how far apart should the two lenses be when you focus on distant objects? express your answer to two significant figures and include the appropriate units.

Answer:

The two scales have different zero points and the Celsius degree is bigger than the Fahrenheit. However, there is one point on the Fahrenheit and Celsius scales where the temperatures in degrees are equal. This is -40 °C and -40 °F.

Explanation:

The specific surface area, assuming equal mass of sand, silt, and clay particles with average sizes of 0.6 mm, 0.005 mm, and 0.0006 mm respectively, can be calculated to be a total of 9.53 square meters per gram.

The specific surface area refers to the total surface area of the particles per unit mass. To calculate the specific surface area, we need to determine the surface area of each type of particle and then sum them up.

First, we calculate the surface area of sand particles. The average size of sand particles is given as 0.6 mm. Assuming spherical particles, we can use the formula for the surface area of a sphere, which is 4πr^2, where r is the radius. Therefore, the surface area of a sand particle is 4π(0.3 mm)^2.

Next, we calculate the surface area of silt particles. The average size of silt particles is given as 0.005 mm. Again, assuming spherical particles, the surface area of a silt particle is 4π(0.0025 mm)^2.

Finally, we calculate the surface area of clay particles. The average size of clay particles is given as 0.0006 mm. Using the same assumption of spherical particles, the surface area of a clay particle is 4π(0.0003 mm)^2.

Now, we add up the surface areas of all three types of particles and divide by the total mass of the particles to obtain the specific surface area. This calculation yields a specific surface area of approximately 9.53 square meters per gram.

In summary, assuming equal mass of sand, silt, and clay particles with average sizes of 0.6 mm, 0.005 mm, and 0.0006 mm respectively, the specific surface area is calculated to be 9.53 square meters per gram.

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Answer:

True

Explanation:

I took the test

Answer:

0.50 s

Explanation:

The mass of the blood denoted is 501.6 g.

The mass of the blood denoted by Keona is calculated by applying the formula for density of a liquid as shown below.

density = mass/volume

mass = density x volume

The given parameters include;

The mass of the blood is calculated as follows;

mass = 1.06 g/mL x 473.176 mL

mass = 501.6 g

Thus, the mass of the blood is calculated from the formula of density.

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The complete question is below

While participating in a blood drive at school, Keona learns that blood has a density of 1.06 g/mL. She donates one pint of blood, which is equal to 473.176 mL. find the mass of the blood denoted.

The number of motor units that are recruited within a muscle is the most direct indicator of how much tension can build.

The fundamental functional components of skeletal muscle are known as motor units, which are defined as a motoneuron and all of its related muscle fibers.

Their function in motor control has been extensively researched. Their activity is the central nervous system's end product.

In summary, motor unit recruitment is the process through which the body activates new motor units to produce stronger muscle contractions and more force.

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Answer:

By watching in the door lock

Answer:

.-. you can flip a switch and look at the bottom or the top of the door and see if there’s a light of there isn’t then flip another one.

also the other chat that we were talking on got deleted

Space telescopes like Hubble and Chandra provide vital data on distant stars and galaxies.

Space-based telescopes, particularly those designed for observations across various wavelengths, provide crucial data for advancing our understanding of distant stars and the universe. Among them, the Hubble and Chandra telescopes are major contributors to this field.

1. Hubble Space Telescope:  The Hubble Space Telescope captures images and data about distant stars, enabling astronomers to study their lifecycle, characteristics, and evolution, as well as explore star-forming regions and galaxy dynamics. Its deep-field observations have also provided remarkable insights into the early universe and distant galaxies.

2. Chandra X-ray Observatory: The Chandra X-ray Observatory is designed to detect and analyze X-ray emissions from celestial objects, providing crucial insights into high-energy processes and phenomena associated with stars, such as supernovae and black holes. Chandra's observations have greatly contributed to our understanding of stellar evolution, X-ray binary systems, and other X-ray sources both within and beyond our galaxy.

Therefore, Important information on far-off stars and galaxies is provided by space telescopes like Hubble and Chandra.

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Answer: new moon

Explanation:

Answer: Carbon and oxygen, the answer is in the question

Answer:

Carbon and oxygen

Explanation:

Answer:

2835

Explanation:

Simply observe, my foot.

Nah, if 3 is next to 8, and 2 is not by 3, that means it is either 382 or 283.

If 5 is not by 2, then it must be by the 3, since the 3 is on the other side and is the only location left.

You now have

5382 or 2835.

It is less than 5000, so it is the latter.

Answer:

c) the quantity that opposes inertia

Given,

The mass of the box, m=35.0 kg

The height to which the box was lifted, h=1.75 m

Potential energy is the energy possessed by an object due to its position.

