If 2.12 Moles of bromine react with excess phosphorus; How many moles of phosphorus tribromide can be produced?



Round all answers to the hundredths place.

Answer:

\(T_{f,sol}=-15.0\°C\)

Explanation:

Hello there!

In this case, for these problem about the colligative property of freezing point depression, it is possible set up the following equation:

\(T_{f,sol}-T_{f,water}=-i*m*Kf\)

Whereas the van't Hoff's factor, i, is 2 since KCl is ionized in two ions (K+ and Cl-); and the molality (m) of the solution is computed by:

\(m=\frac{75g*\frac{1mol}{74.55g} }{250g*\frac{1kg}{1000g} } \\\\m=4.02mol/kg\)

Thus, since the freezing point of water (ice) is 0°C, we obtain the following freezing point of the solution by plugging in:

\(T_{f,sol}=-(2)(4.02mol/kg)(1.86\°C/mol*kg)\\\\T_{f,sol}=-15.0\°C\)

Best regards!

Answer:

Cellular respiration uses energy in glucose to make ATP. Aerobic (“oxygen-using”) respiration occurs in three stages: glycolysis, the Krebs cycle, and electron transport.

Explanation:

In glycolysis, glucose is split into two molecules of pyruvate. This results in a net gain of two ATP molecules.

Answer:

There are five main types of chemical reactions. These are synthesis, decomposition, combustion, single replacement and double replacement.

Explanation:

Explanation:

List the known and unknown quantities and plan the problem. Change each percent abundance into decimal form by dividing by 100. Multiply this value by the atomic mass of that isotope. Add together for each isotope to get the average atomic mass.

Answer:

The atomic mass of second isotope is 7.016

Explanation:

Given data:

Average Atomic mass of lithium = 6.941 amu

Atomic mass of first isotope = 6.015 amu

Relative abundance of first isotope = 7.49%

Abundance of second isotope = ?

Atomic mass of other isotope = ?

Solution:

Total abundance = 100%

100 - 7.49 = 92.51%

percentage abundance of second isotope = 92.51%

Now we will calculate the mass if second isotope.

Average atomic mass of lithium = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

6.941 = (6.015×7.49)+(x×92.51) /100

6.941 =  45.05235 + (x92.51) / 100

6.941×100 = 45.05235 + (x92.51)

694.1 - 45.05235   = (x92.51)

649.04765 = x 92.51

x = 485.583 /92.51

x = 7.016

The atomic mass of second isotope is 7.016

____________________________________________________

(Hope this helps can I pls have brainlist (crown)☺️)

Lewis electron dot notation is a method for representing the valence electrons in an atom. In this notation, the valence electrons are shown as dots around the symbol of the element. The number of dots represents the number of valence electrons.

The Lewis electron dot notation is a useful tool for understanding the chemical behavior of elements. It allows us to see how many valence electrons an atom has and how they are distributed. This information can be used to predict the types of chemical bonds that an atom is likely to form. For example, the Lewis electron dot notation for nitrogen is:
N: ·
Nitrogen has five valence electrons, so there are five dots around the symbol.
In addition to representing individual atoms, the Lewis electron dot notation can also be used to represent molecules. In a molecule, the dots represent the shared electrons between the atoms.  The Lewis electron dot notation is an important concept in chemistry that helps us to understand the properties and behavior of atoms and molecules.

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Answer:

The tension in the string is 78.73 N.

Explanation:

The tension in the string can be determined from the expression;

v = \(\sqrt{\frac{T}{m} }\)

where: v is the speed of the wave in the sting, T is the tension in the string and m is the mass per unit length of the sting.

Given that: v = 16.2 m/s, and m = 0.3 kg/m.

Then;

16.2 = \(\sqrt{\frac{T}{0.3} }\)

Square both sides to have,

\((16.2)^{2}\) = \(\frac{T}{0.3}\)

T = \((16.2)^{2}\) x 0.3

  = 252.44 x 0.3

  = 78.732

T = 78.732 N

The tension in the string is 78.73 N.

