In right triangle ABC, mA = 90°, sin B = x - 0.33, and cos C = 6x +0.62.
Solve for x.

Answer:

6a(2b+1)

is it this

if it's correct mark me brainliest pleasee

The length of the chord is 6

Simply said, a circle is a rounded form without any edges or line segments. It has the geometric form

The circle's general equation is written as follows: x2 + y2 + 2gx + 2fy + c = 0. The center of the circle in this general form of the equation of a circle is (-g, -f), and its radius is given by r = g2+f2cg2+f2c.

The circle's general equation is written as follows: x2 + y2 + 2gx + 2fy + c = 0. The coordinates of the circle's center and radius are determined using this general form. The equation in this case represents a circle that does not pass through the origin because c is a constant term.

We possess

4x2+4y2−12x+32y=27…(1)

We shall have y=0 when the specified circle intersects the x-axis, therefore

4x2+4y2−12x+32y=27

=>4x2−12x=27

=>4x2−12x−27=0…(2)

The answers to (2) are:

x1=−3/2

x2=9/2

Thus, the supplied circle intersects the x-axis at the following points:

A(−3/2,0) and B(9/2,0)

The length of the chord we want is defined as the distance d between these sites. The well-known formula for calculating the distance between points A and B is used to calculate the distance d:

d=root((9/2−(−3/2))^2+(0−0)^2)

√=6^2

=6

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The probability of leaving it in any given class is 1/4, the probability of leaving it in the 5th class is 1/4, or\(0.250 (25.0%).\)

The probability that the student left her iClicker device in the 5th class is 0.250 (25.0%). This is because the probability of leaving it in any given class is 1/4, and as she attends 5 different classes,

there is 5/4 or 1.25 chances of her leaving it in the 5th class.

To explain further, the probability of an event can be calculated by dividing the number of ways the event can occur by the total number of possible outcomes. In this case, the event is leaving the iClicker device in the 5th class, and the total number of possible outcomes is 5 (for the 5 classes).

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Answer:

Step-by-step explanation:

A) 700 cookies in 7 days.

im not sure of B

In this case, The critical numbers are x = 1.

To find the critical numbers of g(y) = (y-2)/(y^2-2y+4), we first find the derivative g'(y) and then set it equal to zero or find where it's undefined.

g'(y) = (2y-2)/((y^2-2y+4)^2).

The critical numbers are y = 1. 2.

For f(x) = x^(-2)ln(x), you probably meant f(x) = x^(-2)ln(x).

In this case, find the derivative f'(x) and set it equal to zero or find where it's undefined.

f'(x) = -2x^(-3)ln(x) + x^(-2)(1/x).

The critical numbers are x = 1.

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(4+4i)^4 in standard form is -16√2. De Moivre's Theorem states that for any complex number z = r(cosθ + isinθ), raised to the power of n, the result can be expressed as: z^n = r^n(cos(nθ) + isin(nθ))

To use De Moivre's Theorem to find the power of a complex number, we can follow these steps:

Write the complex number in polar form: a + bi = r(cosθ + isinθ), where r is the modulus (magnitude) of the complex number and θ is the argument (angle).

Apply De Moivre's Theorem, which states that (r(cosθ + isinθ))^n = r^n(cos(nθ) + isin(nθ)).

Let's find (4+4i)^4 using De Moivre's Theorem:

Step 1: Convert (4+4i) to polar form.

We have a = 4 and b = 4, so the modulus (r) can be found using the formula r = √(a^2 + b^2):

r = √(4^2 + 4^2) = √32 = 4√2

The argument (θ) can be found using the formula θ = arctan(b/a):

θ = arctan(4/4) = arctan(1) = π/4

So, (4+4i) can be written in polar form as 4√2(cos(π/4) + isin(π/4)).

Step 2: Apply De Moivre's Theorem.

