In a bell-shaped curve, the x-axis (horizontal direction) of the graph represents which of the following

The magnitude of the electrostatic force exerted on an electron by another electron when they are 0.10 meter apart is 2.31 x 10^-28 Newtons.

The electrostatic force between two charged particles can be calculated using Coulomb's law. Coulomb's law states that the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

In this case, both electrons have the same charge, which is the elementary charge denoted as e. The magnitude of the charge of each electron is 1.60 x 10^-19 Coulombs. Using Coulomb's law and substituting the values, we can calculate the magnitude of the electrostatic force.

The calculated value, 2.31 x 10^-28 Newtons, represents the magnitude of the electrostatic force between the two electrons when they are 0.10 meter apart. It signifies the strength of the repulsive force between the negatively charged electrons due to their electrostatic interaction.

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The refrigerator is removing 300 watts of heat every hour.

Energy can only be changed in form; it cannot be created or destroyed, according to the basic law of thermodynamics. For any system, energy transfer examples include mass crossing the control boundary, external work, or heat transfer across the barrier. These have an impact on the energy reserves of the control volume.

The rate of heat removal from within the refrigerator may be calculated using the formula below thanks to the First Law of Thermodynamics and the definition of a refrigeration cycle.

Rate of heat transfer to the space, measured in watts.

Q=800 W W=500

The refrigerator removes heat at a rate of (800-500) 300 watts per hour.

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To achieve an outlet temperature of 125°C, needed a heat flux of 6919 W/m².

To solve this problem, we need to use the energy balance equation, which relates the heat transfer rate, mass flow rate, specific heat capacity, and temperature difference.

Q = mdot × cp × (Tout - Tin)

Where,

Q = heat transfer rate (W)

mdot = mass flow rate (kg/s)

cp = specific heat capacity of air (J/kg.K)

Tout = outlet temperature (K)

Tin = inlet temperature (K)

We can assume that the air is incompressible, and thus the specific heat capacity of air at constant pressure (cp) can be taken as a constant value of 1005 J/kg.K.

Next, we can use the Reynolds number to determine the flow regime in the tube.

Re = (ρ × D × V) / μ

Where,

ρ = density of air (kg/m³)

D = diameter of the tube (m)

V = velocity of air (m/s)

μ  = viscosity of air (Pa.s)

Assuming atmospheric pressure and using the properties of air at 20°C, we get:

ρ = 1.2041 kg/m³ and μ = 1.81 x 10^-5 Pa.s

Re = (1.2041 kg/m³ × 0.05 m × (0.005 kg/s / (π×(0.025 m)² / 4))) / (1.81 x 10^-5 Pa.s) = 26197

Since the Reynolds number is greater than 4000, we can assume that the flow is turbulent and fully developed.

Next, we can use the Dittus-Boelter equation to calculate the heat transfer coefficient (h).

ν = 0.023 × Re^(4/5) × Pr^(0.4)

Where,

Pr = Prandtl number of air (unitless)

Pr = (cp × μ) / k, where k is thermal conductivity of air at 20°C, k=0.0263 W/m.K

Pr = (1005 J/kg.K × 1.81 x 10^-5 Pa.s) / 0.0263 W/m.K = 0.706

ν = 0.023 × (26197)^(4/5) × (0.706)^(0.4) = 119.23

h = (ν × k) / D = (119.23 × 0.0263 W/m.K) / 0.05 m = 62.25 W/m².K

Now we can calculate the required heat flux using the energy balance equation.

Q = mdot × cp × (Tout - Tin) = h × pi × D × (Tout - Tin)

We can rearrange the equation to get the heat flux (q).

q = Q / (π × D × (Tout - Tin)) = h × (Tout - Tin)

Substituting the values, we get:

q = 62.25 W/m².K × (125°C - 20°C) = 6919 W/m²

Therefore, to achieve an outlet temperature of 125°C, we need a heat flux of 6919 W/m².

