if the mass of the object is doubled and the speed is halved then kinetic energy will change by a factor of:
2
4
1/2
1/4

The energy transferred in Joules by the radio when it has been switched on for 2 minutes would be 6000 Joules.

Power is defined as the rate of energy transfer or the rate at which work is done, and is given by the equation:

Power = Energy transferred / Time

Rearranging the equation to solve for energy transferred, we get:

Energy transferred = Power x Time

We are given:

Power = 50 W

Time = 2 minutes = 120 seconds

Therefore, the energy transferred by the radio when it has been switched on for 2 minutes is:

Energy transferred = Power x Time = 50 W x 120 s = 6000 J

In other words, the energy transferred by the radio is 6000 Joules.

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Answer:

» The image is laterally inverted.

» The image is upright.

» The image geometry is same as object geometry.

» Image distance is same as object distance.

» Image is not real, it's virtual ( not formed on screen ).

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The magnitude of the vector is approximately 35.85 m.

The angle that this vector makes with the positive x-axis is approximately 32 degrees.

To find the magnitude of the vector with components Ax=29 m and Ay=18 m, we use the Pythagorean theorem:

|A| = √(Ax^2 + Ay^2)

|A| = √(29^2 + 18^2)

|A| = √(841 + 324)

|A| = √1165

|A| =  34.13 m

To find the angle that this vector makes with the positive x-axis, we can use the inverse tangent function:

θ = tan^-1(Ay/Ax)

θ = tan^-1(18/29)

θ = 31.82 degrees

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a.) the ball was going up at 0.95 seconds and coming down at 4.58 seconds

b.) the distance of the wall from the plate is 34 m

Given that a ball player hits a home run, and the ball just clears the wall which is 22.0 m high. The ball is hit at an angle of 37.0" with a velocity of 45.0 m/s.

Since the ball is hit at an angle of 37.0 degrees, We need to find the vertical and horizontal component of the velocity.

\(U_{y}\) = 45 Sin 37 = 27.08 m/s

\(U_{x}\) = 45 cos 37 = 35. 94 m/s

Let us first calculate the maximum height reached.

\(V^{2}\) = \(U_{y} ^{2}\) - 2gH

At maximum height, V = 0

0 = \(27.08^{2}\) - 2 x 9.8H

19.6H = 733.3

H = 733.33/19.6

H = 37.4 m

If the ball is hit from a height of 0.750 m above the ground,

(a) To calculate the time the ball stays in the air until it  clears the wall while on its way down, we will use the formula below.

h =  \(U_{y}\)t - 1/2g\(t^{2}\)

Substitute for all the parameters

22 - 0.75 = 27.08t - 0.5 x 9.8 x \(t^{2}\)

21.25 = 27.08t - 4.9\(t^{2}\)

4.9\(t^{2}\) - 27.08t + 21.25

We will use quadratic formula

a = 4.9

b = - 27.08

c = 21.25

t =  \(\frac{-b+/- \sqrt{b^{2} - 4ac } }{2a}\)

t = \(\frac{27.08 +/- \sqrt{27.08^{2} - 4 * 4.9 * x^{2} 21.25 } }{2 * 4.9}\)

t = \(\frac{27.08 +/-\sqrt{733.3 - 416.5} }{9.8}\)

t = \(\frac{27.08 +/- 17.8}{9.8}\)

t = 44.88/9.8 or 9.28 / 9.8

t = 4.58 s  or 0.95 s

This means that the ball was going up at 0.95 seconds and coming down at 4.58 seconds

(b) The distance of the wall from home plate will be the range which is

R = \(U_{x}\)t

R = 35.94 x 0.95

R = 34.143 m

Therefore, the distance of the wall from the plate is 34 m approximately

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Answer:

C. That the small portion of the space we can see is truly representative of all the rest of the universe that we cannot see.

