How much heat has been lost when a 78 g piece of copper is placed into a calorimeter and cools from 120°C to
40°C ? Copper's specific heat capacity is 0.385 J/ 3°C.
2,402.4 J
O-1201.23
1,201.23
0-2,402.4
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2. Aldabad

Answer:

365 mL

Explanation:

There are 1,000 mL per every 1 L. As such, to convert between the two measurements, you need to multiply the given volume (0.365 L) by the conversion. To allow for the cancellation of units (liters), liters should be in the denominator of the conversion.

1,000 mL = 1 L

 0.365 L            1,000 mL
----------------  x  -----------------  = 365 mL
                               1 L

In the balanced equation \(2C_{2} H_{6}\) + \(7 O_{2}\) --> \(4 CO_{2}\) + \(6H_{2}O\) if 21 g of \(C_{2} H_{6}\) reacts with 32 g O₂, C₂H6 is the limiting reactant.

To determine the limiting reactant, we need to compare the amount of each reactant to the stoichiometric ratio in the balanced equation.

Let's calculate the number of moles for each reactant using their molar masses:

For \(C_{2} H_{6}\) (ethane):

Molar mass of \(C_{2} H_{6}\) = 2(12.01 g/mol) + 6(1.01 g/mol) = 30.07 g/mol

Number of moles of C₂H6 = 21 g / 30.07 g/mol ≈ 0.698 mol

For O₂ (oxygen):

Molar mass of O₂ = 2(16.00 g/mol) = 32.00 g/mol

Number of moles of O₂ = 32 g / 32.00 g/mol = 1.00 mol

Next, we compare the moles of each reactant to the stoichiometric ratio in the balanced equation:

2 moles of \(C_{2} H_{6}\) react with 7 moles of O₂ to produce 4 moles of CO₂ and 6 moles of H₂O.

From the given amounts, we have:

0.698 mol \(C_{2} H_{6}\) and 1.00 mol O₂.

Using the stoichiometric ratio, we can calculate the expected amount of CO₂ and H₂O produced for each reactant:

For C₂H6:

Expected moles of CO₂ = 0.698 mol C₂H6 * (4 mol CO₂ / 2 mol C₂H6) = 1.396 mol CO₂

For O₂:

Expected moles of CO₂ = 1.00 mol O₂ * (4 mol CO₂ / 7 mol O₂) ≈ 0.571 mol CO₂

Comparing the expected moles, we see that the calculated amount of CO₂ is greater when used \(C_{2} H_{6}\) as the limiting reactant. Therefore, the limiting reactant in this reaction is \(C_{2} H_{6}\).

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If the caffeine concentration in a particular brand of soda is 2.99 mg/oz, drinking, The number of cans of soda would be lethal is 258 cans.

Caffeine is a stimulant. In the brain, it blocks the effects of a chemical called adenosine, which makes you feel sleepy. we then feel more alert and energetic, which is why many people drink soda, coffee or tea to stay awake. Caffeine may keep you awake even if you don't want it to

Given

v = 10 000/3.23 =3095.96 oz

Therefore,

Number of cans = 3095.96 /12 =258 cans

If the caffeine concentration in a particular brand of soda is 2.99 mg/oz, drinking, The number of cans of soda would be lethal is 258 cans.

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The total amount of hydrogen gas generated is 9.76 L, under the condition that 15.9 g of hydrochloric acid reacts with excess zine metal.

Furthermore the balanced chemical equation for the reaction between hydrochloric acid and zinc metal is:
2HCl + Zn → ZnCl₂ + H₂
The molar mass of HCl is 36.46 g/mol.
Then, 15.9 g of HCl is equivalent to 15.9 g / 36.46 g/mol = 0.436 mol of HCl.
As per  the balanced chemical equation, 1 mole of HCl reacts with 1 mole of Zn to produce 1 mole of H₂ gas.
Hence, 0.436 mol of HCl will produce 0.436 mol of H₂ gas.
In Stp (Standard Temperature and Pressure), one mole of any gas occupies 22.4 L.
So, 0.436 mol of H₂ gas will occupy:
0.436 mol × 22.4 L/mol = 9.76 L (approx)
Then, approximately 9.76 L of hydrogen gas will be produced when 15.9 g of hydrochloric acid reacts with excess zinc metal at STP.
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When an alarm sounds in the laboratory, it is important to respond quickly and remain calm. Listen for any other instructions, turn off any equipment in use, and be prepared to leave immediately.

