How many atoms of oxygen are on the reactants side of this balanced equation?
2AgNO3 (aq)+ Cu(s) —Cu(NO3)2 (aq)+ 2Ag(s)
12
2
3

6

Answer:

4/15

Explanation:

15/15 - 11/15 = 4/15

If 11/15 is the probability that it'll rain tomorrow, then the rest should be the probability that it'll not rain tomorrow.

Answer:

Overall reaction equation is:

Cl2(g) + CHCl3(g) --> HCl(g) + CCl4(g)

The intermediates are Cl(g), CCl3(g).

Rate law= ka^1/2 c

Explanation:

This reaction is a non elementary reaction. A non elementary reaction is one that does not take place in a single reactive encounter. In other words, the reaction is comprised of many steps.

The overall reaction equation is the sum of all the reaction steps after all intermediates have been cancelled out. The rate law is obtained from the slowest step in the reaction sequence.

Sally is wrong because copper is less electropositive than hydrogen, thus, can not displace hydrogen from dilute acids.

The reactions to prepare copper (ii) chloride are:

the chlo­ri­na­tion of cop­per sul­fide at a high tem­per­a­ture

reaction of copper (ii) oxide with dilute hydrochloric acid

The equations of the given reactions are as follows:CuS + Cl₂ ---> CuCl₂ + SCuO + 2HCl ----> CuCl₂ + H₂O

Reactive metals are metals that readily give up their electrons to form positive ions.

Reactive metals displace hydrogen from dilute acids. They are found in group 1A and 2A of the periodic table. Copper is not a reactive metal and will not displace hydrogen from acids.

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Sally is wrong because copper chloride is not made from the reaction of copper and dilute hydrochloric acid.

2. Copper (ii) chloride can be prepared as follows:

3. the equations of the reaction are:

Single replacement reactions are reactions in which a more reactive atom replaces another atom in a compound.

An example of a single replacement reaction is the reaction of chlorine gas with copper sulfide at high temperatures to form copper chloride.

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Answer:

The lungs

Explanation:

Asthma is a disease that affects the airways of your lungs. With asthma, your airways' lining tends to always be in a hypersensitive state characterized by redness and swelling. Causing the airways to swell and, in severe cases, close completely off.

hope this helps, this should also probably be in biology:)

Metal extraction is a reduction process because the extracted metal is in a bound state and has a positive valence. The addition of electrons converts cations into atoms or metals.

Metal extraction is always a reductive process. Metals have positive valences in the bound state, and cations are converted to atoms or metals by the addition of electrons. So by definition it is a reductive process.

Example - Mⁿ⁺ + ne⁻ → M

Mining is the process of extracting metal ores buried deep underground. Metal ores occur in varying amounts in the Earth's crust. By extracting metals from ores, minerals in the ground can be used. Ore is very different from the finished metal you see in buildings and bridges. Ore consists of the desired metallic compounds and impurities and a geological material called gangue. The recovery of metals and their separation takes place in several main steps.

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The carbonyl stretching vibration of guanine is expected to give rise to a peak in the vibrational-Raman spectrum at a wavenumber of around 1660-1700 cm^-1.

How to explain the information

The specific location of the peak can be affected by a variety of factors, including the excitation wavelength, the sample preparation method, and the environment in which the sample is analyzed.

If the 514.5 nm line of an argon ion laser is used as the incident light source, the Raman shift associated with the carbonyl stretching vibration of guanine would be expected to be in the range of 620-670 cm^-1. However, it's important to note that the exact position of the peak may vary depending on the specific experimental conditions.

An overview was given as the information is incomplete.

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6.02 x \(10^{20\) formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

To convert formula units of MgCl₂ to moles of MgCl₂, we need to use Avogadro's number, which relates the number of formula units to the number of moles.

Avogadro's number (NA) is approximately 6.022 x 10^23 formula units per mole.

Given that we have 6.02 x 10^20 formula units of MgCl₂, we can set up a conversion factor to convert to moles:

(6.02 x 10^20 formula units MgCl₂) * (1 mol MgCl₂ / (6.022 x 10^23 formula units MgCl₂))

The formula units of MgCl₂ cancel out, and we are left with moles of MgCl₂:

(6.02 x 10^20) * (1 mol / 6.022 x 10^23) = 0.1 mol

Therefore, 6.02 x 10^20 formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

It's important to note that this conversion assumes that each formula unit of MgCl₂ represents one mole of MgCl₂. This is based on the stoichiometry of the compound, where there is one mole of MgCl₂ for every one formula unit.

