Help me pretty please

Answer:

Hydrogen in its metallic state (usually considered a nonmetal)​

Lithium.

Sodium.

Potassium.

Rubidium.

Cesium.

Francium.

Explanation:

Answer:

The list of elements that contains only metals is tin, copper and cesium.

Carbon and iodine aren't metals.

Helium isn't metal.

Neither iodine, carbon, nor argon are metals.  

(Hope this helps) Sky

Answer:

This statement is in the context of Lewis Structures, which are diagrams that show the bonding between atoms of a molecule and the lone pairs of electrons that may exist in the molecule. The diagrams show the valence electrons of the atoms that participate in a bond.

When there is more than one possible site in the molecule or ion, the central or the charged atom must be focused on.

To determine which atom is the central or charged atom, you should look at the molecular/ionic structure and identify the atom with the highest electronegativity or charge density.

In general, the atom with the highest electronegativity or charge density is the central or charged atom.

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Answer:

2.1056L or 2105.6mL

Explanation:

We'll begin by calculating the number of mole in 10g of Na2CO3. This can be obtained as follow:

Molar mass of Na2CO3 = (23x2) + 12 + (16x3) = 106g/mol

Mass of Na2CO3 = 10g

Mole of Na2CO3 =.?

Mole = mass /molar mass

Mole of Na2CO3 = 10/106

Mole of Na2CO3 = 0.094 mole

Next, we shall determine the number of mole CO2 produced by the reaction of 0.094 mole of Na2CO3. This is illustrated below:

Na2CO3 + 2HCl —> 2NaCl + H2O + CO2

From the balanced equation above,

1 mole of Na2CO3 reacted to produce 1 mole of CO2.

Therefore, 0.094 mole of Na2CO3 will also react to 0.094 mole of CO2.

Next, we shall determine the volume occupied by 0.094 mole of CO2 at STP. This is illustrated below:

1 mole of a gas occupy 22.4L at STP. This implies that 1 mole CO2 occupies 22.4L at STP.

Now, if 1 mole of CO2 occupy 22.4L at STP, then, 0.094 mole of CO2 will occupy = 0.094 x 22.4 = 2.1056L

Therefore, the volume of CO2 produced is 2.1056L or 2105.6mL

Answer:

Answer Choice D

Explanation:

Study Island Question

Answer:

1.Phenolphthalein

2.Method

a.Use the pipette and pipette filler to add 25 cm 3 of alkali to a clean conical flask.

b.Add a few drops of indicator and put the conical flask on a white tile.

c.Fill the burette with acid and note the starting volume.

d.Slowly add the acid from the burette to the alkali in the conical flask, swirling to mix.

Explanation:

Answer:

Atomic mass of Hydrogen is 1.00784 u

Atomic mass of Carbon is 12.0107 u

Explanation:

Answer:

Smithers thinks that a special juice will increase the productivity of workers. He creates two groups of 50 workers each and assigns each group the same task (in this case, they're ... Group A is given the special juice to drink while they work. Group ... 1. Control Group. Group B. 2. Independent Variable. volume of special juice.

Explanation:

Answer:

1. Group B

2. The juice

3. The number of stacks of paper

4. the juice did not help improve a quicker process

5. Group A can be given the juice, Group B can be given the juice without the special ingredient

USE QUIZLET FLASH CARDS IT CAN HELP YOU WITH A LOT OF QUESTION

Explanation:

In a chemical reaction, the rates at which reactants are converted into products depend on various factors, including temperature, pressure, and concentration of the reactants. When the concentrations of reactants and products remain constant in a system, it typically indicates that the forward and reverse reaction rates are equal, resulting in a state of chemical equilibrium.

At equilibrium, the concentrations of reactants and products do not change over time, because the rates of the forward and reverse reactions are balanced. This occurs when the rate of the forward reaction, which converts reactants into products, is equal to the rate of the reverse reaction, which converts products back into reactants. As a result, the concentrations of both reactants and products remain constant.

