Help me please, it’s regular science for 5th grade.

Answer:

This is actually very true

Step-by-step explanation:

lol

Answer:

7n-12

Step-by-step explanation:

Answer:

Step-by-step explanation:

12 n - 12

Answer:

256

Step-by-step explanation:

The quotient of the given expression will be 256.

From the given data

\(=\dfrac{2^{4} }{2^{-4} }\)

Now it will become

\(2^{4} \times 2^{4} = 2^{8} =256\)

Thus the quotient of the given expression will be 256

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The mean of this distribution is 26.5. The standard deviation is 8.0623. The probability that the number will be exactly 36 is P (x = 36) = 0.0286. The probability that the number will be between 21 and 23 is P (21 < x < 23) = 0.0400. The probability that the number will be larger than 26 is P (x > 26) = 0.2857. P (x > 16 | x < 18) = undefined. The 49th percentile is 29.3700. The minimum for the lower quartile is 19.75.

a. The mean of a uniform distribution is the average of the maximum and minimum values, so in this case, the mean is:

mean = (12 + 41) / 2 = 26.5

Therefore, the mean of this distribution is 26.5.

b. The standard deviation of a uniform distribution is given by the formula:

sd = (b - a) / sqrt(12)

where a and b are the minimum and maximum values of the distribution, respectively. So in this case, the standard deviation is:

sd = (41 - 12) / sqrt(12) = 8.0623

Therefore, the standard deviation of this distribution is 8.0623.

c. Since the distribution is uniform, the probability of getting any specific value between 12 and 41 is the same. Therefore, the probability of getting exactly 36 is:

P(x = 36) = 1 / (41 - 12 + 1) = 0.0286

Rounded to four decimal places, the probability is 0.0286.

d. The probability of getting a number between 21 and 23 is:

P(21 < x < 23) = (23 - 21) / (41 - 12 + 1) = 0.0400

Rounded to four decimal places, the probability is 0.0400.

e. The probability of getting a number larger than 26 is:

P(x > 26) = (41 - 26) / (41 - 12 + 1) = 0.2857

Rounded to four decimal places, the probability is 0.2857.

f. The probability that x is greater than 16, given that it is less than 18, can be calculated using Bayes' theorem:

P(x > 16 | x < 18) = P(x > 16 and x < 18) / P(x < 18)

Since the distribution is uniform, the probability of getting a number between 16 and 18 is:

P(16 < x < 18) = (18 - 16) / (41 - 12 + 1) = 0.0400

The probability of getting a number greater than 16 and less than 18 is zero, so:

P(x > 16 and x < 18) = 0

Therefore:

P(x > 16 | x < 18) = 0 / 0.0400 = undefined

There is no valid answer for this question.

g. To find the 49th percentile, we need to find the number that 49% of the distribution falls below. Since the distribution is uniform, we can calculate this directly as:

49th percentile = 12 + 0.49 * (41 - 12) = 29.37

Rounded to four decimal places, the 49th percentile is 29.3700.

h. The lower quartile (Q1) is the 25th percentile, so we can calculate it as:

Q1 = 12 + 0.25 * (41 - 12) = 19.75

Therefore, the minimum for the lower quartile is 19.75.

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Answer:

C

Step-by-step explanation:

I think because there is no space or a sign in-between the f and 5, which means you multiply.

Minor arc TB s given to be 270 degrees

Minor arc TB + arc TCB = 360 degrees (sum of angles at a point)

90 + arc TCB = 360

arc TCB = 360 - 90

arc TCB = 270

The correct option is option C

Answer:

give the pic..................

Answer: y = -1x + 3

Step-by-step explanation:

Point-Slope form: y - y1 = m(x-x1)

Replace the form with the values provided:

y - 15 = -1(x+12)

Once you get this, you need to get y by itself in order to get it in slope intercept form.

Distribute:

y -15 = -1x - 12

Add -15 to the right side:

y = -1x + 3

Answer:

c = -22, 22

Step-by-step explanation:

\( {(x - 11)}^{2} = {x}^{2} - 22x + 121\)

\( {(x + 11)}^{2} = {x}^{2} + 22x + 121\)

Answer:

Correct.

Step-by-step explanation:

This is correct,can i please get brainliest,really need it

Answer:

5/3

Step-by-step explanation:

HTH :)

Answer:

3

Step-by-step explanation:

5-2=3

Just do it the other way to find the answer!