Additionally, this conversion is valid for any substance, not just MgCl₂, as long as you know the value of Avogadro's number and the number of formula units or particles you have.

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The rate of a reaction refers to how fast or slow a reaction progresses over time. Option B is correct.

It is a measure of the change in concentration of reactants or products per unit of time. The rate of a reaction can be expressed in different units, such as moles per liter per second or grams per second. Factors that can affect the rate of a reaction include the concentrations of the reactants, the temperature, the presence of a catalyst, and the surface area of the reactants.

The rate law equation, which expresses the dependence of the reaction rate on the concentrations of the reactants, can also be used to determine the rate of a reaction under different conditions. The rate of a reaction is important for many applications, such as designing chemical reactions for industrial processes, optimizing reaction conditions in laboratories, and understanding biological processes that involve chemical reactions. Option B is correct.

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Answer:

buoyancy. ...

Explanation:

........

Answer:

buoyancy

Explanation:

mark as brainliest

Answer:

..........................

Okay, let's solve this step-by-step:

1) The standard reduction potentials for Cu2+/Cu are: E°Cu2+/Cu = +0.34 V.

This is the reduction potential when [Cu2+] = 1 M and [Cu] = 1 M.

2) The actual reduction potential (Ered) depends on the concentrations of oxidized and reduced species.

Here,

[Cu2+] = 4.48 M on the right side.

[Cu2+] = 0.0032 M on the left side.

3) Ered = E° + 0.0591 log([oxidized]/[reduced]) (Nernst equation)

So for the right side:

Ered = +0.34 + 0.0591 log(4.48/1) = +0.34 + 0.186 = +0.526 V

And for the left side:

Ered = +0.34 + 0.0591 log(0.0032/1) = +0.34 - 0.093 = +0.247 V

4) The cell potential (Ecell) is the difference between the two half-cell potentials:

Ecell = +0.526 - 0.247 = +0.279 V

So the cell potential for the given reaction at 25°C is +0.279 V.

Let me know if you have any other questions!

Answer:

Explanation:

Contour lines are used to determine elevations and are lines on a map that are produced from connecting points of equal elevation (elevation refers to height in feet, or meters, above sea level).

Answer: A volume of 59 mL of 0.220 M HBr solution is required to produce 0.0130 moles of HBr.

Explanation:

Given: Moles = 0.0130 mol

Molarity = 0.220 M

Molarity is the number of moles of solute present in liter of a solution.

\(Molarity = \frac{moles}{volume (in L)}\)

Substitute the values into above formula as follows.

\(Molarity = \frac{moles}{volume (in L)}\\0.220 M = \frac{0.0130 mol}{Volume (in L)}\\Volume (in L) = 0.059 L\)

As 1 L = 1000 mL

So, 0.059 L = 59 mL

Thus, we can conclude that a volume of 59 mL of 0.220 M HBr solution is required to produce 0.0130 moles of HBr.

Answer:

decreases

Explanation: decreases,as shelter is a limiting factor becasue the trees for example were there home now it is covered in melaleuca

hope this helps

Answer:

a should be the correct answer

Explanation:

there will not be many shelters that suit some animals needs

Answer:

i the answer to your question should be C

Explanation:

Hope this helps!

The atomic mass of an element related to a mole in grams, is the mass of one mole of atoms. Therefore, option C is correct.

An atom's mass is its atomic mass. Although the kilogramme is the SI measure of mass, the unified atomic mass unit, or dalton, is a common way to express atomic mass. An unbound carbon-12 atom in its ground state has a mass of 112 of a Da.

A mass that is one-twelfth the mass of an atom of carbon-12 is known as an atomic mass unit. Any isotope of any element's mass is represented in terms of the carbon-12 reference standard.

The size of an atom is indicated by its atomic mass. Technically speaking, an atom's mass is the total weight of its protons, neutrons, and electrons.

Thus, option C is correct.

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Answer:

c......................

Answer:

electrons will fill the lowest energy orbitals first and then move up to higher energy orbitals only after the lower energy orbitals are full

Answer:

Partial lunar eclipse.

Explanation:

A lunar eclipse is a cosmological event by which, in the presence of the Earth between the Sun and the Moon, the latter does not receive the light of the Sun in the totality of its visible face, with which a part (or the totality ) of her is in the dark.

