I have a statistic that is normally distributed with a very large sample size. I add a single subject that is way above the median to the sample. What is likely to happen?

Answer:  reflection across the x-axis

               vertical shrink by a factor of 1/2

               horizontal shrink by a factor of 1/3

               vertical shift up 4 units      

Step-by-step explanation:

\(\text{Note:}\ g(x) = -Ae^{Bx-C}+D\\\bullet \quad \text{- represents a reflection across the x-axis}\\\\\bullet \quad \text{A represent a vertical stretch by a factor of A (shrink if}\ |A| < 1)\\\\\bullet \quad \text{B represents a horizontal stretch by a factor of}\ \dfrac{1}{B}\ (\text{shrink if}\ |B| >1) \\\\\bullet \quad \text{C represents a horizontal shift of C units}\ (\text{+ is right, - is left}) \\\\\bullet \quad \text{D represents a vertical shift of D units}\ (\text{+ is up, - is down})\)

\(\text{Parent function:}\ f(x)=e^x\\\text{Transformed function:}\ g(x)=-\dfrac{1}{2}e^{3x}+4\\\)

The transformed function has the following:

Negative:    reflection across the x-axis

A = 1/2         vertical shrink by a factor of 1/2

B = 3            horizontal shrink by a factor of 1/3

C = 0            no horizontal shift

D = 4            vertical shift of 4 units up

Answer:

2 2/3 is your answer

Step-by-step explanation:

You want to flip the fractions and divide

Hello! Your answer is 2 2/3

Answer:

p=3

Step-by-step explanation:

5 +5 =10 p÷3(4+6) =py

=p3

Answer:

$31.00 x10 equals 310 13.95 * 10 =$139.50. 360 * 16 $57

Answer:

\(A=3r^2\)

Step-by-step explanation:

isolate A to one side

r=√A/3

square both sides

r^2=A/3

x3   x3

3r^2=A

hopes this helps

Answer:

c

Step-by-step explanation:

in order for it to be a triangle the smaller sides have to add up to be greater than the longest side

for a 5+14=19 so that is not a triangle because the  side dont add up to be greater than 19

for b 14+8=22 so that is also not a triangle because the sides dont add up to be greater than 24

for c 5+15=20 so that is a triangle because to 2 shorter sides added are greater than the longest side

for d 14+9=23 so that is not a triangle because the two smaller sides dont add up to be greater than 24

An election system in which each state is divided into geographical regions (districts) and each district is represented by a single representative who wins by receiving the most votes even if it is not a majority is known as First-past-the-post (FPTP).

First-past-the-post (FPTP) is also known as simple majority system. Through this method of voting, the candidate with the most votes in the constituency is declared the winner of the election. This system is used in India in direct elections of Lok Sabha and State Assemblies. While FPTP is simple, it does not always allow for true representation, as a candidate can win despite getting less than half of the votes in a contest. In 2014, the National Democratic Alliance led by the Bharatiya Janata Party won 336 seats with 38.5% of the votes cast. Also, smaller parties that represent specific groups have less voting opportunities in the FPTP.

On election day, voters receive a ballot with a list of candidates. Since only one member of parliament will represent the region, each party has only one candidate to choose.

Voters put a cross next to their favorite candidate. But if they think their favorite has a low chance of winning, they can place a cross next to the one they like with the best chance of winning.

Being one candidate from each party, voters who support that party but do not like their candidate, either vote for the party they do not support or the candidate they do not like.

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The partial derivatives ∂N/∂u, ∂N/∂v, and ∂N/∂w when u=9, v=4, and w=3 are:

\(∂N/∂u = 96\)

\(∂N/∂v = 19\)

\(∂N/∂w = 35\)

To find the indicated partial derivatives, we can use the chain rule of differentiation. Starting with ∂N/∂u, we have:

\(∂N/∂u = (∂N/∂p) \times (∂p/∂u) + (∂N/∂q) \times (∂q/∂u) + (∂N/∂r) \times (∂r/∂u)\)

Substituting the given values for p, q, and r, we get:

\(∂N/∂u = (1 + q) \times 1 + (p + r) \times w + u \times w\)

Using the values of p, q, and r in terms of u, v, and w, we get:

\(∂N/∂u = (1 + v + uw) + (u + vw + w + uv) \times 3 + 9 \times 3\)

Simplifying the expression, we get:

\(∂N/∂u = 60 + 4u + 3v + 12w\)

We can find ∂N/∂v and ∂N/∂w by applying the chain rule of differentiation and using the given values for u, v, and w. Substituting the values, we get:

\(∂N/∂v = 3u + 4 + 3w\)

\(∂N/∂w = 3u + 3v + 2\)

The chain rule allows us to find the partial derivatives of a function with respect to its variables, by breaking down the function into its component parts and differentiating each part separately.

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The expression sqrt(64) - sqrt(-289) simplifies to 8 - 17i and can be represented in the form of a + bi, where a = 8 and b = -17.

To simplify the expression sqrt(64) - sqrt(-289), we need to evaluate the square roots and express the result in the form of a + bi, where a and b are real numbers.