The vapor pressure of methanol at 40°C is 0.234 atm.

Only two types of alcohol are methanol and ethanol. Ethanol, sometimes referred to as ethyl alcohol, has a chemical composition of two carbon atoms. Methanol, sometimes referred to as methyl alcohol, is made up of just one carbon atom.

ln(P2/P1) = (ΔHvap/R) x (1/T1 - 1/T2)

ΔGvap = -RTln(Pvap/P) = ΔHvap - TΔSvap

ΔGvap = -RTln(Pvap/P) = -166.6 kJ/mol

ΔSvap = S(g) - S(l) = 239.9 J/mol-K - 126.8 J/mol-K = 113.1 J/mol-K

ΔHvap = ΔGvap + TΔSvap = -166.6 kJ/mol + (298.15 K)(113.1 J/mol-K) = -134.6 kJ/mol

Now we can use the Clausius-Clapeyron equation to find the vapor pressure of methanol at -30°C and 40°C.

At -30°C, we have:

T1 = 25°C + 273.15 = 298.15 K

T2 = -30°C + 273.15 = 243.15 K

ΔHvap = -134.6 kJ/mol

R = 8.314 J/mol-K

ln(P2/5 atm) = (-134.6 kJ/mol / 8.314 J/mol-K) x (1/298.15 K - 1/243.15 K)

P2 = 0.0038 atm

Therefore, the vapor pressure of methanol at -30°C is 0.0038 atm.

At 40°C, we have:

T1 = 25°C + 273.15 = 298.15 K

T2 = 40°C + 273.15 = 313.15 K

ΔHvap = -134.6 kJ/mol

R = 8.314 J/mol-K

ln(P2/5 atm) = (-134.6 kJ/mol / 8.314 J/mol-K) x (1/298.15 K - 1/313.15 K)

P2 = 0.234 atm

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The statement is correct. The photoelectric effect refers to the phenomenon where electrons are ejected from the surface of a material when it is exposed to light. The frequency of light striking an electron in a metal must be above the threshold frequency in order for the photoelectric effect to occur.

The statement is correct. The photoelectric effect refers to the phenomenon where electrons are ejected from the surface of a material when it is exposed to light. However, for the photoelectric effect to occur, the frequency of the incident light must be above a certain threshold frequency.

The threshold frequency is the minimum frequency of light required to dislodge electrons from the material. Below this threshold frequency, regardless of the intensity or duration of the light, no electrons will be emitted.

This behavior can be explained by the particle-like nature of light, where light is composed of discrete packets of energy called photons. The energy of a photon is directly proportional to its frequency. Only photons with energy greater than or equal to the binding energy of the electrons in the material can dislodge them.

Therefore, the frequency of light striking an electron in a metal must be above the threshold frequency in order for the photoelectric effect to occur.

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The temperature of the gas in Kelvin, after its volume is reduced to 2,450 mL, is approximately 143.27 K.

To determine the temperature of the gas in Kelvin after its volume is reduced, we can use the combined gas law, which relates the initial and final conditions of pressure, volume, and temperature for a given amount of gas.

The combined gas law equation is:

(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂

Where P₁ and P₂ are the initial and final pressures, V₁ and V₂ are the initial and final volumes, T₁ is the initial temperature in Kelvin, and T₂ is the final temperature in Kelvin.

Given that the initial volume V₁ is 3,480 mL, the initial temperature T₁ is -70.0 °C (which needs to be converted to Kelvin), and the final volume V₂ is 2,450 mL, we can substitute these values into the equation.

To convert -70.0 °C to Kelvin, we add 273.15 to it, resulting in T₁ = 203.15 K.

