The texture of an igneous rock made up entirely of crystals big enough to be easily seen with the naked eye is phaneritic. Phaneritic texture is sometimes referred to as coarse-grained igneous texture. Granite, the most well known example of an intrusive igneous rock, has a phaneritic texture.
Concentration (mol dm-³) 0.5- 0.4- 0.3- 0.2- 0.1 2. 3 5 The following equilibrium reaction is given: 2HI(g) = H₂(g) + I₂(g) Time (s) H₂/ HI Cy A change in pressure will not affect equilibrium in this case as the number of moles of gas is the same on both sides of the equation. AH> 0 A graph plotting the concentrations of the substances present versus time is given in Figure 7.10. a) b) Explain the physical situation in the container from t=0 s to t = 5 s. Which external factor was altered in order to bring about a change in the shape of the graph at t = 5 s? Explain. Calculate Kat t = 3 s. 1 dm³ COCI, decomposes
Based on the information provided, we have a reaction between hydrogen iodide (HI) gas and hydrogen gas (H₂) to form iodine gas (I₂). The equilibrium is represented by the equation:
2HI(g) = H₂(g) + I₂(g)
The concentration values given in the table correspond to the concentrations of H₂ and HI at different times.
a) From t=0 s to t=5 s: Without the specific graph mentioned in Figure 7.10, it is difficult to provide a precise explanation of the physical situation in the container during this time period. However, based on the equilibrium reaction given, we can make some general observations. At the start (t=0 s), the concentrations of H₂ and HI may be high. As time progresses, the reaction proceeds, and the concentrations of H₂ and HI may decrease while the concentration of I₂ increases. The specific behavior will depend on the rate of the forward and reverse reactions.
b) External factor altered at t=5 s: To bring about a change in the shape of the graph at t=5 s, some external factor must have been altered. The most likely factor is the total pressure within the container. Since the reaction involves gases, changes in pressure can affect the equilibrium position. However, according to the information given, a change in pressure will not affect equilibrium in this case since the number of moles of gas is the same on both sides of the equation. Therefore, if the shape of the graph changes at t=5 s, some other external factor, such as temperature or the addition of a catalyst, must have been altered.
c) Calculation of K at t=3 s: The equilibrium constant (K) can be calculated at any given time using the concentrations of the reactants and products. However, the concentrations of H₂ and HI at t=3 s are not provided in the information given. Without the necessary data, it is not possible to calculate K at t=3 s.
Lastly, the statement "1 dm³ COCI, decomposes" seems incomplete. If you provide additional information or clarify the question, I'll be happy to assist you further.
The elements fluorine (F), chlorine (Cl), and iodine (I) are all part of the same _________on the periodic table.
Explanation:
The elements Fluorine (F),Chlorine (Cl) and Iodine (I) are all part of the same Group ( i.e, Group 17 ) on the periodic table.
Answer:
Group
Explanation:
2. When an acid is dissolved in water, what ion does the water form? Explain what happens to form this ion.
When an acid is added to water, hydronium ions are formed.
What happens when the acid is added to water?
The acid has the ability to give protons that is hydrogen ions. When acid is added to water, water acts as base and takes up the protons released by the acid and forms hydronium ions that is H3O+ ions.
This process is exothermic in nature that is it releases heat. So acid is always added to water and not water to acid.
Therefore, when an acid is added to water, it gives hydronium ions in the water.
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A car tire is inflated to 82.0 kPa in a repair shop where the temperature is 26.0 C
what is the temperature of the air inside the tire is the pressure increases to 87.3 kPa, when the car is taken outside
To determine the temperature of the air inside the tire when the pressure increases to 87.3 kPa, we can use the ideal gas law equation:
PV = nRT
Where:
P = pressure
V = volume
n = number of moles
R = gas constant
T = temperature
Assuming the volume of the tire remains constant, we can rearrange the equation as follows:
P₁/T₁ = P₂/T₂
Where:
P₁ = initial pressure (82.0 kPa)
T₁ = initial temperature (26.0 °C + 273.15 K) [converting Celsius to Kelvin]
P₂ = final pressure (87.3 kPa)
T₂ = final temperature (unknown)
Substituting the values into the equation:
82.0 kPa / (26.0 °C + 273.15 K) = 87.3 kPa / T₂
Now, let's solve for T₂:
T₂ = (87.3 kPa * (26.0 °C + 273.15 K)) / 82.0 kPa
Calculating the expression:
T₂ ≈ 299.19 K
To convert this temperature back to Celsius:
T₂ ≈ 299.19 K - 273.15 ≈ 26.04 °C
Therefore, the temperature of the air inside the tire, when the pressure increases to 87.3 kPa, is approximately 26.04 °C.
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How many grams of oxygen gas will be produced when 2.50 moles of potassium chlorate is decomposed?
