if 0.450 moles of iron iii oxide (fe2o3) are allowed to react with an excess of aluminum (al) and 43.6 grams of iron (fe) is produced, what is the percent yield of iron? 2al fe2o3 2fe al2o3 a. 86.5 % b. 84.4 % c. 65.4 % d. 43.6 % e. 13.5 %

Answers

Answer 1

86.5% is the percent yield of iron.

To calculate the percent yield of iron, we need to first determine the theoretical yield of iron, which is the amount of iron that would be produced if the reaction went to completion. We can use stoichiometry to determine this:

1 mole of Fe2O3 reacts with 2 moles of Al to produce 2 moles of Fe.
0.450 moles of Fe2O3 would require 0.900 moles of Al (since there is a 2:1 mole ratio between Al and Fe2O3).
0.900 moles of Al would produce 2 x 0.450 = 0.900 moles of Fe.

The molar mass of Fe is 55.85 g/mol, so the theoretical yield of Fe would be:

0.900 moles x 55.85 g/mol = 50.27 g

Since the actual yield of Fe is given as 43.6 g, we can calculate the percent yield as:

(actual yield/theoretical yield) x 100%
= (43.6 g/50.27 g) x 100%
= 86.5%

Therefore, the answer is (a) 86.5%.

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Related Questions

which size of micropipette would you select to deliver 215 microliters?

Answers

The size of micropipette that you would select to deliver 215 microliters would be a micropipette with a volume range of 200-1000 microliters.

What is a micropipette?

A micropipette is a laboratory instrument used to measure and dispense small volumes of liquid, typically in the range of microliters (µL) or nanoliters (nL). They are commonly used in chemistry, biology, and biochemistry experiments, as well as in clinical and industrial settings.

Micropipettes consist of a handle, a digital or manual volume adjustment mechanism, and a tip that is placed into the liquid to be dispensed. They work by creating a vacuum or positive pressure inside the tip, which draws or pushes the liquid out of the tip.

Micropipettes come in different volume ranges and it is important to select the right one to ensure accurate delivery of the desired volume. For example, a micropipette with a volume range of 2-10 microliters would not be suitable for delivering 215 microliters, while a micropipette with a volume range of 200-1000 microliters would be more appropriate.

It's also important to note that, even if the micropipette is able to deliver 215 microliters, you should always check the calibration of the micropipette before use, to make sure that it's delivering the correct volume.

Hence, a micropipette with a volume range of 200-1000 microliters is suitable to deliver 215 microliters.

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Which value represents the first ionization energy of a nonmetal?
a. 497.9kJ
b. 577.4kJ
c. 811.7kJ
d. 1000kJ

Answers

The value which represents the first ionization energy of a nonmetal is 1000KJ . Option (d) is correct.

Nonmetals, which are found in the right-hand region of the periodic table, have relatively large ionization energies and therefore tend to gain electrons. Ionization energies generally increase in going from left to right across a given period.

Ionization Energy is the energy required to remove an electron from an atom in its gaseous state.

The first ionization tends to decrease from top to bottom within a group and increase from left to right across a period.

The atoms of the alkali metals have larger radii than those of nonmetals. Because of this, the attraction of the positively charged atomic nucleus for the valence electron is much less than that of a nonmetal.

Therefore, the first ionization energy of an alkali metal is much less than that of a nonmetal. Because of this, alkali metals lose their single valence electron which produces a cation with a charge of +1.

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Plz Help!

Make a funny sentence for flammability and compounds for Magnesium

Answers

∵*A funny sentence*∴

1 point
Thermal energy is due to the movement of molecules and the heat they
produce. Thermal energy is therefore
potential energy
kinetic energy
none of the above

Answers

potential and kinetic but i would just say potential

chemistry image below

chemistry image below

Answers

A very reactive metal as per the diagram is option D

What is a metal?

In the context of the periodic table, a metal is a chemical element that is typically a good conductor of heat and electricity.

Metals are found on the left side of the periodic table, as well as in the middle (known as the transition metals), and include elements such as copper, iron, gold, silver, aluminum, and titanium.

