How many milligrams are in 6.38 x 10⁻² pounds? 454 g = 1 lb

Answer:

NO ONE DOSE :(

Explanation:

Sodium phosphate is a generic term for a variety of salts of sodium (Na +) and phosphate\((PO _{4 }^{3-} .\))

To make 4.0 L of 0.80 M sodium phosphate, we need to find the volume of 1.0 M sodium phosphate required.

If one gram of solute is able to be dissolved in one liter of solution, then the molarity of the solution is equal to one mole. In a solution, the most crucial thing that happens is that the solute and the solvent mix together to produce the solution.

As a result, the volume of the whole solution is measured out.

The coherent unit for molarity or molar concentration, as defined by the International System of Units (SI), is

We can use the following formula to find the volume of the solution:

M1V1 = M2V2,

where M1 and V1 are the initial molarity and volume of the solution, respectively, and M2 and V2 are the final molarity and volume of the solution, respectively.

Using the above formula:

M1V1 = M2V24.0 L × 0.80 M = M2V2V2 = (4.0 L × 0.80 M) / 1.0 MV2 = 3.2 L

Therefore, the volume of 1.0 M sodium phosphate, to the nearest tenth of a liter, that must be used to make 4.0 L of 0.80 M sodium phosphate is 3.2 L.

The correct option is option D.

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Answer:

N,I and F

hope this helps

Explanation:

The strength and cohesion of clay rich regolith or soil change with the addition of water as the water reduces the strength of clays. So, option (b) is correct.

Clay is defined as a type of fine grained natural soil material which contains clay minerals. It is the oldest known ceramic material. It comes from the ground that usually in areas where streams or rivers are once flowed. Clay is made from minerals, plant life, and animals like all the ingredients of soil. When we add water in the clay it's pressure breaks up the remains of flora, fauna, and minerals, pulverizing them into fine particles. This is the smallest of the three soil particle sizes, sand, silt and clay. These particles are less than 0.002 millimeters in diameter, feels sticky when wet, and can be formed into a ball.

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The correct question is,

How do the strength and cohesion of clay-rich regolith or soil change with the addition of water?

group of answer choices

A. water lowers the strength and cohesion.

B. water reduces the strength of clays but raises the cohesion of the soil.

C. water increases the strength and cohesion.

D. water does not affect the cohesion but lowers the strength.

If 1.2 mol Zn and 5.5 mol HCl combine, with Zn acting as the limiting reactant, 1.2 mol ZnCl2 and 1.2 mol H2 resulting from the reaction.

By dividing the volume of each solution by its molarity, you can get the number of moles of each reactant. By dividing the number of moles of each reactant by its stoichiometric coefficient in the balanced chemical equation, you may determine which reactant is the limiting one.

Reaction stoichiometry

The balanced reaction is:

Zn + 2 HCl → ZnCl₂ + H₂

Zn: 1 mole

HCl: 2 moles

ZnCl₂: 1 mole

H₂: 1 mole

moles of ZnCl₂= (1.2 moles of Zn× 1 mole of ZnCl₂)÷ 1 mole of Zn

moles of ZnCl₂= 1.2 moles

moles of H₂= (1.2 moles of Zn× 1 mole of H₂)÷ 1 mole of Zn

moles of H₂= 1.2 moles

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To create a high pitch or a low pitch sound, the length and frequency of the vibrating object or sound wave are important factors.

More the length = lower frequency = lower pitch

Low Pitch: a low pitch sound is created by a lower frequency of vibrations. In this case, the waves are further apart.

For instance, when you pluck a guitar string loosely, it produces a lower pitch sound because the  vibrations are slower and the waves are spaced farther apart.

Blowing air into a large opening on a tuba or a bass instrument produces a low-pitched sound due to the slower vibrations of the air column.

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Answer:

The RMM of Ca (OH)2 is

40+ (16+1)2

40+(17)2

40+34

74

The RMM of Al2SO4 is

(27×2)+32+(16×4)

54+32+64

=150

Explanation:

Note that the RAM of:

Ca=40

O=16

H=1

Al=27

S=32

The question requires us to calculate the energy, in joules (J), necessary to heat 83.5g of water from 26.7 °C to 75°C.

The heat energy (Q) can be calculated from the mass of the sample (m), its specific heat capacity of the substance (C) and temperature variation (ΔT), as given by the following equation:

Since the question did not provide a value for the specific heat capacity of water, we'll adopt the value 4.182 J/g.°C. Applying the values provided by the question, we can calculate the heat energy as:

Therefore, the heat energy necessary to heat the amount of water given grom 26.7 to 75°C is 1.69 x 10^4 J (or 16900 J).

The missing component in the acid wave process is the activator or the catalyst. The activator is a solution that helps to initiate the chemical reaction between the permanent waving lotion and the hair's proteins.