Thus, if the lunar eclipse implies an absence of sunlight in the entire lunar surface, the eclipse will be total, while if the eclipse implies an absence of light only in part, the eclipse will be partial (which is the most common event).

The statement that is true regarding the atom that has a charge of +1 in its nucleus for it to have no net charge is that there is one negatively charged electron outside the nucleus (option B).

An atom is made up of three subatomic particles namely;

The number of protons and electrons in the atom is responsible for the net charge of that atom. For example, if there are more protons than electrons, the atom will be positively charged.

However, according to this question, an atom has a charge of +1 in its nucleus. This means that for this atom to have no net charge i.e. 0, there must also be one electron orbiting outside the nucleus.

Therefore, the statement that is true regarding the atom that has a charge of +1 in its nucleus for it to have no net charge is that there is one negatively charged electron outside the nucleus.

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If heat is going into the system, then energy must have come out from the surroundings.

If heat is entering a system, it means that the system is gaining thermal energy, which can lead to an increase in temperature, changes in state, or other effects depending on the nature of the system and the heat transfer mechanism.

The first law of thermodynamics, also known as the law of conservation of energy, states that the total amount of energy in a closed system remains constant, and energy can neither be created nor destroyed, only transferred or converted from one form to another.

When heat enters a system, it is either used to increase the internal energy of the system or to perform work, such as moving a piston or driving an electrical generator.

The amount of heat transferred to a system can be quantified using the equation Q = mcΔT, where Q is the heat transferred, m is the mass of the substance, c is its specific heat capacity, and ΔT is the change in temperature.

Therefore, if the system is gaining energy in the form of heat, then the surroundings (the rest of the universe) must be losing that same amount of energy. This is because energy is conserved.

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In the reaction 239/93 Np -> 239/94 Pu + X, the symbol "X" represents an electron. Option C is correct.

This reaction involves the radioactive decay of Neptunium-239 (239/93 Np) into Plutonium-239 (239/94 Pu). Specifically, it undergoes beta decay, which involves the emission of an electron.

During beta decay, a neutron in the Neptunium-239 nucleus is converted into a proton, and an electron (also known as a beta particle) is emitted. The electron carries a negative charge (-1) and is represented by the symbol "e^-" or simply "e". It balances the charge and atomic number in the reaction equation.

The balanced equation for the reaction is:

239/93 Np -> 239/94 Pu + 0/-1 e

So, in summary, the symbol "X" in the reaction 239/93 Np -> 239/94 Pu + X represents an electron (e^-) emitted during the beta decay of Neptunium-239.

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COMPLETE QUESTION

in the reaction 239/93 Np -> 239/94 Pu+X, what does X represent

A. PROTON

B. POSITRON

C. ELECTRON

D. NEUTRON

There are approximately 3.47 x 10²² molecules in 5.657g H₂SO₄.

To calculate the number of molecules in 5.657g H₂SO₄, we need to use the Avogadro's number and the molar mass of H₂SO₄.

The molar mass of H₂SO₄ is 98.079 g/mol.

We need to calculate the number of moles of H₂SO₄:

Number of moles = mass/molar mass

                             = 5.657g / 98.079 g/mol

                            = 0.05767 mol.

Then, we can use Avogadro's number, which is 6.022 x 10²³ molecules/mol, to find the number of molecules:

Number of molecules = number of moles x Avogadro's number

                                   = 0.05767 mol x 6.022 x 10²³ molecules/mol

                                    = 3.47 x 10²² molecules

To calculate the number of molecules in a given sample of a substance, you need to use the Avogadro's number, which is 6.022 x 10²³ molecules/mol. This means that one mole of a substance contains 6.022 x 10²³ molecules.

We are given the mass of H₂SO₄, which is 5.657 g. To calculate the number of molecules, we first need to determine the number of moles of H₂SO₄ in the given sample. The molar mass of H₂SO₄ is 98.08 g/mol. So, the number of moles of H₂SO₄ can be calculated as follows:

moles = mass / molar mass

moles = 5.657 g / 98.08 g/mol

moles = 0.0576 mol

Now, we can use the Avogadro's number to determine the number of molecules of H₂SO₄ in 0.0576 moles:

number of molecules = moles x Avogadro's number

number of molecules = 0.0576 mol x 6.022 x 10²³ molecules/mol

number of molecules = 3.47 x 10²² molecules

As a result, in 5.657 g of the material, there are roughly 3.47 x 1022 molecules of H₂SO₄.

