How can the knowledge of a material’s chemical makeup or use be utilized?
A. To classify minerals
B. To identify minerals
C. To determine the color of the minerals
D. To determine how to break down minerals

Answer:

B i think

Explanation:

Statement a is true, as the melting points of saturated fatty acids do increase with increasing chain length. Statement b is false, as saturated fatty acids do not contain double bonds. Statement c is false, as △9, 12-all cis, 18:3 represents alpha-linolenic acid, not linoleic acid. Statement d is true, as glycerol is indeed a by-product of the hydrolysis of fats.

a. True. The melting points of saturated fatty acids increase with increasing chain length. This is because longer fatty acid chains have stronger intermolecular forces, such as van der Waals forces, which require more energy to break and result in higher melting points.

b. False. Saturated fatty acids do not have double bonds. They are composed of only single carbon-carbon bonds. Double bonds are found in unsaturated fatty acids.

c. False. △9, 12-all cis, 18:3 is not linoleic acid. It represents the structure of alpha-linolenic acid. Linoleic acid is △9, 12-18:2, which means it has two double bonds located at the 9th and 12th carbon positions.

d. True. A by-product of the hydrolysis of fats is glycerol. When fats undergo hydrolysis, they are broken down into their constituent fatty acids and glycerol. Glycerol is a three-carbon molecule that is a component of triglycerides (fats).

During hydrolysis, the ester bonds between the fatty acids and glycerol are cleaved, resulting in the release of fatty acids and glycerol.

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Answer:

B. homogeneous mixture/solution

The density (in g/cm³) of a cube of metal that is 2 inches on a side and weighs 444.5 grams is 3.4 g/cm³ (1st option)

First, we shall obtain the volume of the metal. Details below:

Volume = L³

Volume = 5.08³

Volume = 131.1 cm³

Finally, we shall obtain the density of the metal. Details below:

Density = mass / volume

Density of metal = 444.5 / 131.1

Density of metal = 3.4 g/cm³

Thus, we can conclude from the above calculation that the density of the metal is 3.4 g/cm³ (1st option)

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Complete question:

What is the density (in g/cm³) of a cube of metal that is 2 inches on a side and weighs 444.5 grams?

3.4 g/cm³

8.89 g/cm³

55.56 g/cm³

0.180 g/cm³

Answer: The particles are moving fast but close together.

Answer:

its in the explanation.

Explanation:

1.In liquids, particles are quite close together and move with random motion throughout the container. Particles move rapidly in all directions but collide with each other more frequently than in gases due to shorter distances between particles.

2.It assumes the shape of the part of the container which it occupies particles can move/slide past one another.

Hope this helps. :)

Answer:

Explanation:

Atoms are the basic building blocks of ordinary matter. Atoms can join together to form molecules, which in turn form most of the objects around you. ... A particular atom will have the same number of protons and electrons and most atoms have at least as many neutrons as protons.

To determine the number of moles in each substance, we need to divide the mass of the substance by its molar mass.

67.42 g Si:

The molar mass of Si is 28.0855 g/mol (rounded to 4 decimal places). Therefore, the number of moles of Si is:

67.42 g / 28.0855 g/mol = 2.3992 mol (rounded to 4 decimal places).

11.82 g gold:

The molar mass of gold is 196.9665 g/mol (rounded to 4 decimal places). Therefore, the number of moles of gold is:

11.82 g / 196.9665 g/mol = 0.060 mol (rounded to 3 decimal places).

28.8 g Br₂:

The molar mass of Br₂ is 159.808 g/mol (rounded to 3 decimal places). Therefore, the number of moles of Br₂ is:

28.8 g / 159.808 g/mol = 0.1803 mol (rounded to 4 decimal places).

Therefore, the number of moles in each substance is:

2.3992 mol Si

0.060 mol gold

0.1803 mol Br₂.

Mercury(II) oxide, a red solid, decomposes when heated to produce mercury and oxygen gas. Mercury(II) oxide is a red solid. When it is heated, it decomposes into mercury metal and oxygen gas. A reaction is also considered to be a decomposition reaction even when one or more of the products are still compounds.

Answer:

2HCl is the product of this reaction 2 is added in order to balance the reaction

Answer:

aluminium has 13 protons,13 electron,and 14 neutron.