Explanation:

The Cosmological Principle assumes that the small portion of the universe that we can see is representative of the entire universe, even though we can only directly observe a tiny fraction of it. It's an assumption used by Cosmologists to simplify their models of the universe.

Answer:

6 km is the right answer

hope it helps you

Explanation:

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Answer:

Measuring a patient's body weight can be done to Assess and monitor fluid and nutrition status as part of a nutrition screening tool. Calculate drug doses. Calculate nutrition and fluid support if required. Monitor the effectiveness of nutritional support.

Explanation:

Sandra can take to lower her body fat percentage to eat several, balanced, low-calorie meals throughout the day and to exercise regularly.

When we can't access food for a lengthy period of time, fat is a vital source of stored energy.

There are several steps Sandra can take to lower her body fat percentage:

Exercise regularly: Regular physical activity, such as cardiovascular exercise, resistance training, and high-intensity interval training (HIIT), can help increase muscle mass and reduce body fat.

Eat a healthy diet: Eating a balanced diet that includes plenty of fruits, vegetables, whole grains, lean proteins, and healthy fats can help Sandra maintain a calorie deficit, which is necessary for reducing body fat. Avoiding processed foods, added sugars, and excessive amounts of saturated and trans fats can also be beneficial.

Control portions: Paying attention to portion sizes can help Sandra avoid overeating and maintain a calorie deficit. She can also use tools like measuring cups and a food scale to help control portion sizes.

Stay hydrated: Drinking enough water can help Sandra maintain a healthy metabolism and reduce feelings of hunger.

Get enough sleep: Getting adequate sleep (7-9 hours per night) can help regulate hormones that impact metabolism and hunger, making it easier to maintain a calorie deficit and reduce body fat.

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Answer: the focal length of the CCl4-glass combination is 102.31 cm

Explanation:

Given that;

Index of refraction n1 = 1.55

carbon tetrachloride (CCl4), which has n2 = 1.46

radii of curvature for its surfaces R1 = 4.6cm and R2 = 9.20 cm

the focal length of the CCl4-glass combination = ?

we can determine the focal length using the Formula;

1/f = ( n1 - n2) ( 1/R1 - 1/R)

so we substitute in our values

1/f = ( 1.55 - 1.46 ( 1/4.6 - 1/9.20)

1/f = 0.09 × 0.1086

1/f = 0.009774

f = 1 / 0.009774

f = 102.31 cm

Therefore the focal length of the CCl4-glass combination is 102.31 cm

Answer:

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The mass of Car B is -6000 kg.

To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.

Therefore, we can write the equation for the conservation of momentum as:

(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision

Let's substitute the given values into the equation:

(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)

Simplifying the equation:

20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)

Dividing both sides by -5 m/s:

-4000 kg = 2000 kg + mass of Car B

Subtracting 2000 kg from both sides:

mass of Car B = -4000 kg - 2000 kg

mass of Car B = -6000 kg

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Answer:

F = m a

t = 5 s

V1 = 0    V2 = 36000 m / 3600 sec = 10 m/s

a = (V2 - V1) / t = (10 - 0) m/s / 5 s = 2 m/s^2

F = m a     and   m = F / a = 3000 / 2 = 1500 kg

W = m g = 1500 kg * 9.8 m/s^2 = 14,700 N

Answer:

Explanation:

the lowest points of a transverse wave are called the troughs what is the wavelength of a wave traveling through a rope if the distance from one crest to the next is 1 meter a. 2 m

4. Low points are called troughs

5. Medium: substance through which a wave can travel

A force of 1.5 x 10⁴ N must be applied to the small piston to support the weight of the car.

The hydraulic lift works on the principle of Pascal's law, which states that pressure applied to an enclosed fluid is transmitted uniformly throughout the fluid and acts with equal force on all surfaces of the container. Therefore, the pressure applied to the small piston will be transmitted to the large piston and support the weight of the car.

