How is the amplitude related to the energy of a wave?

Answer:

mass and on the net force acting on it. ... Tap again to see term ... Newton's second law of motion states that an object's acceleration depends on its ... You hit a ping-pong ball & a tennis ball with a tennis rack

All the equations of motion are as follows, Displacement (s) equation, Final velocity (v) equation, Average velocity (v_avg) equation, Displacement (s) equation with average velocity, and Displacement (s) equation.

In terms of its motion as a function of time, equations of motion define how a physical system behaves. In more detail, the equations of motion define how a physical system behaves as a collection of mathematical functions expressed in terms of dynamic variables.

In conclusion, equations of motion define how a physical system behaves in terms of how its motion changes over time.

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The mass of a substance is not directly related to latent heat. Instead, latent heat is a parameter that describes the amount of energy required or released during a phase shift of a substance.

Latent heat can be thought of as hidden energy that is supplied or extracted to change the state of a substance without changing its temperature or pressure.

Latent heat is energy released or absorbed, by a body or a thermodynamic system, during a constant-temperature process—typically a first-order phase transition.

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The height h is 25.91 cm. Pressure can be exerted by liquids, gases, or solids and can be influenced by factors such as temperature, volume, and altitude.

What is Pressure?

Pressure is defined as the force per unit area applied in a direction perpendicular to the surface of an object. It is usually expressed in units such as pascals (Pa), pounds per square inch (psi), or atmospheres (atm).

To solve for the height h, we need to use Bernoulli's equation, which states that the sum of pressure, kinetic energy, and potential energy is constant along a streamline of fluid flow.

At point A, the gauge pressure is 34.5 kPa. Since the flow is open to the atmosphere, we can assume that the absolute pressure at point A is:

P_A = P_atm + P_gauge

= 101.3 kPa + 34.5 kPa

= 135.8 kPa

At point B, the fluid is at rest, so the velocity is zero. Therefore, the kinetic energy term in Bernoulli's equation is zero.

Using the density of water and the density of mercury, we can convert the heights of the water column and the mercury column into pressure terms.

Let h1 be the height of the water column, and h2 be the height of the mercury column. Then, the pressure difference between points A and B is:

ΔP = ρ_water * g * h1 - ρ_mercury * g * h2

where g is the acceleration due to gravity.

Setting the pressures at A and B equal to each other, we have:

P_A + ΔP = P_B

Solving for h1, we get:

h1 = (P_B - P_A + ρ_mercury * g * h2) / (ρ_water * g)

The pressure at point B is atmospheric pressure, which is 101.3 kPa.

Plugging in the given values, we get:

h1 = (101.3 kPa - 135.8 kPa + 13600 kg/m³ * 9.81 m/s² * h2) / (1000 kg/m³ * 9.81 m/s²)

h1 = (-34.5 kPa + 133137.6 Pa * h2) / 9810 Pa/m

Multiplying both sides by 100 cm/m to convert units, we get:

h1 = (-0.345 m + 13.31376 cm * h2)

Setting h1 = 0 (since we want the height at which the water column stops), we get:

0 = -0.345 m + 13.31376 cm * h2

Solving for h2, we get:

h2 = 0.345 m / (13.31376 cm)

= 25.91 cm

Therefore, the height h at which the water column stops is:

h = h1 + h2

= 0 + 25.91 cm

= 25.91 cm

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Answer:

D- Its internal energy remains constant. As the ice is being heated from -10°C to 0°C, it is not yet melting or undergoing a change in phase. Therefore, there is no latent heat of fusion involved. The internal energy of the ice remains constant as it is only being heated and not actually changing phase.

The mass of the picture is approximately 5.19 kilograms.

The deformation in this case is called shear deformation, a type of deformation that occurs when parallel internal surfaces slide past one another. It is caused by shear stress in the structure. The shear stress (τ) is the force (F) applied divided by the cross-sectional area (A) of the nail. The shear strain (γ) is the displacement (Δx) divided by the original length (L0).

