How can electronegativity be used to explain the reaction we see in terms of the numbers and types of bonded being formed in lithium?

Answer:

6

Explanation:

bromine has 1, hydrogen has 4 and nitrogen has 1 therefore equaling 6

The number of atoms in NH₄Br is six.

An atom is a particle of matter that uniquely defines a chemical element. An atom consists of a central nucleus that is surrounded by one or more negatively charged electrons. The nucleus is positively charged and contains one or more relatively heavy particles known as protons and neutrons.

Atoms are the basic building blocks of matter. Anything that takes up space and anything with mass is made up of atoms.

In the given formula, there is one N atom, four H atoms and one Br atom making a total of six atoms.

Therefore, the number of atoms in NH₄Br is six.

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To convert a quantity in cm2 to in2, you can use the conversion factor 1 in = 2.54 cm. Here are some examples of how to do this:

Example 1: Convert 100 cm2 to in2
Step 1: Divide the quantity in cm2 by the conversion factor (2.54 cm/in)
100 cm2 / (2.54 cm/in) = 39.37 in2

Example 2: Convert 50 cm2 to in2
Step 1: Divide the quantity in cm2 by the conversion factor (2.54 cm/in)
50 cm2 / (2.54 cm/in) = 19.69 in2

Example 3: Convert 200 cm2 to in2
Step 1: Divide the quantity in cm2 by the conversion factor (2.54 cm/in)
200 cm2 / (2.54 cm/in) = 78.74 in2

Example 4: Convert 75 cm2 to in2
Step 1: Divide the quantity in cm2 by the conversion factor (2.54 cm/in)
75 cm2 / (2.54 cm/in) = 29.53 in2

Remember, to convert cm2 to in2, you divide the quantity in cm2 by the conversion factor 2.54 cm/in.

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Direct contact between objects causes conduction or heat transfer. The heat is transferred inside the fluid during convection. Heat transfer in radiation happens by electromagnetic waves without the use of particles.

First, ascertain whether the two things are in contact. If they are, conduction is how heat is transferred between them. Determine whether there is a fluid medium, such as a liquid or gas, connecting the items if they are not in contact.

Evidence of heat transport is apparent. Convection is the phenomenon that causes the air to shimmer over radiators. Conduction is the phenomenon that causes you to feel warm when you place your hand on a spoon that has been sitting in a hot bowl of soup (radiation).

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Answer:

precipitation occur

Explanation:

the solute do not dissolve in water

a common colligative property that is explored in many experiments and real-life applications is the freezing point depression.

Freezing point depression is a colligative property that depends on the number of solute particles in a solution, but not on their identity or chemical properties. When a solute is added to a solvent, it lowers the freezing point of the solution compared to the pure solvent. This is because the presence of solute particles disrupts the crystal lattice structure of the solvent, making it more difficult for the solvent molecules to arrange themselves in an ordered manner and form ice crystals. As a result, a solution will freeze at a lower temperature than the pure solvent.

Freezing point depression is a useful colligative property in many applications, such as in antifreeze solutions used in automobiles and in the preservation of food and biological samples by freezing. It is also commonly explored in chemistry experiments, where it can be used to determine the molecular weight of an unknown solute by measuring the freezing point depression of a known solvent-solute solution.
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A. the expansion occurs isothermally and reversibly -27.9 J/K mol, the expansion occurs isothermally against a constant external pressure of 1.00 atm. -27.9 J/K mol and the expansion occurs adiabatically and reversibly 37.1 ln(T f/300) J/K mol.

Pressure is the force applied perpendicular to the surface of an object per unit area. It is typically measured in units of Pascals (Pa) or pounds per square inch (psi). Pressure is an important concept in many fields such as physics, engineering, and fluid mechanics.

a. ds = R ln(P f/P i) = R ln (1/5) = -27.9 J/K mol

ds surr = 0 J/K mol

ds univ = -27.9 J/K mol

b. ds = R ln(P f/P i) = R ln(1/5) = -27.9 J/K mol

ds surr = 0 J/K mol

ds univ = -27.9 J/K mol

c. ds = cp ln(T f/Ti ) = 37.1 ln(T f/300) J/K mol

ds surr = 0 J/K mol

ds univ = 37.1 ln(T f/300) J/K mol

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The modify in include up to entropy (ΔS_univ) is the aggregate of the entropy changes of the system and the environment, so ΔS_un

a. Isothermal and reversible advancement:

In an isothermal handle, the temperature remains relentless. Since CO2 carries on in a culminated world, we are ready to utilize the ideal gas law: PV = nRT, where P is the weight, V is the volume, n is the number of moles, R is the ideal gas steady, and T is the temperature.

