if 50.0 mL of a 0.200 M solution of the weak base N-ethylmorpholine (C6H13NO) is mixed with 8.00 mL of 1.00 M HCl and then diluted to a final volume of 100.0 mL with water, the result is a buffer with a pH of 7.00. Compute the Kb of N-ethylmorpholine.

Answer:

Acid: H2O

Base: CH3NH2  

Conjugate acid:  CH3NH3+

Conjugate base: OH-

Explanation:

Acid: proton donor

Base: proton receiver

Answer:

conjugate base : OH . conjugate acid: CH3NH3 bronsted Lowry acid : H2O . bronsted Lowry base:CH3NH2

Explanation:

Gravitational potential energy

= mgh

= (5kg)(9.81N/kg)(150m)

= 7357.5J.

Answer:

\(\boxed {\boxed {\sf 7350 \ Joules}}\)

Explanation:

Gravitational potential energy can be found using the following formula:

\(E_P=m*g*h\)

Where m is the mass, g is the gravitational acceleration, and h is the height.

The mass of the object is 5 kilograms. On Earth, the acceleration due to gravity is 9.8 meters per square second. The height is 150 meters.

\(m= 5 \ kg \\g= 9.8 \ m/s^2 \\h= 150 \ m\)

Substitute the values into the formula.

\(E_p=(5 \ kg)(9.8 \ m/s^2)(150 \ m)\)

Multiply the first two numbers.

\(E_P=(49 \ kg*m/s^2)(150 \ m)\)

\(E_p=(49 \ N)(150 \ m)\)

Multiply.

\(E_p=7350 \ N*m\)

\(E_p= 7350 \ J\)

The gravitational potential energy of the object is 7350 Joules

Answer:

244 g NaF

Explanation:

(3.75 L) x (1.55 mol/L NaF) x (41.98817 g NaF/mol) = 244

To find the mole fraction of He in the gas, we first need to calculate the total number of moles of gas in the sample. Since 6.02x10^23 atoms make up one mole of gas, we can calculate the number of moles in the sample by dividing the number of atoms by Avogadro's number:

6.02x10^23 atoms / 1 mole = 2.0 moles of gas

Next, we need to calculate the mole fraction of He in the gas. This is the ratio of the number of moles of He to the total number of moles of gas in the sample:

Mole fraction of He = moles of He / total moles of gas
Mole fraction of He = 6.02x10^19 / 2.0
Mole fraction of He = 3.01x10^19

Finally, to express the mole fraction in parts per million (ppm), we need to multiply by 10^6:

Mole fraction of He (in ppm) = 3.01x10^19 x 10^6
Mole fraction of He (in ppm) = 3.01x10^25 ppm

Therefore, the mole fraction of He in the gas sample is 3.01x10^25 ppm.
Hi! I'd be happy to help you with your question. To find the helium (He) mole fraction in parts per million (ppm), follow these steps:

1. Calculate the total number of moles of gas: We are given that there are 2.0 moles of gas in total.
2. Calculate the moles of He atoms: We are given 6.02 x 10^19 He atoms. To convert atoms to moles, divide by Avogadro's number (6.022 x 10^23 atoms/mol):
  (6.02 x 10^19 atoms) / (6.022 x 10^23 atoms/mol) ≈ 0.0001 mol He.
3. Calculate the mole fraction of He: Divide the moles of He by the total moles of gas:
  (0.0001 mol He) / (2.0 mol gas) = 0.00005.
4. Convert the mole fraction to ppm: Multiply the mole fraction by 1,000,000:
  0.00005 x 1,000,000 = 50 ppm.

So, the helium mole fraction in the given gas mixture is approximately 50 ppm.

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The first step in the preparation of magnesium metal is the precipitation of Mg(OH)₂ from sea water by the addition of Ca(OH)₂ the concentration of Mg₂ (aq) in sea water is 5.37 × 10⁻² m then ph at which [Mg₂ ] is decreased to 1.0 × 10⁻⁵ m is 1.27

Magnesium is the element and also one of the alkaline earth metal and metallic magnesium is prepared either by electrolysis of molten MgCl₂ or by metallothermic reduction of its halides by alkali or alkaline-earth metals

Here given data is concentration = 5.37 × 10⁻² m

We have to find pH= ?

pH = -log[HA]

pH = -log[Mg₂]

pH = -log[5.37 × 10⁻² m]

pH = 1.27

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Answer:

Zinc mercury transition metal

Silicon boron metalloid

Oxygen nitrogen non metal

Sodium alkali metal

Explanation:

Answer:

malleable

Explanation:

The image represent in malleable property of metal.

The image possibly represents the photoelectric effect of a metal, which is when it emits electrons after being exposed to electromagnetic radiation. Metals are also characterized by physical properties such as conductivity, malleability, metallic luster, and metallic bonding.

Based on your question, the image possibly represents the photoelectric effect, a key property of metals. This phenomenon occurs when a metal surface exposed to electromagnetic waves of a certain frequency absorbs radiation and emits electrons. These emitted electrons are called photoelectrons. Metals can also exhibit free electron model behavior, where electrons freely roam within the metal structure.