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Answer:

3 miles

Explanation:

5 + 2 - 2 - 2 = 3 miles

Explanation:

what is the answer

Answer:

(x +1), (x -5) and (x +1)

Explanation:

The computation of the factorization is shown below

Data provided in the question

\(X^3 - 3x^2 - 9x - 5\)

Based on the above information, the factors are

Now we have to open these equations in order to get the factors which are as follows

\(= x^3 + x^2 - 4x^2 - 4x - 5x - 5\)

\(= x^2( x + 1) - 4x ( x + 1) - 5(x + 1)\)

\(= (x + 1) (x^2 - 4x - 5)\)

\(= (x + 1)(x^2 -5x + x - 5)\)

So,

= (x + 1) (x - 5) (x + 1)

Therefore the (x +1), (x -5) and (x +1) are the factors of the mention polynomial give in the question

The question addresses the stability of the atmosphere and the factors that determine convective stability or instability. It also explains the difference between the adiabatic lapse rate of dry air and wet saturated air.

a) The stability of the atmosphere is determined by the temperature profile and relative densities of the air cell and atmosphere. If the temperature of the surrounding atmosphere decreases with altitude at a rate greater than the adiabatic lapse rate of the air cell, the atmosphere is considered convectively stable.

In this case, the air cell will return to its original position. Conversely, if the temperature of the surrounding atmosphere decreases slower than the adiabatic lapse rate of the air cell, the atmosphere is convectively unstable. The air cell will continue moving in the same direction.

b) The adiabatic lapse rate refers to the rate at which temperature decreases with altitude for a parcel of air lifted or descending adiabatically (without exchanging heat with its surroundings). The adiabatic lapse rate of dry air is higher (around \(9.8^0C\) per kilometer) compared to the adiabatic lapse rate of wet saturated air (around 5°C per kilometer).

This difference arises because when water vapor condenses during the ascent of saturated air, latent heat is released, reducing the rate of temperature decrease. A diagram can illustrate the difference between the two lapse rates, showcasing their respective slopes.

c) When wet unsaturated air rises from the ocean surface, its temperature decreases at a rate equal to the dry adiabatic lapse rate. However, if the ambient lapse rate (temperature decrease with altitude) is higher than the adiabatic lapse rate for dry air, a temperature inversion layer forms at higher altitudes.

In this inversion layer, the temperature increases with altitude instead of decreasing. A schematic diagram can depict the temperature changes of the wet air in comparison to the ambient temperature, showing the inversion layer.

Cumulus clouds form at the altitude where the rising moist air reaches the level of the temperature inversion layer. These clouds are formed due to the condensation of water vapor as the air parcel cools to its dew point temperature.

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Answer:

A fish that lives near the surface of the ocean most likely has a swim bladder (or body cavity) that is full of oxygen

Explanation:

The swim bladder is the organ present in the majority of bony fishes that provides buoyancy. The swim bladder is a bladder filled with oxygen and found in the in the body of the fish

The function of the swim bladder is to provide adequate ballast or hydrostatic balance to enable a fish to keep to a certain depth in a body of water thereby the fish does not float to the surface or sinks further

The swim bladder is also used as a sound communicating organ.

The shape of a defined region in a random dot kinematogram is detected by manipulating the coherence of the dots within that region, which makes the motion of the dots more perceptually salient and allows the shape to be more easily detected.

In a random dot kinematogram, the shape of a defined region is detected by its motion. This is because a random dot kinematogram is a visual display consisting of randomly moving dots that can be manipulated to create a variety of stimuli. These stimuli can be used to study various aspects of visual perception, including motion perception, object recognition, and spatial attention.

To detect the shape of a defined region in a random dot kinematogram, researchers typically use a technique called "coherence manipulation". This involves manipulating the percentage of dots that move in a defined direction within a specific region of the display. By increasing the coherence of the dots within the defined region, the motion of the dots becomes more perceptually salient, allowing the shape of the region to be more easily detected.

