Answer:
The molecular geometry of the molecule changes as atoms are replaced with lone pairs
Explanation:
A molecule having five atoms attached to a central atom possesses five electron domains and is expected to have a trigonal bipyramidal electron and molecular geometry. The axial bonds are expected to be at an angle of 90 degrees while the equatorial bonds are expected to be at an angle of 120 degrees.
However, if one of the atoms is replaced with a lone pair, the electron geometry remains trigonal bipyramidal but the molecular geometry changes to see-saw. both equatorial and axial bonds are now less than 120 degrees and 90 degrees respectively.
If two atoms are replaced by lone pairs, the electron geometry remains trigonal bipyramidal but the molecular geometry changes to T shaped with a bond angle less than 90 degrees.
If three atoms are replaced by lone pairs, the electron geometry remains trigonal bipyramidal while the molecular geometry changes to linear with a bond angle of 180 degrees.
The replacement of atoms with lone pairs will result in the change of the molecular geometry from trigonal bipyramidal to see-saw by 1 atom replacement, T shaped by two atom replacement, and linear by 3 atoms replacement.
The shape of the molecule with 5 atoms attached to the central atom has been trigonal bipyramidal. The molecular geometry of the molecule as atoms are replaced with the lone pairs.
By the replacement of the atoms with lone pairs, the following geometry changes are observed:
The lone pairs replaced by 1 atom do not change the electron geometry. However, the molecular geometry has been changed to see-saw.The replacement of two atoms with loan pairs will change the molecular geometry of the molecule to T shaped.The replacement of 3 atoms with lone pair will result in the change in the molecular geometry to linear.No further change in the molecular geometry has been possible with the linear geometry.
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What is the name of the compound p205
what charge does al typically have in ionic compounds, and why? responses 1 , because in the ground state it has one unpaired electron. 2 , because it has two electrons in the 2s subshell. 3 , because it has three valence electrons
4 , because it is in the fourth row of the periodic table.
The correct option is 3. Aluminum typically has a charge of +3 in ionic compounds, and the reason behind this is the number of valence electrons in the outermost shell of the aluminum atom.
How is the charge of Aluminum determined in ionic compounds?In ionic compounds, the charge of an element is determined by the number of valence electrons present in its outermost shell. The valence electrons are those that are involved in chemical bonding and they determine the reactivity of an atom. This gives aluminum an atomic number of 13 and an electron configuration of 1s²2s²2p⁶3s²3p¹.
In the case of aluminum, it has three valence electrons in its outermost shell, which means it can lose these three electrons to form a positively charged ion with a charge of +3. So, in ionic compounds, aluminum typically has a charge of +3.
Moreover, when aluminum loses these three valence electrons, it attains a noble gas configuration, which is a stable configuration that many elements strive to achieve.
What is aluminum?Aluminum is a chemical element with the symbol Al and atomic number 13. It is a silvery-white, soft, non-magnetic, and ductile metal in the boron group. It is the third most abundant element after oxygen and silicon and the most abundant metal in the Earth's crust. It is commonly used in various applications due to its low density, high strength-to-weight ratio, and good corrosion resistance.
Therefore, option 3 is the correct reason for Al having +3 charge.
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Consider a nonadiabatic well-stirred reactor with simplifi ed chemistry, i.e., fuel, oxidizer, and a single product species. the reactants, consisting of fuel (yf = 0.2) and oxidizer (yox = 0.8) at 298 k, fl ow into the 0.003-m3 reactor at 0.5 kg / s. the reactor operates at 1 atm and has a heat loss of 2000 w. assume the following simplifi ed thermodynamic properties: cp = 1100 j / kg-k (all species), mw = 29 kg / kmol (all species), hf f o , = −2000 kj/ kg, hf ox o , = 0, and hf o , pr = −4000 kj/ kg. the fuel and oxidizer mass fractions in the outlet stream are 0.001 and 0.003, respectively. determine the temperature in the reactor and the residence ti
The first step is to calculate the molar flow rate of fuel, oxidizer, and product. This is done by dividing the mass flow rate (0.5 kg/s) by the molecular weight of each species (29 kg/kmol).
