If the real length of an object is 5.5 meters, which set of four measurements is the most accurate?

Answer:

1.9

Explanation:

a)  the average power of the elevator motor during this period is 0.1696 hp

b) The power during an upward trip with constant speed is 16.13 horsepower.

To calculate the average power of the elevator motor during the period of acceleration, we need to find the work done by the motor and divide it by the time taken.

Given:

Mass of the elevator (m) = 682 kg

Acceleration (a) = (1.80 m/s - 0) / 3.10 s = 0.5806 m/s²

Time taken for acceleration (t) = 3.10 s

(a) First, let's calculate the displacement (d) using the formula for uniformly accelerated motion:

d = 0.5 * a * t^2

= 0.5 * 0.5806 m/s² * (3.10 s)^2

= 1.0153 m

Next, we can calculate the work done (W) by the elevator motor:

W = m * a * d

= 682 kg * 0.5806 m/s² * 1.0153 m

= 391.55 J

Now, to find the average power (P), we divide the work done by the time taken:

P = W / t

= 391.55 J / 3.10 s

= 126.36 W

To convert the power to horsepower, we can use the conversion factor: 1 horsepower (hp) = 745.7 watts.

Therefore, the average power of the elevator motor during this period is:

P = 126.36 W / 745.7

= 0.1696 hp

(b) During an upward trip with constant speed, the elevator does not accelerate, so the power required is only to counteract the force of gravity and friction. The power during an upward trip with constant speed is equal to the power required to overcome the force of gravity and friction.

The force of gravity (Fg) can be calculated using:

Fg = m * g

= 682 kg * 9.8 m/s²

= 6683.6 N

The power (P) required is given by the formula:

P = Fg * v

= 6683.6 N * 1.80 m/s

= 12030.5 W

To convert the power to horsepower:

P = 12030.5 W / 745.7

= 16.13 hp

Therefore, the power during an upward trip with constant speed is 16.13 horsepower.

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Answer:

D

Explanation:

Answer:

 \(r^2 = \frac{ 2 k \ Ze^2}{ 2m}\)

Explanation:

For this exercise we must use the principle of conservation of energy

starting point. The proton very far from the nucleus

          Em₀ = K = ½ m v²

final point. The point where the proton is stopped (v = 0)

          Em_f = U = q V

where the potential is

          V = k Ze / r²

Let us consider that all the charge of the nucleus is in the center, therefore r is the distance from this point to the proton that is approaching

Energy is conserved

          Em₀ = Em_f

           ½ m v² = e (\(k \frac{Ze}{r^2}\))

          \(r^2 = \frac{ 2 k \ Ze^2}{ 2m}\)

with this expression we can find the closest approach distance (r)

The wavelength of this wave is 1 meter (option d).

To determine the wavelength of a longitudinal wave, we need to find the distance between two consecutive compressions or rarefactions. In this case, the distance between the center of the fifth compression and the center of the ninth compression is given as 4 meters. Since there are four compressions between the fifth and ninth compression, the total distance covered by these four compressions is 4 meters. Therefore, the average distance between consecutive compressions is 4 meters divided by 4, which is 1 meter. The wavelength of a longitudinal wave is the distance between two consecutive points with the same phase, which, in this case, is the distance between consecutive compressions. It is important to note that the number of compressions or rarefactions does not directly affect the wavelength. The wavelength is determined by the distance between consecutive points with the same phase. In this case, the given information allows us to calculate the average distance between consecutive compressions, giving us the wavelength of the wave. (option d).

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Answer:

t=0.08 seconds or 2.49 seconds

Explanation:

using x= ut + 0.5at^2

x = 1

u=12.6m/s

a= -9.8m/s^2. (since it's moving upward )

1=12.6t - (0.5×9.8× t^2)

1= 12.6t - 4.9 t^2

4.9 t^2-12.6t+1=0

solving for t using quadratic formula

t=0.08 seconds or 2.49 seconds

One natural source of radioactivity is radon gas, which is produced from the decay of uranium in rocks and soil.

It emits alpha particles, which are stopped by a sheet of paper but can be dangerous if inhaled. Radon is most common in areas with high concentrations of uranium and can accumulate in poorly ventilated buildings, particularly in basements. Long-term exposure to radon is a significant cause of lung cancer, particularly among smokers.

To protect themselves, people can test their homes for radon levels and install mitigation systems if necessary. However, radon is also used in some medical treatments and as a tracer in scientific research. Sources for this report include the United States Environmental Protection Agency, the World Health Organization, and the National Cancer Institute.

