how many protons does gold have

Answer:

Friction always slows a moving object down. ... Friction can be a useful force because it prevents our shoes slipping on the pavement when we walk and stops car tyres skidding on the road. When you walk, friction is caused between the tread on shoes and the ground. This friction acts to grip the ground and prevent sliding.

Answer: 7.81 mol HgO (How many moles of mercury(II) oxide, HgO, are needed to produce 125 g of oxygen, O2?)

Explanation:

The example that is nonpolar is d. a molecule with no partial charges.

When the charges of the molecule are symmetrical and there are no partial charges, it indicates that the molecule is nonpolar.

Polar molecules have partial positive and negative charges on either end of the molecule.

This occurs as a result of the polarity of the molecule, which is created by the difference in electronegativity between the two atoms forming the bond.

The charge distribution on the molecule is unbalanced due to this polarity, with the electron density more concentrated around the more electronegative atom.

The measurement of the polarity of a molecule is based on the difference in electronegativity between the two atoms forming the bond.

The polarity of a molecule can be determined using various methods, including the dipole moment method, which measures the magnitude of the dipole moment of the molecule.

The dipole moment measures the charge distribution in the molecule and is measured in Debye (D) units, where 1 D = 3.336 × 10-30 Cm.

In conclusion, a molecule with no partial charges is nonpolar.

The other options such as a negative ion, a neutral ion, and a positive ion are polar molecules as they have partial charges on either end of the molecule.

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Answer:

Water

Explanation:

hope that helps:)

The Bradford assay, we typically use Coomassie Brilliant Blue dye to detect and quantify protein concentration in a sample. This dye binds to amino acid residues in proteins and results in a color change that can be measured spectrophotometrically.

 The Bradford assay, the dye used is called Coomassie Brilliant Blue G-250. This dye interacts with proteins, allowing for the quantification of protein concentrations in a sample. The absorbance of the resulting protein-dye complex can be measured to determine the protein concentration based on a standard curve.The Bradford assay is based on the use of the dye Coomassie Brilliant Blue G-250, which is frequently abbreviated as Coomassie G-250 or Coomassie Blue. This is one of two Coomassie dyes that are often confused.

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The refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.

To calculate the kilowatt-hours (kWh) of electric energy used by the refrigerator in 30 days, we need to multiply the power rating by the total running time.

Given:

Power rating of the refrigerator = 500 W

Running time per day = 12 hours

Number of days = 30

First, we need to convert the power rating from watts to kilowatts:

Power rating = 500 W / 1000 = 0.5 kW

Next, we calculate the total energy used in kilowatt-hours (kWh) over the 30-day period:

Energy used = Power rating × Running time × Number of days

Energy used = 0.5 kW × 12 hours/day × 30 days

Energy used = 180 kWh

Therefore, the refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.

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MOG-AB associated demyelinating disease is a condition that resembles typical multiple sclerosis (MS) but involves the presence of anti-MOG antibodies.

Expanding anti-MOG testing is crucial in diagnosing and managing MOG-AB associated demyelinating disease for several reasons. Firstly, distinguishing this condition from typical MS is essential as their treatment approaches differ. While typical MS is primarily managed with disease-modifying therapies, MOG-AB associated demyelinating disease often requires immunosuppressive agents to target the pathogenic antibodies. Accurate diagnosis prevents unnecessary treatments and improves patient outcomes.

Additionally, MOG-AB associated demyelinating disease can manifest with atypical clinical features and different radiological patterns compared to typical MS. Therefore, comprehensive testing for anti-MOG antibodies helps identify patients who may benefit from alternative diagnostic and therapeutic strategies.

Furthermore, recognizing the presence of anti-MOG antibodies aids in predicting disease course and prognosis. Patients with MOG-AB associated demyelinating disease may have a higher likelihood of relapses and optic neuritis but a lower risk of developing long-term disability compared to MS patients. Tailoring management plans based on this information allows for personalized care.

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To increase the equilibrium constant (K) of a reaction by a factor of 10, the change in Gibbs free energy (ΔG°) must decrease by approximately 5.708 kcal/mol. Whereas, the change in entropy (ΔS°) must increase by approximately 14.15 J/mol K.

This can be achieved by adjusting the reaction conditions or altering the concentrations of reactants and products.

If the change in entropy (ΔS°) is zero and the equilibrium constant of a reaction at 25°C is increased by a factor of 10, the change in enthalpy (ΔH°) must change by approximately 1.364 kcal/mol.

This implies a shift in the energy balance of the reaction, which can be influenced by adjusting temperature or introducing catalysts.

If the change in enthalpy (ΔH°) is zero and the equilibrium constant of a reaction at 25°C is increased by a factor of 10, the change in entropy (ΔS°) must increase by approximately 14.15 J/mol K.

This suggests that the reaction becomes more disordered or has an increased number of possible microstates, leading to a higher entropy value.