In detail, the acid wave process is a chemical process that involves the use of an acid-based solution to break down the hair's disulfide bonds, which determine the hair's natural texture and shape. The permanent waving lotion contains an acid (usually glyceryl mono thioglycolate) that softens the hair and makes it pliable. Once the permanent waving lotion has been applied, the activator is added to the hair, which helps to open up the disulfide bonds further.

The activator is usually a solution of hydrogen peroxide or sodium bromate. After a certain amount of time, the hair is rinsed thoroughly to remove any residual permanent waving lotion or activator. Finally, the neutralizer is applied to the hair. The neutralizer (usually ammonium thioglycolate) stops the chemical reaction between the hair and the waving lotion. It helps to restore the hair's pH balance and re-form the disulfide bonds in a new shape.

The neutralizer is left on the hair for a specified amount of time, and then the hair is rinsed and styled. In conclusion, the three components of the acid wave process are the permanent waving lotion, activator, and neutralizer. Each component plays a vital role in breaking down and reforming the disulfide bonds in the hair to create a new texture and shape.

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Answer:

Explanation:

A perfect diamond is a single molecule made of carbon atoms.

DNA is a super long molecule that has information uniquely describing every human being.

When two or more atoms chemically bond together, they form a molecule.

They are very small in size.

They have space between them.

They are in constant random motion.

molecules move when Particles move rapidly in all directions but collide with each other more frequently than in gases due to shorter distances between particles.

In 1926, French physicist Jean Perrin received the Nobel Prize in physics for proving, conclusively, the existence of molecules.

Molecules can exist in free state because they are very stable.

The smallest particle of a compound capable of existing on its own is a Molecule-not a atom.

Hello! HNO2 is not a strong acid so therefore your answer is A.

A rule of thumb, the rest are strong acids, so when you ever come across a similar question you will be able to rule out the wrong answers quicker :).

Strong acid list:

H2SO4

HNO3

HCLO4

HCLO3

HCL

HBr

HI

hope this helps!

20 mL of 0.170 M NaOH solution is required to neutralize 20 mL of 0.170 M HCl solution.

To determine the volume of 0.170 M NaOH solution required to neutralize 20 mL of a 0.170 M HCl solution, we can use the equation:

moles of acid = moles of base

First, let's calculate the number of moles of HCl in 20 mL of the solution:

moles of HCl = (0.170 mol/L) x (20 mL / 1000 mL/L) = 0.0034 mol

Since the neutralization reaction between HCl and NaOH has a 1:1 stoichiometry, we know that 0.0034 mol of NaOH will be required to completely neutralize the HCl.

Next, we can use the concentration of the NaOH solution to determine the volume required:

moles of NaOH = 0.0034 mol

Molarity of NaOH = 0.170 M

Volume of NaOH = moles of NaOH / Molarity of NaOH = 0.0034 mol / 0.170 mol/L = 0.02 L or 20 mL

Therefore, 20 mL of 0.170 M NaOH solution is required to neutralize 20 mL of 0.170 M HCl solution.

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a. The mass in grams of potassium chlorate that are needed to react completely with the 120 grams of glucose is 326.4 g

b. The mass in grams of carbon dioxide that is formed is 176 g.

c.  The mass in grams of water that is formed is 72 g

d. The mass of glucose that will react with 12.00g of a KClO₃-NaCl mixture that is 75% KClO₃ by mass is 3.30 g

The balanced equation of the reaction is given below:

Balanced equation of reaction: 4 KClO₃ + C₆H₁₂O₆ ---> 4 KCl + 6 CO₂ + 6 H₂O

Molar mass of glucose = 180 g/mol

Molar mass of KClO₃ = 122.5 g/mol

Molar mass of H₂O = 18 g/mol

Molar mass of CO₂= 44 g/mol

a. The mass in grams of potassium chlorate that are needed to react completely with the 120 grams of glucose = 120/180 * 4 * 122.5

mass =  326.4 g

b. The mass in grams of carbon dioxide that is formed = 120/180 * 6 *44

mass = 176 g.

c.  The mass in grams of water that is formed = 120/180 * 6 * 18

mass = 72 g

d. The mass of glucose that will react with 12.00g of a KClO₃-NaCl mixture that is 75% KClO₃ by mass = 0.75 * 12/122.5 * 1/4 * 180

mass =  3.30 g

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Step 1 - First, we need to transform kg into g. We need to multiply it by 1000:

158 kg = 158,000 g of phosphorus

Step 2 - Now we need to know the molar mass of phosphorus. Look for it at the periodic table. It is 30.97 g/mol.

