Help these are due today

Answer:

this is a required answer. look it once.

The conjugate base of the acid Nh4+ is ammonia  NH3.

What is conjugate base?

A conjugate base is the base member, X-, of two compounds that convert into one another by acquiring or losing a proton, according to a more comprehensive definition. In a chemical process, the conjugate base has the capacity to either gain or absorb a proton.

The conjugate base's formula is the acid's formula less one hydrogen. The base that reacts changes into its conjugate acid. The conjugate acid's formula is the base's formula plus one hydrogen ion.

Because it gives an H+ ion to the water, NH+4 is the acid. After that, it turns into ammonia (NH3), which is the conjugate base of NH+4.

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Answer:D

Explanation:

Answer:

D

Explanation:

Answer:

A

Explanation: 11/22

Answer: 1. Crest  2. Trough 3. Wave Length 4. Amplitude

Explanation:

Answer:

So what you want to do is to place sulfur on top with the two fluorine's  on the bottom left and right hand side at slight angles. You don't want to make it look interconnected as one whole bond. Draw a single line from each "F" to the "S" to model two fluorine atoms bond to one sulfur atom (Single bond, only one electron is being shared between each).

The oxidation half reaction in the given electrochemical cell is d) Sn → Sn^2+ + 2e^−.

In the given cell, we can identify the oxidation half reaction by observing the change in the oxidation state of the species involved. In this case, the oxidation state of Sn (tin) changes from 0 to +2, indicating that Sn has undergone oxidation. Therefore, the correct oxidation half reaction is the one where Sn loses electrons and forms Sn^2+ ions.

Option d) Sn → Sn^2+ + 2e^− represents the oxidation half reaction, where Sn loses two electrons and forms Sn^2+ ions. The reduction half reaction in this cell is 2H^+ + 2e^− → H2, where two hydrogen ions gain two electrons to form hydrogen gas (H2).

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Answer: Water is SUPER soluble and regarded as an universal solvent because it is polar in nature and dissolves most inorganic solutes and some polar organic solutes to form aqueous solutions.

Explanation:

WATER is a substance which is composed of the elements such as hydrogen and oxygen that are combined in the ratio of 2:1. The physical properties of water include:

--> it is a colourless, odourless and tasteless liquid and

--> the boiling point of water is 100°C(this is due to the presence of hydrogen bonding).

The solubility of a solute in a solvent at a particular temperature is the maximum amount of solute in moles or grams that will saturate 1000 dm³ or grams of the solvent.

Water is regarded as a universal solvent BECAUSE it is capable of dissolving many substances. This solubility helps maintain different processes in life such as acting as the solvent which helps cells transport and use substances like oxygen or nutrients.

0.16 mol of O2 occupies a volume of 4.67 L at 28°C and a pressure of 0.998 atm.

To answer this question, we can use the Ideal Gas Law equation:
PV = nRT
Where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.
First, we need to convert the temperature from Celsius to Kelvin:
T = 28°C + 273.15 = 301.15 K
Next, we can plug in the given values:
(0.998 atm) V = (0.16 mol) (0.08206 L·atm/mol·K) (301.15 K)
Simplifying the equation:
V = (0.16 mol) (0.08206 L·atm/mol·K) (301.15 K) / (0.998 atm)
V = 4.67 L
The volume of a gas is dependent on the number of moles, pressure, and temperature. In this question, we were given the number of moles, pressure, and temperature of O2 gas and were asked to determine the volume it occupies. We used the Ideal Gas Law equation, which relates the variables of a gas to each other. The gas constant R is a proportionality constant that depends on the units used for pressure, volume, and temperature. By rearranging the Ideal Gas Law equation, we were able to solve for the volume. It's important to note that the volume of a gas is directly proportional to the number of moles of gas present. Additionally, the volume of a gas is inversely proportional to the pressure exerted on the gas. Finally, the volume of a gas is directly proportional to the temperature of the gas in Kelvin.

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Answer:

80 MOLES OF WATER ARE PRODUCED WHEN 20 MOLES OF PROPANE ARE BURNED IN EXCESS OXYGEN ON A GAS GRILL.

Explanation:

Equation for the reaction:

C3H8 + 5 O2 --------->  4 H2O + 3 CO2 + Heat

The above equation is in the presence of excess oxygen.

