Answer:
In legal terminology, the assured clear distance ahead (ACDA) is the distance ahead of any terrestrial locomotive device such as a land vehicle, typically an automobile, or watercraft, within which they should be able to bring the device to a halt.[1] It is one of the most fundamental principles governing ordinary care and the duty of care for all methods of conveyance, and is frequently used to determine if a driver is in proper control and is a nearly universally implicit consideration in vehicular accident liability.[2][3][4] The rule is a precautionary trivial burden required to avert the great probable gravity of precious life loss and momentous damage.[5][6][7] Satisfying the ACDA rule is necessary but not sufficient to comply with the more generalized basic speed law, and accordingly, it may be used as both a layman's criterion and judicial test for courts to use in determining if a particular speed is negligent, but not to prove it is safe.[8] As a spatial standard of care, it also serves as required explicit and fair notice of prohibited conduct so unsafe speed laws are not void for vagueness.[9][10][11] The concept has transcended into accident reconstruction and engineering.[12]
This distance is typically both determined and constrained by the proximate edge of clear visibility, but it may be attenuated to a margin of which beyond hazards may reasonably be expected to spontaneously appear. The rule is the specific spatial case of the common law basic speed rule,[13] and an application of volenti non fit injuria. The two-second rule may be the limiting factor governing the ACDA, when the speed of forward traffic is what limits the basic safe speed, and a primary hazard of collision could result from following any closer.[2][3]
As the original common law driving rule preceding statutized traffic law,[13] it is an ever important foundational rule in today's complex driving environment. Because there are now protected classes of roadway users–such as a school bus, mail carrier, emergency vehicle, horse-drawn vehicle, agricultural machinery, street sweeper, disabled vehicle,[14] cyclist, and pedestrian–as well as natural hazards which may occupy or obstruct the roadway beyond the edge of visibility,[14] negligence may not depend ex post facto on what a driver happened to hit, could not have known, but had a concurrent duty to avoid.[13][15] Furthermore, modern knowledge of human factors has revealed physiological limitations–such as the subtended angular velocity detection threshold (SAVT)–which may make it difficult, and in some circumstance impossible, for other drivers to always comply with right-of-way statutes by staying clear of roadway.[16][17]
As common law rule or statute
Determining the ACDA
ACDA rule-specific case generalized to the Basic Speed Law
Safe speed
"Assurance" beyond proximate edge of clear visibility as transference of liability
Derivations
Tables of reference constants and safe speeds
See also
Notes
References
pa follow at pa brainlest na den
Answer:if you cannot clearly discern time and distance
Explanation:
how could you test the idea that solar enefgy is required for the hydrolisis of water during phtotosyntheiss
One way to test this hypothesis would be to conduct an experiment in which water is subjected to light sources of varying intensity.
What is phtotosyntheiss?Photosynthesis is a process used by plants and some other organisms to convert light energy, typically from the sun, into chemical energy that can be used to fuel biological processes. During photosynthesis, light energy is absorbed by chlorophyll molecules in the plant's leaves and is then used to convert carbon dioxide and water into sugars and oxygen. This process provides the oxygen we breathe and the food we eat, making it one of the most important processes on Earth.
During the experiment, the rate of hydrolisis can be measured, and this data can then be compared to determine if the energy from the solar source is required for hydrolisis. Additionally, a control experiment can be conducted using light sources that do not contain solar energy, such as a light bulb, to compare to the solar energy experiment. This will allow scientists to determine the effect of the solar energy on the rate of hydrolisis, and confirm or refute the hypothesis.
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a skier traveling 11m/s goes up a 19 degree inclined plane, and glides up 15m before coming to rest. what is the average coefficient of friction?
Answer:
do you mind telling me what is it your asking so i can help ?
Explanation:
he upper ball is released from rest, collides with the stationary lower ball, and sticks to it. the strings are both 50.0 cm long. the upper ball has mass 2.00 kg, and it is initially 10.0 cm higher than the lower ball, which has mass 3.00 kg. find the frequency and maximum angular displacement of the motion after the collision
If the ball is released from rest and collides with stationery ball then the frequency is 0.71 Hz and maximum angular displacement of the motion after collision is 6.28° .
