If a horse can trot with an average velocity of 13 km/h, how far can it travel in
8 hours?
A. 2 km
B. 104 km
C. 35 km
D. 78 k

Given :

A badminton shuttlecock leaves the racquet traveling 30 m/s.

It goes over the net 0.5  seconds later with a speed of 10 m/s.

To Find :

The average acceleration of the shuttlecock.

Solution :

We know, average acceleration(a) is given by :

\(a = \dfrac{\text{Change in speed}}{\text{Time taken }}\\\\a = \dfrac{10-30}{0.5 }\ m/s^2\\\\a = -40\ m/s^2\)

Therefore, the average acceleration is -40 m/s².

Answer:

Force of gravity, F = 70 N      

Explanation:

It is required to find the force of gravity acting on an object that has a mass of 7 kg. Force of gravity always acts in downward direction.

The force of gravity is equal to the weight of an object. It is given by :

\(F=mg\)

g = acceleration due to gravity, for Earth, g = 10 m/s²

So,

\(F=7\times 10\\\\F=70\ N\)

So, 70 N of force of acting on an object.

D. Basketball

the answer is Basketball.

it is the most popular youth team sport for girls

in the united states

Answer:

the resultant wave is the algebraic sum of all the waves reaching that particular point at a given time.

Explanation:

imagine two or three waves reaching a particular particle x at the same time. The particle will vibrate those waves and give out or transmit a resultant wave which is the algebraic sum of the incoming two waves. If both the waves have the same amplitude and phase, the resultant wave will be amplified. However if the waves have the same amplitude and equal but opposite phase then the resultant wave will be a straight line

Voltage = (current) x (resistance)

Voltage = (4.00 A) x (330 Ω)

Voltage = 1,320 V  (D)

Answer:

Lx W

Explanation:

Okay, here are the steps to calculate the full distance traveled when an object is thrown at a certain speed and angle:

You have the initial velocity (v): 35 m/s

You have the launch angle (θ): 45 degrees

We need to split the initial velocity into its horizontal (vx) and vertical (vy) components.

To calculate vx (horizontal component):

vx = v * cosθ

vx = 35 * cos(45) = 24.7 m/s

To calculate vy (vertical component):

vy = v * sinθ

vy = 35 * sin(45) = 24.7 m/s

We can calculate the horizontal distance (d) traveled using:

d = vx * t (where t is time)

Since there is no air resistance, the vertical velocity (vy) will remain constant. This means the time the object is in the air is:

t = vy / g (where g is acceleration due to gravity, 9.8 m/s^2)

t = 24.7 / 9.8 = 2.52 seconds

Now we can calculate the full horizontal distance traveled:

d = vx * t

d = 24.7 * 2.52

= 62.3 meters

So the full distance the object will travel when thrown at 35 m/s at a 45 degree angle is approximately 62 meters.

Let me know if you have any other questions!

Answer:

To calculate the full distance traveled by an object thrown at a velocity of 35 m/s at an angle of 45 degrees, we need to consider the horizontal and vertical components of the motion separately.

The horizontal component of the motion remains constant throughout the trajectory and is given by:

Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)

In this case, the initial velocity is 35 m/s, the angle is 45 degrees, and we need to find the time of flight.

The time of flight can be calculated using the vertical component of the motion. The vertical motion can be described using the equation:

Vertical displacement = (Initial velocity * sin(angle))^2 / (2 * acceleration)

Where the initial velocity is 35 m/s, the angle is 45 degrees, and the acceleration is the acceleration due to gravity, approximately 9.8 m/s^2.

The vertical displacement is zero at the highest point of the trajectory since the object comes back down to the same height it was launched from. So we can solve the equation for the time of flight.

Using these calculations, we can find the horizontal distance traveled by the object.

