Ice at 0. 0∘c has a density of 917 kg/m3. a 3. 00 cm3 ice cube is gently released inside a small container filled with oil and is observed to be neutrally buoyant. what is the density of the oil, rhooil?

Answers

Answer 1

The density of the oil is 917kg/ m³.

An object is said to be naturally buoyant when ithas the tendency to float in a fluid.

from the law of floating when a body float in a liquid,the weight of the liquid displaced by its immersed part is equal to the total weight of body.

That is

weight (w)=upthrust (u)

w=u

therefore

u=Dvg

where, D= density of the ice

v= volume of ice

g= acceleration due to gravity

from the question

given:

 D  = 917kg/m {}^{3} \)

v = 3.00cm {}^{3} \)

g = 9.8m/s {}^{2} \)

substitute these values in above equation

u = 917(3 \times 10 {}^{ - 6} )(9.8)\)

u=0.027N

but,

upthrust= weight of oil displaced.And the ice will displaced an amount of oil,equal to its own weight.

therefore,

density of oil = u/gv = (0.027)/3 \times 10 {}^{ - 6)} (9.8)\)

density of oil = 917kg/m {}^{3} \)

hence the density of the oil is 917kg/m {}^{3} \)

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Related Questions

A fish swimming in a horizontal plane has velocity v with arrowi = (4.00 î + 1.00 ĵ) m/s at a point in the ocean where the position relative to a certain rock is r with arrowi = (14.0 î − 2.80 ĵ) m. After the fish swims with constant acceleration for 19.0 s, its velocity is v with arrow = (23.0 î − 1.00 ĵ) m/s.
(a) What are the components of the acceleration of the fish?
ax =
m/s2
ay =
m/s2

(b) What is the direction of its acceleration with respect to unit vector î?
° counterclockwise from the +x-axis

(c) If the fish maintains constant acceleration, where is it at t = 26.0 s?
x =
m
y =
m

In what direction is it moving?
° counterclockwise from the +x-axis

Answers

(a) We can find the components of the acceleration of the fish by using the following kinematic equation:

v = u + at

where u is the initial velocity, v is the final velocity, a is the acceleration, and t is the time interval.

Let's find the acceleration of the fish in the x-direction first:

v_x = u_x + a_xt

where v_x is the x-component of the final velocity, u_x is the x-component of the initial velocity, a_x is the x-component of the acceleration, and t is the time interval.

Substituting the given values, we get:

23.0 = 4.00 + a_x * 19.0

Solving for a_x, we get:

a_x = (23.0 - 4.00) / 19.0 = 0.895 m/s^2

Similarly, we can find the acceleration of the fish in the y-direction:

v_y = u_y + a_yt

where v_y is the y-component of the final velocity, u_y is the y-component of the initial velocity, a_y is the y-component of the acceleration, and t is the time interval.

Substituting the given values, we get:

-1.00 = 1.00 + a_y * 19.0

Solving for a_y, we get:

a_y = (-1.00 - 1.00) / 19.0 = -0.105 m/s^2

Therefore, the components of the acceleration of the fish are:

a_x = 0.895 m/s²

a_y = -0.105 m/s²

What is acceleration?

The rate of change of velocity of an object over the course of time is defined as acceleration.  It is a vector quantity, that also means it has magnitude as well as direction. Acceleration occurs when an object changes its velocity, either by increasing or decreasing its speed or by changing its direction of motion. The following formula may be utilized to calculate an object's acceleration:

a = (v_f - v_i) / t

(b) To find the direction of the acceleration with respect to unit vector î, we can use the following formula:

θ = tan⁻¹(a_y / a_x)

Substituting the values we just found, we get:

θ = tan⁻¹(-0.105 / 0.895) = -6.84°

Therefore, the direction of the acceleration with respect to unit vector î is 6.84° clockwise from the +x-axis.