To find (4+4i)^4, we raise the modulus to the power of 4 and multiply the argument by 4:

(4√2)^4(cos(4(π/4)) + isin(4(π/4)))

Simplifying this expression:

(16√2)(cos(π) + isin(π))

Now, cos(π) = -1 and sin(π) = 0, so the expression becomes:

-16√2 + 0i

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Answer:

49.7 mph

Step-by-step explanation:

divide the length value by 1.609

An estimate for the total volume of food and water you've ingested in the last day is 3000-5000 milliliters. On average, the heart pumps about 5 liters of blood per minute. 10-20% or more error I'm expecting. Calculating heart blood volume compared to food and drink consumption is crucial for understanding circulation and liver function.

D.1 Estimating the amount of food and water consumed in a day can be difficult without specific measurements, but a rough estimate can be made based on typical intake amounts. On average, a person may consume 2-3 liters of water and 1000-2000 calories per day, resulting in an estimated total volume of 3000-5000 milliliters.

D.2 The amount of blood pumped by the heart varies from person to person and depends on factors such as heart rate and overall health. On average, the heart pumps about 5 liters of blood per minute, which is much larger than the estimated volume of food and water intake.

D.3 Estimating food and water intake and blood flow is prone to error due to variability and uncertainties in personal measurements. Individuals' habits, health, and physical activity levels can affect these estimates, potentially resulting in a significant error of 10-20% or more.

D.4 The calculation of the heart's blood volume compared to food and drink consumption is crucial for understanding the circulation system and liver role.

The liver processes nutrients, detoxifies, and produces blood components, while the heart is responsible for circulating blood throughout the body. The vast difference in volume between the two is emphasized, emphasizing the heart's crucial role in maintaining circulation.

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Answer:

-0.2

Step-by-step explanation:

to find n you need to get it all by itself so you subtract 16.2 from both sides so on the left side it cancels out and on the right side it equals -.02 which is then equal to n which is your answer

Answer:

c and d are monomial because they have only one term

Answer:

1

Step-by-step explanation:

hope this help:) I use slop formula

Answer:

1

Step-by-step explanation:

Y2-y1/ x2-x1

6-5/3-2

1/1 = 1

Answer:

pretty sure its 2 mugs

Step-by-step explanation: i might be wrong

Answer:

4/6

Step-by-step explanation:

Jon is painting a box like a rectangular prism with dimensions of 15 by 8 by 12 inches. Total surface area of the box that he has to paint is 792 square inches.

Let:

w = width of the rectangular prism

l = length of the rectangular prism

h =height of the rectangular prism

Then, the surface area can be calculated as:

surface area = base area + top area + left side area + right side area + front side area + back side area.

surface area = 2 (w x l) + 2 (l x h) + 2 (w x h)

Substitute:

w = 8 inches

l = 15 inches

h = 12 inches

Surface area = 2 (8 x 15) + 2 (15 x 12) + 2 (8 x 12)

                     = 2 x (120 + 180 + 96)

                     = 792

Hence, Jon has to paint 792 sq. in.

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The unknown measures of the right angle triangle are m∠V = 69° , RV = 12.85 and m∠R = 21°

A right triangle is a triangle that has one of its angles as 90 degrees.

Therefore, the side and angles of a right triangle can be found using trigonometric ratios.

Hence,

tan v = opposite / adjacent

opposite side = 12

adjacent side = 4.6

Therefore,

tan V = 12 / 4.6

v = tan⁻¹ 2.60869565217

v = 69.0265065627

m∠V = 69°

Let's find  m∠R

m∠R = 180 - 69 - 90

m∠R = 21°

Let's find RV

sin 69° = opposite / hypotenuse

sin 69 = 12 / h

cross multiply

h = 12 / sin 69

h = 12 / 0.93358042649

h = 12.8537402885

RV = 12.85 units

Therefore, the unknown side and angles of the triangle are as follows:

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https://www.coursehero.com/tutors-problems/Calculus/16028189-Part-of-a-cross-country-skiers-path-can-be-described-with-the-vector/

Answer:

14) D; 16) C.

Step-by-step explanation:

14) the given equation can be written (x-2)(x-1/2)=0;

D. -2; 1/2.

16. if the original length is 'x', then it is possible to make up the equation of area:

(x+3)²=225; ⇒ x=12;-18; x=12 [m], the C option.