The relationship between shear stress and shear strain is given by the shear modulus (G) in the formula:

τ = G * γ

To find the weight of the picture, we need to calculate the shear stress first:

The cross-sectional area A of the nail is given by the formula for the area of a circle:

A = πr² = π(d/2)² = π(0.0015 m / 2)² = 1.767 x 10^-6 m².

The shear strain γ is given by:

γ = Δx / L0 = (1.80 x 10^-6 m) / (5 x 10^-3 m) = 0.36.

The shear stress τ can now be calculated by rearranging the formula:

τ = G * γ

=> τ = (80 x 10^9 N/m²) * 0.36 = 28.8 x 10^9 N/m²

The force F on the nail is equal to the weight w of the picture, and it can be calculated from the shear stress:

τ = F / A

=> F = τ * A = (28.8 x 10^9 N/m²) * (1.767 x 10^-6 m²) = 50.89 N.

Since weight w = m * g, where m is mass and g is the acceleration due to gravity (approximately 9.81 m/s²), we can find the mass m:

m = w / g = (50.89 N) / (9.81 m/s²) = 5.19 kg.

So, the mass of the picture is approximately 5.19 kilograms.

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The increase in length of the iron wire when warmed from 20°C to 45°C is approximately 8.25 millimeters. The specific heat capacity of the object is approximately 9.62 J/kg°C. The heat capacity of the object is approximately 1.83 J/°C.

ΔL = L × α × ΔT

Where:

ΔL is the change in length

L is the original length of the wire

α is the coefficient of linear expansion for iron

ΔT is the change in temperature

The coefficient of linear expansion for iron is typically 1.1 x \(10^(^-^5^)\) °\(C^(^-^1^)\).

Given:

L = 30 m (original length of the wire)

α = 1.1 x \(10^(^-^5^)\) °\(C^(^-^1^)\) (coefficient of linear expansion)

ΔT = 45°C - 20°C = 25°C (change in temperature)

ΔL = 30 m × (1.1 x \(10^(^-^5^)\) °\(C^(^-^1^)\)) × 25°C

= 30 m × 1.1 x\(10^(^-^5^)\) × 25

= 8.25 x \(10^(^-^3^)\) m

2) Q = mcΔT

Where:

Q is the heat energy transferred

m is the mass of the object

c is the specific heat capacity

ΔT is the change in temperature

Given:

Q = 2200 J (heat energy transferred)

m = 190 g (mass of the object)

ΔT = 12°C (change in temperature)

a. Specific heat capacity (c):

one need to rearrange the formula to solve for c:

c = Q / (m × ΔT)

Substituting the given values:

c = 2200 J / (190 g × 12°C)

First, need to convert the mass to kilograms:

m = 190 g = 190 g / 1000 = 0.19 kg

Now can calculate the specific heat capacity:

c = 2200 J / (0.19 kg × 12°C)

= 9.62 J/(kg°C)

b. Heat capacity (C):

The heat capacity is the amount of heat energy required to raise the temperature of the object by 1 degree Celsius.

C = mc

Substituting the given values:

C = 0.19 kg × 9.62 J/(kg°C)

= 1.83 J/°C

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In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

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Answer: the angular velocity of a particle at the Earth's surface is approximately 7.27 x 10^-5 rad/s, and the linear velocity of the particle is approximately 464.1 m/s.

Explanation:

Answer:

Explanation:

When an object experiences acceleration to the left, the net force acting on this object will also be to the left.

From Newton's second law of motion, the acceleration of the object is given as;

a = ∑F / m

a = -F / m

The negative value of "a" indicates acceleration to the left

where;

∑F is the net force on the object

m is the mass of the object

At a constant force, F = ma ⇒ m₁a₁ = m₂a₂

If the mass of the object was doubled, m₂ = 2m₁

a₂ = (m₁a₁) / (m₂)

a₂ = (m₁a₁) / (2m₁)

a₂ = ¹/₂(a₁)

Therefore, the following can be deduced from the acceleration of this object;

Answer:

 (C) Mechanical Force

Explanation:

The force needed to accelerate a mass of 40 kg from velocity v₁ = (4î - 5) + 3k)m/s to v = (8î + 3) - 5k)m/s in 10 seconds is 12.4 N.