Answer:
\(m_{O_2}=120gO_2\)
Explanation:
Hello!
In this case, since the decomposition of potassium chlorate is:
\(2KClO_3\rightarrow 2KCl+3O_2\)
We can see a 2:3 mole ratio between potassium chlorate and oxygen (molar mass 32.0 g/mol), thus, via stoichiometry, we compute the mass of oxygen that are produced by the decomposition of 2.50 moles of this reactant:
\(m_{O_2}=2.50molKClO_3*\frac{3molO_2}{2molKClO_3} *\frac{32.0gO_2}{1molO_2}\\\\m_{O_2}=120gO_2\)
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The parent function f(x) = 1/x has been translated 4 units to the left and 3 units down to create gpx). Which of the following
transformation functions produces g(x)?
g(x) = f(x-3) +4
g(x) = f(x+3) - 4
Oc_g(x)=f(x-4) + 3
Od g(x) = f(x+4) − 3
The original function f(x) = 1/x becomes g(x) = 1/(x+4) - 3 after the transformation.
How to solveThe correct transformation function that reflects a shift of 4 units to the left and 3 units down is g(x) = f(x+4) - 3.
This is because, in function notation, adding to the input value inside the function (x+4) shifts the function to the left, while subtracting from the output of the function (-3) shifts it down.
So, the original function f(x) = 1/x becomes g(x) = 1/(x+4) - 3 after the transformation.
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An igneous rock floats because air bubbles became trapped when molten material erupted from an underground volcano.
How else can this rock be accurately described?
intrusive
extrusive
large crystals
coarse texture
Answer:
D coarse texture
Explanation:
An igneous rock floats because air bubbles became trapped when molten material erupted from an underground volcano. This rock can be accurately described as extrusive and the correct option is option 2.
What are igneous rocks?Igneous rocks (from the Latin word for fire) form when hot, molten rock crystallizes and solidifies. The melt originates deep within the Earth near active plate boundaries or hot spots, then rises toward the surface. Igneous rocks are divided into two groups, intrusive or extrusive, depending upon where the molten rock solidifies.
Igneous rocks can be easily identified with their texture, density, colour, and mineral composition. Its texture depends on the shape, size, time period to cool down and solidify, and the arrangement of crystals in the rock.
Therefore, an igneous rock floats because air bubbles became trapped when molten material erupted from an underground volcano. This rock can be accurately described as extrusive and the correct option is option 2.
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PLEASE HELPPPPPP 100 POINTS!!!!!!!
This isn't a Chemistry question. You might have better luck getting an answer if you posted under Geography.
How many grams of Aspirin (acetylsalicylic acid) should we form in this reaction if we started with 2.08g of Salicyclic Acid?
Taking into account the reaction stoichiometry, 2.713 grams of aspirin are formed when 2.08 grams of salicyclic acid reacts.
Reaction stoichiometryIn first place, the balanced reaction is:
C₄H₆O₃ + C₇H₆O₃ (Salicyclic Acid) →C₉H₈O₄ (aspirin) + C₂H₄O₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
C₄H₆O₃: 1 moleC₇H₆O₃: 1 moleC₉H₈O₄: 1 moleC₂H₄O₂: 1 moleThe molar mass of the compounds is:
C₄H₆O₃: 102 g/moleC₇H₆O₃: 138 g/moleC₉H₈O₄: 180 g/moleC₂H₄O₂: 60 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
C₄H₆O₃: 1 mole ×102 g/mole= 102 gramsC₇H₆O₃: 1 mole ×138 g/mole= 138 gramsC₉H₈O₄: 1 mole ×180 g/mole= 180 gramsC₂H₄O₂: 1 mole ×60 g/mole= 60 gramsMass of aspirin formedThe following rule of three can be applied: if by reaction stoichiometry 138 grams of salicyclic acid form 180 grams of aspirin, 2.08 grams of salicyclic acid form how much mass of aspirin?
\(mass of aspirin=\frac{2.08 grams of salicyclic acidx 180 grams of aspirin}{138 grams of salicyclic acid}\)
mass of aspirin= 2.713 grams
Then, 2.713 grams of aspirin are formed when 2.08 grams of salicyclic acid reacts.
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What's the pH of a solution with a concentration of hydronium ions of 5.29×10–10?Question 4 options:A) 3.34B) 5.29C) 9.28D) 12.1
Answer:
The answer is C.
Explanation:
We are given: H3O+ = 5.29 * 10 ^ -10
We use the pH formula to find pH:
pH = -log[H3O+]
= -log[5.29 * 10 ^ - 10]
= 9.28
what law deals with volume and pressure
Volume and pressure are the properties of the gas that are related by Boyle's law of the ideal gas equation.
