:

Area of R = 1/2 ∫(C) x dy - y dx

= 1/2 ∫(0 to 2π) [(-3cos^3(t))(dy/dt) - (-3sin^3(t))(dx/dt)] dt.

Substituting the values of dx/dt and dy/dt, we have:

Area of R = 1/2 ∫(0 to 2π) [(-3cos^3(t))(-9sin^2(t)cos(t)) - (-3sin^3(t))(9cos^2(t)sin(t))] dt

= 1/2 ∫(0 to 2π) [27cos^4(t)sin^2(t) + 27cos^2(t)sin^4(t)] dt

= 27/2 ∫(0 to 2π) cos^4(t)sin^2(t) + cos^2(t)sin^4(t) dt.

This integral is a bit involved to evaluate analytically, so numerical methods or software can be used to approximate the value.

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The population of interest is: A. all people in Emerald, Queensland.

The population of interest refers to the group of individuals that the research is trying to draw inferences about. In this case, the international fast food chain is looking to assess the level of interest in opening a franchise in Emerald, Queensland.

Therefore, the population of interest is all people who live in Emerald, Queensland, as they are the group that the research is trying to understand. The sample of 100 addresses that the research firm selected is just a subset of this population and the questionnaires are being sent to them to infer about the entire population.

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Step-by-step explanation:

the correct answer is option a 6a-7

Answer:

There is nothing  to multiply.

Include the problem please

The chance that the hospital will run out of sleeping pills on any given day is 0.5000 (or 0.5000 with four decimal places).

To calculate the chance that the hospital will run out of sleeping pills on any given day, we can use the normal distribution and Z-score.

First, let's calculate the Z-score using the formula:

Z = (X - μ) / σ

Where:

X = consumption rate per day (1,155 pills)

μ = average consumption rate per day (1,155 pills)

σ = standard deviation (81 pills)

Z = (1,155 - 1,155) / 81

Z = 0

Now, we need to find the probability associated with this Z-score. However, since the demand for sleeping pills can be considered continuous and not discrete, we need to calculate the area under the curve from negative infinity up to the Z-score. This represents the probability of not running out of sleeping pills.

We discover that the region to the left of a Z-score of 0 is 0.5000 using a basic normal distribution table or statistical software.

To find the probability of running out of sleeping pills, we subtract this probability from 1:

Probability of running out of sleeping pills = 1 - 0.5000

Probability of running out of sleeping pills = 0.5000

Therefore, on any given day, the hospital has a 0.5000 (or 0.5000 with four decimal places) chance of running out of sleeping tablets.

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Answer:

-6, -2

Step-by-step explanation:

-2 ×3 = -6

-6 ×3 = -18

-18 x3 = -54

-54 x3 = -162