(c) To find the position of the fish at t = 26.0 s, we can use the following kinematic equations:

x = u_xt + 0.5 a_xt²

y = u_yt + 0.5 a_yt²

where x is the position in the x-direction, y is the position in the y-direction, u_x is the initial velocity in the x-direction, u_y is the initial velocity in the y-direction, a_x is the acceleration in the x-direction, a_y is the acceleration in the y-direction, and t is the time interval.

Let's first find the position of the fish in the x-direction:

x = u_xt + 0.5 a_xt²

Substituting the given values, we get:

x = 14.0 + 0.5 * 0.895 * (26.0 - 19.0)² = 37.4 m

Similarly, we can find the position of the fish in the y-direction:

y = u_yt + 0.5 a_yt²

Substituting the given values, we get:

y = -2.80 + 0.5 * (-0.105) * (26.0 - 19.0)²= -3.17 m

Therefore, the fish is at the position (37.4 m, -3.17 m) at t = 26.0 s.

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A car increases its speed from 30 km/h to 60 km/h in 5 seconds. Its acceleration​

Answers

Answer:6km/sec

Explanation: Acceleration = Change in velocity / Time

Change in velocity = 60km/h minus 30km/hr

Time = 5seconds

Think of one example where Bob would need to calculate the net force on a person at the water park.

Think of one example where Bob would need to calculate the net force on a person at the water park.

Answers

Well Bob would need to calculate to net force of someone going down a water slide. Since the person is going down the slide, the person will go faster, depending on their mass/weight and the gravitational pull. As phrased in Newton’s Second Law.


Newton’s Second Law:
Newton's second law of motion pertains to the behavior of objects for which all existing forces are not balanced. The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object.

An example of the scenario where Bob would need to calculate the net force will be when there's someone going down on a water slide.

The net force refers to the sum of the forces that act on an object. Net force is vital for the acceleration of mass.

For example, when we kick a football, the ball takes off and then moves through the air. In this case, a net force acts on the football.

Also, when there's someone going down on a water slide, the net force can be calculated.

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explain the condition of the velocities of two bodies in motion when their velocities are added for relative velocity.​

Answers

Answer:

We encounter occasions where one or more objects move in a frame which is non-stationary with respect to another observer. For example, a boat crossing a river that is flowing at some rate or an aeroplane encountering wind during its motion.

Explanation:

The compounds that make up
plastic are ___________
because they contain carbon and
hydrogen

The compounds that make upplastic are ___________because they contain carbon andhydrogen

Answers

Answer:

ethylene

Explanation:

ethylene is a compound consist of two double bonded carbon atom and four hydrogen atoms at room temperature is a gas

Answer:

Ethylene

Explanation:

Because Ethylene is a simple molecule composed of two double-bonded carbon atoms and four hydrogen atoms. It's a gas at room temperature. Ethylene molecules can be chemically bonded, end to end, to form a polymer named polyethylene.

A car traveling south is 200 kilometers from its starting point after 2 hours. What is the average velocity of the car? (OP A. 100 kilometers/hour south B. 200 kilometers/hour C. 200 kilometers/hour north 100 kilometers/hour ​

Answers

Answer:

A

Explanation:

take note that v=d/t (velocity is distance over(divided by) time, so in this case it would be 200 (distance) divided by 2 (time)

the sears tower in chicadgo sways back and forth at a frequency of 0.1 hz. what is the period of vibation?

Answers

The period of vibration of the Sears Tower in Chicago is 10 seconds.

The period of vibration of the Sears Tower in Chicago can be calculated using the formula T = 1/f, where T represents the period and f represents the frequency. Therefore, the period can be calculated as follows:

T = 1/0.1 Hz
T = 10 seconds

So the period of vibration of the Sears Tower in Chicago is 10 seconds.

