in an array vasked omplantation of a dictionary you can store key vakue pairs

Answer:

The laboratory demonstration consists of the following;

The compounds present in the combustion reaction = Methane, CH₄ and Oxygen, O₂

The chemical equation for the combustion reaction is given as follows;

CH₄ + 2O₂ → CO₂ + 2H₂O

Therefore;

A. The equation given as CH₄ + O → CO₂ is not correct because;

1) Oxygen gas exist as diatomic molecules, O₂, and given that the experiment involves the mixture of gases, the oxygen gas present which can exist as a separate compound, should be represented as O₂

2) The number of oxygen molecules in the reaction is two rather than one

3) The product also includes two molecules of water (vapor) H₂O

B. The correct equation for the reaction should be given as follows;

CH₄ + 2O₂ → CO₂ + 2H₂O

B i) The constituents of the equation is obtained by the knowledge of the fact that the combustion reaction of an organic substance such as methane in the presence of oxygen yields, carbon dioxide and water (vapor)

The equation showing the relative amounts the reacting compounds is by balancing the basic equation of the combustion of methane in the presence of oxygen

Explanation:

Answer: same concentration

Explanation:

H+ makes it more acidic, OH- makes is more basic. 7 is neutral so it has the same amount of both.

Answer: 1024 sodium ions

Explanation: The mathematical equation, N = n × NA, can be used to find the number of atoms, ions or molecules in any amount (in moles) of atoms, ions or molecules: 10 moles of helium atoms = 10 × (6.022 × 1023) = 6.022 × 1024 helium atoms. 10 moles of sodium ions = 10 × (6.022 × 1023) = 6.022 × 1024 sodium ions. (that took long)

The amount of work that has been done would be 72 Joules.

The work done by a body can be defined as the amount of energy transferred from one body to another body.  In other words, work is the product of force and the distance moved by the force.

This can be expressed mathematically as:

Work = force x distance moved by the force.

In this case:

Force = 12 newton

Distance = 6 meters

Work done = 12 x 6

                   = 72 NM or 72 Joules

In other words, if I move a 12 Newton box by 6 meters across the floor, the amount of work done would be 72 Joules.

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1. The ideal gas law is expressed as PV = nRT, where P represents pressure, V represents volume, n represents the number of moles of gas, R represents the ideal gas constant, and T represents temperature.

2. To calculate the volume in ft^3 of 101 b mol of an ideal gas at 68°F and 30 psia, we can use the ideal gas law equation. However, we need to convert the given temperature and pressure to the appropriate units. Once the conversion is done, we can substitute the values into the equation and solve for V.

3. For the gas mixture consisting of 2% N2, 79% CH4, and 19% C2H6 at 120°F and 13.8 psia, we can determine the partial pressure of each component and the volume fraction of each component. The partial pressure of a component is calculated by multiplying the total pressure by the corresponding percentage.

4. The value of the ideal gas constant R is 10.7316 (ft^3·atm)/(lb·mol·K).

1. The ideal gas law, PV = nRT, relates the pressure, volume, temperature, number of moles, and the ideal gas constant for an ideal gas.

2. To calculate the volume of 101 b mol of an ideal gas at 68°F and 30 psia, we first need to convert the temperature to Kelvin and the pressure to atm. The conversion for temperature is K = (°F + 459.67) × (5/9), and for pressure, 1 atm = 14.696 psia. Once the conversion is done, we can substitute the values into the ideal gas law equation and solve for V.

3. For the gas mixture, we can calculate the partial pressure of each component by multiplying the total pressure (13.8 psia) by the corresponding percentage (2%, 79%, and 19%). The volume fraction of each component can be obtained by dividing the volume of the component by the total volume of the mixture.

4. The value of the ideal gas constant R depends on the chosen units. To express pressure in atm, temperature in Kelvin, volume in cubic feet, and quantity in pound moles, the appropriate value for R is 10.7316 (ft^3·atm)/(lb·mol·K). This value allows for consistent units in the ideal gas law equation and ensures accurate calculations.

Please note that the provided explanations are general guidelines for solving the given problems. It is important to double-check the specific unit conversions and calculations for accurate results.

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Answer:c

Explanation: the proportions of components can vary

Answer:

lilpeep66661

Explanation:

add me i play

In some plants such as Cactuses, the stem is flattened and green and carries out the function of the leaf. Such a stem, adapted for the manufacture of food is called phylloclade. The leaves here are reduced or modified into spines to lessen the transpiring surface.

when all the electrons in an atom occupy the lowest possible energy states, the atom is said to be in its Ground state.