I hope this helps!

Answer: x = 3

Step-by-step explanation:

we subtract 2 from both sides, in order to get the variable by itself.

x + 2 (- 2) = 5 (- 2)

x = 3

Answer:

The answer is 20p – 10 or 10(2p – 1)

Step-by-step explanation:

4(2p + 2) + 6(2p − 3)

8p + 8 + 12p – 18

20p – 10 or 10(2p – 1)

Answer:

subtract 5 , m=(-15)

Step-by-step explanation:

15-5

=10

n:

5-10

=(-5)

m:

(-5)-10

=(-15)

hope it help

The sample size cannot be determined from this information alone. A confidence interval for a population mean is calculated based on the mean of a sample, the sample size, and the standard deviation.

Deviation is the difference between the expected value or average of a set of data and the actual value. For example, if the average of a set of numbers is 10 and one of the numbers is 15, the deviation of that number is 5. Deviation is a measure of how much variation exists in a set of data. It is an important tool used to measure the accuracy of a data set and identify outliers within that data set. Deviation is also used to measure the volatility of a stock or other investment, which is a measure of how much its price changes over time.

Therefore, to determine the sample size, the mean, standard deviation, and confidence interval of the sample must all be known.

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The sample size cannot be determined from this information alone. A confidence interval for a population mean is calculated based on the mean of a sample, the sample size, and the standard deviation.

Deviation is the difference between the expected value or average of a set of data and the actual value. For example, if the average of a set of numbers is 10 and one of the numbers is 15, the deviation of that number is 5. Deviation is a measure of how much variation exists in a set of data. It is an important tool used to measure the accuracy of a data set and identify outliers within that data set. Deviation is also used to measure the volatility of a stock or other investment, which is a measure of how much its price changes over time.

Therefore, to determine the sample size, the mean, standard deviation, and confidence interval of the sample must all be known.

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Complete Question:
A 95% confidence interval for a population mean was reported to be 152 to 160. If s 15, what sample size was used in this study?

The equation of the circle is x²+y²-x-y+0.25=0

What is a circle?

A circle is a particular type of ellipse in mathematics or geometry where the eccentricity is zero and the two foci are congruent. A circle is also known as the location of points that are evenly spaced apart from the centre. The radius of a circle is measured from the centre to the edge. The line that splits a circle into two identical halves is its diameter, which is also twice as wide as its radius.

For a circle with radius r and center (h,k), its equation would be (x-h)² + (y-k)² = r²

Given, center is (0.5,0.5) and radius is 0.5, h=0.5, k=0.5, r=0.5

The equation becomes:

(x-0.5)² + (y-0.5)² = 0.5²

⇒x²+0.25-x+y²+0.25-y=0.25

⇒x²+y²-x-y+0.25=0

Thus, the equation of a circle becomes x²+y²-x-y+0.25=0

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A representation of the linear function on the Cartesian plane is shown in the image attached below.

In this question we need to plot a linear function on a Cartesian plane, which represents a line in a graphic sense- According to Euclidean theorem, lines can be generated with the location of two distinct points. First, determine the y-coordinates associated to two given x-coordinates:

x = 0

y = - 300 · 0 + 1200

y = 0 + 1200

y = 1200

x = 1

y = - 300 · 1 + 1200

y = - 300 + 1200

y = 900

Second, add the points on the Cartesian planes and generate a line that passes through the points. The resulting line is shown in the image attached below.

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a) To find the particular solution of the differential equation y + 4y' + 3y = 6x^2 + x + 9 using the Method of Undetermined Coefficients, we assume that the particular solution has the form:

y_p(x) = Ax^2 + Bx + C

where A, B, and C are coefficients to be determined.

