Imagine you derive the following expression by analyzing the physics of a particular system: M= (mv2r)(mGr2). Simplify the expression for M using the techniques mentioned above.

Answers

Answer 1

Answer:

The simplified expression is \(M = \frac{v^2 r}{G}\)

Explanation:

From the question we are told that  

     \(M = \frac{ \frac{m v^2}{r} }{\frac{ mG}{r^2 } }\)

So simplifying we have

    \(M = \frac{m v^2}{r} * \frac{r^2 }{ mG }\)

    \(M = \frac{v^2 r}{G}\)

Thus the simplified formula is \(M = \frac{v^2 r}{G}\)


Related Questions

The Jamaican Bobsled Team is sliding down a hill in a toboggan at a rate of 5 m/s when he reaches an even steeper slope. If he accelerates at 2 m/s2 for the 5 m slope, how fast is he traveling when he reaches the bottom of the 5 m slope?

Answers

Answer:

6.71 m/s

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 5 m/s

Acceleration (a) = 2 m/s²

Distance (s) = 5 m

Final velocity (v) =.?

The final velocity at the bottom of the slope can be obtained as shown below:

v² = u² + 2as

v² = 5² + (2 × 2 ×5)

v² = 25 + 20

v² = 45

Take the square root of both side

v = √45

v = 6.71 m/s

Thus, the velocity of the Jamaican Bobsled Team when he reached the bottom of the slope is 6.71 m/s

What are the rock forming minerals and its meaning.

Answers

Answer:

There are almost 5000 known mineral species, yet the vast majority of rocks are formed from combinations of a few common minerals, referred to as “rock-forming minerals”.

Any mineral that forms igneous, sedimentary, or metamorphic rocks and that typically, or solely, forms as an intimate part of rock-making processes.

If an irregularly shaped object (such as a wrench) is dropped from rest in a classroom and feels no air resistance, it will If an irregularly shaped object (such as a wrench) is dropped from rest in a classroom and feels no air resistance, it will accelerate and turn about its center of gravity with uniform angular speed. accelerate and turn about its center of gravity with uniform angular acceleration. accelerate and turn until its center of gravity reaches its lowest point. accelerate and spin until its center of gravity reaches its highest point. accelerate but will not spin.

Answers

Answer:

It accelerate but will not spin.

Explanation:

If an irregular shaped object is dropped from rest without feeling any form of air resistance it will accelerate without spinning and this is due to the fact that there is no Torque around  the center of gravity

A race car traveling at 100 m/s enters an unbanked turn of 400 m radius. The coefficient of (static) friction between the tires and the track is 1.1. The track has both an inner and an outer wall. Which statement is correct

Answers

Answer:

The race car will crash into the outer wall

Explanation:

max fr = μsN = 1.1 mg = 11 m

mv2/R = m(100)2/(400) = 25 m > fr

Vhat are you looking for when you research a potential employer?
personal information about the managers
company history
related industry news
what its product or service is

Answers

B because I had it before

TRUE/FALSE, the scientific question is written like “I wonder if [dependent variable] is affected by [independent variable].”

Answers

True as the independent variable is over the dependent variable and controls it as the dependent relies on the independent.

if it took her 2.7 seconds to lift the lawnmower, how much power did she output

Answers

Answer:

N/A

Explanation:

The following formula can be used to compute the power output of a person lifting a lawnmower:

Work (W) / Time (t) = Power (P).

Where:

Work (W) is defined as the force used to lift the lawnmower multiplied by the distance traveled (i.e., work done against gravity).

Time (t) is the amount of time it takes to lift the lawnmower.

To determine the power output, however, we would need to know the force used to lift the lawnmower as well as the distance it was lifted. We won't be able to provide an accurate power output value without this information.

Suppose there are 3 molecules in a container. If each molecule has a 1-in-2 chance of being in the left half of the container, what is the probability that there are exactly 2 molecules in the left half of the container?

Answers

Answer:

Total probability = 3/8

Explanation:

Below is the calculation:

Number of molecules in the container = 3

The probability of one molecule in the left half, P = 3 / 2 = 1.5 or 1/2

The probability of second molecule in the left half, P1 = (3/4)

Total probability = P x P1

Total probability = (1/2) x (3/4)

Total probability = 3/8

Help pleaseeeeeeeeeeeee

Help pleaseeeeeeeeeeeee

Answers

A it’s not that hard tbh

The half life of a radioactive element is 2000 hours. Approximately how much time is required for
the decay of 2/3 of its nuclei?

