how would i solve (4x 3 + 7y 3z 4) 2 ?

To get rid of a fraction in an equation, you need to multiply both sides of the equation by the reciprocal of the fraction.

An element of a whole is a fraction. The number is represented mathematically as a quotient, where the numerator and denominator are split. Both are integers in a simple fraction. A fraction appears in the numerator or denominator of a complex fraction. The numerator of a proper fraction is less than the denominator.

To get rid of a fraction in an equation, you need to multiply both sides of the equation by the reciprocal of the fraction.

For example, if you have the equation:

1/3x = 4

To get rid of the fraction 1/3, you can multiply both sides of the equation by its reciprocal, which is 3/1 (or just 3):

(3/1) * (1/3)x = (3/1) * 4

Simplifying, we get:

x = 12

So the solution to the original equation is x = 12.

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Answer:

X=7 Y=5

Step-by-step explanation:

The given statement is True because If the sample mean is close to the population parameter, it suggests representative sampling regarding the variable of interest, although other factors should be considered too.

When the sample mean closely approximates the population parameter, it indicates that the sample is capturing the central tendency of the population. The mean is a measure of central tendency that reflects the average value of the variable of interest in the population.

If the sample mean is similar to the population mean, it suggests that the sample is a good representation of the population in terms of that particular variable.

However, it is important to note that representativeness is a relative concept. A sample may be considered representative in one sense but not necessarily in all aspects. Other factors, such as the sampling method, sample size, and sampling bias, also influence the representativeness of a sample.

In summary, when the obtained mean of the observations in a research study is close to the population parameter, it provides evidence that the sample is representative of the target population to some degree, indicating that the sample captures the central tendency of the population for the variable under investigation.

However, representativeness should be assessed in consideration of other factors as well.

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The predicted value of y when x = 3, based on the least-squares regression line equation y = 50 - 15x, is y = 50 - 15(3) = 5.

The given least-squares regression line equation y = 50 - 15x represents a linear relationship between the variables x and y. In this equation, the coefficient of x (-15) represents the slope of the line, and the constant term (50) represents the y-intercept.

To find the predicted value of y when x = 3, we substitute x = 3 into the equation and solve for y. Plugging in x = 3, we have y = 50 - 15(3). Simplifying this expression, we get y = 50 - 45 = 5.

Therefore, when x = 3, the predicted value of y based on the least-squares regression line is 5. This means that according to the regression line, when x is 3, the expected or estimated value of y is 5.

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The chi-square distribution approaches symmetry as the number of degrees of freedom rises.

The distribution of the sum of the squares of k independent standard normal random variables continues to be the chi-squared distribution with k degrees of freedom.

A continuous, non-negative, positively skewed probability distribution is the chi-square distribution. Unlike the z and t scores used for quantitative variables, the Chi-square statistic can be used to compare the difference between the observed and expected frequencies of values of a categorical random variable.

The chi-square distribution changes from a descending slope to a hump form as the degrees of freedom (k) rise. The hump changes from being highly right-skewed to being roughly normal as the degrees of freedom rise.

As a result, the assertion is accurate.

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Answer:

The answer is -4

Step-by-step explanation:

Because yo subtract both numbers and you take the sign of the bigger number which is negative  that's why is -4

Answer: -44

Step-by-step explanation:

To find a positive number such that the sum of and is as small as possible, we need to use optimization. This problem requires optimization over a closed interval. The given problem is as follows, Let x be a positive number. Find a positive number such that the sum of and is as small as possible.

To find a positive number such that the sum of and is as small as possible, we need to use optimization. This problem requires optimization over a closed interval. The given problem is as follows, Let x be a positive number. Find a positive number such that the sum of and is as small as possible. So, we need to minimize the sum of and . Now, let's use calculus to find the minimum value of the sum.To find the minimum value, we have to find the derivative of the sum of and , i.e. f(x) with respect to x, which is given by f '(x) as shown below:

f '(x) = 1/x^2 - 1/(1-x)^2

We can see that this function is defined on the closed interval [0, 1]. The reason why we are using the closed interval is that x is a positive number, and both endpoints are included to ensure that we cover all positive numbers. Therefore, the problem requires optimization over a closed interval. This means that the minimum value exists and is achieved either at one of the endpoints of the interval or at a critical point in the interior of the interval.