The upper Ball is released from the rest ;
the speed of the 2.2 Kg ball which was initially 10 cm higher then 3 Kg ball ,
means : KE = PE
⇒ v² = 2gh ;
⇒ v = √(2 x 9.8 x 0.1)
⇒ v = 1.4 m/s .
the principle of linear momentum is used to find the final speed after collision ,
⇒ m₁×v₁ \(+\) m₂×v₂ = vf×(m₁ + m₂)
⇒ 2(1.4) + 3(0) = vf(2 + 3)
⇒ 2.8 = 5vf
⇒ vf = 2.8/5
⇒ vf = 0.56 m/s
maximum displacement (\(h_{f}\)) is = 0.56²/2×9.8
= 0.56/19.6
= 0.028 m ;
the maximum angular displacement is calculated by :
Cosθ = (0.5 - 0.028)/0.5
Cosθ = 0.472/0.5
Cosθ = 0.994
θ = cos⁻¹(0.994)
θ = 6.28°
and the maximum frequency is = (1/2π)√g/L
= (1/2π)√9.8/0.5 = 0.71 Hz .
Therefore , the frequency is 0.71 Hz and the maximum angular displacement is 6.28° .
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A 2 ω resistor and a 8.0 mh inductor are used in an lr circuit. if the initial current in the circuit is 2.0 a when a switch is thrown that allows the current in the circuit to decay, at what time will the current be 1.0 a?
The initial current is 2A, resistance is 2Ω, and inductance is 0.008H. The time for current decay to 1A is found to be around 2.1ms using the natural logarithm.
The current in an LR circuit can be modeled by the equation:
\(I(t) = I0e^{(-Rt/L)}\)
where I(t) is the current at time t, I0 is the initial current, R is the resistance, L is the inductance, and e is the mathematical constant e.
We are given that the initial current is 2.0 A, the resistance is 2 Ω, and the inductance is 8.0 mH (or 0.008 H). We want to find the time it takes for the current to decay to 1.0 A.
Substituting the given values into the equation, we get:
\(1.0 A = 2.0 A \times e^{(-2\Omega t/0.008H)}\)
Simplifying, we can divide both sides by 2.0 A and take the natural logarithm of both sides:
\(ln(0.5) = -2\Omega t/0.008H\)
Solving for t, we get:
\(t = -0.008H \times ln(0.5) / 2\Omega\)
Plugging in the given values, we get:
\(t \approx 0.0021 s\) or 2.1 ms
Therefore, it will take approximately 2.1 ms for the current to decay to 1.0 A.
In an LR circuit, the inductor resists changes in current, so when the switch is thrown and the current starts to decay, the inductor generates a back EMF that opposes the change in current. This causes the current to decay exponentially over time, as described by the above equation.
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Which two forces operate over the longest distances?
A. Gravitational and weak nuclear
B. Electromagnetic and weak nuclear
C. Gravitational and strong nuclear
D. Electromagnetic and gravitational
Answer:
D Electromagnetic and gravitational
Alpha Centauri has an apparent magnitude of -0.27, whereas the apparent
magnitude of Alpha Crucis is 0.77. Identify which star appears brighter when observed from
Earth. Explain your answer.
Answer:
The star, Alpha Crucis, is brighter than the star, Alpha Centauri, when observed from Earth
Explanation:
The given parameters are;
The apparent magnitude of the star Alpha Centauri = -0.27
The apparent magnitude of the star Alpha Crucis = 0.77
Let relative brightness of two stars is given by the relation
\(\dfrac{b_1}{b_2} = 2.512^{(m_1 - m_2)}\)
Where;
m₁ = The apparent magnitude of the star Alpha Centauri = -0.27
m₂ = The apparent magnitude of the star Alpha Crucis = 0.77
b₁ = The brightness of the star Alpha Centauri
b₂ = The brightness of the star Alpha Crucis
Which gives;
\(\dfrac{b_1}{b_2} = 2.512^{(-0.27 - 0.77)}= 0.383689\)
Therefore;
b₁/b₂ = 0.383689 and
b₁ = b₂ × 0.383689
b₂ = b₁/0.383689 = 2.606×b₁
b₂ = 2.606×b₁
b₂ > b₁, b₂ is brighter than b₁, that is the star, Alpha Crucis is brighter than the star, Alpha Centauri, when observed from Earth.