Start by calculating the change in velocity (Δv) experienced by the object. This can be done by subtracting the initial velocity v₁ from the final velocity v.

Δv = v - v₁ = ((8î + 3) - 5k) - ((4î - 5) + 3k)

= 8î + 3 - 5k - 4î + 5 - 3k

= 4î - 8k + 8

Next, calculate the acceleration (a) using the formula:

a = Δv / t

where t is the time interval, given as 10 seconds.

a = (4î - 8k + 8) / 10

= (0.4î - 0.8k + 0.8) m/s²

The force (F) required to accelerate the object can be found using Newton's second law:

F = m * a

where m is the mass, given as 40 kg.

F = (40 kg) * (0.4î - 0.8k + 0.8) m/s²

= (16î - 32k + 32) N

Simplify the expression to obtain the final answer:

F = 16î - 32k + 32 N

≈ 12.4 N

Therefore, the force needed to accelerate a mass of 40 kg from velocity v₁ = (4î - 5) + 3k)m/s to v = (8î + 3) - 5k)m/s in 10 seconds is approximately 12.4 N.

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Answer:

80 n

Explanation:

An item at rest will remain at rest, and an object in motion will continue to move in a straight path at a constant speed, according to the first law of motion, commonly known as the law of inertia.

Newton's laws of motion govern how a baseball moves as a result of being thrown or struck. According to Newton's first law, a moving ball will continue to move in a straight line until other forces are acting on it.

The ball is severely distorted by the enormous force the bat applies to it ball being struck. The average force acting during the bat-ball collision is therefore about two tons, with a peak force of nearly four tons, during the 0.7 millisecond contact time. There's a lot of force there!

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The resulting angular speed of the flat, uniform circular disk is 0.237 rad/s.

Angular momentum is a fundamental concept in physics that describes the rotational motion of an object around an axis. It is defined as the product of the moment of inertia of an object and its angular velocity with respect to a chosen axis.

We can use conservation of angular momentum to solve this problem. The initial angular momentum of the disk is zero because it is stationary. The final angular momentum of the system (disk + person) is:

L = Iω

where I is the moment of inertia of the disk and person about the axis of rotation, and ω is the resulting angular speed of the disk.

The moment of inertia of the disk about its axis is:

I_disk = (1/2)mr²

where the disk's radius is r and its mass is m.  Substituting the given values, we get:

I_disk = (1/2)(150 kg)(5.44 m)² = 2226.24 kg·m²

The moment of inertia of the person about the axis can be approximated as:

I_person = mr²

where r is the distance from the axis to the person. Substituting the given values, we get:

I_person = (47.0 kg)(1.54 m)² = 109.64 kg·m²

The total moment of inertia of the system is:

I = I_disk + I_person = 2226.24 kg·m² + 109.64 kg·m² = 2335.88 kg·m²

The final angular momentum of the system is:

L = Iω

where ω is the resulting angular speed of the disk. Substituting the given values, we get:

(2335.88 kg·m²)ω = (197.64 kg·m²/s)(2.80 m/s)

Solving for ω, we get:

ω = (197.64 kg·m²/s)(2.80 m/s) / (2335.88 kg·m²) = 0.237 rad/s.

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The volume of this cube of copper is 2790 cm³.

How firmly a material is packed together is determined by its density. The definition of it is the mass per unit volume.

Given parameter:

Mass of the pure copper cube: M = 25 kg = 25000 g.

We have to find; the volume of this cube of copper, V = ?

We know that density of pure material always remains constant and density of copper is 8.96 g/cm³ at room temperature.

So, the volume of this cube of copper, V = Mass of the pure copper cube/ density

= 25000/8.96 cm³

= 2790 cm³.

Hence,  the volume of this cube of copper is 2790 cm³.