What is molecular?Molecular is a term used to describe the smallest units of matter. Molecules are made up of atoms and are held together by a chemical bond, which involves the sharing of electrons between atoms.
This gives us the following molar flow rates:
Fuel: 0.017 kmol/s
Oxidizer: 0.027 kmol/s
Product: 0.046 kmol/s
Next, we need to calculate the enthalpy change for the reaction. Since we are dealing with a single product species, the enthalpy change can be calculated using the following equation:
ΔH = (hf f o , + hf ox o , - hf o , pr) * n
Where:
hf f o , = Enthalpy of formation of fuel
hf ox o , = Enthalpy of formation of oxidizer
hf o , pr = Enthalpy of formation of product
n = Molar flow rate of product
Substituting the given values, we get the following:
ΔH = (-2000 + 0 - (-4000)) * 0.046 = 920 kJ/s
Now we can calculate the heat of reaction by multiplying the enthalpy change with the molar flow rate of the reactants. This gives us the following result:
Heat of reaction = (0.017 kmol/s * 920 kJ/s) + (0.027 kmol/s * 920 kJ/s) = 24.12 kJ/s
We can then calculate the temperature of the reactor by subtracting the heat loss (2000 W) from the heat of reaction and dividing by the total mass flow rate of the reactants (0.5 kg/s) multiplied by the specific heat capacity (1100 J/kg-K). This gives us the following result:
T = (24.12 kJ/s - 2000 W) / (0.5 kg/s * 1100 J/kg-K) = 436 K
Finally, we can calculate the residence time by dividing the volume of the reactor (0.003 m3) by the total mass flow rate of the reactants (0.5 kg/s). This gives us the following result:
Residence time = 0.003 m3 / 0.5 kg/s = 0.006 s
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The temperature in the reactor is approximately 10.74 K. and 0.006 s.
The temperature in the reactor and the residence time, we need to solve the following set of equations:
dU = w + Q / m
Next, we need to find the rate of change of mass flow rate, which is given by:
dm = Fv - D
here Fv is the volume flow rate of reactants and D is the diffusion rate of the product.
Finally, we can use the above equations to find the temperature in the reactor and the residence time as follows:
Temperature in the reactor:
T = (dU / Q) / (m / cP)
here cP is the specific heat at constant pressure.
Residence time:
t = (m / D)
We can assume that the reactants have a volume flow rate of 0.5 kg/s and the product species has a volume flow rate of 0.001 kg/s. Therefore, the mass flow rate of the reactants is:
m = 0.5 kg/s * 0.002 m3/kg = 0.001 kg/s
The diffusion rate of the product can be calculated as:
D = k * (yox - yf) / (yf + yox)
here k is the reaction rate constant and (yox - yf) / (yf + yox) is the molar fraction of the product species.
Using the values of k, m, and (yox - yf) / (yf + yox) from the problem statement, we can calculate the diffusion rate of the product as:
D = 1 * (0.003 - 0.2) / (0.2 + 0.003)
= 0.00006 / 0.003
= 0.1833
Therefore, the residence time of the reactor is:
t = (0.001 kg/s / 0.1833 kg/mol) = 0.051 s
The temperature in the reactor is given by:
T = (dU / Q) / (m / cP)
here cP is the specific heat at constant pressure of the reactants, which is 1100 J/kg-K.
T = (w + Q / m) / (0.001 kg/s / 1100 J/kg-K) / (0.001 kg/s / 0.003 m3/kg)
= 10.74 K
Residence time = 0.003 m3 / 0.5 kg/s = 0.006 s
Therefore, the temperature in the reactor is approximately 10.74 K and 0.006 s.
