How do different factors affect solubility? Check all of the boxes that apply.
Increasing temperature decreases the solubility of gases.
Stirring increases the solubility of solids.
Increasing pressure increases the solubility of liquids
Decreasing temperature decreases the solubility of solids.
Increasing pressure increases the solubility of gases.
Decreasing the amount of solvent decreases the solubility of solids, liquids, and gases

The molecular weight of unknown gas : 23.46 g/mol

Given

A vessel contains 10% of oxygen and 90% of an unknown gas.

diffuses rate of mixed gas = 86 s

diffuses rate of O₂ = 75 s

Required

the molecular weight of unknown gas (M)

Solution

The molecular weight of mixed gas :(M O₂=32 g/mol)

\(\tt 0.1\times 32+0.9\times M=3.2+0.9M\)

Graham's Law :

\(\tt \dfrac{r_{O_2}}{r_{mixed~gas}}=\sqrt{\dfrac{M_{mixed}}{M_{O_2}} }\\\\\dfrac{75}{86}=\sqrt{\dfrac{3.2+0.9M}{32} }\\\\0.76=\dfrac{3.2+0.9M}{32}\\\\24.32=3.2+0.9M\\\\21.12=0.9M\rightarrow M=23.46~g/mol\)

At equilibrium, the number of moles of Cl2(g) present is approximately 347.37 mol.

To determine the number of moles of Cl2(g) at equilibrium, we need to use the given equilibrium constant (Kc) and set up an ICE table to track the changes in the reactants and products.

The balanced equation for the reaction is:

CO(g) + Cl2(g) ⇌ COCl2(g)

Let's set up the ICE table:

  CO(g)     +     Cl2(g)     ⇌     COCl2(g)

Initial: 0.3500 0.05500 0

Change: -x -x +x

Equilibrium: 0.3500 - x 0.05500 - x x

Using the equilibrium concentrations in the ICE table, we can write the expression for the equilibrium constant (Kc) as:

Kc = [COCl2(g)] / [CO(g)][Cl2(g)]

Substituting the values into the equation, we have:

1.2 × 10^3 = (0.05500 - x) / [(0.3500 - x)(0.05500 - x)]

Simplifying the equation, we can cross-multiply and rearrange:

1.2 × 10^3 × (0.3500 - x)(0.05500 - x) = 0.05500 - x

Expanding and rearranging, we get:

0 = (1.2 × 10^3 × 0.05500 - 1.2 × 10^3x + 0.05500x) - x

Simplifying further:

0 = 66 - 1.245x + 0.05500x - x

0 = 66 - 0.19x

0.19x = 66

x = 66 / 0.19

x ≈ 347.37

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Answer:

2530 gm

Explanation:

2 in x 2 in x 2in    * 2.54 cm /in * 2.54 cm / in * 2.54 cm /in  * 19.3gm / cm^3 =

2530 gm    (See how all of the units 'cancel out' and you are left with gm?)

The mass of the gold cube is approximately 2.538 kg, which corresponds closely to option B) 3 kg, considering dimensional analysis.

Using dimensional analysis, we'll convert the given measurements to the desired units. Start by converting inches to centimeters: 1 inch = 2.54 cm.

Side length of cube = 2.0 inches × 2.54 cm/inch = 5.08 cm.

Now, calculate the volume of the cube: Volume = (Side length)³ = 5.08 cm × 5.08 cm × 5.08 cm = 131.38 cm³.

Given density = 19.3 g/cm³. Multiply the volume by density to find the mass: Mass = Volume × Density = 131.38 cm³ × 19.3 g/cm³ = 2538.0474 g.

Convert grams to kilograms: Mass in kg = 2538.0474 g × (1 kg / 1000 g) = 2.5380474 kg.

Rounded to three decimal places, the mass is approximately 2.538 kg, which is closest to option B) 3 kg. Note that the options provided seem to have incorrect units.

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The complete question is:

Gold has a density of 19.3 g/cm³. What is the mass, in kg, of a

cube of gold measuring 2.0 inches on each side? Use

dimensional analysis, NOT the density formula.

A) 2.5 kg

B)  3

C) 2.5

D) 3 kg

Answer:

A reaction rate is generally the speed (or rate) at which a chemical reaction takes place. It is usually expressed in terms of volume or a unit of time.

Answer:

the speed at which a chemical reaction takes place

Answer:

3;2

Explanation:

The pressure inside the tire is approximately 1.970796 newtons per square centimeter (N/cm²) when measured in those units.

To convert the pressure from pounds per square inch (psi) to newtons per square centimeter (N/cm²), we need to use the conversion factors between these units.

First, let's convert pounds to newtons:

1 pound = 0.45359237 kilograms

1 kilogram = 9.80665 newtons

Next, let's convert square inches to square centimeters:

1 square inch = 6.4516 square centimeters

Now, we can perform the conversion:

1 psi = (0.45359237 kg) × (9.80665 N/kg) / (6.4516 cm²)

≈ 0.070307 N/cm²

Therefore, the pressure inside the tire of 28.0 psi is approximately equal to 28.0 × 0.070307 N/cm², which is approximately 1.970796 N/cm².