The concept of Le Chatelier's principle can help explain why concentrations of reactants and products remain constant at equilibrium. According to Le Chatelier's principle, when a system at equilibrium is subjected to a change in temperature, pressure, or concentration, the system will adjust in a way that opposes the change. For example, if the concentration of a reactant is increased, the system will shift towards the side with fewer moles of reactant in order to restore the equilibrium. Similarly, if the concentration of a product is increased, the system will shift towards the side with fewer moles of product.

As a result of these shifts, the rates of the forward and reverse reactions will be adjusted to restore equilibrium, and the concentrations of reactants and products will remain constant. If the concentration of a reactant or product decreases, the system will shift in the opposite direction to restore equilibrium. This dynamic balancing of the forward and reverse reaction rates is what allows the concentrations of reactants and products to remain constant at equilibrium in a closed system.

Answer:

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Explanation:

Answer:cool kid

Explanation:cool kid

Answer:

1,42 Å

Explanation:

La longitud de enlace de Bi-I se obtiene por

Bi-I = Radio del átomo de Bi + Radio del átomo de yodo

pero radio del átomo de yodo = 1.39Å

Longitud del enlace Bi-I = 2,81 Å

Por lo tanto, el radio del átomo de Bi = 2,81 Å - 1,39 Å

radio del átomo de Bi = 1,42 Å

Answer:

The second option

Answer:

Intent to cause harm

The percentage composition of oxygen in NaOH is 40%. The correct answer is C.

The formula for sodium hydroxide (NaOH) is Na + OH, which means it contains one atom of sodium (Na), one atom of oxygen (O), and one atom of hydrogen (H). The molecular weight of NaOH is 40 g/mol, which can be calculated by adding the atomic weights of its components: Na (23 g/mol) + O (16 g/mol) + H (1 g/mol).

The weight of oxygen in NaOH can be calculated by finding the weight of one oxygen atom and multiplying it by the number of oxygen atoms in one molecule of NaOH, which is one. The weight of one oxygen atom is approximately 16 g/mol.

Therefore, the weight of oxygen in NaOH is 16 g/mol. To calculate the percentage composition of oxygen in NaOH, we need to divide the weight of oxygen by the molecular weight of NaOH and multiply by 100.

(16 g/mol ÷ 40 g/mol) × 100% = 40%

Therefore, the answer is (c) 40%.

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Note: The question would be as

What's the percentage composition of oxygen in NaOH is: a.16% b. 4% c.40% d. 8%

A balanced chemical equation for this reaction :

FeS(s)+2HCl(aq)→FeCl2(aq)+ H2S(g)

Given

Word equation

Required

Balanced equation

Solution

The chemical equation can be expressed in terms of:

Skeleton equation

FeS(s)+ HCl(aq) --> FeCl2 (aq) + H2S (g)

Balanced equation

FeS(s)+2HCl(aq)→FeCl2(aq)+ H2S(g)

Answer:

Three half-lives

Explanation:

12.5% is one-eighth. One eighth is the cube of one half, so it would take three half-lives to reduce a reactant's concentration to 12.5%

Three half-lives are required for the concentration of reactant to decrease to 12. 5% of its original value.

Half -life of a substance is defined as the time which is required for half of the quantity of a radioactive substance to get decayed.It is a term which is used in nuclear chemistry for describing how quickly unstable atoms undergo radioactive decay into other nuclear species by emitting particles or the time which is required for number of disintegrations per second of radioactive material to decrease by one half of its initial value.

In the given example 12.5 % is 1/8  and three times 1/2 that is 1/2×1/2×1/2=1/8 , hence  three half lives are  required for the concentration of reactant to decrease to 12. 5% of its original value.

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The true statement is: It took the car the same amount of time to travel the first 10 meters as it did to travel the last 10 meters (Option C)

The following data were obtained from the question:

Now, we shall determine the time taken to travel the first 10 m. This is shown below:

Next, we shall determin the time taken to travel the last 10 m. This is shown below:

From the above illlustration, we can see clearly that it took the car the same time to travel the first 10 m and the last 10 m.

Thus, the true statement is option C: It took the car the same amount of time to travel the first 10 meters as it did to travel the last 10 meters

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The most accurate statement considering the dipole moment is: c. The O-Cl bonds are all polar, but due to the linear shape of the molecules, the individual dipoles cancel to yield no net dipole moment for either molecule.

