Answer:
where is the video?
Explanation:
1. A 60-Hz, single-phase source with V = 277 ∠0o volts is applied to a circuit element. (a) Determine the instantaneous source voltage. Also determine the phasor and instantaneouscurrents entering the positive terminal if the circuit element is (b) a 30-resistor, (c) a 15-mH inductor, (d) a capacitor with 100mF.
(a) The instantaneous source voltage can be determined by using the given magnitude and phase angle. Since the phase angle is 0°, the instantaneous source voltage can be written as:
V(t) = 277 * cos(2π * 60 * t)
(b) For a 30-Ω resistor, the current entering the positive terminal is the same as the source current. Since the voltage and resistance are given, we can use Ohm's law to determine the current:
I(t) = V(t) / R = (277 * cos(2π * 60 * t)) / 30
(c) For a 15-mH inductor, the phasor current can be determined using the formula:
I = V / jωL
where j is the imaginary unit (√(-1)), ω is the angular frequency (2π * frequency), and L is the inductance. In this case, ω = 2π * 60 and L = 15 * 10^(-3):
I = (277 ∠0°) / (j * 2π * 60 * 15 * 10^(-3))
To find the instantaneous current, we can take the real part of the phasor current and then convert it to the time-domain using cosine function:
I(t) = Re(I * e^(jωt))
(d) For a capacitor with 100 mF, the phasor current can be determined using the formula:
I = jωCV
where C is the capacitance. In this case, ω = 2π * 60 and C = 100 * 10^(-3):
I = (j * 2π * 60 * 100 * 10^(-3)) * 277 ∠0°
To find the instantaneous current, we can take the imaginary part of the phasor current and then convert it to the time-domain using sine function:
I(t) = Im(I * e^(jωt))
which unit would be most
suitable for its scale?
Answer:
down below
Explanation:
for a scale, kg is used, as well as grams
for force, newtons is used
hii please help i’ll give brainliest if you give a correct answer please please hurry it’s timed
Answer:
Sorry I'm wrong The person above is correct.
I tried.
Answer:
The net force on the brick is 0N and the brick remains at rest.
Explanation:
Net force = 5N - 5N
= 0N
1.slope of distance time graph gives______in the case of uniform motion.
2.The magnitude of velocity and______will be equal if motion is along a straight path.
the first one answer is speed and the second one is direction.
Answer:
1. Slope of distance time graph gives Speed in the case of uniform motion
2.The magnitude of velocity and Displacement will be equal if motion is along a straight path
Explanation:
PLEASE MARK BRAINLEST
Explain what is wrong with the following statement: A man walked at an average
velocity of 5.2m/s.
Answer:
check explanation
Explanation:
Whenever we talk about velocity ,it means that we r telling them the speed of the object+the direction of the motion of object but here direction isn't mentioned. That's the fault in the statement
Hydrogen is found as a gas on Earth but exists in all four states in the solar
system. Four samples of hydrogen have equal masses but are each in a
different state. Which statement about the relative amounts of thermal
energy in the samples is true?
Answer:the sample of solid has less energy than the sample of gas
Explanation:
Apex
Based on the Radioactive Decay chart in the reading, which of the following elements would emit destructive radioactive material? a. Plutonium b. Carbon c. Hafnium d. Thorium
Based on the Radioactive Decay chart in the reading, Plutonium is the element that would emit destructive radioactive material, therefore the correct answer is option A
What is radioactivity?This radiation is released when a nucleus undergoes radioactive decay and transforms into a different isotope that may be radioactive (unstable) or non-radioactive depending on the number of neutrons and protons in the nucleus (stable).in other words one can say The ability of some unstable atoms to emit nuclear radiation spontaneously
Thus, Plutonium is the element that would emit destructive radioactive material, according to the radioactive decay chart in the reading, so option A is the appropriate response.
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The compound beam is fixed at A, pin connected at B, and supported by a roller at C. Draw the shear and moment diagrams for the beam.
The composite beam is supported by a roller at A, pin attached at B, and fastened at C. (See pic). The sheer and moment diagrams' figures are included.
At the intersection of "A" and "B," the shear force remains constant. in the Shear diagram, the first incline plane.
Linear shifts in shearing force are present between "B" and "C." The bending moment diagram thus reveals the parabolic shape.
The moment is 0 at point "B."
By calculating the shear force and bending moment at a specific place on a structural element, such as a beam, shear and bending moment diagrams are analytical approaches that are used in conjunction with structural analysis to help structural design.
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what is the speed of light faster than the speed of sound in air?