Consider two celestial objects with masses m1 and m2 with a separation distance between their centers r. If the first mass m1 were to double and the second mass m2 were to triple, what would happen to the magnitude of the force of attraction
The new magnitude of the force of attraction will be 6 times the original force of attraction
How to determine the initial force Mass 1 = m₁Mass 2 = m₂ Gravitational constant = GDistance apart = rInitial force (F₁) = ?F = Gm₁m₂ / r²
F₁ = Gm₁m₂ / r²
How to determine the new force Mass 1 = 2m₁Mass 2 = 3m₂ Gravitational constant = GDistance apart (r) = rNew force (F₂) =?F = Gm₁m₂ / r²
F₂ = G × 2m₁ × 3m₂ / r²
F₂ = 6Gm₁m₂ / r²
But
F₁ = Gm₁m₂ / r²
Therefore
F₂ = 6Gm₁m₂ / r²
F₂ = 6F₁
Thus, the new magnitude of the force of attraction will be 6 times the original force of attraction
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Because scientists cannot actually precisely measure a process like soil erosion over the entire planet, they must _____.
A. prove their hypotheses without the use of external measurements
B. rely on anecdotal evidence to prove their hypothesis
C. use statistical sampling and mathematical models to produce estimates
D. focus on developing sound scientific theories with correlating data
E. rely on peer review to provide consensus on the validity of the hypothesis
Your answer is C. I hope this helps you.
a bubble of 3 moles of argon gas (monatomic) is submerged underwater, and undergoes a temperature increase of 20° c. how much heat was required in joules?
To calculate the amount of heat required, we can use the formula:
Q = nCΔT
where Q is the amount of heat required, n is the number of moles of gas,
C is the molar heat capacity at constant volume, and ΔT is the change in temperature.
For monatomic argon gas, the molar heat capacity at constant volume is given by:
C = (3/2)R
where R is the universal gas constant, which is 8.31 J/(mol·K).
Therefore, C = (3/2) × 8.31 J/(mol·K) = 12.46 J/(mol·K)
Substituting the values into the formula, we get:
Q = 3 × 12.46 J/(mol·K) × 20 K
Q = 1495.2 J
Therefore, the amount of heat required to increase the temperature of the bubble of 3 moles of argon gas (monatomic) by 20°C is approximately 1495.2 J.
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1. Width of A postage stamp is one m, 15 cm, or 20 mm
2. A thickness of ACD 0.1 m 0.01 m or 0.001 m
3. Height of a bus 152.4 mm, 20M, or 250 cm
4 Length of an inch worm 25.4 mm, 25.4 cm or 0.254 m
5. Length of a football field 91.44 m 200 m or one km
Will give brainless
#1 explain why there is no such thing as a quick and easy way to lose weight.
#2 why can’t you not always trust “before and after” photos?
#3 what are three things you should do before you buy exercise equipment?
#4 name a exercise equipment, how it is supposed to work and why you are skeptical about it?
Exercise is a vigorous activity that tends to help us to burn calories and loose weight in the process.
What is exercise?Exercise is a vigorous activity that tends to help us to burn calories and loose weight in the process. There is no quick way to loose weight because the calories were added on gradually and must also be lost gradually.
Before and after photos does not show the loss in calories. This can only be determined by measurement.
Before you buy exercise equipment;
Ensure that the equipment meets your unique needsEnsure that you can afford itEnsure that you have enough space to contain the equipmentAn example of an exercise equipment is a stationary bicycle. It works when you sit or stand on it and cycle repeatedly though it doesn't move. I am skeptical about it because it may not help you burn a lot of calories except you use it for long periods of time.