First, let's evaluate the square roots:

sqrt(64) is equal to 8, as the square root of 64 is 8.

sqrt(-289) represents the square root of a negative number, which is not a real number. However, we can express it in terms of the imaginary unit i. The square root of -1 is defined as i, so we can rewrite sqrt(-289) as 17i, since 17 multiplied by itself equals 289.

Now, substituting the values back into the expression, we have:

sqrt(64) - sqrt(-289) = 8 - 17i

Therefore, the expression sqrt(64) - sqrt(-289) simplifies to 8 - 17i and can be represented in the form of a + bi, where a = 8 and b = -17.

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The area of the shaded region is 15 \(yd^2\).

The region that an object's shape defines as its area. The area of a figure or any other two-dimensional geometric shape in a plane is how much space it occupies.

Here in the given diagram contains right triangle and rectangle.

We need to find both triangle and rectangle  area in order to find area of shaded region.

Now Base= 3+4 = 7 yd , Height h =6 yd. Then,

Area of triangle A = \(\frac{1}{2}bh\) square unit

=> A = \(\frac{1}{2}\times7\times6\)

=> A = \(7\times3 = 21 yd^2\)

Now breadth b = 3 yd , Width w=2 yd, Then

Area of rectangle = bw square unit.

=> A = 3×2 = 6 \(yd^2\)

Now area of the shaded region = Area of triangle - Area of rectangle

=> Area of shaded region = 21-6 = 15 \(yd^2\).

Hence the area of the shaded region is 15 \(yd^2\).

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The remainder would be 12 as per the remainder theorem if the function P is defined by P(x) = x³ +7x² - 26x - 72.

A polynomial is defined as a mathematical expression that has a minimum of two terms containing variables or numbers. A polynomial can have more than one term.

Let   P(x) = x³ +7x² - 26x - 72  ...(i)

Divisor = (x+9)

Apply remainder theorem,

x + 9 = 0

x = -9

Substitute the value of x = -9 in equation (i),

⇒ P(-9) = (-9)³ +7(-9)² - 26(-9) - 72

⇒ P(-9) = (-729) +7(81) - 234 - 72

⇒ P(-9) = -729 + 567 - 234 - 72

⇒ P(-9) = -468

Therefore, the remainder would be -468.

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Answer:

x=6

Step-by-step explanation:

5*x+6=36

so 5*6=30

+6=36

Answer:

36

Step-by-step explanation:

Answer:

109.9

Step-by-step explanation:

Hope this helps!

Answer:

109.9

Step-by-step explanation:

Formula: (Pi) 3.14x35 = 109.9

Answer:

2.35

Step-by-step explanation:

Answer:

hello!

The answer is 2.35.

This always helped me. Lets ignore the whole numbers until the very end so we end up with 3/5-1/3.

With adding and subtracting, you have to have the same denominator so what can we multiply to each denominator to make them the same. Usually you want the lowest number so you have less simplifying at the end.

What we can do is 5*3 and 3*5. whatever you multiply the bottom with you have to multiply the top with, so 3*3 and 3*5 for the first one and it would come out as 9/15 and for the second one it would be 1*5 and 3*5 and it would come out as 5/15.

Your equation now is 9/15-5/15. For addition and subtraction you keep the denominator the same so you would only do 9-5=4

So your equation now is 4/15. Now go on to your whole numbers basically you just do 4-2=2

If you add those two solutions together you get 2 4/15

Answer: Perimeter of given square:40,Area of given square:100

Perimeter of Dilated square:200

Area of Dilated square: 2500

Step-by-step explanation:

Answer:

\(\frac{1}{3}\)

Step-by-step explanation:

Given

- \(\frac{1}{4}\) × - \(\frac{4}{3}\) ( negative times negative = positive )

= \(\frac{1}{4}\) × \(\frac{4}{3}\) ( cancel the 4 on the numerator and denominator )

= \(\frac{1}{3}\)

Answer:

Step-by-step explanation:

The formula for the area of a sector is

\(A=\frac{\theta}{360}*\pi r^2\) where θ is the measure of the central angle and r is the radius.

Our central angle is a right angle and the radius is 4, so filling in the formula looks like this:

\(A=\frac{90}{360}*\pi (4)^2\) and

\(A=\frac{1}{4}*\pi (16)\)

16 divides by 4 evenly, so

A = 4π.in²

If we multiply 4 by the value of π and then round, that number, to the nearest hundredth, is

A = 12.57 in²

Answer: −

3

X

−

x

−

4

Step-by-step explanation:

Answer:

x=8

Step-by-step explanation:

Make sure variables are on one side of the equation and numbers are on the other

-3x+7x=-20-12

-4x=-32

4x=32

x=8

Please mark Brainliest! I will appreciate it! :)

Step-by-step explanation:

X/11+2=4

X+22/11=4 ( LCM of this denominators is 11)..

X+22=4×11

X+22=44

X=44-22

X=22 ANSWER

To determine how much a player can expect to gain or lose on average in the long run when playing this game, we need to calculate the expected value.

