In an electrolytic cell, the cathode is where _____ A) anions are attracted to B) a graphite electrode is used C) oxidation occurs D) reduction occurs E) electrons are created

Answer: The mitochondria, as bacteria, only wanted to rob the host cells of their energy and then leave them to die. But the bacteria soon realized the benefit of working together with simple cells. The simple cells provide them with antioxidants to protect them from free radicals and toxic reactive oxygen species that the mitochondria generate as a byproduct of energy production.

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The value of ΔG at 298 K for a reaction mixture containing 1.9 atm N2, 1.6 atm H2, and 0.65 atm, the answer is (a) -3.86 × 10^3.

NH3 can be calculated using the equation:

ΔG = ΔG° + RT ln(Q)

where ΔG is the standard Gibbs free energy change, ΔG° is the standard Gibbs free energy change at standard conditions, R is the gas constant, T is the temperature in Kelvin, and Q is the reaction quotient.

In this case, we are given ΔG° as -33.3 kJ/mol. To calculate Q, we need to use the partial pressures of the gases in the reaction mixture. The reaction stoichiometry tells us that the ratio of the partial pressures of N2, H2, and NH3 is 1:3:2. Therefore, we can write:

Q = (P(NH3))^2 / (P(N2) * P(H2)^3)

Plugging in the given values of P(N2) = 1.9 atm, P(H2) = 1.6 atm, and P(NH3) = 0.65 atm, we can calculate Q. Then, using the value of R = 8.314 J/(mol·K) and the temperature T = 298 K, we can substitute these values into the equation and solve for ΔG.

The calculated value of ΔG at 298 K for the given reaction mixture is approximately -3.86 × 10^3 J/mol. This value is equivalent to -3.86 kJ/mol. Therefore, the answer is (a) -3.86 × 10^3.

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Answer:

spectral emission lines from hydrogen atoms

Explanation:

There are 20.8 moles of propanol

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

1.2 x 10⁵ molecules of propanol

\(\tt \dfrac{1.25\times 10^{25}}{6.02\times 10^{23}}=20.8~moles\)

Answer:

i. If the area is doubled keeping the force constant, then pressure will be halved.

ii. If force is doubled keeping area constant, then pressure will also be doubled.

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This chemical is known as lead (II) nitrate. It is an ionic assembly (salt compound) comprised of lead cations in the +2 oxidation state. With regard to the naming convention, each lead (II) cation is paired with two nitrate anions, each having a charge of -1.

Chemical nomenclature is a set of principles for naming chemical substances in a systematic manner. The International Union of Pure and Applied Chemistry designed and developed the most widely used nomenclature in the world (IUPAC).

The basic goal of chemical nomenclature is to guarantee that no ambiguity exists between a spoken or written chemical name and the chemical compound to which the name refers. Each chemical name should only relate to one substance.

It is required to indicate the charge of these cations or compounds containing these cations when identifying them. Ionic compounds are formed when cations and anions interact. The cation of an ionic compound is named first, followed by the anion. When writing their chemical formulae, they use the same format.

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Answer:

That is def true

Explanation:

Answer:

Mostly large grains, with a sticky texture, 55% sand, 40% clay, and 5% silt

Explanation: I took the test, hope it helps.

Mostly large grains, with a sticky texture, 55% sand, 40% clay, 5% silt. The correct option is A.

One side of the triangle represents sand, the other side represents clay, and the third side represents silt.

A soil texture triangle is used to classify a soil's texture class. The percentages of sand, silt, and clay are scaled on the sides of the soil texture triangle.

Clay percentages are read across the triangle from left to right. Silt is read from top to bottom, upper right to bottom.

Jonathan used the soil triangle to identify a sample of soil as sandy clay; the soil description that allowed Jonathan to make this identification is 55% sand, 40% clay, and 5% silt, with mostly large grains and a sticky texture.

Thus, the correct option is A.

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Answer:  A -Covalent Solid, B -  Ionic Solid , C - Metallic Solid , D -

Molecular solid

Explanation: Covalent Solid:- Atoms are held together by covalent bond.