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Four ample of teel, lead, alcohol and gla all have the ame ma and are all initially at 20 °C. After 100 calorie of heat i added to each ample, the final temperature are 38. 2 °C for the teel, 85. 6 °C for the lead, 23. 4 °C for the alcohol, and 30 °C for the gla. Which of thee four material ha the larget pecific heat capacity?
The larget specific heat capacity is the alcohol. Option A.
The specific heat of a substance is the heat capacity of a sample of the substance divided by the mass of the sample, sometimes called the mass heat capacity. Water has a very high specific heat. That means it has to absorb a lot of energy before the temperature changes.
On the other hand, sand and asphalt have low specific heat. This means that the temperature changes faster. The temperature rise in milk is higher because the specific heat of water is greater than that of milk. Water has the highest specific heat capacity that any liquid can produce. Specific heat is defined as the amount of heat that one gram of material must absorb or release to change its temperature by one degree Celsius.
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Comic-strip hero Superman meets an asteroid in outer space and hurls it at 800 m/s, as fast as a bullet. The asteroid is a thousand times more massive than Superman. In the strip, Superman is seen at rest after the throw. Taking physics into account, what would be his recoil speed (in km/s)?
Answer:
800km/s
Explanation:
Initial momentum = final momentum
the total momentum is zero, Before the release of the asteroid , but Superman and the asteroid are not moving.
So, according to the Conservation of momentum the total momentum when the astronaut is been thrown will equals to zero . Then we can say
Initial momentum = final momentum
Because the momentum of the Superman immediately the asteroid is been thrown is equal to the momentum of the asteroid
Momentum =(mass ×velocity)
the mass of the asteroid i= 1000M
Given velocity = 800 m/s,
momentum =(1000M)(800 m/s)
= 800,000M m/s.
to get the answer, we need to divide by Superman's mass, M, which gives his recoil velocity of 800,000 m/s.
But we're told to convert to km/ s
We know that 1m/s=0.001km/s
=(800,000M m/s)× (0.001km/s)
=800km/s
Therefore, his recoil speed (in km/s) is 800km/s
Describe something Joule believed that contradicted the beliefs of his peers.
Answer:
Joule, a 19th-century physicist, believed in the conservation of energy, which contradicted the beliefs of his peers at the time. His contemporaries believed that energy was a substance that could be created or destroyed. In contrast, Joule believed that energy could only be transformed from one form to another but could never be created or destroyed. He demonstrated this through a series of experiments where he showed that heat and mechanical work were equivalent forms of energy and that the total amount of energy in a closed system remained constant.
Joule's ideas challenged the established scientific beliefs of his time. They paved the way for the development of the first law of thermodynamics, which states that the total energy in a closed system is constant and cannot be created or destroyed. By proposing and demonstrating these ideas, Joule made significant contributions to the development of classical physics and helped lay the foundations of modern energy science.
Answer:
James Prescott Joule was a 19th-century British physicist who made significant contributions to the study of thermodynamics. One of his beliefs that contradicted the beliefs of his peers was the idea that heat was a form of energy.
At the time, the prevalent belief was that heat was a fluid-like substance called "caloric" that flowed from hot objects to cold objects. Joule challenged this idea and proposed that heat was actually a form of energy that could be transformed into other forms of energy, such as mechanical energy.
Joule's work showed that heat was a conserved quantity, much like energy, and that it could be quantified in terms of work done. This was a significant departure from the prevailing ideas of the time and helped lay the foundation for the study of thermodynamics.
