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If the magnification is -4 the the image is larger and is it inverted in nature.
The magnification of the body is given is -4, here the signs show the nature of the image and the numerical value is the times to which the object has been magnified. Here, it is inverted because there is negative sign and it is enlarged as the magnification is more than 1.
Therefore, a magnification of -4 indicates that the image is both inverted and larger than the object. The resultant picture will be a larger, inverted version of the object if it is seen via a lens or mirror with a magnification of -4.
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Related Questions
The energy goes from _____ to the _____ above it.
Answers
Answer:
The energy goes from the ground state to the excited states above it.
true/false. Article 130, Work Involving Electrical Hazards, by definition, covers work involving four hazards caused by either proximity or equipment failure.
Answers
This statement is False, Article 130, Work Involving Electrical Hazards, by definition, covers work involving four hazards caused by either proximity or equipment failure.
Electrical hazards refer to the potential risks associated with the use of electricity, which can cause injury or even death. These hazards can arise from a variety of sources, including electrical systems, appliances, tools, and wiring.
Electrical hazards can include electrical shock, burns, and electrocution. Electrical shock occurs when a person comes into contact with an electrical current and can cause muscle contractions, respiratory failure, and cardiac arrest. Burns can result from direct contact with an electrical current or from an arc flash, which is a sudden release of electrical energy. Electrocution is a severe form of electrical shock that can result in death. It is essential to receive proper training and education on electrical safety and to always be aware of potential electrical hazards in the environment.
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An airplane is flying in horizontal flight at a constant velocity. The weight of the airplane is 40,000 N. The wings produce a lift force that is perpendicular to the wings and a drag force that is parallel to the wings. The engine produces a forward thrust force of 2,000 N. Which of the following statements is true?
a. The lift force on the airplane is zero.
b. The drag force on the airplane is zero.
c. The lift force on the airplane is 42,000 N upward.
d. The drag force on the airplane is 38,000 N downward.
e. The drag force on the airplane is 2,000 N backward.
Answers
Answer:
a
Explanation:
the plane is not going up and the rest are true
Describe the key ideas that are part of cell theory.
Answers
Answer:
Search mo sa goegle hahaha
Please help me with this question.
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With 20 windings, the generator will produce a higher EMF and, consequently, a larger current. This increased current will provide more power to the light bulb, resulting in a brighter illumination compared to the dim illumination observed with only 5 windings.
When you increase the number of wire windings in the generator from 5 to 20, the effect on the light bulb will be a brighter illumination. The brightness of the light bulb is directly proportional to the number of windings in the generator.
By increasing the number of windings, you are increasing the amount of wire wrapped around the magnet. This results in a higher number of turns per unit length, leading to an increased magnetic flux passing through the wire coils.
According to Faraday's law of electromagnetic induction, a change in magnetic flux induces an electromotive force (EMF) in a conductor, which in this case is the copper wire. The induced EMF causes electric current to flow through the wire, creating a flow of electrons.
The 30-W light bulb requires a certain amount of electrical power to produce its specified brightness. With 20 windings, the generator will produce a higher EMF and, consequently, a larger current. This increased current will provide more power to the light bulb, resulting in a brighter illumination compared to the dim illumination observed with only 5 windings.
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Four point masses 2kg, 4kg, 6kg and 8kg are placed at the corners of Square ABCD of 2cm long respectively. Find the Position of centre of mass of the system from the corner A.
please help me I give you 50 coins
Answers
Let's call the mass at point A M1, the mass at point B M2, the mass at point C M3, and the mass at point D M4.
The x-coordinate of the center of mass is given by:
x_cm = (M1*x1 + M2*x2 + M3*x3 + M4*x4) / (M1 + M2 + M3 + M4)
The y-coordinate of the center of mass is given by:
y_cm = (M1*y1 + M2*y2 + M3*y3 + M4*y4) / (M1 + M2 + M3 + M4)
We know that the distance between any two adjacent corners of the square is 2cm. Therefore, we can say that the coordinates of the four masses are:
M1 = 2kg at (0,0)
M2 = 4kg at (2,0)
M3 = 6kg at (2,2)
M4 = 8kg at (0,2)
Substituting these values into the equations above, we get:
x_cm = (2*0 + 4*2 + 6*2 + 8*0) / (2 + 4 + 6 + 8) = 2
y_cm = (2*0 + 4*0 + 6*2 + 8*2) / (2 + 4 + 6 + 8) = 2
Therefore, the center of mass of the system is located at a distance of 2cm from corner A along the x-axis and 2cm from corner A along the y-axis.