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Answer:

its DDDDDDDDDDDDDDDDDD

The structure that is least likely to exist is HS.

Sulfur is an element in group 16. Sulfur is a divalent element that has two lone pairs of electrons. This means that sulfur forms compounds in which it is bonded to two atoms or groups.

All the molecules listed can exist because they consists of structures in which sulfur is bonded to two atoms or groups. The only structure that can not exist is HS because it does not satisfy the valency of sulfur.

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Answer:

the electrode at the center of a plasma ball emits a high-frequency,high-voltage alternating electric current. This current flows through the plasma filaments to create colorful tendrils of light.

Explanation:

what colors depend upon the gases used inside the plasma ball? common gases include neon, argon, xenon, and krypton.

Answer:

24.31 g/mol.

Explanation:

moles =mass/molar mass

n=w/m

Precision relates to the consistency and reproducibility of measurements, while accuracy reflects how close measurements are to the true value.

Precision and accuracy are two important concepts in the context of errors in measurements. While they both pertain to the quality of data, they refer to different aspects.

Precision refers to the degree of consistency or reproducibility in a series of measurements. It reflects the scatter or spread of data points around the average value. If the measurements have low scatter and are tightly clustered, they are considered precise. On the other hand, if the measurements have a high scatter and are widely dispersed, they are considered imprecise.

Accuracy, on the other hand, refers to the closeness of measurements to the true or target value. It represents how well the measured values align with the actual value. Accuracy is achieved when measurements have a small systematic or constant error, which is the difference between the average measured value and the true value.

Errors in measurements can be classified into two types: random errors and systematic errors.

Random errors are associated with the inherent limitations of measurement instruments or fluctuations in the measurement process. They lead to imprecise data and affect the precision of measurements. Random errors can be reduced by repeating measurements and calculating the average to minimize the effect of individual errors.

Systematic errors, on the other hand, are caused by consistent biases or inaccuracies in the measurement process. They affect the accuracy of measurements and lead to a deviation from the true value. Systematic errors can arise from factors such as instrumental calibration issues, environmental conditions, or experimental techniques. These errors need to be identified and minimized to improve the accuracy of measurements.

In summary, precision refers to the degree of consistency or reproducibility of measurements, while accuracy refers to the closeness of measurements to the true value. Random errors affect precision, while systematic errors affect accuracy. To ensure high-quality measurements, both precision and accuracy need to be considered and appropriate techniques should be employed to minimize errors.

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Answer:

D

Explanation:

there is no other answer choice that does not move. This is a fool-proof question because all the other answer choices contain movement except the butterfly resting

Answer:

Coevalent

Explanation:

Because I am smart

Answer:

what are the options?

Explanation:

Answer:

What's the gas given in the question??

The potential energy is 84.366 J.

We know that,  potential energy is PE= mgh

PE= 5.0 * 9.81 * 1.72

PE= 84.366 J

Potential energy is a form of stored energy that is dependent on the relationship between different system components. When a spring is compressed or stretched, its potential energy increases. If a steel ball is raised above the ground as opposed to falling to the ground, it has more potential energy. It is capable of performing more work when raised. Potential energy is a characteristic of systems rather than of particular bodies or particles; for instance, the system made up of Earth and the elevated ball has more potential energy as they become further apart.

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Answer: d=m/v

Explanation: The formula for density is d = M/V, where d is density, M is mass, and V is volume. Density is commonly expressed in units of grams per cubic centimetre.

The term that the scientist would use in this case is partial pressure. Option D

The pressure that one particular gas component within a mixture of gases exerts is referred to as partial pressure. It is the pressure that the gas would experience at the same temperature if it were the only thing in the entire volume.

When researching gas mixtures, such as in gas laws, gas phase equilibria, and gas collecting methods, partial pressures are extremely crucial for the gas.

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Use equation: (C=m/V). Now, the known concentration of copper(ll) ion solution and a colorimeter to produce a cu(ll) ion conc./absorbance calibration curve. you will be able to read its conc. from the curve.

A titration is a technique in which a solution of known concentration is used to determine the concentration of an unknown solution. The titrant (the known solution) is added from a buret to a known quantity of the analyte (the unknown solution) until the reaction is complete.

A calibration curve is a way to identify the concentration of an unknown compound. These curves use data points of known compounds at varying concentrations, and researchers or developers can use these curves to find where an unknown substance plots.

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Below is a diagram of the alkene 2-methyl-2-butene:

CH3   CH3

 \   /

  C=C

 /   \

H     H

Part 1: A one-step procedure utilising the Wittig reagent

With the aid of a Wittig reagent, we may carry out the following reaction to produce 2-methyl-2-butene in a single step:

Ph3P=CHCH3 + CH3CH2C(CH3)2Br → CH3CH2C(CH3)2CH=CHCH3 + Ph3PBr Here, the alkyl halide CH3CH2C(CH3)2Br and the Wittig reagent Ph3P=CHCH3 combine to produce the desired alkene 2-methyl-2-butene and Ph3PBr as a byproduct.