Now we can solve for T₂:

(T₂ * V₁) / T₁ = V₂

T₂ = (V₂ * T₁) / V₁ = (2,450 mL * 203.15 K) / 3,480 mL

Simplifying the equation, we find:

T₂ ≈ 143.27 K

Therefore, the temperature of the gas in Kelvin, after its volume is reduced to 2,450 mL, is approximately 143.27 K.

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Answer:

(CH2CH3).

!

CH-CH-CH-CH=CH-CH2-CH2-CH3

!

(CH2CH3)

2, 3-diethyl–4-octene

i am not sure.

Answer:

A. True

Explanation:

source: https://www.chem.purdue.edu/gchelp/atoms/elements.html

an element CANNOT BE BROKEN DOWN. an atom is a particular element; that is, the smallest version of a substance known to humankind. it doesnt matter whether it is a physical or chemical mean. an element CANNOT be broken down.

Answer:

A particular kind of matter

Explanation:

The best description of cis-trans isomers is that they differ in their spatial arrangement around inflexible double bonds. Option E is correct.

Specifically, cis-trans isomers are a type of stereoisomers that have the same molecular formula and the same covalent bonds but differ in the spatial arrangement of their atoms due to the inflexibility of a double bond. In cis isomers, the two substituents on each carbon atom are on the same side of the double bond, while in trans isomers, the two substituents on each carbon atom are on opposite sides of the double bond.

This results in different physical and chemical properties for the two isomers. For example, cis and trans isomers of some compounds may have different boiling points, melting points, and reactivities.  Cis-trans isomerism is an important concept in organic chemistry as it affects the properties and behavior of molecules and can have significant implications for their biological activity, environmental fate, and industrial applications. Option E is correct.

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The element Ar classified as noble gas in the periodic table. Therefore, the correct option is option A.

The noble gases are a group of chemical elements that share several characteristics. They are all monatomic, odourless, and colourless gases with relatively little chemical reactivity under normal conditions. Oganesson (Og) is a highly radioactive element created synthetically.

Although the IUPAC has included oganesson since "group 18" and "noble gas" have been used interchangeably, oganesson may not be appreciably chemically noble and therefore is projected to deviate from the norm and just be reactive owing to relativistic effects. Its chemistry is still being studied due to the exceptionally short 0.7 ms ½ of its sole known isotope. The element Ar classified as noble gas in the periodic table.

Therefore, the correct option is option A.

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Answer:

i just took the test its digestion

Explanation:

Explanation:

this is a single Replacement Reaction, so Na and Cl will form a bond.

Answer:

71 graham formal.

Dont get mad if i am wrong 0-0

Explanation:

Answer:

It appears that the diagram you provided represents the chemical compound chlorine monofluoride (CI-F). The arrow below the compound may be intended to indicate the movement or flow of electrons in the compound.

Chlorine monofluoride is a highly reactive and toxic compound that is used as a powerful oxidizing agent. It is a compound of chlorine and fluorine, with the chemical formula ClF. It is a yellowish gas at room temperature and has a strong, pungent smell. Chlorine monofluoride is highly reactive and can ignite or explode upon contact with many materials, including water. It is used in a variety of industrial processes, such as the production of semiconductors and the purification of aluminum. However, it can also be harmful to human health if inhaled or ingested, and it should be handled with caution.

Explanation:

Carbon atoms may thus form bonds to as many as four other atoms. For example, in methane (CH 4​start subscript, 4, end subscript), carbon forms covalent bonds with four hydrogen atoms

__________________________________________________________

Answer:

1.135986935e+39

Answer:

\(\boxed {\boxed {\sf 4.60 \times 10^{23} \ atoms \ Mg}}\)

Explanation:

We are asked to find how many atoms of magnesium are in 0.764 moles of magnesium.

We convert moles to atoms using Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are atoms of magnesium. So, there are 6.022 × 10²³ atoms of magnesium in 1 mole of magnesium.

Convert using dimensional analysis and set up a conversion factor using Avogadro's Number.