Based on the given data, we can calculate the control limits using 3-sigma for the diameter of the auto pistons.

a) The value of x is 155.56 mm (rounded to two decimal places).

b) The value of R is 4.44 mm (rounded to two decimal places).

c) Using 3-sigma, the Upper Control Limit (UCL) for the diameter is calculated as:

UCL = x + 3R = 155.56 + 34.44 = 156.93 mm (rounded to two decimal places)

The Lower Control Limit (LCL) for the diameter is calculated as:

LCL = x - 3R = 155.56 - 34.44 = 154.19 mm (rounded to two decimal places)

d) Using 3-sigma, the Upper Control Limit for the Range (UCLR) is calculated as:

UCLR = D4 * R = 2.115 * 4.44 = 7.89 mm (rounded to two decimal places)

The Lower Control Limit for the Range (LCLR) is always 0 in this case since negative ranges are not possible.

e) If the true diameter mean should be 155 mm, the new centerline (nominal line) would be 155 mm. In this case, the UCL and LCL would be calculated using 3-sigma as follows:

UCL = Nominal + 3R = 155 + 34.44 = 156.37 mm (rounded to two decimal places)

LCL = Nominal - 3R = 155 - 34.44 = 153.63 mm (rounded to two decimal places)

Please note that the control limits calculated using 3-sigma assume a normal distribution and the data follows the same pattern in the future.

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The complete question is:

What is the value of x? = x= 155.56 mm (round your response to two decimal places). b) What is the value of R? R= 4.44 mm (round your response to two decimal places). c) What are the UCL, and LCL; using 3-sigma? Upper Control Limit (UCL) = 156.93 mm (round your response to two decimal places). Lower Control Limit (LCL) = 154.19 mm (round your response to two decimal places). d) What are the UCLR and LCLR using 3-sigma? Upper Control Limit (UCLR)= 7.89 mm (round your response to two decimal places). Lower Control Limit (LCLR)= 0.99 mm (round your response to two decimal places). e) If the true diameter mean should be 155 mm and you want this as your center (nominal) line, what are the new UCL and LCL? Upper Control Limit (UCL)= 156.37 mm (round your response to two decimal places). Lower Control Limit (LCL;)= 153.63 mm (round your response to two decimal places). Refer to Table 56.1-Factors for Computing Control Chart Limits (3 sigma) for this problem Auto pistons at Wemming Chung's plant in Shanghai are produced in a forging process, and the diameter is a critical factor that must be controlled. From sample sizes of 10 pistons produced each day, the mean and the range of this diameter have been as follows: Day 1 2 3 4 5 Mean x (mm) 150.9 153.2 153.6 153.5 154.6 Range R (mm) 4.0 4.8 4.1 4.8 4.5

1. The given statement "A negative attitude, misperception, and partial hearing loss are all examples of noise in the basic communication process" is True

2. The given statement "Employee motivation and pay satisfaction are major components in Frederick Herzberg's two-factor theory" is True

1) Negative attitude, misperception, and partial hearing loss are all examples of noise in the basic communication process.

Noise refers to any external or internal element that disrupts communication. Communication is the exchange of messages between two or more people, so noise in communication refers to anything that interferes with the exchange of messages.

2)Employee motivation and pay satisfaction are major components in Frederick Herzberg's two-factor theory.

Herzberg's two-factor theory, also known as the motivation-hygiene theory, identifies the two types of factors that affect job satisfaction:

hygiene factors and motivating factors.

Employee motivation and pay satisfaction are examples of motivating factors that contribute to job satisfaction.

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It will take 20 hours to fill the 920-gallon water in the pool if Daniel began filling an empty swimming pool at 8:30 a.M. After 5 hours, the pool contained 230 gallons of water.

Fraction number consists of two parts one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.

We have:

After 5 hours the pool filled with 230 gallons

Let's suppose that after x hours the pool will fill with 920 gallons

After x hours the pool filled with 920 gallons.

