Answer:
1.) The 1ˢᵗ three term is (-32), (-7) and 18
2.) The 1ˢᵗ three term is 127, 106 and 85
Step-by-step explanation:
1.)Here,
First Term = a₁ = - 32
Common Difference = (d) = 25
Now, For 1ˢᵗ three term,
n = 1
a₁ = - 32
n = 2
aₙ = a + (n - 1)d
a₂ = (-32) + (2 - 1) × 25
a₂ = (-32) + 1 × 25
a₂ = (-32) + 25
a₂ = -7
n = 3
aₙ = a + (n - 1)d
a₃ = (-32) + (3 - 1) × 25
a₃ = (-32) + 2 × 25
a₃ = (-32) + 50
a₃ = 18
Thus, The 1ˢᵗ three term is (-32), (-7) and 18
2.)Here,
First Term = a₁ = 127
Common Difference = (d) = -21
Now, For 1ˢᵗ three term,
n = 1
a₁ = 127
n = 2
aₙ = a + (n - 1)d
a₂ = 127 + (2 - 1) × (-21)
a₂ = 127 + 1 × (-21)
a₂ = 127 - 21
a₂ = 106
n = 3
aₙ = a + (n - 1)d
a₃ = 127 + (3 - 1) × (-21)
a₃ = 127 + 2 × (-21)
a₃ = 127 - 42
a₃ = 85
Thus, The 1ˢᵗ three term is 127, 106 and 85
-TheUnknownScientist
write functions of simple machine
Answer:
The basic purpose for which most simple machines are designed is to reduce the effort (force) required to perform a simple task. To achieve this, the force applied must act over a longer distance or period of time resulting in the same amount of work being performed by a smaller force.
Answer:
to make work easier by reducing the effort to be used
Explanation:
Can someone please help
99.16 Newtons is the new force of attraction between the particles.
What causes an atoms to attract one another?The forces that hold atoms together to create molecules and solids are referred to as chemical bonds. The attraction between the electrons of one atom and the nuclei of another atom as a result of this electric force is what is known as a chemical bond.
\(F = (kq1q2)/r^2\)
\(9,916 = (kq1q2)/r^2\)
\(F = (k*(q1/5)*(q2/5))/(2r)^2\)
\(F = (1/100)((kq1*q2)/(r^2))\)
So, the new force of attraction is:
\(F = (1/100)*9,916 = 99.16\)Newtons (rounded to 4 decimal places)
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Why don't normal everyday collisions result in fusion?
An unknown material has a mass of 3.5 g and a volume of
5.5 cm3 What is the density of the material? Round to the nearest tenth.
Explanation:
Density=mass/volume
density= 3.5 g ÷ 5.5cm
density=0.63
nail tips exert tremendous pressures when they are hit by hammers because they exert a large force over a small area. what force must be exerted on a nail with a circular tip of 1.00 mm diameter to create a pressure of (this high pressure is possible because the hammer striking the nail is brought to rest in such a short distance.)
2.18X103 N force must be exerted on a nail with a circular tip of 1.00 mm diameter to create a pressure.
diameter, d = 0.95 mm = 0.95x10-3m
P = 3.1X10^9 Pa
r = d/2 = 0.95/2 x 10^-3 m
= 0.475 x 10^-3 m
Area = \(\pi\) r2
= 3.14 x ( 0.475 x 10^-3 m)2
= = 3.14 x 0.225 x 10^-6
= 0.706 × 10-6 m2
Force = PXA
= 3.1 x 10^9 x 0.70 6 × 10^-6
F = 2.18X103 N
Pressure , within the physical sciences, the perpendicular force in step with unit per area , or the stress at a factor inside a restricted fluid.
A easy instance of pressure can be seen by retaining a knife to a bit of fruit. In case you keep the flat part of the knife towards the fruit, it might not reduce the area. The force is spread out of a massive vicinity (low strain).
The SI unit of pressure is pascal (represented as Pa) which is identical to one newton in line with rectangular metre (N/m2 or kg m-1s-2).
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A 66-kg bicyclist (including the bicycle) accelerates uniformly from 0.50 m/s to 1.50 m/s, traveling 6.0m. What is the net force acting on the bicyclist?