Now, let's find the derivatives of y_p(x):

y_p'(x) = 2Ax + B y_p''(x) = 2A

Substituting these derivatives and y_p(x) into the original differential equation, we get:

(Ax^2 + Bx + C) + 4(2Ax + B) + 3(Ax^2 + Bx + C) = 6x^2 + x + 9

Expanding and collecting like terms, we have:

(A + 3A)x^2 + (4B + 2A + 3B)x + (C + 4B + 3C) = 6x^2 + x + 9

By equating the coefficients of corresponding powers of x on both sides, we obtain the following equations:

A + 3A = 6 -> 4A = 6 -> A = 3/2 4B + 2A + 3B = 1 -> 4B + 3B + 3 = 1 -> 7B = -2 -> B = -2/7 C + 4B + 3C = 9 -> C + 3C - 8/7 = 9 -> 4C = 81/7 -> C = 81/28

Therefore, the particular solution of the differential equation is:

y_p(x) = (3/2)x^2 - (2/7)x + 81/28

b) To find the particular solution of the differential equation y" + 36y = 24cos(6x) - 12sin(6x) using the Method of Undetermined Coefficients, we assume that the particular solution has the form:

y_p(x) = Acos(6x) + Bsin(6x)

where A and B are coefficients to be determined.

Now, let's find the derivatives of y_p(x):

y_p'(x) = -6Asin(6x) + 6Bcos(6x) y_p''(x) = -36Acos(6x) - 36Bsin(6x)

Substituting these derivatives and y_p(x) into the original differential equation, we get:

(-36Acos(6x) - 36Bsin(6x)) + 36(Acos(6x) + Bsin(6x)) = 24cos(6x) - 12sin(6x)

Simplifying, we have:

-36Acos(6x) - 36Bsin(6x) + 36Acos(6x) + 36Bsin(6x) = 24cos(6x) - 12sin(6x)

The terms with sin(6x) cancel out, and we are left with:

0 = 24cos(6x) - 12sin(6x)

This equation is satisfied for any values of A and B.

Therefore, the particular solution of the differential equation is:

y_p(x) = Acos(6x) + Bsin(6x)

where A and B can be any real numbers.

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Answer:

We can start by simplifying each parentheses separately and then adding the resulting expressions:

(2^4 – 5^3 – 7) + (−5^5 − 5^2 + 9 + 17)

= (16 - 125 - 7) + (-3125 - 25 + 9 + 17) (using the fact that 2^4 = 16 and 5^3 = 125)

= (-116) + (-3124) (combining like terms)

= -3240

Therefore, the answer is -3240. To express this number in standard form, we write it as:

-3.24 x 10^3

The negative sign indicates that the number is less than zero, and the 3.24 tells us the value of the number. The "x 10^3" part means that we need to multiply 3.24 by 10^3 (which is 1000) to get the actual value of the number:

-3.24 x 10^3 = -3.24 * 1000 = -3240

So, the answer in standard form is -3.24 x 10^3.

A sample distribution with n = 20 and a five-number summary of 2, 4, 6, 8, and 10 can be generated by arranging the values in increasing order as follows: 2, 2, 3, 4, 4, 5, 6, 6, 7, 8, 8, 8, 9, 9, 9, 9, 10, 10, 10, 10.

To construct a sample distribution with a specific five-number summary, we need to determine the arrangement of values within the dataset. The five-number summary consists of the minimum value (2), the first quartile (Q1, 4), the median (Q2, 6), the third quartile (Q3, 8), and the maximum value (10).

Since the dataset has 20 observations, we need to arrange these values in increasing order while ensuring that they match the given five-number summary. In this case, we can start by placing the minimum value of 2 at the beginning of the dataset. Next, we need to include additional values between 2 and 4 to represent the first quartile. We can add two 2's, a 3, and two 4's to achieve this.

Moving forward, we continue adding values to match the remaining quartiles. For Q2, we include values 5 and 6, and for Q3, we include three 8's and four 9's. Finally, we add four 10's to represent the maximum value.

By arranging the values in this manner, we obtain a sample distribution with n = 20 and a five-number summary of 2, 4, 6, 8, and 10.

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To prove that lim x → 0 x^4 cos(2/x)=0, we need to show that for any ε > 0, there exists a δ > 0 such that |x^4 cos(2/x)| < ε whenever 0 < |x| < δ.

First, we note that -1 <= cos(2/x) <= 1 for all x. Therefore, we have:

x^4 <= x^4 cos(2/x) <= x^4 for all x

Taking the limit as x approaches 0 of both sides, we get:

lim x â 0 x^4 <= lim x â 0 x^4 cos(2/x) <= lim x â 0 x^4

Using the fact that lim x â 0 x^4 = 0, we can conclude that:

0 <= lim x â 0 x^4 cos(2/x) <= 0

Thus, by the squeeze theorem, we have:

lim x â 0 x^4 cos(2/x) = 0

Therefore, we have shown that lim x â 0 x^4 cos(2/x) = 0.