Metals possess unique physical properties like conductivity, malleability, and metallic luster. Malleability refers to the metal's ability to deform without breaking, while conductivity refers to the metal's ability to transfer heat or electricity. A metallic luster gives metals their characteristic shiny appearance.

Finally, metals are also known for their metallic bonding—a unique force that holds together the atoms within a metallic solid. Metallic bonding gives rise to many useful and varied bulk properties of metals.

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The half-life of a first-order reaction is 13 min. If the initial concentration of reactant is 0. 085 m, it takes 10.6  min for it to decrease to 0. 055 m.

In a first-order reaction, the half-life is the time it takes for the concentration of the reactant to decrease by half. Given that the half-life is 13 min, we can calculate the rate constant using the formula: k = 0.693 / t(1/2), where t(1/2) is the half-life.

Plugging in the values, we get k = 0.693 / 13 = 0.0531 min⁻¹. Now, we can use the rate constant to calculate the time it takes for the concentration to decrease from 0.085 m to 0.055 m.

Using the equation ln(C₀ / C) = k * t, where C₀ is the initial concentration, C is the final concentration, k is the rate constant, and t is the time, we find that t = (ln(0.085 / 0.055)) / 0.0531

≈ 10.6 min.

Therefore, it takes approximately 10.6 minutes for the concentration to decrease to 0.055 m.

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The chemical equation for the ionization of triprotic acid H₃PO₄ in water: H₃PO₄ + H₂O ↔ H₃O⁺ + H₂PO₄⁻.

The equation above shows that H₃PO₄ reacts with water (H₂O) to form hydronium ions (H₃O⁺) and the dihydrogen phosphate ion (H₂PO₄⁻). This reaction occurs in three stages, as H₃PO₄ is a triprotic acid, meaning it can donate three hydrogen ions (protons) to water molecules.

The ionization of H₃PO₄ occurs in a step-wise manner:

1. The first proton is donated to a water molecule, forming H₃O⁺ and the hydrogen phosphate ion (HPO₄²⁻):
H₃PO₄ + H₂O ↔ H₃O⁺ + HPO₄²⁻

2. The second proton is donated to another water molecule, forming H₃O⁺ and the phosphate ion (PO₄³⁻):
HPO₄²⁻ + H₂O ↔ H₃O⁺ + PO₄³⁻

3. The third proton is donated to a third water molecule, forming H₃O⁺ and another hydrogen phosphate ion:
PO₄³⁻ + H₂O ↔ H₃O⁺ + H₂PO₄⁻

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Protons and neutrons are particles that are approximately the same size, while electrons are much smaller. As a result, the correct option is C, neutrons.

The mass of an atom is concentrated in its nucleus, which is made up of protons and neutrons. Electrons revolve around the nucleus of an atom. Electrons are much smaller than the nucleus of an atom, which is made up of protons and neutrons. Protons and neutrons are similar in mass, while electrons are considerably less massive. The correct answer is option C, which is neutrons, because protons and electrons are not similar in mass. In fact, electrons are about 1800 times less massive than protons and neutrons. Quarks are the smallest particles that make up the particles that form atoms. These particles come in six different flavours and are held together by other particles known as gluons. However, quarks' masses are not similar to one another.

Electrons, which are much less massive than protons and neutrons, and quarks, which do not have equivalent masses, are not particles of almost equal mass. Consequently, option C, neutrons, is the correct answer.

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Answer:

The ideal gas law specifies the mechanical behavior of ideal gases. It is capable of calculating the volume of gases produced or consumed.

In chemical equations, these equations are widely used to convert between volumes and molar quantities.

Use ideal gas law

Therefore

is the same for both So, = same for both.

When n increases, T decreases, so, n is 1 for and 0.5 for , implying that is hotter.

The temperatures of the gases will not be equal.

\(PV=nRT\)

∵V is the same for both

∴T= same for both.

When n increases, T decreases, so, n is 1 for hydrogen gas and 0.5 for  oxygen gas ,implying that oxygen gas will have more temperature than hydrogen gas since its number of moles are lower than hydrogen gas.

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ANSWER

The addition of HCl will shift to reactants

EXPLANATION

When some strong acid is added to a buffer, the equilibrium is shifted to the left, and the hydrogen ion concentration increases by less than expected for the amount of strong acid added. Buffer solution helps in adjusting the pH of a substance.

Since the HCl is a strong acid, it will shift to the left (reactant sides)

Answer:

On the pereiodic table.

Explanation:

Answer:

Because.in theory, it's impossible for philosophers (Greeks) don't have the proper equipment and also they don't have enough facts to back it up

Explanation:

Hope this helps

Answer:

Ne

Explanation:

Comparing Ne and Na, Neon atoms will have the greatest ionization energy.

The ionization energy is the energy required to remove the most loosely held electrons within an atom.

