In which of the following tools would a normal or bell-shaped curve be expected if no special conditions are occurring? (x3)
a. flow chart
b. cause and effect diagram
c. check sheet
d. histogram

Possible partitions of the set A = {1, 2, 3, 4, 5, 6, 7, 8} are:

1.{{1, 2, 3}, {4, 5}, {6, 7, 8}}

2.{{1, 2, 3, 4}, {5, 6}, {7, 8}}

3.{{1, 2}, {3, 4, 5}, {6, 7, 8}}

4.{{1, 2, 3}, {4, 5, 6}, {7, 8}}

To form a partition of a set A, we need to create non-empty subsets of A such that each element of A belongs to exactly one subset.

Possible partitions of the set A = {1, 2, 3, 4, 5, 6, 7, 8} are:

1.{{1, 2, 3}, {4, 5}, {6, 7, 8}}

2.{{1, 2, 3, 4}, {5, 6}, {7, 8}}

3.{{1, 2}, {3, 4, 5}, {6, 7, 8}}

4.{{1, 2, 3}, {4, 5, 6}, {7, 8}}

Note that each of these partitions satisfies the conditions of a partition, i.e., they are non-empty, disjoint subsets whose union equals the original set A.

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The probability of all 4 computers being good was 45.62%, the probability of 3 being good and 1 being defective was 4.58%, and the probability of 2 being good and 2 being defective was 2.29%.

1. The probability that all 4 are good is 90/100 x 89/99 x 88/98 x 87/97 = 0.4562, or 45.62%.

2. The probability that 3 are good and 1 is defective is 90/100 x 89/99 x 88/98 x 10/97 = 0.0458, or 4.58%.

3. The probability that 2 are good and 2 are defective is 90/100 x 89/99 x 10/98 x 10/97 = 0.0229, or 2.29%.

For the first problem, we can use the formula P(A) = n(A)/n(T), which is the probability of an event A occurring. In this case, P(A) = n(A)/n(T) = 4/100 = 0.04. This gives us the result of 0.4562, or 45.62%.

For the second problem, we use the same formula P(A) = n(A)/n(T), which is the probability of an event A occurring. In this case, P(A) = n(A)/n(T) = 3/100 = 0.03. This gives us the result of 0.0458, or 4.58%.

For the third problem, we use the same formula P(A) = n(A)/n(T), which is the probability of an event A occurring. In this case, P(A) = n(A)/n(T) = 2/100 = 0.02 ,then the probability of the next event, which is 89/99, then the probability of the next event, which is 10/98, then the probability of the last event, which is 10/97. This gives us the result of 0.0229, or 2.29%.

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Answer:

-8a - 6b

Step-by-step explanation:

6a - 13b - 14a + 7b =

6a-14a = -8a

-13b + 7b = -6b

-8a - 6b

The best response for a person handling biohazards with an open wound on their hands is to not  work with biohazards until the cut is healed or cleared by a healthcare professional to work with the use of waterproof bandages and double gloves.

Biohazards are extremely dangerous because they can get into the human body and cause a lot of damage.

This is why a person with an open would or existing cut should not handle a biohazard until they are cleared to to so by a trained healthcare professional.

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Answer:

A

Step-by-step explanation:

In a box plot, interquartile range (IQR) can be used to describe the spread of any given data.

IQR = Q3 - Q1

✔️IQR for Town A:

Q3 = 40

Q1 = 20

IQR = 40 - 20 = 20°

✔️IQR for Town B:

Q3 = 30

Q1 = 20

IQR = 30 - 20 = 10°

We can conclude that the IQR for town A, 20°, is greater than the IQR for town B, 10°.

The number of visitors to Disneyland who stayed for at least 3 hours, spent at least $20 but did not go on the Matterhorn ride is 40.

Let x be the number of visitors who stayed for at least 3 hours, spent at least $20 but did not go on the Matterhorn ride.

Let y be the number of visitors who stayed for at least 3 hours, spent at least $20 and went on the Matterhorn ride.

Then, we can write two equations:

x + y = 120                                          

(Equation 1)

20x + 25y = Total amount spent                

(Equation 2)

Since we don't know the total amount spent, we can't use Equation 2 to solve for x and y.

However, we can use the information given in the question to write another equation:

x + y = Total number of visitors who stayed for at least 3 hours and spent at least $20, regardless of whether they went on the Matterhorn ride.       (Equation 3)

We know that the total number of visitors who stayed for at least 3 hours and spent at least $20 is 80 (since 2/3 of the visitors met these criteria).

So, we have:

x + y = 80                                                                                                           (Equation 3')

Now, we have three equations with two unknowns.

We can solve for x and y by solving the system of equations.