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The answer is: The electronic configuration of Nitrogen is \(1s^22s^22p^3\).

Electronic configuration: The electronic configuration is defined as the distribution of electrons of an atom in the atomic or molecular orbitals and is written using the labels for the subshell.

How to decide which orbital is filled first?

(Shown in image)

         \(1s^22s^22p^3\)

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Nitrogen's complete electron configuration is 12s2s22p3.

The shorthand electron configuration for noble gases is [He] 2s22p3. Nitrogen has an atomic number of 7. The nitrogen atoms' nucleus contain this many protons. An atom that is neutral has an equal number of protons and electrons. Thus, the ground state electron configuration will consist of 7 electrons in the suitable s and p orbitals (state of lowest energy). For nitrogen, the entire electron configuration is 1s22s22p. Scientists may easily express and explain how the electrons are organized around the nitrogen atom's nucleus by using the configuration notation for nitrogen (N). As a result, it is simpler to comprehend and forecast how atoms will cooperate to form chemical bonds.

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Chemical compound, any substance composed of identical molecules consisting of atoms of two or more chemical elements. All the matter in the universe is composed of the atoms of more than 100 different chemical elements, which are found both in pure form and combined in chemical compounds.

Answer:

A compound is a unique substance that consists of two or more elements combined in fixed proportions.

Explanation:

okkk

1)The new volume at a pressure of 1 atm is 0.25 L.

2)The new temperature of the container at a volume of 2 L is approximately 398°C.

3)The new pressure at 2.5 L is approximately 4.8 atm.

4)The new volume at a temperature of 60°C is approximately 55.8

1)To solve these gas law problems, we can use the ideal gas law equation, which states:

PV = nRT,

where P is pressure, V is volume, n is the number of moles of gas, R is the ideal gas constant, and T is temperature in Kelvin.

Balloon volume at a pressure of 0.5 atm:\(V_1\) = 0.5 L, \(P_1\)= 0.5 atm.

New volume at a pressure of 1 atm:\(P_2\) = 1 atm.

We can use the relationship\(P_1V_1 = P_2V_2\) to find the new volume (\(V_2\)).

(0.5 atm)(0.5 L) = (1 atm)(\(V_2\))

\(V_2\) = 0.25 L.

Therefore, the new volume at a pressure of 1 atm is 0.25 L.

2)Container volume: \(V_1\) = 2 L, \(T_1\)= 125°C.

New temperature at the same volume: \(V_2\) = 2 L.

We can use the relationship\(V_1\)/\(T_1\) = \(V_2\)/\(T_2\) to find the new temperature (\(T_2\)).

(2 L)/(125 + 273) K = (2 L)/(\(T_2\) + 273) K

Solving for\(T_2\), we get \(T_2\) ≈ 398°C.

Therefore, the new temperature of the container at a volume of 2 L is approximately 398°C.

3)Initial volume: \(V_1\)= 4.0 L, \(P_1\) = 3.0 atm.

Final volume: \(V_2\) = 2.5 L.

Since the temperature (T) is constant, we can use the relationship \(P_1\)\(V_1\) = \(P_2V_2\) to find the new pressure (\(P_2\)).

(3.0 atm)(4.0 L) = (\(P_2\))(2.5 L)

\(P_2\) ≈ 4.8 atm.

Therefore, the new pressure at 2.5 L is approximately 4.8 atm.

4)Initial volume: \(V_1\)= 50 mL, \(T_1\) = 25°C.

New temperature: \(T_2\) = 60°C.

We need to convert the temperatures to Kelvin.

\(T_1\)= 25 + 273 = 298 K, \(T_2\) = 60 + 273 = 333 K.

We can use the relationship \(V_1/T_1 = V_2/T_2\) to find the new volume (\(V_2\)).

(50 mL)/(298 K) = (\(V_2\))/(333 K)

\(V_2\) ≈ 55.8 mL.

Therefore, the new volume at a temperature of 60°C is approximately 55.8

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Answer:

There are 0.379 moles of Ca in the given sample.

Explanation:

Hey there!

We're given that we have 15.2 grams of Ca (Calcium). We need to convert grams to moles.

There are many different conversion types for moles. A few examples are:

There are really endless possibilities for conversion factors. Since we want to find the number of moles in a certain sample, we first need to define what a mole is.