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The moment-generating function for y is given as eⁿᵇ - eⁿᵃ / n(b-a) and derivation of  moment-generating function of y is e-1/t

Given that,

The interval (0, 1) is covered by a uniform distribution of y, and a > 0 is a constant.

The moment generating function is eⁿᵇ - eⁿᵃ / n(b-a)

The given interval is (0,1)

Here a =0;

         b=1;

Now substitute the values of a and b in the above moment generating function we get,

y=eⁿᵇ - eⁿᵃ / n(b-a)

y=e^1-e^0/t(1-0)

y= e-1/t

Therefore, the derivation of the moment generating function is e-1/t

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The result of the integral is (10/5)sin^5(x) - (20/7)sin^7(x) + (10/9)sin^9(x) + c. To evaluate the integral ∫10cos^5(x)sin^4(x)dx, we can use a trigonometric identity and a substitution.

To simplify the integrand, we can use the trigonometric identity cos^2(x) = 1 - sin^2(x) and substitute u = sin(x).

Apply the trigonometric identity: cos^5(x) = (1 - sin^2(x))^2 * cos(x) = (1 - u^2)^2 * cos(x). Now we have the integrand as 10(1 - u^2)^2 * cos(x) * u^4.

Use the substitution: Let u = sin(x), then du = cos(x)dx. We can rewrite the integral as ∫10(1 - u^2)^2 * u^4 * du.

Expand the integrand: 10u^4 - 20u^6 + 10u^8.

Integrate each term: The integral of u^4 is u^5/5, the integral of u^6 is u^7/7, and the integral of u^8 is u^9/9.

Substitute back: Replace u with sin(x) in the antiderivative expression obtained in the previous step.

Add the constant of integration, c, to obtain the final result.

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Answer:

c) x = 120, y = 70

Step-by-step explanation:

Since lines a, b and c are parallel, x = 120.

That angle inside the triangle kind of below x would be 180-120 = 60 degrees.

All 3 inside (interior) angles of a triangle add up to 180.

So 60+50+y = 180

110 + y = 180

y = 180-110

y = 70.

x =120, y = 70.

Choose option c.

The flag pole to which Jeremy's shadow aligns with is 12.33 ft

Equate the ratio of Jeremy's shadow to flagpole

8 : 16 = 74 in : x

74 in = 6.16667

So,

8 : 16 = 6.16667 : x

8/16 = 6.16667 / x

cross product

8 × x = 16 × 6.16667

8x = 98.66672

divide both sides by 8

x = 98.66672 / 8

x = 12.33334

Therefore, the flag pole is approximately 12.33 ft long

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Equations are written by equating the expressions to each other. The value of x is 7

Equations are written by Equating the expressions to each other.

Given the equation below:

10 - x = 3

Subtract 10 from both sides

10 - x - 10 = 3 - 10

-x = -7

Multiply both sides by -1

-(-x) = -(-7)

x = 7

Hence the value of x is 7

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Step-by-step explanation:

23.35......is answer.......

Answer:

none of the statements are true

Step-by-step explanation:

given the final statement in the solution is

5 = 0 ← not possible

this indicates the system has no solution.

then none of the previous statements are true

Answer:

I can't see the file. But I did something that sounded LIKE this. So try multiplying the parallel sides.

Step-by-step explanation:

Determine the angle of depression.

Answer: 0.0120 degree

There are 8,640 ways the five people can be seated in the eight empty seats.

To determine the number of ways the five people can be seated in eight empty seats, we can use the concept of permutations.

Since the order in which the people are seated matters, we need to calculate the number of permutations of five people taken from eight seats.

