How many of each subatomic particle can be found in an atom of Rubidium-82?Number of Electrons:Number of Protons:Number of Neutrons:

Here, we are required to determine how many electrons are typically involved in bonding for group 1, group 2 and group 3 elements and How many electrons are typically involved in bonding for group 6, 7 and 8 elements.

The Valence electrons are the electrons which are available for bonding and chemical reactions in elements.

The Valence electrons are the electrons which are available for bonding and chemical reactions in elements.However, not all Valence electrons are actively involved in bonding. This is evident in the group 7(halogens) elements, although they have 7 Valence electrons, only one is actively involved in bonding.

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Approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M.

To determine the mass of glucose (C6H12O6) required to prepare a 0.215 M solution in 5000 mL, we need to use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

First, let's convert the volume of the solution from milliliters (mL) to liters (L):

5000 mL = 5000/1000 = 5 L

Now, we can rearrange the formula to solve for moles of solute:

moles of solute = Molarity (M) x volume of solution (L)

moles of solute = 0.215 M x 5 Lmoles of solute = 1.075 mol

Since glucose (C6H12O6) has a molar mass of approximately 180.16 g/mol, we can calculate the mass of glucose using the equation:

mass of solute = moles of solute x molar mass of solute

mass of glucose = 1.075 mol x 180.16 g/mol

mass of glucose = 194.0 g (rounded to three significant figures)

Therefore, approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M. It's important to note that the molar mass of glucose used in this calculation may vary slightly depending on the level of precision required.

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Answer:

because the cells make drugs at the start of injury!

Answer:

a) alternate interior angles are congruent

Explanation:

on edgen

The concentration in weight percent is 40%

The following data were obtained from the question:

Concentration in weight percent = (mass of sugar / total mass) × 100

Concentration in weight percent = (6.000 / 15.000) × 100

Concentration in weight percent = 0.4 × 100

Concentration in weight percent = 40%

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Answer: you have to talk to someone who wont mind wanting to wanting to like you a lot like that.

Explanation:  I wish I could be able to talk to someone who would want to get to like me like that, so its a very relatable situation.

The amount, in mL, of the suspension that should be given to an infant weighing 17 lb will be 1.16 mL

0.8 mL of the liquid contains 80.0 mg of the drug.

The recommended dose is 15 mg per kg of body weight

The infant to be given the drug weighs 17 lb.

First, let's convert the weight of the infant to kg.

1 lb = 453.59 g

17 lb =       453.59 x 17/1

                   = 7711.03 g

1000 g = 1 kg

7711.03 g = 7711.03 x 1/1000

               = 7.711 kg

So, the baby's weight is 7.711 kg.

The drug dose for the baby can thus be calculated as:

15 mg x 7.711 = 115.67 mg

But 0.8 mL of the drug contains only 80.0 mg. How many mL will contain 115.67 mg?

                   0.8 x 115.67/ 80.0 = 1.16 mL

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Answer:

option C : cellular respiration

Explanation:

cellular respiration is taking place in this diagram .

as in respiration food get oxidised to release energy and it releases CO2 and water

Answer:

change in colour , change in temperature , form of bullbes

Explanation:

Answer:

Evolution of gas.

Formation of a precipitate.

Change in color.

Explanation:

Answer:

Physical Properties

Explanation:

PHYSICAL PROPERTY

Answer:

phycical propertys

Explanation:

jut took the test got it right

1.) Chemist needs 79.02 g of KMnO4 to make 4.00 L of a 0.50 M solution. 2.)  You will need to use 0.12 L of 1.50 M solution to make 2.40 L of 0.0750 M solution. 3.) Solution has a molality of 0.00229 mol/kg.

Molality is defined as a measure of number of moles of solute in a solution corresponding to 1 kg or 1000 g of solvent.

1.) As, mass = moles x molar mass

Molar mass of KMnO4 is 158.03 g/mol

So, mass = 0.50 mol x 158.03 g/mol = 79.02 g

Therefore, the chemist needs 79.02 g of KMnO4 to make 4.00 L of a 0.50 M solution.

2.)As , C1V1 = C2V2

Here C1 is initial concentration, V1 is initial volume, C2 is final concentration and V2 is the final volume.

1.50 M x V1 = 0.0750 M x 2.40 L

Now, V1 = (0.0750 M x 2.40 L) / 1.50 M

So, V1 = 0.12 L

You will need to use 0.12 L of the 1.50 M solution to make 2.40 L of the 0.0750 M solution.

3.) Formula for molality is: m = (moles of solute) / (kg of solvent)

As, moles = (mass of solute) / (molar mass of solute)

= (20 g) / (58.44 g/mol) = 0.344 mol

m = (0.344 mol) / (150 g / 1000 g/kg) = 0.00229 mol/kg

So, the solution has a molality of 0.00229 mol/kg.

