In the first propagation step of the bromination of 2,3-dimethylbutane, the newly formed Br radicals react with the molecules of 2,3-dimethylbutane. Give the major products formed by the first propagation step including both organic and inorganic products. Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. Include all free radicals by right-clicking on an atom on the canvas and then using the Atom properties to select the monovalent radical.

The mass of manganese-56 in a 1.0mg sample remaining at the end of 10.4 hours is 0.0025mg

What is Half Life?

Half-life, in radioactivity, is the amount of time needed for half of a radioactive sample's atomic nuclei to decay (change spontaneously into other nuclear species by emitting particles and energy), or, alternatively, the amount of time needed for a radioactive material's rate of disintegrations per second to decrease by half.

Cobalt-60, a radioactive isotope used in radiotherapy, has a half-life of 5.26 years, for instance. As a result, after that time, a sample that contained 8 g of cobalt-60 at first would only have 4 g of cobalt-60 and would produce half as much radiation. Only 2 g of cobalt-60 would remain in the sample after an additional delay of 5.26 years. The initial sample's mass and volume don't change noticeably,

10.4/2.6= 4

The mass of manganese-56 in a 1.0mg sample remaining at the end of 10.4 hours is 0.0025mg

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Answer

-52.2 Joules

Explanation

Given that;

Mass of krypton, m = 12.3 g

Temperature change, ΔT = 22.2°C - 39.3°C = -17.1°C

The specific heat of gaseous krypton, c = 0.248 J/g°C.

What to find:

The energy change, Q.

Step-by-step solution:

The energy change, Q can be determined using:

Q = mcΔT

Putting the values of the given parameters into the formula, this yields:

Therefore the energy change = -52.2 Joules

Answer:Each shell can hold a maximum number of electrons. moving through the elements in the periodic table, each atom has one more electron than the last because the number of electrons is the same as the atomic number. Electrons occupy the shells in order, starting with the shell that is nearest the nucleus.

Explanation:

Answer: Gold Wire

Explanation:

Out of all of these options only gold wire is an element, elements are pure and cannot be broken down by any chemical means

hope it helped, good luck :)

Answer: sand, silt, and clay.

Approximately 148.59 grams of carbon dioxide could be made.The remaining reactant, since \(O_2\)is the limiting reactant, all the CO will not be completely consumed. There would be no CO leftover as it is completely consumed in the reaction.

To determine the grams of carbon dioxide produced, we need to identify the limiting reactant first. The balanced chemical equation for the reaction is:

2 CO +\(O_2\) -> 2 \(CO_2\)

To find the limiting reactant, we compare the number of moles of each reactant and determine which one is present in a lower amount relative to the stoichiometry of the reaction.

First, we convert the given volumes of gases to moles using the ideal gas law equation:

n = PV / RT

where:

n = number of moles

P = pressure

V = volume

R = ideal gas constant

T = temperature

Assuming the reaction takes place at standard temperature and pressure (STP), which is 273.15 K and 1 atm, we can use the values to convert the volumes to moles:

For carbon monoxide (CO):

n(CO) = (75.3 L) / (22.414 L/mol) = 3.36 moles

For oxygen (O2):

n(O2) = (38.0 L) / (22.414 L/mol) = 1.69 moles

According to the balanced equation, the stoichiometry of the reaction is 2:1 for CO to \(O_2\)This means that for every 2 moles of CO, we need 1 mole of \(O_2\). In this case, the ratio of moles is 3.36:1.69, which shows an excess of CO.

To find the limiting reactant, we compare the mole ratio to the stoichiometry ratio. Since there is a surplus of CO, it is the excess reactant, and\(O_2\)is the limiting reactant.

To determine the amount of carbon dioxide produced, we use the stoichiometry of the reaction. From the balanced equation, we know that for every 2 moles of CO, 2 moles of CO2 are produced.

Since\(O_2\) is the limiting reactant, we use its moles to calculate the moles of \(Co_2\)produced:

n(\(CO_2\)) = 2 * n(\(O_2\)) = 2 * 1.69 moles = 3.38 moles

Finally, we convert the moles of\(CO_2\) to grams using the molar mass of carbon dioxide, which is 44.01 g/mol:

mass(\(CO_2\)) = n(\(CO_2\)) * molar mass(\(CO_2\) = 3.38 moles * 44.01 g/mol ≈ 148.59 grams

Therefore, approximately 148.59 grams of carbon dioxide could be made.

