if a =3 and b=2 find the value of (a-b)2- 2ab​

Answer: multiply the number of weeks by 3 or A ( if in assessment guide book)

Step-by-step explanation: just look at the point where its between 2 and 4

If the sample size is small and the sample variance is large then

small treatment effect still be statistically significant.

As we know that,

Statustical significance refers to claim that a result from data generated by testing or experimentation is likely to be attributable to specific cause.

Sample size is the total number of individuals or items that comprise a sample.

And, the variance is a descriptive statistic, which falls under the category of a measure of spread.

The circumstance in which a very small treatment effect can be found to be significant is best described by option A: If the sample size big and the sample variance is small.

A large sample size will increase the probability that the results of a statistical test will yield significant results. This is why most statistical tests are accompanied by a measure of effect size. A statistically significant result associated with a very large sample size, will likely have a small effect size, an undesirable result for a researcher, as it implies one of the only reasons significant results were obtained was due to the large sample, not necessary the magnitude of the experimental effect.

Likewise, if variance is small, this will also increase the probability that the results of a statistical test will yield significant results. Variance is simply another word in statistics for the error. A decrease in error will lead to an increased probability of obtaining significant results, hence the idea that a small amount of variance will lead to an increased probability of significant results.

Hence, if the sample size is small and the sample variance is large then

small treatment effect still be statistically significant.

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Answer:

wait im srry i didnt get the question wht grade u in?

An estimated 50118 peοple will be infected after 60 days

The given fοrmula fοr mοdeling the number οf peοple infected with the virus is:

\(P(t) = e^{0.22t\)

Tο estimate the number οf peοple infected after 30 days, substitute t = 30 intο the fοrmula:

\(P(30) = e^{(0.22*30)} = e^{6.6 = 787.9\)

Therefοre, an estimated 788 peοple will be infected after 30 days.

Tο estimate the number οf peοple infected after 60 days, substitute t = 60 intο the fοrmula:

\(P(60) = e^{(0.22*60)} = e^{13.2 = 50117.9\)

Therefοre, an estimated 50118 peοple will be infected after 60 days.

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The simplified expression for (f ∘ g)(x) is 2 + x (option d).

To find and simplify (f ∘ g)(x), we need to substitute the expression for g(x) into f(x) and simplify.

Given:

f(x) = log₃(9x)

g(x) = \(3^x\)

Substituting g(x) into f(x):

(f ∘ g)(x) = f(g(x)) = log₃\((9 * 3^x)\)

Now, we simplify the expression:

log₃\((9 * 3^x)\) = log₃(9) + log₃\((3^x)\)

Since logₓ(a * b) = logₓ(a) + logₓ(b), we have:

log₃(9) + log₃\((3^x)\) = log₃\((3^2)\) + x

Using the property logₓ\((x^a)\) = a * logₓ(x), we get:

log₃\((3^2)\) + x = 2 * log₃(3) + x

Since logₓ\((x^a)\) = a, where x is the base, we have:

2 * log₃(3) + x = 2 + x

Therefore, (f ∘ g)(x) simplifies to:

(f ∘ g)(x) = 2 + x

So, the correct answer is (d) 2 + x.

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Complete Question:

Given f(x)=log₃(9x) and g(x)=\(3^x\). Find and simplify (f ∘ g)(x)

(a) 2x

(b) x

(c) \(27^x\)

(d) 2+x

(e) None of these.

Answer:

false 1/10 false 80 13/1

Answer:

the third one (2,-18)

Step-by-step explanation:

The students were interested in the proportion of rental apartments in these suburbs that were leased as furnished apartments and whether this varied with the number of bedrooms in these apartments 500x + 900y + 1500z = 750,000

formal test, using a = 0.05,of whether the proportions of furnished apartments varies across number of bedrooms, that is, whether the furnishing status of an apartment independent of the number of bedrooms in the apartment You may use R to carry out these calculations, but please state the following information from this test: i. the table of expected frequencies ii. the observed value of the test statistic iii. the relevant degrees of freedom for the distribution of the test statistic iv

500x + 900y + 1500z = 750,000 - - - (1)

x + y + z = 1000 - - - - (11)

x = 200 + y + z - - - - (111)

x + 2y + 3z = 1550 - - - (1V)

I bedroom = x

2 bedroom = y

3 bedroom = z

All the condition s gjvbbs'

500x + 900y + 1500z = 750,000 - - - (1)

x + y + z = 1000 - - - - (11)

x = 200 + y + z - - - - (111)

x + 2y + 3z = 1550 - - - (1V)

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Step-by-step explanation:

Resting is important for muscle regeneration.

Answer:

The answer would be option B.

Step-by-step explanation:

There are more people clustered in 22-25 years and the outlier is 38-41 years.

Answer:

B.