Answer:

when you multpily or divide powers of 10 you just add or subratact respectivley

Explanation:

(5.93 x 10 ^ 3) (2.3 x 10^ -2) = (5.93 * 2.3 ) x 10 ^ 3 +(-2)

                                             = 13.639 x 10 ^ 3-2

                                             = 13 . 639 x 10

                                              1.3639 x 10^2

Answer:

Potential energy is the energy in a body due to its position. While kinetic energy is the energy in a body due to its motion.

Answer:

Explanation:

i hope it helps :)

Answer:

1s2 2s2 2p6 3s2 3p4

Explanation:

below

Answer:

the valency of sodium is one because sodium loses 1 electron to become stable

The pH and the pOH of an aqueous solution that is 0.045 M in HCl(aq) and 0.095 M in HBr(aq) at 25 °C is 1.35, and 12.98 respectively.

To calculate the pH and pOH of the solution, we need to use the concentration of the acidic solutions and the dissociation constants of HCl and HBr.

First, calculate the pH:

For HCl (aq):

[HCl] = 0.045 M

HCl is a strong acid and dissociates completely in water, so the concentration of H⁺ ions is equal to the concentration of HCl:

[H⁺] = 0.045 M

Taking the negative logarithm (base 10) of the H⁺ concentration gives us the pH:

pH = -log10(0.045)

pH = 1.35

Now, let's calculate the pOH:

For HBr(aq):

[HBr] = 0.095 M

HBr is also a strong acid, and its dissociation is similar to HCl. The concentration of H⁺ ions is equal to the concentration of HBr:

[H⁺] = 0.095 M

Again, taking the negative logarithm (base 10) of the H⁺ concentration gives us the pH:

pH = -log10(0.095)

pH = 1.02

Since pH + pOH = 14 (at 25 °C), we can calculate the pOH:

pOH = 14 - pH

pOH = 14 - 1.02

pOH = 12.98

Therefore, the pH of the solution is approximately 1.35, and the pOH is approximately 12.98.

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Answer:

I think A.

Explanation:I say A because of the substance melting the quicking does have the highest melting point because its the highest.

When a base is mixed with an acid, a neutralization reaction occurs.

This type of reaction involves the combination of H+ ions from the acid with OH- ions from the base to form water (H2O) and a salt. The salt produced depends on the specific acid and base used. For example, when hydrochloric acid (HCl) is mixed with sodium hydroxide (NaOH), the resulting salt is sodium chloride (NaCl). The reaction is not spontaneous and requires an input of energy to occur. Typically, the heat produced during the reaction is used to drive the reaction forward. When a base is mixed with an acid, the type of reaction that occurs is called a neutralization reaction. In this process, the acidic and basic properties of the reactants are neutralized, producing water and a salt as the products. This reaction is important in various chemical processes and everyday situations, such as in the regulation of pH levels and the formation of salts. Neutralization reactions are essential for maintaining a balance in different environments and have various practical applications.

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Answer:

1120 mm Hg

plus give brainliest

An insulated cup contains 75 g of water at 24 °C. A 26 g sample of metal at 82.25°C is added. The final temperature of the water and metal is 28.34°C. The specific heat of the metal is 0.972 J/ g°C.

Given that :

Mass of the metal = 26 g

The specific heat of the metal = ?

Initial temperature of the metal = 82.25°C

Equilibrium temperature = 28.34°C

Mass of the water = 75 g

Specific heat of water = 4.18 J/ g°C

Initial temperature of the water = 24 °C

The specific heat capacity is given as :

26 × c × ( 82.25 - 28.34) = 75 × 4.18 ( 28.34 - 24)

26 × c × 53.91 = 313.5  × 4.34

c = 0.972 J/ g°C

Thus, the specific heat capacity of metal is 0.972 J/ g°C.

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Answer:

3/4

Explanation:

2Al2O3 → 4Al + 3O2

Molar ratio of oxygen to aluminum is 3/4.

Answer: 3:4

Explanation: Got it right on Edge

Answer:

hope this is help helpful

Explanation:

natural gas are considered nonrenewable because they can not be replenished in a short period of time.

Answer: The concentration of a solution made by combining 52 grams of  \(NaCH_{3}COO^{-}\) with 150 mL of water is 4.22 M.

Explanation:

Given: Mass = 52 grams

Volume = 150 mL (1 mL = 0.001 L) = 0.150 L

Molarity is the number of moles of a substance present in liter of a solution.

And, moles is the mass of a substance divided by its molar mass.

Hence, moles of \(NaCH_{3}COO^{-}\) (molar mass = 82.034 g/mol) is as follows.

\(Moles = \frac{mass}{molar mass}\\= \frac{52 g}{82.034 g/mol}\\= 0.633 mol\)

Therefore, concentration of given solution is as follows.

\(Molarity = \frac{moles}{Volume(in L)}\\= \frac{0.633 mol}{0.150 L}\\= 4.22 M\)

Thus, we can conclude that the concentration of a solution made by combining 52 grams of  \(NaCH_{3}COO^{-}\) with 150 mL of water is 4.22 M.