Taking care of yourself can sometimes be hard work and can even lead to feelings of
Answers
Answer:
deception
Explanation:
An amusement park ride called the Rotor debuted in 1955 in Germany. Passengers stand in the cylindrical drum of the Rotor as it rotates around its axis. Once the Rotor reaches its operating speed, the floor drops but the riders remain pinned against the wall of the cylinder. Suppose the cylinder makes 26.0 rev/min and has a radius of 3.70 m. 1) What is the coefficient of static friction between the wall of the cylinder and the backs of the riders
Answers
Answer:
μs = 0.36
Explanation:
While the drum is rotating, the riders, in order to keep in a circular movement, are accelerated towards the center of the drum.This acceleration is produced by the centripetal force.Now, this force is not a different type of force, is the net force acting on the riders in this direction.Since the riders have their backs against the wall, and the normal force between the riders and the wall is perpendicular to the wall and aiming out of it, it is easily seen that this normal force is the same centripetal force.In the vertical direction, we have two forces acting on the riders: the force of gravity (which we call weight) downward, and the friction force, that will oppose to the relative movement between the riders and the wall, going upward.When this force be equal to the weight, it will have the maximum possible value, which can be written as follows:\(F_{frmax} = \mu_{s}* F_{n} = m * g (1)\)
where μs= coefficient of static friction (our unknown)As we have already said Fn = Fc.The value of the centripetal force, is related with the angular velocity ω and the radius of the drum r, as follows:\(F_{n} = m* \omega^{2} * r (2)\)
Replacing (2) in (1), simplifying and rearranging terms, we can solve for μs, as follows:\(\mu_{s} = \frac{g}{\omega^{2} r} (3)\)
Prior to replace ω for its value, is convenient to convert it from rev/min to rad/sec, as follows:\(\omega = 26.0 \frac{rev}{min} * \frac{1min}{60 sec} *\frac{2*\pi rad }{1 rev} = 2.72 rad/sec (4)\)
Replacing g, ω and r in (3):\(\mu_{s} = \frac{g}{\omega^{2} r} = \frac{9.8m/s2}{(2.72rad/sec)^{2} *3.7 m} = 0.36 (5)\)Describe different atoms of the same element.
Answers
Explanation:
Isotopes are atoms with different atomic masses which have the same atomic number. The atoms of different isotopes are atoms of the same chemical element; they differ in the number of neutrons in the nucleus.
Answer:
The atoms of a chemical element can exist in different types. These are called isotopes. They have the same number of protons (and electrons), but different numbers of neutrons. Different isotopes of the same element have different masses.
Explanation:
A 59-kgkg person riding a bike puts all her weight on each pedal when climbing a hill. The pedals rotate in a circle of radius 18 cmcm . What is the maximum torque she exerts?
Answers
A 59-kg person riding a bike puts all her weight on each pedal when climbing a hill. The pedals rotate in a circle of radius 18 cm. the maximum torque she exerts is 104.07Nm.
given that :
mass ,m = 59 kg
radius , r = 18 cm
The force , F = mg
F = 59 × 9.8
F = 578.2 N
The torque is expressed as:
torque = force × radius
torque = 578.2 N × 0.18 m
torque = 104.07 Nm
Thus, if the mass is 59 kg and the radius is 18 cm then maximum torque she exerts is the 104.07 Nm.
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what is scientific learning
Answers
Answer:
the learning which is gained through observation and experimentation
Select all that apply.
A chemist is likely to do which of the following?
analyze the ingredients in ice cream
determine why planets orbit the Sun
determine how to separate gasoline from other substances in petroleum
determine the force necessary to push a button through a button hole
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Answer:
Determine how to separate gasoline from other substances in petroleum
calculate the boyant force on 1.0x10^7 of solid steel completely submeg in water and compete this with steel weight
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The required buoyant force of the solid steel submerged in water is 124681934 N.
What is force?Force is defined as an object which is in a state of motion then its rate of change of momentum is called force.
Here,
To calculate the buoyant force on the steel object, we need to first determine the volume of the steel object. Let's assume the density of steel is 7,860 kg/m³.
Mass of the steel object = 1.0x10⁷ kg
Density of steel = 7,860 kg/m³
The volume of steel object = Mass of steel object / Density of steel
= (1.0x10⁷ kg) / (7,860 kg/m³)
= 1271.78 m³
Buoyant force = Weight of displaced water
= Density of water x Volume of displaced water x gravitational acceleration
= (1000 kg/m³) x (1271.78 m³) x (9.81 m/s²)
= 124681934 N
The weight of the steel object is given as 1.0x10⁷ N.