The net force acting on the bicyclist is 11.022 Newton.
Given the following data:
Mass of bicyclist = 66 kg Initial velocity = 0.50 m/s Initial velocity = 1.50 m/sDistance traveled = 6.0 metersTo find the net force acting on the bicyclist, we would apply Newton's Second Law of Motion:
Mathematically, Newton's Second Law of Motion is given by this formula;
\(Force = mass\) × \(acceleration\)
First of all, we would determine the acceleration by using the third equation of motion;
\(V^2 = U^2 + 2aS\\\\1.5^2 = 0.5^2 + 2a(6)\\\\2.25 = 0.25 + 12a\\\\12a = 2.25 - 0.25\\\\12a = 2\\\\a = \frac{2}{12}\)
Acceleration, a = 0.167 \(m/s^2\)
Now, we can find the net force acting on the bicyclist:
\(Force = 66\) × \(0.167\)
Force = 11.022 Newton
Therefore, the net force acting on the bicyclist is 11.022 Newton.
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currently the largest optical telescope mirrors have a diameter of a. 10 m b. 12 m c. 15 m d. 20 m
Currently, the largest optical telescope mirrors have a diameter of a 20 m , so option d is is correct.
The largest optical telescope mirrors have a diameter of a 20m.However, please note that technology and advancements in telescope construction are continuously evolving, so it's possible that larger telescope mirrors have been developed since then. It's always a good idea to consult the latest sources or refer to current astronomical news for the most up-to-date information.An optical telescope is a telescope that gathers and focuses light mainly from the visible part of the electromagnetic spectrum, to create a magnified image for direct visual inspection, to make a photograph, or to collect data through electronic image Therefore option d is correct option.
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21. A 50.0 kg diver steps off a diving board and drops straight down into the water. The water provides an average net force of resistance of 1500 N to the diver's fall. If the diver comes to rest 5.0 m below the water's surface, what is the total distance between the diving board and the diver's stopping point underwater?
Answer:
d = 15.28 [m]
Explanation:
To solve this problem we must use Newton's second law which tells us that the sum of forces on a body is equal to zero.
Let's take the downward movement as positive i.e. the acceleration will be positive, and the resistance force as negative since it opposes the movement.
∑F = m*a
where:
∑F = sum of forces [N]
m = mass = 50 [kg]
a = acceleration [m/s²]
g = gravity acceleration = 9.81 [m/s²]
The forces acting on the diver are the weight down and the resistance force up.
\(F_{w}-F_{r}=m*a\)
where:
Fw = weight = m*g = mass by the gravity acceleration
Fr = resistance force = 1500 [N]
\((50*9.81)-1500=50*a\\-1009.5=50*a\\a=-20.19[m/s^{2} ]\)
The negative sign indicates that the acceleration is upward, that is, it opposes the fall of the diver in the water and for this reason it stops when it reaches 5 meters deep.
The key to solving this problem is to understand that when the diver hits the water, he does it with an initial velocity. In this way with the following formula of kinematics we can find the initial velocity or velocity of entry on the surface of the water.
\(v_{f}^{2} =v_{o}^{2} -2*a*x\)
where:
Vo = initial velocity [m/s]
Vf = final velocity = 0 (The diver comes to rest = no movement)
a = acceleration = 20.19 [m/s²]
x = distance from the diver's stopping point to the water surface = 5 [m].
\(0 = v_{o}^{2} -2*20.19*5\\v_{o}=\sqrt{(2*20.19*5)} \\v_{0}=14.2[m/s]\)
Now we use the same expression of kinematics again. But with the difference that the final velocity is the velocity of entry into the water and the initial velocity is zero since the diver is launched without initial velocity. Acceleration is equal to gravitational acceleration.
\(v_{f}^{2} =v_{o}^{2}+2*g*x_{1}\\ 14.2^{2}=0+(2*9.81*x_{1})\\201.64=19.62*x_{1}\\x_{1} = 10.28[m]\)
Then the total fall distance will be 5 meters in the water plus the calculated distance in the air.
\(d=5+10.28\\d = 15.27[m]\)
In order to solve the steps of the diving board the average net force is given as 1500N an is towards the divers fall.