As the water input contained at a constant rate

So the value of x can be evaluated:

\(\rm x = \frac{920\times5}{230}\)

x = 20 hours

Thus, it will take 20 hours to fill the 920-gallon water in the pool if Daniel began filling an empty swimming pool at 8:30 a.M. After 5 hours, the pool contained 230 gallons of water.

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Answer:

25%

Step-by-step explanation:

Answer:

1 <—5⁰

25<—5²

1/25<—5-²

5<—5¹

Answers:

==============================================================

Explanation:

I'm assuming 7/5 is the scale factor. If so, notice how 7/5 = 1.4 which is larger than 1.

The scale factor being larger than 1 means we have an enlargement.

The image is going to be larger compared to the preimage.

The preimage rectangle is 12 in by 6 in. Multiply each dimension by 1.4 to get 12*1.4 = 16.8 and 6*1.4 = 8.4

The image rectangle is 16.8 inches by 8.4 inches

Answer:

This is an enlargement. The dimensions of the scaled rectangle is 16.8 inches by 8.4 inches.

Step-by-step explanation:

This is a dilation.

A dilation makes a figure larger or smaller.

In this case, the scale factor is an enlargement; the figure will be larger.

The figure will be larger because the scale factor, 7/5, is larger than one (1).

If the scale factor were smaller than one (1), it would be a reduction.

In dilations, a scale factor is how much larger the image will be.

In other words, multiply the side lengths by the scale factor.

The original rectangle has a length of 12 inches and a width of 6 inches.

\(12*7/5=84/5\)

\(6*7/5=42/5\)

It will be more convenient to change the products, which are fractions, to decimals.

\(84/5=16.8\)

\(42/5=8.4\)

Therefore, the dimensions of the scale rectangle is 16.8 inches by 8.4 inches.

Answer:

16x+6

Step-by-step explanation:

5x+2+3x+1+5x+2+3x+1 =

16x+6

Answer:

16x + 2

Step-by-step explanation:

\(\boxed{\begin{minipage}{4 cm}\underline{Perimeter of a rectangle}\\\\$P=2(w+l)$\\\\where:\\ \phantom{ww}$\bullet$ $w$ is the width. \\\phantom{ww}$\bullet$ $l$ is the length.\\\end{minipage}}\)

Given expressions:

To write an expression for the perimeter of the rectangle, substitute the given expressions for the width and length into the perimeter formula:

\(\begin{aligned}\implies \textsf{Perimeter} &=2\left(5x+2+3x-1 \right)\\ &= 2(5x+3x+2-1)\\&=2(8x+1)\\&=16x+2\end{aligned}\)

If 12 students are excellent students and they make up 37.5% of the class, the total number of students in the class can be found using a proportion. The result is 32 students in the entire class.

If 12 students are excellent students and they make up 37.5% of the class, we can use the following proportion to find the total number of students in the class:

Number of excellent students / Total number of students = Percentage of excellent students as a decimal

Substituting the given values into the equation, we get:

12 / Total number of students = 0.375

To solve for the total number of students, we can isolate the variable by multiplying both sides of the equation by the reciprocal of 0.375, which is 2.6667 (rounded to four decimal places):

12 / 0.375 = Total number of students

Total number of students = 32

Therefore, there are 32 students in the entire class.

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The finite population correction factor is used in computing the standard error of the sample mean when the sample size is smaller than 5% of the population size.

The finite population correction factor is a adjustment made to the standard error of the sample mean when the sample is taken from a finite population, rather than an infinite population.

It accounts for the fact that sampling without replacement affects the variability of the sample mean.

When the sample size is relatively large compared to the population size (more than half), the effect of sampling without replacement becomes negligible, and the finite population correction factor is not necessary.

In this case, the standard error of the sample mean can be estimated using the formula for sampling with replacement.

On the other hand, when the sample size is small relative to the population size (less than 5%), the effect of sampling without replacement becomes more pronounced, and the finite population correction factor should be applied.

This correction adjusts the standard error to account for the finite population size and provides a more accurate estimate of the variability of the sample mean.

Therefore, the correct answer is option 2: the finite population correction factor is used when the sample size is smaller than 5% of the population size.

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