Answer:
Last option i.e M= Fr²/Gm
Help .What is the measure of angle A?
Answer:
58
Step-by-step explanation:
What is the degree of the polynomial below?
x ^6 +3 - 2x^2 + 4x^7 - 4x
O A. 7
O B. 6
C. 5
D. 4
abstract algebra
(2) Suppose that |G| = pqr where p, q, r are distinct prime numbers. Show that G is not a simple group. Give an example of a simple group of order pqr where p, q, r are distinct prime numbers.
It can be shown that PSL(2,7) has order 168, which is equal to 2^3 * 3 * 7. Since 7 is a prime and 2 and 3 are coprime to 7, it follows that PSL(2,7) is a simple group of order 168.
By Sylow's theorems, we know that there exist Sylow p-subgroup, Sylow q-subgroup, and Sylow r-subgroup in G. Let P, Q, and R be the respective Sylow p, q, and r-subgroups. Then by the Sylow's theorems, we have:
|P| = p^a for some positive integer a and p^a divides qr
|Q| = q^b for some positive integer b and q^b divides pr
|R| = r^c for some positive integer c and r^c divides pq
Since p, q, and r are distinct primes, it follows that p, q, and r are pairwise coprime. Therefore, we have:
p^a divides qr
q^b divides pr
r^c divides pq
Since p, q, and r are primes, it follows that p^a, q^b, and r^c are all prime powers. Therefore, we have:
p^a = q^b = r^c = 1 (mod pqr)
By the Chinese remainder theorem, it follows that there exists an element g in G such that:
g = 1 (mod P)
g = 1 (mod Q)
g = 1 (mod R)
By Lagrange's theorem, we have |P| = p^a divides |G| = pqr. Similarly, we have |Q| = q^b divides |G| and |R| = r^c divides |G|. Therefore, we have:
|P|, |Q|, |R| divide |G| and |P|, |Q|, |R| < |G|
Since |G| = pqr, it follows that |P|, |Q|, |R| are all equal to p, q, or r. Without loss of generality, assume that |P| = p. Then |G : P| = |G|/|P| = qr. Since qr is not a prime, it follows that there exists a nontrivial normal subgroup of G by the corollary of Lagrange's theorem. Therefore, G is not a simple group.
An example of a simple group of order pqr where p, q, and r are distinct primes is the projective special linear group PSL(2,7). It can be shown that PSL(2,7) has order 168, which is equal to 2^3 * 3 * 7. Since 7 is a prime and 2 and 3 are coprime to 7, it follows that PSL(2,7) is a simple group of order 168.
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what is an equation of the line shown on the graph in the point-slope form, using the point(1,-1)
My sister has three Maltese puppies. Scout weighs pounds, Kenadi weighs pounds, and Major weighs pounds. What is the order of the puppy’s weights from greatest to least?
Answer:
i dont think thats right its d
Step-by-step explanation:
PLZ ANSWER ASAP DUE IN A FEW MINS
Answer:
Solution given:
diameter=14cm
radius [r]=14/2=7cm
now
area of semi circle or shaded region: ½πr²=½(3.14*7²)=76.93cm²[approximately]
Find the value of z.
someone please help me
9514 1404 393
Answer:
C. f(x) = 2(3^x)
Step-by-step explanation:
The y-intercept is the function value when x=0. Your choices are ...
A. f(0) = 1 +2 = 3
B. f(0) = 3(1) = 3
C. f(0) = 2(1) = 2 . . . . . the function of interest
D. f(0) = 2(1) -2 = 0
4-3
Write a program that prompts the user to input an integer between 0 and 35. The prompt should say Enter an integer between 0 and 35:.
If the number is less than or equal to 9, the program should output the number; otherwise, it should output:
A for 10
B for 11
C for 12
. . .
and Z for 35.
(Hint: For numbers >= 10, calculate the ACSII value for the corresponding letter and convert it to a char using the cast operator, static_cast().)
Here's a sample program in C++ that satisfies your requirements:
```
#include
using namespace std;
int main() {
int num;
cout << "Enter an integer between 0 and 35: ";
cin >> num;
if (num <= 9) {
cout << num << endl;
} else if (num >= 10 && num <= 35) {
char letter = static_cast('A' + num - 10);
cout << letter << endl;
} else {
cout << "Invalid input." << endl;
}
return 0;
}
```
- The program prompts the user to input an integer between 0 and 35 using the `cout` and `cin` statements.
