i need to find the missing angle using trig ratios for this problem

The Inequality which ensure triangle exists is A. 7/4 < x < 11/2

Inequality is defined as the relation between two quantities with the sign of inequality that is >, <, ≤ , ≥ ."

Inequalities are simply created through the connection of two expressions. In this case, it should be noted that the expressions in an inequality are not always equal.

Theorem used In ΔABC,

AB + BC >AC

AC+ BC >AB

AC + AB > BC

According to the question,

In triangle ABC.

AC = 18units

BC = 6x units,

AB = 2x + 4 units

Substitute the value in the inequality to ensure triangle exists we get 7/4 < x < 11/2. The correct option is A.

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Answer: 80

Step-by-step explanation:

Answer: The correct answer is 80

Step-by-step explanation:

in parentheses 3x4 = 12 - 4 = 8

6 + 4 = 10

10 x 8 = 80

1. Relation 1 is a function

2. Relation 2 is a function

3. Relation 3 is not a function

4. Relation 4 is a function

From the question, we have the following parameters that can be used in our computation:

The relations (1) to (4)

Relation (1)

This relation is a function

This is because each range value point to unique domain values

Relation (2)

This relation is a function

This is because each range value point to unique domain values

Relation (3)

This relation is not a function

This is because domain values w have different range values.

Relation (4)

This relation is a function

This is because each range value point to unique domain values

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Answer:

The car dealer must sell 105 cars in May to reach his goal.

Step-by-step explanation:

Given that the car dealer sold 84 cars in April, and wants to increase his May sales by 25%, to determine the number of cars he must sell to reach his goal it is necessary to perform the following calculation:

84 + (84 x 0.25) = X

84 + 21 = X

105 = X

Therefore, the car dealer must sell 105 cars in May to reach his goal.

The patient needs 17.66 mg of medication A .

It is given that a patient has weight 157 lbs.

We apply division because we need to find the cost of one item given the  cost of many items. If you need to find the cost of many items from the cost of one item,  apply the multiplication operation.

We need to convert this weight in kilogram using unitary method , we get      1 pound have = 0.45 kilogram

           157 pound will have \(=157\times0.45\)

                                              \(=70.65\) kilogram

A patient receive 0.25 mg of Medication A per kg

Using unitary method , we get

  1 kg of body receives = 0.25 mg of medication A

  70.65 kg of body receives \(=0.25\times 70.65\)

                                                \(=17.66\) mg of medication A

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Answer:

The sequence is step 7, 9, 1, 4, 2, 8

Step-by-step explanation:

They give us a series of steps to organize the operation of the inverse of the function y = (x-4) / (33-x)

they give us 9 steps, which 3 are incorrect since it is only done in 6 steps.

1. The first step is step # 7

It is the exchange of variables, it would be:

x = (y -4) / (33 - y)

2. The second step is step # 9

the denominator (33-y) is multiplied by x, like this:

x * (33 - y) = y -4

3. The third step is step # 1

Multiply the x by 33 - y, like this:

33 * x - x * y = y - 4

4. The fourth step is step # 4

We rearrange the equation:

33 * x + 4 = y + x * y

5. The fifth step is step # 2

We take common factor "and"

33 * x + 4 = y * (1 + x)

6. The sixth and last step is step # 8

We solve for "y", that is, we pass divide (1 + x) and it would be:

y = f ^ -1 (x) = 33 * x + 4 / (1 + x)

Here are the correct matches to the expressions to their solutions.

The GCF of 28 and 60 is 4.

(-3/8)+(-5/8) = -4/4 = -1.

-1/6 DIVIDED BY 1/2 = -1/6 X 2 = -1/3.

The solution of 0.5 x = -1 is x = -2.

The solution of 1/2 m = 0 is m = 0.

-4 + 5/3 = -11/3.

-2 1/3 - 4 2/3 = -10/3.

4 is not a solution of -4 < x.

