In two to three sentences, explain how to build a simple electromagnet. Remember


to use proper grammar and mechanics when writing your sentences.

Answer:

There is a thick layer of rubber coating on the wires.

Explanation:

This isn't just the case with birds, your headphones, if you notice closely have a layer of rubber coating as well, to protect you from accidentally touching the wires inside and hurting yourself.

Answer:

I think firs one is 30

second one is 4

third one is 12

I am not sure about my answers.

The answer to Part A is that Ricardo has a larger magnitude momentum than Paula after the push-off. According to the law of conservation of momentum, the total momentum of an isolated system remains constant if no external forces are acting on it.

In this case, we can consider Paula and Ricardo as an isolated system since no external forces are acting on them during the push-off. Initially, the total momentum of the skaters is zero since they are at rest. After the push-off, the skaters move in opposite directions, and their momenta have opposite signs. However, the total momentum of the system must still be conserved.

Since Ricardo weighs more than Paula, he has a greater mass. Therefore, if both skaters push off with the same force, Ricardo will have a smaller velocity than Paula after the push-off. However, since momentum is a product of mass and velocity, we need to consider both factors to determine who has the greater momentum.

After the push-off, the total momentum of the system is non-zero and has the same magnitude for both skaters but opposite signs. Therefore, the magnitude of Ricardo's momentum must be greater than Paula's momentum, since he has a greater mass, and their velocities have opposite signs.

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Complete question:

Two ice skaters, Paula and Ricardo, initially at rest, push off from each other. Ricardo weighs more than Paula. Part A Which skater, if either, has the greater momentum after the push-off? Explain. Match the words in the left column to the appropriate blanks in the sentences on the right. Reset Help zero Initially, the total momentum of the skaters is since they are at rest. After the push-off, the total momentum Therefore, Ricardo has after the push-off. non-zero increases decrease remains the same a larger magnitude momentum than Paula a smaller magnitude momentum than Paula the same magnitude momentum as Paula Submit Request Answer

:

Explanation:

this graph show the decrease in velocity  with time

at time t=0 velocity is 40 m/sec

at time t=12sec velocity is decreases from 40 to 10 m/s

so the acceleration of the object at time=12 sec is

a=v/t

a=Δv/t

Δv=v1-v2=40-10=30 m/s

a=30/12=2.5 m/s^2

Answer:

methyl

EXPLANATION

Engineers study momentum because momentum is important. Momentum is the product of the mass and velocity of an object. It is a vector quantity, possessing a magnitude and a direction.

Answer:

Because...

Explanation:

Engineers are a big impact to America as well as the whole earth they need to study momentum because it helps and is main parts of being an engineer without knowing or studying what momentum I you will Have a very hard time

The time taken by the ball to reach the surface of the moon that drops from a height of 1.5 m from the moon is 1.36s.

Given that the acceleration of gravity on the surface of the moon is, \(a=g=1.62 ms^{-2}\). The distance of the ball from the surface is the height of the ball from the surface. So, \(h=d=1.5 m\).

Since the ball is dropped under gravity or free-fall motion from rest, then the initial velocity is zero (i.e.) \(v=0ms^{-1}\). Let t be the time taken by the ball to reach the surface of the moon.

By the equation of motion, the equation is given by \(h=v_{0} t+\frac{1}{2}gt^{2}\), where g is the gravity, t is the time taken by an object, h is the distance of the object, and \(v_{0}\) is the initial velocity of an object from the rest.

Substitute the values of h, g, and \(v_{0}\) in the above equation, and we get

\(1.5=(0)t+\frac{1}{2}(1.62)t^{2}\)

\(1.5=0.81t^{2}\)

\(t^{2} =\frac{1.5}{0.81}\)

\(t^2=1.852\)

\(t=\pm1.36s\)

The time taken cannot be negative.

Therefore, The time taken by the ball to reach the surface of the moon is 1.36s.

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Answer:

Steps include:

Assumption: both planet earth and this hypothetical planet are spheres of uniform density.

Explanation:

Let \(M_0\), \(r_0\), and \(\rho_0\) denote the mass, radius, and density of planet earth.

The radius and density of this hypothetical planet would be \((1/2)\, r_0\) and \(2\, \rho_0\), respectively.

The volume of a sphere is \(\displaystyle V = \frac{4}{3}\, \pi\, r^3\).

Therefore:

The mass of an object is the product of its volume and density. Hence, the mass of the earth could also be represented as:

\(\displaystyle M_0 = \rho_0\, V_0 = \frac{4}{3}\, \pi\, {r_0}^{3}\, \rho_0\).

In comparison, the mass of this hypothetical planet would be:

\(\begin{aligned}M &= \rho\, V\\ &= (2\, \rho_0) \cdot \left(\frac{1}{6}\, \pi\, {r_0}^3\right) \\ &= \frac{1}{3}\, \pi\, {r_0}^{3}\, \rho_0 \end{aligned}\).