The newton's second law that tells us that the sum of forces on a body is equal to zero. the acceleration will be positive, and the resistance force as negative since it opposes the movement. ∑F = m*a.Learn more about the steps off a diving board and drops straight.
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A parked car of mass 720kg is hit by another car. The car that was parked is now moving with a velocity of 6 m/s. What is the change in momentum (Δp) of the car ? kgm/s
Answer:
4320
Explanation:
change in momentum ft = (v-u) m
where our v= 0
air located above a cold land surface will gradually become cooler. what happens to the air as it cools? a. its pressure increases, and it rises above warmer air. b. it becomes denser and sinks below warmer air. c. its pressure decreases, and it sinks below warmer air. d. it becomes less dense and rises above warmer air.
As the air cools, it becomes denser and sinks below warmer air (option b). Cooling causes a decrease in air molecules' kinetic energy, reducing their speed and increasing their proximity to each other.
This increased density leads to higher air pressure. According to the ideal gas law, decreasing temperature decreases the air pressure.
This denser, cooler air displaces the warmer, less dense air, causing it to rise. This process is known as convection.
It creates vertical air movements, with cooler air sinking and warmer air rising.
The resulting circulation patterns play a crucial role in weather and climate systems, influencing wind patterns, cloud formation, and precipitation. Thus, the correct option is b.
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what current flows when a 45 v potential difference is imposed across a 1.8 kω resistor?
When a 45 V potential difference is applied across a 1.8 kΩ resistor, a current flows through the resistor, following Ohm's law (I = V/R). Therefore, the current can be calculated by dividing the voltage by the resistance: I = 45 V / 1.8 kΩ = 0.025 A. This means that a current of 0.025 A, or 25 milliamperes (mA), flows through the resistor.
The flow of current through the resistor can cause various effects, depending on the circuit design and the properties of the resistor itself. For example, the resistor may generate heat as a result of the current flow, which can be a concern in some applications.
Additionally, the resistor can serve to limit the amount of current that flows through the circuit, which can help protect other components from damage due to overloading or short circuits.
Overall, understanding how current flows through resistors and other components is essential for designing and troubleshooting electrical circuits. By applying the principles of Ohm's law and other fundamental concepts, engineers, and technicians can ensure that circuits operate safely and effectively.
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used to accurately measure the volume of solutions when adding a solid to be dissolved
To make the solute dissolve, thoroughly mix and add a little quantity of solvent after transferring the solute to a container
What is a solute?A solute is a material dissolved in another substance known as a solvent in a homogeneous mixture made of two or more components.
A solute's concentration in a solution is a measure of how much of that solute is dissolved in the solvent and the amount of solvent present, such as salt. Solutes are the best cleaning agents and additives.
Add a little quantity of solvent after transferring the solute to a container ideally a volumetric flask,
Which most precisely measures the volume of the solution indicated on the flask. To make the solute dissolve, thoroughly mix.
Hence the above process should be followed to dissolve, and thoroughly mix.
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which is the best definition of pitch
Answer:
a black or dark viscous substance obtained as a residue in the distillation of organic materials and especially tars
Explanation:
help me i dont understand
Answer:
B
Explanation:
At the highest/maximum point the vertical velocity is zero because as the projectile is launched it eventually changes direction. At this instant it momentarily stop causing the maximum velocity to be zero.
hopefully this makes sense
:)
What are alkali earthmetals?
Answer:
The alkaline earth metals are the elements that correspond to group 2 of the modern periodic table. This group of elements includes beryllium, magnesium, calcium, strontium, barium, and radium. The elements of this group are quite similar in their physical and chemical properties.
Explanation:
A turtle moves at the speed of 0.25 m/s towards the line of arrival that is 100m away from the line of start when the turtle is 20m before the arrival line. The speed of the rabbit is 1m/s. After how many seconds of the start of the rabbit would the turtle reach the end? How long does it take the rabbit to cover the 100m? Would the rabbit beat the turtle?
We can compare the times taken by the turtle and the rabbit 320 s > 100 s This means that the rabbit will reach the arrival line much before the turtle does. Therefore, the rabbit will beat the turtle in this race.