A quantum mechanical system's ground state is its stationary, lowest energy state; this energy is often referred to as the system's zero-point energy. Any state that has more energy than the ground state is said to be excited. The ground state is frequently referred to as the vacuum state or the vacuum in quantum field theory.

They are referred to as degenerate if they have more than one ground state. There are degenerate ground states in many systems. Degeneracy arises whenever a unitary operator exists that interacts nontrivially with a ground state and commutes with the system's Hamiltonian.

The third law of thermodynamics states that a system is in its ground state at absolute zero degrees Celsius, and that ground state's degeneracy determines the system's entropy. At absolute zero, many systems, including a flawless crystal lattice, have a singular ground state and so have zero entropy. In systems that display negative temperature, it is also conceivable for the most excited state to have absolute zero temperature.

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Among the given options, hydrogen bonds between regions of the polypeptide chain are the most critical for maintaining the native tertiary structure of a globular protein. They provide specific and directional interactions, contributing significantly to the stability of the folded protein.

The most critical factor for maintaining the native tertiary structure of a globular protein is the hydrogen bonds between regions of the polypeptide chain in the folded protein. Here's why:

1. Hydrogen bonds are formed between the electronegative atoms, typically oxygen or nitrogen, and hydrogen atoms in the protein. They contribute to the stabilization of the folded structure by providing specific and directional interactions between different regions of the polypeptide chain.

2. The hydrophobic effect, which involves the burying of non-polar residues in the protein interior, is important for stabilizing the protein's overall structure, but it does not directly contribute to maintaining the native tertiary structure.

3. Disulfide bonds between cysteine (Cys) residues can form covalent bonds and play a critical role in stabilizing the tertiary structure of some proteins, especially those found in extracellular environments. However, not all proteins have disulfide bonds, and the absence of disulfide bonds does not necessarily lead to loss of the native tertiary structure.

4. Salt bridges, also known as ionic bonds, occur between oppositely charged side chains and contribute to the stabilization of protein structure. While they can play a role in maintaining the structure, they are generally less critical compared to hydrogen bonds.

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Given that the volume remains constant, the sample of oxygen gas will have a pressure of 10.67 kPa at a temperature of -62.0°C, according to the question.

The force per unit area applied to a surface is described by the fundamental physical quantity known as pressure. It is quantified in units of force like pounds per square inch (psi) or newtons per square metre (N/\(m^2\)). In addition to measuring the amount of force delivered to an area, pressure can also be used to gauge how much work a system has accomplished.

Because a gas sample's pressure and temperature are inversely correlated, when the temperature varies, so does the gas pressure. The Ideal Gas Law, which states that P*V = n*R*T, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature, describes the relationship between pressure and temperature for a certain volume of gas.

As a result, we may modify the Ideal Gas Law equation to solve for P in order to determine the pressure at -62.0°C:

P = (n*R*T) / V

P = (n*R*(-62.0 + 273.15)) / V

P = (n*R*211.15) / V

P = (6.58 kPa * 8.314 J/K·mol * 211.15 K) / V

P = 10.67 kPa

Given that the volume remains constant, the pressure of the sample of oxygen gas will be 10.67 kPa at -62.0°C.

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Answer:

I guess 1-mole carbon dioxide contains 6.02 x 10^23 molecules.

When using silica gel or alumina, increasing the polarity of the eluent will increase the rate that a polar compound passes through the column.

Silica gel and alumina are both polar stationary phases. In chromatography, the interaction between the stationary phase and the analyte determines the retention of the analyte on the column. Polar compounds will have stronger interactions with these polar stationary phases compared to non-polar compounds.

The eluent, or mobile phase, is responsible for carrying the analyte through the column. When the polarity of the eluent is increased, it competes more effectively with polar analytes for interactions with the polar stationary phase. As a result, polar analytes are less retained and move through the column more rapidly.

In summary, increasing the polarity of the eluent in column chromatography using silica gel or alumina as stationary phases leads to a faster migration of polar compounds through the column. This occurs because the polar eluent reduces the interaction strength between the polar analyte and the polar stationary phase, allowing the analyte to move more quickly through the column.