The period of vibration is the time it takes for one complete cycle of motion. In this case, the Sears Tower in Chicago sways back and forth at a frequency of 0.1 Hz, which means it completes 0.1 cycles of motion per second. To calculate the period of vibration, we can use the formula T = 1/f, where T is the period and f is the frequency. Plugging in the given frequency, we get T = 1/0.1 Hz, which simplifies to T = 10 seconds. Therefore, the period of vibration of the Sears Tower in Chicago is 10 seconds.

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A 7.50 kg bowling ball moving6.42 m/s strikes a 1.60 kg bowlingpin at rest. After, the pin moves14.8 m/s at a -47.0° angle. Whatis the y-component of the ball'sfinal velocity?y-component (m/s)Enter

A 7.50 kg bowling ball moving6.42 m/s strikes a 1.60 kg bowlingpin at rest. After, the pin moves14.8

Answers

let the bowling ball initially is moving along the x-axis,

The whole process can be represented as,

Before the collision the net kinetic energy of the balls is,

\(K_{iy}=\frac{1}{2}\times m_1\times(v_1\cos (90^o))^2+\frac{1}{2}\times m_2\times(0)^2\)

where the values of the variables are given as,

\(\begin{gathered} m_1=7.5\text{ kg} \\ v_1=6.42ms^{-1} \\ m_2=1.6\text{ kg} \end{gathered}\)

As the value of cos(90) is zero.

Substituting the known values,

The value of the net kinetic energy with the velocity along the y-axis before the collision is,

\(K_{iy}=0\)

The velocity of the second ball is at rest in the initial state, thus its value is taken as zero.

After the collision of the balls, the net kinetic energy is,

\(\begin{gathered} K_{fy}=\frac{1}{2}\times m_1\times(v^{\prime}_1\sin (\alpha))^2+\frac{1}{2}\times m_1\times(v^{\prime}_2\sin (-47^o))^2 \\ K_{fy}=\frac{1}{2}\times m_1\times(v_{1fy})^2+\frac{1}{2}\times m_1\times(v^{\prime}_2\sin (-47^o))^2 \end{gathered}\)

Negative sign here indicating the direction of the final balls motion will be opposite to the each other.

The values of the variables are given as,

\(v^{\prime}_2=14.8ms^{-1}\)

Substituting the known values,

The value final kinetic enegry of the balls with velocity along the y-axis is,

\(\begin{gathered} K_{fy}=\frac{1}{2}\times7.5\times(v_{1fy})^2+\frac{1}{2}\times1.6\times(14.8\times\sin (360^o-47^o)^2 \\ K_{fy}=3.75\times(v_{1fy})^2-93.72 \end{gathered}\)

Here 360 degree is used because the pin ball direction is downward of the positive x-axis.

Then by the law of conservation of energy along the y-axis,

\(\begin{gathered} K_{iy}=K_{fy} \\ 0=3.75\times(v_{1fy})^2-93.72 \\ (v_{1fy})^2=\frac{93.72}{3.75} \\ (v_{1fy})^2=25 \\ v_{1fy}=5ms^{-1} \end{gathered}\)

Thus, the y component of the final velocity of the bowling ball of mass m1 is 5 meter per second.

A 7.50 kg bowling ball moving6.42 m/s strikes a 1.60 kg bowlingpin at rest. After, the pin moves14.8

What happened to the maximum height of consecutive swings

Answers

Answer:

we need more info

Explanation:

a particle undergoes three successive displacements in a plane, as follows: , 4.00 m southwest; then , 5.00 m east; and finally , 6.00 m in a direction 60.0° north of east. choose a coordinate system with the y axis pointing north and the x axis pointing east. what are (a) the x component and (b) the y component of ? what are (c) the x component and (d) the y component of ? what are (e) the x component and (f) the y component of ? next, consider the net displacement of the particle for the three successive displacements. what are (g) the x component, (h) the y component, (i) the magnitude, and (j) the direction of the net displacement? if the particle is to return directly to the starting point, (k) how far and (l) in what direction should it move?