Answers

Approximately 4300 hours is required for the decay of 2/3 of its nuclei.

Radioactive decay is the random process by which the nuclei of radioactive substances disintegrate into smaller particles. The time taken for half of the radioactive nuclei in a substance to decay is known as the half-life of the substance. In the following paragraphs, I'll explain how to calculate how much time is required for the decay of 2/3 of its nuclei if the half-life of a radioactive element is 2000 hours.The half-life of a radioactive element is the time it takes for half of its original nuclei to decay. The quantity of the substance that has decayed by half of its original quantity is called the half-life. If the half-life of a substance is T, the fraction of the original amount of the substance that remains after a time t is given by the equation:N(t) = N₀(1/2)^(t/T),Where N₀ is the initial number of radioactive nuclei and N(t) is the number of radioactive nuclei remaining after a time t. If we want to know the time it takes for two-thirds of the nuclei to decay, we must solve for t when N(t)/N₀ = 1/3. Putting this into the equation, we have:(1/3)N₀ = N₀(1/2)^(t/T).Simplifying this equation, we get:(1/2)^(t/T) = 1/3.Dividing both sides of the equation by (1/2)^(2000/T), we get:(1/3)/(1/2)^(2000/T) = (1/2)^(t/T - 2000/T).Taking the logarithm of both sides, we get:(t/T - 2000/T)log(1/2) = log(1/3).Simplifying this equation, we get:t/T = -log(1/3)/log(1/2) + 2000/T.To get an approximate solution to this equation, we can make use of the fact that the half-life of a substance is much smaller than the time it takes for most of its nuclei to decay. Therefore, the quantity 2000/T is much larger than one. This allows us to neglect the second term on the right-hand side of the equation. Then we have:t/T = 2.15.Substituting the value of T as 2000 hours, we get:t = 4300 hours.

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If the mass = 1.50 kg, F1 = 1.50 N, 0, = 35.0°, 02 = 45.00 and the acceleration of the object in the + x direction is 1.0 m/s?, what must be the force F2? (Shown in image)

If the mass = 1.50 kg, F1 = 1.50 N, 0, = 35.0, 02 = 45.00 and the acceleration of the object in the +

Answers

The magnitude of force F₂ is determined as 0.38 N.

What is the magnitude of F₂?

The magnitude of force (F₂) is calculated by applying Newton's second law of motion as follows;

F = ma

where;

F is the resultant of the two forcem is the mass of the objecta is the acceleration of the object

The resultant forces in the x-direction is given as

F₁cosθ₁  +  F₂cosθ₂ = maₓ

(1.5 cos35) + F₂(cos45) = 1.5 x 1

1.23 + 0.71F₂ = 1.5

0.71F₂ = 1.5 - 1.23

0.71F₂ = 0.27

F₂ = 0.27/0.71

F₂ = 0.38 N

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Give an example of each type of electromagnetic radiation.

Answers

Answer:

Nearly all frequencies and wavelengths of electromagnetic radiation can be used for spectroscopy. Radio waves, infrared rays, visible light, ultraviolet rays, X-rays, and gamma rays are all types of electromagnetic radiation. Radio waves have the longest wavelength, and gamma rays have the shortest wavelength.

Explanation:

A skier of mass 82.9 kg starts from rest at the top of a frictionless incline of height 20 m. At the bottom of the incline, the skier encounters a horizontal surface. The skier travels on the horizontal surface a distance of 95.2 meters before coming to a rest. What is the magnitude of the (constant) friction force (in N) that the rough horizontal surface exerts on the skier

Answers

Answer: 170.67 N

Explanation:

Given

Mass of skier is \(m=82.9\ kg\)

Height of the inclination is \(h=20\ m\)

Here, the potential energy of the skier is converted into kinetic energy which is consumed by the friction force by applying a constant force that does work to stop the skier.

\(\Rightarrow mgh=F\cdot x\quad \quad [\text{F=constant friction force}]\\\\\Rightarrow 82.9\times 9.8\times 20=F\cdot 95.2\\\\\Rightarrow F=\dfrac{16,248.4}{95.2}\\\\\Rightarrow F=170.67\ N\)

Thus, the horizontal friction force is 170.67 N.

When an object is in circular motion it is constantly changing its velocity.

Answers

Its tangential speed is constant although its velocity is changing. As the object changes direction, it results in a changing of positive and negative signs of the velocity. Although, the magnitude of the velocity (speed) is not changing.