Part 2: Organometallic reagent-based two-step sequence

The following processes can be used to produce 2-methyl-2-butene in two steps using an organometallic reagent:

Step 1: Grignard Reaction

CH3MgBr + CH3CH2C(CH3)2Br → CH3CH2C(CH3)2CH2MgBr

Here, the alkyl halide CH3CH2C(CH3)2Br and the Grignard reagent CH3MgBr (methyl magnesium bromide) react to form the equivalent Grignard reagent, CH3CH2C(CH3)2CH2MgBr.

Step 2: Aldehyde or ketone reaction

CH3CH2C(CH3)2CH2MgBr + CH3CHO → CH3CH2C(CH3)2CH=CHCH3 + MgBr(OCH3)

The proton transfer that results in the creation of an enolate is followed by the formation of a magnesium alkoxide intermediate in the reaction process. Following the enolate's attack on the aldehyde's electrophilic carbon, a proton transfer and the removal of the leaving group produce the desired alkene result.

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The change that causes bubbles is a Physical change, because heat only changes the attractions of the molecules.

The heat gives more energy to the molecules causing them to move faster and break their bonds, going from a liquid to a gaseous atate.

Answer:

\(1)20 \\ 2)13 \\ 3)82 \\ 4)56 \\ 5)26 \\ 6)1 \\ hope \: it \: helps \\ plzzz \: mark \: it \: as \: brainliest...\)

Answer:

The answer is a messy model.

Explanation:

It's not a limitation, only an inconvenience. Something that's not really neat is still useful. Hope I helped!

Answer:

Explanation:

Yes

Answer:

bleaching powder, white or nearly white powder that is usually a mixture of calcium chloride hypochlorite, CaCl (OCl); calcium hypochlorite, Ca (OCl) 2; and calcium chloride, CaCl 2. Sometimes called chloride of lime, it can be prepared by reacting calcium hydroxide or slaked lime, Ca (OH) 2, with chlorine gas, Cl 2.

Explanation:

For Test One, phenotype ratio is Short fur : Long fur = 2 : 0; For Test Two, the phenotype ratio is Short fur : Long fur = 3 : 1; For Test Three, the phenotype ratios will be Short fur : Long fur = 0 : 2

For Test One:

Parent 1: FF (homozygous dominant for short fur)

Parent 2: Ff (heterozygous for short fur)

The Punnett square for this cross will give the following genotype ratios:

FF : Ff = 1 : 1

And the corresponding phenotype ratios will be:

Short fur : Long fur = 2 : 0 or 100% short fur

For Test Two:

Parent 1: Ff (heterozygous for short fur)

Parent 2: Ff (heterozygous for short fur)

The Punnett square for this cross will give the following genotype ratios:

FF : Ff : ff = 1 : 2 : 1

And the corresponding phenotype ratios will be:

Short fur : Long fur = 3 : 1 or 75% short fur and 25% long fur

For Test Three:

Parent 1: ff (homozygous recessive for long fur)

Parent 2: ff (homozygous recessive for long fur)

The Punnett square for this cross will give the following genotype ratios:

ff : ff = 1 : 0

And the corresponding phenotype ratios will be:

Short fur : Long fur = 0 : 2 or 100% long fur

For this investigation, the test variable is the breed of hamster and the outcome variable is the phenotype of the hamster.

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Answer:

a. 2.41 g

Explanation:

First we calculate the number of lithium ion moles (Li⁺) in the solution, multiplying the concentration times the volume:

500 mL ⇒ 500 / 1000 = 0.500 L

Then we convert moles of Li⁺ to moles of Li₃PO₄, keeping in mind that for each mole of Li₃PO₄ there are 3 Li⁺ moles:

Finally we convert Li₃PO₄ moles to grams, using its molar mass:

The mass of lithium phosphate, Li₃PO₄ required to prepare the solution is 2.41 g

The correct answer to the question is Option A. 2.41 g

We'll begin by calculating the concentration of Li₃PO₄. This can be obtained as follow:

Li₃PO₄(aq) —> 3Li⁺(aq) + PO₄³¯(aq)

From the balanced equation above,

3 moles of Li⁺ is present in 1 mole of Li₃PO₄.

Therefore,

0.125 M Li⁺ will be present in = 0.125 / 3 = 0.0417 M Li₃PO₄.

Thus, the concentration of Li₃PO₄ is 0.0417 M

Molarity of Li₃PO₄ = 0.0417 M

Volume = 0.5 L

Mole = Molarity x Volume

Mole of Li₃PO₄ = 0.0417 × 0.5

Mole of Li₃PO₄ = 0.02085 mole

Molar mass of Li₃PO₄ = (3×7) + 31 + (16×4) = 116 g/mol

Mass = mole × molar mass

Mass of Li₃PO₄ = 0.02085 × 116

Thus, the mass of Li₃PO₄ required to prepare the solution is 2.41 g

The correct answer to the question is Option A. 2.41 g

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