Answers

let east is the positive x direction

north is the positive y direction

for the net displacement

d = 4 * (- cos(45) i - j * sin(45)) + 5 i + 6 * (cos(60) i + j * sin(60))

d = 5.17 i + 2.37 j

for the return vector

d = - 5.17 i - 2.37 j

d = sqrt(5.17^2 + 2.37^2) at arctan(2.37/5.17) degree south of west

d =  5.69 m at 24.6 degree south of west  

the return vector is 5.69 m at 24.6 degree south of west  

displacement is defined as the change in position of an object from one point to another in a straight line with direction

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If a runner's power is 400 W as she runs, how much chemical
energy does she convert into other forms in 10.0 minutes?

Answers

Answer:

\(240 kJ\)

Explanation:

A Watt is defined as a Joule per second. 10.0 minutes, converted in seconds, are \(10.0*60 =600s\). At this point, we just multiply the two numbers: \(400 J/s * 600.0s = 240 000.0J\)

1. Give the reason of magnesium has valency two​

Answers

It is because magnesium has 2 electrons in its outermost shell .

What is stagflation stagflation occurs when ?.

Answers

Stagflation is the simultaneous look in an economic system of gradual increase, excessive unemployment, and growing costs.

As soon notion by economists to be impossible, stagflation has passed off repeatedly within the advanced international since the 1970s. policy answers for gradual growth generally tend to worsen inflation and vice versa.

Stagflation is a scenario of each excessive inflation and high unemployment; happens while output is falling at the same time that prices are rising. The life of labor unions and salary controls in nationalized industries sparked it.

Economists have proven that stagflation changed into conventional amongst seven primary marketplace economies from 1973 to 1982. After inflation quotes started to fall in 1982, economists' awareness shifted from the causes of stagflation to the "determinants of productiveness boom and the results of actual wages at the call for exertions".

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In what part of the electromagnetic spectrum does the sun radiate maximum energy? How does this compare to earth?

Answers

The visible region of the electromagnetic spectrum is where the Sun radiates maximum energy. Since Earth is substantially cooler, the majority of the radiation it emits is longwave radiation.

The complete spread of electromagnetic radiation by wavelength or frequency. Despite the fact that all electromagnetic waves have a wide range of frequencies, wavelengths, and photon energies, they all move at the speed of light in a vacuum known as the electromagnetic spectrum.

The sun emits electromagnetic waves over a wide spectrum, from radio waves with a wavelength of 10 meters to X-rays with a wavelength of 2 nanometers. Visible light, with a wavelength of around 500 nanometers, is the most powerful of them to reach the earth's surface. The visible spectrum is where the Sun's energy is most intensely emitted. The maximum amount of radiation that the Earth emits occurs at 10 mm, in the infrared heat spectrum. Since the Earth's surface temperature is far lower than that of the sun and its radiation has longer wavelengths than solar radiation, the majority of this energy is then reradiated into space. The atmosphere is easily able to absorb the longer wavelengths that the Earth radiates.

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Spring constant of 80 N/m how much elastic potential if it’s stretched .20 metered

Answers

The elastic potential energy of the spring is 1.6 J.

What is the elastic potential energy of the spring?

The elastic potential energy of the spring is the energy stored in the spring and it is calculated as follows;

U = ¹/₂kx²

where;

k is the spring constant x is the extension of the spring

The given parameters include;

the spring constant of the spring, k = 80 N/mthe extension of the spring, x = 0.2 m

U = ¹/₂kx²

U = ¹/₂ (80) (0.2)²

U = 1.6 J

Thus, the elastic potential energy of the spring is a function of the spring constant and the extension of the spring.

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A 2. 74 kg object and changes velocity by 16. 49 m/s in 16. 19 s. How large of a force acted on the object? Which choice represents the best formula to calculate this answer?

Answers

The force on the object is 0.822 N.

Forces affect the motion of objects. They can cause movement. You can also slow down, stop, or change the direction of objects that are already moving. We say that a force changes its velocity because it changes the speed or direction of an object. Remember that acceleration is a change in velocity. F= mdv / dt

So m= 2.74 kg and dv= 16.49-16.19 = 0.30.