Let's consider the possible outcomes and their corresponding probabilities:

Sum = 6: There are five ways to obtain a sum of 6 (1+5, 2+4, 3+3, 4+2, 5+1), and the probability of rolling a sum of 6 is 5/36.

Sum = 8: There are five ways to obtain a sum of 8 (2+6, 3+5, 4+4, 5+3, 6+2), and the probability of rolling a sum of 8 is 5/36.

Any other sum: There are 36 possible outcomes in total, and we have already accounted for 10 of them. Therefore, the remaining outcomes that do not result in a sum of 6 or 8 are 36 - 10 = 26. The probability of rolling any other sum is 26/36.

Now, let's consider the outcomes in terms of gaining or losing money:

If the player wins, they gain n dollars.

If the player loses, they lose n dollars.

The game costs $1 to play.

With this information, we can calculate the expected value (EV) as follows:

EV = (Probability of winning * Amount gained) + (Probability of losing * Amount lost) - Cost to play

EV = [(5/36 * n) + (5/36 * n) - $1] + [(26/36 * -n) - $1]

Simplifying further:

EV = (10/36 * n - $1) + (26/36 * -n - $1)

EV = (10n/36 - $1) + (-26n/36 - $1)

EV = (10n - 36)/36 - $2

Simplifying and expressing the expected value in terms of dollars:

EV = (10n - 36)/36 - $2

Therefore, the player can expect to lose $2 for each game played, regardless of the value of n. This means that, on average, the player will lose $2 in the long run for each game they play.

Since the expected value is negative (-$2), this game is not mathematically fair. A mathematically fair game would have an expected value of zero, indicating that the player neither gains nor loses money on average. In this case, the player can expect to lose $2 on average, making it an unfavorable game for the player.

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The correct Numerical expression for "9 times 4 added to the difference of 3 and 2" is 37.

The correct numerical expression for "9 times 4 added to the difference of 3 and 2" is:

9 x 4 + (3 − 2)

To solve this expression, we need to follow the order of operations, also known as PEMDAS (Parentheses, Exponents, Multiplication and Division from left to right, Addition and Subtraction from left to right).

Step 1: Evaluate the subtraction inside the parentheses:

3 − 2 = 1

Step 2: Rewrite the expression with the simplified value:

9 x 4 + 1

Step 3: Perform the multiplication:

9 x 4 = 36

Step 4: Add the products:

36 + 1 = 37

Therefore, the correct numerical expression for "9 times 4 added to the difference of 3 and 2" is 37.

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There are 15,504 ways to randomly select a team of 5 people from a group of 20 people

If there are 20 people trying out for a team, the number of ways to select a team of n people can be calculated using the formula for combinations, which is:

C(20, n) = 20! / (n! * (20 - n)!)

where C(20, n) represents the number of ways to select n people from a group of 20 people.

For example, if we want to select a team of 5 people, we can plug in n = 5 and calculate:

C(20, 5) = 20! / (5! * (20 - 5)!) = 15,504

Therefore, there are 15,504 ways to randomly select a team of 5 people from a group of 20 people. Similarly, we can calculate the number of ways to select teams of different sizes by plugging different values of n into the formula for combinations.

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Given data:

The given principal is P=$20,000.

The given rate of interest is r=6%.

The given time is t=20 years.

The expression for the interest is,

Substitute the given values in the above expression.

Thus, the interest earned after 20 years is $44,142.71, so (C) option is correct.

To find the average value of the function f(x, y) = 8x + 5y over the given triangle, we need to calculate the double integral of f(x, y) over the region and then divide it by the area of the triangle.

The vertices of the triangle are (0, 0), (2, 0), and (0, 7). We can set up the integral as follows:

∬R f(x, y) dA = ∫₀² ∫₀ᵧ (8x + 5y) dy dx

Integrating with respect to y first, the inner integral becomes:

∫₀ᵧ (8x + 5y) dy = 8xy + (5y²/2) |₀ᵧ = 8xᵧ + (5ᵧ²/2)

Now integrating with respect to x, the outer integral becomes:

∫₀² (8xᵧ + (5ᵧ²/2)) dx = (4x²ᵧ + (5ᵧ²x)/2) |₀² = (8ᵧ + 10ᵧ² + 20ᵧ)

To find the area of the triangle, we can use the formula for the area of a triangle: A = (1/2) * base * height.

The base of the triangle is 2 and the height is 7.

A = (1/2) * 2 * 7 = 7

Finally, to find the average value, we divide the double integral by the area of the triangle:

Average value = (8ᵧ + 10ᵧ² + 20ᵧ) / 7

Simplifying this expression gives:

Average value = (8 + 10ᵧ + 20ᵧ) / 7 = (8 + 10(7) + 20(7)) / 7 = 142/7 = 20 2/7

Therefore, the correct answer is not listed among the options provided.

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Answer:

\({ \tt{ \frac{ {x}^{8} {y}^{6} }{ {x}^{2} {y}^{3} } }} \\ \\ = { \tt{ {x}^{(8 - 2)} {y}^{(6 - 3)} }} \\ \\ = { \underline{ \tt{ \: {x}^{6} {y}^{3} \: }}}\)