As for the remaining reactant, since \(O_2\)s the limiting reactant, all the CO will not be completely consumed. To determine the amount of CO leftover, we subtract the moles of CO used from the initial moles of CO:

Remaining moles of CO = Initial moles of CO - Moles of CO used

Remaining moles of CO = 3.36 moles - 2 * 1.69 moles ≈ 0 moles

Thus, there would be no CO leftover as it is completely consumed in the reaction.

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Answer:

A

Explanation:

27 us the number of protons when we subtract 27 from 59 it will be 32 because a mass number is the sum of proton and neutron but tell u more on the comment

Answer: A - An atom of cobalt contains more neutrons than protons.

Explanation: The atomic number is the number of protons in an atom. The atomic mass is the sum of protons & neutrons in an atom. So, with simple math we can figure out the number of neutrons. Total 59 - 27 protons = 32 neutrons. Which means that A is the only right answer in this case.

Little Extra: A & B would both be correct if Cobalt was a negatively charged ion. An atom is an ion if it is charged, and an ion is either negatively charged or positively charged. For example, if Cobalt had 27 protons & 26 electrons it's overall charge would be positive since it has more protons than electrons. And it would be negatively charged if Cobalt had 27 protons & 28 electrons. No charge if there are 27 protons & 27 electrons because proton +1 and electron -1. Imagine 27-27=0 no charge, 27-26= +1 charge, 27-28= -1 charge

I hope this made you smarter.

In foods and drinks, aspartame, a synthetic, non-saccharide sweetener that is 200 times sweeter than sucrose, is frequently used as a sugar replacement.

a. The molar mass of aspartame can be calculated by summing the atomic masses of its constituent elements, which are carbon (C), hydrogen (H), nitrogen (N), and oxygen (O). Therefore,

Molar mass of aspartame = (14 x atomic mass of C) + (18 x atomic mass of H) + (2 x atomic mass of N) + (5 x atomic mass of O)

= (14 x 12.01) + (18 x 1.01) + (2 x 14.01) + (5 x 16.00)

= 294.30 g/mol

Therefore, the molar mass of aspartame is 294.30 g/mol.

b. To determine the number of moles of aspartame present in 1.00 mg of aspartame, we need to use the following formula:

Number of moles = Mass / Molar mass

where Mass is the mass of the substance in grams and Molar mass is the molar mass of the substance in grams per mole.

Converting the given mass of 1.00 mg to grams, we get:

Mass = 1.00 mg = 0.001 g

Using the molar mass calculated in part a, we get:

Number of moles = 0.001 g / 294.30 g/mol = 3.40 x 10^-6 moles

Therefore, there are 3.40 x 10^-6 moles of aspartame present in 1.00 mg of aspartame.

c. To determine the number of molecules of aspartame present in 1.00 mg of aspartame, we need to use Avogadro's number:

Number of molecules = Number of moles x Avogadro's number

where Avogadro's number is 6.02 x 10^23 molecules per mole.

From part b, we know that there are 3.40 x 10^-6 moles of aspartame present in 1.00 mg of aspartame. Substituting this value in the above equation, we get:

Number of molecules = 3.40 x 10^-6 moles x 6.02 x 10^23 molecules per mole

= 2.05 x 10^18 molecules

Therefore, there are 2.05 x 10^18 molecules of aspartame present in 1.00 mg of aspartame.

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Metals can be removed from ores by reduction – the deletion of oxygen or forming a metal element from a compound.

Metal is extracted from mashed ore by one of two major methods: smelting or electrolysis. Smelting uses heat to discrete the valuable metal from the rest of the ore. Smelting usually needed a reduction agent, or another chemical, to separate metal from its ore.

Isolation of metal from concentrated Ore – Here the ore is changed to its oxide form and then reduced. The steps involved are either scorching or roasting and then heating with a reducing agent.

So we can conclude that trade extraction of metals from minerals is usually practiced by dump leaching, heap leaching, tank leaching, or pushed leaching.

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Explanation:

could you post the text? its inconvenient to go back and forth to the picture.

The correct option is b. at an angle; If a bullet passes through glass and leaves an oval-shaped hole, it entered the glass at an angle.

An oval resembles the form, contour, or shape of an egg.

For instance:

Thus, If a bullet passes through glass and leaves an oval-shaped hole, it entered the glass at an angle.

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Answer:

it's volume also decrease

Answer:

121 million joules energy is released

Explain :

As there are 500 moles of hydrogen gas in a kilogram, this means that burning a kilogram of hydrogen gas releases 500 times as much energy or 121 million joules .

Answer: C. Gaining 5 electrons

Explanation: Aluminium has 3 valence electrons to have a full outer shell it would need 5 to become an octet (8).