If time is 1 second,

F=2.74*0.3

= 0.822N

Therefore, the force on the object is 0.822 N.

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you touchdown long with a speed of 145 knots on a 8,501 foot runway and the braking is not working, so you decide to takeoff and climbout. the engines require 5 seconds to spool up and then the airplane requires 10 seconds of acceleration to lift off again. the 4,000 foot marker flashed by 2 seconds ago. do you have enough runway to lift off? (use 143 knots for average ground speed due to the tailwind.)

Answers

The answer is yes, the airplane has enough runway to lift off.

To determine whether the airplane has enough runway to lift off, we need to calculate how far the airplane will travel during the spool-up time and the acceleration time, and compare this distance to the remaining runway.

First, let's convert the touchdown speed of 145 knots to feet per second:

\(145 knots = 145 * 1.68781 = 244.78 ft/s\)

Next, let's calculate the distance traveled during the spool-up time:

distance_spoolup = \(244.78 * 5 = 1223.9 ft\)

During the 10 seconds of acceleration, the airplane will cover a distance given by:

distance_acceleration =\(0.5 * a * t^2\)

where a is the acceleration and t is the time of acceleration. We don't know the acceleration of the airplane, but we can use the fact that the average ground speed due to tailwind during the previous landing was 143 knots, or 143 * 1.68781 = 241.94 ft/s. This means that the airplane's acceleration must be at least:

\(a = (143 - 244.78) / 10 = -10.478 ft/s^2\)

Note that the acceleration is negative because the airplane is decelerating during the spool-up time.

Using this acceleration, we get:

distance_accelera\(1223.9 - 523.9 = 700 ft\)tion = \(0.5 * (-10.478) * 10^2 = -523.9 ft\)

The negative sign indicates that the airplane will decelerate during the acceleration time, but this is expected since we are assuming that the airplane's brakes are not working.

So the total distance traveled during the spool-up time and the acceleration time is:

total_distance = distance_spoolup + distance_acceleration =

Since the 4,000-foot marker flashed by 2 seconds ago, this means that the airplane has traveled 2 seconds * 143 ft/s = 286 ft since the marker. Therefore, the remaining runway is:

remaining_runway =\(8501 - 4000 - 286 = 4215 ft\)

The airplane needs at least 700 ft to lift off, so the question is whether it has enough runway left to cover this distance. Since the remaining runway is 4215 ft and the required distance is 700 ft, the airplane can lift off without running out of the runway.

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Which accurately explains concave and convex lenses?

a - With both concave and convex lenses, placement of the object dictates which side of the lense the image will appear.
b - With both concave and convex lenses, placement of the object does not dictate which side of the lense the image will appear.
c - With concave lenses, placement of the object does not dictate which side of the lense the image will appear, but with convex lenses, they do.
d- With convex lenses, placement of the object does not dictate which side of the lense the image will appear, but with concave lenses, they do.

Answers

Answer:

c

Explanation:

on edg

If a circuit has 48 amps of current and an applied voltage of 240 volts, the resistance is ___.
a. 5 ohms
b. 10 ohms
c. 15 ohms
d. 25 ohms

Answers

To calculate the resistance in the circuit, you can use Ohm's Law, which is V = I * R, where V represents voltage, I represents current, and R represents resistance.

Given that the circuit has 48 amps of current (I) and an applied voltage of 240 volts (V), you can rearrange Ohm's Law to find the resistance:

R = V / I
R = 240 volts / 48 amps

R = 5 ohms

So, the correct answer is:
a. 5 ohms

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Typical electrical wires in your house are generally made of copper (electron density of 8.47∗1024 electrons per cm3 ) and are usually either 14 gauge (diameter of 1.63 mm ), 12 gauge (diameter of 2.05 mm ), or 10gauge(2.59 mm) wires.
(A) If you have a 14 gauge wire that is carrying the maximum current of 20 , what would be the average drift speed of the electrons in the wire? Tries 1/8
(B) Usinq the averaqe speed you just calculated in Part (A), how much time would it take an electron to travel 8.84 m?