When a metal loses one or more electrons, it forms a positively charged ion. This electron loss can occur in a number of ways, but the most common way is through a process called oxidation.

In a metal, the outermost electrons are held relatively loosely and can be easily removed, leaving behind a positively charged ion. The process of electron loss is often facilitated by chemical reactions with other substances, such as oxygen in the air or an acid in a solution.

Option D has one electron on the outermost shell and will likely loose the electron

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A photon of wavelength 1,094 nm is emitted when an electron in hydrogen makes a transition to the third level. determine the level that the electron started it.

Answers

The electron started in the second energy level (n₁ = 2) before transitioning to the third level.

To determine the initial level of the electron in a hydrogen atom, we can use the Rydberg formula, which relates the wavelength of a photon emitted or absorbed during an electron transition to the energy levels in hydrogen:

1/λ = R * (1/n₁² - 1/n₂²)

Where, λ is the wavelength of the photon,

R is the Rydberg constant (approximately 1.097 x 10^7 m^-1),

n₁ is the initial energy level,

n₂ is the final energy level.

Given that, the wavelength of the emitted photon is 1,094 nm (or 1.094 x 10^-6 meters) and the electron transition occurs to the third level (n₂ = 3), we can substitute these values into the formula and solve for n₁:

1/λ = R * (1/n₁² - 1/n₂²)

1/(1.094 x 10^-6) = 1.097 x 10^7 * (1/n₁² - 1/3²)

Simplifying the equation:

1.094 x 10^6 = 1.097 x 10^7 * (1/n₁² - 1/9)

1/n₁² - 1/9 = (1.094 x 10^6) / (1.097 x 10^7)

1/n₁² - 1/9 ≈ 0.0997

1/n₁² ≈ 0.0997 + 1/9

1/n₁² ≈ 0.1997

n₁² ≈ 1 / 0.1997

n₁² ≈ 5.004

n₁ ≈ √5.004

n₁ ≈ 2.24

Therefore, the electron started in the second energy level (n₁ = 2) before transitioning to the third level.

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What are three main ideas in Dalton's atomic theory

Answers

According to the first section of his theory, atoms—which cannot be divided—make up all stuff. The second portion of the theory states that the mass and characteristics of every atom in a certain element are the same. Compounds, according to the third section, are atoms that combine two or more distinct types.

The substance is referred to as.

KOM-pownd a substance in chemistry that is produced by the chemical fusion of a number of distinct elements Water is a chemical made of a elements oxygen and hydrogen, while table salt is a compound made of the elements sodium and chloride.

What does the word "compound" mean?

When two or more distinct chemical elements are combined in a specified order, a compound is produced. Chemical bonds that are difficult to break are created by the interaction of a components.

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During aerobic respiration, h2o is formed. Where does the oxygen atom for the formation of the water come from?.

Answers

For the creation of water, molecular oxygen provides the oxygen atom.

Where does the oxygen atom come from that directly contributes to the creation of water?

As the ETC's final electron acceptor, oxygen performs this function. The oxygen atoms then absorb the electrons from the complex IV and combine with the protons of hydrogen to form water. The oxygen atoms are extracted from the gaseous oxygen.

Where does the oxygen atom that is needed to create water during aerobic respiration come from?

All that is known is that this oxygen atom was initially one of the atoms in the process' reactants.

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A student stirs a cup of hot chocolate with a cold metal spoon and observes that the spoon becomes warmer. According to the law of conservation of energy, which answer choice best describes why the spoon became warmer? The high-energy hot chocolate particles transfer some of their energy to the spoon particles, which causes the spoon to become warmer. The high-energy spoon particles destroy some of the hot chocolate particles, which causes the spoon to become warmer. The high-energy hot chocolate particles destroy some of the spoon particles, which causes the spoon to become warmer. The high-energy spoon particles transfer some of their energy to the hot chocolate particles, which causes the spoon to become warmer.

Answers

The high-energy hot chocolate particles transfer some of their energy to the spoon particles, which causes the spoon to become warmer.