- The `if` statement checks whether the number is less than or equal to 9. If it is, it outputs the number using the `cout` statement.
- The `else if` statement checks whether the number is between 10 and 35 (inclusive). If it is, it calculates the corresponding letter using the ASCII value for 'A' and the given number. The `static_cast` statement converts the calculated value to a character. Finally, the program outputs the letter using the `cout` statement.
- The `else` statement handles the case when the input is outside the range of 0 to 35. It outputs an error message using the `cout` statement.
- The program ends with the `return 0` statement.
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A continuous random variable X has probability density function f(x) = c(1+x)(1 - 2 over the domain -1<<1. (a) i. Evaluate the constant e (the integration can be done by MATLAB). ii. Plot the probability density function over the domain (-1,1). Is this density function skewed to the right, skewed to the left, or symmetric? (b) Use MATLAB to evaluate I i. the mean y = E(X)= |- «f(x) dx; ii. E(X)= (- 22 f(x) dx; iii. the variance o2 = Var(X) = E(X) – H?, and the standard deviation o. *(c) i. Use MATLAB to find an expression for the cumulative distribution function F(x). ii. Check the result in (i) by differentiation. Hint: simplify (ans) might help! iii. Evaluate P(-0.2 X <0.2).
(a)i. Evaluating the constant:
\($$\int_{-1}^{1} c(1+x)(1-2x) dx = 1$$$$\implies c = \frac{3}{4}$$\)
Therefore, the probability density function is:
\($$f(x) = \frac{3}{4} (1+x)(1-2x), -1< x < 1$$\) ii. Plotting the probability density function:
From the graph, it is observed that the density function is skewed to the left.
(b)i. The mean:
\($$E(X) = \int_{-1}^{1} x f(x) dx$$$$E(X) = \int_{-1}^{1} x \frac{3}{4} (1+x)(1-2x) dx$$$$E(X) = 0$$\)
ii. The second moment about the origin:
\($$E(X^2) = \int_{-1}^{1} x^2 f(x) dx$$$$E(X^2) = \int_{-1}^{1} x^2 \frac{3}{4} (1+x)(1-2x) dx$$$$E(X^2) = \frac{1}{5}$$\)
Therefore, the variance is:
\($$\sigma^2 = E(X^2) - E(X)^2$$$$\implies \sigma^2 = \frac{1}{5}$$\)
iii. The standard deviation:
$$\sigma = \sqrt{\sigma^2} = \sqrt{\frac{1}{5}} = \frac{\sqrt{5}}{5}$$(c)
i. The cumulative distribution function:
\($$F(x) = \int_{-1}^{x} f(t) dt$$$$F(x) = \int_{-1}^{x} \frac{3}{4} (1+t)(1-2t) dt$$\)
ii. The probability density function can be obtained by differentiating the cumulative distribution function:
\($$f(x) = F'(x) = \frac{3}{4} (1+x)(1-2x)$$\)
iii. Evaluating\(P(-0.2 < X <0.2):$$P(-0.2 < X <0.2) = F(0.2) - F(-0.2)$$$$P(-0.2 < X <0.2) = \int_{-0.2}^{0.2} f(x) dx$$$$P(-0.2 < X <0.2) = \int_{-0.2}^{0.2} \frac{3}{4} (1+x)(1-2x) dx$$$$P(-0.2 < X <0.2) = 0.0576$$\)
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I’m just confused and don’t know how to solve this
MK = 22 units
1) Examining that triangle, we can notice that the line segment EF divides into two halves the legs LM and LK.