Comparing the buoyant force with the weight of the steel object, we find that the buoyant force is greater than the weight of the steel object. This means that the steel object will float in water, as the buoyant force is enough to counteract the weight of the object.
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Two uncharged spheres are separated by 2.60 m. If 1.90 x 1012 electrons are removed from one sphere and placed on the other determine the magnitude of the Coulomb force (im N) an one of the spheres, treating the spheres as point charges.
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The magnitude of the Coulomb force between the spheres, when 1.90 x \(10^{12\) electrons are transferred, is 2.34 x \(10^{-4\) Newtons.
To determine the magnitude of the Coulomb force between two uncharged spheres.
Given that 1.90 x \(10^{12\) electrons are removed from one sphere and placed on the other, we need to calculate the charge on each sphere. The charge on a single electron is -1.6 x \(10^{-19\) coulombs, so the charge transferred from one sphere to the other is:
Q = (1.90 x \(10^{12\)) × (-1.6 x \(10^{-19\)) = -3.04 x \(10^{-7\) coulombs
Since one sphere loses electrons and becomes positively charged, while the other gains electrons and becomes negatively charged, the magnitude of the charge on each sphere is:
|Q| = 3.04 x \(10^{-7\) coulombs
Now, we can calculate the magnitude of the Coulomb force using Coulomb's law:
F = k * (|Q1| * |Q2|) / \(r^2\)
where k is the electrostatic constant (k = 8.99 x \(10^{9}\) N \(m^{2}\)/\(C^{2}\)) and r is the distance between the centers of the spheres (r = 2.60 m).
Plugging in the values, we get:
F = (8.99 x \(10^{9}\) N \(m^{2}\)/\(C^{2}\)) * (3.04 x \(10^{-7\)C)² / \((2.60 m)^2\)
Simplifying this expression, we find:
F ≈ 2.34 x \(10^{-4\) N
Therefore, the magnitude of the Coulomb force between the spheres, when 1.90 x \(10^{12\) electrons are transferred, is approximately 2.34 x \(10^{-4\) Newtons.
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A tank, in the shape of a cube with each side measuring 2 meters, is half-full of water. Above the water is air that is pressurized to 5 kPa. Calculate the resultant force on one side of the tank due to the air and water (ignore atmospheric pressure) and determine the height of this force above the bottom of the tank.
Answers
Answer:
Explanation:
The tank is half full so height of water level is at 1 m . Centre of gravity of water will be at height of .5 m . Pressure will act at this point .
Pressure = h d g where h is height of centre of mass of water column , d is density of water and g is acceleration due to gravity .
Pressure of water column = .5 x 10³ x 9.8 = 4.9 k Pa .
Air is pressurized to 5 kPa so
resultant pressure on one side of the tank due to the air and water
= 4.9 + 5 kPa = 9.9 kPa .
Total force on one face = pressure x area of one face under water
= 9.9 x 10³ x .5 x 2²
= 19.8 kN .
Help pleasessssssssssssss
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Sorry I had the answer but it wont let me type numbers :(.:
Please help me with this and if I have good answer u will be marked as brilliant !!!!
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you made $100,000 this year. you have $0 in adjustments, $11,500 in deductions and $7,300 in exemptions. What is your taxable increase?
Answers
The tax rate you will pay is displayed in tax brackets for each category of taxable income.
Thus, For instance, in 2022, the first $10,275 of your taxable income is subject to the lowest tax rate of 10% if you are single.
Up until the maximum amount of your taxable income, the following portion of your income is taxed at a rate of 12%.
As taxable income rises, the tax rate rises under the progressive tax system. Overall, this has the result that taxpayers with higher incomes often pay a greater rate of income tax than taxpayers with lower incomes.
Thus, The tax rate you will pay is displayed in tax brackets for each category of taxable income.
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You and your friend each drive 100.0 km. You travel at 30.0 km/h. Your friend travels at 45 km/h. How long will your friend be waiting for you at the end of the trip?.
Answers
Answer:
See below
Explanation:
100 km / 45 km/hr = 2.222 hr
100 km / 30 km/hr =3.3333 hr
Difference = 1.111 hr = 1 hr 6 2/3 min
if you drop your textbook it falls because the earth pulls it downward. at the same time, your textbook pulls on the earth with a force that is group of answer choices zero. equal to the downward pull on the textbook and in the same direction. immeasurably small. equal to the downward pull on the textbook but in the opposite direction.
Answers
The force that your textbook exerts on the Earth is immeasurably small, since the mass of the textbook is much, much smaller than the mass of the Earth.