What is laboratory?

Laboratory is a place where scientific experiments and measurements are performed. It is equipped with various types of equipment and instruments to carry out experiments and tests. Laboratories are usually used by scientists and technicians to conduct experiments, analyze samples, and conduct research. It is an area that is designed to be kept clean and organized in order to ensure safety and accuracy when conducting experiments. Laboratories can be found in many different settings such as hospitals, universities, research and development centers, and manufacturing facilities.

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The expression 7.0x\(10^7\) ÷ 2.0x\(10^4\) can be expressed in proper scientific notation as 3.5x10^3.

To express the division 7.0x\(10^7\) ÷ 2.0x\(10^4\) in proper scientific notation, we need to perform the division and adjust the result to the appropriate format.

Dividing the numbers, we get:

7.0x\(10^7\) ÷ 2.0x\(10^4\)= 3.5x\(10^{(7-4)\)= 3.5x\(10^3\)

The result of the division is 3.5, and we adjust the exponent by subtracting the exponent of the divisor from the exponent of the dividend (7 - 4 = 3).

Therefore, the proper scientific notation representation of the division 7.0x\(10^7\) ÷ 2.0x\(10^4\) is 3.5x\(10^3\).

Scientific notation is a way to express numbers using a coefficient (in this case, 3.5) multiplied by a power of 10 (in this case, 10^3). It allows for more concise representation of very large or very small numbers.

In this case, the division resulted in a number that is smaller than the dividend and has a positive exponent, indicating a smaller magnitude compared to the original numbers. The coefficient represents the significant digits of the result, while the power of 10 represents the scale or magnitude of the number.

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Answer:

Krypton

Explanation:

Answer:

C

Explanation:

trust me :)

Answer:

mitochondria are present in the cells of all types of aerobic organisms like plants and animals, whereas Chloroplast is present in green plants and some algae, protists like Euglena. Mitochondria is the colourless, bean shape organelles. Chloroplasts are green colour and disc shape organelles.

Explanation:

Answer:

"At the top of the first and tallest hill, your potential energy is at its highest it will ever be on this ride. As you begin to descend, your potential energy decreases until it's all gone at the bottom of the hill." The shorter the hill the roller coaster climbs, the greater its kinetic energy.

Conduction is the transfer of thermal energy through direct contact. Convection is the transfer of thermal energy through the movement of a liquid or gas.

So I think you should go with the 3rd option.

Hope this was helpful.

Answer:

What the other guy said

Explanation:

Answer:

A

Explanation:

nitrogen has the similar properties because carbon is the opposite of oxygen

I believe the answer is B, neutrons

Answer:

less than 4.9 newtons Explanation:

The 107 moles of electrons are needed to produce 53.5 mol of solid zinc.

The electron is a subatomic particle that contains a negative elementary charge. The electron's mass is approximate 1/1836th that of the proton and has an intrinsic angular momentum of a half-integer value. No two electrons can have the same quantum state.

An electron is bounded to the nucleus of an atom by the attractive Coulomb force. If the number of electrons differs from the nucleus's electrical charge is known as an ion. Each orbital has a unique set of quantum numbers that exist around the nucleus of an atom.

Solid zinc can be formed by chemical reactions:

Zn²⁺  +  2e⁻   →  Zn (s)

One mole of zinc is produced when two moles of electrons are accepted by one mole of zinc ions

One mole of solid zinc is produced from electrons = 2 moles

The 53.5 mol of zinc will be produced from electrons = 2 × 53.5 = 107 mol

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Answer:

Temperature and Heat

Explanation:

Proportional to the average kinetic energy of the molecules in a substance.