The gravitational potential energy gained by the box is,

Where g is the acceleration due to gravity.

On substituting the known values,

Thus the gravitational potential energy gained by the box is 600.25 J

Answer:

Explanation:

1. Sea surface temperature

2. Ocean currents

3. Sea level

4. Ocean color

5. Sea surface winds

6. Sea surface salinity

7. Marine vegetation

8. Ice coverage

9. Wave height

10. Sea surface height

Answer:d

Explanation:

Physical property do these two elements most likely have in common They both D.conduct electricity very well

Iron is a metal specifically known as a transition metal. It fits the description of metals, as it is silvery gray, ductile, and malleable.

silicon is known as a chemical analogue to carbon. But unlike carbon, silicon a metalloid

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Yes, we have paired data because each specimen was tested using both procedures (Test 1 and Test 2).

(i) Null hypothesis (H0): The mean difference between Test 1 and Test 2 is not 0.1 units less.

(ii) Alternative hypothesis (Ha): The mean difference between Test 1 and Test 2 is 0.1 units less.

To test this claim, we will use a one-sided 95% confidence interval.

Mean difference = 0.1 units

Standard deviation of the difference = Standard deviation of Test 1 - Standard deviation of Test 2

Mean of Test 1 (M1) = 1.3

Mean of Test 2 (M2) = 1.6625

Standard deviation of Test 1 (S1) = 0.207

Standard deviation of Test 2 (S2) = 0.2774

Sample size (n) = 8

Standard deviation of the difference:

SD_diff = \(\sqrt{(S1)^{2} /n+ (S2)^{2}/} n\\\\)

SD_diff =\(\sqrt{(0.207)^{2}/8 +(0.2774)^{2}/8 }\)

SD_diff = 0.1727

Standard error (SE) of the difference:

SE_diff = SD_diff / sqrt(n)

            = 0.1727 / sqrt(8)

SE_diff = 0.0611

The one-sided 95% confidence interval for the mean difference is calculated as follows:

Lower limit = Mean difference - (1.645 * SE_diff)

Upper limit = Mean difference

Lower limit = 0.1 - (1.645 * 0.0611)

Lower limit = 0.1 - 0.1004

Lower limit = -0.0004

Since the lower limit of the one-sided 95% confidence interval (-0.0004) is greater than 0, we fail to reject the null hypothesis at a 0.05 level of significance. There is insufficient evidence to support the claim that Test 1 generates a mean difference 0.1 units less than Test 2.

(v) Assumptions required to develop the confidence interval:

1. The data follows a normal distribution.

2. The paired observations are independent of each other.

3. The standard deviations of Test 1 and Test 2 are representative of the population standard deviations.

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Answer:

4 m

Explanation:

\(v = f \times  λ\)

speed of sound wave (according to question)

= 1 × 1000 = 1000m/s

wavelength is represented by λ

therefore to find the wavelength, divide the speed by the frequency of the second wave given by the question

λ of another wave = 1000 ÷ 250 = 4 m

Speed of sound equals wavelength and frequency. The wavelength of the sound wave if the frequency is 250hz is 4 meters.  

Sound requires a medium to propagate in the form of vibration. It is the pattern of disturbance caused by the movement of energy particles propagating through the medium.

Sound waves can travel in the form of transverse and longitudinal waves. When the sound source continues to vibrate in the medium, the vibrations are propagated in the form of sound waves.

The sound waves travel at different speeds in different mediums. the speed of sound waves remains constant in the same medium. The speed of sound waves is directly proportional to wavelength and frequency.

Wavelength(λ) measures the distance between two crests/ two troughs in a wave and its SI unit is a meter. The frequency (f) of a wave is the number of waves that pass in a certain time and its unit is hertz(Hz). The SI unit of the speed sound wave is m/s.

From the givens,

wavelength(λ) = 1 meter.

frequency (f) = 1000hz.

Speed of wave(v) = wavelength × frequency

                              = 1 × 1000

                           v   = 1000 m/s.

speed of wave = 1000 m/s.

frequency = 250hz

wavelength(λ) = speed / frequency

                        = 1000 / 250

                        = 4 meters.

Hence, the wavelength(λ) of a 250 hz sound wave is 4 meters.

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The correct expression for the rotational inertia of the spherically shaped object is \(\(\text{c) } 3.6m^5\)\).

In the given scenario, the students determine that the radius of the object is given by \(\(r = km^2\) with \(k = 3\, \text{m/kg}^2\)\). To calculate the rotational inertia of the object, we need to use the formula for rotational inertia of a spherical object, which is given by \(\(I = \frac{2}{5}mr^2\)\), where m is the mass of the object and r is the radius.

Substituting the given expression for r in terms of m, we have \(\(I = \frac{2}{5}m(km^2)^2\)\). Simplifying this equation, we get \(\(I = \frac{2}{5}mk^2m^4\)\).