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Answer:

The number of pounds of helium  n = 666.995 lbm

Explanation:

Given that :

the volume V = 68000 ft³

the temperature T = 80 f = (80 + 460)°R =540°R

the pressure P = 14.2 psia

Using the ideal gas equation PV =nRT to determine the number of pounds of helium within, we have :

n = PV/RT

where;

R = 2.6809 psia. ft³/lbm.R        (from the tables of A-1E for helium)

n = (14.2 × 68000)/(2.6809 × 540)

n = 965600/1447.686

n = 666.995 lbm

∴

The number of pounds of helium  n = 666.995 lbm

Answer:

The difference in velocity divided by rate = acceleration.

80 - 10 = 70km/h

60 sec. per hour, so 70 × 60 = 4,200 km/s

4.200/8=525

520/60 = 8.6666666667 km/h

Explanation:

Not the answer but hope it puts you in the neighborhood.

The resultant acceleration of the car is 2.43 m/s².

Acceleration is define as the rate of change of velocity with respect to the time and it will be calculated as:

Acceleration = Velocity / Time

Given that, velocity of car = 80km/h - 10km/h = 70km/h

As we know that 1 km = 1000m

and 1 hour = 3600 sec

So that 70km/h = 19.4 m/s

Given time = 8 sec

Now putting values on the acceleration equation, we get

Acceleration = 19.4 m/sec / 8sec = 2.43 m/s²

Hence required acceleration is 2.43 m/s².

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The new pressure be if pressure is kept constant, to compress nitrogen is 3 atm.

Boyle's law is significant because it explains how gases behave. It explains with certainty that the relationship between gas pressure and volume is inverse. So, when you exert pressure on gas, the volume decreases and its pressure increases.

P1V1 = P2V2

P1 and V1 are initial pressure and volume.

P2 and V2 are final pressure and volume.

P1 = 1 atm

V1 = 750 mL

P2 = ?

V2 = 500 mL

Putting values

2 * 750 mL = P2 * 500 mL

P2 = 3 atm

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Answer:

3.6  moles

Explanation: i got that quistion right .

1 Rolaids tablet can neutralize 235 mg of HCl, the calculations are shown in the below section.

First, we have to find the amount of acid (HCl) that is present in the stomach. It is estimated that about 0.16 M HCl is present in the stomach, which is produced by parietal cells.  It is clear that the density of HCl is similar to that of water. Hence, the density of HCl is taken as 1 g/mL. Now we need to find out the amount of HCl that is present in the solution. Let's calculate it.

Molarity = moles / volume (L)

0.155 = moles / 1 mole/1000 mL

moles = 0.155 × 1/1000 = 1.55 × 10⁻⁴ mol

Number of moles of HCl in 1000 mL of HCl solution is 1.55 × 10⁻⁴ mol.

Now let's calculate the mass of HCl in 1000 mL of the solution.

Molar mass of HCl = 36.5 g/mol mass of 1.55 × 10⁻⁴ mol of HCl = 36.5 × 1.55 × 10⁻⁴ = 0.005 m g

Volume of 1 Rolaids tablet = 20 mL

Density of Rolaids tablet = 1.6 g/mL

Mass of 1 Rolaids tablet = density × volume = 1.6 g/mL × 20 mL = 32 g

Mass of HCl neutralized by 1 Rolaids tablet is 47 times its own weight of HCl solution.

Hence, the amount of HCl neutralized by 1 Rolaids tablet is 0.005 × 47 = 0.235 g = 235 mg.

This means that 1 Rolaids tablet can neutralize 235 mg of HCl.

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A water molecule can bond to up to 3 other water molecules by hydrogen bonding.

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Answer: Mass takes into account the force of gravity.

Explanation:

Answer:

Metals react by losing electrons.  So, there is high reactivity due to lower attraction. Non-metals react by gaining electrons. So, there is high reactivity due to higher attraction.

Explanation:

Metals react by losing electrons. So, there is high reactivity due to lower attraction. Non-metals react by gaining electrons. So, there is high reactivity due to higher attraction. Also, electrons lost by metals transfer to the nonmetals. It is easier for the metals to lose their valance electrons and form cations rather than gaining electrons.

Metals do not hold on to or attract electrons while nonmetals hold on to or attract electrons.

In the periodic table, metals are found towards the left hand side of the table while nonmetals are found towards the right hand side of the table.

Electron affinity of elements increase from left to right across the period. Electron affinity refers to the ability of elements to attract or hold electrons. This ability increase steadily across the period.