Let's calculate step by step:

Step 1: Calculate the time of flight

Vertical displacement = 0 (at the highest point)

0 = (35 * sin(45))^2 / (2 * 9.8)

0 = (24.75^2) / 19.6

0 = 616.0125 / 19.6

0 = 31.43

Step 2: Calculate the time of flight

Vertical displacement = (Initial velocity * sin(angle)) * time - (1/2) * acceleration * time^2

0 = (35 * sin(45)) * time - (1/2) * 9.8 * time^2

0 = 24.75 * time - 4.9 * time^2

4.9 * time^2 - 24.75 * time = 0

time * (4.9 * time - 24.75) = 0

time = 0 (initial point) or 24.75 / 4.9

time = 5.05 seconds

Step 3: Calculate the horizontal distance

Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)

Horizontal distance = 35 * 5.05 * cos(45)

Horizontal distance = 35 * 5.05 * (sqrt(2)/2)

Horizontal distance = 88.96 meters

The answers are 1) The value of R2 is not relevant as it implies a downward force on the plank, 2) The reactions at C and D are 66.3 N and 90 N, respectively, and 3) The vertical force at B to lift the plank clear of D is 686.4 N. The reaction at C is zero, and the reaction at D is 61.4 kg.

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Answer:

- 7.088 m/s²

Explanation:

As we know that,

★ Acceleration = Change in velocity/Time

→ a = (v - u)/t

Here,

→ a = (10.9 m/s - 27.7 m/s)/2.37 s

→ a = -16.8/2.37 m/s²

→ a = -7.088 m/s² [Answer]

Negative sign denotes that the velocity is decreasing.

Answer:

\(\boxed {\boxed {\sf -7.09 \ m/s^2}}\)

Explanation:

We are asked to find the acceleration of a car. Acceleration is the change in velocity with respect to time. We will use the following formula:

\(a= \frac {v_f-v_i}{t}\)

In this formula, \(v_f\) is the final velocity, \(v_i\) is the initial velocity, and \(t\) is the time. The car slows down from 27.7 meters per second to 10.9 meters per second in 2.37 seconds. Therefore:

Substitute the values into the formula.

\(a= \frac{ 10.9 m/s-27.7 m/s}{2.37 \ s}\)

Solve the numerator.

\(a= \frac{-16.8 \ m/s}{2.37 \ s}\)

Divide.

\(a= -7.088607595 \ m/s/s\)

\(a= -7.088607595 \ m/s^2\)

The original measurements of velocity and time have 3 significant figures, so our answer must have the same. For the number we found, that is the hundredth place. The 8 in the thousandth place tells us to round the 8 in the hundredth place up to a 9.

\(a \approx - 7.09 \ m/s^2\)

The acceleration of the car is approximately -7.09 meters per second squared. The acceleration is negative because the car is slowing down.

Answer:

★ For example, a useful analogy for explaining the Earth's gravity force is that the Earth can pull on objects without touching them just like a magnet can affect other objects without touching them. In Addition, the main notion to convey here is that forces can act at a distance with no perceivable substance in between.

Explanation:

Hope you have a great day :)

No, objects have no need to touch for interaction.

We know that there are some forces which interact with the objects from far distance without touching such as gravity of the earth. The Earth's gravitational force is that the Earth can pull on objects without touching them so we can conclude that objects have no need to touch for interaction with one another.

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We are given:

Mass of object (m) = 12 kg

acceleration (a) = 6 m/s²

Solving for the Force:

From newton's second law of motion:

F = ma

replacing the variables

F = 12*6

F = 72N

vi = initial speed = 75 miles/hour =167.7 m/s

vf = final speed = 25 miles/hour = 55.9234 m/s

t = time = 2.5 seconds=

a = acceleration

Replacing with the values given:

a = 44.74 m/s^2

We have a vector 6.28 units long in 105° direction

Therefore the vector C is

Answer:

TRUE

Explanation:

Gases move from high-pressure area to low-pressure area

Answer:

d

Explanation:

Answer:

False

Explanation:

I'm not sure but from what I've learned everything has matter.

The small car and the truck experience the same magnitude of momentum change.

The given problem is based on the concept of momentum and law based on it, which is known as Conservation of momentum. As per the law of conservation of momentum, "Whenever there is a collision between the two objects, then the change in momentum before collision is equal to the change in momentum after the collision".

From the conservation of momentum, whatever magnitude of momentum is lost by one of the vehicles will be gained by the other vehicle and momentum will be conserved.

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Answer:

it has 40 potential/ 20 kinetic energy/ do the math

Explanation:

energy

Answer:

The time it takes the ball to stop is 0.021 s.

Explanation:

Given;

mass of the softball, m = 720 g = 0.72 kg

velocity of the ball, v = 15.0 m/s

applied force, F = 520 N

Apply Newton's second law of motion, to determine the time it takes the ball to stop;

\(F = ma = \frac{mv}{t} \\\\t = \frac{mv}{F} \\\\t = \frac{0.72 \ \times \ 15}{520} \\\\t = 0.021 \ s \\\)

Therefore, the time it takes the ball to stop is 0.021 s.

Nuclear fusion reaction is mainly responsible for the cause of energy radiation from the sun.

Solar energy is created due to this nuclear fusion. The discharge of energy in the sun is 10²⁶ joules per second

There is nuclear fusion of hydrogen into helium molecules.

Takes place in solar nucleus/plasma, because this reaction can occur only in high temperature.

The special type of fusion that take place in sun is proton-proton fusion.

This kind of fusion is responsible for the cause of energy radiance and is a very efficient method of producing energy.

The 2 condition which help H-H atoms come together is large mass of the sun and the force of gravity.

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One in twelve males have color blindness whereas One in two-hundred females have color blindness. Thus, Option D is correct.

Color blindness is the ability to distinguish different colors. It is hard to differentiate the colors between the same color family. A person with color blindness can not able to see red and green, and can able to see grey, black, and white. It is often inherited.

A person with color blindness can not able to differentiate the colors between red and green. There are three types of color blindness they are Deuteranomaly (difficulty with red-green color blindness and it makes green look redder), Protanomaly(red look greener), Protanopia, and deuteranopia (difficulty in identifying red and green). It is cured by using proper contact lenses.

Thus, One in twelve males has color blindness. Hence, the ideal solution is option D.

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Explanation:

A concave lens is also known as a diverging lens because it is shaped round inwards at the centre and bulges outwards through the edges, making the light diverge. They are used to treat myopia as they make faraway objects look smaller than they are.

Answer:

B

Explanation:

B

Answer:

1) 1.67eV

2) 505nm

Explanation:

The maximum kinetic energy of photoelectrons ,

 KEmax=λhc−W=(0.3×10−6)(1.6×10−19)(6.62×10−34)(3×108)eV−2.46eV=1.67eV

If λ0 is the cut-off wavelength, W=λ0hc

or λ0=Whc=2.46×1.6×10−19(6.62×10−34)(3×108)=5.05×10−7m=505×10−9=505nm

We know that the work function is the minimum photon energy for taking place of photoelectric effect. 

To find the speed of a star in which the hydrogen transition from level 2 to level 1 appears at wavelength 120.8 nm, we can use the Doppler effect. The Doppler effect states that the observed wavelength of light (λobs) emitted by a moving object will be shifted relative to its rest wavelength (λrest) by an amount proportional to the object's velocity (v) with respect to the observer:

λobs = λrest * (1 + v/c)

where c is the speed of light.

In this case, we can use the known rest wavelength of the transition (121.6 nm) and the observed wavelength (120.8 nm) to solve for the velocity:

120.8 nm = 121.6 nm * (1 + v/c)

Solving for v, we get:

v = c * (120.8 nm - 121.6 nm) / 121.6 nm = -12.5 * 10^5 m/s

This is the velocity of the star away from the observer.

To find the speed for a star in which this line appears at wavelength 121.1 nm, we can use the same formula:

v = c * (121.1 nm - 121.6 nm) / 121.6 nm = -2.5 * 10^5 m/s

To find the speed for a star in which this line appears at wavelength 121.8 nm, we can use the same formula:

v = c * (121.8 nm - 121.6 nm) / 121.6 nm = -0.8 * 10^5 m/s

The doppler effect is a physics phenomenon related to the perceived frequency variation of a moving wave relative to an observer.

This effect was studied by the Austrian physicist Christian Doppler (1803-1853) and the discovery was named after him. Hence, the doppler effect.

The doppler effect can be observed in any and all electromagnetic waves, such as light, or mechanical waves, such as sound.

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The potential energy of the lemming when it lands is 0.9108672 J.

To determine the potential energy (PE) of the lemming when it lands, we need to consider the conservation of energy. The potential energy of an object is given by the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height.

Given:

Mass of the lemming (m) = 0.0780 kg

Height of the cliff (h) = 5.36 m

First, let's calculate the potential energy when the lemming is on the cliff. Using the given formula, we have:

PE = mgh

PE = 0.0780 kg * 9.8 m/s² * 5.36 m

PE = 0.413616 J

Next, we need to determine the final kinetic energy of the lemming just before it lands. We can use the equation for kinetic energy (KE) given by KE = (1/2)mv², where v is the velocity of the lemming.