Equation 1: x + y = 120

Equation 3': x + y = 80

Subtracting Equation 3' from Equation 1,

we get:

y = 40

Substituting y = 40 into Equation 3',

we get:

x + 40 = 80x

          = 40

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Step-by-step explanation:

\( = \lim \limits_{x \to0}x \cot(2x) \)

\( = \lim \limits_{x \to0} \frac{x}{ \tan(2x) } \)

\( = \lim \limits_{x \to0} \frac{x}{ \tan(2x) } \times \frac{2x}{2x} \)

\( = \lim \limits_{x \to0} \frac{2x}{ \tan(2x) } \times \lim \limits_{x \to0} \frac{x}{2x} \)

\( = \lim \limits_{u \to0} \frac{u}{ \tan(u) } \times \frac{1}{2} \)

\( = \frac{1}{2} \)

Answer:

\(E.~11\)

Step-by-step explanation:

\(Given, 2x^2-3x=5\)

\(4x^2-6x+1\)

\(2(2x^2-3x)+1\)

\(2(5)+1\)

\(=10+1\)

\(=11\) ✔︎

᪥༄᪥༄᪥༄᪥༄᪥༄᪥༄

hope it helps...

have a great day!!

Answer:

easy bro go and use m-a-t-h w-a-y

Step-by-step explanation:

it's going to help

The correct statement is: provided that the sample size is reasonably large (for any population).

The Central Limit Theorem states that, under certain conditions, the sampling distribution of the sample mean will be approximately normal, regardless of the shape of the population distribution.

These conditions include a random sample from the population and a sufficiently large sample size (typically, n > 30 is considered large enough).

Therefore, the Central Limit Theorem is important because it allows us to make inferences about the population mean using the normal distribution, even if we do not know the population distribution.

This is useful in many applications of statistics, including hypothesis testing, confidence intervals, and estimating population parameters

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Answer:

771

Step-by-step explanation:

Answer:

771

Step-by-step explanation:

Answer:

thats the equation for slope-intercept form

Step-by-step explanation:

m is the slope and b is where the line intercepts on the y axis

Answer:

linear equation

Step-by-step explanation:

happy to help ya :)

Based on the given data, we can calculate the control limits using 3-sigma for the diameter of the auto pistons.

a) The value of x is 155.56 mm (rounded to two decimal places).

b) The value of R is 4.44 mm (rounded to two decimal places).

c) Using 3-sigma, the Upper Control Limit (UCL) for the diameter is calculated as:

UCL = x + 3R = 155.56 + 34.44 = 156.93 mm (rounded to two decimal places)

The Lower Control Limit (LCL) for the diameter is calculated as:

LCL = x - 3R = 155.56 - 34.44 = 154.19 mm (rounded to two decimal places)

d) Using 3-sigma, the Upper Control Limit for the Range (UCLR) is calculated as:

UCLR = D4 * R = 2.115 * 4.44 = 7.89 mm (rounded to two decimal places)

The Lower Control Limit for the Range (LCLR) is always 0 in this case since negative ranges are not possible.

e) If the true diameter mean should be 155 mm, the new centerline (nominal line) would be 155 mm. In this case, the UCL and LCL would be calculated using 3-sigma as follows:

UCL = Nominal + 3R = 155 + 34.44 = 156.37 mm (rounded to two decimal places)

LCL = Nominal - 3R = 155 - 34.44 = 153.63 mm (rounded to two decimal places)

Please note that the control limits calculated using 3-sigma assume a normal distribution and the data follows the same pattern in the future.

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The complete question is:

What is the value of x? = x= 155.56 mm (round your response to two decimal places). b) What is the value of R? R= 4.44 mm (round your response to two decimal places). c) What are the UCL, and LCL; using 3-sigma? Upper Control Limit (UCL) = 156.93 mm (round your response to two decimal places). Lower Control Limit (LCL) = 154.19 mm (round your response to two decimal places). d) What are the UCLR and LCLR using 3-sigma? Upper Control Limit (UCLR)= 7.89 mm (round your response to two decimal places). Lower Control Limit (LCLR)= 0.99 mm (round your response to two decimal places). e) If the true diameter mean should be 155 mm and you want this as your center (nominal) line, what are the new UCL and LCL? Upper Control Limit (UCL)= 156.37 mm (round your response to two decimal places). Lower Control Limit (LCL;)= 153.63 mm (round your response to two decimal places). Refer to Table 56.1-Factors for Computing Control Chart Limits (3 sigma) for this problem Auto pistons at Wemming Chung's plant in Shanghai are produced in a forging process, and the diameter is a critical factor that must be controlled. From sample sizes of 10 pistons produced each day, the mean and the range of this diameter have been as follows: Day 1 2 3 4 5 Mean x (mm) 150.9 153.2 153.6 153.5 154.6 Range R (mm) 4.0 4.8 4.1 4.8 4.5

Answer:

x=1

Step-by-step explanation:

log2( x^2 -x+2) = 1+2log2(x)

Rewriting 1 as log2(2)

log2( x^2 -x+2) = log2(2)+2log2(x)

We know that a log b = log a^b

log2( x^2 -x+2) = log2(2)+log2(x^2)

we know log a + log b = log (ab)

log2( x^2 -x+2) = log2(2*x^2)