It is found that up to 0.0980 g of Agloz dissolves in 2.00 L of aqueous solution at a certain temperature. Determine the value of Ksp for AglO3. 1 2 Based on the given values, fill in the ICE table to determine concentrations of all reactants and products. AglO3(s) = Ag+ (aq) + 103-(aq) Initial (M) Change (M) Equilibrium (M)

Answers

The value of Ksp for AglO₃, if it is found that up to 0.0980 g of Aglo₃ dissolves in 2.00 L of aqueous solution at a certain temperature, is 0.2625 mol/L

To determine the value of Ksp for AglO₃, we must find the concentration of Ag⁺ ion and IO₃⁻ ion in the saturated solution of AglO₃ be x M. Since one mole of AglO₃ produces one mole of Ag⁺ ion and one mole of IO₃⁻ ion. The balanced chemical equation for the dissociation of AglO₃ is as follows:

AglO₃(s) ⇌ Ag+ (aq) + IO₃⁻(aq)

Initially, the concentration of AglO₃ is x M. As the AglO₃ is completely dissociated in the aqueous solution, the concentration of Ag⁺ ion and IO₃⁻ ion also become x M at the equilibrium. Hence, the equilibrium concentration of Ag⁺ ion and IO₃⁻ ion is x M.

The Ksp expression for the dissociation of AglO₃ is as follows:

Ksp = [Ag⁺][IO₃⁻]

Ksp = x × x = x²

Ksp = 0.0980 g/ (2.00 L) × 1000 g/ 1 kg × 1 mol/ 187.81 g

= 0.2625 mol/L (approx)

Thus, the value of Ksp for AglO₃ is 0.2625 mol/L.

ICE table is shown below:

              AglO₃(s) ⇌ Ag⁺ (aq) + IO₃⁻(aq)

Initial (M)       x              0                 0

Change (M) -x              +x               +x

Equilibrium (M) x          x                 x

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How many moles of HCI can be produced from 0.424 gram of SOCI₂?
SOCI2 + H₂O → SO₂ + 2HCI

700 moles
0.00700 moles
0.0038 moles
0.040 moles

Answers

Mole of HCI = 0.00700 moles

what is moles?The mole is the amount of substance of a system which contains as many elementary entities as there are atoms in 0.012 kilogram of carbon 12; its symbol is “mol”A mole is a very important unit of measurement that chemists use. A mole of something means you have 602,214,076,000,000,000,000,000 of that thing, like how having a dozen eggs means you have twelve eggs. Chemists have to measure using moles for very small things like atoms, molecules, or other particles., a mole of water contains NA number of H2O molecules. However, each water molecule contains 2 hydrogen atoms and one oxygen atom. Therefore, one mole of H2O contains 2 moles of hydrogen and one mole of oxygen

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An isotope of neon has an atomic mass of 22.0 grams per mole. Calculate the relative rates of diffusion of the isotope of neon and carbon dioxide. The molecular mass of CO2 is 44.0 grams per mole.​

Answers

The relative rates of diffusion of the gasses is √2 from the calculation.

What is the rate of diffusion?

The rate of diffusion refers to the speed at which particles or molecules spread or disperse through a medium from an area of higher concentration to an area of lower concentration.

We know that from the Graham's law, we have that;

\(R_{1}\)/\(R_{2}\) = √\(M_{2}\)/\(M_{1}\)

\(R_{1}\)= rate of diffusion of Ne

\(R_{2}\)  = rate of diffusion pf carbon dioxide

\(M_{2}\)= molar mass of carbon dioxide

\(M_{1}\) = molar mass of Ne

Then;

\(R_{1}\)/\(R_{2}\) = √44/22

\(R_{1}\)/\(R_{2}\) =  The relative rates of diffusion of the gasses is √2

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How many moles are there in 15.0 grams of sio2?
a
0.170 mol
b 0.340 mol
c 0.534 mol
d 0.250 mol
e 0.208 mol
check it

Answers

the answer is D. 0.250 mol

PLEASE ANSWER QUICK!!!! 35 POINTS RIGHT ANSWERS ONLY!!!!!!!
How much energy does the water in this experiment absorb according to the calorimeter data?