In this case, the beginning conditions are P1 = 5.00 atm, V1 (beginning volume) darkens, n = 1.00 mole, and T = 300 K. The extreme conditions are P2 = 1.00 atm and V2 (final volume) is cloud.

Since the strategy is reversible, the alter in entropy (ΔS) is given by ΔS = nR ln(V2/V1). Utilizing the ideal gas law, we are going forward with it as ΔS = nR ln(P1/P2).

Utilizing the values, we have ΔS = (1.00 mole) * (8.314 J K^(-1) mol^(-1)) * ln(5.00 atm/1.00 atm) = 9.21 J K^(-1).

Since the expansion is isothermal, there's no temperature differentiate between the system and the environment, so ΔS_surr = 0.

The modify in add up to entropy (ΔS_univ) is the complete of the entropy changes of the system and the environment, so ΔS_univ = ΔS + ΔS_surr = 9.21 J K^(-1).

b. Isothermal improvement against a unfaltering exterior weight:

In this case, the exterior weight is reliable and rise to to the extreme weight (1.00 atm). The strategy is still isothermal, so the temperature remains reliable.

Utilizing the same condition as in parcel a, we have ΔS = nR ln(P1/P2). Ceasing inside the values, we get ΔS = (1.00 mole) * (8.314 J K^(-1) mol^(-1)) * ln(5.00 atm/1.00 atm) = 9.21 J K^(-1).

Since the expansion is against a steady exterior weight, the environment do work on the system, and the surroundings' entropy modify (ΔS_surr) is given by ΔS_surr = -w_surr/T, where w_surr is the work done by the environment. In this case, since the strategy is isothermal, the work done is w_surr = -PΔV = -PΔnRT.

Change in enthropy (ΔS) = -(1.00 atm) multiplied by (1.00 mole) multiplied by (8.314 J K^(-1) mol^(-1)) multiplied by ln(5.00 atm/1.00 atm) / 300 K = -0.0308 J K^(-1).

The change in entropy (ΔS_univ) = 9.18 J K^(-1).

c. Adiabatic and reversible expansion:

In an adiabatic handle, there's no warm exchange between the system and the environment, so ΔS = 0.

The change in entropy of the environment (ΔS_surr) in addition since no warm is traded.

The modify in include up to entropy (ΔS_univ) is the aggregate of the entropy changes of the system and the environment, so ΔS_un

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the standard reduction potentials for the half-reactions involved in the reaction. Look up the values in a standard reduction potential table. The standard reduction potentials are as follows:

Calculate the overall standard cell potential (E°cell) by subtracting the standard reduction potential of the anode from the standard reduction potential of the cathode:
E°cell = E°cathode - E°anode

In this case, the cathode is the reduction half-reaction involving Cu2+ and the anode is the oxidation half-reaction involving MnO2. Therefore:
E°cell = (+0.34 V) - (+1.23 V)
E°cell = -0.89 V


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This substance's chemical formula is C₈H₈O₂ and To create the 0.8 M solution, 19.04 g of  MgCl₂ must be dissolved in 250 mL of water.

The chemical formula for a chemical compound's molecular formula lists the variety of atoms that make up the molecule.

Assuming we have 100 g of the molecule, the masses of its constituent parts are as follows in order to get its molecular formula:

-70.6 g of carbon

-5.9 g of hydrogen

-23.5 g of oxygen

We next divide these masses by the molar masses of the constituent components to obtain the moles:

-carbon: 70.6 g / 12 g/mol = 5.88 mol

-hydrogen: 5.9 g / 1 g/mol = 5.9 mol

-oxygen: 23.5 g / 16 g/mol = 1.47 mol

To get the molar ratio, divide the moles by the least number (1.47 mol for oxygen):

-carbon: 5.88 mol / 1.47 mol = 4

-hydrogen: 5.9 mol / 1.47 mol = 4

-oxygen: 1.47 mol / 1.47 mol = 1

As a result, we have the empirical formula:

This empirical formula's molar mass is

4 x 12 g/mol + 4 x 1 g/mol + 16 g/mol = 68 g/mol

In order to arrive at our final result, we divide the molar mass of our compound by the molar mass of the empirical formula.