Answer: B. Metallic Bonds, Hydrogen Bonds, Van der Waals forces, Ionic Bonds

Explanation:

The types of forces from weakest at the top to strongest at the bottom is  metallic Bonds, hydrogen bonds, van der waals forces, ionic Bonds. Therefore, option B is correct.

Chemical bonds known as metallic bonds are produced by the electrostatic attraction of positively charged metal ions and conduction electrons. A structure of positively charged ions may be thought of as sharing free electrons.

Metal atoms form metallic connections. Ionic bonds link metals to non-metals, whereas metallic bonds link many metal atoms. Metallic bonding can be observed in action on copper wires and sheets of aluminum foil.

While nonmetal bonds among themselves are often covalent, those between metals and nonmetals are typically ionic. However, the contact involved has a distinct character and is known as metallic bonding in compounds that only include metal atoms.

Thus, option B is correct.

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Answer:

not enough information: picture

Explanation:

I'm sorry:(

Answer:

Trend Line Graph.

The graph highlights two other points on the trend line. Use them to find another equation for the trend line shown for this scatterplot.

✔ y = 82x + 998

Explanation:

The complete Lewis electron-dot diagram for ethyne is shown in the attached diagram below:

A lewis electron dot structure can be utilized to represent the number of bonds, the lone pairs left in the atoms, and the bonding atoms in the molecule.

Solid lines are used to represent the bonds between atoms that are directly bonded to one another and excess electrons are denoted as dot pairs and are represented next to the atoms.

As the valence electrons of each carbon atom are equal to 4 from the electronic configuration of the carbon atom. First, the total number of valence electrons in a molecule is 4 + 1 + 1 + 4 = 10.

As each carbon atom needs only 4 electrons to complete its octet. As the octet completes, the rest of the electrons are assigned as the lone pairs of atoms. But there are no lone pairs in the molecule of the ethyne.

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Answer:

Volume of stock solution needed = 6.0299 mL

Explanation:

Dilution consists of lowering the amount of solute per unit volume of solution. It is achieved by adding more diluent to the same amount of solute.

This is deduced when thinking that both the dissolution at the beginning and at the end will have the same amount of moles.

Data:

M1 = 6.01 M stock solution concentration

M2 = 0.3624 M diluted solution concentration

V2 =100 mL diluted solution volume

V1 = ? stock solution volume

M1 * V1 = M2 * V2

\(V1=\frac{M2*V2}{M1} =\frac{0.3624M*100mL}{6.01M} =6.0299 mL\)

Answer:

B

Explanation:

please mark me brainliest and 5 star

happy Christmas

Answer:

0.246 M

Explanation:

The reaction that takes place is:

First we calculate how many HCl moles reacted, using the given volume and concentration:

Then we convert HCl moles into Sr(OH)₂ moles, using the stoichiometric coefficients of the balanced reaction:

Finally we calculate the concentration of the original Sr(OH)₂ solution:

Answer:

C4H9

Explanation:

If H = 15.88%

Then C = 100.00 – 15.88 = 84.12

Divide each % value by respective atomic mass

H = 15.88/1 = 15.88

C = 84.12/12 = 7.01

Divide through by smaller value

H = 15.88/7.01 = 2.26

C = 7.01/7.01 = 1

Remove fraction , multiply by 4

H = 9

C = 4

Empirical formula = C4H9

The hydrocarbon could be ( C4H9)2 = C8H18 = octane.

Explanation:

Dilution refers to the process of preparing a lower concentration solution from higher concentrations. Thus, the volume of the solution of interest is combined with the appropriate volume of solvent, reaching the desired concentration.

Therefore, the dilution factor is the total number of volumes your material will be dissolved in.

Dilution solutions are a necessary process in the laboratory, as stock solutions are often purchased and stored in very concentrated forms.

In order for solutions to be used (in a titration, for example), they must be precisely diluted, obtaining a known, lower concentration.