2) And since LF ≅ FM and LE ≅ EK then we can state that FE is the Midsegment of that triangle. Therefore we can write out the following ratio:
\(\begin{gathered} M=\frac{1}{2}\cdot b \\ 35+2x=\frac{1}{2}\cdot(x+34) \\ 35+2x=\frac{x}{2}+17 \\ 2x=\frac{1}{2}x-18 \\ \frac{3}{2}x=-18 \\ 3x=-36 \\ x=-12 \end{gathered}\)Now that we have the quantity of x, let's plug it into the length of MK, given by the formula x+34
\(\begin{gathered} MK=x+34 \\ MK=-12+34 \\ MK=22 \end{gathered}\)Hence, the length of MK is 22 units
simplify
5cat + 3act - 6tac
Answer:
the correct answer is 2 act
Step-by-step explanation:
there is same base (act)
then 5+3=8
and 8-6 = 2act
Use integration to find a general solution of the differential equation. (Use C for the constant of integration. dy/dx = e^x/5 + e^x
Answer:
Step-by-step explanation:
Q7-8 PLEASE HELP ME
Answer:
(-4,-7)
Step-by-step explanation:
Use the online graphing calculator called Desmos. That's what I did. Just input the two equations and it'll show you the completed graph. I hope this help you:)
3/4(-4.2 - x) = 5 enter answer as mixed number
Answer:
x = -10 13/15
Step-by-step explanation:
3/4(-4.2 - x) = 5
4/3 * (3/4(-4.2 - x) = 5) ==> multiply by the reciprocal of a number to get 1
1(-4.2 - x) = 5 * 4/3
-4.2 - x = 20/3
-4 2/10 - x = 20/3
-(4 + 2/10) - x = 20/3
-(40/10 + 2/10) - x = 20/3
-42/10 - x = 20/3
42/10 - 42/10 - x = 42/10 + 20/3
-x = 42/10 + 20/3
30 * (-x = 42/10 + 20/3) ==> LCM(Least common multiple) of 10 and 3 is 30.
-30x = 30 * 42/10 + 30 * 20/3
-30x = 30/10 * 42 + 30/3 * 20
-30x = 3 * 42 + 10 * 20
-30x = 126 + 200
-30x = 326
30x = -326
x = -326/30
x = -(300 + 26)/30
x = -300/30 - 26/30
x = -10 - 26/30
x = -(10 + 26/30)
x = -10 26/30
x = -10 13/15
HELPP!!!! Tyrell is working on the middle school yearbook. He wants to fit a 4×6 inch photo into a space that is 3 inches wide. At what percent should he set the copier zoom button to achieve this size?
Answer:
50%
Step-by-step explanation:
Step one:
By convention, the dimension of a shape is described as
Lenght first, followed by width
Hence
lenght = 4 in
Width = 6 in
Step two:
Therefore, to achieve a new width of 3 in, the initial width must be divided by 2, which is a 50% reduction.
3/6*100
0.5*100
=50%
Answer:its 75 percent
Step-by-step explanation:
a 86-ft tree casts a shadow that is 110 ft long. what is the angle of elevation of the sun? round the answer to two decimal places
The angle of elevation of the sun is 38.24 degrees (rounded to two decimal places).
The ratio of the height of the tree and the length of the shadow can be found by using the formula for tan which is given by:
tan(x) = (opposite/hypotenuse)
In the given problem statement, the height of the tree is opposite to the angle we are trying to find and the length of the shadow is the hypotenuse of the right-angled triangle. Therefore, we can say that:
tan(x) = opposite/hypotenuse = 86/110
We can use the inverse tangent function to find the value of x. This is because tan is the ratio of the opposite side (height of the tree) to the adjacent side (length of the shadow), and the inverse tangent function gives the angle that has that ratio.
So, tan x = 86/110 => x = tan⁻¹ (86/110) = 38.24 degrees (rounded to two decimal places). Therefore, the angle of elevation of the sun is 38.24 degrees.
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I’ll mark the brainliest
The equation in the problem solves the speed as 48.99 miles per hour. At this speed the car takes 100 feet to stop ( also shown in the equation as they replaced d with 100).
This means any speed below 48.99 miles per hour would stop before hitting the tree.
The fastest the car can go would be 48.98 miles per hour.
Justify by replacing s in the equation with 48.98 and solve for d:
48.98 ^2 = (sqrt( 30(0.8)d)
2399.04 = 24d
D = 2399.04/24
D = 99.96 feet
This is less than 100 feet so the car will not hit the tree.
henry works at a retail store and is eligible for 18 days leave for a year. How many days of leave is he entitled to for 9 months of work?
the circle passes through the point ( 7 , 6 ) (7,6)(, 7, comma, 6, ). what is its radius?