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The learning activities titled "Hypothesis," "Variables and Hypothesis," and "Constructing a Hypothesis" all share certain similarities and differences. A question that arises in response to an observation is similar to a scientific research question in that both require some level of investigation to achieve an answer. However, scientific research questions are typically more specific and refined, with a defined methodology for obtaining data and verifying results.

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Answer:

Pressure increases as the depth increases. The pressure in a liquid is due to the weight of the column of water above. Since the particles in a liquid are tightly packed, this pressure acts in all directions. For example, the pressure acting on a dam at the bottom of a reservoir is greater than the pressure acting near the top.

Explanation:

Answer:

18 g

Explanation:

We'll begin by converting 500 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

500 mL = 500 mL × 1 L / 1000 mL

500 mL = 0.5 L

Next, we shall determine the number of mole of the glucose, C₆H₁₂O₆ in the solution. This can be obtained as follow:

Volume = 0.5 L

Molarity = 0.2 M

Mole of C₆H₁₂O₆ =?

Molarity = mole / Volume

0.2 = Mole of C₆H₁₂O₆ / 0.5

Cross multiply

Mole of C₆H₁₂O₆ = 0.2 × 0.5

Mole of C₆H₁₂O₆ = 0.1 mole

Finally, we shall determine the mass of 0.1 mole of C₆H₁₂O₆. This can be obtained as follow:

Mole of C₆H₁₂O₆ = 0.1 mole

Molar mass of C₆H₁₂O₆ = (12×6) + (1×12) + (16×6)

= 72 + 12 + 96

= 180 g/mol

Mass of C₆H₁₂O₆ =?

Mass = mole × molar mass

Mass of C₆H₁₂O₆ = 0.1 × 180

Mass of C₆H₁₂O₆ = 18 g

Thus, 18 g of glucose, C₆H₁₂O₆ is needed to prepare the solution.

Answer:

density

Explanation:

density, volume holds fluid, and temperature is negligible

Answer:

False

Explanation:

Answer:

\( {256x}^{4}+{256x}^{3} + {96x}^{2} + 16x + 1 \)

Explanation:

\( {(1 + 4x)}^{4} = (1 + 4x)(1 + 4x)(1 + 4x)(1 + 4x)\)

The coefficient of the kth term (ordering in increasing order for the exponent of x) is just the number of ways we have to choose k factors from that expression, so if we let k be the exponent of x, and n be the total number of terms, the coefficient of x^k is \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \)

Which, of course, we have to multiply for the product of the two terms.

For example, the coefficient of the third grade term in \( {(1+4x)}^{4} \) is \( \binom{4}{3}=4\)

So we have \( {(1 + 4x)}^{4} = \binom{4}{4} \cdot {(4x)}^{4}+\binom{4}{3} \cdot {(4x)}^{3} + \binom{4}{2} \cdot {(4x)}^{2} + \binom{4}{1} \cdot 4x + \binom{4}{0} \cdot 1 \)

Which is equal to \( 1 \cdot {(4x)}^{4}+4 \cdot {(4x)}^{3} + 6 \cdot {(4x)}^{2} + 4 \cdot 4x + 1 \cdot 1 = {256x}^{4}+{256x}^{3} + {96x}^{2} + 16x + 1 \)

Hope this helps :)

The pressure of the gas when the temperature changes from -75.0°C to 1000.0°C will be approximately 9.51 atm.

Gay-Lussac's law states that the pressure exerted by a given quantity of gas varies directly with the absolute temperature of the gas.

It is expressed as;

P₁/T₁ = P₂/T₂

Given that:

We substitute our values into the expression above.

P₁/T₁ = P₂/T₂

P₁T₂ = P₂T₁

\(P_2 = \frac{P_1T_2}{T_1}\\ \\P_2 = \frac{1.480\ *\ 1273.15 }{198.15} \\\\P_2 = 9.51 \ atm\)

Therefore, the final pressure is 9.51 atm.

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Answer:

Pentane » Hexane » Hexanol

Explanation:

Pentane and Hexane are simple molecular structured with discrete molecules having weak vanderwaals forces of attraction. But Hexane has high molecular mass than pentane hence pentane has lower boiling point than Hexane.

Hexanol has hydrogen bonds between highly electronegative oxygen atom and the hydrogen atom which break on high heat energy application hence it has high boiling point.

The net ionic equation for the reaction between aqueous sodium fluoride and hydrochloric acid is H+(aq) + F- (aq) → HF (g)

The ions in an aqueous solution that are created when chemicals are dissociated are represented by the ionic reaction equation. The cations and anions dissociating from the appropriate molecule or chemical is how the ionic reaction is demonstrated.

The ionic equation for the reaction between aqueous sodium fluoride (NaF) and hydrochloric acid (HCl) is:

NaF(aq) + HCl(aq) → NaCl(aq) +HF(g)

Another way to write it is,

Net ionic equation: H+(aq) + F- (aq) → HF (g)

This is a neutralization reaction, in which an acid (HCl) and a base (NaF) react to form a salt (NaCl) and water (HF). In this case, the hydrogen ion (H+) from the hydrochloric acid reacts with the fluoride ion (F) from the sodium fluoride to form hydrogen fluoride gas (HF), and the sodium and chloride ions remain in solution as the salt sodium chloride (NaCl).