136 g/mol / 68 g/mol = 2

We multiply the index numbers by 2 to get the molecular formula C₈H₈O₂.

The following equation is used to determine how much MgCl2 is required to make a 0.8 M solution of it in 250 mL (0.250 L):

c = n/V ⇒ n = c * V

c - molarity of the solution (0.8 M)

n - number of moles of solute

V - the volume of the solution

Now we plug in the values we have:

n = 0.8 M * 0.250 L

n = 0.2 mol

Now, we can determine the mass of the solute using the molar mass of MgCl2 (M = 95.211 g/mol):

n = m/M

m = n * M

m - the mass of the substance

m = 0.2 mol * 95.211 g/mol

m = 19.04 g

Therefore, 19.04 g of MgCl2 are required to create a 0.8 M solution in 250 mL.

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Since we are told that O2 is the excess reactant, we need only to focus on C2H6, which will be our limiting reactant. Convert the mass of C2H6 to moles by dividing the mass by the molar mass of C2H6:

(5 g C2H6)(30.069 g/mol) = 0.1663 mol C2H6

Since C2H6 is the limiting reactant, its quantity will determine how much of each product is formed. We are asked to find the number of grams (the mass) of H2O produced. The molar ratio between H2O and C2H6 per the balanced equation is 6:2. That is, for every 6 moles of H2O that is produced, 2 moles of C2H6 is used up (intuitively, then, the number of moles of H2O produced should be greater than the number of moles of C2H6 consumed, specifically 3 times greater).

So, the number of moles of H2O produced would be (0.1663 mol C2H6)(6 mol H2O/2 mol C2H6) = 0.499 mol H2O. We multiply by the molar mass of H2O to convert moles to mass: (0.499 mol H2O)(18.0153 g/mol) = 8.987 g H2O.

Note: If significant figures must be considered, then the answer would be 8.99 g H2O.

Answer:

0.0123 M/s

Explanation:

The reaction rate is the rate at which the reaction takes place and results in an increased concentration of the products. The rate of the reaction is 0.0123 M/s.

The reaction rate is the increase of the concentration of the product with respect to time in seconds. The rate of reaction is given by,

\(\rm rate = \rm \dfrac {\Delta C}{\Delta t}\)

Given,

Change in product concentration = 1.478

Time period = 120 seconds

Substituting values in the above equation:

\(\begin{aligned} \rm rate &= \rm \dfrac {\Delta C}{\Delta t}\\\\& = \dfrac{1.478}{120}\\\\&= 0.0123 \end{aligned}\)

Therefore, option B. 0.0123 M/s is the reaction rate.

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Answer:

option d) is the correct answer

Answer: 316 g

Explanation:

Gold is given as a volume but the answer is asked for as a mass. Use the density of gold to find the mass of gold in 16.39 mL.

16.39 mL x (19.3 g/mL) = 316.327 g = 316 g

Note that the mL cancel and you are left with grams.

Answer:

D) Water is less dense as a liquid than as a solid because of changes in bond structure.

Explanation:

I hope I was able to help!

Have a nice day :)

The correct statements about water is that hydrogen bonding causes water to be strongly cohesive and is less dense as a liquid and solid.

It is bonding in between the hydrogen atom and most electronegative atoms like flourine, chlorine, oxygen atoms, etc.

Hence water is less dense as a liquid than as a solid because of changes in bond structure and hydrogen bonding causes water to be strongly cohesive.

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The grams of H₂ produced, if the chemical reaction produces 129 grams of  AlCl₃ are 2.92 grams. (Option b)

To determine the grams of H₂ produced, we need to use the balanced equation and the molar ratios between AlCl₃ and H₂.