The preparation of solutions from liquid solute should follow the following order:

1. Measure the solute volume;

2. Quantitatively transfer to the volumetric flask;

3. Makeup to volume with solvent;

4. Homogenize the solution;

5. Store the solutions in suitable, labeled containers.

Answer: 1. Measure the solute volume;

2. Quantitatively transfer to the volumetric flask;

3. Makeup to volume with solvent;

4. Homogenize the solution;

5. Store the solutions in suitable, labeled containers.

Some types of solids that are insoluble in water are:

Many solids are insoluble in water, meaning they do not dissolve in water to a significant extent. Here are some examples of common solids that are generally insoluble in water:

Metals: Most metals, such as gold, silver, platinum, and copper, are insoluble in water.

Non-Metallic Elements: Many non-metallic elements, such as carbon (in the form of graphite or diamond), sulfur, phosphorus, and iodine, are insoluble in water.

Metal Oxides: Some metal oxides, particularly those of less reactive metals, are insoluble in water. Examples include aluminum oxide (Al2O3), iron(III) oxide (Fe2O3), and lead(II) oxide (PbO).

Metal Carbonates: Most metal carbonates are insoluble in water. Examples include calcium carbonate (CaCO3), lead(II) carbonate (PbCO3), and copper(II) carbonate (CuCO3).

Metal Sulfides: Many metal sulfides are insoluble in water. Examples include lead(II) sulfide (PbS), silver sulfide (Ag2S), and mercury(II) sulfide (HgS).

Insoluble Salts: Certain salts have limited solubility in water. Examples include silver chloride (AgCl), lead(II) iodide (PbI2), and calcium sulfate (CaSO4).

It's important to note that while these solids are generally insoluble in water, they may exhibit some solubility to a small extent. The solubility of a solid in water can vary depending on factors such as temperature, pressure, and the presence of other solutes.

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In this question, we have the following reaction:

2 H2 + O2 -> 2 H2O

At STP (standard temperature and pressure), 1 mol of gas is equal to 22.4 Liters of volume, and also equal to 6.022*10^23 molecules or particles, and this is the Avogadro's constant number. For our question, we have 2 moles of H2, 1 mol of O2 and 2 moles of H2O, according to this, we will have:

1.204*10^24 molecules of H2

2 moles of H2

44.8 L of H2

6.022*23 molecules of O2

1 mol of O2

22.4 L of O2

1.204*10^24 molecules of H2O

2 moles of H2O

44.8 L of H2O

Answer:

because of the substance contained in a fire extingudher it woulfnt start a fire.

Look at my screenshot:

The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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Answer:

Molar mass of the unknown gas is 64.6 g/mol

Explanation:

Let's think this excersise with the Ideal Gases Law.

We start from the N₂. At STP conditions we know that 1 mol of anything occupies 22.4L.

We apply: P . V = n . R . T

5 atm . V = 1 mol . 0.082 . 325K

V = (1 mol . 0.082 . 325K) / 5 atm = 5.33 L

It is reasonable to say that, if we have more pressure, we may have less volume.

As this is the volume for 1 mol of N₂, our mass is 28 g. Then, the density of the nitrogen and the unknown gas is 28 g/5.33L = 5.25 g/L

Our unknown gas has, this density at 27°C and 2 atm.

If we star from this, again: 1 mol of any gas occupy 22.4L at STP, we can calculate the volume for 1 mol at those conditions:

P₁ . V₁ / T₁ = P₂ . V₂ / T₂

1 atm . 22,4L / 273K = 2 atm . V₂ / 300K

Remember that the value for T° is Absolute (T°C + 273)

[ (1 atm . 22.4L / 273K) . 300K] / 2 atm = V₂ → 12.3L

This is the volume for 1 mol of the unknown gas at 2 atm and 27°C

We use density to determine the mass: 12.3 L . 5.25 g/L = 64.6 g

That's the molar mass: 64.6 g/mol

Answer

The millimeter is the smallest line (subdivision) on the meter stick.

This means the millimeter is the unit of the smallest reading that can be made without estimating.