What is force?Force is a push or pull on an object due to its interaction with another object. Force is a vector quantity that is described by its magnitude and direction. It is typically measured in Newtons and represented by the symbol F. Force can cause an object to accelerate, change its direction, or change its shape. Force is an integral part of physics and is governed by the laws of motion.
This force is equal to the downward pull on the textbook but in the opposite direction, meaning that it is trying to pull the Earth up, canceling out the downward force. However, since the force exerted by the textbook is so small, it is not enough to counteract the pull of gravity, and thus the textbook falls.
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for the primitive yo-yo in fig, to find the downward acceleration of the cylinder and the tension in the string. you can take the toy as solid cylinder and icm=1/2mr2 , where m is the mass of the yo-yo toy
Answers
The downward acceleration of the solid cylinder at the given tension in the string is determined as 2Tr/MR.
Downward acceleration of the cylinder
The downward acceleration of the solid cylinder is determined from the principle of conservation of angular momentum as shown below;
Iα = Tr
where;
I is moment of inertia of the solid cylinderα is angular acceleration of the cylinderT is tension in the stringr is length of the stringα = Tr/I
\(\frac{a}{R} = \frac{Tr}{I} \\\\\frac{a}{R} = \frac{Tr}{\frac{1}{2} MR^2}\\\\\frac{a}{R} =\frac{2Tr}{MR^2} \\\\a = \frac{2Tr}{MR}\)
where;
a is the downward acceleration of the solid cylinderR is radius of the cylinderThus, the downward acceleration of the solid cylinder at the given tension in the string is determined as 2Tr/MR.
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What is the process where light bounces back from an object at the same angle and intensity as it. is received by the object?
Answers
Answer: It is Reflection
Explanation: Reflection occurs when incoming solar radiation bounces back from an object or surface that it strikes in the atmosphere, on land, or water, and is not transformed into heat.
An object with a mass of 7 kg accelerates 8 m/s2 when an unknown force is applied to it. What is the amount of the force?
Answers
The amount of force applied to the 7kg object that caused it to accelerate at 8m/s² is 56 newtons.
What is the force applied to the object?A force is simply a push or a pull of an object resulting from the object's interaction with another object.
From newton's second law;
Force = mass × acceleration
Given the data in the question;
Mass of the object = 7kgAcceleration = 8m/s²Applied force = ?Plug the given values into the formula to determine the applied force.
Force = mass × acceleration
Force = 7kg × 8m/s²
Force = 56kgm/s²
Force = 56 N
Therefore, the applied force is 56 newtons.
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A
where light does not strike.
A) mirror
C) wave
is an area
B) transparent
D) shadow
q
Answers
Answer:
d
Explanation:
because when an object stand in front of light, light bends around the other and doesn't go through it
A toy is undergoing SHM on the end of a horizontal spring with force constant 310 N/m . When the toy is 0.120 m from its equilibrium position, it is observed to have a speed of 3 m/s and a total energy of 3.6 J .
1.) Find the mass of the toy.
2.) Find the amplitude of the motion.
3.) Find the maximum speed obtained by the object during its motion.
Answers
Answer:
1) the mass of the toy is 0.304 kg
2) the amplitude of the motion is 0.1524 m
3) the maximum speed obtained by the object during its motion is 4.87 m/s
Explanation:
Given the data in the question;
force constant of spring k = 310 N/m
position of toy x = 0.120 m
speed v = 3 m/s
Total energy E = 3.6 J
let m represent mass of toy.
1.) Find the mass of the toy.
we know that; The total energy of the system equals the sum of kinetic energy of the toy and the potential energy of the spring;
E = \(\frac{1}{2}\)kx² + \(\frac{1}{2}\)mv²
we substitute
3.6 = ( \(\frac{1}{2}\) × 310 × (0.120)² ) + ( \(\frac{1}{2}\) × m × (3)² )
3.6 = 2.232 + 4.5m
3.6 - 2.232 = 4.5m
1.368 = 4.5m
m = 1.368 / 4.5
m = 0.304 kg
Therefore, the mass of the toy is 0.304 kg
2) Find the amplitude of the motion.
we know that;
E = \(\frac{1}{2}\)kA²
where A is the amplitude of the motion,
we substitute
3.6 = \(\frac{1}{2}\) × 310 × A²
3.6 = 155 × A²
A² = 3.6 / 155
A² = 0.0232258
A = √0.0232258
A = 0.1524 m
Therefore, the amplitude of the motion is 0.1524 m
3) Find the maximum speed obtained by the object during its motion;
we know that;
E = \(\frac{1}{2}\)m\(v_{max\)²
where \(v_{max\) is the maximum speed
so we substitute
3.6 = \(\frac{1}{2}\) × 0.304 × \(v_{max\)²
3.6 = 0.152 × \(v_{max\)²
\(v_{max\)² = 3.6 / 0.152
\(v_{max\)² = 23.6842
\(v_{max\)² = √23.6842
\(v_{max\)² = 4.8664 ≈ 4.87 m/s
Therefore, the maximum speed obtained by the object during its motion is 4.87 m/s
Can someone solve this question for me, please?