From the balanced equation:

2 moles of AlCl₃ react with 3 moles of H₂

To find the moles of AlCl₃ produced:

129 grams AlCl₃ x (1 mole AlCl₃ / molar mass AlCl₃) = moles of AlCl₃

Now, using the molar ratios, we can determine the moles of H₂ produced:

moles of AlCl₃ x (3 moles H₂ / 2 moles AlCl₃) = moles of H₂

Finally, we can convert the moles of H₂ back to grams:

moles of H₂ x (molar mass H₂ / 1 mole H₂) = grams of H₂

Let's calculate it:

Given:

Mass of AlCl₃ produced = 129 grams

Molar mass of AlCl₃:

Al: 26.98 g/mol

Cl: 35.45 g/mol x 3 = 106.35 g/mol

Total molar mass = 26.98 g/mol + 106.35 g/mol = 133.33 g/mol

Calculations:

moles of AlCl₃ = 129 g AlCl₃ / 133.33 g/mol = 0.9676 moles AlCl₃

moles of H₂ = 0.9676 moles AlCl₃ x (3 moles H₂ / 2 moles AlCl₃) = 1.4514 moles H₂

grams of H₂ = 1.4514 moles H₂ x (2.02 g/mol / 1 mole H₂) = 2.93 grams of H₂

Therefore, the correct answer is b. 2.92 grams.

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The statement "The asthenosphere is solid rock but much warmer than the layer above it" is true because it is closer to the Earth's core, which is the hottest part of the planet.

The asthenosphere is a layer in the Earth's mantle that is located just below the lithosphere. While it is made up of solid rock, it is much warmer than the lithosphere, which is the layer above it. This is due to the fact that the asthenosphere is closer to the Earth's core, which is the hottest part of the planet.

The heat from the core causes the rock in the asthenosphere to become more ductile, or pliable, than the rock in the lithosphere. This ductility allows the asthenosphere to flow and move more easily than the lithosphere. In fact, it is this flow of the asthenosphere that is believed to cause the movement of the tectonic plates, which is responsible for phenomena such as earthquakes, volcanoes, and mountain building.

Despite being solid, the asthenosphere is still able to deform over long periods of time due to its high temperature, making it a unique and important layer in the Earth's mantle.

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Of the following correctly predicts the most likely mode of radioactive decay for the nuclide \(As^{33}_{84}\)

The nuclide \(As^{33}_{84}\) has an atomic number of 33, indicating that it is arsenic. To predict the most likely mode of radioactive decay for \(As^{33}_{84}\), we need to consider its position on the periodic table and the stability of its nucleus

\(As^{33}_{84}\) falls into the category of a stable nuclide since it has a stable atomic number. Stable nuclides do not undergo radioactive decay. Therefore, it is unlikely that \(As^{33}_{84}\) would undergo spontaneous radioactive decay through alpha decay (emitting an alpha particle), beta decay (emitting a beta particle), or gamma decay (emitting gamma radiation). Nuclides that are unstable and undergo radioactive decay typically have atomic numbers higher than the stable region of the periodic table or have an imbalance of protons and neutrons in the nucleus. However, as \(As^{33}_{84}\) is a stable nuclide, it is not expected to undergo any form of radioactive decay. Hence, the most likely mode of radioactive decay for the nuclie \(As^{33}_{84}\) is no decay at all since it is a stable nuclide.

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The carbon nucleophile which attacks molecular bromine in the acid-catalyzed α-bromination of a ketone an acetylide. The Organometallic reagents like those used in the Grignard, Blaise, Reformatsky, and Barbier reactions as well as reactions involving the organolithium reagents and acetylides are frequently used as carbon nucleophiles.

These chemicals are frequently employed in nucleophilic additions. Compounds or intermediates that contain an electron-rich carbon atom are known as carbon-centered nucleophiles because they have the ability to donate an electron pair from that carbon atom to an electrophile. When writing resonance structures, the strong negative nature of a metal-bonded the carbon is apparent.

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Molecules are formed when two or more atoms chemically bond together. In 3H₂(SO)₄, three molecules are present.

Molecules are the smallest unit present in any compound and are formed by a group of atoms. A number denoted in front of the chemical species is the coefficient that represents the number of molecules.

The coefficient present in front of the reactant or the product in a chemical reaction gives the number of the molecules present in a compound. As three is denoted in front of the sulphuric acid, hence will be the number of the molecules.