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T₁ = 300 K
A. 100 K
C. 325 K
T₁ = 100 K
What is a possible
temperature of the
system after the
divider has been
removed?
B. 75 K
D. 185 K
Answer:
185K
Explanation:
After the molecules mix, they reach a thermal equilibrium.....
Teq =(T1 + T2)/2 =(100+300)/2 =200K
since 185K is closer to 200K than the other options... Therefore the possible equilibrium temperature is 185K
We are given an initial temperature of the system, T1, as:
T1 = 300 K
After the divider is removed, the system will reach thermal equilibrium. According to the second law of thermodynamics, heat will flow from the hotter object to the colder object until the temperatures equalize.
This means the final temperature of the system after the divider is removed will be somewhere in between the initial temperatures of the two parts.
So considering the four answer choices:
A) 100 K - This is too low, the final temperature will be higher than 100K
B) 75 K - Also too low
C) 325 K - This is the initial temperature of one part, so the final temperature cannot be 325K
D) 185 K - This is a plausible final temperature in between 100K and 300K
Therefore, the answer is likely to be D) 185 K
In short, the key points are:
Heat will flow from the hotter to colder object until temperatures equalize
The final temperature will be somewhere in between the initial temperatures of the two parts
Answer choices A,B and C are too low or the same as one of the initial temperatures
Only D) 185K is a plausible intermediate temperature between 100K and 300K
Order the following phases of matter from the phase with the most space between the
atoms to the least space between the atoms.
Answer:
Gas>Liquid>Solid
Explanation:In a gas state, molecules are allowed to move freelyand rarely collide into nearby particles. In a liquid state, the molecules are contained within the liquid and occasionally bump into each other. now in a solid state the atoms arrange themselves into a structure that the atoms sit very tightly next to each other, sometimes vibarating
2 Calculate the volume occupied, at rtp, 12.5 moles of sulfur dioxide gas. (One mole of any gas occupies a
volume of 24 dm³ at rtp.)
Answer:
300 dm³
Explanation:
According to the information given in this problem, SO₂ is 24 dm³/mol at rtp.
We are trying to find the volume of 12.5 moles of SO₂, so we can do the following math to solve:
12.5 mol SO₂ × 24 dm³/mol ⇒ mol cancels out, leaving us with dm³
300 dm³
Therefore, the volume occupied is 300 dm³
What are the series of steps that form oxygen atoms?
Answer:
2.5.2 Atomistic Configurations of Oxygen in Silicon Crystals
Oxygen atoms are incorporated in the silicon lattice on an interstitial position (denoted by Oi), where the oxygen atom sits in an almost bond-centered position between two adjacent Si atoms [101]. Several of the local vibration modes are infrared (IR) active. The predominant IR line at 1104/cm (at room temperature) was calibrated with respect to other analytical methods, such as gas fusion and several radioactive techniques, and is used as the standard method for the quantitative determination of the oxygen content in as-grown silicon crystals (as-grown silicon usually contains only a negligible amount of precipitated oxygen).
What information can a foliated metamorphic rock provide you about the conditions under which it formed?
In the reduction reaction, the hot water and the 95% ethanol act as a solvent pair for the benzil. Which is the better solvent and which is the poorer one?
In the reduction reaction involving benzil, hot water and 95% ethanol act as a solvent pair. Among the two, ethanol is the better solvent as it can dissolve benzil more efficiently, while hot water serves as the poorer solvent due to its lower solubility for benzil.
In the reduction reaction, the 95% ethanol is the better solvent for benzil as it is able to dissolve more of the compound due to its polar nature. Hot water, on the other hand, is a poorer solvent for benzil as it is less polar and less able to dissolve the compound. However, both solvents are necessary for the reduction reaction as they help to create the necessary conditions for the reduction of benzil to take place.
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The rapid destruction of tropical rain forests may be harmful because
The rapid destruction of tropical rain forests is harmful because it reduces habitats for animals and plants, leading to a decrease in biodiversity.