The pH of the solution after 50.0 mL of NaOH has been added is approximately 0.823.

To determine the pH of the solution after 50.0 mL of 0.250 M NaOH has been added to 100.0 mL of 0.200 M HCl, we need to consider the stoichiometry of the reaction between HCl and NaOH and the resulting solution composition.

The balanced equation for the reaction between HCl and NaOH is:

HCl + NaOH → NaCl + H₂O

From the balanced equation, we can see that one mole of HCl reacts with one mole of NaOH to produce one mole of NaCl and one mole of water.

Initial moles of HCl = initial volume of HCl solution (in L) × concentration of HCl (in mol/L)

Initial moles of HCl = 0.100 L × 0.200 mol/L = 0.020 mol

Moles of HCl reacted with NaOH
= moles of NaOH added
= volume of NaOH solution (in L) × concentration of NaOH (in mol/L)

Moles of HCl reacted with NaOH = 0.050 L × 0.250 mol/L = 0.0125 mol

Moles of HCl remaining
= Initial moles of HCl - Moles of HCl reacted with NaOH

Moles of HCl remaining = 0.020 mol - 0.0125 mol = 0.0075 mol

The volume of remaining HCl solution = Initial volume of HCl solution - Volume of NaOH solution added

Volume of remaining HCl solution = 100.0 mL - 50.0 mL = 50.0 mL = 0.050 L

The concentration of HCl in the remaining solution = Moles of HCl remaining / Volume of remaining HCl solution

Concentration of HCl in the remaining solution = 0.0075 mol / 0.050 L = 0.150 M

The concentration of HCl in the remaining solution is 0.150 M.

pH = -log[H⁺]

Since HCl is a strong acid, it completely dissociates in water to form H+ ions. Therefore, the concentration of H+ in the solution is equal to the concentration of HCl.

pH = -log(0.150) ≈ 0.823

Therefore, the pH of the solution after 50.0 mL of NaOH has been added is approximately 0.823.

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The characteristics and the type of molecular bond they describe:

1. Bonds found in Halite (between Na⁺ and Cl⁻): Ionic bond

2. Bonds found between Si and O in the Si-O tetrahedron: Covalent bond

3. Bonds inside the water molecule (between the H and O): Covalent bond

4. Bonds that exist between two water molecules: Hydrogen bond

5. Strongest bond type: Covalent bond

6. Weakest bond type: Van der Waals bond

7. Bonds that are used by water to dissolve salt: Ionic bond

The ionic bond is a type of molecular bond found in halite (between Na⁺ and Cl⁻). The Si-O tetrahedron is held together by a covalent bond. The bond inside the water molecule (between the H and O) is also a covalent bond. The hydrogen bond is the type of bond that exists between two water molecules. The covalent bond is the strongest bond type, while the van der Waals bond is the weakest bond type. Water uses the ionic bond to dissolve the salt.

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Answer:

3.2

Explanation:

dont trust me

Answer :

Step-by-step explanation :

Molarity: It is defined as number of moles of solute dissolved per litre of solution.

Molarity is represented by 'M'

Required Formula :

\( { \boxed{\sf M = \dfrac{Number \: of \: moles \: of \: solute}{Volume \: of \: {sol}^{n} (ml) } \times 1000}}\)

Here,

Number of moles = Given mass/molar mass

Substituting the values,

\(:\implies \) No. of moles = 12.3/62

\(:\implies \) 0.198 mol

Now,

\(:\implies \) M = 0.198/564 × 1000

\(:\implies \) M = 198/564

\(:\implies \) M = 0.34 M

Therefore, Molarity of the solution is 0.34 M

Answer :

Step-by-step explanation :

Molarity: It is defined as number of moles of solute dissolved per litre of solution.

Molarity is represented by 'M'

Required Formula :

\( { \boxed{\sf M = \dfrac{Number \: of \: moles \: of \: solute}{Volume \: of \: {sol}^{n} (ml) } \times 1000}}\)

Here,

Number of moles = Given mass/molar mass

Substituting the values,

\(:\implies \) No. of moles = 12.3/62

\(:\implies \) 0.198 mol

Now,

\(:\implies \) M = 0.198/564 × 1000

\(:\implies \) M = 198/564

\(:\implies \) M = 0.34 M

Therefore, Molarity of the solution is 0.34 M

Answer:

Lithium sulfide

The configuration of water can be sketched as follows: H--O--H, where the two hydrogen atoms share one pair of electrons with the oxygen atom.