The most accurate statement considering the dipole moment is option c. In this case, the molecules in question have linear shapes, and all the O-Cl bonds are polar.

A polar bond occurs when there is an unequal distribution of electron density between two atoms, resulting in a separation of positive and negative charges. However, even though the O-Cl bonds are polar, the linear molecular structure leads to the cancellation of the individual dipole moments.

The dipole moment of a molecule is determined by both the magnitude and direction of its constituent bond dipoles. In this scenario, the linear shape causes the dipole moments to point in opposite directions, effectively canceling each other out.

As a result, there is no net dipole moment for either molecule. This cancellation of dipole moments due to molecular geometry is known as "vector sum" or "vector cancellation."

Thus, option c accurately describes the absence of a net dipole moment in the given molecules despite having polar O-Cl bonds.

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Answer:17.47m

Explanation:

Explanation:

Molarity is defined as moles of solute per liters of solution.

c

=

n

V

Glacial acetic acid is actually anhydrous acetic acid, which implies that the acetic acid is not actually dissolved in a solvent and therefore is not ctually a solute.

However, you can still calculate its molarity based on the number of moles of you get per liter of glacial acetic acid.

To do that, start with a sample o

1.000 L

of glacial acetic acid. You know that at

25

∘

C

, glacial acetic acid has a density of

1.049 g/mL

, which tells you that every mililiter of glacial acetic acid has a mass of

1.049 g

.

This means that the mass of the sample will be

1.000

L

⋅

1000

mL

1.000

L

⋅

1.049 g

1

mL

=

1049 g

To find how many moles you get in the sample, use the given molar mass, which tells you how many grams of acetic acid you get per mole

1049

g

⋅

1 mole CH

3

COOH

60.05

g

=

17.469 moles CH

3

COOH

Now that you know the volume of the sample and how many moles it contains, you can say that

c

=

17.469 moles

1.000 L

=

17.47 M

I'll keep the number of sig figs given for the density of glacial acetic acid.

When for a solution concentration of hydroxide ions becomes equal to the concentration of hydronium ions, its pH becomes equal to 7.

pH of any solution is used to define the acidity, basicity or neutrality of the solution.

When the concentration of hydronium ion is equal to the concentration of the hydroxide ion then the resultant solution will be neutral, as they have a pH equals to 0.

Hence, pH of the solution becomes equal to 7.

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Answer:

A reactant is a substance that is present at the start of a chemical reaction. The substance(s) to the right of the arrow are called products . A product is a substance that is present at the end of a chemical reaction.

Explanation:

Answer:   Ionic Bonds

"When it forms the nitride ion, it gains three electrons to form a 3- ion: N3− . In ionic compounds, the charges of constituent ions must balance. This can be achieved by having three sodium ions per nitride ion. Therefore, the formula of sodium nitride is Na3N"

Explanation:

https://socratic.org/questions/what-is-the-formula-for-sodium-nitride#:~:text=When%20it%20forms%20the%20nitride,nitride%20is%20Na3N%20.

The index of hydrogen deficiency (IHD) for the molecule C6H14 is 2, indicating the presence of two types of unsaturation, which can include double bonds, rings, or a combination of both.

The formula C6H14 represents a molecule with 6 carbon atoms and 14 hydrogen atoms. To calculate the index of hydrogen deficiency (IHD), we need to compare the actual number of hydrogen atoms in the molecule with the maximum number of hydrogen atoms possible for a molecule with the same number of carbon and heteroatoms.
The maximum number of hydrogen atoms for a saturated molecule can be calculated using the formula (2n + 2), where n is the number of carbon atoms. In this case, the maximum number of hydrogen atoms is (2 * 6 + 2) = 14.

The IHD can be calculated using the formula (2n + 2 - H)/2, where n is the number of carbon atoms and H is the actual number of hydrogen atoms in the molecule. Substituting the values, we get (2 * 6 + 2 - 14)/2 = 2.
The IHD of 2 suggests that there are two types of unsaturation point present in the molecule. The possible types of unsaturation include double bonds and rings. Therefore, the molecule with the formula C6H14 can have either double bonds or rings or a combination of both.