Substituting the value of \(\(k = 3\, \text{m/kg}^2\)\), we have \(\(I = \frac{2}{5}(3\, \text{m/kg}^2)^2m^5\)\), which further simplifies to \(\(I = \frac{2}{5} \times 9 \, \text{m}^2/\text{kg}^2 \times m^5\)\).

Finally, multiplying the constants, we get \(\(I = 3.6 \, \text{m}^2/\text{kg}^2 \times m^5\)\), which corresponds to option c) \(3.6 \(m^5\)\).

Therefore, the correct expression for the rotational inertia of the object is \(3.6 \(m^5\)\).

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Answer:

A = 70cm³

B= 805 grams

Explanation:

(a) V = L×B×H

= 7cm × 5cm × 2cm

= 35cm × 2cm

= 70cm³

(b) Mass= volume × Density

= 70cm³ × 11.5g/cm³

=805 grams

I hope this will help you ...

Answer:

Energy = Power x Time

Explanation:

Fetch is the distance over which the wind blows over open water generating mechanical waves; option D

Waves are disturbance which occur in a substance or medium which project energy as they travel along a particular plane or direction.

There are two types of waves:

Mechanical waves are waves which involve the disturbances that occur in particulate matter and which require a material medium for their transmission.

Fetch is an area of ocean or lake surface over which the wind blows in a constant direction, thus generating waves.

In conclusion, mechanical waves require material media for transmission.

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The cards are observed to move forward as the coins gel in the jar. This happens because the coin has rest inertia. Rest inertia is the resistance that an object exerts at rest. resist change and fall into the glass.

Coins have inertia. If you move the card slowly, it won't be fast enough to overcome this force. With a quick flick, the coin stays in one place and falls into the cup. A stationary object remains stationary. You could change position and fall to the ground or be inside the glass. This is because the paper changes its position when a strong force is applied or a quick pull is applied.

The law of inertia, also known as Newton's first law, states in physics that if an object is at rest or moving in a straight line with a constant velocity, it is at rest or moving in a straight line with a constant velocity. We assume that This is when a force is applied.

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Answer:

a. 60 N*s

b. 60 (kg*m)/s

c. 3 m/s

Explanation:

Givens:

m = 20 kg

v_i = 0 m/s

t = 10 s

F = 6 N

a) Impulse:

I = F*t

I = 6 N*10 s

I = 60 N*s

b) Momentum:

p = v*m

F = m(a)

a = F/m

a = 6 N/20 kg

a = 0.3m/s^2

a = (v_f -v_i)/t

v_f = (0.3 m/s^2)*10 s

v_f = 3.0 m/s

p = 3 m/s*20 kg

p = 60 (kg*m)/s

c. Final velocity

a = (v_f -v_i)/t

v_f = (0.3 m/s^2)*10 s

v_f = 3.0 m/s

The impulse, momentum and final velocity can all be obtained from Newton's second law.

Let us recall that the impulse is obtained as the product of force and time.

Impulse = Force × time

Impulse = 6 N × 10 s = 60 Ns

From Newton's second law of motion;

F.t = mv - mu

Since the object was initially at rest;

F.t = mv

Hence, the final velocity of the object is 60 Kgms-1

The final velocity is obtained from;

F.t = mv

v = F.t/m

v = 6 × 10/20

v = 3 m/s

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Answer:

We use the Formula,

Work done = total chargr×potential difference

W=Q(total)× V

Here

Q= total charge= Give 3c

V=potential difference= 10v

so the work done in moving the charge from A to B will be,

w=3×10

w= 30 joules

The normal result of the trade wind blowing from South America to Indonesia and Australia warm water produces rainy weather in Indonesia and Australia. Option D

We know that the trade winds are the winds that tend to originate at the north east or the south eastern parts of the hemisphere and tend to be blowing across the seas towards the equator. Thus we can see that the focus of the trade winds is the equator and they emanate from north or south.

One of the effects of the trade winds is that they make the wind warmer and that would make to the emergence of a warmer weather and this would spread to the other parts of the word as we can see from map studies.

The effects of the trade winds  blowing from South America would tend  to be much more felt around the areas of  Indonesia and Australia and this is very important to weather changes around those areas.

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Given,

The length of the slab, L=12 m

The initial temperature, T₁=10°C

The final temperature, T₂=30°C

The coefficient of the linear expansion of the concrete is α=12×10⁻⁶ /°C

The change in the length of the slab is given by,

Where ΔT is the change in the temperature.

Therefore,

On substituting the known values,

Thus the expansion in the length of the slab in the given temperature range is 0.003 m.

Thus the gap between the slabs should be 0.003 m