Compare these two expressions. Notice that \(\displaystyle M = \frac{1}{4}\, M_0\). In other words, the mass of the hypothetical planet is one-fourth the mass of planet earth.

The acceleration of free fall near the surface of a planet is equal to the gravitational field strength at that very position.

Consider a sphere of uniform density. Let the mass and radius of that sphere be \(M\) and \(r\), respectively. Let \(G\) denote the constant of universal gravitation. Right next to the surface of that sphere, the strength of the gravitational field of that sphere would be:

\(\displaystyle g = \frac{G \cdot M}{r^2}\).

(That's the same as if all the mass of that sphere were concentrated at a point at the center of that sphere.)

Assume that both planet earth and this hypothetical planet are spheres of uniform density.

Using this equation, the gravitational field strength near the surface the earth would be:

\(\displaystyle g_0 &= \frac{G \cdot M_0}{{r_0}^2}\).

.

On the other hand, the gravitational field strength near the surface of that hypothetical planet would be:

\(\begin{aligned}g &= \frac{G \cdot (M_0/4)}{{(r_0/2)}^2} = \frac{G \cdot M_0}{{r_0}^2}\end{aligned}\).

Notice that these two expressions are equal. Therefore, the gravitational field strength (and hence the acceleration of free fall) would be the same near the surface of the earth and near the surface of that hypothetical planet.

As a side note, both \(g\) and \(g_0\) could be expressed in terms of \(\rho_0\) and \(r_0\) alongside the constants \(\pi\) and \(G\):

\(\begin{aligned}g &= \frac{G \cdot M}{r^2}\\ &= \frac{G \cdot (1/3)\, \pi\, {r_0}^3 \, \rho_0}{(r_0/2)^2} = \frac{4}{3}\,\pi\, G\, r_0\, \rho_0\end{aligned}\).

\(\begin{aligned}g_0 &= \frac{G \cdot M_0}{{r_0}^2}\\ &= \frac{G \cdot (4/3)\, \pi\, {r_0}^3 \, \rho_0}{{r_0}^2} = \frac{4}{3}\,\pi\, G\, r_0\, \rho_0\end{aligned}\).

Answer:

C

Explanation:

Use formable metal flashing:

Answer:

stainless steel

Explanation:

Flashing can be made from many different materials, including metal (copper, aluminum, stainless steel, lead, etc.)

David Popenoe's research suggests that the weakest families on earth may be found in Western, industrialized nations.

Industrialized countries such as America, France, the United Kingdom, and other Western nations have weaker family values and structures than developing nations, according to David Popenoe's research. The family's crucial role in society's economic, social, and emotional stability has long been recognized by social scientists.

Popenoe's research supports the notion that Western, industrialized societies may be experiencing a family crisis.Popenoe says that family disintegration and weakening is a serious social problem in the Western world. Popenoe's studies found that Western societies, which place a high value on independence, individualism, and personal satisfaction, are at odds with the family's objectives of commitment, obligation, and selflessness.

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When two forces act in opposite directions, the resultant force can be calculated by subtracting the smaller force from the larger force. The formula for calculating the resultant force is: resultant force = force1 - force2.

When two forces act in opposite directions, the resultant force can be calculated using the following formula:

resultant force = force1 - force2

Where force1 is the larger force and force2 is the smaller force acting in the opposite direction.

For example, suppose there are two forces acting on an object: 10 Newtons to the left and 5 Newtons to the right. To find the resultant force, you would subtract the smaller force from the larger force:

resultant force = 10 N - 5 N

resultant force = 5 N to the left

So in this case, the resultant force is 5 Newtons to the left.

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Answer:

200 N to the right

Explanation:

The horizontal distance at which the parcel should be dropped away from the island in order to be landed there is 697.5 m.

The horizontal distance travelled by the plane is calculated as follows;

X = vt

where;

h = ut + ¹/₂gt²

where;

h = 0 + ¹/₂gt²

h = ¹/₂gt²

2h = gt²

t = √(2h/g)

t = √(2 x 100 / 9.8)

t = 4.5 seconds

Horizontal distance = 155 m/s x 4.5 s

Horizontal distance = 697.5 m

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The first, third, and fourth complexes pump protons into the intermembrane space as a result of the energetically "downhill" motion of electrons down the chain. Finally, oxygen receives the electrons and combines them with protons to create water.

Electrons must be taken from glucose in order for glycolysis to take place, which is the splitting of a molecule of glucose into two molecules of pyruvate. When glucose is stripped of its electrons, it fragments into two molecules of pyruvate.

The electron transport chain, a collection of proteins in the inner membrane of the mitochondrion, is where the electron carriers deliver the electrons. The electron transport chain is where electrons go from a higher to a lower energy level before being transferred to oxygen (forming water).