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a) Solubility (g KHT/L) = (0.950 g KHT) / (0.025 L) = 38 g KHT/L

b) Solubility (mol KHT/L) = (38 g KHT/L) / (188.18 g/mol) = 0.202 mol KHT/L

c) [K+] = [HT-] = 0.202 mol KHT/L

d) Ksp = (0.202)(0.202) = 0.0408

A more detailed explanation of the answer.

a) To calculate the solubility of KHT in g KHT/L of solution, follow these steps:
1. Convert the volume of the solution to liters: 25.00 mL = 0.025 L
2. Calculate the solubility by dividing the mass of KHT by the volume of the solution:
Solubility (g KHT/L) = (0.950 g KHT) / (0.025 L) = 38 g KHT/L

b) To calculate the solubility of KHT in mol KHT/L of solution, follow these steps:
1. Determine the molar mass of KHT (K = 39.10 g/mol, H = 1.01 g/mol, C = 12.01 g/mol, O = 16.00 g/mol):
Molar mass of KHT = K + 2*(C + H + 2*O) = 39.10 + 2*(12.01 + 1.01 + 2*16.00) = 188.18 g/mol
2. Convert the solubility from g KHT/L to mol KHT/L:
Solubility (mol KHT/L) = (38 g KHT/L) / (188.18 g/mol) = 0.202 mol KHT/L

c) To determine [K+] and [HT-] in this solution, follow these steps:
1. Since KHT dissociates into K+ and HT-, the concentrations of K+ and HT- will be equal to the solubility of KHT in mol KHT/L:
[K+] = [HT-] = 0.202 mol KHT/L

As there is a trace of solid present and the reaction is at equilibrium, we can determine the Ksp at this temperature by following these steps:
1. Write the balanced chemical equation for the dissociation of KHT: KHT (s) <-> K+ (aq) + HT- (aq)
2. Write the expression for the Ksp: Ksp = [K+][HT-]
3. Plug in the concentrations calculated earlier: Ksp = (0.202)(0.202) = 0.0408

So, at this temperature (Tp), the Ksp for KHT is 0.0408.

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Answer: By the very laws of the universe, matter cannot be created or destroyed, the Big Bang cannot have happened by its own power. There was a creator involved.

The balanced redox reaction in acidic solution:

6H₂O₂(aq) + 2Cr₂O₇⁻²(aq) + 14H⁺(aq) → 3O₂ + 4Cr³⁺(aq) + 20H₂O(l)

To balance the redox reaction in acidic solution:

H₂O₂(aq) + Cr₂O₇⁻²(aq) → O₂(g) + Cr³⁺(aq)

We will follow the steps for balancing redox reactions in acidic solution:

Step 1: Assign oxidation numbers to all elements in the equation:

H₂O₂(aq): H has an oxidation state of +1, O has an oxidation state of -1.

Cr₂O₇⁻²(aq): Cr has an oxidation state of +6, O has an oxidation state of -2.

O₂(g): O has an oxidation state of 0.

Cr³⁺(aq): Cr has an oxidation state of +3.

Step 2: Identify the elements that are being oxidized and reduced:

Oxidation: Cr is being reduced from +6 to +3.

Reduction: H₂O₂ is being oxidized from -1 to 0.

Step 3: Write the half-reactions for oxidation and reduction:

Oxidation half-reaction: H₂O₂(aq) → O2(g)

Reduction half-reaction: Cr₂O₇⁻²(aq) → Cr³⁺(aq)

Step 4: Balance the atoms other than H and O in each half-reaction:

Oxidation half-reaction: 2H₂O₂(aq) → O₂(g)

Reduction half-reaction: Cr₂O₇⁻²(aq) → 2Cr³⁺(aq)

Step 5: Balance the oxygen atoms by adding water molecules (H2O) to the side that lacks oxygen:

Oxidation half-reaction: 2H₂O₂(aq) → O₂(g) + 2H₂O(l)

Reduction half-reaction: Cr₂O₇⁻²(aq) → 2Cr³⁺(aq)

Step 6: Balance the hydrogen atoms by adding hydrogen ions (H+) to the side that lacks hydrogen:

Oxidation half-reaction: 2H₂O₂(aq) → O₂(g) + 2H₂O(l)

Reduction half-reaction: Cr₂O₇⁻²(aq) + 14H+(aq) → 2Cr³⁺(aq) + 7H₂O(l)

Step 7: Balance the charges by adding electrons (e-) to the appropriate side of each half-reaction:

Oxidation half-reaction: 2H₂O₂(aq) → O₂(g) + 2H₂O(l) + 4e-

Reduction half-reaction: Cr₂O₇⁻²(aq) + 14H+(aq) + 6e- → 2Cr³⁺(aq) + 7H₂O(l)

Step 8: Multiply each half-reaction by a factor that will equalize the number of electrons in both half-reactions:

Multiply the oxidation half-reaction by 3 and the reduction half-reaction by 2:

6H₂O₂(aq) → 3O₂(g) + 6H₂O(l) + 12e-

Cr₂O₇⁻²(aq) + 14H+(aq) + 12e- → 4Cr³⁺(aq) + 14HvO(l)

Step 9: Combine the two half-reactions, canceling out the electrons on both sides:

6H₂O₂(aq) + 2Cr₂O₇⁻²(aq) + 14H⁺(aq) → 3O₂ + 4Cr³⁺(aq) + 20H

Step 10: Combine all the species to form the balanced redox reaction:

6H₂O₂(aq) + 2Cr₂O₇⁻²(aq) + 14H⁺(aq) → 3O₂ + 4Cr³⁺(aq) + 20H₂O(l)

Step 11: Simplify the equation by canceling out common species:

6H₂O₂(aq) + 2Cr₂O₇⁻²(aq) + 14H⁺(aq) → 3O₂ + 4Cr³⁺(aq) + 20H₂O(l)

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This problem is stating a situation in which a solid object is fully immersed in a liquid and the buoyant force is larger that its weight, so that you need to discuss whether this is possible or not.

In general terms, it is necessary to keep in mind that when the buoyant force is larger than its weight, the object will float. On the other side, when the buoyant force is smaller than the weight, then the object will sink.

It means that it could be possible to have this scenario under specific conditions. Now, the Archimedes' principle can be applied with the following version:

\(F_B+W>m_{obj}*a\\\\\rho _{fluid}*V*g+m_{obj}*g>m_{obj}*a\\\\\rho _{fluid}*V-m_{obj}>m_{obj}*a\)

It means that the object can move down the liquid if has a significant acceleration (could be external), even when the buoyant force is larger than the weight

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The net ionic equation when the ammonium nitrate is dissolved in the water :

NH₄NO₃(s) + H₂O(l) ⇄ NH₄⁺(aq)  + NO₃⁻(aq)

The component that will ionizes in the aqueous solution that is the ammonium ion. The nitrate ion is that does not ionize in the aqueous solution.

The acid-base hydrolysis in equilibrium that is the established when the ammonium nitrate is dissolved in the water, the net ionic equation is as :

NH₄NO₃(s) + H₂O(l) ⇄ NH₄⁺(aq)  + NO₃⁻(aq)

The ions has the equal and the oppisite charges. They both can combine in the electrically neutral ratio of the 1:1.  The net ionic equation can be depicts by the molecules and the ions.

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The work done on the gas in this case is 7.75 Joules or 7.75 L atm.

The work done by the gas in any thermodynamic process can be calculated by using the formula:

W = P∆V

In the isothermal process, the temperature of the gas remains constant, which means that the pressure and volume are inversely proportional to each other.

Therefore, the formula becomes:

W = nRTln(V2/V1)

W is the work done on the gasn is the number of moles of gas

R is the gas constant

T is the absolute temperature of the gas

V1 is the initial volume of the gas

V2 is the final volume of the gas

n = 2 moles

V1 = 15 L

V2 = 20

Lp = 1 atm

R = 0.0821 L atm/K mol

T = constant (since it's an isothermal process)

Therefore,W = (2 mol)(0.0821 L atm/K mol)(273 K) ln(20 L/15 L)

W = 7.75 L atm or 7.75 Joules

(since 1 L atm = 101.3 J)

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