What is the velocity of an object accelerating at 7.0 m/s² after 4.0s when it is initially moving at 3.0 m/s? Value
Answer:
31.0 m/s
Explanation:
Given:
\(\vec a=7.0 \ m/s^2\\\\t=4.0 \ s\\\\\vec v_0 = 3.0 \ m/s\)
Find:\(\vec v_f=?? \ m/s\)
\(\boxed{\left\begin{array}{ccc}\text{\underline{The 4 Kinematic Equations:}}\\\\1. \ \vec v_f=\vec v_0+\vec at\\\\2. \ \Delta \vec x=\frac{1}{2}(\vec v_f-\vec v_0)t\\\\3. \ \Delta \vec x=\vec v_0t+\frac{1}{2}\vec at^2\\\\ 4. \ \vec v_f^2=\vec v_0^2+2\vec a \Delta \vec x \end{array}\right}\)
Using the first kinematic equation:
\(\vec v_f=\vec v_0+\vec at\\\\\Longrightarrow \vec v_f=3.0+(7.0)(4.0)\\\\\Longrightarrow \vec v_f=3.0+28.0\\\\\therefore \boxed{\boxed{\vec v_f=31.0 \ m/s}}\)
Thus, the objects final velocity is found.
Add an E-W force and a N-S force so the object is at equilibrium.
Add a Force
re
Given: 64.0 N. 128.7°CCW
Tap to learn about CCW
The addition of vectors allows to find the vector that the equilibrium is
F = (40.02 i ^ - 49.95 j ^) N
Parameters given
Vector value A = 64.0 N and tea = 128.7ºTo find
The vector that allows equilibrium
The force is a vector magnitude so the sum of the force must be done using the methods to add vectors.
One of the easiest methods to perform the addition of vectors is the analytical method where each vector is decomposed in a Cartesian system and the components added using algebraic summation and then the resulting vector is constructed.
We decompose the vector
cos θ = \(\frac{A_x}{A}\)Ax / A
sin θ = \(\frac{A_y}{A}\)
Aₓ = A cos θ
\(A_y\)= A sin θ
Aₓ = 64 cos 128.7
\(A_y\) = 64 sin 128.7
Aₓ = -40.02 N
\(A_y\) = 49.95 N
To find the vector that allows equilibrium, we work each axis independently
X axis
Aₓ + Fₓ = 0
Fₓ = - Aₓ
Fₓ = 40.02 N
Y axis
\(A_y + F_y =0 \\F_y = - A_y\\F_y = - 49.95 N\)
We can write the resulting vector in two ways
1) F = (40.02 i ^ - 49.95 j ^) N
2) in the form of module and angle
Let's find the module with the Pythagoras' Theorem
F =\(\sqrt{F_x} ^2 + F_y^2)\\F = \sqrt{40.02^2 + 49.95^2 }\)
F = 64 N
Angles
tan θ = \(\frac{F_y}{F_x}\)
θ = tan⁻¹ \(\frac{F_y}{F_x}\)
θ = tan⁻¹ \(\frac{-49.95}{40.02}\)
θ = -51.3º
This angle is measured clockwise from the positive side of the x-axis
In conclusion using the sum of vectors we can find the vector that allows the equilibrium is
F = (40.02 i^ - 49.95 j^ ) N
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The hog-nosed bat is the smallest mammal on Earth: it is about the same size as a bumblebee and has an average mass of 2.0 g. Suppose a hog-nosed bat with this mass flies at 2.0 m/s when it detects a bug with a mass of 0.20g flying directly toward it at 8.0 m/s. What fraction of the total kinetic energy
dissipated when it swallows the bug?
Given
\(m_1 = 2g\\\\m_2 = 0.2g\\\\v_1 = 2m/s\\\\v_2 = -8m/s\)
The expression for a perfectly inelastic collision,
\(m_1v_1 + m_2v_2 = (m_1+m_2)v_f\)
Therefore,
\(v_f = \frac{m_1v_1 + m_2v_2}{(m_1+m_2)} \\\\v_f = \frac{(2*2)+(0.2*-8)}{2+0.2}\\\\v_f = 1.09m/s\)
Since the bat and the bug fly towards each other, and after some time the bat swallows the bug, it is said to be a condition of perfectly inelastic collision.