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Answer:

n nnjhuig

Explanation:

bjbhvucvcg

Answer:

This can be found by my multiplying number of moles with avogadro number

So we have:

2.5 × 6.022 × 10²³

= 15.055 × 10²³

Therefore there are 15.055 × 10²³ atoms in 2.5 moles of Aluminium

Answer:

i think it is..... smaller than normal range of highs and low tides  

Moon and Sun are at right angles to the Earth

Explanation:

Moon and Sun are at right angles to the Earth and gravity of the Sun and Moon work against is the right statement about NEAP tides.

Tides are the cyclic deformation of water body occur due to external gravitational force.

NEAP tides are also known as small tides as their heights are not very much and this is occur due to opposite attraction of water towards the gravity of the sun and moon. As sun and moon are present in the right angle direction with respect to the earth.

Hence, option (1) & (2) is correct, i.e. gravity of sun and moon is opposite and they are present at the right angle to the earth.

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After isolating a gram-positive rod, the next step would be to perform additional tests to identify the exact species of the rod. Some tests that can be conducted include catalase test, oxidase test, and biochemical tests like API systems or Vitek systems.

These tests help to determine the metabolic properties of the bacteria, allowing for a more accurate identification. Once the species is identified, further tests can be conducted to determine its susceptibility to antibiotics and other treatments. It is important to identify the species accurately as some gram-positive rods can be pathogenic and cause infections in humans and animals.

After isolating a gram-positive rod, the next steps involve performing additional tests to identify the specific bacterium. Start with a catalase test to differentiate between catalase-positive and catalase-negative bacteria. If positive, conduct tests such as coagulase and mannitol fermentation to distinguish between species like Staphylococcus. If negative, proceed with a spore stain and tests like hemolysis patterns on blood agar to differentiate between Streptococcus and other gram-positive rods like Bacillus or Clostridium. Finally, use biochemical tests, such as carbohydrate fermentation and API strips, to confirm the bacterial identification.

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The partial pressure of carbon dioxide ( Pco₂ ) in the alveoli is affected by several factors.  increase Pco₂ , decrease alveolar ventilation and same metabolism and vice versa is hypoventilation. decrease Pco₂ is hyperventilation. no change in Pco₂,breathing air with low amount of Pco₂

The partial pressure of carbon dioxide is affected by :

The  increase Pco₂ :decrease alveolar ventilation and the unchanged metabolism and the vice versa called as hypoventilation.  decrease Pco₂ increase alveolar ventilation and unchanged metabolism and vice versa called as hyperventilation. no change in Pco₂ , breathing air with low amount of Pco₂.

Thus, The partial pressure of carbon dioxide ( Pco₂ ) in the alveoli is affected by several factors. ach of the following conditions as causing an increase, decrease, or no change in alveolar Pco₂ : increase Pco₂ , decrease alveolar ventilation. decrease Pco₂ increase alveolar ventilation. no change in Pco₂ , breathing air with low amount of Pco₂

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Answer:

43.3 L

Explanation:

Applying,

V/T = V'/T'................... Equation 1

Where V = Initial volume of the ball0on, T = Initial temperature of the balloon, V' = Final volume of the balloon, T' = Final Temperature of the balloon.

make V' the subject of the equation

V' = VT'/T................ Equation 2

From the question,

Given: V = 47 L, T = 320 K, T' = 295 K

Substitute these values into equation 2

V' = (47×295)/320

V' = 43.3 L

Answer:

B

Explanation:

Both plain and plateau have flat surfaces. However, a plain is located in a low-lying area while a plateau is located on an elevated area. In essence, a plateau can be viewed as an elevated plain or a plain that is bordered by cliffs.

The correct option is B.

The purpose of adding base in the aldol condensation reaction is c) Deprotonate α-carbon to generate electrophile.

What is aldol condensation?

Aldol condensation is a reaction in organic chemistry that involves the condensation of two carbonyl compounds, typically an aldehyde and a ketone, to form a β-hydroxy carbonyl compound.

In the aldol condensation reaction, a base is added to deprotonate the α-carbon of the carbonyl compound, typically an aldehyde or a ketone. The deprotonation of the α-carbon generates an enolate ion, which is an excellent nucleophile. This deprotonation step is crucial in generating the reactive electrophile necessary for the aldol condensation reaction.

By deprotonating the α-carbon, the base increases the electron density on the carbon atom, making it more nucleophilic and prone to react with another carbonyl compound. This enables the formation of a new carbon-carbon bond, resulting in the formation of an aldol product.

Therefore, the purpose of adding a base in the aldol condensation reaction is to deprotonate the α-carbon and generate an electrophilic enolate ion, which can then react with another carbonyl compound to form the desired product.

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Answer:

D. 108g of water

Explanation:

16g CH4 produces 2(18)g of H20

1g CH4 produces \(\frac{36}{16}\)g of H2O

48g CH4 produces \(\frac{36}{16}\)×48

                                108g of H20

Answer:

D. 108g of water

Explanation:

Answer:

They can be found along the Atlantic coast of the United States.