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Explanation:

I think it will increase a little bit ... just image ... if the temperature is 0, the velocity will be 0 too. because the vibration of atom is so weak and the sound cant progation.

Answer:

The velocity will increase.

Explanation:

Wave velocity and the temperature of the medium are directly proportional so if the temperature increases, the velocity will increase.

This question involves the concept of Ohm's Law.

Circuit "A(TOP-LEFT), C(BOTTOM-LEFT), D (BOTTOM-RIGHT)" correctly shows Ohm's Law.

Therefore circuit B (top-right) does not correctly show ohm's law.

Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points.

According to Ohm's Law:

V = IR

where V = Voltage

I = Current

R = Resistance

We will then apply this  rule to every circuit to check its validity:

CIRCUIT 'A' (TOP-LEFT), CIRCUIT 'B' (TOP-RIGHT) and CIRCUIT 'C' (BOTTOM-LEFT): validly follows ohms law while  circuit B (top-right) do not follow ohms law.

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Answer:

The term referring to is radioactive decay.

To answer the question, we need to know the half-life of the radioactive material. Let's assume the half-life is 10,000 counts.

After one half-life, the count would be halved to 40,000 counts. After the second half-life, the count would be halved again to 20,000 counts. After the third half-life, the count would be halved again to 10,000 counts. And after the fourth half-life, the count would be halved again to 5,000 counts.

So after 4 half-lives, we would expect the count to be 5,000.

After 4 half-lives, the remaining number of counts would be calculated by dividing the initial number of counts by 2 raised to the power of the number of half-lives. In this case:

Initial counts: 80,000

Number of half-lives: 4

Remaining counts = 80,000 / (2^4) = 80,000 / 16 = 5,000 countsSo, after 4 half-lives, you would expect to have 5,000 counts remaining.

Answer:

The term referring to is radioactive decay.

To answer the question, we need to know the half-life of the radioactive material. Let's assume the half-life is 10,000 counts.

After one half-life, the count would be halved to 40,000 counts. After the second half-life, the count would be halved again to 20,000 counts. After the third half-life, the count would be halved again to 10,000 counts. And after the fourth half-life, the count would be halved again to 5,000 counts.

So after 4 half-lives, we would expect the count to be 5,000.

After 4 half-lives, the remaining number of counts would be calculated by dividing the initial number of counts by 2 raised to the power of the number of half-lives. In this case:

Initial counts: 80,000

Number of half-lives: 4

Remaining counts = 80,000 / (2^4) = 80,000 / 16 = 5,000 countsSo, after 4 half-lives, you would expect to have 5,000 counts remaining.

Explanation:

Therefore, based on the estimated duration of a galactic year, Earth has been around for approximately 18.4 to 20.4 galactic ye

A "galactic year" refers to the time it takes for our solar system to complete one orbit around the Milky Way galaxy. The exact duration of a galactic year is not precisely determined due to various factors, such as the varying speeds of stars within the galaxy. However, it is estimated to be roughly 225-250 million years.

To calculate the number of galactic years Earth has been around based on the age of the solar system (4.6 billion years), we can divide the age of the solar system by the estimated duration of a galactic year:

Number of Galactic Years = Age of the Solar System ÷ Duration of a Galactic Year

Number of Galactic Years = 4.6 billion years ÷ 225-250 million years

Number of Galactic Years ≈ 18.4 to 20.4 galactic years

Therefore, based on the estimated duration of a galactic year, Earth has been around for approximately 18.4 to 20.4 galactic years.

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The beat frequency produced when a 240 Hz tuning fork and a 246 Hz tuning fork are sounded together is 6 Hz. This corresponds to option d) 6 hertz.

When two tuning forks with slightly different frequencies are sounded together, they produce a beat frequency. The beat frequency is the result of the interference between the two waves produced by the tuning forks.