1. The GCF of 28 and 60 is 4.

The greatest common factor (GCF) of two numbers is the largest number that is a factor of both numbers. To find the GCF of 28 and 60, we can factor each number completely:

28 = 2 x 2 x 7

60 = 2 x 2 x 3 x 5

The factors that are common to both numbers are 2 and 2. The GCF of 28 and 60 is 2 x 2 = 4.

2. (-3/8)+(-5/8) = -1.

To add two fractions, we need to have a common denominator. The common denominator of 8/8 and 5/8 is 8. So, (-3/8)+(-5/8) = (-3 + (-5))/8 = -8/8 = -1.

3. -1/6 DIVIDED BY 1/2 = -1/3.

To divide by a fraction, we can multiply by the reciprocal of the fraction. The reciprocal of 1/2 is 2/1. So, -1/6 DIVIDED BY 1/2 = -1/6 x 2/1 = -2/6 = -1/3.

4. The solution of 0.5 x = -1 is x = -2.

To solve an equation, we can isolate the variable on one side of the equation and then solve for the variable. In this case, we can isolate x by dividing both sides of the equation by 0.5. This gives us x = -1 / 0.5 = -2.

5. The solution of 1 m = 0 is m = 0.

To solve an equation, we can isolate the variable on one side of the equation and then solve for the variable. In this case, we can isolate m by dividing both sides of the equation by 1. This gives us m = 0 / 1 = 0.

6. -4 + 5/3 = -11/3.

To add a fraction and a whole number, we can convert the whole number to a fraction with the same denominator as the fraction. In this case, we can convert -4 to -4/3. So, -4 + 5/3 = -4/3 + 5/3 = -11/3.

7. -2 1/3 - 4 2/3 = -10/3.

To subtract two fractions, we need to have a common denominator. The common denominator of 1/3 and 2/3 is 3. So, -2 1/3 - 4 2/3 = (-2 + (-4))/3 = -6/3 = -10/3.

8. 4 is not a solution of -4 < x.

The inequality -4 < x means that x must be greater than -4. The number 4 is not greater than -4, so it is not a solution of the inequality.

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Answer:

0.9 grams

Step-by-step explanation:

The point estimate for the average weight of Soap Bar A is:

\(A=\frac{121+122+124+ 123+ 120+ 124+ 121+ 121+ 121+ 123+ 120}{11}\\A=121.82\ grams\)

The point estimate for the average weight of Soap Bar B is:

\(B=\frac{121+120+122+ 119+ 121+ 122+ 122+ 120+ 120 +121+ 122+123+119}{13}\\B=120.92\ grams\)

Therefore, the point estimate for the true difference between the given population means is:

\(Dif = A-B\\Dif = 121.82-120.92\\Dif=0.9\ grams\)

The point estimate for the difference is 0.9 grams.

Answer:

So if PT=TQ and TQ=7x-9

PT=5x+3=TQ=7x-9

5x+3=7x-9

minus 5x both sides

3=2x-9

add 9 both sides

12=2x

divide 2

6=x

PT=5x+3

PT=5(6)+3

PT=30+3

PT=33

PT=QT=33

x=6

with help from heliy02

Step-by-step explanation:

Answer: $1.50

Step-by-step explanation: 1. subtract the 3.25 from 4.50 to get a difference that is the price of the added hotdog 2. now that you know each hot dog cost $1.25 you can do 3.25 - 2(1.25) to get 0.75 which is the price of one soda. 3. You can no multiply $0.75 by two (the amount of sodas) to get the answer $1.50.