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Answer:

An air mass acquires these characteristics above an area of land or water known as its source region. When the air mass sits over a region

a. The Inverse Square Law states that the intensity or strength of a physical quantity decreases with the square of the distance from its source.

b. The values of E and r in the given circuit are: E = 4V (e.m.f. of the cell) and r = ∞

a. In the context of electrostatics, the Inverse Square Law describes the relationship between the electric field strength and the distance from a charged particle.

b. For the first scenario (V = 4V and I = 1A), we have:

4V = 1A * R1,

R1 = 4Ω.

For the second scenario (V = 2V and I = 2.5A), we have:

2V = 2.5A * R2,

R2 = 0.8Ω.

Total resistance in the circuit (when ammeter reads zero current) is given by:

= R1 + R2 + r.

Since the ammeter reads zero current, we have:

E = I * R_total,

4V = 0A * R_total,

R_total = ∞ (infinity).

Therefore, we can conclude that the internal resistance r of the cell is infinite (or very high compared to the resistances in the circuit).

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The pressure of the tank, when filled with water at a depth of 6 m, is approximately 580.124 atmospheres (atm). To calculate the pressure of the tank, one can use the equation: Pressure (P) = Density (ρ) × g × Depth (h)

Pressure (P) = Density (ρ) × g × Depth (h)

Given: Density of water (ρ) = 1000 kg/m³

Acceleration due to gravity (g) = 9.8 m/s²

Depth (h) = 6 m

Using the given values, one can calculate the pressure:

Pressure = 1000 kg/m³ × 9.8 m/s² × 6 m Pressure

= 58800 kg·m⁻¹·s⁻²

Now, let's convert the units to pascals (Pa) using the conversion 1 atm = 1.013 x \(10^5\) Pa:

Pressure = 58800 kg·m⁻¹·s⁻² × (1 atm / 1.013 x\(10^5\) Pa)

Pressure = 580.124 atm

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The dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

Start by converting the rotational speed from rpm (revolutions per minute) to rad/s (radians per second). Since 1 revolution is equal to 2π radians, we can use the conversion factor:

Angular speed (ω) = (1100 rpm) × (2π rad/1 min) × (1 min/60 s)

ω ≈ 115.28 rad/s

The moment of inertia (I) is given as 2.0 × 10^-7 kg⋅m².

Use the formula for rotational kinetic energy:

Rotational Kinetic Energy (KE_rot) = (1/2) I ω²

Substituting the given values:

KE_rot = (1/2) × (2.0 × 10^-7 kg⋅m²) × (115.28 rad/s)²

Calculate the value inside the parentheses:

KE_rot ≈ (1/2) × (2.0 × 10^-7 kg⋅m²) × (13274.28 rad²/s²)

KE_rot ≈ 1.331 × 10^-3 J

Round the result to the proper number of significant figures, which in this case is three, as indicated by the given moment of inertia.

KE_rot ≈ 4.8 × 10^-4 J

Therefore, the dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

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Answer:

B.

Explanation:

it is impossible to make an engine work without heating up because there is friction plus I took the test

Answer:It is not possible to build an engine that runs without heating up.

Explanation:

Answer:

9,600 thank u

Explanation:

because blah blah blah

Answer:

Momentum is Mass x Velocity.

Its pretty obvious that the 80kg student Moving at 4ms-¹ has more momentum.

80x4 = 320kgms-1

0.001x250= 0.25kgms-¹

The Second student also Has More Inertia. Inertia is the resistance to motion offered by a Body. An Object with greater mass has more tendency to resist Motion .

So

The 80Kg student wins all.

Answer:

i think it is 80 kg

Explanation:

Answer:

33 m/s

first i do 27+6=33 +s2=

Answer:

Look down below

Explanation:

300Hz is the 5th harmonic in a 60 Hz system, or the 6th harmonic in a 50 Hz system.

Answer: The capacitor is fully charged when the voltage of the power supply is equal to that at the capacitor terminals. This is called capacitor charging; and the charging phase is over when current stops flowing through the electrical circuit.