PLEASE ANSWER QUICK!!!! 35 POINTS RIGHT ANSWERS ONLY!!!!!!!How much energy does the water in this experiment

Answers

The heat energy absorbed by the water in the experiment according to the calorimeter data is 10450 J

How do i determine the heat energy absorbed by the water?

From the question give above, the following data were obtained:

Mass of water (M) = 100.0 gSpecific heat capacity of water (C) = 4.18 J/gºC Initial temperature of water (T₁) = 21.2 °CFinal temperature of water (T₂) = 46.2 °CChange in temperature (ΔT) = 46.2 - 21.2 = 25 °C Heat absorbed by water (Q) =?

From calorimetry, we understood that heat absorbed is given by the following formula

Q = MCΔT

Inputting the given parameters, we can obtain the heat absorbed by the water as follow:

Q = 100 × 4.18 × 25

Q = 10450 J

Thus, we can conclude that the heat energy absorbed by the water is 10450 J

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an orbital is defined as a region of the most probable location of

Answers

Answer:

Electron

The three-dimensional region around the nucleus, an orbital, indicates the probable location of an electron. Describe the contributions of each of the following experimenters to our understanding of the atom. 1. Louis de Broglie hypothesized that electrons have wavelike properties.

Explanation:

Hope it helps

A 1.07 g sample of a noble gas occupies a volume of 0.363 L at 308 K and 90.3 kPa.
Identify the noble gas in this sample.

Answers

The noble gas is Kyrpton

Ideal gas equationThe ideal gas equation gives the relationship between moles volume, temperature and pressure of a gas

The ideal gas equation is give below:

PV = nRT

where P is pressure, V is volume, T is temperature,n is number of moles andR is molar gas constant; R = 8.314 LkPa/K.mol

number of moles n = mass/molar mass

n = m/Mm

therefore, the ideal gas equation becomes;

PV = mRT/Mm

Mm = mRT/PV

substituting the data provided

Mm = 1.07 * 308 * 8.314/90.3 * 0.363

Mm, molar mass = 83.6

the noble gas that has a mass of 83.6 is Krypton.

Therefore, the noble gas is Kyrpton

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What is the other name for a helium nucleus?

Answers

Hi there.

Thanks for chosing Brainly! How are you today?

Another name for Helium Nucleus is Alpha Particle.

Alpha Particles are the same as a Helium Nuclues, just a different word usage. They have the same definitions.

Thanks for your question.

- Tutor John

Explain the differences between bronze and brass, and steel and cast iron. Which is best used for cooking wares?

Answers

Answer:

Steel and cast iron

Explanation:

They are all metal but assuming that you are finding the best material for your pan i suggest going for steel or cast iron

Estimate the ΔH (kcal/mol) for the reaction of hydrogen and oxygen to form water: 2 H2 + O2 2 H2O ΔH = ?

Answers

To estimate the deltaH for the reaction we can do it from the bond energies, that is, starting from the energy needed to form or break a bond.

The reaction energy will be equal to the binding energy of the reactants minus the binding energy of the products. To calculate each bond energy we must first identify which bonds are involved in the reaction. They give us a balanced reaction:

\(2H_2+O_2\rightarrow2H_2O\)

For the reaction, we have the following bonds

\(\begin{gathered} 2\lbrack H-H\rbrack+1\lbrack O=O\rbrack\rightarrow2\lbrack H-O-H\rbrack \\ 2\lbrack H-H\rbrack+1\lbrack O=O\rbrack\rightarrow2\times2\lbrack O-H\rbrack \end{gathered}\)

Now we are going to calculate the energy taking into account the values that we can find in tables of the bond energy.