Step 3 - We transform grams into moles:

30.97 g ---- 1 mol

158,000 g ---- x mol

x = 5,101.7 moles of phosphorus

Step 4 - We transform moles into atoms using Avogrado's constant:

6.022 x 10^23 ---- 1 mol

x ---- 5,101.7 moles of phosphorus

x = 3.072 x 10^27 atoms

If you want to calculate it in another way:

158000/30.97 x 6.022 x 10^23 = 3.072 x 10^27 atoms

Answer: There are 3.072 x 10^27 atoms of phosphorus

Answer:

To get the answer, you want to look at the balanced equation and note that 2 moles of aluminum (Al) can produce 1 mole of aluminum oxide (Al2O3). That's the critical relationship that exists.

Answer:

Consequently, what happens when gas obtained by heating slaked lime and ammonium chloride is passed through copper sulphate solution? The HCl in the gas mixture will form hydrochloric and the H+ will react with some of the NH3(aq), forming NH4^+, and with some of the SO4^2-, forming HSO4^-.

The gas obtained by heating Ammonium Chloride and slaked lime is passed through copper sulphate, deep blue solution will be formed.

The gas obtained by heating Ammonium Chloride and slaked lime is ammonia gas.

2NH₄Cl + Ca(OH)₂  ---> CaCl₂ + 2NH₃ + 2H₂O

Ammonia reacts with copper (II) ions to precipitate light blue copper hydroxide.

Ammonia causes the copper ion to go back into the solution as a deep blue ammonia complex.

However, in excess ammonia, the precipitate dissolves.

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Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore, 8moles of Oxygen gas (0₂) will be needed to make as much water as possible.

The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity or amount of substance. We know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number.

2H₂ + O\(_2\) \(\rightarrow\) 2H₂O

the mole ratio between oxygen and hydrogen is 1:2

mole of oxygen =1/2 mole of hydrogen = 8moles

Therefore, 8moles  of Oxygen gas (0₂) will be needed to make as much water as possible.

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molar mass of PF5 = 125.966 g/mol

125 g PF5 × (1 mol PF5/125.966 g PF5) = 0.992 mol PF5

0.992 mol PF5 × (6.022 × 10^23 molecules PF5);

= 5.97 × 10^23 molecules PF5

Since there 5 fluorine atoms per molecule of PF5,

(5.97.× 10^23 molecules PF5) × (5 atoms F/1 molecule PF5)

= 2.99 × 10^24 atoms F

Technician A's statement is partially correct. When moisture enters an A/C system, it can react with the refrigerant and lubricant oils to form acidic compounds, which can damage the A/C system components. However, it is not the moisture itself that creates the acid but rather the chemical reactions that occur when it mixes with the refrigerant and oils.

Technician B's statement is also correct. Evacuating an A/C system removes moisture by boiling it away. When the pressure in the system is reduced, any moisture present will boil and be removed from the system as a gas. This is an important step in the A/C system service process to ensure that the system operates properly and efficiently.

In conclusion, both technicians are partially correct. Moisture entering the A/C system can lead to the formation of acidic compounds, which can damage the system. Evacuating the system is an effective way to remove moisture and ensure proper operation of the A/C system.

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Answer:

C Ian sure2.94atm

Explanation:

I am low student

When the engineer adds an additional 1.2 atm of nitrogen dioxide, the total pressure of the mixture is 4.9 atm + 1.2 atm = 6.1 atm. At equilibrium, the pressure of dinitrogen tetroxide is approximately 2.3 atm.

This is calculated by subtracting the equilibrium pressure of nitrogen dioxide (2.7 atm) from the total pressure of the system (6.1 atm). Therefore, after equilibrium is reached the second time, the pressure of dinitrogen tetroxide is 2.3 atm.

When nitrogen dioxide gas is added to a system, the equilibrium pressure of dinitrogen tetroxide is determined by Le Chatelier's principle. This principle states that when a system is disturbed from equilibrium, it will shift to re-establish equilibrium.

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Answer:1.75 atm = 1750 kPa

1.75 atm = 1327.5 mmHg

Explanation:

Answer:

n=mass/molar mass

mass=?,molar mass=12+(35.5)4=154g/mol.n=4.63x10²

mass=4.63x10²x154=7128g

Answer: 31161.9 J

Explanation:

Pure toluene (c7h8) has a normal boiling point of 110.60oc. A solution of 7.80 g of anthracene (c14h10), in 100.0 g. toluene has a boiling point of 112.06oc. The molality of the solution is 0.438 mol/kg. and the molal boiling point elevation constant for Toluene is 3.33 °C/m.

Given that,

Molecular weight of Toluene, C7H8 = 92 g/mol

Molecular weight of Anthracene, C14H10 = 178 g/mol

Boiling point of pure Toluene, Tb° = 110.6°C

Boiling point of Toluene solution containing Anthracene, Tb = 112.06°C

We need to find the molality of the solution and the molal boiling point elevation constant for Toluene.