The formula for permutations is given by:

P(n, r) = n! / (n - r)!

where n represents the total number of items and r represents the number of items taken at a time.

In this case, we have 8 empty seats (n) and want to seat 5 people (r). Therefore, we can calculate the number of ways as:

P(8, 5) = 8! / (8 - 5)!

= 8! / 3!

= (8 * 7 * 6 * 5 * 4 * 3!) / 3!

= 8 * 7 * 6 * 5 * 4

= 8,640

Hence, there are 8,640 ways the five people can be seated in the eight empty seats.

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x = amount of the 80% broth

y = amount of water with 0% broth

keeping in mind that water has no broth in it, so 0% of broth, let's plug in those percentages in decimal format to see how much each one has.

what's 80% of "x"? well (8/100) * x = 0.80x.

what's 0% of "y"?  well hell is just 0.

what's 60% of 200? well anyhow is just 120.

\(\begin{array}{lcccl} &\stackrel{liters}{quantity}&\stackrel{\textit{\% of liters that is}}{\textit{broth only}}&\stackrel{\textit{liters of}}{\textit{broth only}}\\ \cline{2-4}&\\ \textit{80\% Sol'n}&x&0.80&0.80x\\ water&y&0.00&0\\ \cline{2-4}&\\ mixture&200&0.60&120 \end{array}~\hfill \begin{cases} x + y = 200\\\\ 0.80x+0=120 \end{cases} \\\\[-0.35em] ~\dotfill\\\\\)

\(\stackrel{\textit{using the 2nd equation}}{0.8x=120}\implies x=\cfrac{120}{0.8}\implies \boxed{x=150~liters} \\\\\\ \stackrel{\textit{using the 1st equation}}{150 + y = 200}\implies y=200-150\implies \boxed{y=50~liters}\)

Area of the region enclosed by one loop of the curve is pi/288.

To find the area of the region enclosed by one loop of the curve, we can use the formula for the area of a polar region:

A = 1/2 * ∫(r^2)dθ

We can use this formula with the equation for r given:

A = 1/2 * ∫(sin^2(6θ))dθ

This integral can be simplified by noting that sin^2(x) = (1/2)(1 - cos(2x))

Thus,

A = 1/2 * ∫(1/2)(1 - cos(12θ))dθ

This integral can be solved by noting that the antiderivative of (1/2)(1 - cos(12θ)) is (1/24)(sin(12θ) + θ).

Therefore, the area enclosed by one loop of the curve is

A = 1/2 * ((1/24)(sin(12θ) + θ)) evaluated from 0 to pi/6

A = (1/48)(sin(2pi) + pi/6)

   = (1/48)(0 + pi/6)

   = pi/288

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Answer:

The point of intersection between 2x+3y=12 and 2x-y=4 is (3,2)

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

Here, we want to reflect over the y-axis

by reflection over the y-axis, (x,y) becomes (-x,y)

Thus, we simply are going to negate the x values of the points given

So the correct answers are;

P’(4,-8)

Q’ (6,6)

R’ (-1,-7)

Answer:

this is the answer I have done.

Answer:

8x-29y Sorry if wrong!

Step-by-step explanation:

You have to distribute first and then combine like terms.

Answer:

8x-29y

Step-by-step explanation:

You have to distribute first and then combine like terms.

And that is where you get your answer.

Hope this helps.

Answer:

B

Step-by-step explanation:

1.25 is incorrect becuase 25% is .25 not 1.25

The dimensions of the coop are length = 12 ft and width = 9 ft

Since the coop is a rectangle, the area of the coop is A = LW where

Now, the length of the coop 3 feet longer than the width, so, L = W + 3

Now, the area of the coop A = 108 ft²

So, A = LW

A = (W + 3)W

108 = W² + 3W

Re-arranging,

W² + 3W - 108 = 0

So, we solve the equation to find the width of the coop

W² + 3W - 108 = 0

Factorizing, we have

W² + 12W - 9W - 108 = 0

W(W + 12) - 9(W + 12) = 0

(W + 12)(W - 9) = 0

W + 12 = 0 or W - 9 = 0

W = -12 or W = 9

Since W cannot be negative, W = 9

Since L = W + 3

Substituting the value of W into L, we have

L = W + 3

L = 9 + 3

L = 12 ft

So, dimensions of the coop are length = 12 ft and width = 9 ft

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The general solution to the differential equation dy/dx = 1/3(sin x − xy^2), y(0)=5 is: y = ±√[(sin x - e^(x/2)/25)/x], if sin x - xy^2 > 0 and y(0) = 5

To solve this differential equation, we can use separation of variables.