They experience all four seasons.

Explanation:

The characteristic of temperate broadleaf forests are they can be found along the Atlantic coast of the United States and experience all four seasons.

As the name suggested that temperate broadleaf forests are those forests in which temperature througout the year is moderate and leaf of the tress are broad in shape.

Hence they can be found along the Atlantic coast of the United States and experience all four seasons are the characteristics of this forest.

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Answer:

Definetly Nitrogen

Explanation:

Nitrogen is the most electronegative

Answer:

A. Sympathetic

and

C. Parasympathetic

Explanation:

Ap3x

Answer:

Sand dunes are created when wind deposits sand on top of each other until a small mound starts to form. Once that first mound forms, sand piles up on the windward side more and more until the edge of the dune collapses under its own weight.

The best reagent for each step is NaNH2, NH2 and CH3I, and HBr.

First of all in the presence of strong base ammonia, we het the clcylated product chain elongation gives but-2-ene followed by bromination gives 2-dibromobutane.

Alkyne using NH3 gets converted into Elongated chain alkyne followed by Hbr.

The reaction of bromine with (E)-stilbene is a classic reaction performed as an example of an electrophilic addition reaction of alkenes. The reaction is stereospecific through an anti addition to the double bond. The traditional reaction uses a bromine solution in methylene chloride, which has very high toxcity.

This bromination reaction demonstrates the stereochemistry of the electrophilic addition of bromine to an alkene. The bromine in this greener approach is generated in situ and eliminates the use of methylene chloride.

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To make up 1 L of a 0.5 M solution of EDTA starting with the free acid, the pH must be adjusted to 7.0. EDTA is a weak acid with a pKa of 2.0, 2.67, 6.16, and 10.26 for the four acetic acid groups.

At a pH of 7.0, EDTA will exist in a buffered state, meaning that it will be partially protonated and partially deprotonated.

To adjust the pH of the EDTA solution to 7.0, an alkali solution such as 10 M NaOH must be added. The amount of NaOH required can be calculated using the Henderson-Hasselbalch equation:

pH = pK a + log([base]/[acid])

where [base] is the concentration of the deprotonated form of EDTA and [acid] is the concentration of the protonated form of EDTA.

At a pH of 7.0, the acid-base equilibrium of EDTA will be:

[EDTA-] = [HEDTA]

At this pH, the buffer capacity is high. Since the pKa of EDTA is close to the desired pH, the buffer will resist changes in pH caused by added acids or bases.

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Answer:

A. 8600 J

General Formulas and Concepts:

Thermochemistry

Specific Heat Formula: q = mcΔT

Explanation:

Step 1: Define

[Given] m = 1600 g

[Given] ΔT = 214 °C - 202 °C = 12 °C

[Given] c = 0.450 J/g °C

[Solve] q

Step 2: Find Heat

Step 3: Check

Follow sig fig rules and round. We are given 2 sig figs as our lowest.

8640 J ≈ 8600 J

Topic: AP Chemistry

Unit: Thermodynamics

Answer:

i think 2?

Explanation:

AI2 O2

srry if wrong but

hope this helps

The function of Y would be to keep oxygen-rich blood and oxygen-poor blood separate. The last option is the correct one.

Y is the septum

The septum is a structure of the heart that separates the left atrium from the right atrium as well as the two ventricles.

Thus, the structure prevents oxygenated blood from mixing with deoxygenated blood.

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Answer:

A common effect of UV radiation is erythema or sunburn.

Explanation:

This happens when skin cells are damaged by the absorption of energy from UV rays.

Answer:

A common effect of UV radiation is erythema or sunburn.

Explanation:

This happens when skin cells are damaged by the absorption of energy from UV rays.

Answer:

Explanation:

Combustion of coal releases carbon as CO2. Phytoplankton remove carbon dioxide from the atmosphere by photosynthesis. Carbon is passed along the food chain as fish eat the plants. Penguins feed on the fish, taking in the carbon compounds containing the original carbon atom.

The carbon atoms in coal end up in a penguin due to the process of food chain.

Penguins are aquatic flightless birds that are found in the Southern Hemisphere.

The food chain leads to the carbon atom into the penguin.

The carbon atoms are release from the coal combustion.

The released atoms go into plants leaves.

The herbivorous eat plants.

Then the carnivorous eats the herbivorous.

The carnivorous can be a fish and fish are eaten by penguins.

Thus, in this way, the carbon atoms in coal end up in a penguin due to the process of food chain.

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Answer:

You must change the size of each ingredient by the size of the product. Let's say my recipe calls for 1 bag of flower and 2 eggs. I want to double the amount of product that I make, so I must multiply each of my ingredients by 2. I would now use 2 bags of flower and 4 eggs.