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Answer:

0.375 m/s north & 0.375 m/s east

Explanation:

We have that If you walk 800m north, 600m east, and 200 meters south at a speed of 1m/s you will have a velocity of

V=0.5m/sec

From the question we are told

If you walk 800m north, 600m east, and 200 meters south at a speed of 1m/s. What is your velocity?

Generally the equation for the velocity  is mathematically given as

\(v=\frac{displacement}{time}\)

Where

Displacement of 800m north, 600m east, and 200 meters south from the Cartesian coordinated is given as

\(600\sqrt{2}\)

And time

\(T=\frac{distance}{speed}\\\\T=\frac{800+600+200}{1}\\\\T=1600s\)

Therefore

\(V=\frac{600\sqrt{2}}{1600}\)

V=0.5m/sec

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(a) The time of flight be for a tennis ball launched by the ball machine is 0.19 s.

(b) The range of the tennis ball be is 1.01 m.

(c)  The final velocity of the ball with which it reaches the ground is 7.16 m/s.

The time of flight of the tennis ball is calculated as follows;

h = vt + ¹/₂gt²

1.2 = 5.3t + 0.5(9.8)t²

1.2 = 5.3t + 4.9t²

4.9t² + 5.3t - 1.2 = 0

a = 4.9, b = 5.3, c = 1.2

solve using quadratic formula

t = 0.19 s

Thus, the time of flight be for a tennis ball launched by the ball machine is 0.19 s.

The range of the tennis ball is calculated as follows;

R = vt

R = 5.3 x 0.19

R = 1.01 m

The final velocity of the ball with which it reaches the ground is calculated as follows;

vf = vo + gt

vf = 5.3 + 9.8(0.19)

vf = 7.16 m/s

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Answer:

The answer is "1.5625".

Explanation:

Please find the complete question with its solution file in the attachment.

Answer:

force needed for the bus to go round the corner is 50,000 N.

Explanation:

To find the force needed for the bus to go round the corner, we can use the formula for centripetal force:

F = (mv^2)/r

where F is the centripetal force, m is the mass of the object, v is the velocity of the object, and r is the radius of the circular path.

Plugging in the values given in the problem, we get:

F = (2500 kg)(5 m/s)^2 / 50 m

= 50,000 N

So the force needed for the bus to go round the corner is 50,000 N.

Answer:

B. Pre-contemplation

Explanation:

Hope this helps :)

If enough experimental data supports a hypothesis, it is considered a well-supported scientific theory, but it is not considered to be 100% true or proven. Scientific theories are always open to further investigation and revision based on new evidence. Therefore, option C ("Is proven 100% true") is incorrect.

Option A ("Is accepted as true until proven false") is also incorrect because scientists do not accept a hypothesis as true until it has been rigorously tested and supported by a large body of evidence. Even then, scientists recognize that any scientific theory is subject to revision or falsification if new data or evidence emerges that contradicts it.

Option B ("Becomes an Observational Law") is also incorrect because scientific laws are typically descriptive, rather than explanatory. They describe what happens in a given set of circumstances, but they do not explain why it happens. Hypotheses and theories, on the other hand, attempt to explain why certain phenomena occur, and they are supported by experimental evidence.

Therefore, none of the options are completely accurate, but the most appropriate answer is that the hypothesis becomes a well-supported scientific theory.

The 10/90 principle can be a powerful tool for taking control of your situation and improving your life. By taking responsibility for what you can change and focusing on your reaction to the situation, you can make positive changes in your life and become the master of your own destiny.

The 10/90 principle refers to the idea that life is made up of 10% of what happens to you and 90% of how you respond to it. In other words, you may not be able to control what happens to you, but you can control your reaction to it. By taking responsibility for what you can change rather than being a victim of what you cannot change, you can take control of your situation and improve your life.One example of a situation where the 10/90 principle could be applied is losing a job. Losing a job can be a devastating experience, and it can be easy to feel like a victim in this situation. However, by applying the 10/90 principle, you can take control of your situation and make positive changes in your life.The first step in applying the 10/90 principle in this situation would be to take responsibility for what you can change. This could mean updating your resume, networking with others in your field, and applying for new jobs. By taking action and doing what you can to find a new job, you are taking control of your situation and improving your chances of finding a new job.
The second step would be to focus on your reaction to the situation. Instead of dwelling on the negative aspects of losing your job, try to focus on the positive aspects. This could mean using the extra time to pursue a new hobby or spend more time with family and friends. By focusing on the positive aspects of the situation, you are taking control of your reaction and improving your overall well-being.
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An aerial photographic image's corners, edge-centers, or both may contain a series of marks known as fiducial marks. These traces are recorded on the original film by the camera.