In this case, we have a 240 Hz tuning fork and a 246 Hz tuning fork. To find the beat frequency, we need to calculate the difference between the frequencies of these two tuning forks:

Beat frequency = |Frequency1 - Frequency2|
Beat frequency = |240 Hz - 246 Hz|
Beat frequency = |-6 Hz|

Since frequency cannot be negative, we take the absolute value of the result:

Beat frequency = 6 Hz

So, the beat frequency produced when a 240 Hz tuning fork and a 246 Hz tuning fork are sounded together is 6 Hz. This corresponds to option d) 6 hertz.

In summary, the beat frequency is the difference between the frequencies of two tuning forks sounded together. In this case, with a 240 Hz and a 246 Hz tuning fork, the beat frequency is 6 Hz.

The complete question is:

The beat frequency produced when a 240 hertz tuning fork and a 246 hertz tuning fork are sounded together is

a) 245 hertz

b) 240 hertz

c) 12 hertz

d) 6 hertz

e) none of the above

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The directions of the pulses can be determined by examining the variables in the equations.

In the equation y₁ = 5 / [ (3x - 4t)²+ 2 ], the term (3x - 4t) represents the motion of the pulse. The presence of a positive sign indicates that the pulse travels in the positive x-direction.

In the equation y₂ = -5 / [ (3x + 4t - 6)² + 2 ], the term (3x + 4t - 6) represents the motion of the pulse. Here, the presence of a negative sign indicates that the pulse travels in the negative x-direction.

To summarize:

- The pulse described by y₁ travels in the positive x-direction.
- The pulse described by y₂ travels in the negative x-direction.

By examining the signs and analyzing the terms in the equations, we can determine the directions of the pulses on the same string.

Remember to always consider the signs and variables when determining the direction of a pulse or wave.

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Answer:

A. B. Pls Give Branliest

Explanation:

Answer:

My answer got deleted.. all my brainliests too

Explanation:

A for the first, B for second.

Answer:

a) Check the file attached below for the diagram

b) Change in velocity vector between F and G,  \(\overrightarrow{\triangle V} = \overrightarrow{V_G}\)

Explanation:

a) The diagram that represents the description is contained in the file attached to this solution. A vector, \(V_G\) that represents the velocity of the object at point G is also indicated.

A very good point to note is that the direction of the velocity is always acting tangent to the path

b) The change in velocity vector between F and G

The change in velocity vector is \(\overrightarrow{\triangle V} = \overrightarrow{V_G} - \overrightarrow{V_F}\)

Since the object starts from rest at point F, \(\overrightarrow{V_F} = 0\)

Therefore, Change in velocity vector between F and G, \(\overrightarrow{\triangle V} = \overrightarrow{V_G}\)

Option Z is correct. The stainless steel container was likely the hottest. Stainless steel is an excellent heat conductor because it quickly warms the substance.

Stainless steel is an excellent heat conductor because it quickly warms the substance or allows heat to travel through it. Stainless steel is also corrosion-resistant.

Foam, glass, and plastic, on the other hand, are all poor heat and electrical conductors. As a result, they do not allow heat to travel through.

As a result, we may deduce that, among the available possibilities, the stainless steel container was most likely the hottest.

Hence Option Z is correct. The stainless steel container was likely the hottest.

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The skater's final angular speed is equal to 12 rad/s.

When implemented to angular momentum, the regulation of conservation means that the momentum of a rotating item is no longer exchanged until some form of external torque is carried out. Torque, in this sense, can check with any outside pressure that acts upon the object for the purpose to twist or rotate.

The law of conservation of angular momentum states that once no external torque acts on an item, no trade of angular momentum will occur. The angular momentum of a machine is conserved as long as there may be no net external torque performing on the machine.

In angular kinematics, the conservation of angular momentum refers back to the tendency of a device to keep its rotational momentum inside the absence of outside torque. For a round orbit, the system for angular momentum is (mass) ×(pace) ×(radius of the circle): (angular momentum) = m × v × r.

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A child on a merry-go-round both revolves and rotates around the merry-go-round's axis.