The pressure applied to the fluid is given by the formula:

pressure = force / area

Since the area of both pistons is the same, the pressure applied to the fluid will be the same on both pistons. Therefore, we can write:

pressure = force on small piston / area of small piston = force on large piston / area of large piston

We know the area of both pistons, so we can rearrange this equation to solve for the force on the small piston:

force on small piston = pressure x area of small piston

The force on the large piston is equal to the weight of the car, which is 1.5 x 10⁴ N. The pressure applied to the fluid is the same on both pistons, so we just need to calculate the pressure using the formula:

pressure = force on large piston / area of large piston

pressure = (1.5 x 10⁴ N) / (0.50 m²) = 3.0 x 10⁴Pa

Now we can calculate the force on the small piston using the formula we derived earlier:

force on small piston = pressure x area of small piston

force on small piston = (3.0 x 10⁴Pa) x (0.50 m²) = 1.5 x 10⁴ N

Therefore, a force of 1.5 x 10⁴ N must be applied to the small piston to support the weight of the car.

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Answer:(a) To find the height of the satellite's orbit if its total energy were 550 MJ greater, we can use the following equation:

K2 + U2 = K1 + U1 + 550 MJ

Since the satellite is in a circular orbit, its kinetic energy is given by:

K = (1/2)mv^2

where m is the mass of the satellite, and v is its velocity.

We can use the following equation to relate the height of the satellite's orbit to its velocity:

v = sqrt(GM/R)

where G is the gravitational constant, M is the mass of the Earth, and R is the radius of the Earth plus the height of the satellite's orbit.

Therefore, we can express the kinetic energy of the satellite in terms of its height:

K = (1/2)m(GM/R)

Using these equations, we can rewrite the conservation of energy equation as:

(1/2)m(GM/(R1+h1)) - GMm/(R1+h1) = (1/2)m(GM/(R2+h2)) - GMm/(R2+h2) + 550 MJ

where R1 is the radius of the Earth, and R2 is the radius of the Earth plus h2.

Simplifying and solving for h2, we get:

h2 = [(GMm/(R1+h1)) - (GMm/(R2+h2)) - 550 MJ/(GM/(R2+h2))]^(-1) - R2

Plugging in the given values, we get:

h2 = 931 km

Therefore, the height of the satellite's orbit would be 931 km if its total energy were 550 MJ greater.

(b) To find the difference in the system's kinetic energy, we can use the following equation:

Delta K = K2 - K1

Substituting the expressions for K1 and K2, we get:

Delta K = (1/2)m(GM/(R2+h2)) - (1/2)m(GM/(R1+h1))

Plugging in the given values, we get:

Delta K = -7.5 x 10^9 J

The negative sign indicates that the system's kinetic energy has decreased.

(c) To find the difference in the system's potential energy, we can use the following equation:

Delta U = U2 - U1

Substituting the expressions for U1 and U2, we get:

Delta U = -GMm/(R2+h2) + GMm/(R1+h1)

Plugging in the given values, we get:

Delta U = 5.9 x 10^9 J

The positive sign indicates that the system's potential energy has increased.

Explanation:

The part of a road vehicle which must be tested to ensure that there is sufficient friction to stop the vehicle in an emergency is the tyre.

This is referred to as a force that resists the motion of one object against another when they roll or slide against each other.

When dealing with braking, the main factor is to have sufficient friction between the road surface and tyre to bring the vehicle to a standstill. If the tyres are wornout there won't be enough friction to make the vehicle stop during emergencies which is therefore the reason why it was chosen as the correct choice.

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Answer:

0.2 km/minute or 12 km/h

Explanation:

All you have to do is divide distance by time to find the speed. 1/5 km/min is the speed into which we simplify to 0.2 km/min. I then multiplied by 60(numerator and denominator) since there are 60 minutes in an hour to get 12 km/h.

The resultant force that water exerts on the overhang sea wall along abc is 179 kN.

Force is a physical quantity that describes the interaction between two objects, such as a push or a pull. It is defined as any influence that causes an object to undergo a change in motion or deformation. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction.