The way in which one atom interacts with another atom is mostly influenced by the configuration of the
A. electrons farthest from the nucleus.
B. protons in the center of the nucleus.
C. electrons closest to the nucleus.
D. protons on the outer edge of the nucleus.

Answers

The way in which one atom interacts with another atom is mostly influenced by the configuration of the electrons farthest from the nucleus.

Option A.

What is atom?

An atom can be defined as the smallest part of a substance that cannot be broken down chemically. Each atom has a nucleus (center) made up of protons (positive particles) and neutrons (particles with no charge).

The arrangement of electrons in orbitals and shells around the nucleus is referred to as the electronic configuration of the atom.

Thus, we can conclude that the way in which one atom interacts with another atom is mostly influenced by the configuration of the electrons farthest from the nucleus.

The remaining options do not fit the empty space properly, and they include;

protons in the center of the nucleus.electrons closest to the nucleus.protons on the outer edge of the nucleus.

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Identify three main ideas about models

Answers

Answer:

Approaches mathematical learning through inquiry

-Explore real contexts, problems, situations, and models

-Learning through doing shifts the focus on the students

-Problems have multiple entry and exit points

-Links to other disciplines

Explanation:

quizlet

what volume of silver metal have a mass of 2500.0 grams?​

Answers

Answer:

238 cm3

Explanation:

You take the formula for volume, V = 2500.0 g/10.5 g/cm3 = 238.095 = 238 cm3. The answer is rounded to 3 significant figures.

It's important to match your exercise shoes with the type of exercise in which you will be participating, Please select the best answer from the choices provided OT​

Answers

Answer:

the answer is true

Explanation:

A runner is moving at a speed of 20 m/s. How much distance would they cover in 10 seconds?

Answers

Answer:

200 meters

Explanation:

20 x 10 = 200

200meter down is the correct answer

A projectile is fired straight up with an initial velocity of 40.0 m/s . Approximately how high will the projectile ?

Answers

Answer:

it depends on the wind and any other conditions but if you have a controlled environment it should take 1 second to get 40 meters but it could go higher in which it could take about 5 seconds to go 200 meters

Explanation:

hope it helped

:)

Two adjacent students stand on stationary skateboards, face each other, and
push apart. The skateboarder on the left weighs 55 kg, the one on the right is
65 kg. If the lighter skateboarder moves at 4.2 m/s, determine the speed and
direction of the heavier skateboarder.

Answers

so the heavy skateboarder will move off with speed 2.45 m/s in the opposite direction

Forgetting takes place only in short-term memory. Please select the best answer from the choices provided T F

Answers

Answer:

false

Explanation:

Answer:

false

Explanation:

edge

Calculate the quantity of heat energy which must be transferred to 2.25 kg of brass to raise its temperature from 20°C to 240°C if the specific heat of brass is 394 J/kgK.

Answers

The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

How do i determine the quantity of heat energy?

First, we shall list out the given parameters from the question. This is shown below:

Mass of brass (M) = 2.25 Kg Initial temperature of brass (T₁) = 20 °CFinal temperature of brass (T₂) = 240 °CChange in temperature of brass (ΔT) = 240 - 20 = 220 °CSpecific heat capacity of brass (C) = 394 J/kgKQuantity of heat energy (Q) =?

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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what does it mean that cobalt -60 has a half-life of 5.27 years?

Answers

The statement that cobalt-60 has a half-life of 5.27 years means that it takes approximately 5.27 years for half of the initial quantity of cobalt-60 to decay.

What is half-life?

Cobalt-60 is a radioactive isotope of cobalt, meaning it undergoes radioactive decay over time. During this process, the unstable atomic nucleus of cobalt-60 spontaneously emits radiation and transforms into a different element.

The half-life is the time it takes for half of the radioactive material to decay.

In the case of cobalt-60, if you start with a certain amount of cobalt-60, after 5.27 years, approximately half of it will have decayed into another element, while the remaining half will still be cobalt-60. After another 5.27 years, half of the remaining cobalt-60 will decay, and the process continues.

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Rank the six combinations of electric charges on the basis of the electric force acting on q1.

a.
q1 = -1nC
q2= +1nC
q3= +1nC

b.
q1 = -1nC
q2= -1nC
q3= -1nC

c.
q1 = +1nC
q2= +1nC
q3= -1nC

d.
q1 = +1nC
q2= -1nC
q3= +1nC

Answers

The anwser for this question would be D. Q1 = +1nC , Rank the six combinations of the electric charges on the basis of the electric force acting on q1.