Answers

A. The average drift speed of the electrons in the wire is  1.19 x \(10^{-3}\)cm/s.

B. The time it would take an electron to travel 8.84 m is 7.43 x \(10^{5}\)sec

(A) To find the average drift speed of electrons in a wire, we can use the equation:

I = nAvq

Where:
I is the current in Amperes
n is the electron density in electrons per \(cm^{3}\)
A is the cross-sectional area of the wire in \(cm^{2}\)
v is the average drift velocity of electrons in cm/s
q is the charge of an electron, which is 1.6 x \(10^{-19}\) Coulombs

First, we need to find the cross-sectional area of the wire. The formula for the area of a circle is:

A = π\(r^{2}\)

Where:
A is the area of the circle
r is the radius of the circle

Given that the wire diameter is 1.63 mm, we can find the radius by dividing it by 2:

r = 1.63 mm / 2 = 0.815 mm = 0.0815 cm

Now, we can calculate the area:

A = \(π(0.0815 cm)^{2}\) = 0.0209 \(cm^{2}\)

Next, we can rearrange the equation to solve for v:

v = I / (nAq)

Given that the current is 20 A and the electron density is 8.47 x \(10^{24}\)electrons per \(cm^{3}\), we can substitute these values into the equation:

v = 20 A / (8.47 x \(10^{24}\) electrons per cm^3 * 0.0209 cm^2 * 1.6 x \(10^{-19}\) C)

Simplifying the expression:

v = 1.19 x \(10^{-3}\) cm/s

Therefore, the average drift speed of electrons in the 14 gauge wire carrying a maximum current of 20 A is approximately 1.19 x \(10^{-3}\) cm/s.

(B) To calculate the time it would take for an electron to travel a distance of 8.84 m, we can use the formula:

t = d / v

Where:
t is the time in seconds
d is the distance in meters
v is the average drift velocity of electrons in meters per second

Given that the distance is 8.84 m and the average drift velocity is 1.19 x 10^-3 cm/s, we need to convert the velocity to meters per second:

v = 1.19 x \(10^{-3}\) cm/s * 0.01 m/cm = 1.19 x \(10^{-5}\) m/s

Now, we can substitute the values into the formula:

t = 8.84 m / 1.19 x \(10^{-5}\)m/s

Simplifying the expression:

t = 7.43 x \(10^{5}\)s

Therefore, it would take approximately 7.43 x \(10^{5}\) seconds for an electron to travel a distance of 8.84 m.

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describe a cars velocity when it goes around a track at a constant speed

Answers

Answer:

A race car on an oval track has a constant speed. But, as the race car goes around the track, the direction in which the car is moving changes. This means that the velocity of the car is changing. An object has constant velocity if neither the speed nor direction it is moving changes.

a student pushed a 100 N bicycle over a distance of 15 m in 5 s. calculate the power generated.

Answers

The catch in this one is:  We don't know how much force the student used to push the bike.  

It wasn't necessarily the 100N.  That's just the weight of the bike. But you know that you can push a car, a wagon, or a bicycle hard, you can push it not so hard, you can give it a little push, you can give it a big push, you can push it strong, you can push it weak, you can push it medium.  The harder you push, the more it'll accelerate, but it's completely up to you how hard you want to push.  That's what's so great about wheels !  That's why they were such a great invention ! This is where I made my biggest mistake. This guy came into my store one day and said he's got this great invention, it's definitely going to take off, it'll be a winner for sure, he called it a "wheel".  I looked at it, I turned it over and I looked on all sides. I thought it was too simple.  I didn't know then it was elegant. I threw him out.  I was so dumb.  I could have invested money in that guy, today I would have probably more than a hundred dollars.