Given:

Velocity of the lemming (v) = 4.84 m/s

Calculating the kinetic energy, we have:

KE = (1/2) * 0.0780 kg * (4.84 m/s)²

KE = 0.9108672 J

According to the conservation of energy, the potential energy at the top of the cliff is equal to the kinetic energy just before landing.

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Answer:

a, The dimension of volume is L³

b. The dimension of speed = L/T

Explanation:

The three fundamental quantities are Mass, Length and time. Other physical quantities are obtained from or derived from these three. These other quantities are known as derived quantities. The units of the fundamental quantities are Kilogram (kg) for Mass, meters for length, and second for time.

In the given question:

a. Volume = length * breadth * height

since breadth and height all measure length, the dimension of volume becomes:

volume = length * length * length = L³

Thus, the dimension of volume is L³

b. Speed, v = distance/time

Distance measures length, therefore, the dimension of speed will be:

Speed = length / time = L/T

Therefore, the dimension of speed = L/T

Answer:

I believe the answer is sea floor spreading

Answer:

3.33×10^-5 meters above the origin along the positive y-axis

Explanation:

The weight of an object is given by its mass multiplied by the acceleration due to gravity, which is 9.81 m/s² near the surface of the earth. For an electron with mass me, its weight is:

W = me * g

= 9.11×10^-31 kg * 9.81 m/s²

= 8.93×10^-30 N

Since the electric force acting on the electron is opposite to its weight, the electric force must have the same magnitude as its weight but in the opposite direction:

|F_E| = |W| = 8.93×10^-30 N

The electric force between two point charges is given by Coulomb's law:

F_E = k * |q1| * |q2| / r²

where k is the Coulomb constant, q1 and q2 are the charges of the two particles, and r is the distance between them.

In this problem, q1 is the fixed charge of -0.55 nC at the origin, and q2 is the charge of the electron, which we want to find. Since we know the magnitude of the electric force between the two charges, we can solve for the distance between them:

r² = k * |q1| * |q2| / |F_E|

= 8.99×10^9 N⋅m²/C² * 0.55×10^-9 C * |q2| / (8.93×10^-30 N)

= 6.95×10^6 * |q2|

Taking the square root of both sides, we get:

r = 2.64×10^-3 * sqrt(|q2|)

Now, we need to find the distance r at which the electric force between the two charges is equal in magnitude but opposite in direction to the weight of the electron. Equating the expression for r above with the distance y along the y-axis where the electron is placed, we get:

2.64×10^-3 * sqrt(|q2|) = y

Since the electron is placed on the y-axis, its x and z coordinates are zero, and the distance between the electron and the fixed charge is simply the y-coordinate. The electric force between the charges will be attractive (i.e., in the negative y direction), so the direction of the force vector will be opposite to the positive y direction. Therefore, we can write the electric force on the electron as:

F_E = - k * |q1| * |q2| / y²

Setting this equal to the weight of the electron, we have:

k * |q1| * |q2| / y² = |W|

|q2| = |W| * y² / (k * |q1|)

= 8.93×10^-30 N * y² / (8.99×10^9 N⋅m²/C² * 0.55×10^-9 C)

= 1.56×10^-20 * y²

Substituting this expression for |q2| into the expression for r above, we get:

r = 2.64×10^-3 * sqrt(1.56×10^-20 * y²)

= 1.35×10^-11 * y

Equating this expression for r with the expression for y above, we have:

2.64×10^-3 * sqrt(1.56×10^-20 * y²) = y

Squaring both sides and simplifying, we get:

y = 3.33×10^-5 m

Therefore, the electron must be placed at a distance of 3.33×10^-5 meters above the origin, along the positive y-axis, in order for the electric force acting on it to be exactly opposite to its weight.

To summarize, we used Coulomb's law to relate the electric force between the electron and the fixed charge at the origin to the distance between them, and equated this force with the weight of the electron. We then solved for the distance at which the two forces are equal in magnitude but opposite in direction, and found that the electron must be placed 3.33×10^-5 meters above the origin along the positive y-axis.

Hope this helps!