Molality of the solution:

Molality is defined as the number of moles of solute per kilogram of solvent.

(Here, the solvent is Toluene and the solute is Anthracene.) Number of moles of Anthracene,

n2 = Weight of Anthracene / Molecular weight of Anthracene = 7.80 g / 178 g/mol = 0.0438 moles

Number of kilograms of solvent,

w1 = Weight of Toluene / 1000 = 100.0 g / 1000 = 0.1 kg

Molality of solution, m = n2 / w1 = 0.0438 / 0.1 = 0.438 mol/kg

Therefore, the molality of the solution is 0.438 mol/kg.

Molal boiling point elevation constant for Toluene:

The elevation in the boiling point of the solvent is given by the formula:

ΔTb = Kb . m . i

where Kb is the molal boiling point elevation constant. m is the molality of the solution. i is the van't Hoff factor (which is equal to 1 for non-electrolytes like Anthracene)

ΔTb = Tb - Tb°= 112.06°C - 110.6°C = 1.46°C

We know that m = 0.438 mol/kg

Hence,1.46 = Kb . 0.438 . 1Kb = 3.33 °C/m

Therefore, the molal boiling point elevation constant for Toluene is 3.33 °C/m.

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Answer:

correct is A, but it isn't quite right. Only when the electronegativity values of the two atoms are the same will the bond be 100% covalent.

The process by which we pass a metal to shape, form, or improve a metal through compression or stretching is the process that we refers to as forging the metal.

We know that metals can be used for a number of purposes. In fact the raw metal must be passed through a process that makes the metal quite fit for use. We refer to this process that the metal passes as the process of refining.

Now the process by which we pass a metal to shape, form, or improve a metal through compression or stretching is the process that we refers to as forging the metal.

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For the pH after the addition of each volume of acid, we need to consider the reaction between methylamine (CH₃NH₂) and HNO₃. Methylamine is a weak base, and HNO3 is a strong acid. The reaction can be written as:

CH₃NH₂ + HNO₃ -> CH₃NH₃+ + NO₃-

First, let's calculate the initial moles of methylamine in the 100.0 ml sample:

moles CH₃NH₂ = volume (L) * concentration (mol/L)

moles CH₃NH₂ = 0.100 L * 0.100 mol/L

moles CH₃NH₂ = 0.010 mol

Since CH₃NH₂ is a weak base, it will react with HNO₃ in a 1:1 ratio. Therefore, the number of moles of CH₃NH₂ reacting will be equal to the number of moles of HNO₃ added.

Now let's calculate the moles of HNO₃ added for each case:

a) 0.0 ml (no HNO₃ added): 0.010 mol

b) 20.0 ml: moles HNO₃ = 0.020 L * 0.250 mol/L = 0.005 mol

c) 40.0 ml: moles HNO₃ = 0.040 L * 0.250 mol/L = 0.010 mol

d) 60.0 ml: moles HNO₃ = 0.060 L * 0.250 mol/L = 0.015 mol

Now we need to calculate the moles of CH₃NH₂ and CH₃NH₃+ remaining after the reaction.

For case a) 0.0 ml:

moles CH₃NH₂ remaining = 0.010 mol - 0.000 mol = 0.010 mol

moles CH₃NH₃+ formed = 0.000 mol

For case b) 20.0 ml:

moles CH₃NH₂ remaining = 0.010 mol - 0.005 mol = 0.005 mol

moles CH₃NH₃+ formed = 0.005 mol

For case c) 40.0 ml:

moles CH₃NH₂ remaining = 0.010 mol - 0.010 mol = 0.000 mol

moles CH₃NH₃+ formed = 0.010 mol

For case d) 60.0 ml:

moles CH₃NH₂ remaining = 0.010 mol - 0.015 mol = -0.005 mol (Excess acid)

moles CH₃NH₃₊ formed = 0.015 mol

Since methylamine is a weak base, we need to consider the Kb value to calculate the concentration of hydroxide ions (OH-) and then convert it to pH.

The Kb expression for methylamine is:

Kb = [CH₃NH₃+][OH-] / [CH₃NH₂]

We can assume that [OH-] ≈ [CH₃NH₃+], so the equation becomes:

Kb = [OH-]^2 / [CH₃NH₂]

Rearranging the equation:

[OH-] = sqrt(Kb * [CH₃NH₂])

Now, let's calculate the OH- concentration and convert it to pH for each case:

a) 0.0 ml:

[OH-] = sqrt(3.7x10^-4 * 0.010 mol) ≈ 0.00608 M

pOH = -log10(0.00608) ≈ 2.22

pH = 14

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Answer:

Water and plastic

Explanation:

The other two dont make as much sense