Explanation:
The speed of light in air is approximately 300,000,000 meters per second. The speed of sound in air is approximately 343 meters per second. Light is the propagation of electromagnetic waves, while sound is the physical vibration of the medium
From which part of the nervous system do cells that innervate neuromuscular junctions originate?
A) Peripheral nervous system (PNS)
B) Autonomic nervous system
C) Somatic motor division of the PNS
D) Central nervous system (CNS)
E) Visceral motor division of the PNS
E
Which statement best describes the function
Cells that innervate neuromuscular junctions originate from the central nervous system (CNS).
The central nervous system (CNS) is one of the two main parts of the nervous system, with the other being the peripheral nervous system (PNS). The CNS consists of the brain and spinal cord, which are responsible for receiving, processing, and sending information throughout the body.
The brain is the control center of the body and is responsible for cognitive functions such as thinking, memory, and decision-making. The spinal cord is responsible for transmitting information between the brain and the rest of the body, and for controlling reflexes.
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Please sb help me fr
Answer:
I think it might be box 1. Hope this is right have a good day
me lo traduses plis no se ingles solo escribe lo que dice en la guia
10. Josie and Trey were working on their physics project and both built catapults. Trey's catapult shot a ball
30 meters in 10 seconds, while Josie's catapult shot a ball 45 meters in 15 seconds. Whose catapult caused
the ball to move at a faster speed?
Answer:
Josie's ball faster than T
Two flying fish have an inelastic collision while in mid-flight. One fish has a mass of 0. 650 kg and a velocity of 15. 0 m/s to the right; the other has a mass of 0. 950 kg and a velocity of 13. 5 m/s to the left. Find the change in their kinetic energy after the collision
The change of kinetic energy is -156.7 joules.
\(V1_{i}\) =15
\(V2_{i}\)= -13.5(as towards left)
V= common velocity during collision
On applying momentum conservation during the collision
\(m_{1}V1_{i} + m_{2}V2_{i} = V ( m_{1} + m_{2})\)
\(0.650 \ 15 + 0.950 \ (-13.5) = (0.625 + 0.950) \ V\)
\(\frac{3.075}{1.6}\) =V
V= -1.92 m/s
To kind change in kinetic energy we will subtract final and initial kinetic energy
ΔK=\(\frac{1\ (m_{1} + m_{2} ) \ V}{2} ^{2}\) - \(\frac{1\ (m_{1} ) \ V1_{i} }{2} ^{2}\) - \(\frac{1\ (m_{2} ) \ V2_{i} }{2} ^{2}\)
ΔK= \(\frac{1\ (0.625 + 0.950 ) \ (-13.5)}{2} ^{2}\) - \(\frac{1\ (0.625 ) \ 15 }{2} ^{2}\)- \(\frac{1\ (0.950 ) \ 13.5 }{2} ^{2}\)
ΔK= = - 156.7 J
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How far will you travel if you walk for 10.0 minutes at a speed of 1.50 m/s?
Answer:
15
Explanation:
distance = speed × time.
An object that is not moving has no energy?
Answer: A motionless object can have energy. The energy that the object has is called potential energy.
Explanation:
A 1 kg box is sitting on a flat horizontal surface that has a coefficient of static friction value of 0.8. What answer best states the minimum force required to move the box in the horizontal direction?
A. >-9.8N
B. >9.8N
C. >7.84N
D. >9N
The normal force felt by the box has magnitude
F[normal] = (1 kg) g = 9.8 N
so that the maximum magnitude of static friction is
F[s. friction] = 0.8 F[normal] = 7.84 N
In order to get the box to move, (C) a minimum force of 7.84 N is required.
If a 5.00 kg box slides down a ramp inclined at 60.0° above the horizontal, what is the
acceleration of the box
Answer:
A 70 kg box is slid along the floor by a 400 n force. The coefficient of friction between the box and the floor is 0. 50 when the box is sliding
What would happen if the gravitational force between the moon suddenly disappeared?
Two stationary positive point charges, charge 1 of magnitude 4.00 nC and charge 2 of magnitude 1.80 nC , are separated by a distance of 58.0 cm. An electron is released from rest at the point midway between the two charges, and it moves along the line connecting the two charges. What is the speed vfinal of the electron when it is 10.0 cm from charge 1? Express your answer in meters per second.
The final speed of the electron, denoted as \($v_{\text{final}}$\), when it is 10.0 cm away from charge 1 can be calculated using the principles of electrostatics.
The initial position of the electron is at the midpoint between the two charges. We know that the charges are positive and stationary. Therefore, the electric field produced by charge 1 points towards charge 2. As the electron is negatively charged, it will experience a force in the opposite direction, i.e., towards charge 1. This force will cause the electron to accelerate.