Explanation:

she is right

The number of protons in the nucleus of an aluminum neutral atom is equal to 13.

A neutral atom can be demonstrated as one in which the number of protons is equal to the number of electrons ( negative charge ). The net electric charge of a neutral atom equals zero. Therefore, this kind of atom is referred to as a neutral atom.

For a neutral atom, we usually say that the number of electrons will be equal to the number of protons. All elements organized in the modern periodic table are in a neutral state.

The given atomic number of Al is 13. The number of electrons in the atom is equal to 13 and the valence electron is filled in its electron shell so it is the element of the 3rd period.

The atomic number of Al atom = 13

The number of electrons = number of protons = 13

Therefore, the protons in the neutral atom of Al are equal to 13.

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Answer:

Anaerobic metabolism

Overview. Anaerobic metabolism is the creation of energy through the combustion of carbohydrates in the absence of oxygen. This occurs when your lungs cannot put enough oxygen into the bloodstream to keep up with the demands of your muscles for energy.

Explanation:

Answer:

6CO2 + 6H2O → C6H12O6 + 6O2 is a balanced equation

Explanation:

Carbon, Oxygen, Hydrogen

Reactants are carbon dioxide and water, products are glucose and oxygen

Dynamic Equilibrium I have no idea about (soz)

I believe this might be endothermic

2) The heat capacity of aluminum is 219.44 J/mol.°C.

3) a) the experimental ΔHs of ice is -0.154 kJ/mol.

b) too high

Calculate the heat released by the aluminum:

q = mcΔT

where q = heat released, m = mass of aluminum, c = specific heat capacity of water and ΔT = change in temperature.

q = (24.7 g) (0.903 J/g°C) (100.0°C - 23.4°C)

q = 18643.26 J

Next, calculate the heat absorbed by the calorimeter:

q = mcΔT

q = (99.5 g + 24.7 g) (15.8 J/°C) (23.4°C - 19.5°C)

q = 4009.92 J

The heat released by the aluminum is equal to the heat absorbed by the calorimeter and water:

18643.26 J = 4009.92 J + q3

where q3 = heat absorbed by the water.

q3 = 14633.34 J

Calculate the molar heat capacity of aluminum:

Cp,m = q3 / (nΔT)

where Cp,m = molar heat capacity, n = number of moles of aluminum, and ΔT = change in temperature.

n = m / M

where m = mass of aluminum and M = molar mass of aluminum (26.98 g/mol).

n = 24.7 g / 26.98 g/mol

n = 0.916 mol

Cp,m = 14633.34 J / (0.916 mol * 76.6°C)

Cp,m = 219.44 J/mol.°C

Therefore, the heat capacity of aluminum is 219.44 J/mol.°C.

3) (a) To calculate the experimental ΔHs of ice, we first need to calculate the heat gained by the water and the heat lost by the ice during the process.

Heat gained by water = mass of water × specific heat capacity of water × change in temperature

= 100.0 g × 4.184 J/g·°C × (-20.1°C)

= -8,423.84 J

Heat lost by ice = mass of ice × heat of fusion of ice

= 25.6 g × 6.01 kJ/mol

= 154.496 J

Since the process is assumed to be adiabatic (no heat exchange with the surroundings), the heat gained by the water must be equal to the heat lost by the ice.

Thus, -8,423.84 J = 154.496 J = -8,269.344 J

The negative sign indicates that the process is exothermic. Therefore, the experimental ΔHs of ice is:

ΔHs = -154.496 J/mol = -0.154 kJ/mol

(b) If the student forgets to include the calorimeter term in the calculation, the calculated ΔHs of ice will be too high. This is because the heat absorbed by the calorimeter during the process is not accounted for, leading to an overestimation of the heat gained by the water and underestimation of the heat lost by the ice.