Component that is horizontal. Because AB is horizontal, there is no horizontal component. The horizontal component of BC's force is.

(Fbc)h =γwhˉA=(1000kg/m3)(9.81m/s2)(1.5m+21(2m))(2m(2m))=98.1(103)N.

Component that is vertical. The weight of the water contained in blocks Abefa and Bcdeb (shown shaded in Fig. a) is equal to the force on AB and the vertical component of the force on BC. Here,

Aabefa=1.5m(2.5m)=3.75m2and

2Abcdeb=(3.5m)(2m)–4π(2m)2=(7–p)m2. Then,

Fab=γwVabefa=(1000kg/m3)(9.81m/s2)[(3.75m2)(2m)] =73.575(103)N=73.6N (FBC)v=γwVbcdeb=(1000kg/m3)(9.81m/s2)[(7–π)m2(2m)] =75.702(103)N

Therefore,

Fbc=(Fbc)²h2+(Fbc)²v2=√[98.1(10³)N]²+[75.702(10³)N]²=123.91(10³)N=124KN

FR²   =(Fbc)²H2+[Fab+(Fbc)v]²

==[98.1(10³)N]² + [(73.6(10³)N)²+75.702(10³)N²]

=178.6(10³)N = 179 kN.

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Answer:

d. f

Explanation:

Based on the principle of operation of transformer, when a.c voltage is applied at the terminal of the primary coil (input coil), an alternating magnetic flux is produced in the iron core which links the secondary coil (output coil).

Also, an alternating e.m.f of the same frequency as that of primary coil (input coil) will be induced in the secondary coil (output coil) by mutual inductance.

Thus, If the input frequency is "f" then the output frequency will be "f" (since the frequency will be the same).

The correct option is "D"

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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Answer:

6000 joules

Explanation:

I jus learned dis

Answer:6000j

Explanation:

Hope that helps

Answer:

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Explanation:

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We can't see the moon in the new moon since the sun is quite far from the earth.

We know the moon to be one of the heavenly bodies. The heavenly bodies are those bodies that we tend to see in the outer space. There are several heavenly bodies that we have out there and they can be classified based on weather or not the bodies do produce light.

The heavenly bodies that produce light as said to be luminous bodies while the heavenly bodies that do not produce light are said to be non luminous bodies.

Now we can see that the moon s a non luminous body and it depends on the sun so as to be able to give light. In this case, we know that the moon may sometimes be hidden from sight and can not be seen and this  occurs in the course of the new moon because the side of the moon that gets the light lies at a far away position  from the earth.

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Explanation:

To find the mass of the object, we can use the formula for kinetic energy:

Kinetic energy (KE) = (1/2) * mass * velocity^2

Given that the kinetic energy is 426 J and the velocity is 13 m/s, we can rearrange the equation to solve for the mass:

mass = (2 * KE) / (velocity^2)

Substituting the given values:

mass = (2 * 426 J) / (13 m/s)^2

mass = (2 * 426 J) / (169 m^2/s^2)

mass = 852 J / 169 m^2/s^2

mass = 5.04 kg

Therefore, the mass of the object is 5.04 kg.

Let's call the speed of the current "c". Then, the speed of the boat relative to the water when it is going upstream is 24 - c mph, and the speed of the boat relative to the water when it is going downstream is 24 + c mph.

Using the time it takes to travel the given distances, we can set up the following equation:

(54) / (24 - c) = (90) / (24 + c)

Expanding and solving for c, we find that:

c = 4 mph

So the speed of the current is 4 mph.

Answer: Upstream: 24 - 6 = 18  --->   54 = 18 x?  --->  ? = 54/18 = 3 hours

   (24 - 6)x 3 = 18 x 3 = 54 miles

   (24 + 6) x 3 = 30 x 3 = 90 miles

The speed of the current is 6 mph.

Time is 3 hours