\(\frac{6.022 \times 10^{23} \ atoms \ Mg}{1 \ mol \ Mg}\)

We are converting 0.764 moles of magnesium to atoms, so we multiply by this value.

\(0.764 \ mol \ Mg *\frac{6.022 \times 10^{23} \ atoms \ Mg}{1 \ mol \ Mg}\)

The units of moles of magnesium cancel.

\(0.764 *\frac{6.022 \times 10^{23} \ atoms \ Mg}{1 }\)

\(0.764 *6.022 \times 10^{23} \ atoms \ Mg\)

\(4.600808 \times 10^{23} \ atoms \ Mg\)

The original value of moles (0.764) has 3 significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place. The 0 in the thousandth place tells us to leave the 0 in the hundredth place.

\(4.60 \times 10^{23} \ atoms \ Mg\)

0.764 moles of magnesium contains approximately 4.60 × 10²³ atoms of magnesium.

The mass of chlorine gas product formed is 61.4 g.

What is the mass ?

First, we need to determine which reactant is limiting and which is in excess. To do this, we can use the given mass of HCl and convert it to moles:

63.2 g HCl × (1 mol HCl/36.46 g HCl) = 1.73 mol HCl

Next, we can use stoichiometry to determine how many moles of \(Cl_{2}\) will be produced from 1.73 mol of HCl:

1.73 mol HCl × (2 mol \(Cl_{2}\)/4 mol HCl) = 0.865 mol \(Cl_{2}\)

Finally, we can convert the moles of \(Cl_{2}\) to grams using its molar mass:

0.865 mol \(Cl_{2}\) × (70.91 g \(Cl_{2}\)/1 mol \(Cl_{2}\)) = 61.4 g \(Cl_{2}\)

Therefore, the mass of chlorine gas product formed is 61.4 g.

What is stoichiometry ?

Stoichiometry is a branch of chemistry that deals with the calculation of the quantities of reactants and products involved in a chemical reaction. It involves using balanced chemical equations to calculate the amounts of reactants required to produce a certain amount of product, or the amount of product that can be obtained from a given amount of reactant. Stoichiometry is an important tool for predicting the outcomes of chemical reactions and for designing chemical processes in industry.

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Answer:

K and Br

Explanation:

K and Br would form an ionic bond because K (potassium) is a metal and Br (bromine) is a nonmetal. Ionic bonds are created between metals and nonmetals.

Answer:

B

Explanation:

Particles in a solid have fixed locations in a volume that does not change. Solids have a definite volume and shape because particles in a solid vibrate around fixed locations.

Explanation:

Na3PO4+ FeCl3 = 3NaCl + FePO4

Hope it will help :)❤

The net ionic equation is found to be balanced by both mass and charge. There are equal masses of each element on the product and reactant sides in a balanced net ionic equation.

A chemical equation which shows only those elements, compounds, and ions which are directly involved in the chemical reaction is defined as the net ionic equation. The net ionic equation give us information about the ions that exists in aqueous medium.

A net ionic equation does not consider the spectator ions. The ions which do not participate in chemical reactions and are seen on both sides of the reactions are called spectator ions.

The complete ionic equation for the given reaction is:

3Na⁺ (aq) + PO₄³⁻ (aq) + Fe³⁺ (aq) + 3Cl⁻ (aq) → 3Na⁺ (aq) + 3Cl⁻ (aq) + FePO₄ (s)

The net ionic equation is:

PO₄³⁻ (aq) + Fe³⁺ (aq) → FePO₄ (s)

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1) Tool used fοr spreadsheets and analysis are Micrοsoft Excel. Thus, option (b) is cοrrect.

2) Tool used tο create presentations are Microsoft PowerPoint. Thus, Option a) is cοrrect.

A spreadsheet is a type of cοmputer software that captures, displays, and manipulates data that is οrganized in rows and columns.