Usually, the electron affinity values of nonmetals are very high showing that they easily hold on to and attract electrons while the electron affinity values of metals is very low showing that they do not easily hold on to and attract electrons.

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Synthesis reaction

It is a reaction in which 2 or more reactants combine with each other to form one product .

Check option C

Sulphate and water are combining to form sulfuric acid .

Hence option C is correct

Answer:

SO3 + H2O => H2SO4

Explanation:

I took the test :)

: PM2.5 is defined as the mass concentration of particles in the air less than or equal to 2.5 micrometers in diameter.Question 15: False, carbon dioxide (CO2) is not considered a criteria air pollutant.

Question 16: The closest answer is 50%, but the exact percentage is not provided in the question.Question 17: The term "photochemical smog" is most synonymous with ozone (O3), which is a criteria air pollutant.Question 18: True, attainment of ambient air quality standards requires that measured concentrations at all monitoring stations within an air district are below ambient air standards.

Question 14 asks about the definition of PM2.5. PM2.5 refers to particulate matter with a diameter less than or equal to 2.5 micrometers. It represents the mass concentration of particles suspended in the air, which are small enough to be inhaled into the respiratory system and can have adverse health effects.

Question 15 states whether carbon dioxide (CO2) is a criteria air pollutant. Criteria air pollutants are a set of pollutants regulated by environmental agencies due to their detrimental impact on air quality and human health. However, carbon dioxide is not considered a criteria air pollutant because it does not directly cause harm to human health or the environment in the same way as pollutants like ozone or particulate matter.

Question 16 asks about the percentage of carbon monoxide (CO) emissions from mobile sources in Santa Clara County. While the exact percentage is not provided in the question, the closest answer option is 50%. However, it is important to note that the precise percentage may vary depending on specific local conditions and emissions sources.

Question 17 inquires about the criteria air pollutant most synonymous with the term "photochemical smog." Photochemical smog is primarily associated with high levels of ground-level ozone (O3). Ozone is formed when nitrogen oxides (NOx) and volatile organic compounds (VOCs) react in the presence of sunlight, creating a hazy and polluted atmospheric condition.

Question 18 addresses the concept of "attainment" of ambient air quality standards. To achieve attainment, measured concentrations of pollutants at all monitoring stations within an air district must be below the established ambient air quality standards. This ensures that the air quality in the given area meets the required standards for protecting human health and the environment.

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The gas given off at the cathode is hydrogen while the gas given off at the anode is oxygen.

The term electrolysis has to do with the decomposition of a substance by the passage of direct current through it.

The ions present in the system are H^+, OH^- and NO3^- ions. The gas given off at the cathode is hydrogen while the gas given off at the anode is oxygen.

The half reaction equation of the reduction is;

2H^+(aq) + e ----->H2(g)

The oxidation half reaction equation is;

4OH^- (aq)------> 2H2O(l) + 4e

The overall equation is;

4H^+(aq) + 4OH^- (aq)------> 4H2(g) + 2H2O(l) + 4e

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Al2 (SO4)3 + H2 + H2SOy 2 Al mass = 1.105 g,

2 Al molar mass = 26.98 g/mol,

and 2 Al moles = 1.105 / 26.98 = 0.041 moles.

KOH concentration is 1.4 M.

KOH's volume is 52.2 mL, or 0.0522 L, and its moles are 1.4 x 0.0522, or 0.07308 moles.

2Al + 2 KOH + 4 H2SO4 + 22H2O2KAI concentration of H2SO4 = 9.0 M volume of H2SOy = 21.8 ml = 0.0218 L moles of H2SO4 = 9.0 X 0.0218 = 0.1962 moles (SO4).

Aluminum contains the fewest number of moles, 12 H2O + 3 H2.

Reagent is constrained by aluminum.

A 2 mole Al creates a 3 mole H2 from the aforementioned reaction. In other words, 0.041 moles of Al generate 0.041 x 1.5 moles of H2, or 0.0615 moles of H2.

H2 quantity equals moles times molar mass.

= 0.0615 x 2g

Amount of H₂ produced = 0.123g

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Answer: check out the image

Explanation: check out the image

The substance in the image above would be classified as a mixture of elements (option E).

A compound is a substance formed by chemical bonding of two or more elements in definite proportions by weight.

On the other hand, a mixture is made when two or more substances are combined, but they are not combined chemically.

According to this question, an image is shown with two different substances or elements as distinguished by coloration (white and purple). These elements are combined but not chemically bonded, hence, is a mixture.

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