Answer:

Step-by-step explanation:

We first examine a simple hidden Markov model (HMM). We observe a sequence of rolls of a four-sided die at an "occasionally dishonest casino", where at time t the observed outcome x_t Element {1, 2, 3, 4}. At each of these times, the casino can be in one of two states z_t Element {1, 2}. When z_t = 1 the casino uses a fair die, while when z_t = 2 the die is biased so that rolling a 1 is more likely. In particular: p (x_t = 1 | z_t = 1) = p (x_t = 2 | z_t = 1) = p (x_t = 3 | z_t = 2) = p (x_t = 4 | z_t = 1) = 0.25, p (X_t = 1 | z_t = 2) = 0.7, p (X_t = 2 | z_t = 2) = p (X_t = 3 | z_t = 2) = p (X_t = 4 | z_t = 2) = 0.1. Assume that the casino has an equal probability of starting in either state at time t = 1, so that p (z1 = 1) = p (z1 = 2) = 0.5. The casino usually uses the same die for multiple iterations, but occasionally switches states according to the following probabilities: p (z_t + 1 = 1 | z_t = 1) = 0.8, p (z_t = 2) = 0.9. The other transition probabilities you will need are the complements of these. a. Under the HMM generative model, what is p (z1 = z2 = z3), the probability that the same die is used for the first three rolls? b. Suppose that we observe the first two rolls. What is p (z1 = 1 | x1 = 2, x2 = 4), the probability that the casino used the fair die in the first roll? c. Using the backward algorithm, compute the probability that we observe the sequence x1 = 2, x2 = 3, x3 = 3, x4 = 3 and x5 = 1. Show your work (i.e., show each of your belief for based on time). Consider the final distribution at time t = 6 for both p (z_t = 1) = p (z_t = 2) = 1.

ANSWER:

Let say we have that the first state of the die is state 1. Therefore the probability of this is p(z1=1)=0.5.

Also the probability that the same die is used(i.e. casino would be in the same state) is p(z2=1|z1=1)=0.8.

Again, suppose the first state of the die is state 2. So, p(z1=2)=0.5 and p(z2=2|z1=2)=0.9.

Other transition probabilities can be written as

p(zt+1=2|zt=1)=1-p(zt+1=1|zt=1)=.2

p(zt+1=1|zt=2)=1-p(zt+1=2|zt=2)=.1

p(z3=1|z1=1) = [p(z3=1|z2=2)*p(z2=2|z1=1)]+[p(z3=1|z2=1)*p(z2=1|z1=1)] = 0.1*0.2+0.8*0.8 = 0.66

p(z3=2|z1=2) = [p(z3=2|z2=2)*p(z2=2|z1=2)]+[p(z3=2|z2=1)*p(z2=1|z1=2)] = 0.9*0.9+0.2*0.1 = 0.83

With this, the total probability that the same die is used for the first three rolls (i.e. casino would be in the same state) is  given thus;

{p(z1=1)*p(z3=1|z1=1)}*{p(z1=2)*p(z3=2|z1=2)}

=  0.5*0.66+0.5*0.83 = 0.745

Prob = 0.745

Solution:

Let's simplify each inequality one by one.

This means that...

Hoped this helped!

Largest fraction 5/12 and 3/8, 2/5 and 19/45, 5/7, 13/14and 19/21

1) Between 5/12 and 3/8

Lets multiply both the 5/12 with 8/8 and 3/8 with 12/12

Therefore , new equations are  

5/12 x 8/8 = 40/ 96

3/8 x 12/12 = 36/96

So, 5/12 is larger fraction.

2) Between 19/45, 5/7

Lets multiply both the 19/45 with 7/7 and 5/7 with 45/45

Therefore , new equations are  

19/45 x 7/7 = 133/ 315

5/7 x 45/45 = 225/315

So, 5/7 is larger fraction.

3) Between 13/14and 19/21

Lets multiply both the 13/14 with 3/3 and 19/21 with 2/2

Therefore , new equations are  

13/14 x 3/3 = 39/42

19/21 x 2/2 = 38/42

So, 13/14 is larger fraction.

In arithmetic, a number expressed as a quotient, in which a numerator is divided via a denominator. In a easy fraction, both are integers. A complex fraction has a fraction inside the numerator or denominator. In a right fraction, the numerator is much less than the denominator

In arithmetic, a fraction described because the a part of the whole thing. as an instance, a pizza is divided into four identical pieces, then each piece is represented by means of ¼. Fractions help to distribute and choose the numbers easily and make the calculation faster.