We cannot determine the center or radius of the circle based on the given information.
How to find the radius of the circle passing through the point (7, 6)?To find the radius of the circle passing through the point (7, 6), we need to determine the center of the circle.
Let's assume that the center of the circle is (a, b). Since the circle passes through point (7, 6), we can set up an equation using the distance formula between the center (a, b) and point (7, 6) as follows:
√((7 - a)² + (6 - b)²) = r
where r is the radius of the circle.
We can see that this equation represents the distance between the center of the circle and the point (7, 6) is equal to the radius of the circle.
We also know that the distance between the center of the circle and any point on the circle is equal to the radius. Therefore, if we can find the distance between (a, b) and another point on the circle, we can solve for the radius.
However, we do not have any other information about the circle, such as another point or the equation of the circle. Therefore, we cannot determine the center or radius of the circle based on the given information.
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You know from geometry that the sum of three angles in a triangle is equal to 180. you are given a triangle in which angle b measures 5 more than twice angle a in the triangle. angle c measures 11 less than 3 times the measure of angle a. what is the measure of the small angle, middle angle and the largest angle of this triangle?
The measure of the smallest angle is 31°, the middle angle is 67°, and the measure of the largest angle is 82°.
A triangle is a plane shape with three edges and three vertices. All triangles have three internal angles, and the addition or sum of these angles gives 180°. In the question above, the three angles of the triangle are not given, though, we are given some clues as to how we can find them:
First angle:Not much is said about the first angle, so we'll call it angle a.
Second angle:We are told that the second angle (angle b) is 5 more than twice
angle a. The '5 more' means '5+' twice the value of angle a. Thus;
angle b = 5 + 2a
Third angle:The third angle, angle c is 11 less than 3 times the measure of angle
a, meaning that angle c is 3 times angle a minus 11, thus;
angle c = 3a - 11
The addition of angle a, angle b and angle c gives 180°, hence:
a + 5 + 2a + 3a - 11 = 180°
a + 2a + 3a + 5 - 11 = 180°
6a -6 = 180
6a = 180 + 6
6a = 186
Dividing both sides by 6,
a = 31°
Now that we know the value of angle a, angle b will be
5 + 2(31) = 67°
and angle c is
3(31) - 11 = 82°
Hence, the measure of the smallest angle, angle a is 31°, the middle angle, angle b is 67°, and the largest angle, angle c is 82°.
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In 2010 Sacramento received 23 inches in annual precipitation , in 2011 the city received 17 inches in anual percpation , in which year was there more precpition?
Answer:
There was more precipitation in the year 2010.
Step-by-step explanation:
Here in this question, we have the data for the amount of precipitation received in two different years in a city called Sacramento.
Now, we are tasked with finding in which of the two years was there more precipitation.
From the question, we can identify the following;
in 2010, precipitation was 23 inches
in 2011, precipitation was 17 inches
We can see that 23 inches is greater than 17 inches. So what this mean is that the precipitation in 2010 was more than the precipitation received in 2011.
Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $35. For one performance, 15 advance tickets and 30 same-day tickets were sold. The total amount paid for the tickets was $750. What was the price of each kind of ticket?
The price of the same day ticket is $15 while the price of the advance tickets is $20
What is a simultaneous equation?
We can see that;
The combined cost of one advance ticket and one same-day ticket is $35.For one performance, 15 advance tickets and 30 same-day tickets were sold. The total amount paid for the tickets was $750.Forming the simultaneous equation we have;
Let the same day ticket be x and the advance ticket be y
x + y = 35
30x + 15y = 750
x = 35 - y
Hence;
30(35 - y) + 15y = 750
1050 - 30y + 15y = 750
1050 - 15y = 750
-15y = 750 - 1050
y = 20
Thus;
x + 20 = 35
x = 35 - 20
x = 15
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Ixl dilations-find the scale factor and center dilation
The scale factor is 2 and center dilation is reduced.