In this reaction,

1 mole of propane forms 4 moles of H2O

If 20 moles of propane were to be used, how many moles of water will be produced?

1 mole of propane = 4 moles of water

20 moles of propane = ( 4 * 20 ) moles of water

= 80 moles of water.

So, if 20 moles of propane were burned in excess oxygen, 80 moles of water will be formed. Propane is heavier than air and when properly combusted produces a large amount of heat. It is also non toxic.

80 MOLES OF WATER are produced when 20.0 moles of propane are burned in excess oxygen on a gas grill.

C₃H₈ + 5 O₂ --------->  4 H₂O + 3 CO₂ + Heat

The above equation is in the presence of excess oxygen.

In this reaction, 1 mole of propane forms 4 moles of H₂O

1 mole of propane = 4 moles of water

20 moles of propane = ( 4 * 20 ) moles of water

20 moles of propane= 80 moles of water.

Thus, if 20 moles of propane were burned in excess oxygen, 80 moles of water will be formed.

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At equilibrium, a significant quantity of starting ketone will be present with the enolate in the first case.

Ketones are substances produced by the liver. It is formed when there is insufficient insulin in the body to turn sugar into energy.

In this case a substantial amount of ketone will exist along side the enolate at equilibrium.


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2-methylpropan-2-ol is a secondary alcohol, the correct answer is option (d)

The term "2-methylpropan-2-ol" refers to a specific type of organic compound that belongs to the alcohol family. The compound is also known by its IUPAC name, which is "2-methylpropan-2-ol."

The "2-methyl" part of the name indicates that the compound contains a methyl group (-CH3) attached to the second carbon atom of the parent chain, which is propane. The "-ol" suffix indicates that the compound belongs to the alcohol family, meaning it contains a hydroxyl group (-OH) attached to one of the carbon atoms in the molecule.

The term "secondary alcohol" refers to the specific type of alcohol that has a hydroxyl group (-OH) attached to a secondary carbon atom, which is a carbon atom that is bonded to two other carbon atoms. In the case of 2-methylpropan-2-ol, the hydroxyl group is attached to the second carbon atom of the parent chain, which is a secondary carbon atom, and thus, it is considered a secondary alcohol.

It is important to note that the classification of alcohols as primary, secondary, or tertiary depends on the number of carbon atoms bonded to the carbon atom bearing the hydroxyl group. Primary alcohols have one carbon atom bonded to the carbon bearing the hydroxyl group, while tertiary alcohols have three carbon atoms bonded to the carbon bearing the hydroxyl group. Therefore the correct option is d.

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Answer: the number of protons minus the number of electrons

Explanation:

The ph for each of the cases in the titration of 50.0 ml of 0.190 m hclo(aq) with 0.190 m koh(aq) is 10.1878.

Case 1  when 0.0 mL of KOH is added Ph is 4.0596

Case 2  when 25.0 mL of KOH is added Ph is 7.398

Case 3  when 35.0 mL of KOH is added Ph is 7.766

Case 4  when 50.0 mL of KOH is added Ph is 10.1878

Case 5  when 60.0 mL of KOH is added Ph is 12.2374

Calculation :

1) .when 0.0 mL of KOH is added

HClO dissociates as:

HClO          ----->     H+   +  ClO-

0.19                 0         0

0.19-x               x         x

Ka = [H+][ClO-]/[HClO]

Ka = x*x/(c-x)

Assuming x can be ignored as compared to c

So, above expression becomes

Ka = x*x/(c)

so, x = sqrt (Ka*c)

x = sqrt ((4*10^-8)*0.19) = 8.718*10^-5

since c is much greater than x, our assumption is correct

so, x = 8.718*10^-5 M

use

pH = -log [H+]

= -log (8.718*10^-5)

= 4.0596

2)when 25.0 mL of KOH is added

Given:

M(HClO) = 0.19 M

V(HClO) = 50 mL

M(KOH) = 0.19 M

V(KOH) = 25 mL

mol(HClO) = M(HClO) * V(HClO)

mol(HClO) = 0.19 M * 50 mL = 9.5 mmol

mol(KOH) = M(KOH) * V(KOH)

mol(KOH) = 0.19 M * 25 mL = 4.75 mmol

We have:

mol(HClO) = 9.5 mmol

mol(KOH) = 4.75 mmol

4.75 mmol of both will react

excess HClO remaining = 4.75 mmol

Volume of Solution = 50 + 25 = 75 mL

[HClO] = 4.75 mmol/75 mL = 0.0633M

[ClO-] = 4.75/75 = 0.0633M

They form acidic buffer

acid is HClO

conjugate base is ClO-

Ka = 4*10^-8

pKa = - log (Ka)

= - log(4*10^-8)

= 7.398

use:

pH = pKa + log {[conjugate base]/[acid]}

= 7.398+ log {6.333*10^-2/6.333*10^-2}

= 7.398

3)when 35.0 mL of KOH is added

Given:

M(HClO) = 0.19 M

V(HClO) = 50 mL

M(KOH) = 0.19 M

V(KOH) = 35 mL

mol(HClO) = M(HClO) * V(HClO)

mol(HClO) = 0.19 M * 50 mL = 9.5 mmol

mol(KOH) = M(KOH) * V(KOH)

mol(KOH) = 0.19 M * 35 mL = 6.65 mmol

We have:

mol(HClO) = 9.5 mmol

mol(KOH) = 6.65 mmol

6.65 mmol of both will react

excess HClO remaining = 2.85 mmol

Volume of Solution = 50 + 35 = 85 mL

[HClO] = 2.85 mmol/85 mL = 0.0335M

[ClO-] = 6.65/85 = 0.0782M

They form acidic buffer

acid is HClO

conjugate base is ClO-

a = 4*10^-8

pKa = - log (Ka)

= - log(4*10^-8)= 7.398

use:

pH = pKa + log {[conjugate base]/[acid]}

= 7.398+ log {7.824*10^-2/3.353*10^-2}

= 7.766

4)when 50.0 mL of KOH is added

Given:

M(HClO) = 0.19 M

V(HClO) = 50 mL

M(KOH) = 0.19 M

V(KOH) = 50 mL

mol(HClO) = M(HClO) * V(HClO)

mol(HClO) = 0.19 M * 50 mL = 9.5 mmol

mol(KOH) = M(KOH) * V(KOH)

mol(KOH) = 0.19 M * 50 mL = 9.5 mmol

We have:

mol(HClO) = 9.5 mmol

mol(KOH) = 9.5 mmol

9.5 mmol  of both will react to form ClO- and H2O

ClO- here is strong base

ClO- formed = 9.5 mmol

Volume of Solution = 50 + 50 = 100 mL

Kb of ClO- = Kw/Ka =  1*10^-14/4*10^-8 = 2.5*10^-7

concentration ofClO-,c = 9.5 mmol/100 mL = 0.095M

ClO- dissociates as

ClO-        + H2O   ----->     HClO  +   OH-

0.095                        0         0

0.095-x                      x         x

Kb = [HClO][OH-]/[ClO-]

Kb = x*x/(c-x)

Assuming x can be ignored as compared to c

So, above expression becomes

Kb = x*x/(c)

so, x = sqrt (Kb*c)

x = sqrt ((2.5*10^-7)*9.5*10^-2) = 1.541*10^-4

since c is much greater than x, our assumption is correct

so, x = 1.541*10^-4 M

[OH-] = x = 1.541*10^-4 M

use:

pOH = -log [OH-]

= -log (1.541*10^-4)

= 3.8122

use:

PH = 14 - pOH

= 14 - 3.8122

= 10.1878

5)when 60.0 mL of KOH is added

Given:

M(HClO) = 0.19 M

V(HClO) = 50 mL

M(KOH) = 0.19 M

V(KOH) = 60 mL

mol(HClO) = M(HClO) * V(HClO)

mol(HClO) = 0.19 M * 50 mL = 9.5 mmol

mol(KOH) = M(KOH) * V(KOH)

mol(KOH) = 0.19 M * 60 mL = 11.4 mmol

We have:

mol(HClO) = 9.5 mmol

mol(KOH) = 11.4 mmol

9.5 mmol of both will react

excess KOH remaining = 1.9 mmol

Volume of Solution = 50 + 60 = 110 mL

[OH-] = 1.9 mmol/110 mL = 0.0173 M

use:

pOH = -log [OH-]

= -log (1.727*10^-2)

= 1.7626

use:

PH = 14 - pOH

= 14 - 1.7626

= 12.2374

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The axes in the coordinate grid on the right represent the walls of a room. the distance from that corner of the room to the corner of the furthest bed is 11 axes. A coordinate grid has two perpendicular lines, or axes (pronounced AX-eez), labeled just like number lines. The horizontal axis is usually called the x-axis. The vertical axis is usually called the y-axis. The point where the x- and y-axis intersect is called the origin.