To calculate \($v_{\text{final}}$\), we can use the conservation of energy. Initially, the electron is at rest, so its initial kinetic energy is zero. The final kinetic energy is given by \(\frac{1}{2mv^2_{final}}\), where m is the mass of the electron. The change in potential energy is given by \($q\Delta V$\), where q is the charge of the electron and \($\Delta V$\) is the change in electric potential.
The change in potential energy can be calculated by considering the electric potential at the midpoint and at a point 10.0 cm from charge 1. The electric potential at a point due to a point charge is given by \($V = \frac{kq}{r}$\), where k is the electrostatic constant, q is the charge, and r is the distance from the charge. By considering the signs and magnitudes of the charges, we can determine the change in potential energy.
By equating the initial kinetic energy to the change in potential energy, we can solve for \($v_{\text{final}}$\). The mass of an electron is known, and the values for the charges and distances are provided in the problem. Converting the given values to SI units (coulombs and meters), we can perform the necessary calculations to find the final speed of the electron.
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An iron rod with an initial length of 12.64 m has its temperature raised from 9o C to 38.10o C. If iron has a coefficient of thermal expansion of 12x10-6 1/oC, what is the change in length of the rod in mm?
We will have the following:
First, we remember that:
\(\Delta L=\alpha\ast L_0\ast\Delta T\)So:
\(\begin{gathered} \Delta L=(12\ast10^{-6}1/C)(12.64m)(38.1C-9C)\Rightarrow\Delta L=4.413888\ast10^{-3}m \\ \\ \Rightarrow\Delta L\approx4.41mm \end{gathered}\)So, the change in length of the rod is approximately 4.41 mm.
Please answer correctly
No trolling or links, please
Answer: Wave a the first answer is right
Brainliest.
Explanation:
Please help, I will give brainly.
The specific latent heat of vaporization of water is 2300 kj/kg.
What is the specific latent heat of vapourization?
Specific latent heat of vapourization is the quantity of heat required to convert unit mass of a substance from liquid to vapour state without change of temperature.
We have...
Q = heat energy = 69 kj
m = mass = 0.030 kg
L = Specific heat
The formula is given by:
Q = mL
L = Q / m
L = 69 / 0.030
L = 2300 kj / kg
The diameter of a nickel is 21 mm .
How far from your eye must it be held so that it has the same apparent size as the moon? (Use the astronomical data inside the back cover of the textbook.)
The nickel must be placed at a distance of 2.96 meters from your eyes, in order to have the same angular size of the moon.
We can determine the distance at which the nickel must be placed in order to have the same angular size by using the tangent of the angle as before, where the adjacent is the distance between your eyes and the nickel, so we have, knowing the angular size, and knowing the diameter of the penny "the opposite".
The diameter of a nickel is 21 mm = 21 x 10⁻³
(21 x 10⁻³ / adj) = tan 9.037 x 10⁻³
adj = (21 x 10⁻³) / (tan 9.037 x 10⁻³)
= 2.96 m
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TRUE/FALSE. an independent-measures study has m1 = 49 and m2 = 45 with an estimated standard error of this study, cohen’s d = 4/4 = 1.00.
The statement "An independent-measures study has m1 = 49 and m2 = 45 with an estimated standard error of this study, cohen’s d = 4/4 = 1.00" is false.
Cohen's d is not calculated by dividing the difference in means by the estimated standard error. Cohen's d is calculated by dividing the difference in means by the pooled standard deviation.
To calculate Cohen's d, the formula is:
\(d = \frac{M_1 - M_2}{SD_{\text{pooled}}}\)
where M1 and M2 are the means of the two independent groups and \({SD_{\text{pooled}}}\) is the pooled standard deviation. The pooled standard deviation takes into account the sample sizes and standard deviations of both groups.
Without the sample sizes or the standard deviations of the two groups, it is not possible to determine the correct value of Cohen's d or whether the statement is true or false.
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an x-ray machine makes a picture of a broken arm (shown above)by sending high energy photons through an object that is opaque to visible wavelengths and measures the relative intensity of the x-rays that emerge on the other side. denser substances, such as bone, absorb more photons than less dense substances and thus show up differently.consider the table of x-ray absorptions shown above. near the center of an arm, the x-rays pass through 3.4 cm of muscle, 3.3 cm of bone, and 3.2 more cm of muscle. what fraction of the incident x-rays get through this part of the arm? (hint: assume muscle has the same x-ray stopping power as fat.)