A mole is one unit of a certain item. For instance, one cup would be equivalent to one mole. Moles are simply a hypothetical unit in chemistry that act as a placeholder.

Now, how do we find the number of moles?

We know that a mole of something is one of that substance. In this case, we're referring to one atom of Calcium.

Therefore, we need to reference a periodic table to understand what the mass of one atom of calcium is equivalent to. I'll be using the official AP Chemistry periodic table as issued by the College Board.

When we reference the periodic table, we see the mass of one atom of calcium is equivalent to 40.08 amu (atomic mass units).

We learn in chemistry that we can use the terms amu and grams interchangeably, so we have learned that one mole of calcium is equivalent to 40.08 grams.

How do we work this out?

Now, we need to find out how many moles are in 15.2 grams of calcium. We can use dimensional analysis to work this out.

Our starting unit will be 15.2 grams of Ca.

We want to convert this into moles, so we need to cancel out our grams value. Additionally, since we know that we have 40.08 grams of Ca in one mole, we can set these up as two ratios:

These ratios can be used to express the relationship between the moles of calcium and the mass of one calcium atom. However, we need our value of grams to cancel out, so since we will be using cross multiplication in our dimensional analysis, we need to use the ratio with grams on the bottom.

Now that we have selected our ratio, we can set up a multiplication problem of our two ratios:

\(\displaystyle \text{15.2 grams Ca} \times \frac{\text{1 mole Ca}}{\text{40.08 grams Ca}}\)

We assume that we have a denominator of 1 below 15.2 grams Ca.

Now, we perform our multiplication.

\(\displaystyle \frac{\text{15.2 grams Ca} \ \times \ \text{1 mole Ca}}{\text{40.08 grams Ca}}\)

We see that our remaining unit is going to be mole(s) Ca, so we can go ahead and drop our grams Ca unit.

\(\displaystyle \frac{\text{15.2} \ \times \ \text{1 mole Ca}}{\text{40.08}}\)

Now, we need to simplify a little bit.

\(\displaystyle \frac{\text{15.2}}{\text{40.08}} = \text{? moles Ca}\)

Finally, let's divide our fraction and evaluate our equation to find the value of moles Ca.

\(\displaystyle \frac{15.2}{40.08} = \text{0.379241517 moles Ca}\)

Are we done yet?

Not just yet! To complete our work, we need to find the number of significant figures we can use. We are given two values in which we can use to judge how many significant figures we are limited to.

In chemistry, we always use the least number of significant figures for precision calculations, so we need to round our answer to three significant figures.

\(0.379241517 \approx 0.379\)

Therefore, there are approximately 0.379 moles of Ca in the given sample.

The formula for the hydrate is BaCl₂ × ₀.₀₈₂H₂O, and the name of the hydrate is Barium Chloride Monohydrate.

Calculating the value of "x" in the combination BaCl₂ × ₓH₂O will help us discover the hydrate's formula and name. The mass of water that was contained in the hydrate is represented by the difference between the mass before and after heating.

Mass of hydrated barium chloride (BaCl₂ × ₓH₂O) = 10.05 g

Mass of anhydrous barium chloride (BaCl₂) = 8.57 g

To find the mass of water lost:

Mass of water lost = Mass of hydrated barium chloride - Mass of anhydrous barium chloride

= 10.05 g - 8.57 g

= 1.48 g

Thus, the molar mass of water (H₂O) is 18.015 g/mol, calculate the number of moles of water lost:

Moles of water lost = Mass of water lost ÷ Molar mass of water

= 1.48 g ÷ 18.015 g/mol

= 0.082 moles

Now compare the moles of water lost to the moles of anhydrous barium chloride that are still present, in order to calculate the value of "x" in the hydrate formula BaCl₂ × ₓH₂O.

One mole of hydrated barium chloride loses "x" moles of water to produce one mole of anhydrous barium chloride, as shown by the chemical equation.

Moles of anhydrous barium chloride = 1 mole

The ratio of moles of water get reduced to moles of anhydrous barium chloride is 1:x, we can set up the following equation:

0.082 moles (water) ÷ 1 mole (anhydrous barium chloride) = 1:x

To solve for x:

x = 0.082

Thus, the formula for the hydrate is BaCl₂ × ₀.₀₈₂H₂O. Hence, name the hydrate, we use the prefix "mono" for the subscript 0.082. The name of the hydrate is Barium Chloride Monohydrate.

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