Fiducial markers are tiny metal objects, usually made of gold, that are positioned inside or close to a tumor to help direct the placement of radiation beams during therapy. They are about the size of a grain of rice.

Tiny metal things are called fiducial markers (about the size of a grain of rice). They assist your healthcare professionals in aligning the radiation beams and guarantee that your radiation therapy is administered consistently.

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Fiducial marks are a set of marks that can be found in the corners, edge-centers, or both of an aerial photographic image. The camera captures these traces on the original film.

Given  the Ryerson Campus is at a scale of  1:1000

Then the photographic scale (s) = 1:3000

The focal length of camera (f) = 152mm = 0152m

The format is (k) =  230 x 230mm = 0.23m

the photographic scale (s) = F/H where H is the image height

1/3000 = 0.152 /H Then H = 456m

Assume that there is longitudinal overlap as P1 = 60% and side to side overlap as 30%. Therefore margin of ground photograph = (1-P1) x k/s

(1-0.6) x 0.23/1/3000 = 276mm

Now width of ground photograph = (1-0.3) x 0.23/1/3000 = 483m

Hence the central points are plotted within the area range in 276m x 483m magnitude.

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Answer:

One should draw a diagram showing the placement of the charges.

When both charges of -Q are placed there will be no force in the vertical direction because of cancellation of forces.

A line from one corner of the square to the other makes an angle of 45 degrees,

2 cos 45 deg will be the force due to one charge.

2 * .707 = 1.41 N

So for both charges the force is (horizontal, vertical is zero)

2 * 1.41 = 2.82 N

b) is correct

The magnitude of the net force that acts on the center charge will be 2.82 N.Option B is correct.

When the matter is put in an electromagnetic field, it has an electric charge, which causes it to experience a force. A positive or negative electric charge can exist.

Charges that are similar repel each other, whereas charges that are dissimilar attract each other. The term "neutral" refers to an item that has no net charge.

Case 1 ;

One point charge +Q is placed at the center of a square, and a second point charge -Q is placed at the upper-left corner of the square.

When both charges of -Q are placed there will be no force in the vertical direction because of the cancellation of forces.

A line from one corner of the square to the other makes an angle of 45 degrees,

The force due to the one charge at the angle of the 45° will be;

\(\rm F_1 = 2 \times cos 45^0 \\\\ \rm F_1 =1.41 \ N\)

For both the charge the net force is the double the force due to the one charge;

\(\rm F = 2 \times F_1 \\\\ \rm F = 2 \times 1.41 \\\\ F=2.82 \ N\)

The magnitude of the net force that acts on the center charge will be 2.82 N.

Hence option B is correct.

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A car traveling at a constant speed of 20 m/s has travelled 3 minutes × 60 seconds/minute * 20 m/s = 3600 meters after 3 minutes.

The rate at which an object's position changes in any direction is referred to as its speed. The ratio of distance travelled to travel time is used to determine speed. Velocity and speed are two terms used to describe how quickly an object moves along a path. That is to say, velocity is a vector and speed is a scalar value.

Speed is defined as the rate at which a distance changes over time. The base units of distance and time are combined to form the SI unit of speed. Distance multiplied by speed Time is equal to one metre per second. The SI unit for speed is the m/s.

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Therefore, the magnitude of the vector is approximately 361.3 meters.

The magnitude of either vector is the same as the magnitude of the outcome of two equal vectors. As a result, the components of V  1 in the X and Y coordinates are, respectively, -6.6 units and 0 units.

Using the Pythagorean equation, we can determine the magnitude of a vector with x and y components:

|v| = √(x² + y²)

where |v| denotes the vector's size.

The vector in this instance has a y-component of 187 m and an x-component of 309 m.

When we enter these numbers into the solution, we obtain:

|v| = √((-309)² + (187)²)

|v| = √(95658 + 34969)

|v| = √(130627)

|v| ≈ 361.3

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Answer:

Explanation:

Wavelength = 100m. Speed = V. 2.) Frequency = 20 Hz. Wavelength = 200 m. Speed = ... 2=1.7m. F=Y/2 f=2×10. 5.) Wavelength = 502 km. Speed= 100 m/s.

Answer:using Newton third law

Let initial velocity of block be u1=3m/s

Mass of moving block m1 =1kg

Final velocity of block =V

Mass of stationary block m2= 4kg

Since they stick together, their final velocity will be the same.

m1u1 + m2u2=(m1+m2)v

(1*3)+(0*4)=(1+4)v

3=5v

Divide both sides by 5

V=0.6

Final velocity is 0.6m/s

Explanation:

The resistance expected of the heater is 50.1 ohms.