Hydrogen atoms are the most abundant elements in the universe, making up about 75% of all baryonic mass. They are composed of a single proton and electron, and have a mass of 1.00794 amu (atomic mass unit). Hydrogen atoms have the smallest atomic radius of any atom, allowing them to form strong covalent bonds with itself and other atoms. This makes them extremely useful in many reactions, including the formation of water, hydrocarbons, and other organic molecules. Hydrogen atoms also have a relatively low first ionization energy, making them easily ionized in reactions. This means they can be used to transfer electrons, thus making them important in many oxidation-reduction reactions. Hydrogen atoms are also important in the formation of stars and planets, and can be used to measure the age and composition of stars.

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The overall reaction for the oxidation of SO2 by O2 to give SO3 is:

SO2(g) + O2(g) ⟶ 2SO3(g)

The two given reactions are:

NO2(g) + SO2(g) ⟶ NO(g) + SO3(g)

2NO(g) + O2(g) ⟶ 2NO2(g)

Adding these reactions, we get:

NO2(g) + SO2(g) ⟶ NO(g) + SO3(g)

2NO(g) + O2(g) ⟶ 2NO2(g)

2NO2(g) + SO2(g) + O2(g) ⟶ 2NO(g) + 2SO3(g)

Therefore, the overall reaction for the oxidation of SO2 by O2 to give SO3 is:

SO2(g) + O2(g) ⟶ 2SO3(g)

where the catalyst NO2 is not explicitly shown. All the reactants and products are in the gas phase.

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Answer:

1 mole of carbon.

Explanation:

The presence of a coenzyme like NAD+ or NADP+ is necessary for the efficient catalysis of alcohol oxidation by the enzyme.

An enzyme that catalyzes the oxidation of an alcohol is likely to be accompanied by a coenzyme called NAD+ (nicotinamide adenine dinucleotide) or NADP+ (nicotinamide adenine dinucleotide phosphate).

Coenzymes are non-protein molecules that work alongside enzymes to facilitate enzymatic reactions. In the case of alcohol oxidation, NAD+ or NADP+ serves as a coenzyme that acts as an electron acceptor.

During the oxidation process, the alcohol molecule donates electrons to the coenzyme, which is then reduced to NADH or NADPH. This reduction reaction allows the enzyme to carry out the oxidation reaction efficiently.

The role of NAD+ or NADP+ as a coenzyme is crucial in alcohol oxidation, as it helps in the transfer of electrons and participates in the overall redox reaction.

The reduced form of the coenzyme (NADH or NADPH) can then go on to donate the electrons to other metabolic pathways or serve as a reducing agent in cellular processes. Overall, the presence of a coenzyme like NAD+ or NADP+ is necessary for the efficient catalysis of alcohol oxidation by the enzyme.

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Answer:

Explanation:

Density of a substance can be found by using the formula

From the question

Density = 11.35 g/cm³

mass of iron = 1.1 g

To find the volume substitute the values into the above formula and solve for the volume

That's

Making volume the subject we have

So we have

= 0.096916

We have the final answer as

Hope this helps you

The given statement " Unlike covalent bonds, which produce a crystal lattice, ionic bonds are formed between 2 individual atoms, giving rise to true, discrete molecules" is false because Ionic bonds are not formed between two individual atoms.

Ions, which are atoms or molecules that have gained or lost electrons to become charged, come together to form ionic bonds rather than between two separate atoms.

An ionic bond forms a crystal lattice structure rather than a distinct molecule when one ion gives electrons to another ion. On the other hand, covalent bonds often develop between separate atoms that share electrons, leading to the development of distinct molecules.

It's crucial to remember that this generalisation is not always true, as some covalent substances, like silicon and diamond, can also form extended crystal lattice structures.

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Explanation:

\(\large{\pink{ \underline { \underline{ \red{ \boxed{ \blue{ \sf{B. The \: mass \: of \: each \: isotope}}}}}}}}\)

The molecular formula of a compound is a whole number multiple of its empirical formula. The empirical formula of the hydrocarbon is C₄H₉.

The empirical formula of a compound can be defined as the formula which gives the simplest whole number ratio of atoms of various elements present in one molecule of the compound.

Here moles of 'C' = moles 'CO₂' = 6.16 / 44 = 0.14 moles

Moles of 'H' = 2 × moles 'H₂O' = 2 × 2.84/18.02 = 0.315 moles

Divide both number of moles by 0.14. Then we get

1 mol 'C' and 2.25 mol 'H'

Multiply both with 4 to obtain a whole number.

Then the number of carbon is 4 and that of hydrogen is 9.

Thus the empirical formula is C₄H₉.

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C. physical change

Explanation:

That's the answer