Step-by-step explanation:

Answer:

1500625

Work:

5^4 = 625

7^4 = 2401

Multiply them and it equals 1500625

Answer:

Step 1: Steps for construction

Take AB at 5.5 cm                                    

Step 2: construct as 45 degree  

Step 3: A draw angle ABY=45 degree    

Step 4: cut off from AY, a segment AD=5 cm

Step 5: With B as center and radius as 3.5cm draw an arc.

Step 6: With D as the center and mark radius as 5 cm and draw an arc cut the 1st arc at C

Step 7: join B to C and C to D

Result: Then ABCD is a required quadrilateral  

Hope this helps you hit the crown :D

tell me if correct ok?

9514 1404 393

Answer:

  see the attachment

Step-by-step explanation:

1. Lay out points A and B so they are 5.5 cm apart.

2. Set the compass to 5 cm and draw arcs that intersect above and below segment AB. Label the intersection points Y and Z.

3. Draw segment YZ as a perpendicular bisector of AB.

4. Label the intersection of YZ and AB point E.

5. Using E as the center and AE as the radius, draw an arc that intersects segment YZ at F.

6. Draw segment AD through F. D will lie on the circle of radius 5 cm centered at A. This segment makes 45° angle DAB.

7. Draw an arc of radius 4 cm centered at D through the vicinity of point C.

8. Draw an arc of radius 3.5 cm centered at B through the vicinity of C. The intersection point with the arc of step 7 is point C.

9. Draw quadrilateral ABCD meeting the given requirements.

_____

About the attachment

My geometry tool draws circles of a given radius more easily than arcs of a given radius, so you see circles where only arcs are needed.

The solution of the equation x^ay! + 5xy + (4 + x)y = 0, where x > 0, can be represented as a power series of the form y = ΣCnx^n, where C0 = 1 and Cn = 0 for n = 1, 2, 3, ...

To find the solution of the equation x^ay! + 5xy + (4 + x)y = 0, we can represent the solution as a power series expansion of the form y = ΣCnx^n, where Cn is the coefficient of x^n and n ranges from 0 to infinity. Plugging the power series into the equation, we get:

x^a*(ΣCnx^nn!) + 5x*(ΣCnx^n) + (4 + x)(ΣCn*x^n) = 0

We can then collect the terms with the same powers of x:

ΣCnx^(n+a)n! + Σ5Cnx^(n+1) + Σ(4 + x)Cnx^n = 0

For the equation to hold true for all powers of x, each term with the same power of x must be zero. Therefore, we can determine the coefficients Cn for each power of x. For n = 0, the term ΣCnx^a0! simplifies to C0x^a0! = C0*x^a. Since the equation must hold for all x > 0, the coefficient C0 must be non-zero. Therefore, C0 = 1. For n = 1, the term Σ5Cnx^2 simplifies to 5C1x^2 = 0. Therefore, C1 = 0. Similarly, for n = 2, 3, 4, ... , the terms involving Cn will also be zero, as they are multiplied by powers of x. Hence, the solution of the equation x^ay! + 5xy + (4 + x)y = 0 can be represented as y = C0x^a = x^a, where a is a positive real number, and the coefficients Cn are zero for n = 1, 2, 3, ....

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The probability of obtaining a five-card poker hand that contains two pairs is approximately 0.0475, or 4.75%.

To calculate the probability of obtaining a five-card poker hand with two pairs, we need to determine the number of favorable outcomes (hands with two pairs) and the total number of possible outcomes (all possible five-card hands).

A hand with two pairs consists of two cards of one rank, two cards of another rank, and a fifth card of a different rank. There are 13 ranks to choose from, and for each rank, we can choose 2 out of the 4 cards to form the pairs. The fifth card can be any of the remaining 11 ranks.

The number of ways to select two ranks for the pairs is given by C(13, 2) = 78. For each pair rank, there are C(4, 2) = 6 ways to select the two cards. The fifth card can be chosen from the remaining 11 ranks in C(11, 1) = 11 ways.

Therefore, the number of favorable outcomes is 78 × 6 × 6 × 11 = 37,368.

The total number of possible five-card hands is C(52, 5) = 2,598,960.

Thus, the probability of obtaining a hand with two pairs is 37,368 ÷ 2,598,960 ≈ 0.0475, or 4.75%.

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The total weight is 18.5 kilograms

The athlete's speed is approximately 7.92 m/s, with an uncertainty of 0.0157 m/s.

To calculate the athlete's speed and the uncertainty in the speed, we can use the rules of error propagation. The formula for speed is:

v = d/t

where v is the speed, d is the distance, and t is the time.

Given:

d = 400 ± 0.2 m (distance)

t = 50.5 ± 0.1 s (time)

Let's start by calculating the speed using the central values:

v = 400 m / 50.5 s

v ≈ 7.92 m/s

Now, let's calculate the uncertainty in the speed using error propagation rules. The formula for error propagation when dividing is:

Δv/v = √[(Δd/d)² + (Δt/t)²]

where Δv is the uncertainty in speed, Δd is the uncertainty in distance, and Δt is the uncertainty in time.