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Answer:

Y = -½x + 3/2

Y = -3x + 5

Y = 1/4x - 3¼

Step-by-step explanation:

Parallel implies they have the same gradient

Perpendicular implies the gradient is a negative reciprocal of the other.

The histogram shows that petal length is distributed in a slightly skewed unimodal shape, while the boxplot reveals that the median value is 3.0 and there are some outliers with values greater than 6.0.

The histogram of Petal. Length shows that the data is distributed in a slightly skewed unimodal shape, with most of the data concentrated in the lower range of petal length values. This indicates that the majority of observations have petal lengths of less than 4.0 cm. The bin-width used was 0.5 and the data was distributed into 9 bins.

The boxplot of Petal. Length reveals more information about the distribution of the data. The median value is 3.0, the interquartile range is from 2.0 - 5.1, and there are some outliers with values greater than 6.0. This indicates that while the majority of observations have petal lengths between 2.0 and 5.1 cm, there are a few observations with petal lengths greater than 6.0 cm. This boxplot also shows that the data is slightly skewed to the right, as the median is less than the mean, which is 3.76 cm.

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Answer:

9

Step-by-step explanation:

You don't need to pass through each edge once.

If we name the top vertex 1 and the bottom vertex 2 then here are the possible combinations:

A-1-B

A-B

A-2-B

A-1-B-A-2-B

A-2-B-A-1-B

A-B-1-A-2-B

A-B-2-A-1-B

A-1-B-2-A-B

A-2-B-1-A-B

Some people say 6 because they think you need to pass through all the edges. But the only restriction with travelling on the edges is you can't pass one twice. The point is read the wording and it becomes easy.

Hope this helps!

Answer:

A,B, D

Step-by-step explanation: I just took that test and i got it right

The sum of the functions is option B. (f + g)(x) = 2x³ + 3x² - 5x - 3.

A function is defined as a relation from a set to another set  such that the elements in the first set maps to one and only one element in the second set.

Or in other words, no elements in the first set has more than one image in the second set.

Given the two functions,

f(x) = 2x³ + 3x² - 7x + 2 and g(x) = 2x - 5.

We have to find (f + g) (x).

Sum of the functions is,

(f + g)(x) = f(x) + g(x)

             = (2x³ + 3x² - 7x + 2) + (2x - 5)

             = 2x³ + 3x² - 7x + 2x + 2 - 5

             = 2x³ + 3x² - 5x - 3

Hence the sum of the given function is 2x³ + 3x² - 5x - 3.

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Answer: 2/90 = 1/45

Step-by-step explanation:

1) The three main trigonometric ratios of the given triangle are:

sin B = 5/9.43

cos B = 8/9.43

tan B = 5/8

2) The measure of angle A is: ∠A = 39.6°

3) The length of side x is: x = 39.5 mm

The six trigonometric ratios of a right angle triangle are:

sin x = opposite/hypotenuse

cos x = adjacent/hypotenuse

tan x = opposite/adjacent

cot x = 1/tan x

sec x = 1/cos x

cosec x = 1/sin x

1) The three main trigonometric ratios of the given triangle are:

sin B = 5/9.43

cos B = 8/9.43

tan B = 5/8

2) The measure of angle A is gotten from:

∠A = cos⁻¹ (47/61)

∠A = 39.6°

3) The length of side x using trigonometric ratios is:

21/x = tan 28

x = 21/tan 28

x = 39.5 mm

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Given that , \( x +\dfrac{1}{x}=\sqrt{11}\)

And we are interested in finding out the value of \( x^3+\dfrac{1}{x^3}\)

Taking the given equation,

\(\longrightarrow x +\dfrac{1}{x}=\sqrt{11} \)

cube both the sides ,

\(\longrightarrow \left( x +\dfrac{1}{x}\right)^3=(\sqrt{11})^3\\ \)

simplify using identity,

\(\longrightarrow x^3+\dfrac{1}{x^3}+3(x)\bigg(\dfrac{1}{x}\bigg)\bigg( x +\dfrac{1}{x}\bigg)=11\sqrt{11}\\ \)

\(\longrightarrow x^3+\dfrac{1}{x^3}+3\sqrt{11}= 11\sqrt{11}\\ \)

\(\longrightarrow x^3+\dfrac{1}{x^3}=11\sqrt{11}-3\sqrt{11}\\ \)

\(\longrightarrow \boxed{x^3+\dfrac{1}{x^3}= 8\sqrt{11} }\)

And we are done!