Users can style, organize, and cοmpute data in a spreadsheet using Microsoft Excel.

You can use PowerPoint on your Cοmputer, Laptop, or mobile device to: Create slideshows from inception οr from a template

Microsoft Word is a word editing sοftware that can create basic and complicated documents.

3) Tool used for authoring dοcuments are Microsoft Word. Thus, Option a) is cοrrect.

4) the best apprοach would be Research the problem and give a presentation on how yοu approached the problem, and provide the different books as examples on various slides of the presentation. Thus, Option a) is cοrrect.

5) The best wοuld be A spreadsheet with all your calls and the toughest ones highlighted using fill cοlor. Thus, Option c) is cοrrect.

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Answer:

(a) \(m_{HNO_3}=2412gHNO_3\)

(b) \(Y=80.3\%\)

Explanation:

Hello.

(a) In this case, by starting with 1216 grams of ammonia, we can firstly compute the yielded moles of NO in the first reaction considering the given yield as a fraction (0.962):

\(n_{NO}=1216 g NH_3*\frac{1molNH_3}{17gNH_3}*\frac{4molNO}{4molNH_3}*0.962=68.81molNO\)

Next, in the second chemical reaction we compute the yielded moles of NO₂ with the 91.3-percent:

\(n_{NO_2}=68.81molNO*\frac{2molNO_2}{2molNO}*0.913=62.82molNO_2\)

Finally, for the percent yield of the last chemical reaction and the molar mass of nitric acid (63 g/mol) we compute the yielded grams of nitric acid:

\(m_{HNO_3}=62.82molNO_2*\frac{2molHNO_3}{3molNO_2} *\frac{63gHNO_3}{1molHNO_3}*0.914\\ \\m_{HNO_3}=2412gHNO_3\)

(b) In this case, we compute the moles of NO, NO₂ and the grams of nitric acid as well as the previous literal yet removing the percent yields since we are going to compute theoretical yields:

\(n_{NO}=1216 g NH_3*\frac{1molNH_3}{17gNH_3}*\frac{4molNO}{4molNH_3}=71.53molNO\)

\(n_{NO_2}=71.53molNO*\frac{2molNO_2}{2molNO}=71.53molNO_2\)

\(m_{HNO_3}=71.53molNO_2*\frac{2molHNO_3}{3molNO_2} *\frac{63gHNO_3}{1molHNO_3}*0.914=3004gHNO_3\)

Thus, the overall percent yield is:

\(Y=\frac{2412g}{3004g} *100\%\\\\Y=80.3\%\)

Best regards.

Answer:

Explanation:

If a zero is found between significant digits, it is significant

The question is incomplete. The complete question is :

Hydrogen \((H_2)\) gas and oxygen \((O_2)\) gas react to form water vapor \((H_2O)\). Suppose you have 11.0 mol of \(H_2\) and 13.0 mol of \(O_2\) in a reactor. Calculate the largest amount of \(H_2O\) that could be produced. Round your answer to the nearest 0.1 mol .

Solution :

The balanced reaction for reaction is :

\($2H_2(g) \ \ \ \ + \ \ \ \ \ O_2(g)\ \ \ \rightarrow \ \ \ \ 2H_2O(g)$\)

11.0                      13.0

11/2                       13/1     (dividing by the co-efficient)

6.5 mol               13 mol    (minimum is limiting reagent as it is completely consumed during the reaction)

Therefore, \(H_2\) is limiting reagent. It's stoichiometry decides the product formation amount from equation above it is clear that number of moles for \(H_2O\) will be produced = number of moles of \(H_2\)

                                     = 11.0 mol

At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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Answer:

With the adsorption of cations like zinc as Zn (OH)+ or ZnCl+ or both, the anion exchange is known to increase. The solid phase has an impact on the anions' concentration in the soil solution. Anions are negatively adsorbed as a result of the exchange complex's overall negative charge.