It can also cause climate change due to reduced carbon absorption and an increase in heat-trapping greenhouse gases, resulting in more extreme weather patterns. The destruction of tropical rain forests is a serious concern, with millions of acres destroyed worldwide each year. This destruction can be attributed to many causes, such as illegal logging, wildfires, over-farming and over-grazing. As a result, essential services and resources provided by the forests, such as clean water and soil health, are diminished. Additionally, the trees themselves can store large amounts of carbon, which is released into the atmosphere when they are burned or cut down. This further contributes to climate change, as carbon dioxide is a major heat-trapping greenhouse gas. Furthermore, deforestation reduces the habitats of many animals, leading to a decrease in biodiversity.
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which of the following CANNOT be classified as a substance? A. table salt B. air C. nitrogen D. gold
Answer:
C. Nitrogen
Explanation:
All of the other options are mixtures making them substances, but nitrogen is an element. (while gold is an element, there are often times that gold is mixed with other elements, creating a substance)
What is the concentration (M) of CH3OH in a solution prepared by dissolving 11.7 g of CH3OH in sufficient water to give exactly 330. mL of solution
The molarity of CH3OH is 1.5M
What is molarity of a solution?The amount of a substance in a certain volume of solution is referred to as its molarity (M). Molarity is defined as the number of moles of a solute per litre of a solution. Molarity is another word for a solution's molar concentration.
Molality and molarity are two measures of a chemical solution's concentration. The primary difference between the two is one of volume and mass.
Molality is concerned with the moles of a solute in relation to the mass of a solvent, whereas molarity is concerned with the moles of a solute in proportion to the volume of a solution.
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Which is the smallest volume?
A
2.3 liters
B
0.4 mL
С
980 cm
D
1050 mL
heat
I am a halide with 4 energy levels?
Answer:
Potassium Iodide?
Explanation:
The pharmacy stocks nitroglycerin 2% ointment. How many grams of this ointment should be mixed with an ointment base to obtain 100 grams of an ointment with a concentration of 0.2% ? (round answer to nearest whole number, if needed) Your Answer:
1000 grams of nitroglycerin 2% ointment should be mixed with the ointment base to obtain 100 grams of an ointment with a concentration of 0.2%.
To determine the amount of nitroglycerin 2% ointment needed to mix with an ointment base to obtain 100 grams of an ointment with a concentration of 0.2%, we can use the concept of a proportion.
Let's set up the proportion:
(grams of nitroglycerin 2% ointment) / 2% = 100 grams / 0.2%
To solve for the grams of nitroglycerin 2% ointment, we can cross-multiply and then divide:
(grams of nitroglycerin 2% ointment) = (2% / 0.2%) * 100 grams
Calculating the right side of the equation:
(grams of nitroglycerin 2% ointment) = (2 / 0.2) * 100 grams
= 10 * 100 grams
= 1000 grams
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how do seagrasses and mangroves increases the health of coral reefs?
Answer:
Seagrass slow down the water movements and trap the heavy metals and nutrient rich runoff
Mangroves and seagrasses stabilize the sediments, slow down the water movements and trap the heavy metals and nutrient rich runoff, thus improving the water quality for corals and fish communities. They also enhance the biomass of coral reef fishes by providing nursery habitats.
consider two solutions: solution x has a ph of 4; solution y has a ph of 7. from this information, we can reasonably conclude that _____.
the concentration of hydrogen ions in solution y is 1000 times as great as the concentration of hydrogen ions in solution x
the concentration of hydrogen ions in solution x is 1000 times as great as the concentration of hydrogen ions in solution y
solution y has no free hydrogen ions (h+) the concentration of hydrogen ions in solution x is 3 times as great as the concentration of hydrogen ions in solution y.
Consider two solutions: solution x has a ph of 4; solution y has a ph of 7. from this information, we can reasonably conclude that the concentration of hydrogen ions in solution x is 1000 times as great as the concentration of hydrogen ions in solution y.