The kinetic energy of the bat before it swallows the bug is,
\(KE_b = \frac{1}{2}m_1v_1^2\\\\KE_b = \frac{1}{2}2*2^2\\\\KE_b = 4gm^2/s^2\)
The kinetic energy of the bat after it swallows the bug is,
\(KE_f = \frac{1}{2}(m_1+m_2)v_f^2\\\\KE_f = \frac{1}{2}(2+0.2)1.09^2\\\\KE_f = 1.3gm^2/s^2\)
The total dissipation in the kinetic energy of the bat is calculated as,
\(\delta KE = KE_b - KE_f\\\\\delta KE = 4 - 1.3\\\\\delta KE = 2.7 gm^2/s^2\)
The fraction of the dissipated kinetic energy of the bat is calculated as,
\(d = \frac{\delta KE}{KE_b}\\\\d = \frac{2.7}{4}\\\\d = 0.67\)
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After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 53.0 cm . The explorer finds that the pendulum completes 91.0 full swing cycles in a time of 136 s. What is the magnitude of the gravitational acceleration on this planet?
The magnitude of the gravitational acceleration on this planet is 11.8 m/s²
How can the magnitude of the gravitational acceleration be determined?
On earth, gravity causes an acceleration of 9.8 m/s2.
G = GM/r2 is the formula used to calculate the acceleration caused by gravity.
The gravitational field on Earth has a strength of 9.8 or 10.
The Earth's gravitational field has a strength of 9.8 N/kg.
Accordingly, for every kg of mass, an object will experience 9.8 N of pressure.
If the gravitational field is weaker, the object has a lower weight.
Solving this for g:
g = (4p^2*L)/P^2.
I am assuming that the pendulum as a length of 49.0 m and that the pendulum completes 104 full swings in 133 s.
Since the pendulum completes 104 full swings in 133 s:
P = 133/104 s.
Then, given that L = 49.0 m:
g = (4p^2*L)/P^2
= [4p^2*(49.0 m)]/(133/104 s)^2
= 1.18 x 10^3 m/s^2.
This value of g seems rather large. Did you happen to have 49.0 cm = 0.49 m? If so, then:
g = (4p^2*L)/P^2
= [4p^2*(0.49 m)]/(133/104 s)^2
= 11.8 m/s^2.
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Explain why earth spins like a top and Uranus like a ball
Answer:
Earth spins like top because The earth is rotating around an rotational axis which is tilted 23 degrees with respect to earth's
orbit . where as Uranus rotation is very different from earth.It rotates on its sides
UV light is blocked from reaching the dermis by ___ in the skin.
a keratin
b melanin
C vitamin D
d sebaceous glands
UV light is blocked from reaching the dermis by melanin in the skin. Thus, option (B) is correct.
UV light (ultraviolet light) is a form of electromagnetic radiation with a wavelength of 10 to 400 nm, which is shorter than visible light but longer than X-rays. These are found in sunlight and contribute 10% of total solar light.
Melanin performs a number of biological activities, including skin and hair pigmentation and skin and eye photoprotection. Pigmentation of the skin is caused by the formation of melanin-containing melanosomes in the epidermis's basal layer.
UV rays cause melanin, a pigment in the skin, to be activated. This is the skin's initial line of defence against UV rays. Melanin absorbs UV rays, which can cause major skin damage. This is the procedure that results in a tan.
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how do i calculate this?
CAR 1
Momentum = Mass/Velocity
M = 2100/20
M = 105 m/s^2
CAR 2
Momentum = Mass/Velocity
M = 2100/30
M = 70 m/s^2
Describe when the chemical
reaction occurs in a dry-cell
battery
Answer:
For a dry-cell battery to operate, oxidation will occur from the zinc anode and reduction will take place in the cathode. The most common type of cathode is a carbon graphite. Once reactants have been turned into products, the dry-cell battery will work to produce electricity.
Explanation:
The battery operates through electrochemical reactions called oxidation and reduction. These reactions involve the exchange of electrons between chemical species. If a chemical species loses one or more electrons, this is called oxidation. The opposite process, the gain of electrons, is called reduction.
what is the formula for calculating the resistance of wire
The formula for calculating the resistance of wire by thickness and length is R = (ρ * L) / A.