Ionic Solid:-A solid compound formed by chemical reaction of a cation(+) and with an anion (-) . Metallic Solid:-Atoms of metal held together by metallic bonds.  Molecular solid:-  molecules are held together by Vander waal forces. A >1000 °C does not conduct electricity.B 850 °C conducts electricity in the liquid state.C 750 °C conducts electricity in the solid state.D 150 °C does not conduct electricity.

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Answer:

= 3.01 x 10²³ atoms of gold (Au)

Explanation:

1 mole of any substance => 1 Avogadro's Number of particles = 6.02 x 10²³ particles.

∴ for 5 moles of gold atoms => 5 moles x 6.02 x 10²³ atoms/mole

= 3.01 x 10²³ atoms of gold (Au)

The pH of the 2.20 M solution of the weak acid CH3CO2H can be calculated using the equilibrium expression and the dissociation constant (Ka) of the acid.

To determine the pH of the solution, we need to consider the dissociation of the weak acid CH3CO2H. The equilibrium expression shows the formation of H3O+ ions (hydronium ions) and CH3CO−2 ions (acetate ions) from the dissociation of CH3CO2H in water.

The Ka value represents the acid dissociation constant and is given as 1.76×10−5. This value indicates the degree of dissociation of the acid. Since the acid is weak, it only partially dissociates, and we can assume that the initial concentration of CH3CO2H remains relatively unchanged.

To find the pH, we need to determine the concentration of H3O+ ions. Since CH3CO2H is a weak acid, we can approximate the concentration of H3O+ ions to be equal to the concentration of the acid that dissociates. Therefore, the concentration of H3O+ ions is approximately 2.20 M.

Using the equation pH = -log[H3O+], we can calculate the pH of the solution.

In this case,

\(pH = -log(2.20) = -log(2.20) = 0.657.\)

Therefore, the pH of the 2.20 M solution of CH3CO2H is approximately 0.657.

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Taking into account the reaction stoichiometry, 8 moles of Ag can be produced from 8 moles of AgNO₃ and 5 moles of Zn.

In first place, the balanced reaction is:

2 AgNO₃ + Zn → 2 Ag + Zn(NO₃)₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 1 mole of Zn reacts with 2 moles of AgNO₃, 5 moles of Zn reacts with how many moles of AgNO₃?

\(amount of moles of AgNO_{3}= \frac{5 moles of Znx2 moles of AgNO_{3}}{1 mole of Zn}\)

amount of moles of AgNO₃= 10 moles

But 10 moles of AgNO₃ are not available, 8 moles are available. Since you have less moles than you need to react with 5 moles of Zn, AgNO₃ will be the limiting reagent.

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 2 moles of AgNO₃ form 2 moles of Ag, 8 moles of AgNO₃ form how many moles of Ag?

\(amount of moles of Ag=\frac{8 moles of AgNO_{3}x2 moles of Ag }{2 moles of AgNO_{3}}\)

amount of moles of Ag= 8 moles

Then, 8 moles of Ag can be produced from 8 moles of AgNO₃ and 5 moles of Zn.

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Answer:

manganese, Mn

Explanation:

From the question, we have;

The number of electrons in the 3d sub level = 5

The kind of element = d-block element

On the periodic table, the elements with electrons in the 3d-sublevel in increasing order are;

Sc, 3d¹ 4s²

Ti  3d² 4s²

V  3d³ 4s²

Cr 3d⁵ 4s¹

Mn 3d⁵ 4s²

Fe 3d⁶ 4s²

Co 3d⁷ 4s²

Ni 3d⁸ 4s²

Cu 3d¹⁰ 4s¹

Zn 3d¹⁰ 4s²

The elements with 5 electrons in their 3d-sublevel are chromium Cr and manganese, Mn however the electronic configuration of chromium is given as 3d⁵ 4s¹ rather than 3d⁴ 4s² due to the minor difference in the gap of energy between the 3d and the 4s orbital as such the element that has the main characteristic of 5 electrons in its 3d sub level is manganese, Mn.

Answer:

Floating ice can insulate bodies of water. Answer: b. Discuss how a high specific heat helps to buffer temperature for organisms. Water's high specific heat is important to life because...