Only about 0.01% of the incident x-rays make it through this part of the arm.To solve this problem, we need to use the table of x-ray absorptions to determine the absorption coefficients of muscle and bone at the energy of the x-rays used by the machine. Let's assume that the x-rays have an energy of 50 keV, which is typical for medical imaging.
According to the table, the absorption coefficient for muscle at 50 keV is 0.2 cm^2/g, and the absorption coefficient for bone is 1.3 cm^2/g. We also know the thicknesses of the muscle and bone through which the x-rays must pass: 3.4 cm of muscle, 3.3 cm of bone, and 3.2 cm more of muscle.
To calculate the fraction of incident x-rays that get through this part of the arm, we can use the Beer-Lambert law, which states that the intensity of the x-rays decreases exponentially as they pass through a material:
I = I0 * e^(-mu*x)
where I is the intensity of the x-rays after passing through a thickness x of material, I0 is the initial intensity of the x-rays, mu is the absorption coefficient of the material at the energy of the x-rays, and e is the base of the natural logarithm.
Using this equation, we can calculate the fraction of incident x-rays that get through each layer of the arm:
For the first layer of muscle:
I1 = I0 * e^(-0.2*3.4) = 0.306 * I0
For the layer of bone:
I2 = I1 * e^(-1.3*3.3) = 0.00054 * I0
For the second layer of muscle:
I3 = I2 * e^(-0.2*3.2) = 0.000104 * I0
Therefore, the fraction of incident x-rays that get through this part of the arm is:
I3 / I0 = 0.000104
In other words, only about 0.01% of the incident x-rays make it through this part of the arm. This is because the bone absorbs most of the x-rays due to its higher density and higher absorption coefficient.
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two students will be working together diluting concentrated acid for their experiment. before beginning, they think about the ramp acronym and quickly assess the risk of their planned procedure. choose the best assessment for each letter.
By using the RAMP acronym, the students can examine and manage the risks connected with their diluting concentrated acid approach, resulting in a safer and more regulated experimental process.
To assess the risk of their planned procedure using the RAMP acronym, the best assessment for each letter would be as follows:
R - Recognize hazards: The students should identify and acknowledge any potential hazards associated with diluting concentrated acid.
A - Assess risks: The students should evaluate the risks associated with the procedure. This involves considering the probability and potential consequences of accidents or mishaps, such as acid splashes, improper handling, or inhalation of fumes.
M - Minimize risks: The students should take measures to minimize the identified risks. This includes implementing safety protocols and precautions.
P - Prepare for emergencies: The students should be prepared to respond to any potential emergencies or accidents that may occur during the procedure.
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Which statement illustrates how engineering has influenced society?
A. Digital cameras require far less time to generate images than film cameras
do.
B. Digital cameras allow people to take more pictures and share them more
widely than film cameras did.
C. People want the cameras in their cell phones to be able to capture high-
resolution images
D. People expect that advances in imaging technology will keep up with their
needs for sharing pictures.
The statement illustrates how engineering has influenced society in that People want the cameras in their cell phones to be able to capture high-resolution images. Option C is corect.
What is a digital camera?A digital camera that creates pictures that can be saved on a computer and seen on a screen.
People want their mobile phone cameras to be able to take high-resolution pictures, which shows how engineering has affected society.
Statement B illustrates how engineering has influenced society.
Hence option C is correct.
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Auntie Sarah mops the floor by applying a force of 9N at an angle of 60° to the floor, How much work has she done
after mopping a total distance of 10m?
Answer:
9×1/2×10=45J
Explanation:
\(w = f \times d \times \cot( \beta ) \)
f=9N
d=10m
cos(B)=1/2
The velocity of a particle traveling along an axis is given. Near what time is the instantaneous acceleration equal to 0?.
When the velocity of a particle moving along an axis is known, the instantaneous acceleration equal to zero is given as 0.6t.
What is the formula for immediate acceleration?We estimate the average speed between two places in time separated by t while allowing t to decrease. The outcome is the velocity function's derivative, v. (t).
The slope of the tangent line to the graph at any given location on the graph corresponds to the instantaneous acceleration there. The instantaneous acceleration of the particle is equal to 0 when this line is horizontal and has a slope of 0. According to the plot, these times correlate to the velocity function's extrema, which can be found at t = 1.75, 2.75, 3.25, and for all t = 4.
t = 0.6 is the most likely choice.
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What is the energy of a photon emitted with a wavelength of 518 nm?
A. 1.03 x 10-13
B. 3.43 x 10-22
O C. 3.84 x 10-19 J
D. 1.28 x 10-27
Answer:
C
Explanation: