how to solve what is the ph of a solution made by 93 mL of .010 M HClO4 41 ml of .040 M HCL and 866 mL of water

Answer:

n = 0.223 mol.

Explanation:

Hello there!

In this case, according to the given information, it is possible for us to approach this problem via the ideal gas law, which involves the pressure, moles, temperature and volume of the gas:

\(PV=nRT\\\\\)

Thus, by solving for moles we obtain:

\(n=\frac{PV}{RT}\)

Therefore, we plug in the given volume, temperature (in Kelvins) and pressure to obtain:

\(n=\frac{0.9atm*8L}{0.08206\frac{atm*L}{mol*K}*(120+273)K} \\\\n=0.223mol\)

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Answer:

Fish is the best time to go

Explanation:

Chicken nuggets and a salad and some onion rings and a new charger

Answer:

cavalent bond =diamond, carbon, silica, hydrogen gas, water, nitrogen gas

ionic= i don't know

metallic bonds= Silver, gold, nickel, copper, ironl, cobalt, calcium and magnesium, gold, barium, platinum, chromium,

Explanation:

not all are objects so pick the ones that are.

The pH of the solution is 3.88, which is made by combining 55 ml of 0.060 m hydrofluoric acid with 125 ml of 0.120 m sodium fluoride.

Hydrofluoric acid (HF) is a weak acid and its conjugate base is the fluoride ion (F⁻). When HF is added to an aqueous solution of sodium fluoride (NaF), the HF reacts with NaF to form the conjugate base F⁻ and sodium hydroxide (NaOH) through the following reaction;

HF + NaF → H₂O + Na⁺ + F⁻

The resulting solution contains a mixture of HF and F⁻ ions, making it a buffered solution.

To calculate the pH of the solution, we need to determine the concentration of each species in the solution, as well as the acid dissociation constant (Ka) for HF.

The Ka for HF is 7.2 × 10⁻⁴ at 25°C.

First, we will calculate the moles of HF and F⁻ in each solution;

moles of HF = 0.060 mol/L × 0.055 L = 0.0033 mol

moles of F⁻ = 0.120 mol/L × 0.125 L = 0.015 mol

Next, we need to determine the total moles of F⁻ in the solution:

moles of F⁻ = 0.0033 mol + 0.015 mol = 0.0183 mol

Since F⁻ is the conjugate base of HF, we can use the Henderson-Hasselbalch equation to calculate the pH of the solution;

pH = pKa + log([F⁻]/[HF])

where [F⁻]/[HF] is the ratio of the concentration of F^- to HF.

pKa = -log(Ka) = -log(7.2 × 10⁻⁴) = 3.14

[F⁻]/[HF] = moles of F⁻/moles of HF

[F⁻]/[HF] = 0.0183 mol / 0.0033 mol

[F⁻]/[HF] = 5.55

Substituting into the Henderson-Hasselbalch equation, we get:

pH = 3.14 + log(5.55)

pH = 3.14 + 0.744

pH = 3.88

Therefore, the pH of the solution is 3.88.

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5.20 g / 40.00 g = 0.130 moles NaOH

molarity = moles of solute / liters of solution

M = 0.130 moles / 0.500 L

M = 0.260

b) 0.260 M

The molarity of the solution is 0.260M

Molarity is the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution. It is denoted by M.

Solution is a homogeneous mixture composed of two or more substances.

Molarity = Moles of solute / litres of solution

5.20g / 40.00g/mol = 0.130 moles NaOH

M = 0.130 moles / 0.500L

M = 0.260M

Hence, option 2 is the answer.

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The value of Ksp for Ba\(CrO_4\) is approximately 2.49 × \(10^{-16 }\)at 25 °C.

\(BaCrO_4\)(s) ↔ \(Ba_2\)+(aq) + \(CrO_42\)-(aq)

The equilibrium expression for the solubility product of BaCrO4 is:

Ksp = [\(Ba_2\)+][\(CrO_42\)-]

We can use the given solubility  \(CrO_42\) to calculate the concentrations of \(Ba_2\)+ and \(CrO_42\)- at equilibrium:

\(BaCrO_4\)(s) ↔ \(Ba_2\)+(aq) + \(CrO_42\)-(aq)

Initial: 0 0 0

Equilibrium: x x 3.7x\(10^{-6}\) mol/L

Since 1 L of water contains 3.7 mg of BaCrO4 at equilibrium, the molar solubility of BaCrO4 is:

molar solubility = (3.7 mg / BaCrO4) / (molar mass of BaCrO4)

= (3.7 × \(10^{-6 }\)mol / L) / (233.39 g / mol)

≈ 1.58 × \(10^{-8}\) M

Therefore, at equilibrium, [\(Ba_2\)+] = [\(CrO_4\)2-] = x = 1.58 × \(10^{-8}\) M.

Substituting these values into the equilibrium expression for Ksp:

Ksp = [\(Ba_2\)+][\(CrO_4\)2-] = (1.58 × \(10^{-8}\))² ≈ 2.49 × \(10^{-16}\)

Ksp, or the solubility product constant, is a measure of the solubility of a sparingly soluble salt in a solvent. It is a constant value that describes the equilibrium between the solid salt and its ions in the solution. Ksp is the product of the concentrations of the ions raised to the power of their stoichiometric coefficients, each raised to the power of their respective coefficients.

Ksp is a measure of the maximum amount of salt that can be dissolved in a solvent at a given temperature and is dependent on the temperature, pressure, and ionic strength of the solution. If the ion concentration exceeds the Ksp, then the salt will precipitate out of the solution until a new equilibrium is reached.

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Answer:

1. 7.227x10²⁴ O atoms

2. 0.1944 mol

3. 3.18x10²³ atoms

Explanation:

1. To solve this problem we need to use Avogadro's number, which states the number of molecules that are in 1 mol of a substance:

There are 3 O atoms per NaNO₃ molecule, thus the answer is (3* 2.409x10²⁴) 7.227x10²⁴ atoms.

2. First we convert 10.5 g of N₂O₅ into moles, using its molar mass:

There are 2 N moles per N₂O₅ mol, thus the answer is (2*0.0972) 0.1944 mol.

3. First we convert grams into moles:

Then we use Avogadro's number:

There are 14 O atoms per Fe(H₂O)₂(SO₄)₃ molecule, so the answer is (7.95x10²² * 4) 3.18x10²³ atoms.

Answer:

MAIN IDEA
What the authors meant is not to judge people by their looks.

_____________________________________________________________

THE UGLY DUCKLING

The ugly duckling doesn't fit with the other ducklings and grows up, to be a fabulous bird. In the beginning, he is teased because of his looks, in a quote, "As the ugly duckling grew, many animals in the pond criticized him. His feathers were too dark, his neck was too long, and his body was too big. His fellow ducklings refused to recognize that underneath the feathers, the ugly duckling was kind, good, and gentle. The ugly duckling shed many tears because none of the other animals would play with him."

Near the end, however, it states, "He believed that the swans would never be his friends and looked down into the pond in despair. Then, his eyes opened wide, for he saw his reflection. To his great astonishment, the ugly duckling discovered that he was a beautiful, royal swan! The swans welcomed their new friend, whose lovely appearance was matched only by his kind heart. He now felt like he belonged." Throughout the course of the story, the other birds' views change since now they realize how awful they felt for mistreating the ugly duckling.

_____________________________________________________________

THE PRINCESS AND THE PEA

The king and queen didn't believe that she was a princess, so they had her endure the trial of sleeping on twenty mattresses with a pea under the very bottom one. Near the beginning of the story, it states, "The disheveled maiden looked at the king in disbelief. "I am a princess, come to see the prince," she explained, all the while shivering. The king summoned his wife, the queen, for advice. The queen looked at the hideous creature in disbelief, thinking that no princess would ever allow herself to be found in such a state. She thought quickly and came up with a clever plan. The queen put a small pea at the bottom of a bed and piled twenty mattresses on top of it. When the girl arrived at the room, she had to climb a ladder to reach the top of the bed, where she collapsed in exhaustion." This is when the king and queen were in doubt that she was a princess.

However later on it stated, "Bright and early the next morning, the king and queen arrived at the girl's bed-chamber. The queen asked the girl how she had slept the night before. "Absolutely terribly!" bemoaned the maiden. "I have spent the entire night tossing and turning. I don't know whether there is something hard in the bed, or your mattresses are rocks, but my body is black and blue." The queen and the king stared at the maiden in astonishment. Only a real princess would have such delicate skin that she could feel a pea under twenty mattresses. The queen and king brought her to the prince, who was thrilled to meet a real princess with such an independent spirit." As you can see the king and queen believed that she was a princess now because they stated, "Only a real princess would have such delicate skin that she could feel a pea under twenty mattresses."

_____________________________________________________________

CONCLUSION
Both stories focus on how the main character is doubted or mistreated because of how they look, but throughout the stories, the main character proves them wrong.

Explanation:

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Answer:

3: 1 CH4+ 2 O2-> 1 CO2 + 2 H2O

4: 2 K+ 2 H2O -> 2 KOH+ 1 H2

Explanation:

Answer:

0⁰c , 5 mmHg

Explanation:

Because at this temperature we all know water can be in state of both solid and liquid and when pressure is decreased it can be in form of gas too

The amount in grams of Pbl₂ can be dissolved in a 500 mL of a 0.050 M Nal solution is approximately 7.42 x 10⁻⁶ grams.

The activity is defined as the concentration of an ion in solution divided by its concentration in its pure state.

To calculate the amount of PbI₂ that can be dissolved in a 500 mL of a 0.050 M NaI solution, we can use the following steps:

1. Write the balanced equation for the dissolution of PbI₂:
  PbI₂ (s) ⇌ Pb²⁺ (aq) + 2I⁻ (aq)

2. Use the Ksp expression for PbI₂:
  Ksp = [Pb²⁺] * [I⁻]²

3. Determine the initial concentration of I⁻ in the NaI solution:
  [I⁻] = 0.050 M (given)

4. Assume that x mol of PbI₂ dissolves:
  [Pb²⁺] = x
  [I⁻] = 0.050 + 2x

5. Plug the values into the Ksp expression:
  Ksp = x * (0.050 + 2x)²

6. Use the given Ksp value for PbI₂ at 25 °C:
  7.9 x 10⁻⁹ = x * (0.050 + 2x)²

7. Solve for x:
  x ≈ 3.22 x 10⁻⁸ mol/L

8. Determine the mass of dissolved PbI₂ in 500 mL of solution:
  mass = x * volume * FW of PbI₂
  mass ≈ (3.22 x 10⁻⁸ mol/L) * (0.500 L) * (461.01 g/mol)
  mass ≈ 7.42 x 10⁻⁶ g

Approximately 7.42 x 10⁻⁶ grams of PbI₂ can be dissolved in a 500 mL of a 0.050 M NaI solution at 25 °C.

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Answer:

3.39e+20

Explanation:

Answer:

1 / 2 of her money would be left

Explanation:

Tammy spent 2/5 of her savings on a watch. She then spent 1/6 of the remainder on a bag. What fraction of her money did she have left?

Taking the question bits by bit;

Tammy spent 2/5 of her savings on a watch

Amount Spent = 2/5

Remainder = 1 - 2/5 = 3/5

She then spent 1/6 of the remainder on a bag

Amount Spent = 1/6  *  3/5 = 1/2  *  1/5  = 1 /10

Total amount spent = 2/5 + 1 /10 =   (4 + 1 ) / 10 = 5 / 10 = 1 / 2

Amount left = 1 - 1 /2 = 1 / 2

The acetic acid solution will have a lower concentration than the NaOH solution.

This is because when carrying out a titration, the goal is to add a known amount of a reagent, in this case NaOH, to a solution of unknown concentration, in this case acetic acid.

When the endpoint of the titration is reached, the amount of NaOH added is proportional to the molarity of the acetic acid solution. Therefore, if the coarse titration volume is higher, then the concentration of the acetic acid solution must be lower than the concentration of the NaOH solution.

Additionally, the volume of NaOH needed to reach the endpoint is greater when the concentration of acetic acid is lower. Thus, based on the coarse titration volume, we can expect the acetic acid solution to have a lower concentration than the NaOH solution.

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If large amounts of sulfate are present during methane production, the contaminant that may accompany methane production is hydrogen sulfide (H2S).

If large amounts of sulfate are present during methane production, the contaminant that may accompany methane production is hydrogen sulfide (H2S).

Sulfate-reducing bacteria (SRB) can convert sulfate to hydrogen sulfide during the anaerobic decomposition of organic matter in the presence of methane-producing bacteria. This process is known as anaerobic sulfate reduction, and it is commonly used in the production of biogas (which is mainly composed of methane). However, the presence of hydrogen sulfide in biogas can be problematic as it is toxic, corrosive, and can cause odor issues.

Therefore , biogas producers  often take steps to remove hydrogen sulfide from the biogas before it is used or sold.

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The following is true of pericyclic reactions: D. All of these statements are true of pericyclic reactions. The correct option is D.

Pericyclic reactions are a class of organic reactions that involve the simultaneous rearrangement of sigma bonds and pi bonds in a cyclic transition state. These reactions exhibit several characteristic features.

A. They are concerted reactions: Pericyclic reactions occur in a single step, without the formation of any intermediates. The reactants rearrange their bonds simultaneously to form the products.

B. They proceed via a cyclic transition state: During the reaction, the reactant molecules pass through a cyclic transition state where the rearrangement of bonds takes place. This cyclic transition state is often visualized as a ring-shaped structure.

C. No intermediates are formed: As pericyclic reactions are concerted, they do not involve the formation of any intermediates along the reaction pathway.

Therefore, all of these statements are true of pericyclic reactions. They are concerted, proceed via a cyclic transition state, and do not involve intermediates. These characteristics make pericyclic reactions distinct from stepwise reactions that involve the formation of intermediates. The correct option is D.

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Answer:

It is important to note that iron, cobalt, and nickel which appear in period 4, of the transition metals, next to each other, share very similar physical and chemical properties and are known collectively as the iron triad

The comparison of the properties of iron includes

Chemical properties

1) Atomic number; The atomic number of iron is 26 while the atomic number of nickel is 28

2) The oxidation states of iron are 2, 3, 6 while the oxidation state of nickel are 2,3

3) The ionization energies in kJ/mol  are first 759, second 1561, and third 2957 for iron and first 737, second 1753, and third 3393 for nickel

Physical properties

1) The mass of iron is 55.85 with density = 7.87 g/cm³, the mass of nickel is 58.69 with density = 8.91 g/cm³

2) The melting point of iron is 1530°C, boiling point 2862°C and that of nickel are 1455°C and 2732°C

3) The electrical conductivity of iron is 16 and that of nickel is 23

Explanation:

Answer:

???

Explanation:

Answer:

5

Explanation:

The refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.

To calculate the kilowatt-hours (kWh) of electric energy used by the refrigerator in 30 days, we need to multiply the power rating by the total running time.

Given:

Power rating of the refrigerator = 500 W

Running time per day = 12 hours

Number of days = 30

First, we need to convert the power rating from watts to kilowatts:

Power rating = 500 W / 1000 = 0.5 kW

Next, we calculate the total energy used in kilowatt-hours (kWh) over the 30-day period:

Energy used = Power rating × Running time × Number of days

Energy used = 0.5 kW × 12 hours/day × 30 days

Energy used = 180 kWh

Therefore, the refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.

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In the redox reaction represented by the cell notation sn(s) | sn2(aq) || ag(aq) | ag(s), the oxidizing agent is the species that gets reduced. In this case, the silver ions (Ag+) are being reduced to silver atoms (Ag). Therefore, the oxidizing agent is the silver ions.

To determine the oxidizing agent, you need to identify the species that undergoes reduction. In the given reaction, silver ions gain electrons to form silver atoms. This reduction process indicates that the silver ions are accepting electrons and are acting as the oxidizing agent.

In a redox reaction, the oxidizing agent is always the species that gets reduced, as it accepts electrons from the reducing agent. This transfer of electrons between species is what drives the redox reaction.

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The third law of thermodynamics will allow by the absolute entropies of the substances to be determined by a reference point by which entropy will changes can be measured and assigned an absolute entropy for the substance.

The third law of thermodynamics states that the entropy of an system approaches a constant value as the temperature approaches absolute zero. The entropy of a system at absolute zero is typically zero, and in all the cases it is determined only by the number of different ground states it has.

Consequences: It defines the sign of the entropy of any of the substance at temperatures above absolute zero as positive, and it provides a fixed reference point that allows us to measure the absolute entropy of any of the substance at any temperature.

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Answer:

Answer one:
Solute particles block some of the ability of liquid particles to evaporate. We can then conclude, solutions of solid solutes typically have a lower vapor pressure than pure solvents.

Answer two:
Solutions freezing points are lower than of the pure solvent or solute because freezing (becoming a solid) creates order and decreases entropy.

Answer three:
The presence of solute particles decreases the vapor pressure of the liquid solvent, this means a higher temperature is needed to reach the boiling point.

Explanation:

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helium is in group 8 and period 1

Answer:

I'd say Water

Explanation:

The plant absorbs more water through the roots not sure if i'm correct.

As atomic radius decreases, electronegativity increases. This is mostly because a smaller atomic radius represents a stronger hold on the valence electrons.

The carbon-nitrogen-oxygen (CNO) cycle in high-mass main-sequence stars burns hydrogen to helium in their cores.

In high-mass main-sequence stars, such as massive stars with a mass greater than about 1.5 times that of the Sun, the primary nuclear reaction that powers their cores is the carbon-nitrogen-oxygen (CNO) cycle. This cycle converts hydrogen nuclei (protons) into helium nuclei (alpha particles) through a series of fusion reactions.

The CNO cycle involves the catalytic action of carbon, nitrogen, and oxygen isotopes. In the first step of the cycle, a proton fuses with a carbon-12 nucleus to produce nitrogen-13 and release a gamma ray. Nitrogen-13 then undergoes beta decay, converting a proton into a neutron and transforming into carbon-13. Carbon-13 can capture another proton, forming nitrogen-14. Nitrogen-14 can further undergo fusion reactions with other protons to produce oxygen-15 and eventually return back to carbon-12, completing the cycle.

Overall, the CNO cycle allows high-mass main-sequence stars to convert hydrogen into helium, releasing energy in the process and sustaining the star's energy production.

What elements does the carbon-nitrogen-oxygen (CNO) cycle in high-mass main-sequence stars burn in their cores?

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The correct answer is C. Climate change

Explanation:

Long-term environmental changes occur as major events affect the environment and ecosystems indefinitely. These events differ from short-term environmental changes because the effect of short-term environmental changes is mainly temporary. Also, long-term changes are usually gradual.

Climate change is an example of long-term environmental changes because this implies indefinite and major changes in weather patterns and ecosystems. For example, it is believed climate change will decrease the amount of ice in Earth, change sea level, and lead to the extinction of dozens of species. This does not occur with events such as el niño or a small asteroid impact that affect the environment for a short time and do not imply major changes.

Answer:

it is c) climate change

Explanation:

i just took the quiz

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