We can start by finding the time it takes for the turtle to cover the remaining distance to the arrival line.
Distance to travel by turtle = 100 m - 20 m = 80 m
Speed of turtle = 0.25 m/s
Time taken by turtle to cover the remaining distance = distance/speed = 80 m / 0.25 m/s = 320 s
Therefore, the turtle will take 320 seconds to reach the arrival line from its starting point.
Next, we can find the time taken by the rabbit to cover the entire 100 m distance.
Speed of rabbit = 1 m/s
Time taken by rabbit to cover 100 m = distance/speed = 100 m / 1 m/s = 100 s
Therefore, the rabbit will take 100 seconds to cover the entire 100 m distance.
Now, we can compare the times taken by the turtle and the rabbit.
320 s > 100 s
This means that the rabbit will reach the arrival line much before the turtle does. Therefore, the rabbit will beat the turtle in this race.
What is arrival line?
The "arrival line" is a term used in the context of a competition where participants have to cover a certain distance. It is the point or the line beyond which the participants are supposed to cross or reach to complete the race or the competition.
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If the distance between us and a star is doubled, with everything else remaining the same, the luminosity If the distance between us and a star is doubled, with everything else remaining the same, the luminosity remains the same, but the apparent brightness is decreased by a factor of two. is decreased by a factor of four, but the apparent brightness remains the same. is decreased by a factor of two, and the apparent brightness is decreased by a factor of two. remains the same, but the apparent brightness is decreased by a factor of four. is decreased by a factor of four, and the apparent brightness is decreased by a factor of four.
Answer:
The luminosity remains the same, but the apparent brightness is decreased by a factor of four.
Explanation:
The apparent brightness, F = L/4πr² where L = luminosity and r = distance between us and the star.
Since L is independent of the distance between us and the star, it is constant, then
F ∝ 1/r²
So, F₁/F₂ = r₂²/r₁² where F₁ = apparent brightness at r₁ and F₂ = apparent brightness at r₂
If the distance is doubled, that is r₂ = 2r₁, then
F₁/F₂ = r₂²/r₁²
F₁/F₂ = (2r₁)²/r₁²
F₁/F₂ = 4r₁²/r₁²
F₁/F₂ = 4
F₂ = F₁/4
So, since the luminosity is constant, the luminosity remains the same, but the apparent brightness is decreased by a factor of four.
look at attached photo pls. physics, momentum, acceleration. 30 points:)
1. The deceleration of the aeroplane in the 35s is -1.6m/s²
2. The force acting on the aeroplane is 4.0× 10⁵N
3. The momentum of the aeroplane when its speed is 6.0m/s is 15 ×10⁶kgm/s
What are the equation of motion?The equation of motion are used in solving problems related to motion. The equations of motion are
1. v = u+ at
2 S = ut + 1/2at²
3. v² = u²+2as
where v is the final velocity
u is the initial velocity
S is the distance
t is time
a is the acceleration
The deceleration of the plane after 35s can be calculated as;
v = u+at
v= 6m/s, u= 62m/s , t = 35s
6 = 62+35a
35a = 6-62
35a =- 56
a = - 56/35
a = -1.6m/s²
the negative sign shows that the plane decelerates.
The force acting on the plane is calculated as;
F = ma
F = 2.5×10⁵× 1.6
F = 4× 10⁵N
The momentum of the plane at 6m/s is ;
p = mv
p = 2.5×10⁵ × 6
p = 1.5× 10⁶ kgm/s
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what is electrical power ???
Answer:
Electric power is the rate, per unit time, at which electrical energy is transferred by an electric circuit. The SI unit of power is the watt, one joule per second.
Answer:
Explanation shown below.
Explanation:
Is one generated from the movement of free moving electrons.
Electric energy can be harnessed from different sources.
PLEASE HELP ME! IM TIMED
Answer:
it b
Explanation:
just try
Upon returning to earth after 2 weeks in space, an astronaut will exhibit which of the following? (MACA) An increased blood pressure A decreased urinary output A decreased muscle tone A decreased blood volume An elevated cardiac output
These physiological changes are adaptations to the microgravity environment and are transient, as the body readjusts to Earth's gravity upon return.