Resistance can be defined as the opposition to the flow of electric current in an electric circuit. The S.I unit of resistance is Ohms (Ω).

To calculate the resistance of the heater, we use the formula below.

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the resistance expected of the heater is 50.1 ohms.

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Answer:

Mass and distance.

Explanation:

The force of gravity is proportional to the masses of the two objects and inversely proportional to the square of the distance between them.

Based on the densities of the two liquids, the height of the light liquid in the right arm of the U-tube is 0.203 cm.

Let's first consider the situation before the light liquid is added. At this point, the heavy liquid fills both arms of the U-tube to the same height, h.

The pressure at point A is equal to the pressure at point B

Therefore:

P₀ + ρgh = P₀ + ρgh

where P₀ is the atmospheric pressure, ρ is the density of the heavy liquid, and g is the acceleration due to gravity.

Simplifying this equation, we get:

ρgh = ρgh

Canceling out the ρ and solving for h, we get:

h = h

In other words, the height of the heavy liquid is the same in both arms of the U-tube.

Now let's consider the situation after the light liquid is added to the right arm of the U-tube. We want to find the height, L, of the light liquid in the right arm.

Since the pressure at any two points in a connected vessel is the same, the pressure at point B (the top of the heavy liquid in the right arm) must be equal to the pressure at point C (the top of the light liquid in the right arm).

Therefore, we can write:

P₀ + ρgh = P₀ + ρg(L+h)

where L is the height of the light liquid in the right arm.

Simplifying this equation, we get:

ρgh = ρgL + ρgh

Canceling out the ρgh and solving for L, we get:

L = (ρ/ρ₀)h

where ρ₀ is the density of the light liquid.

Substituting the given values, we get:

L = (0.92 g/cm³ / 13 g/cm³)h

L = 0.070769h

Now we need to find h. We can use the fact that the volume of the heavy liquid in the left arm is equal to the volume of the heavy liquid plus the light liquid in the right arm.

The volume of the heavy liquid in the left arm is:

V₁ = Ah = (13.2 cm²)(h cm)

V₁ = 13.2h cm³

The volume of the heavy liquid plus the light liquid in the right arm is:

V₂ = A(L+h) = (2.11 cm²)(L+h cm)

V₂ = 2.11(L+h) cm³

Since these volumes are equal, we can set them equal to each other and solve for h:

13.2h = 2.11(L+h)

13.2h = 2.11L + 2.11h

11.09h = 2.11L

h = (2.11/11.09)L

Substituting this into our expression for L, we get:

L = 0.070769(2.11/11.09)L

L = 0.01345L

L = 0.01444h

Substituting the given value for the density of the heavy liquid, we get:

L = 0.01444h = 0.01444(13 g/cm³)/(0.92 g/cm³)

L = 0.203 cm

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Complete question:

A heavy liquid with a density 13 g/cm³ is poured into a U-tube as shown in the left- hand figure below. The left-hand arm of the tube has a cross-sectional area of 13.2 cm², and the right-hand arm has a cross-sectional area of 2.11 cm². A quantity of 90.2 g of a light liquid with a density 0.92 g/cm³ is then poured into the right-hand arm as shown in the right-hand figure below.

Determine the height L of the light liquid in the column in the right arm of the U-tube, as shown in the second figure above. Answer in units of cm.

Answer:

mine is 9.75 so take that as you will

Explanation:

Answer: 1.14 kg*m/s

Explanation:

The first person explained everything right, they just forgot to convert the angular acceleration to rads/sec^2 from revs/sec^2. Once that is converted, your answer should come out right.

Another small thing, the answer there has an extra unnecessary step. It tells you to find the square root of w^2 to find w but that is unnecessary since the final equation asked for w^2. Hope this helps! :)

The moment of inertia I of the flywheel about its rotation axis is

Given

Angular displacement,

\(\theta = 30rev \\\\\theta = (30) * 2\pi rad \\\\\theta = 188.495rad\)

Therefore, Final angular velocity (w) will be:

\(w^2 = 2\alpha\theta\\\\w^2 = 2 * (0.200 * 2\pi) * (188.49)\\\\w^2 = 473.73\\\\w = 21.76 rad/s\)

Therefore,

moment of inertia

\(I = 2 * K / w^2\)

\(I = 2 * 330 / 473.73\)

\(I = 1.39kgm^2\)

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