Therefore, there are three molecules present in sulphuric acid.

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Answer:

Uhm if you're failing the class why are you still using brainly to get answers... Where's your momma boy?

Explanation:

It izzz what it izzz

150, tank, concentration

A tank filled with 1000 liters contains 400 liters of a solution saline A in which 20 kg of salt are dissolved then,

The solution for the concentration rho is 0.12 kg/l.

Therefore, the rate of salt being added to the tank is equal to the rate of salt being removed from the tank.

Using the above formula, the concentration of solution B can be calculated.

Let rho be the concentration of solution B.Concentration of saline A is given bymass of salt/volume of solution = 20/400 = 0.05 kg/l

Concentration of saline A after t minutes of mixing with saline B of concentration rho = (20 + 0.1 * rho * t)/(400 + (t * (5 - 3)))In 1 hour = 60 minutes, concentration = 0.12 kg/l

Therefore, we can say:(20 + 0.1 * rho * 60)/(400 + (60 * (5 - 3))) = 0.12

By solving this equation, we get  rho = 150 kg/m3.

Answer: 150, tank, concentration

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Answer:

300 0.24

600 0.46

900 0.70

1200 0.95

1500 1.20

Explanation: correct on behavior gasses tutorial

The volume of the ball is the same as the volume of fluid that it displaces.

Even though the question is incomplete but i will try to help you the much i can. We have to recall that the volume occupied by the tennis ball is equal to the volume of the water displaced and this offers a convenient way of measuring the volume of solids.

The volume of the tennis ball is obtained by accurately measuring he volume of the water before putting in the tennis ball. The volume of the ball is the same as the volume of fluid that it displaces which is Vb = Vf-Vi

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Answer:

40cm^3
Explanation:
I did this assignment and this was the answer so

Answer:

UF6

Explanation:

The molarity of the solution prepared by dissolving 55.55 g of NH4Cl into enough water to make 250.0 ml of solution is 4.16 M.

To calculate the molarity of a solution, we need to divide the moles of solute by the volume of the solution in liters.

First, we need to calculate the number of moles of NH4Cl:

Molar mass of NH4Cl = 14.01 g/mol (atomic mass of nitrogen) + 4 * 1.01 g/mol (atomic mass of hydrogen) + 1 * 35.45 g/mol (atomic mass of chlorine)

= 14.01 + 4.04 + 35.45

= 53.50 g/mol

Number of moles = mass / molar mass

Number of moles of NH4Cl = 55.55 g / 53.50 g/mol

Number of moles of NH4Cl = 1.04 mol

Now, we can calculate the molarity (M):

Molarity = moles of solute / volume of solution (in liters)

Volume of solution = 250.0 ml = 250.0 ml * (1 L / 1000 ml) = 0.250 L

Molarity = 1.04 mol / 0.250 L

Molarity = 4.16 M

Therefore, the molarity of the solution prepared by dissolving 55.55 g of NH4Cl into enough water to make 250.0 ml of solution is 4.16 M.

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Answer:

The correct option is;

a. Latitude measurement, degrees north and south

Explanation:

The lines of latitude give the measured coordinate of a location towards the north or south in relation to the equator by using a division of surface of the Earth, using 180 imaginary horizontal lines that circles the Earth from the equator to the poles, such that the equator, which is the starting point of the measurement is measured as 0, while at the poles, (north and south) the measurement are 90° each from the equator.

Explanation:

The structure (e.g., extent of branching) determines how the individual polymer molecules can orient (or "pack") in the solid state. This, in turn, influences physical properties such as density, crystallinity, melting point, and strength.Thus this is the relationship between the molecular structure of polypropylene and its macroscopic properties such as strength, flexibility, electrical conductivity, etc

Answer:

Part 1 calcium and strontium have same properties as magnesium because all three are in same group.

Part 2 As atomic number of potassium is 19 so it contains 19 protons and 19 electrons because it is neutral

Potassium has 20 neutrons because its mass is 39

We can find neutron = atomic mass - atomic number

Explanation:

Explanation:

Moles of KCl in new solution = 0.325dm³ * (2.76mol/dm³) = 0.897mol.

Hence volume needed = 0.897mol / (3.95mol/dm³) = 0.227dm³ or 0.227L.