Bond Ee (kJ/mol)

H - H 436

O=O 499

O - H 460

Therefore the energy on each side of the reaction will be:

\(\begin{gathered} 2\lbrack H-H\rbrack+1\lbrack O=O\rbrack\rightarrow2\times2\lbrack O-H\rbrack \\ 2\times436\frac{kJ}{mol}+1\times499\frac{kJ}{mol}\rightarrow2\times2\times460\frac{kJ}{mol} \\ 1371\frac{kJ}{mol}\rightarrow1840\frac{kJ}{mol} \end{gathered}\)

The reaction energy will be:

\(\begin{gathered} \Delta H_r=\Delta H_{Reac\tan ts}-\Delta H_{Products} \\ \Delta H_r=1371\frac{kJ}{mol}-1840\frac{kJ}{mol}=-469\frac{kJ}{mol} \end{gathered}\)

We have an exothermic reaction since the result is negative. This means that the energy of the products is greater than that of the reactants.

Now we will convert the energy units to kcal:

\(\Delta H_r=-469\frac{kJ}{mol}\times\frac{1\text{kcal}}{4.184kJ}=-112\frac{kcal}{\text{mol}}\)

ΔH (kcal/mol) estimated of the reaction will be -112kcal/mol

2. If you put 156. 32g barium hydroxide into this reaction, how much aluminium hydroxide can be

produced?

Answers

When 156.32 g of barium hydroxide is reacted, approximately 142.34 g of aluminum hydroxide can be produced, based on the balanced chemical equation and stoichiometry.

To determine the amount of aluminum hydroxide that can be produced when 156.32 g of barium hydroxide is reacted, we need to consider the balanced chemical equation for the reaction and use stoichiometry.

The balanced chemical equation for the reaction is:

Ba(OH)2 + 2AlCl3 → 2Al(OH)3 + 3BaCl2

From the balanced equation, we can see that for every 1 mole of Ba(OH)2, 2 moles of Al(OH)3 are produced.

First, we need to calculate the number of moles of barium hydroxide (Ba(OH)2) in 156.32 g:

Molar mass of Ba(OH)2 = (137.33 g/mol + 2(16.00 g/mol + 1.01 g/mol)) = 171.34 g/mol

Moles of Ba(OH)2 = mass / molar mass = 156.32 g / 171.34 g/mol = 0.911 mol

Now, using the stoichiometry of the balanced equation, we can determine the moles of aluminum hydroxide (Al(OH)3) produced:

Moles of Al(OH)3 = 2 × Moles of Ba(OH)2 = 2 × 0.911 mol = 1.822 mol

Finally, to convert the moles of aluminum hydroxide to grams, we need to multiply by the molar mass of Al(OH)3:

Molar mass of Al(OH)3 = (26.98 g/mol + 3(16.00 g/mol + 1.01 g/mol)) = 78.00 g/mol

Mass of Al(OH)3 = Moles of Al(OH)3 × molar mass = 1.822 mol × 78.00 g/mol = 142.34 g

Therefore, when 156.32 g of barium hydroxide is reacted, approximately 142.34 g of aluminum hydroxide can be produced.

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Select all that apply. Which of the following are limitations to ocean exploration? a lack of interest problems with breathing O intense pressure o few technological advances too many marine organisms​

Answers

Answer:

ABintense pressure and breathin

Explanation:

because scientist never have the tech to go deeper

Answer:

B. Problems with breathing

C. Intense pressure

: Predict the products of a reaction between AgNO3(aq) and KBr(aq) A. NO(g) and Ag(s)
B. Br2(liq) and Ag(s) C. AgBr(s) and KNO3(aq) D. AgNO3(aq) and KBr(aq)

Answers

The products of the reaction between AgNO3(aq) and KBr(aq) are AgBr(s) and KNO3(aq).

When AgNO3(aq) and KBr(aq) are mixed together, a double replacement reaction occurs. In this type of reaction, the positive ions of one compound switch places with the positive ions of the other compound. The balanced equation for the reaction is:

AgNO3(aq) + KBr(aq) → AgBr(s) + KNO3(aq)

Therefore, the products of the reaction are AgBr(s) (silver bromide) and KNO3(aq) (potassium nitrate). The AgBr(s) is a precipitate, which means it forms as a solid in the solution. The KNO3(aq) remains dissolved in the solution.