During cellular respiration, glucose is deemed fully oxidised when the final products of respiration (ATP energy) are produced at the conclusion of the electron transport chain.

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When a wire is pulled through a die and stretched six times its initial length, the cross-sectional area reduces according to the length increase. According to Ohm's law,

this change in cross-sectional area influences the wire's resistance, which is directly proportional to its length and inversely proportional to its cross-sectional area. The wire's resistance grows by a factor of 36, which is equal to the square of the stretching factor (6 x 6 = 36). This is due to the wire's length increasing by a factor of six while its cross-sectional area decreasing by a factor of six times six. As a result, the resistance of the wire after stretching it to six times its original length will be  36 times its original resistance, assuming all other factors (such as the resistivity of the material) remain constant.

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Answer:

In substances such as iron, cobalt, and nickel, most of the electrons spin in the same direction. This makes the atoms in these substances strongly magnetic—but they are not yet magnets. To become magnetized, another strongly magnetic substance must enter the magnetic field of an existing magnet.

The given statement "If you made careful measurements of V vs t for a capacitor C discharging through a resistor R, you should have obtained what is known as an exponential decay curve." is TRUE because when a capacitor discharges through a resistor, the voltage across the capacitor decreases with time.

The relationship between the voltage and time is not linear, but rather follows an exponential decay curve.

This is because the rate of discharge is proportional to the amount of charge remaining on the capacitor, which decreases exponentially with time.

By measuring the voltage at various points in time, we can plot a graph of voltage against time and observe this exponential decay curve.

This curve is a characteristic feature of RC circuits, where R represents the resistance and C represents the capacitance. The time constant of the circuit, which is equal to RC, determines the rate of decay of the voltage.

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Answer:

the  kinetic energy the bat can give to a ball is 2,025 J.

Explanation:

Given;

mass of the bat, m = 2kg

velocity of the bat, v = 45 m/s

The kinetic energy the bat can give to a ball is calculated as;

\(K.E = \frac{1}{2} mv^2\\\\K.E = \frac{1}{2} \times \ 2 \ \times \ 45^2\\\\K.E = 2,025 \ J\)

Therefore, the  kinetic energy the bat can give to a ball is 2,025 J.

Electromagnetic radiation with a wavelength of 589 nm appears as yellow light to the human eye. The energy of one photon of this light is 3.37x10-19J. Thus, a laser that emits 1.3x10-2 of energy in one pulse of light at its wavelength produces (BLANK) photons in each pulse is 3.9 x 10¹⁶

Electromagnetic waves( which include visible light,radio, microwaves etc) carry energy. Each photons( a quantum unit of EM radiation) possess some energy depending on the frequency of the radiation.

The energy of each photon of yellow light is given as-

E=hc/λ

n= energy of laser/energy of one photon

n= E/ El

where E= energy of one photon of the light

El=energy of a laser

λ= wavelength of light

n= no.of photons in each pulse

n=1.3*10-²/3.37*10-¹⁹

n= 3.9*10¹⁶

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The magnitude of the acceleration due to gravity at the surface of a sphere of radius 1.6 m with the given density is approximately 16.1 m/s^2.

The magnitude of the acceleration due to gravity :

g = (4/3) * π * G * ρ * R

Plugging in the values given, we get:

g = (4/3) * π * 6.67 x 10^-11 * 7900 * 1.6

g ≈ 16.1 m/s^2

Therefore, the magnitude of the acceleration due to gravity at the surface of a sphere of radius 1.6 m with the given density is approximately 16.1 m/s^2.

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Answer:

V = 0.896 m/s

Explanation:

This is a typical problem of momentum conservation, whic states the following:

m₁V₁ + m₂V₂ = m₁V₃ + m₂V₄   (1)

In this case V₃ and V₄ would be the final velocity of the trucks after the collision.

With the given data let's see what we have:

m₁ = 5.5x10⁵ kg

m₂ = 2.3x10⁵ kg

V₁ = 5 m/s

V₂ = -5 m/s because it's going to the left (-x axis)

V₄ = 9.1 m/s to the right (Meaning is positive)

V₃ = ??

So to calculate V₃ we just need to replace the data into (1) and solve for V₃:

(5.5x10⁵ * 5) - (2.3x10⁵ * 5) = 5.5x10⁵V₃ + (2.3x10⁵ * 9.1)

2.75x10⁶ + 1.15x10⁶ = 5.5x10⁵V₃ + 2.093x10⁶

V₃ = 2.75x10⁶ - 1.15x10⁶ - 2.093x10⁶ / 5.5x10⁵

V₃ = -0.493x10⁶ / 5.5x10⁵

V₃ = -0.896 m/s

With this sign, it means that is going in the same sense of the other truck, but it's going to the left so this would be positive:

Hope this helps

Deceleration of 1/6 m/s2

Initial Velocity(u) = 25m/s

Final velocity(v) = 0 m/s

Time taken in reaching velocity 0 (t) = 150 s

so as we know from the equation of 2 dimension motions that

So  

As we know that the acceleration is negative so we can conclude that it is a deceleration of 1/6 meter per second square. In the given Question, the information of Fifty - car train has no use in solving acceleration or deceleration.