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c. hope it's help you

The quadratic equation has two real solutions because the value of D is positive and greater than zero or D > 0 option (B) is correct.

Any equation of the form \(\rm ax^2+bx+c=0\) where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.

As we know, the formula for the roots of the quadratic equation is given by:

\(\rm x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}\)

We have a quadratic equation:

y = x² - 11x + 7

As we know, the discriminant formula is used to find the nature of the roots.

The  discriminant formula is:

D = b² - 4ac

The standard quadratic equation is:

y = ax² + bx + c

a = 1, b = -11, and c = 7

Plug the values in the formula:

D = (-11)² - 4(1)(7)

D = 121 - 28

D = 93

As the D is positive and greater than zero or D > 0

Thus, the quadratic equation has two real solutions because the value of D is positive and greater than zero or D > 0 option (B) is correct.

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Answer:

2.7027027027027027

Step-by-step explanation:

1,000 grams make a kilogram

Answer:

72

Step-by-step explanation:

Let

Carl grades = x = 62, 78, 59, 89

Number of grades, N = 4

Mean of Carl's grade = sum of x / number of grades,N

= (62 + 78 + 59 + 89) / 4

= 288/4

= 72

Therefore, mean of Carl's grade = 72

One example of a unital commutative ring R that does not admit a unique factorization into irreducible polynomials is the ring of integers in the number field Q(sqrt(-5)). Consider the polynomial f(x) = x^2 + 5. This polynomial is irreducible over Q, but it factors in R as (x + sqrt(-5))(x - sqrt(-5)).

To see why this polynomial does not admit a unique factorization, suppose that f(x) could be factored into irreducible polynomials g(x) and h(x) in R. Then we would have g(x)h(x) = f(x) = x^2 + 5. Since f(x) is irreducible over Q, it is also irreducible over R, so g(x) and h(x) must be non-constant polynomials. Moreover, since R is a unique factorization domain, g(x) and h(x) must themselves be products of irreducible polynomials.

Now consider the constant coefficient of g(x) and h(x). Since the constant coefficient of f(x) is 5, we must have one of the constant coefficients of g(x) and h(x) equal to 1 and the other equal to 5. Without loss of generality, assume that the constant coefficient of g(x) is 1 and the constant coefficient of h(x) is 5. Then the quadratic coefficient of g(x) and h(x) must sum to 0, since the quadratic coefficient of f(x) is 1. But the only way to get a sum of 0 with a constant coefficient of 1 and 5 is to have the linear coefficient of one of the factors be a multiple of sqrt(-5). Without loss of generality, assume that the linear coefficient of g(x) is a multiple of sqrt(-5). Then the constant coefficient of h(x) must be a unit in R, since it is the product of the constant coefficients of g(x) and h(x). But this implies that h(x) is not irreducible in R, since it has a root in R (namely, -sqrt(-5)).

Therefore, we have shown that f(x) does not admit a unique factorization into irreducible polynomials in R.
Hi! I'd be happy to help you with your question. Let's consider the unital commutative ring R = Z/4Z, which is not a field. We will analyze the polynomial f(x) = 2x^2 in R[x].

First, let's note that 2x^2 can be factored as (2x)^2, and both 2x and 2x^2 are non-constant polynomials in R[x]. Since R is not an integral domain, 2x is not a unit, and thus (2x)^2 is not a unit times an irreducible polynomial.

Now let's consider another factorization of 2x^2: (x+2)(2x). Here, x+2 and 2x are also non-constant polynomials in R[x] and neither is a unit.

Thus, we have two distinct factorizations of 2x^2 in R[x]:
1. (2x)^2
2. (x+2)(2x)

Since both factorizations consist of non-constant polynomials and neither contains a unit, we can conclude that 2x^2 does not admit a unique factorization into irreducible polynomials in the unital commutative ring R = Z/4Z.

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Answer:

  2x -16

Step-by-step explanation:

The area of each rectangle is the product of its length and width. The shaded area is the difference between the areas of the outside rectangle and the inside rectangle.

  shaded area = (2x -1)(x +6) -(2x +5)(x +2)

  = (2x^2 +11x -6) -(2x^2 +9x +10)

  = (2 -2)x^2 +(11 -9)x +(-6 -10)

  = 2x -16 . . . . . area of the shaded region