Upon returning to Earth after spending two weeks in space, an astronaut will exhibit the following physiological changes:
1. An increased blood pressure: Prolonged exposure to microgravity during spaceflight can lead to a redistribution of bodily fluids, causing fluid to accumulate in the upper body.
2. A decreased urinary output: In space, the lack of gravity reduces the hydrostatic pressure in the lower body, which affects fluid balance and renal function.
3. A decreased muscle tone: The absence of gravity-related stress on muscles reduces the need for muscular exertion, causing muscle fibers to weaken and decrease in size.
4. A decreased blood volume: During space travel, the body undergoes fluid shifts due to the redistribution of fluids from the lower body to the upper body. This redistribution can result in a decrease in total blood volume as the fluid accumulates in the upper body, leading to a decrease in overall blood volume.
5. An elevated cardiac output: In response to the fluid shifts and reduced gravity, the cardiovascular system adapts by increasing the cardiac output.
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what has the greatest effect on refraction?
Answer:
Which eye structure has the greatest effect on light refraction? ... They are the ciliary muscle, which controls the shape of the lens for accommodation, and the iris, the pigmented ring of muscles that regulates the amount of light entering the eye.
Explanation:
Benjamina started her walk from the front door of her ground-floor apartment. She walked 6 meters to the corner of the building and then turned the corner and walked 10 meters to her friend’s apartment. Identify the difference between the distance she walked and her displacement.
Answer:
The change in her position (from beginning to end), along with the direction, is considered her displacement.
Explanation:
Answer:
The change in her position ( from beginning to end), along with the direction, is considered her displacement. This value is a measurement and a direction. The total distance along the path from her starting point to her endpoint is considered her distance. This value is a measurement only.
Which of the following industries is the largest producer of primary air pollutants in the United States?
The largest producer of primary air pollution in the United States is what? electricity producing plants.
Answer:
electricity production
Explanation:
A polar bear walks 2.5 meters to the right and then back to the left to exactly where he started his displacement would be
Saturn’s bright rings are located within the roche limit of saturn. This supports the theory that these rings:.
This supports the theory that these rings are formed from moons torn apart by tidal stress.
Write about planet saturn?After Jupiter, the second-largest planet in the Solar System is Saturn. It's a giant planet with a radius around nine and a half times that of the Earth.
Saturn is only one-eighth the average density of Earth, yet it is 95 times more massive due to its bigger volume.
Saturn’s bright rings are located within the Roche limit of Saturn. This supports the theory that these rings are formed from moons torn apart by tidal stress.
Hence this supports the theory that these rings are formed from moons torn apart by tidal stress.
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If a 0.3% decrease in the price of a good causes its quantity supplied to decrease by 1%, then the supply is: A. Unit elastic B. Elastic C. Inelastic D. Perfectly inelastic
If a 0.3% decrease in the price of a good causes its quantity supplied to decrease by 1%, then the supply is C. Inelastic.
In this scenario, the supply of the good is considered inelastic. The elasticity of supply measures the responsiveness of the quantity supplied to changes in price. When the price of a good decreases, and the quantity supplied decreases by a larger percentage, it indicates that the supply is relatively unresponsive to price changes.
To determine the elasticity of supply, we compare the percentage change in quantity supplied to the percentage change in price. In this case, a 0.3% decrease in price results in a 1% decrease in the quantity supplied. Since the percentage change in quantity supplied (1%) is greater than the percentage change in price (0.3%), the supply is considered inelastic.
Inelastic supply means that producers are less responsive to price changes, and a small change in price leads to a proportionally smaller change in quantity supplied. In such cases, producers may find it challenging to adjust their output levels quickly in response to price fluctuations.
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ts, x and y, move toward one another and eventually collide. object x has a mass of 2m and is moving at a speed of 2v0 to the right before the collision. object y has a mass of m and is moving at a speed of v0 to the left before the collision. which of the following describes the magnitude of the forces f the objects exert on each other when they collide?
They will accelerate the same amount but in opposite directions. In physics, a collision is any event wherein or greater our bodies exert forces on each other in a pretty brief time.