Rotation refers to the circular movement of an object around its own axis. In this case, the merry-go-round itself is rotating around its axis as it spins, and so is the child, who is sitting on the merry-go-round. Therefore, the child rotates around the merry-go-round's axis.

Revolution refers to the circular motion of an object around another object or point. In this case, the child is also revolving around the merry-go-round's axis as the merry-go-round spins. This motion can be described as a combination of rotation and translation, as the child is moving around the axis while also moving in a circle with the merry-go-round.

Overall, the motion of a child on a merry-go-round involves both rotation and revolution around the merry-go-round's axis.

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Answer:

Object X reflects yellow and object Y reflects none.

Explanation:

We are able to see the colors of different objects because the light rays falling on the surface of an object reflects back few or none of the colors to our eyes. We see the color that is reflected back to our eyes.

In the context, Marcy has two objects, X and Y. We see that object X is yellow in color because as the light rays falls on the object X, it absorbs all the colors of the spectrum and reflects the color yellow back to our eyes. So we can see that the object X is yellow.

Similarly, when spectrum light falls on the surface of the object Y, it absorbs all light in its body and reflects none of its colors. So the object Y appears to be black to our eyes.

The height of the cannon where the objects are launched from is 18 feet.

The canons of page construction are historical reconstructions, based on careful measurement of extant books and what is known of the mathematics and engineering methods of the time, of manuscript-framework methods that may have been used in Medieval- or Renaissance-era book design to divide a page into pleasing proportions. Since their popularization in the 20th century, these canons have influenced modern-day book design in the ways that page proportions, margins and type areas (print spaces) of books are constructed.

To determine the height of the cannon where the objects are launched from, we need to find the value of "h" when "t" is equal to zero.

Given the equation: h = (-1/5)×t^2 + 5×(t) + 18

Substituting t = 0 into the equation, we have:

h = (-1/5)×(0)^2 + 5(0) + 18

= 0 + 0 + 18

= 18

Therefore, the height of the cannon where the objects are launched from is 18 feet.

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The electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.

To find the electric field strength at a distance 1.20 m on the x-axis, we can use Coulomb's law:

\($$F=k\frac{q_1q_2}{r^2}$$\)

where F is the force between two charges, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is the Coulomb constant.For a single point charge q located at the origin of the x-axis, the electric field E at a distance r is given by:

\($$E=\frac{kq}{r^2}$$\)  where k is the Coulomb constant.

So, let's calculate the electric field due to each charge separately and then add them up:

For the +2.0 C charge at x = 0, the electric field at a distance of 1.20 m is:\($$E_1=\frac{kq_1}{r^2}=\frac{(9\times10^9)(2.0)}{(1.2)^2}N/C$$\)

For the -3.0 C charge at x = 0.40 m, the electric field at a distance of 1.20 m is:

\($$E_2=\frac{kq_2}{r^2}\)

\(=\frac{(9\times10^9)(-3.0)}{(1.20-0.40)^2}N/C$$\)

The negative sign indicates that the direction of the electric field is opposite to that of the positive charge at x = 0.

To find the net electric field, we add the two electric fields\(:$$E_{net}=E_1+E_2$$\)

Substituting the values of E1 and E2:

\($$E_{net}=\frac{(9\times10^9)(2.0)}{(1.2)^2}-\frac{(9\times10^9)(3.0)}{(0.8)^2}N/C$$E\)

net comes out to be -1.5×10⁴ N/C.

Therefore, the electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.

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Due to the uniform distribution of leaves, folivores rarely exhibit dominance hierarchies.

A dominance hierarchy is a type of social hierarchy that arises when members of a social group interact, to create a ranking system. In social living groups, members are likely to compete for access to limited resources and mating opportunities. Rather than fighting each time they meet, relative rank is established between members of the same se x. Based on repetitive interactions a social order is created that is subject to change each time a dominant animal is challenged by a subordinate one. This hierarchical structure can be observed in many species, including humans.

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