Option C, AgBr(s) and KNO3(aq), correctly represents the products of the reaction. Option A, NO(g) and Ag(s), is incorrect because there is no gas formed in this reaction, and silver metal (Ag) does not precipitate out. Option B, Br2(liq) and Ag(s), is incorrect because the reaction does not involve the formation of elemental bromine (Br2). Option D, AgNO3(aq) and KBr(aq), is incorrect as it represents the starting reactants and not the products formed during the reaction.

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What are water turbines used for?

Answers

Answer:

A water turbine is used to convert the energy contained in water, potential energy or kinetic energy, into mechanical or electrical energy. There are two types of water turbines, the reaction water turbine, and the impulse water turbine.

Explanation:

Answer:

Water turbines are used to take energy whether it may be kinetic or potential from the water and convert that energy into mechanical, or electrical energy.

Explanation:

lassify each of the following as an example of a chemical property or a physical property. (a) rubbing alcohol evaporates quickly at room temperature: physical (b) a slice of apple will turn brown if left out in the air: (c) sodium metal (na) reacts violently with water: physical (d) chlorine gas (cl2) is a yellowish-green color: (e) the chemical compound nitrogen triiodide (ni3) explodes with just the slightest touch: (f) mercury (hg) is a liquid at room temperature: physical

Answers

Rubbing alcohol evaporates quickly at room temperature" is a physical property.  "A slice of apple will turn brown if left out in the air" is a chemical property.  "Sodium metal (Na) reacts violently with water" is a chemical property.  "Chlorine gas (Cl2) is a yellowish-green color" is a physical property.  "The chemical compound nitrogen triiodide (NI3) explodes with just the slightest touch" is a chemical property.  "Mercury (Hg) is a liquid at room temperature" is a physical property.

physical: Evaporation is a physical property because it is a change in the state of a substance (from liquid to gas) that does not involve a chemical reaction.

chemical: The browning of an apple slice is a chemical change because it involves a chemical reaction that produces new substances.

chemical: The reaction of sodium metal with water is a chemical change because it involves a chemical reaction that produces new substances.

physical: Color is a physical property because it is a characteristic that can be observed without changing the substance's chemical composition.

chemical: Nitrogen triiodide exploding is a chemical change because it involves a chemical reaction that produces new substances.

physical: Mercury is a liquid at room temperature because of its atomic structure and the physical state of matter is determined by the strength of the intermolecular forces between atoms.

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F) Suppose you saw a vipening. You asked green apple tu xhing ved while turining this questions to your science teacher and got answer what step of scientific learning did you follow?​

Answers

There has been extensive research on how learning works across many different academic fields.

Thus,  Basic studies of the brain mechanisms underlying learning in humans and other species have traditionally been conducted in the fields of neurology and biology and learning.

Studies of how the human mind "computes," creating and applying knowledge, have typically been conducted in the fields of cognitive science and psychology and academic fields.

Studies of how machines (such as computers and robots) learn have typically been conducted in the fields of computer science and other branches of engineering; and studies of how learning occurs in the learning.

Thus, There has been extensive research on how learning works across many different academic fields.

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what bbolume of a 17.5 m stock soultion of acetic acid is required to prepare a 500 ml solution of 1.00 m acetic acid

Answers

Total, 28.6 mL of the 17.5 M stock solution of acetic acid is required to prepare a 500 mL solution of 1.00 M acetic acid.

To determine the volume of the 17.5 M stock solution of acetic acid required to prepare a 500 mL solution of 1.00 M acetic acid, we can use the following formula:

V₁ × C₁ = V₂ × C₂

Where; V₁ = Volume of the stock solution (in liters)

C₁ = Concentration of the stock solution (in moles per liter)

V₂ = Volume of the final solution (in liters)

C₂ = Concentration of the final solution (in moles per liter)

Converting given values to required units;

V₁ = ?