The gauge pressure at point 2 is 98100 Pa or 9.81 x\(10^4\) Pa, which is equivalent to 6.97 x\(10^4\) Pa when rounded to two significant figures.

Step 1: Identification of the given data:

- Elevation at point 1 (h1) = 10.0 m

- Elevation at points 2 and 3 (h2 = h3) = 2.00 m

- Cross-sectional area at point 2 (A2) = 0.0480 \(m^2\)

- Cross-sectional area at point 3 (A3) = 0.0160 \(m^2\)

Step 2: Determination of the discharge rate:

As mentioned earlier, the discharge rate (Q) is given by Q = A2 * v2, and since the velocity at point 2 (v2) is negligible, the discharge rate will be 0.

Therefore, the discharge rate is 0 cubic meters per second.

Step 3: Determination of the gauge pressure at point 2:

To find the gauge pressure at point 2, we'll use Bernoulli's equation:

P1 + (1/2)ρ\(v1^2\) + ρgh1 = P2 + (1/2)ρ\(v2^2\) + ρgh2

Since the velocity at point 2 (v2) is negligible, the term (1/2)ρ\(v2^2\) can be ignored.

The equation simplifies to:

Patm + ρgh1 = P2 + ρgh2

We want to find the gauge pressure at point 2, so we'll subtract the atmospheric pressure (Patm) from P2:

\(P_g_a_u_g_e\) = P2 - Patm

Now let's substitute the given values into the equation:

\(P_g_a_u_g_e\) = (Patm + ρgh1) - Patm

\(P_g_a_u_g_e\) = ρgh1

Plugging in the values:

\(P_g_a_u_g_e\) = (1000 kg/m^3) * (9.81 \(m/s^2\)) * (10.0 m)

\(P_g_a_u_g_e\) = 98100 Pa

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The car will move at a constant speed once it is unleashed, as is assumed. Hence, there is no acceleration. Newton's second law states that a straight line along zero will appear on the graph if F=ma=m(0)=0, F=0.

Acceleration is the rate at which an object changes its velocity. It is a vector quantity, which means it has both magnitude and direction. The standard unit of acceleration is meters per second squared (m/s²).

Acceleration can be caused by forces such as gravity, friction, and electromagnetism. When a force acts on an object, it causes a change in the object's motion, resulting in acceleration.

The relationship between acceleration, velocity, and time is described by the equation a = (v_f - v_i) / t, where a is acceleration, v_f is final velocity, v_i is initial velocity, and t is time.

The effects of acceleration can be seen in everyday experiences, such as feeling pushed back into your seat when a car accelerates or feeling weightless during freefall. Understanding acceleration is important in fields such as physics, engineering, and transportation.

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The speed of the roller coaster at the bottom of the hill if the track was frictionless is 34.04 m/s.

Given that the weight of the roller coaster is 2000 kg and the initial vertical drop of the ride is 59.3 m. We are to find the speed of the roller coaster at the bottom of the hill if the track was frictionless.We know that the roller coaster will lose potential energy due to the vertical drop. Assuming there is no friction, the potential energy will be converted into kinetic energy at the bottom of the hill.Considering the conservation of energy between the potential and kinetic energy, we can set the initial potential energy equal to the final kinetic energy. We can use the formula to calculate potential energy, which is PE = mgh where m = 2000 kg, g = 9.8 m/s², and h = 59.3 m. Therefore,PE = 2000 kg × 9.8 m/s² × 59.3 m = 1,157,924 JWe can use the formula to calculate kinetic energy, which is KE = 1/2mv² where m = 2000 kg and v is the final velocity. Therefore,KE = 1/2 × 2000 kg × v².The total energy remains constant as we know there is no friction. Therefore the final kinetic energy will be equal to the initial potential energy,1,157,924 J = 1/2 × 2000 kg × v²v² = (2 × 1,157,924 J) / 2000 kgv² = 1157.924v = √1157.924v = 34.04 m/s.

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