Introduction to Forces
Warm-Up Active
How do forces affect the motion of an object?

Answers

Answer:

Forces can affect an object.

Balanced forces allow an object to continue moving at a constant motion (law of inertia).

Unbalanced forces cause a change in motion.

Answer:

Because of my physics teacher I would put this entire explanation below if i were u

Explanation:

Forces affect how objects move. They may cause motion; they may also slow, stop, or change the direction of motion of an object that is already moving.

Since force cause changes in the speed or direction of an object, we can say that forces cause changes in velocity. Remember that acceleration is a change in velocity. So forces cause acceleration.

which phase of the moon is above the horizon during the day, but the most difficult to see? group of answer choices full moon waning half new moon first quarter

Answers

We can't see the moon in the new moon since the sun is quite far from the earth.

What is the moon?

We know the moon to be one of the heavenly bodies. The heavenly bodies are those bodies that we tend to see in the outer space. There are several heavenly bodies that we have out there and they can be classified based on weather or not the bodies do produce light.

The heavenly bodies that produce light as said to be luminous bodies while the heavenly bodies that do not produce light are said to be non luminous bodies.

Now we can see that the moon s a non luminous body and it depends on the sun so as to be able to give light. In this case, we know that the moon may sometimes be hidden from sight and can not be seen and this  occurs in the course of the new moon because the side of the moon that gets the light lies at a far away position  from the earth.

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Một chất điểm chuyển động trong mặt phẳng Oxy với phương trình :
{ = 2 + 10

Answers

Answer:

plz write your questions in English

How do the frequencies and the speeds of yellow light and blue light compare?

Answers

Answer: The frequency of yellow light is greater that blue light

Explanation: Hope this helps :)

A 2.5 kg block is initially at rest on a horizontal surface.A horizontal force of magnitude 6.0 N and a vertical force are
then applied to the block (Fig. 6-17).The coefficients of friction for
the block and surface are ms " 0.40 and mk " 0.25. Determine the
magnitude of the frictional force acting on the block if the magnitude
of is (a) 8.0 N, (b) 10 N, and (c) 12 N.

Answers

To solve this problem, we need to determine the frictional force acting on the block with different magnitudes of the applied force.

First, we need to find the normal force on the block, which is equal to the weight of the block. The weight of the block is given by:

W = mg = 2.5 kg x 9.8 m/s^2 = 24.5 N

Next, we need to find the force of the applied vertical force, which is given in the problem as "is". We can use trigonometry to find the vertical component of the force:

Fv = is sinθ

where θ is the angle between the force and the horizontal surface. Since the problem does not give us the value of θ, we will assume it to be 0°, which means the force is purely horizontal.

(a) If the magnitude of the applied force is 8.0 N, then the frictional force can be calculated as:

Ff = μsFn = μs(mg - Fv) = 0.40(24.5 - 0) = 9.8 N

(b) If the magnitude of the applied force is 10 N, then the frictional force can be calculated as:

Ff = μsFn = μs(mg - Fv) = 0.40(24.5 - 10) = 5.8 N

(c) If the magnitude of the applied force is 12 N, then the frictional force can be calculated as:

Ff = μkFn = μk(mg - Fv) = 0.25(24.5 - 12) = 3.1 N

Therefore, the magnitude of the frictional force acting on the block is 9.8 N, 5.8 N, and 3.1 N, for applied forces of 8.0 N, 10 N, and 12 N, respectively.

(a) When the horizontal force is 8 N the frictional force is 11.8 N.

(b) when the applied force is 10 N; the frictional force is 13.8 N.

(c) when the applied force is 12 N; the frictional force is 15.8 N.

What is the magnitude of the frictional force acting on the block?

(a) The magnitude of the frictional force on the block when the horizontal force is 8 N is calculated as;

F - Ff = ma

where;

F is the horizontal force appliedFf is the frictional forcem is the massa is the acceleration

F - μmg = ma

6 - 0.4 x 2.5 x 9.8 = 2.5 a

2.5 a = -3.8

a = -3.8/2.5

a = -1.52 m/s²

when the applied force is 8 N;

8 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 11.8 N

(b) when the applied force is 10 N;

10 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 13.8 N

(c) when the applied force is 12 N;

12 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 15.8 N

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