The scale factor is a ratio that describes how much a figure has been enlarged or reduced. It is calculated by dividing the length of the corresponding sides of the original and dilated figures. If the scale factor is greater than 1, then the figure is enlarged, and if it is less than 1, then the figure is reduced.
To find the scale factor in an IXL dilations problem, you need to compare the corresponding sides of the original and dilated figures.
If the original figure has a side length of 4 units, and the dilated figure has a corresponding side length of 8 units, then the scale factor is 8/4=2. This means that the dilated figure is twice as large as the original figure.
The center of dilation is the point about which the figure is enlarged or reduced. It is the fixed point that remains unchanged during the dilation process.
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Please help me asap!!!
1. Using the table below find the solution. If h(x)= -6, what is x?"
A: x= -8
B: x=8
C: X= -6
D: x=0
у
-9
h(x)
-6
-8
00 000
-7
-6
x= -8
x= 8
Ο Ο Ο
x= -6
x=0
Answer:
The answer for this math problem is B ×=8 for X.
Find the area under the standard normal distribution curve between z=0 and z=0. 98
The area under the standard normal distribution curve between z = 0 and z = 0.98 is:
0.8365 - 0.5000 = 0.3365
To find the area under the standard normal distribution curve between z = 0 and z = 0.98, we can use a standard normal distribution table or a calculator that can compute normal probabilities.
Using a standard normal distribution table, we can look up the area corresponding to a z-score of 0 and a z-score of 0.98 separately and then subtract the two areas to find the area between them.
The area under the standard normal distribution curve to the left of z = 0 is 0.5000 (by definition). The area under the curve to the left of z = 0.98 is 0.8365 (from the standard normal distribution table).
So the area under the standard normal distribution curve between z=0 and z=0.98 is approximately 0.3365.
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QUESTION IS IN IMAGE
Answer:
112
Step-by-step explanation:
so although 8 wouldn't fully trust me here my best bet would be 112 because 68 plus 112 is 180 which is half of 360 and 360 Is the degrees 9f the circle.
An event is considered to be ________, if all possible outcomes of a random experiment are included in the events.
The set of all possible outcomes is called the sample space. Thus in the context of a random experiment, the sample space is our universal set.
A sample space is a set of potential results from a random experiment. The letter "S" is used to denote the sample space. Events are the subset of possible experiment results. Depending on the experiment, a sample area could contain a variety of results.
The set of all potential outcomes or results of an experiment or random trial is referred to as the sample space in probability theory. The potential ordered outcomes, or sample points, are listed as elements in a set that is used to represent a sample space.
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A steel hex nut has two regular hexagonal faces and a hole with a diameter of 0.4 cm through the middle. its mass is 3.03 grams. a regular hexagonal prism is shown. a cylinder is cut out of the middle of the prism. the hexagon has an apothem with length 0.5 centimeters. the base edges have lengths of 0.6 centimeters and the height of the prism is 0.5 centimeters. the cylinder has a diameter of 0.4 centimeters. complete the steps to calculate the density of the steel. calculate the volume of the prism. recall that the area of a hexagon is one-half times the apothem times the perimeter. v = cm3 calculate the volume of the cylinder. round to the nearest hundredth. v = cm3 find the volume of the composite figure. v = cm3 calculate the density by dividing the mass by the volume. d = g/cm3
The density that's gotten by dividing the mass by the volume is 0.91.
How to calculate the density?From the information given, the volume of the cylindrical hole will be:
= πr²h
= 3.14 × (0.4/2)² × 1
= 0.1256
The volume of the pyramid will be:
= 1/3 × A × h
= 1/3 × 6✓3 × 1
= 3.4641
The difference will be:
= 3.4641 - 0.1256
= 3.3385.
The density of the figure will be:
= Mass / Volume
= 3.03/3.3385
= 0.91
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Answer:
Calculate the volume of the prism. Recall that the area of a hexagon is One-half times the apothem times the perimeter.
V = ✔ 0.45 cm3
Calculate the volume of the cylinder. Round to the nearest hundredth.
V = ✔ 0.06 cm3
Find the volume of the composite figure.
V = ✔ 0.39 cm3
Calculate the density by dividing the mass by the volume.
d = ✔ 7.77 g/cm3
Step-by-step explanation:
just did it (edg 2022)