Since the bases are the same the terms inside must be equal

x^2 -x+2 = 2x^2

Subtract 2x^2 from each side

-x^2 -x+2 = 0

Multiply by -1

x^2 +x-2 = 0

Factor

(x+2)(x-1)=0

Using the zero product property

x+2 = 0  x-1=0

x=-2  x=1

Checking the solutions

log2( x^2 -x+2) = 1+2log2(x)

X cannot be negative because 2 log2(x) cannot be negative

log2( 1^2 -1+2) = 1+2log2(1)

x=1

\(\\ \rm\Rrightarrow log_2(x^2-x+2)=1+2log_2x\)

\(\\ \rm\Rrightarrow log_2(x^2-x+2)=log_22+2log_2x\)

\(\\ \rm\Rrightarrow log_2(x^2-x+2)=2log_2(2x)\)

\(\\ \rm\Rrightarrow log_2(x^2-x+2)=log_2(2x^2)\)

\(\\ \rm\Rrightarrow x^2-x+2=2x^2\)

\(\\ \rm\Rrightarrow x^2+x-2=0\)

\(\\ \rm\Rrightarrow (x+2)(x-1)=0\)

log is always positive so x=1

Laws used

To provide a general real-valued solution to a linear system of differential equations, specific equations need to be provided. Without the specific equations, it is not possible to determine the exact solution.

In general, a linear system of differential equations can be written in matrix form as follows:

dY/dt = AY,

where Y is a vector of functions, t is the independent variable, and A is a constant matrix.

To solve this system, one can use methods such as matrix diagonalization, eigenvalues, and eigenvectors, or the method of variation of parameters. These methods allow you to find the general solution of the system, which represents a family of solutions that satisfy the given equations.

It is important to note that the specific form of matrix A and the initial or boundary conditions if provided, will determine the exact solution to the system of differential equations.

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Answer:

By substituting the values of m and n into the expression, 3(4)2 - 4(18) +6= -42

The combination p AND (NOT q) is true when p is true and q is false, and false otherwise.

The statement "p AND (NOT q)" means that both p is true and q is false.

When p is true ("The pond is not frozen over") and q is true ("The fish are not jumping"), then (NOT q) is false, so the combination p AND (NOT q) is false.

When p is true and q is false ("The fish are jumping"), then (NOT q) is true, so the combination p AND (NOT q) is true.

When p is false ("The pond is frozen over"), then the combination p AND (NOT q) is false regardless of the truth value of q.

Therefore, the combination p AND (NOT q) is true when p is true and q is false, and false otherwise.

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A function f maps an element from one domain to a unique range of elements, in this case the only ordered pair which satisfies the previous definition is:

O (2.2) (3,-2) (4,5)

For the two lines to be parallel, the value of n must be 3

When two straight lines are plotted on the coordinate plane, we can tell if they are parallel from the slope, of each line. If the slopes are the same then the lines are parallel.

The slope of each line is calculated as (y2-y1)/x2-x1

for line AB, the slope = (6n-n)/10-4 = 5n/6

for line CD, the slope= 8n-(-6)/9-(-3)=( 8n+6)/12

for AB and CD to be parallel,

5n/6 = (8n+6)/12

multiply both sides by 12

10n= 8n+6

collect like terms

10n-8n= 6

2n= 6

n= 6/2= 3

therefore for the value of n= 3 line CD and AB are parallel.

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Answer: 28x+16

Step-by-step explanation:

Step-by-step explanation:

Decimals can always be put over 1, as they're part of a whole number.

\(\frac{0.75}{1}\)

Multiply both numerator and denominator by 100:

\(\frac{0.75 \times 100}{1\times 100} =\frac{75}{100}\)

\(\frac{0.75}{1} \: and \: \frac{75}{100} \: are \: fractions \: of \: 0.75\)

Answer:

see explanation

Step-by-step explanation:

This polynomial is irreducible, that is cannot be factored.

4x² + 25y² ← is a prime polynomial

Answer:

1, the polynomial itself

Step-by-step explanation:

This is a prime polynomial since the terms have no common factor. The only factors it has are 1 and 4x2+25y2 (the number itself)

Answer: 70 - 79

hope this helps! :)

Answer:

17.5 hours each

Step-by-step explanation:

350/2 = 175

175/10 =17.5

17.5 hours each :)

hope this helps

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The average amount of error in the regression line's predicted rotten tomato ratings is typically represented by the root mean squared error (RMSE).

The average amount of error in the regression line's predicted rotten tomato ratings is typically described by the root mean squared error (RMSE). RMSE is a common metric used to evaluate the accuracy of a regression model's predictions. It represents the square root of the average squared differences between the predicted values and the actual values.

By calculating the RMSE for the regression line's predicted rotten tomato ratings, you can determine the average amount of error in those predictions.

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Answer:

54.54

Step-by-step explanation:

If you take 1200 and divide it by 22, you get this. Hope it helps!