Explanation:

The corresponding formula equation is:

Upper Ca (upper OH) subscript 2 (s) plus 2 upper H upper Cl (l) right arrow upper Ca upper Cl subscript 2 (aq) plus 2 upper H subscript 2 upper O (l)

To obtain the word equation, we shall write out the balanced molecular equation. This is given below:

Calcium hydroxide => Ca(OH)₂

Hydrochloric => HCl

Calcium chloride => CaCl₂

Water => H₂O

Calcium hydroxide + Hydrochloric —> Calcium chloride + water

Ca(OH)₂ + HCl —> CaCl₂ + H₂O

There are 2 atoms of Cl on the right side and 1 atom on the left. It can be balance by writing 2 before HCl as shown below:

Ca(OH)₂ + 2HCl —> CaCl₂ + H₂O

There are a total of 4 atoms of H on the left side and 2 atoms on the right side. It can be balance by writing 2 before H₂O as shown below:

Ca(OH)₂ + 2HCl —> CaCl₂ + 2H₂O

Now, the equation is balanced.

Thus, the corresponding word equation is:

Upper Ca (upper OH) subscript 2 (s) plus 2 upper H upper Cl (l) right arrow upper Ca upper Cl subscript 2 (aq) plus 2 upper H subscript 2 upper O (l)

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Answer:

Upper Ca (upper OH) subscript 2 (s) plus 2 upper H upper Cl (l) right arrow upper Ca upper Cl subscript 2 (aq) plus 2 upper H subscript 2 upper O (l)

Answer:

okay

Explanation:

Coconut, palm, mangroves, water lily, water mint, are a few examples of plants whose seed are dispersed by the water.

Option C is the correct answer about the safety precautions during use of 1-Indanone i.e. none of the above option is correct.

-Indanone is a chemical compound with the formula C6H4(CH2)2CO. It's one of two isomeric benzocyclopentanones, along with 2-indanone. It is an uncolored solid. The enzyme indanol dehydrogenase uses 1-indanone as a substrate.
11H-Indeno-[1,2-b] can be synthesised using 1-Indanone.
-quinolin-10-ylamine, a potential acetylcholinesterase inhibitor for Alzheimer's disease treatment.
When using 1-Indanone, keep the following safety precautions in mind:- Wash thoroughly after handling. Wash contaminated clothing before reusing it. Use with proper ventilation. Avoid coming into contact with your eyes, skin, or clothing. Keep the container tightly shut. Ingestion and inhalation should be avoided.
Store away from incompatible substances in a cool, dry, well-ventilated area. Containers should be tightly closed.

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The compositions of the intermetallic compounds A3B and AB3 are given as percentages of element A and element B, respectively.

Another approach to identifying element B would be to perform chemical analysis on small samples of the compounds. This would involve determining the elemental composition of the samples using techniques such as X-ray fluorescence (XRF) or inductively coupled plasma mass spectrometry (ICP-MS). From the elemental composition, element B could be identified based on its position in the periodic table and its known properties. However, the compositions do not provide enough information to determine the identity of element B.

In order to identify element B, additional information is needed. One possible way to identify element B is to compare the known properties of the compounds formed by A and B. For example, if A forms a cubic structure and B forms a tetragonal structure, then element B is likely zirconium (Zr). However, without additional information, it is not possible to definitively identify element B using only the given compositions of A3B and AB3.  

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Question 19: The fusion of hydrogen releases energy because the mass of a helium nucleus is smaller than the mass of four protons.Question 20: Fusion in the core of a stable massive star cannot proceed beyond iron because it would require temperatures that even stars cannot generate.

Question 19 addresses the reason why the fusion of hydrogen releases energy. The correct statement is that the mass of a helium nucleus is smaller than the mass of four protons. This mass difference results in the release of energy during fusion reactions. In fusion, hydrogen nuclei (protons) combine to form helium nuclei, and in the process, some mass is converted into energy according to Einstein's famous equation, E=mc^2. This energy is released in the form of photons, which can be observed as light and heat.

Question 20 explains why fusion in the core of a stable massive star cannot proceed beyond iron. The correct statement is that it would require temperatures that even stars cannot generate. Fusion reactions in stars involve the fusion of lighter elements to form heavier elements, releasing energy in the process.

However, fusion reactions that produce elements heavier than iron require extremely high temperatures and pressures, which are not achievable in the core of a stable massive star. Iron has the highest binding energy per nucleon, meaning that fusion of iron nuclei would require an input of energy rather than releasing energy. As a result, fusion reactions cease beyond the formation of iron in the core of a star.