First, we can rearrange the equation to get dy/dx on one side and the rest on the other side:

dy/dx = 1/3(sin x − xy^2)

dy/(sin x - xy^2) = dx/3

Now we can integrate both sides:

∫dy/(sin x - xy^2) = ∫dx/3

To integrate the left side, we can use substitution. Let u = xy^2, then du/dx = y^2 + 2xy(dy/dx). Substituting these expressions into the left side gives:

∫dy/(sin x - xy^2) = ∫du/(sin x - u)

= -1/2∫d(cos x - u/sin x)

= -1/2 ln|sin x - xy^2| + C1

For the right side, we simply integrate with respect to x:

∫dx/3 = x/3 + C2

Putting these together, we get:

-1/2 ln|sin x - xy^2| = x/3 + C

To solve for y, we can exponentiate both sides:

|sin x - xy^2|^-1/2 = e^(2C/3 - x/3)

|sin x - xy^2| = 1/e^(2C/3 - x/3)

Since the absolute value of sin x - xy^2 can be either positive or negative, we need to consider both cases.

Case 1: sin x - xy^2 > 0

In this case, we have:

sin x - xy^2 = 1/e^(2C/3 - x/3)

Solving for y, we get:

y = ±√[(sin x - 1/e^(2C/3 - x/3))/x]

Note that the initial condition y(0) = 5 only applies to the positive square root. We can use this condition to solve for C:

y(0) = √(sin 0 - 1/e^(2C/3)) = √(0 - 1/e^(2C/3)) = 5

Squaring both sides and solving for C, we get:

C = 3/2 ln(1/25)

Putting this value of C back into the expression for y, we get:

y = √[(sin x - e^(x/2)/25)/x]

Case 2: sin x - xy^2 < 0

In this case, we have:

- sin x + xy^2 = 1/e^(2C/3 - x/3)

Solving for y, we get:

y = ±√[(e^(2C/3 - x/3) - sin x)/x]

Again, using the initial condition y(0) = 5 and solving for C, we get:

C = 3/2 ln(1/25) + 2/3 ln(5)

Putting this value of C back into the expression for y, we get:

y = -√[(e^(2/3 ln 5 - x/3) - sin x)/x]

So the general solution to the differential equation dy/dx = 1/3(sin x − xy^2), y(0)=5 is:

y = ±√[(sin x - e^(x/2)/25)/x], if sin x - xy^2 > 0 and y(0) = 5

y = -√[(e^(2/3 ln 5 - x/3) - sin x)/x], if sin x - xy^2 < 0 and y(0) = 5

Note that there is no solution for y when sin x - xy^2 = 0.

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Towers of Hanoi game: Algorithm and complexities(a) Algorithm and complexities of moving n disks from Start to Dest:Algorithm:1. If n = 1, move disk 1 from Start to Dest2. If n > 1, do the following:i. Move n-1 disks from Start to A2 using Destii.

Move disk n from Start to Destiii. Move n-1 disks from A2 to Dest using Start Time complexity: Since there are three towers, the minimum number of moves required for n disks is 2^n − 1. Therefore, the time complexity for this problem is O(2^n).Space complexity:

The space complexity of the Towers of Hanoi algorithm is O(n) because it uses a recursive algorithm to solve the problem, and the stack space required by the function calls is proportional to n.(b) Towers of Hanoi game implementation for n=1 to 10Here is the output of the algorithm.

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