The pH scale is a logarithmic scale that measures the concentration of hydrogen ions (H+) in a solution. A lower pH value indicates a higher concentration of hydrogen ions, while a higher pH value indicates a lower concentration of hydrogen ions. In this case, solution x has a pH of 4, while solution y has a pH of 7. Since the pH of solution x is lower than that of solution y, we can conclude that the concentration of hydrogen ions in solution x is higher than that in solution y.
The pH scale is logarithmic, meaning that each unit represents a tenfold difference in hydrogen ion concentration. Therefore, the difference in pH between solution x and solution y is 3 (4 - 7). This means that the concentration of hydrogen ions in solution x is 10^3 times (or 1000 times) greater than the concentration in solution y. Hence, we can reasonably conclude that the concentration of hydrogen ions in solution x is 1000 times as great as the concentration of hydrogen ions in solution y.
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Consider the following reversible reaction.Upper (s) plus upper O subscript 2 (g) double-headed arrow upper C upper O subscript 2 (g).What is the equilibrium constant expression for the given system?
Given the reaction:
C + O2 ⇄ CO2
We can find the equilibrium constant (Keq) using the following:
\(k_{eq}=\frac{[products]}{[reactants]}\)\(k_{eq}=\frac{[products]}{[reactants]}\Rightarrow k_{eq}=\frac{[CO_2]}{[C][O2]}\)Therefore the answer is letter A
Please help me with this
The products have different P _ _ _ _ _ _ _ _ _ to the reactants.
It is 10 letters.
The answer starts with a P.
And when you answer pls make sure it is correct.
Answer:
Procedures
Explanation:
The answer is procedures.
trust me
which point marks the highest temperature and pressure at which it's possible to determine whether a sample of pure x is a liquid or a gas? a b c d e f g h in what region would a sample of pure x be liquid? a b c d e f g h which line must the temperature and pressure have crossed if a gaseous sample of x is observed to condense?
The critical point determines liquid or gas. The liquid region is denoted "L." Condensation occurs when crossing the vaporization curve.
The point that marks the highest temperature and pressure at which it is possible to determine whether a sample of pure substance "X" is a liquid or a gas is called the critical point.
At the critical point, the liquid and gas phases of a substance become indistinguishable, and there is no clear distinction between the two phases. The critical point is denoted by the letter "C" on a phase diagram.
To determine the region where a sample of pure substance "X" would be a liquid, we need to look at the phase diagram.
A phase diagram is a graph that represents the relationship between temperature, pressure, and the different phases of a substance. The region where the sample would be a liquid is typically denoted by the letter "L" on the phase diagram.
If a gaseous sample of substance "X" is observed to condense, it means that it is transitioning from the gas phase to the liquid phase. This transition occurs when the temperature and pressure cross the line separating the gas and liquid phases on the phase diagram.
This line is known as the vaporization curve or the saturation curve. Therefore, the temperature and pressure must cross this line in order for a gaseous sample of substance "X" to condense.
In summary, the critical point marks the highest temperature and pressure where it is possible to determine the phase of a substance.
The liquid phase region is denoted by "L" on the phase diagram, and a gaseous sample of substance "X" will condense when the temperature and pressure cross the vaporization curve.
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Substances have internal energy due to the constant, random motion of their particles. This is a kind of kinetic energy that differs depending on the substance's state of matter. Arrange the states of matter in order of increasing kinetic energy. liquid gas
Answer:
Solid < Liquid < gas
Explanation:
Matter consists of molecules, atoms and ions which are held together by forces of cohesion.
The states of matter are solid, liquid and gas.
Solids have molecules, atoms and ions that are tightly packed hence cannot move freely within the structure of the solid particle. This results in low kinetic energy
Liquids have molecules, atoms and ions that are freely packed together compared to solids hence are able to move freely within the structure of the liquid substance to a some extent. This results in a higher kinetic energy compared to that of the solid particle.