The formula to calculate the resistance of a wire based on its thickness (cross-sectional area) and length is given by Ohm's Law:
R = (ρ * L) / A
Where:
R is the resistance of the wire (in ohms, Ω),
ρ (rho) is the resistivity of the material the wire is made of (in ohm-meters, Ω·m),
L is the length of the wire (in meters, m), and
A is the cross-sectional area of the wire (in square meters, m²).
The resistivity (ρ) is a characteristic property of the material and represents its inherent resistance to electrical flow. It can be found in tables or reference sources for different materials.
To calculate the cross-sectional area (A) of the wire, you can use the formula:
A = π * r²
π (pi) is a mathematical constant approximately equal to 3.14159,
r is the radius of the wire (in meters, m).
The radius (r) must be converted from the wire's thickness, which is typically given in gauge or diameter, to meters.
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The complete question is:
What is a formula to calculate the resistance of a wire by thickness and length?
You own a geotechnical engineering firm in central California and your company has been hired to conduct a slope stability analysis. Consider a 10.0 m-thick mass of regolith (note that this is already measured perpendicular to the slope – so pay attention where you might change the cosine term) sitting on top of a bedrock surface with a slope of 14 degrees. A home is located at the top of this slope (and set back from the edge only 20 m). Upon an initial visit, you determine that the regolith is unsaturated. You also estimate the following additional parameters for this site:
regolith cohesion = 1100 N/m2
regolith angle of internal friction = 15 degrees
density of regolith = 2200 kg/m3 (density of water = 1000 kg/m3 )
a. What is the value for the Factor of Safety? Show your work. Would you consider the slope currently stable? Explain your answer. 4 pts
b. How does the factor of safety change if the water depth increases by 2 m? Does the slope become more or less stable, and by how much? How does this compare to the example above (Part a.)? 3 pts
c. How does the factor of safety change if the angle of internal friction increases by a factor of 2 (this would be the equivalent of changing the material from loose sand to semi-consolidated sediment)? Does the slope become more stable or less stable? 3 pts
d. How does the factor of safety change if the slope is steeper by a factor of 2? Does the material become more or less likely to fail? 3 pts
e. What advice would you give to the homeowners regarding the safety of their home? What remediation can you suggest if any is needed? 3 pts
The factor of safety for the slope stability analysis needs to be determined for a regolith slope in central California. The parameters provided include regolith cohesion, angle of internal friction, and regolith density. The analysis involves evaluating the stability of the slope under different conditions, such as changes in water depth, angle of internal friction, and slope steepness. Recommendations for the homeowners regarding the safety of their homes and potential remediation measures will also be provided.
To calculate the factor of safety, we need to consider the forces acting on the slope. The driving force is the weight of the regolith, which can be calculated by multiplying the density of the regolith by the volume of the slope. The resisting force is the shear strength of the regolith, which is determined by the cohesion and angle of internal friction. The factor of safety is the ratio of the resisting force to the driving force.
a. To determine the factor of safety, we can use the given parameters and calculate the driving force and resisting force. By dividing the resisting force by the driving force, we can obtain the factor of safety. If the factor of safety is greater than 1, it indicates that the slope is stable. If it is less than 1, the slope is considered potentially unstable.
b. If the water depth increases by 2 m, it adds additional weight to the slope, increasing the driving force. This decrease in the factor of safety suggests a less stable slope compared to the initial scenario.
c. If the angle of internal friction increases by a factor of 2, it enhances the shear strength of the regolith. This increase in the factor of safety indicates a more stable slope.
d. If the slope becomes steeper by a factor of 2, it increases the driving force. This decrease in the factor of safety suggests a less stable slope.
e. Based on the analysis, it is important to advise the homeowners that the slope is currently unstable, considering the factor of safety is less than 1. Remediation measures may include slope stabilization techniques such as installing retaining walls, soil reinforcement, or drainage systems to manage water infiltration and reduce driving forces. It is recommended to consult with a geotechnical engineer to develop a comprehensive slope stability plan for the safety of the home.