Calculating the uncertainty in the speed:

Δv = v * √[(Δd/d)² + (Δt/t)²]

Δv = 7.92 m/s * √[(0.2 m / 400 m)² + (0.1 s / 50.5 s)²]

Δv ≈ 0.0157 m/s

Therefore, the athlete's speed is approximately 7.92 m/s, with an uncertainty of 0.0157 m/s.

Putting it all together, we can write the final result as:

v ± Δv = 7.92 ± 0.0157 m/s

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Probability that selected chip is white: 1/2

Probability that the other chip in the bowl is red given if the selected chip is white: 1/3

Let A be the event that bowl A is randomly selected; let B be the event that bowl B is randomly selected; and let C be the event that bowl C is randomly selected. All these three bowls are equally likely to be selected:

P(A) = P(B) = P(C) = 1/3

The probability of selecting a white chip from a bowl depends on from which bowl the chip is selected.

Let W be the event that a white chip is randomly selected.

Attached is the picture solution.

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The probability that the car needs no work on the transmission is 0.9.

Given: Let E be the event that a new car requires engine work under warranty, P(E) = 0.04

Let T be the event that the car requires transmission work under warranty, P(T) = 0.1

P(E and T) = 0.03

(a) Find the probability that the car needs work on either the engine, the transmission, or both.

We know that, P(E or T) = P(E) + P(T) - P(E and T)

Putting the values, we get:P(E or T) = 0.04 + 0.1 - 0.03 = 0.11

Therefore, the probability that the car needs work on either the engine, the transmission, or both is 0.11.

(b) Find the probability that the car needs no work on the transmission.

The probability that the car needs no work on the transmission is given by:P(not T) = 1 - P(T)

Substituting P(T) = 0.1, we get:

P(not T) = 1 - 0.1 = 0.9

Therefore, the probability that the car needs no work on the transmission is 0.9.

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Answer:

x = 48-32 = 16

y = 32/16 × 10 = 20

z = 48/32 × 26 = 39

Step-by-step explanation:

Step 2:

\( ({15x}^{2} - 9x) + (5x - 3)\)

Stepc3:

\(3x(5x - 3)\)

Answer:

x = 10

Step-by-step explanation:

Since the triangles are congruent then corresponding angles are congruent.

∠ E = ∠ B , that is

5x = 50 ( divide both sides by 5 )

x = 10

Answer:

D. \(9(y+3) and 27+9y\)

Step-by-step explanation:

The first expression for each set is using the distributing propety. We can start with the first one. We notice right away that 3 sets of 3y is 9y, when the other expression is 6. So, that is incorrect. Next we see the second one does have a correct y-value, but the integer value of 6 is not the same, since 3*3=9, not 6. For C we can tell that 9*3=27, which is not equal to 12. Therefore, D must be the answer.

The grade point average received by hector is 3.75.

Your grade point average (GPA) is calculated by dividing the total number of credits you have earned in high school by the sum of all of your course grades. The majority of colleges and secondary schools use a 4.0 scale to report grades. A perfect score, or an A, is a 4.0.

The unit value for each course in which a student obtains one of the grades mentioned above is multiplied by the grade point total for that grade to determine the GPA. Then, divide the sum of these products by the sum of the units. The cumulative GPA is calculated by dividing the total grade points by the total number of units.

3 a and one is B received by Hector.

The A = 4.0, B = 3.0, C = 2.0, D = 1.0 is given by college

We have GPA= A+A+A+B/4

GPA=4+4+4+3/4

GPA= 15/4

GPA=3.75

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Complete question

Hector Ramirez received three A's and one B in his college courses. What is his grade point average? Assume each course is three credits. A = 4.0, B = 3.0, C = 2.0, D = 1.0

Answer:

441.5

Step-by-step explanation:

Answer:

42

Step-by-step explanation:

The equation is, c/7 = 6

c/7= 6

By multi[lying both sides with seven,

c = 6*7

c = 42

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The annual income of a certain household that has a z-score of 1.5, is 80,000.

The relationship between a value and a group of values' mean is described statistically by the Z-score. Standard deviations from the mean serve as the unit of measurement for Z-score. The score for a data point is equal to the mean score if the Z-score is 0. A value that deviates by one standard deviation from the mean is indicated by a Z-score of 1.0.

Z-scores can either be positive or negative, with a positive value indicating that the score is above the mean and a negative value indicating that the score is below the mean. Z-scores are measurements of an instrument's variability used in investing and trading that traders can use to estimate volatility.

Let the annual income be x.

x has μ = 50000, σ = 20000

We know that for given x, z = (x−μ)/σ

Given that z - score = 1.5

Substituting the values we get

⇒ 1.5 = (x−50000)/20000

​⇒ 1.5 × 20000 = x−50000

​⇒ 30000 = x − 50000

⇒ x = 30000 + 50000

⇒ x = 80,000

Thus, The annual income of a certain household that has a z-score of 1.5, is 80,000.

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