Gases have molecules, atoms and ions that are very loosely packed compared to the liquid substance and can move freely within the body of its container. This results in very kinetic energy and increased random motion
Answer:
Solid, Liquid, Gas in that order
Explanation:
A 0.520 g sample of an unknown nonelectrolyte compound is dissolved in 4.12 g of lauric acid (Kf = 3.90 °C/m). The freezing point depression is determine to be 4.20 °C. What is the molar mass of the compound?
The molar mass of the unknown nonelectrolyte compound is
Using the formula;
∆T = K m i
Where;
K = freezing point depression constant
m = molality of the solution
i = Van't Hoft factor
Note that i = 1 since the compound is a nonelectrolyte.
To find molality;
Number of moles = 0.520 g/Molar mass
Let the molar mass of the unknown compound be MM
Number of moles = 0.520 g/MM
Number of kilograms of solvent = 4.12 g/1000 = 0.00412 Kg
Molality = 0.520 g/MM * 1/0.00412 Kg
Freezing point depression is 4.20 °C
To find the molar mass of the compound;
4.20 °C = 3.90 °C/m * 0.520 g/MM * 1/0.00412 Kg
4.20 = 492.23/MM
MM = 492.23/4.20
MM = 117.19 g/mol
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Give me an example of something being mixed with titanium
Answer:
Titanium can be mixed / react with fluorine and chlorine etc
Answer: Titanium bromide, Titanium Chloride, Titanium Iodide.
Explanation:
0.75 kg to milligrams
Answer:
750000
Explanation:
multiply the mass value by 1e+6
Answer:
750000 mg is ur answer My G
Explanation:
No Explanation Needed Ig
an effective hot pack salt can release 5850 j of heat to the surroundings. how many grams of licl are needed to release this amount of heat?
4.01 grams of Licl are needed to release this amount of heat
What does one gram weigh?The gram is a unit of mass in the International System of Units (SI) that is equal to one thousandth of a kilogram. It was originally known as the gramme. Gram. This pen cap weighs around one gram. A weight scale like this one may provide a precise mass readout for many different things.
Mass of Licl required to release 5850J of heat to the surroundings.
Let x g Licl required.
Then x g ×∆H = 5850J
x g × 1.46 × 10³ = 5850
x = 5850/ 1.46 × 10³
x = 4.0068
so 4.01g Licl required.
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Could someone help me answer these questions with the answer and typed steps for how each answer was found? I asked this question previously but, I could not read the handwritten answer.
7. A 25 g soil sample was extracted with 75 mL of NH4OAc (pH 7.0), and the filtrate was analyzed
on an atomic absorption unit. The following results were obtained:
100 mg/L Ca2+, 45 mg/L Mg2+, 85.5 mg/L K+, 94.2 mg/L Al3+ and 8.0 mg/L H+.
a. What is the CEC in cmol(+)/kg for this sample?
b. What is the % B.S. for this soil?
c. What is the % acid saturation for this soil sample?
The CEC for this soil sample is 675.2 cmol(+)/kg.
The % Base Saturation for this soil sample is approximately 136.62%.
The % Acid Saturation for this soil sample is approximately 60.55%.