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0.044 mol CaOH

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

2.5 g CaOH

Step 2: Identify Conversions

[PT] Molar Mass of Ca - 40.08 g/mol

[PT] Molar Mass of O - 16.00 g/mol

[PT] Molar Mass of H - 1.01 g/mol

Molar Mass of CaOH - 40.08 + 16.00 + 1.01 = 57.09 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

0.043791 mol CaOH ≈ 0.044 mol CaOH

Answer:65

Explanation:

Answer:

If 2 half-lives have passed, it means that the radioactive substance has decayed twice, so the number of remaining atoms would be:

1st half-life: 400,000 / 2 = 200,000 atoms remaining

2nd half-life: 200,000 / 2 = 100,000 atoms remaining

Therefore, after 2 half-lives have passed, 100,000 atoms would remain, rounded to the nearest whole number

Explanation:

IF U NEED FURTHER HELP AND WANT TO BE FRIEND , SN AP = m_oonlight781

Answer: A

Explanation:

The -ane suffix implies that the compound has only single bonds for carbon-carbon bonds. The but- prefix implies that the compound consists of four carbons. Since 4 bonds are required for each carbon, there will be a total of 10 hydrogen atoms: 3 on each carbon at the end of the chain and 2 for each carbon in the middle of the chain. Thus, butane is A.

The molar mass of MgCrO4 is approximately 140.30 g/mol.

To determine the molar mass of MgCrO4 (magnesium chromate), we need to calculate the sum of the atomic masses of each individual element in the compound.

The chemical formula MgCrO4 indicates that the compound consists of one magnesium atom (Mg), one chromium atom (Cr), and four oxygen atoms (O).

The atomic masses of the elements can be found on the periodic table:

Magnesium (Mg) has an atomic mass of approximately 24.31 g/mol.

Chromium (Cr) has an atomic mass of around 51.99 g/mol.

Oxygen (O) has an atomic mass of about 16.00 g/mol.

Now, we can calculate the molar mass of MgCrO4 by summing up the atomic masses of each element, considering the respective subscripts:

Molar mass = (Atomic mass of Mg) + (Atomic mass of Cr) + 4 × (Atomic mass of O)

Molar mass = (24.31 g/mol) + (51.99 g/mol) + 4 × (16.00 g/mol)

Molar mass = 24.31 g/mol + 51.99 g/mol + 64.00 g/mol

Molar mass ≈ 140.30 g/mol

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Answer:

because the water would diloute the chemicals in the vinegar

Explanation:

To solve this problem, we need to consider the energy required to warm the ice cube from -18.5°C to 0°C, the energy required to melt the ice cube, and the energy required to warm the melted water from 0°C to 55°C. Let's calculate the energy for each step and determine the number of ice cubes needed.

Warming the ice cube to 0°C:

The specific heat capacity of ice is 2.05 J/g°C. The temperature change is from -18.5°C to 0°C. Therefore, the energy required to warm the ice cube can be calculated as:

Energy = mass × specific heat capacity × temperature change

Energy = 24 g × 2.05 J/g°C × (0°C - (-18.5°C))

Energy = 24 g × 2.05 J/g°C × 18.5°C = 899.4 J

Melting the ice cube:

The heat of fusion (specific latent heat of fusion) of water is 334 J/g. We need to determine the energy required to melt the ice cube. The mass of the ice cube is 24 g, so the energy required can be calculated as:

Energy = mass × heat of fusion

Energy = 24 g × 334 J/g = 8016 J

Warming the melted water from 0°C to 55°C:

The specific heat capacity of water is 4.184 J/g°C. We need to determine the energy required to warm the melted water from 0°C to 55°C. The mass of the melted water can be calculated by subtracting the mass of the ice cube that melted from the initial mass of the ice cube (24 g).

Mass of melted water = 24 g - 24 g = 0 g (since all the ice melted)

Therefore, no additional energy is required for this step.

Now, let's add up the energy required for each step to determine the total energy needed to cool the coffee from 85°C to 55°C:

Total energy required = Energy to warm the ice cube to 0°C + Energy to melt the ice cube

Total energy required = 899.4 J + 8016 J = 8915.4 J

Given that each ice cube provides 8915.4 J of energy, we can determine the number of ice cubes needed to cool the coffee.

Energy per ice cube = 8915.4 J

Energy required to cool the coffee = Total energy required = 8915.4 J

The number of ice cubes needed = Energy required to cool the coffee / Energy per ice cube

Number of ice cubes needed = 8915.4 J / 8915.4 J = 1

Therefore, you would need to add 1 ice cube to your 355 mL cup of coffee to bring it to 55°C.

The correct answer is A. 1.

The new volume of the gas whose pressure was changed would be = 40 milliliters.

The initial volume(V1)of the gas= 20ml

The initial pressure(P1) = 4 atm

The final pressure(P2) = 2 atm

The final volume(V2) = ?