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2.Write the formula associating energy with power
3.Write the formula associating potential energy with height.
4. By substitution of the formula on question 3 for the formula in question 2, rewrite the formula for power.
(PLEASE PLEASE HELP ASAP ILL MARK BRAINLIEST)
Answer:
\( Power = \frac {mgh}{time} \)
Explanation:
2. Power can be defined as the energy required to do work per unit time.
Mathematically, it is given by the formula;
\( Power = \frac {Energy}{time} \)
3. Potential energy can be defined as an energy possessed by an object or body due to its position.
Mathematically, potential energy is given by the formula;
\( P.E = mgh\)
Where,
P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
4. Substituting the equation in 3 into equation in 2 above, we have;
\( Power = \frac {mgh}{time} \)
The plates of a parallel-plate capacitor are maintained with constant potential by a battery as they are pulled apart. During this process, the amount of charge on the plates
The amount of charge on the parallel-plate capacitor and electric field decreases during this process.
What is Electric Field?The physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them, is known as an electric field (also known as an E-field).It can also refer to a system of charged particles' physical field. Electric charges and time-varying electric currents are the building blocks of electric fields.The electromagnetic field, one of the four fundamental interactions (also known as forces) of nature, manifests itself in both electric and magnetic fields. Electrical technology makes use of electric fields, which are significant in many branches of physics.For instance, in atomic physics and chemistry, the electric field acts as an attracting force to hold atoms' atomic nuclei and electrons together.To know more about electric field with the given link
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Question:
The plates of a parallel-plate capacitor are maintained with a constant voltage by a battery as they are pulled apart. How is the strength of the electric field affected during this process?
A)The electric field between the plates becomes infinite.
B)The strength of the electric field increases during this process.
C)The amount of charge on the parallel-plate capacitor and electric field decreases during this process..
D)The electric field between the plates becomes zero.
E)The strength of the electric field remains constant.
suppose a nascar race car rounds one end of the martinsville speedway. this end of the track is a turn with a radius of approximately 57.0 m57.0 m . if the track is completely flat and the race car is traveling at a constant 28.5 m/s28.5 m/s (about 64 mph64 mph ) around the turn, what is the race car's centripetal (radial) acceleration?
The race car's centripetal acceleration is 14.25 m/\(s^{2}\)
Centripetal acceleration, a = \(V^{2}\)/r
a = \(28.5^{2}\) / 57 = 14.25 m/\(S^{2}\)
Any change in velocity, including changes in speed, direction, or both, is referred to as acceleration. Even if the speed may be constant in uniform circular motion, the direction of the velocity changes continuously, therefore there is always an accompanying acceleration. You personally experience this acceleration every time you round a corner in your car. If you maintain a constant speed during the turn, you will be moving uniformly in a circle. Because both you and the car are changing directions, you sense a sideways acceleration. The more pronounced the acceleration, the sharper the curve and the greater your speed will be. The magnitude and direction of that acceleration will be looked at in this section.
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Use the circuit diagram to decide if the lightbulb will
light. Justify your answer.
Answer:
The lightbulb will not turn on because a switch is connected to it in parallel and when it is closed, like it is now, it becomes a short, by-passing the bulb completely.
Answer:
Sample Response: The lightbulb will not light because this is a short circuit. The branch without the bulb has almost no resistance, so all the current will flow through that branch instead of flowing through the bulb.
Explanation:
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in any star cluster, stars with lower masses greatly outnumber those with higher masses. T/F
Answer: True
Explanation: It is true that in any star cluster, stars with lower masses greatly outnumber those wth higher masses.
gia tốc a và vận tốc v cùng chiều khi nào trong một chu kì dao động điều hòa ?
Explanation:
Khi một hạt thực hiện SHM Đang chuyển động từ vị trí cực biên về vị trí trung bình, thì vận tốc và gia tốc cùng hướng, tức là hướng về vị trí trung bình