The simplified algebraic expression is given as follows:

\(5\frac{(-1 + \sqrt{3})}{3}\)

The algebraic expression in the context of this problem is defined as follows:

\(\frac{-5 + 5\sqrt{3}}{3}\)

To simplify, we must obtain the common factor of the numerator, which is of 5, as both terms are divisible by 5, as follows:

Hence the simplified algebraic expression is given as follows:

\(5\frac{(-1 + \sqrt{3})}{3}\)

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Answer:

what?-

Step-by-step explanation:

graph? pls.---

Answer:

Where is the graph could you please give it to us!!!

Step-by-step explanation:

Answer:

2 vertical asymptotes occurring at x = 5 and x = -1

Step-by-step explanation:

given

\(f(x) = \frac{14}{(x-5)(x+1)}\)

recall that asymptotic occur at the locations that will make the equation undefined. In this case, the asymptote will occur at x-locations which will cause the denominator to become zero (and hence undefined)

Equating the denominator to zero,

(x-5)(x+1) = 0

(x-5) =0

x = 5 (first asymptote)

or (x+1) = 0

x = -1  (2nd asymptote)

We want to find the asymptotes of the given function.

There are two vertical asymptotes, one at x =5 and the other at x = -1.

First, we can briefly describe what an asymptote is.

An asymptote is a tendency to a given value that never reaches the actual value.

For example, we have vertical asymptotes (that tend to infinity or negative infinity) when we have a quotient with a denominator equal to zero.

Then, for our function:

\(f(x) = \frac{14}{(x-5)*(x +1)}\)

We need to find the values of x such that the denominator becomes zero.

Is ratter easy to see that if x = 5, or x = -1, the denominator becomes equal to zero, then we will have two vertical asymptotes, one at x = 5 and other at x = -1.

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Answer:

The relative risk of being a college graduate for Boone County residents as compared to Cooper County residents is 3.11.

Step-by-step explanation:

Denote the events as follows:

C = Cooper County resident

B = Boone County resident

G = graduate

NG = non-graduate

The information provided is summarized as follows:

               G       NG     Total

     C       18       82       100

     B       28      22        50

Total       46      104      150

Compute the relative risk of being a college graduate for Boone County residents as compared to Cooper County residents as follows:

\(\text{Relative Risk}=\frac{\text{Graduates in Boone County}}{\text{Graduates in Cooper County}}\)

                      \(=\frac{28/50}{18/100}\\\\=\frac{28}{50}\times \frac{100}{18}\\\\=3.11111\\\\\approx 3.11\)

Thus, the relative risk of being a college graduate for Boone County residents as compared to Cooper County residents is 3.11.

The relative risk of remaining a college graduate for Boon County residents in comparison to Cooper County residents would be 0.500

Relative risk is used in the statistical analysis of the data of ecological, cohort, medical, and intervention studies, to estimate the strength of the association between exposures (treatments or risk factors) and outcomes. Mathematically, it is the incidence rate of the outcome in the exposed group.

The relative risk is calculated by dividing the probability of an event for group 1 divided by the probability of an event occurring for group 2.

The probability of the Boone country resided is a college graduate,

By the formula of classical probability \(P(A)=\frac{m}{n}\) then,

\(\frac{18}{100}=0.18\)

The probability of cooper country resided is a college graduate is,\(\frac{18}{50}=0.36\)

The relative risk is being a college graduate Boone country resided as compared to cooper country resident is,

\(\frac{0.18}{0.36} =0.500\)

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