Acceleration is always Positive as it Increases the speed of the body but Deceleration is negative as it for reducing the speed.

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The impulse applied to an object can be calculated using the equation:

Impulse = Change in momentum

The momentum (p) of an object is defined as the product of its mass (m) and velocity (v):

Momentum = mass × velocity

Given:

Mass of the football (m) = 0.430 kg

The initial velocity of the football = 0 m/s (since it was initially at rest)

The final velocity of the football (v) = 5.00 m/s

The change in momentum (∆p) is equal to the final momentum (p_f) minus the initial momentum (p_i):

∆p = p_f - p_i

Since the initial momentum (p_i) is zero, the change in momentum (∆p) is equal to the final momentum (p_f):

∆p = p_f

Substituting the values into the equation, we have:

∆p = (mass × final velocity) - (mass × initial velocity)

∆p = (0.430 kg × 5.00 m/s) - (0.430 kg × 0 m/s)

∆p = (2.15 kg·m/s) - (0 kg·m/s)

∆p = 2.15 kg·m/s

Therefore, the magnitude of the impulse applied to the football is 2.15 kg·m/s.

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When a light rain falls after oil and gasoline have leaked onto the road surface, it can cause the car to become less responsive and more difficult to control.

This is because the oil and gasoline act as a slippery layer on the road surface, which reduces the friction between the tires and the road. The rainwater can then mix with the oil and gasoline, making the layer even more slippery and reducing the vehicle's grip on the road.

To help mitigate this issue, drivers should be aware of their surroundings and the potential for slippery surfaces, and should adjust their speed and driving accordingly. Additionally, using tires with greater tread, or using more aggressive tires designed for wet and slippery conditions, can also help increase the vehicle's grip on the road.

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Answer:

A. Increasing the voltage of the battery

Explanation:

The relationship between voltage, V, current, I and resistance, R, is given as follows;

V = I × R

∴ I = V/R

From the above relationship, the current flowing in the circuit is directly proportional to the voltage of the battery, and inversely proportional to the resistance, 'R', of the circuit

Therefore, increasing the voltage, 'V', of the battery, increases the total current, 'I', flowing in the circuit.

The original length of the coil spring is zero.

The force exerted by the weight of an object hanging from a spring is given by Hooke's Law as:

F = kx

where F is the force, x is the displacement from the spring's resting position, and k is the spring constant.

In this problem, we can assume that the spring is ideal and obeys Hooke's Law. We are given that the spring length when a 40-gram mass is suspended from it is 24 inches, and when an 80-gram mass is suspended from it, the length is 36 inches. Let's use these values to find the spring constant k:

For the 40-gram mass:

F = kx

mg = kx

k = mg / x

k = (0.04 kg) x (9.81 m/s²) / (0.6096 m)

k = 0.64 N/m

For the 80-gram mass:

F = kx

mg = kx

k = mg / x

k = (0.08 kg) x (9.81 m/s²) / (0.9144 m)

k = 0.86 N/m

Now that we have found the spring constant k for the coil spring, we can use it to find the original length of the spring without any weight applied. When no weight is applied to the spring, the displacement x is zero, so we can solve for the original length L as follows:

F = kx

0 = k(L - 0)

L = 0

Therefore, the original length of the coil spring is zero. This means that the spring was already compressed or stretched to some degree before the 40-gram mass was suspended from it.

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ANSWER

d.

EXPLANATION

Let's draw the circuit first,

So, first, we have to solve the parallel,

The equivalent resistance is,

Hence, the total resistance in the circuit is 4 Ohms.

Answer:

A

sound waves are longitudinal waves with the oscillation parallel to the direction in which energy is transferred

A longitudinal wave with the oscillation parallel to the direction in which energy is transferred is the correct. Therefore option A is correct option.

Electromagnetic wave are the wave that contains both electric wave and magnetic wave. These two waves are perpendicular to each other. There are two kinds of this wave, one is longitudinal wave and transverse wave.

When movement of particles of wave move parallel to the direction of wave propagation. To go in parallel direction, there is two way one is in the direction of propagation or anti to the direction of propagation. Transverse is the wave in which wave particle travel perpendicular to the direction of propagation.

The wave that is present in the sound wave is the longitudinal wave.  A longitudinal wave with the oscillation parallel to the direction in which energy is transferred. Therefore option A is correct option

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