C₁ = 17.5 M

V₂ = 500 mL = 0.5 L

C₂ = 1.00 M

Now, we can plug in the values into the formula and solve for V₁

V₁ × (17.5 M) = (0.5 L) × (1.00 M)

V₁ = (0.5 L × 1.00 M) / 17.5 M

= 0.0286 L

≈ 28.6 mL

Now, we can plug in the values into the formula and solve for V₁

V₁ × (17.5 M) = (0.5 L) × (1.00 M)

V₁ = (0.5 L × 1.00 M) / 17.5 M

= 0.0286 L

≈ 28.6 mL

Therefore, approximately 28.6 mL of the 17.5 M stock solution of acetic acid is required.

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Which of the models shown below best represents the modern understanding of the structure of the atom?
Model B
Model A
Model A
Model C
Photos by Phood and Furman
Model B
ОО
Model C

Which of the models shown below best represents the modern understanding of the structure of the atom?Model

Answers

Answer:

The answer may be A because that's what I believe

Here, assume a protein with a melting/unfolding temperature of 78 ºC, an enhtalpy of unfolding ?uHº(Tm) of 400 kJ/mol and a ?CP of 9 kJ/(K mol). Part A - Temperature of maximum stability Calculate the temperature of maximum stability of the protein, i.e. the temperature for which the unfolding free energy reaches a maximum. Provide your answer with 3 significant figures. The margin of error is 2%. Part B - How many proteins are unfolded? Estimate how many proteins per million will be statistically unfolded at the temperature of maximum stability.

Answers

Part A - The temperature of maximum stability for the protein can be calculated using the Gibbs-Helmholtz equation.

It is as \(Tm = ?uHº/?Cp + Tm0\), where \(Tm0\) is the temperature at which ?Gº = 0 (i.e. the folding and unfolding of the protein are in equilibrium). Substituting the given values, we get \(Tm = (400 kJ/mol)/(9 kJ/(K mol)) + 78 ºC = 122 ºC\)  (rounded to 3 significant figures). To account for the margin of error of 2%, the range of temperatures for maximum stability is\(119 ºC to 125 ºC.\)  Part B - At the temperature of maximum stability, the fraction of unfolded proteins can be estimated using the Boltzmann distribution, which describes the probability of a system being in a particular energy state. The fraction of unfolded proteins, f, is given by\(f = e^(-?Gº/RT)\) , where ?Gº is the change in free energy upon unfolding, R is the gas constant, and T is the absolute temperature. At \(Tm, ?Gº = 0,\)  so all proteins will be folded. However, as the temperature deviates from Tm, the fraction of unfolded proteins will increase exponentially. For example, at 120 ºC (which is 1.6% above Tm), the fraction of unfolded proteins will be \(f = e^(-(400 kJ/mol)/(8.314 J/(mol K) x 393 K)) = 0.0025\) , or 2500 proteins per million. At \(124 ºC (which is 2.6% above Tm),\)  the fraction of unfolded proteins will \(be f = e^(-(400 kJ/mol)/(8.314 J/(mol K) x 397 K)) = 0.06\) , or 60,000 proteins per million. Therefore, small deviations from Tm can lead to a significant increase in the fraction of unfolded proteins.

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When iron oxide (Fe2O3) forms what type of bonding happens?

Answers

Answer:

It is represented by Fe2O3. The oxidation state of iron oxide is +3 and +2. The bond formed between iron and oxygen is due to the difference in electronegativity between the two atoms. Since iron is metal and oxygen is non-metal therefore the bonding between oxygen and iron is ionic.

Explanation:

The density of sucrose, table sugar, is 1.56 g/cc. What volume (in cubic centimeters) does 72.0 g of sucrose occupy?

Answers

The volume of sucrose that has a density of 1.56g/cm³ and a mass of 72g is 46.2cm³.

How to calculate volume?

The volume of a substance can be calculated by dividing the mass of the substance by its density.

Volume = mass ÷ density

According to this question, the density of sucrose, table sugar, is 1.56 g/cm³ with a mass of 72.0 g. The volume can be calculated as follows:

Volume = 72g ÷ 1.56g/cm³

Volume = 46.2cm³

Therefore, volume of sucrose that has a density of 1.56g/cm³ and a mass of 72g is 46.2cm³

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