Using the general gas formula;

P1V1 = P2V2

V2 = P1V1/P2

= 4×20/2

= 40ml

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Answer:

The answer is option c.

I hope this helps you.

Answer:

it's mass

Explanation:

just trust me it's just mass

There is a rule the is usually followed when making the most stable electronic congifuration of elements.

It is as follows:

Where we from up to down following the arrows. s means it can hold up to 2 electrons, p can hold up to 6 and d can hold up to 10.

Palladium has atomic number 46, so, in its neutral form, it has 46 electrons.

We start by putting 2 into 1s, to get 1s².

The next 2 goes to 2s, to make 1s²2s².

Then, we go to 2p, so we can put 6 now to get 1s²2s²2p⁶.

For now, we have used 10 of the 46 electrons, so we need to continue.

Next we have 3s then 3p, so we get 1s²2s²2p⁶3s²3p⁶.

Then, we have 4s, so we have 1s²2s²2p⁶3s²3p⁶4s².

Now, we need to go to 3d, which hold up to 10 electrons. We used so far 20 electrons, so we can continue. We put 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰.

Next we 4p and 5s, so we get 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s².

We have used 38 of the electrons so we only have 8 left. The next is 4d, but since we only have 8 electrons left, we can fill only up to 8, to get 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d⁸.

So, the final electron configuration is 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d⁸

The mass percentage of C in morphine would be 4.21%.

The mass percentage of a composition in a compound is the mass of the composition relative to the mass of the entire compound. This can be mathematically expressed as:

Mass percentage = mass of component/mass of substance x 100%

In this case, we are looking for the mass percentage of C in \(C_{17}H_{19}NO_3\).

Molar weight of C = 12 g/mol

Molar mass of  \(C_{17}H_{19}NO_3\) = (12x17) + (1x19) + (14x1) + (16x3)

                                             = 285 g/mol

Mass percentage of C = 12/285

                                     = 4.21% to 2 decimal places.

In other words, the mass percentage of C in morphine is 4.21%.

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Approximately 166.67 mL of water needs to be evaporated from 250 mL of 1 M Ca(OH)2 to make it 3 M.

The relationship between the initial and final concentrations and volumes must be taken into account.

Given: Initial concentration \((C^1) = 1 M Initial volume (V^1) = 250 mL\)

\((C^2) = 3 M final concentration\)

We can use the equation:

\(C^1 * V^1 = C^2 * V^2\)

Where:

\(V^2\)is the final volume of the solution

Rearranging the equation to solve for V2:

\(V^2 = (C^1 * V^1) / C^2\)

Substituting the given values:

\(V^2 = (1 M * 250 mL) / 3 M\)

\(V^2 = 250 mL / 3\)

\(V^2\) ≈ \(83.33 mL\)

To find the amount of water that needs to be evaporated, we subtract the final volume from the initial volume:

Amount of water to be evaporated = \(V^1 - V^2\)

Amount of water to be evaporated = 250 mL - 83.33 mL

Amount of water to be evaporated ≈ 166.67 mL

Therefore, approximately 166.67 mL of water needs to be evaporated from 250 mL of 1 M Ca(OH)2 to make it 3 M.

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The mass of the precipitate formed when 50mL of 16.9% (w/v) solution of AgNO 3 is mixed with 50mL of 5.8% (w/v) NaCl solution is 7.19 g.

Let's calculate the number of moles of NaCl:

Number of moles = Mass(g)/Molecular mass

Number of moles of NaCl = 50×5.8/100/58.5

= 50×5.8/100×58.5

= 0.05 mole

The mass of AgCl can be calculated by referring to Equation 1.

By applying POAC on Ag

Number of moles Ag in AgNO3 = Number of moles Ag in AgCl

Number of moles of AgCl = 0.05mole…(ii)

Molecular mass of AgCl = 143.5………..(iii)

Mass of AgCl = Number of moles × Molecular mass of AgCl ………(iv)

Substitute (ii) and (iii) in (iv)

= 0.05 × 143.5

= 7.16g

The mass of an object is a measure of its inertial properties or the amount of matter it contains. The weight of an object is a measure of the force exerted on it by gravity, or the force required to support it. Mass can best be understood as the amount of matter present in an object or body. Everything around us has mass.

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