Anyway, can we figure out how much force the student used to push with ?  Stay tuned:

-- The bike covered 15 meters in 5 seconds.  Its average speed during the whole push was (15m/5s) = 3 meters/sec.

-- If the bike started out with no speed, and its average speed was 3 m/s, then it must have been moving at 6 m/s at the end of the push.

-- If its speed increased from zero to 6 m/s in 5 seconds, then its acceleration was (6m/s / 5 sec) = 1.2 m/s²

-- The bike's weight is 100N.  

(mass) x (gravity) = 100N

Bikemass = (100N) / (9.8 m/s²)

Bikemass = 10.2 kilograms

-- F = m A

Force = (mass) x (acceleration)

Force = (10.2 kg) x (1.2 m/s²)

Force = 12.24 N

-- Work = (force) x (distance)

Work = (12.24 N) x (15 m)

Work = 183.67 Joules

-- Power = (work done) / (time to do the work)

Power = (183.67 joules) / (5 seconds)

Power = 36.73 watts

An full shopping cart with a mass of 100. kg is moving at 5.0 m/s and runs into a stationary shopping cart that is empty (30. kg). After the collision, the full shopping cart is moving at 2.7 m/s. What is the empty shopping cart moving at?

Answers

The empty shopping cart is moving at 7.67 m/s.

What is law of conservation of momentum?

According to the law of momentum conservation, momentum is only modified by the action of forces as they are outlined by Newton's equations of motion; momentum is never created nor destroyed inside a problem domain.

Total initial momentum = total final momentum

100 kg ×5.0 m/s + 30 kg ×0 m/s = 100 kg ×2.7 m/s + 30 kg ×v

v = (5.0 - 2.7)(100/30) m/s

= 7.67 m/s.

Hence,  the empty shopping cart is moving at  speed of 7.67 m/s.

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Please help giving a lot of points- A rollercoaster cart that has a mass of 4500 kg has 67.5 kJ (kilojoules), or 67,500 J (joules), of gravitational potential

energy. What is its height above the ground?


PT.2


The same 4500 kg rollercoaster cart is moving with 63.0 kJ (kilojoules), or 63,000 J (joules), of kinetic energy at the


bottom of its biggest hill. What is its velocity?

Answers

Answer:

(a) h = 1.5 m (b) v = 5.29 m/s

Explanation:

1. Given that,

Mass of a rollercoaster cart, m = 4500 kg

It has 67,500 J of gravitational potential  energy.

We know that, the gravitational potential  energy is given by :

\(E=mgh\)

Put all the values,

\(h=\dfrac{E}{mg}\\\\h=\dfrac{67500}{4500\times 10}\\\\h=1.5\ m\)

2. The kinetic energy of an object is given by :

\(E=\dfrac{1}{2}mv^2\\\\v=\sqrt{\dfrac{2E}{m}}\\\\v=\sqrt{\dfrac{2\times 63000}{4500}}\\\\v=5.29\ m/s\)

Hence, this is the required solution.

When you put a 9. 0 V battery across a bulb, 0. 1 A of current

flows through the bulb. Calculate the resistance of the bulb

Answers

When a 9.0 V battery is connected to a bulb and 0.1 A of current flows through it, the resistance of the bulb is 90 ohms.

When a 9.0 V battery is connected to a bulb and 0.1 A of current flows through the bulb, we can calculate the resistance of the bulb using Ohm's Law. Ohm's Law states that the current flowing through a conductor is directly proportional to the voltage applied across it and inversely proportional to its resistance.

To find the resistance, we can rearrange Ohm's Law equation (V = IR) to solve for R, where V is the voltage, I is the current, and R is the resistance.

First, let's plug in the given values:

V = 9.0 V (voltage)
I = 0.1 A (current)

Now, we can rearrange the equation to solve for R:

R = V / I

Substituting the given values:

R = 9.0 V / 0.1 A

Dividing 9.0 V by 0.1 A, we get:

R = 90 ohms

Therefore, the resistance of the bulb is 90 ohms.