To calculate the CEC, % Base Saturation (B.S.), and % Acid Saturation for the given soil sample:
a. Calculation of CEC (Cation Exchange Capacity):
CEC is the sum of exchangeable cations in the soil. From the given results, we have:
CEC = Ca2+ + Mg2+ + K+ + Al3+
CEC = (100 mg/L + 45 mg/L + 85.5 mg/L + 94.2 mg/L) / (25 g / 1000)
CEC = 168.7 mg / (25 g / 1000)
CEC = 675.2 cmol(+)/kg
b. Calculation of % Base Saturation (B.S.):
% B.S. represents the percentage of CEC occupied by base cations. In this case, we consider Ca2+, Mg2+, and K+ as base cations. The formula to calculate % B.S. is:
% B.S. = (Ca2+ + Mg2+ + K+) / CEC * 100
% B.S. = (100 mg/L + 45 mg/L + 85.5 mg/L) / (168.7 cmol(+)/kg) * 100
% B.S. = 230.5 mg / (168.7 cmol(+)/kg) * 100
% B.S. = 136.62%
c. Calculation of % Acid Saturation:
% Acid Saturation represents the percentage of CEC occupied by acid cations, in this case, H+ and Al3+. The formula to calculate % Acid Saturation is:
% Acid Saturation = (H+ + Al3+) / CEC * 100
% Acid Saturation = (8.0 mg/L + 94.2 mg/L) / (168.7 cmol(+)/kg) * 100
% Acid Saturation = 102.2 mg / (168.7 cmol(+)/kg) * 100
% Acid Saturation = 60.55%
Please note that the given values were in milligrams per liter (mg/L), and the CEC and % Saturation values were calculated assuming a conversion from mg/L to cmol(+)/kg using the mass of the soil sample (25 g).
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What state had the fewest farms? Wisconsin Georgia Illinois
fill in the blank. "Properties of elements within a _________ on the periodic table change in a predictable way from one side of the table to the other"
Properties of elements within a period on the periodic table change in a predictable way from one side of the table to the other
From one side of the periodic table to the other, properties of elements within a period vary in a predictable manner. A horizontal row represents a period in the periodic table. The number of electron shells is the same for every atom in a row. Moving through a period causes elements to acquire electrons and protons and become less metallic. -Elements in the same period have the same number of electron shells.
As the atomic number rises, comparable features reoccur on a regular basis, which is reflected in this arrangement. From one side of the periodic table to the other, properties of elements within a blank shift in a predictable manner. those with comparable qualities are displayed in a column.
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Measuring Liquid Volume Pre-Lab worksheet
1. The longer distance for each choice is:
1 mile1 meter1 inch2. The complete statements are as follows;
1 mi = 1.6 km1 yd = 0.9444 m1 in = 2.54 cm3. The basic unit of length in the metric system is the meter and is represented by a lowercase m.
4. The meter is defined as the distance traveled by light in absolute vacuum in 1⁄299,792,458 of a second.
5. The values that complete each statement is given below:
1 km = 1000 m1 m = 100 cm1 m = 1000 mm6. The larger value for each option is:
A. 105 centimetersB. 4400 metersC. 12 centimetersD. 1200 millimeters7. The number of millimeters in 1 centimeter is 10 mm
8. Using the ruler and line, the answers are:
2.8 cm29 mm3 cmWhat is the unit for measuring distance in the metric system?The unit for measuring distance in the metric system is the meter. Smaller and larger values of the meter are also used such as millimeters, centimeters, kilometers, etc.
Other units for measuring distance include yards, miles, and inches.
The various units for measuring distance can also be interconverted using their conversion factors.
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If one-eighth of the mass of the original smple of a radioisotope remains unchanged after 4,800 years, the isotope could be? Show all work and explanation.
A. H-3
B. K-42
C. Sr-90
D. Ra-226
Based on the half-life of the material, the isotope is radium-226; option D
What is the half-life of a substance?The half-life of a substance is the time taken for half of the amount of material present in the original sample of the material to decay.
The half-life of materials differs from each other. The half-life may be in millions of years for some materials, whereas for some materials, the half-life could only be in seconds.
The half-life of materials is constant.
Considering the given material;
One-eighth of the mass of the original sample of the radioisotope remains unchanged after 4,800 years.
For one-eight of the material of the isotope to remain, the number of half-lives it has undergone will be;
after one half-life = half of the original sample remains
after two half-lives = one-fourth of the original sample remains
after three half-lives = one-eight of the original sample remains
The half-life of the isotope = 4800/3
The half-life of the isotope = 1600 years
Radium-226 has a half-life of 1600 yers
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