The mean loose time for a molecule in a fluid is the common time between collisions. The imply unfastened path of the molecule is made of the average velocity and the mean unfastened time. These principles are used inside the kinetic concept of gases to compute shipping coefficients including viscosity.
Collision, also known as an effect, in physics, is the surprising, forceful coming collectively in direct touch of two bodies, along with, as an example, billiard balls, a golf membership, and a ball, a hammer, and a nail head, two railroad vehicles while being coupled collectively, or a falling item and a ground.
The verb collide has roots in the Latin word collider, which comes from col- or collectively and leader, to strike or harm, like planes that collide in mid-air.
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calculate the 76- kg pilot's effective weight (the force with which the seat pushes up on him) at the bottom of the circle, and at the top of the circle (assume the same speed).
The minimum radius of the circle is 5249m
The 76kg pilot's effective weight at the bottom of the circle is 5214N
The pilot's effective weight at the top the circle is 3724N
Here's the complete question:
a jet pilot takes his aircraft in a vertical loop.
a) if the jet is moving at a speed of 2000 km/h at the lowest point of the loop, determine the minimum radius of the circle so that the centripetal acceleration at the lowest point does not exceed 6.0g's
b) calculate also the 76kg pilot's effective weight ( the force with which the seat pushes up on him) at the bottom of the circle.
c) calculate the pilot's effective weight at the top the circle. (Assume the same speed.)
a) To determine the minimum radius of the circle so that the centripetal acceleration at the lowest point does not exceed 6.0g's.
v =2000 km/h
v = 2000/3.6 m/s
v = 555.6 m/s
centripetal acceleration, a
a = v²/r
Therefore
6g = v²/r
r = v²/(6g)
r =555.6²/(6*9.8)
r = 5249 m
b) The 76kg pilot's effective weight at the bottom of the circle
76*(6g + g) = 76*7*9.8 = 5214 N
c) The pilot's effective weight at the top the circle.
76*(6g-g) = 76*5*9.8 = 3724 N
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An object is placed 96.5 cm from a glass lens(n = 1.55) with one concave surface of radius 23.5cm and one convex surface of radius 19.3 cm . Part A Determine the final image distance from the center of lens. Follow the sign conventions. Express your answer to two significant figures and include the appropriate units. Part B What is the magnification? Follow the sign conventions. Express your answer using two significant figures.
A biconvex lens with one concave surface of radius 23.5cm and one convex surface of radius 19.3 cm and refractive index 1.55 is placed 96.5 cm from an object. The final image distance from the center of the lens is approximately -16.6 cm and the magnification is approximately 0.17.
To solve this problem, we can use the thin lens equation:
1/f = (n - 1)(1/R1 - 1/R2)
where f is the focal length of the lens, n is the refractive index of the lens material, R1 is the radius of curvature of one lens surface, and R2 is the radius of curvature of the other lens surface.
Part A:
First, we need to determine the focal length of the lens using the thin lens equation. We can assume that the lens is thin, which means that its thickness is negligible compared to the distance from the object and the image. Also, since the object is placed at a distance of 96.5 cm from the lens, we can assume that the light rays are nearly parallel to the principal axis.
Using the thin lens equation, we have:
1/f = (n - 1)(1/R1 - 1/R2)
1/f = (1.55 - 1)(1/23.5 - 1/19.3)
f ≈ 19.2 cm
Since the lens is biconvex, we can assume that the focal length is positive. Therefore, the lens is a converging lens.
Now, we can use the lens equation to determine the final image distance from the center of the lens:
1/o + 1/i = 1/f
where o is the object distance from the center of the lens, and i is the image distance from the center of the lens. Using the values given in the problem, we have:
1/96.5 + 1/i = 1/19.2
Solving for i, we get:
i ≈ 16.6 cm
Since the image is formed on the opposite side of the lens from the object, the image distance is negative. Therefore, the final image distance from the center of the lens is -16.6 cm.
Part B:
The magnification of the image is given by:
m = -i/o
where m is the magnification, and the negative sign indicates that the image is inverted relative to the object. Using the values given in the problem, we have:
m = -(-16.6)/96.5
m ≈ 0.17
Therefore, the magnification is approximately 0.17.
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