Answers
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Mee: 5324611502
Pass: 1234
How can a spinning ball have more lift than one that is not spinning?
Why does the direction of the spin matter?
Relate Bernoulli's principle to the sport of your choice.
Answers
The differential in air pressure on the ball's various sides allows a spinning ball to provide more lift than a non-spinning ball, in accordance with Bernoulli's principle.
According to Bernoulli's principle, the pressure of a fluid decreases as the fluid's velocity increases. A ball is pushed in the opposite direction by a force produced by lower pressure, possibly producing more lift.
The lift is given to the ball by the air because the right side air moves in the same direction of the motion of the ball while the lift side goes into the opposite direction that creates a difference in the air pressure and more lift is the result.
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If the coefficient of kinetic friction between a 24-kg crate and the floor is 0.25 what horizontal force is required to move the crate at a steady speed across the floor?
Answers
The horizontal force required to move the crate at a steady speed across the floor will be 58.86 N.
What is the friction force?
It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).
The given data in the problem is;
Mass,m = 24 kg
The coefficient of kinetic friction, μ=0.25
The friction force is defined as the product of the coefficient of friction and normal reaction.
f=μN
If there is no other force, the horizontal force is equal to the friction force;
F=f
The horizontal force required to move the crate at a steady speed across the floor is found as;
F = μN
The normal reaction force is;
N=W
N=mg
F = μmg
F=0.25 × 24-kg × 9.81 m/s²
F = 58.86 N
Hence horizontal force is required to move the crate at a steady speed across the floor will be 58.86 N.
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Do 2. A cyclist starts from rest and accelerates along a straight path to a speed of
12.15 m/s in a time of 4.5 seconds.
What is the cyclist's acceleration to the nearest tenth?
O
54.7 m/s2
o
24.3 m/s?
2.7 m/s2
De
3.4 m/s?
Answers
The cyclist's acceleration to the nearest tenth is: C. 2.7 \(m/s^2\).
Given the following data:
Initial velocity = 0 m/s (since the cyclist starts from rest).Final velocity = 12.5 m/s.Time = 4.5 seconds.To find the cyclist's acceleration to the nearest tenth:
Acceleration is calculated by subtracting the initial velocity from the final velocity and dividing by the time.
Mathematically, acceleration is given by the formula;
\(A = \frac{V - U}{t}\)
Where:
A is the acceleration.V is the final velocity.U is the initial velocity.t is the time measured in seconds.Substituting the given parameters into the formula, we have;
\(A = \frac{12.5\; - \;0}{4.5} \\\\A = \frac{12.5}{4.5}\)
Acceleration, A = 2.7 \(m/s^2\)
Therefore, the cyclist's acceleration to the nearest tenth is 2.7 \(m/s^2\).
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A car is travelling in a straight line and has its velocity uniformly reduced from 20 m * s ^ - 1 to 12m * s ^ - 1 in a distance of 80 m. The car the travels at the lower velocity for 1 minute, and then decelerates uniformly to rest in a further 12 sec. show the whole journey on a velocity-time graph and calculate
(i) the initial deceleration and the time taken to travel 80 m.
(ii) the final deceleration
(iii) the total displacement for the whole journey
Answers
i) The initial deceleration of the car is -1.6 m/s² and the time taken is 5 seconds
ii) The final deceleration is -1 m/s²
iii) The total dispalcement = 1016 m
What is the initial deceleration of the car?The initial deceleration of the car is given by the formula below:
v² = u² + 2as
where;
v is the initial velocityu is the final velocitya is acceleration/decelerations is the displacementSolving for a;
12² = 20² + 2 * a * 80
a = -1.6 m/s²
Time taken, t = v - u / a
t = 12 - 20 / (-1.6)
t = 5 seconds
Final deceleration:
a = v - u / t
a = 0 - 12 / 12
a = -1 m/s²
iii) Displacement at constant velocity = 12 * 1 * 60
Displacement at constant velocity = 720 m
Final displacement, s = ut + 0.5at²
s = 12 * 12 + 0.5 * 1 * 12²
s = 216 m
Total dispalcement = 80 + 720 + 216
Total dispalcement = 1016 m
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