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Explanation:

Nuclear half-life expresses the time required for half of a sample to undergo radioactive decay. Exponential decay can be expressed mathematically like this:

A

(

t

)

=

A

0

⋅

(

1

2

)

t

t

1/2

(1), where

A

(

t

)

- the amount left after t years;

A

0

- the initial quantity of the substance that will undergo decay;

t

1/2

- the half-life of the decaying quantity.

So, if a problem asks you to calculate an element's half-life, it must provide information about the initial mass, the quantity left after radioactive decay, and the time it took that sample to reach its post-decay value.

Let's say you have a radioactive isotope that undergoes radioactive decay. It started from a mass of 67.0 g and it took 98 years for it to reach 0.01 g. Here's how you would determine its half-life:

Starting from (1), we know that

0.01

=

67.0

⋅

(

1

2

)

98.0

t

1/2

→

0.01

67.0

=

0.000149

=

(

1

2

)

98.0

t

1/2

98.0

t

1/2

=

log

0.5

(

0.000149

)

=

12.7

Therefore, its half-life is

t

1/2

=

98.0

12.7

=

7.72

years

.

So, the initial mass gets halved every 7.72 years.

Sometimes, if the numbers allow it, you can work backwards to determine an element's half-life. Let's say you started with 100 g and ended up with 25 g after 1,000 years.

In this case, since 25 represents 1/4th of 100, two hal-life cycles must have passed in 1,000 years, since

100.0

2

=

50.0

g

after the first

t

1/2

,

50.0

2

=

25.0

g

after another

t

1/2

.

So,

2

⋅

t

1/2

=

1000

→

t

1/2

=

1000

2

=

500

years

.

Answer: On the outside you can't spread radiation from person to person but if a person comes in contact with something radiated from the inside like urine or vomit then yes

The gas likely composed of Hydrogen

Hydrogen is one of the most abundant elements that exist in the world and its natural state is a gaseous state. This means hydrogen can be in other states such as liquid or solid if bonded with other elements but it is not its natural state.

For example:

Ice is solid and it contains both hydrogen and oxygen

Hydrochloric acid is usually liquid and it contains Chlorine and Hydrogen

Because of this, during reactions Hydrogen has a tendency to break its bonds with other elements and return to its gaseous state. Based on this, it is likely the gas in this reaction is hydrogen.

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Answer:

28atm

Explanation:

Using Gay lussac's law equation as follows:

P1/T1 = P2/T2

Where;

P1 = initial pressure (atm)

T1 = initial temperature (K)

P2 = final pressure (atm)

T2 = final temperature (K)

Based on the information provided in this question;

P1 = 30.0 atm, T1 = 30.0°C, P2 = ?, T2 = 10.0°C

NOTE: Absolute temperature i.e. Kelvin is required for this law

T1 = 30°C + 273K = 303K

T2 = 10°C + 273K = 283K

Using P1/T1 = P2/T2

30/303 = P2/283

Cross multiply

P2 × 303 = 30 × 283

303P2 = 8490

P2 = 8490/303

P2 = 28.02

New pressure of the gas = 28atm

Answer:

Because something at absolute zero would have no kinetic energy, and atoms can never stop vibrating.

Explanation:

If something were to reach absolute zero, that means that the particles would reach a position were we are able to detect precisely their velocity and position in the atom.

This cannot be possible because it would violate Heisenberg's Uncertainty Principle, which in brief states that we can measure the velocity of electron but we would be uncertain about the position and vice versa. We cannot predict both velocity and position accurately.

4(four)  electrons are represented in the Lewis electron dot structure of an element with 14 electrons and 14 protons in the neutral state

In the atom of an element, there are several levels of energy that are filled with electrons. The lowest energy level of the electrons is found in the innermost shell, while the greatest energy level is found in the outermost shell. Moving to a higher shell allows an electron to enhance its energy level, whereas moving to a lower shell causes it to reduce its energy level. It possesses an equal amount of positive and negative electric charges (the electrons) (the protons). Since of this, an atom is considered to be neutral because its overall electric charge is zero.

how many electrons are represented in the Lewis electron dot structure of an element with 14 electrons and 14 protons in the neutral state?

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