The coordinate plane has two axes: the horizontal and vertical axes. These two axes intersect one another at a point called the origin.

The x axis is in the plane of the screen and is positive toward the right and negative toward the left. The y axis is in the plane of the screen and is positive toward the top and negative toward the bottom. The z axis is perpendicular to the screen or keyboard, and is positive extending outward from the screen.

With this information, we can conclude that the distance from that corner of the room to the corner of the furthest bed is 11 axes.

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Answer:

true

Explanation:

The desired output of this system which involves a bicycle for transportation is the bicycle forward motion.

This is defined as the process in which goods and people are moved from one location or place to another through the use of vehicle such as bicycle, motorcycle etc.

When riding a bicycle, the input is the force which is exerted on the pedal with the use of the legs and it then results in the bicycle moving forward (forward motion) and is referred to as the output which is therefore the reason why it was chosen as the most appropriate choice.

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Answer:

you can simply answer vl/t1=v2/t2

Answer: 7.60 L of hydrogen gas will be liberated.

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

\(\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}\)    ......(1)

Given mass of Mg = 8.25 g

Molar mass of Mg = 24.305 g/mol

Plugging values in equation 1:

\(\text{Moles of Mg}=\frac{8.25g}{24.305g/mol}=0.340mol\)

The given chemical equation follows:

\(Mg+2HCl\rightarrow MgCl_2+H_2\)

By the stoichiometry of reaction:

If 1 mole of magnesium produces 1 mole of hydrogen gas

So, 0.340 moles of magnesium will be produce = \(\frac{1}{1}\times 0.340=0.340mol\) of hydrogen gas

At STP conditions:

1 mole of a gas occupies 22.4 L of volume

So, 0.340 moles of hydrogen gas will occupy = \(\frac{22.4L}{1mol}\times 0.340mol=7.60L\) of hydrogen gas

Hence, 7.60 L of hydrogen gas will be liberated.

Answer:

increase the rate of reaction.

Explanation:

Answer:

A. It leads to more frequent collisions, which increase reaction rate.

Explanation:

EDG

It is possible that several environmental elements unique to each habitat are the cause of the observed difference in acquired mutations between fish species living on the beach and those in the river.

Fisheries are impacted by climate change in many different ways: freshwater ecosystems are impacted by changes in water temperature, water flow, and fish habitat loss, while marine aquatic ecosystems are impacted by rising ocean temperatures, ocean acidification, and ocean deoxygenation.

The pace of growth is influenced by a number of environmental parameters, including temperature, oxygen content, salinity, and photoperiod. According to recent research, endogenous regulators of an individual's physiological condition, hormones, and genetics are all equally significant.

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The number of moles of potassium hydroxide that would react with 1 mole of hydrochloric acid would be 1 mole.

Stoichiometric mole ratio

The stoichiometric moles of species of a reaction are the coefficients of each species in the balanced symbol equation of the reaction.

The balanced equation of the reaction between potassium hydroxide (KOH) and hydrochloric acid (HCl) is expressed as follows:

\(KOH + HCl --- > KCl + H_2O\)

In this case, the stoichiometric mole of KOH is 1, that of HCl is 1, that of KCl is 1, and that of \(H_2O\) is also 1.

In other words, the stoichiometric mole ratio of KOH and HCl is 1:1. For every 1 mole of KOH, 1 mole of HCl is required for a complete reaction.

Now, the question says what mole of potassium hydroxide will be required to react with 1 mole of hydrochloric acid?

Following the mole ratio, 1 mole of KOH will also be required.

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Answer:

Its B and D :)

Explanation:

I saw the answer key.

Answer:

the answer key is

for atomic but you find it from the periodic table

porotons = atomic number

neutrons = atomic mass - protons number

electrons number = proton number

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The antimicrobial activity of chlorine is due to the formation of hypochlorous acid (option a).