In summary, when a 9.0 V battery is connected to a bulb and 0.1 A of current flows through it, the resistance of the bulb is 90 ohms.

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In a population of ground beetles, a genetic locus that codes for setae on the elytra has two variants: G is dominant and codes for setae on the elytra, and g is recessive and codes for glabrous elytra (no setae). If the frequency of beetles with glabrous elytra is 0.36, what is the frequency of the G allele, assuming the population is in Hardy-Weinberg equilibrium? Show all your calculations. (5 pts) a. 0.6 b. 0.4 C. 0.64 d. 0.16 e. none of the above

Answers

The frequency of the G allele in the population is 0.4, the correct option is B. 0.4.

The frequency of beetles with glabrous elytra in a population of ground beetles is 0.36. The frequency of the G allele is to be calculated, assuming that the population is in Hardy-Weinberg equilibrium.

What is Hardy-Weinberg equilibrium? The Hardy-Weinberg equilibrium is a model that describes the genetic makeup of a non-evolving population.

This model postulates that the genetic variation in a population remains constant from generation to generation in the absence of disturbing influences such as mutation, migration, or natural selection.

According to the Hardy-Weinberg equilibrium, the frequency of alleles and genotypes remains constant if certain conditions are met.

The Hardy-Weinberg equilibrium is represented by the following equation:p2 + 2pq + q2 = 1 Where:p2 = frequency of homozygous individuals (GG)2pq = frequency of heterozygous individuals (Gg)q2 = frequency of homozygous recessive individuals (gg)p + q = 1Now let's move on to the calculation of the frequency of the G allele.

The frequency of individuals with the gg genotype can be obtained from the following equation:q2 = 0.36q2 = 0.36^(1/2)q = 0.6

The sum of the frequency of all genotypes must be equal to 1, which can be used to calculate the frequency of the G allele:p + q = 1p = 1 - qp = 1 - 0.6p = 0.4The frequency of the G allele in the population is 0.4.Therefore, the correct option is B. 0.4.

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What is the separation between the central brirght fringe and the third dark fringe?

Answers

The separation between the central bright fringe and the third dark fringe in a double-slit interference pattern is determined by the distance between the slits, the wavelength of light, and the distance between the screen and the slits. This separation can be calculated using the equation:

d*sin(theta) = (m + 0.5) * lambda

Where:
- d is the distance between the slits
- theta is the angle between the central bright fringe and the third dark fringe
- m is the order of the fringe (m = 0 for the central bright fringe, m = 1 for the first dark fringe, m = 2 for the second dark fringe, and so on)
- lambda is the wavelength of light

By rearranging the equation, you can solve for the separation between the central bright fringe and the third dark fringe. Keep in mind that this equation assumes that the slits are very close together compared to the distance between the slits and the screen.

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In an electric motor, how do the permanent magnets and the electromagnet interact?

Answers

Answer:

A coil of wire becomes an electromagnet when current passes through it. The electromagnet interacts with a permanent magnet, causing the coil to spin. Voilà!

Explanation:

A coil of wire becomes an electromagnet when current passes through it. The electromagnet interacts with a permanent magnet, causing the coil to spin. Voilà! and ig Magnetic torque: Permanent magnets generate a flux field in the rotor. The stator generates a field that interacts with the rotor's magnetic field. Changing the position of the stator field with respect to the rotor field causes the rotor to shift. The shift due to this interaction is the magnetic torque.

What is the origin behind the term " cell phone "

Answers

Answer:

Rae Young at Bell Labs. They diagrammed a network of wireless towers into what they called a cellular layout. Cellular was the chosen term because each tower and its coverage map looked like a biological cell. Eventually, phones that operated on this type of wireless network were called cellular phones.

Explanation:

....,..................,..,.......

Answers

I agree, or is this morse code…?
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