So, the net ionic equation is H+(aq) + F- (aq) → HF (g).

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Answer:No, it is He

Mark me brainlieist

Answer:

c. or b._____________

Explanation:

correct me

Answer:

Tetrahedral

Explanation:

The molecular geometry of SiCl₄ is a tetrahedral shape. According to the VESPR molecular theory, the compound has a shape of a tetrahedron.

(A) Possible Galvanic cells:

Li(s) | Li+ solution || H+ solution | H2(g) | Pt(s)

Half-cell reactions: Li(s) → Li+(aq) + e-; 2H+(aq) + 2e- → H2(g)

Overall reaction: 2Li(s) + 2H+(aq) → 2Li+(aq) + H2(g)

Eºcell = -3.04 V

Zn(s) | Zn2+ solution || H+ solution | H2(g) | Pt(s)

Half-cell reactions: Zn(s) → Zn2+(aq) + 2e-; 2H+(aq) + 2e- → H2(g)

Overall reaction: Zn(s) + 2H+(aq) → Zn2+(aq) + H2(g)

Eºcell = -0.76 V

Zn(s) | Zn2+ solution || O2(g) | H2O(l) | Pt(s)

Half-cell reactions: Zn(s) → Zn2+(aq) + 2e-; O2(g) + 4H+(aq) + 4e- → 2H2O(l)

Overall reaction: Zn(s) + O2(g) + 4H+(aq) → Zn2+(aq) + 2H2O(l)

Eºcell = 1.56 V

(B) The most powerful reducing agent is the one with the lowest Eo value, indicating the greatest proclivity to lose electrons and experience reduction. Based on the Galvanic cells, Li has the most negative Eo value (-3.04 V), making it the most powerful reducing substance.

(c). we can use Faraday's laws of electrolysis to calculate the current and the amount of H₂ gas produced:

Calculate the number of electrons transferred:

From the balanced reaction, we see that 2 moles of electrons (4 e⁻) are transferred for each mole of H₂ produced.

The mass of Zn consumed in 2 hours is 50 g, which is equivalent to 50/65.38 = 0.765 moles of Zn (where 65.38 g/mol is the molar mass of Zn).

Therefore, the total number of electrons transferred is 4 x 0.765 = 3.06 moles of electrons.

Calculate the current:

Faraday's first law states that the amount of chemical change in an electrolytic cell is proportional to the amount of electricity that flows through the cell.

The proportionality constant is the Faraday constant, which is equal to 96,485 C/mol e⁻.

Therefore, the total charge (Q) required to transfer 3.06 moles of electrons is:

Q = 3.06 x 96,485 = 295,038 C

The time (t) taken for this charge to flow through the circuit is 2 hours = 7,200 seconds.

Therefore, the current (I) is:

I = Q/t = 295,038/7,200 = 40.97 A

Calculate the amount of H₂ gas produced:

From the balanced reaction, we know that 1 mole of H₂ gas is produced for every 2 moles of electrons transferred.

Therefore, the number of moles of H₂ gas produced is:

0.765 moles of Zn x (1 mole of H₂/2 moles of electrons) = 0.383 moles of H₂ gas

The molar mass of H₂ is 2 g/mol, so the mass of H₂ gas produced is:

0.383 moles of H₂ gas x 2 g/mol = 0.766 g of H₂ gas

Therefore, the Galvanic cell produces 0.766 g of H₂ gas when it consumes 50 g of Zn metal for 2 hours at a current of 40.97 A.

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Rube Goldberg machines, follows the “law of conservation of energy as it uses a chain reaction to complete a simple task in different manner.

In this machine, various instant kinetic energy is transferred into potential energy and vice-versa, so the total energy remains conserved. Therefore, Rube Goldberg machines follows the law of conservation of energy.

In the machine when marble rolls down from the top it has kinetic energy, the marble hits and falls into a plastic cup, its kinetic energy is then transferred into potential energy that lifts the soda can. Then the potential energy is changed into kinetic energy.

When the marble comes in contact with the next marble, its kinetic energy is transferred to other marble.  

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Answer:

166.56g of NH3 are produced

Explanation:

The reaction of N2 with H2 to produce NH3 is:

N2 + 3H2 → 2NH3

Where 1 mole of N2 produce 2 moles of NH3

4.89 moles of N2 with excess of H2 produce:

4.89 moles N2 * (2 moles NH3 / 1 mole N2) = 9.78 moles NH3

As molar mass of NH3 is 17.031g/mol, mass of NH3 produced is:

9.78 moles * (17.031g / mol) =

Answer: The burning of fossil fuels releases carbon dioxide, methane and other greenhouse gases into the atmosphere. These gases trap heat in the atmosphere, leading to a gradual increase in global average temperatures, known as global warming. This phenomenon has serious impacts on our environment and ecosystems, including extreme weather events and rising sea levels.