The correct answer is a. The antimicrobial activity of chlorine is due to the formation of hypochlorous acid. When chlorine is added to water, it reacts with water molecules to form hypochlorous acid (HOCl) and hypochlorite ions (OCl-). HOCl is a powerful disinfectant and is responsible for the antimicrobial activity of chlorine. It can penetrate bacterial cell walls and disrupt cell membranes, leading to the destruction of bacteria and other microorganisms.

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The strongest oxidizing agent is D. Cu2+.

The strength of an oxidizing agent is determined by its ability to gain electrons or to oxidize other species. The stronger the oxidizing agent, the more easily it gains electrons or oxidizes other species.In general, species with higher oxidation states tend to be stronger oxidizing agents because they have a greater tendency to gain electrons.

Therefore, we need to compare the oxidation states of the given species to determine which is the strongest oxidizing agent.

A. Pb2+ has an oxidation state of +2.

B. Cr2+ has an oxidation state of +2.

C. Fe2+ has an oxidation state of +2.

D. Cu2+ has an oxidation state of +2.

All of the given species have the same oxidation state of +2, so we cannot use oxidation state to compare their oxidizing strength. However, we can compare their standard reduction potentials (E°) to determine which is the strongest oxidizing agent.

The species with the higher (more positive) standard reduction potential is the stronger oxidizing agent.From the table of standard reduction potentials, we can see that the standard reduction potentials (E°) for the half-reactions involving these species are:

Pb2+ + 2e- → Pb(s) E° = -0.13 V

Cr2+ + 2e- → Cr(s) E° = -0.91 V

Fe2+ + 2e- → Fe(s) E° = -0.44 V

Cu2+ + 2e- → Cu(s) E° = +0.34 V

The half-reaction with the highest (most positive) standard reduction potential is Cu2+ + 2e- → Cu(s), indicating that Cu2+ is the strongest oxidizing agent among the given options.Therefore, the answer is D. Cu2+.

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Explanation:

We have a 63.9 g sample of calcium hydroxide. First we have to convert those grams into moles. To do that we have to use the molar mass of calcium hydroxide.

Calcium hydroxide = Ca(OH)₂

molar mass of Ca = 40.08 g/mol

molar mass of O = 16.00 g/mol

molar mass of H = 1.01 g/mol

molar mass of Ca(OH)₂ = 1 * 40.08 g/mol + 2 * 16.00 g/mol + 2 * 1.01 g/mol

molar mass of Ca(OH)₂ = 74.10 g/mol

mass of Ca(OH)₂ = 63.9 g

moles of Ca(OH)₂ = 63.9 g /(74.10 g/mol)

moles of Ca(OH)₂ = 0.862 moles

In 1 molecule of Ca we have 2 atoms of O. So in 1 mol of Ca(OH)₂ we will have 2 moles of O atoms.

1 mol of Ca(OH)₂ = 2 moles of O atoms

moles of O atoms = 0.862 moles of Ca(OH)₂ * 2 moles of O /1 mol of Ca(OH)₂

moles of O atoms = 1.724 moles

One mol is similar to a dozen. When we say that we need a dozen eggs we know that we need 12 eggs. If we want a mol of eggs, we want 6.022*10^23 eggs. So one mol of something is 6.022 * 10^23 of that.

1 mol of O atoms = 6.022 * 10^23 atoms

n° of O atoms = 1.724 moles * 6.022 * 10^23 atoms/1 mol

n° of O atoms = 1.04 * 10^24 atoms

Answer: In a 63.9 g sample of Ca(OH)₂ we have 1.04 *10^24 atoms of oxygen.

The volume of the sauce required is 529.76 mL

The volume has to do with the space that is occupied by an object. We can see that the unit that has been given for the spaghetti sauce is in the non standard unit of cups of tomato sauce. We are now asked to express this value in the metric unit of milliliter.

We have that;

1qt = 4 cups

x = 2.5 cups

x = 1qt  * 2.5 cups/4 cups

x = 0.56 qt

Also;

1q = 946 mL

0.56 qt =  0.56 qt * 946 mL/1q

= 529.76 mL

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This is a lipid diagram.

what type of diagram is this?

Answer: A lipid diagram

is it a proteins or lipid diagram?

Answer: A lipid diagram