What is Boyle's law?Boyle's law is the gas law that gives the relation between the pressure and the volume of the gas at constant moles and temperature conditions. The law is given as,
PV = k (k = constant)
Here P is the pressure and V is the volume of the ideal gas.
From the law, it can be stated that the pressure of the gas is in inverse relation to the volume of the gas. Hence increase in volume decreases the pressure and vice versa.
Therefore, the inverse relationship between the pressure and volume is given by Boyle's law.
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What is the approximate mass of one proton?
Answer:
Both protons and neutrons have the same mass, 1.67*10^-24 grams. This is one Dalton.
Explanation:
An atom is composed of protons, electrons and neutrons. The nucleus contains protons and neutrons and they are collectively called nucleons. The mass of one proton is 1.67 × 10⁻²⁷ kg.
What are protons?The particles which are smaller in size than the size of an atom are called the subatomic particles. An atom contains three sub - atomic particles. They are protons, neutrons and electrons. The positively charged sub atomic particles are called the protons.
In an atom the number of protons and electrons are equal. So the atom is electrically neutral in nature. The mass of one proton is 1.67 × 10⁻²⁷ kg.
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In a chemical reaction, a catalyst changes the ______.
Select one:
a.
heat of reaction
b.
activation energy of the reaction
c.
potential energy of the products
d.
potential energy of the reactants
Answer:
The Correct answer is B
activation energy of the reaction
or
speeds up the reaction
(a) Amina observed that crystals of copper sulphate are formed in the solution, when a
saturated solution of copper sulphate has cooled. Will the solution be still remained as
saturated? Why?
(b) Calculate the mass of sodium sulphate required to prepare its 20% (mass by mass
%) solution in water, if mass of the solution is 80 g
Answer:
See explanation
Explanation:
A saturated solution is a solution that contains just as much solute as it can normally hold at that temperature.
If the temperature is cooled and crystals of copper sulphate are formed in the solution, then the solution is no longer saturated because some solute are now leaving the solution.
b) percent by mass = mass of solute/mass of solution * 100
percent by mass = 20%
mass of solute = x g
mass of solution = 80 g
20 = x/80 * 100
1600 = 100x
x = 1600/100
x = 16 g
How many moles of H atoms are there in 2 moles of CH3CH2CH2CH3?
AnSweR: 10
ExplanAtion: My random idiot friend just told me
How many grams of gold will be produced from 213.46g AuPO4? At. Wt.: Sn = 119g/mol; Au
= 197g/mol; P = 31g/mol; O = 16g/mol
The amount of gold that can be produced from 213.46g AuPO₄ is equal to 143.7g.
What is a mole?A mole is a standard unit that can be used to determine the huge number of quantities of ions, atoms, molecules, or other particular particles. The mass of the 1 mole of any element is known as atomic mass (in grams) and the mass of one mole of any compound is called molar mass.
The number of units in one mole was found to be approximately 6.023 × 10 ²³ also called Avogadro’s constant.
Given, the mass of the AuPO₄ = 213.46 g
The molar mass of the AuPO₄ = 197 + 31 + 4(16) = 292 g/mol
The number of moles of the AuPO₄ = 213/292 = 0.729 mol
If the mole of AuPO₄ will produce one mole of the Au.
Then 0.729 mol of the AuPO₄ will produce Au = 0.729 mol
The mass of the Au (in grams) = 0.729 ×197 = 143.7 g/mol
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which property of physical changes explains why matter is conserved in a physical change
Answer:
b
Explanation:
3
Which chemical equation below is balanced to correctly represent the Law of
Conservation of Mass?
04 Al + 3O2 + 2 Al2O3
O2 AL + O2 + 2 Al2O3
O AL + O2 + Al2O3
Answer:
4Al + 3O₂ → 2Al₂O₃
Explanation:
4Al + 3O₂ → 2Al₂O₃
Only this reaction above obeys the law of conservation of mass. The others flout the rule.
The law of conservation of mass states that "matter is neither created nor destroyed in a chemical reaction but are simply transformed from one form to another".
By this law, the number of atoms on both sides of expression must be the same;
Number of atoms
Elements Left hand side Right hand side
Al 4 4
O 6 6
when an atom absorbs energy, the electrons move from their state to an state. when an atom emits energy, the electrons move from an state to their state and give off a of light.
An atom adjustments from a floor nation to an excited nation via way of means of taking over electricity from its environment in a method referred to as absorption.
The electron absorbs the electricity and jumps to a better electricity level. In the opposite method, emission, the electron returns to the floor nation via way of means of freeing the greater electricity it absorbed.When an atom absorbs electricity, the electrons circulate from their floor nation to an excited nation.
When an atom emits electricity, the electrons circulate from a(n) excited nation to their floor nation and deliver off electricity. When an atom absorbs electricity, the electrons circulate from their floor nation to an Excited nation. whilst an atom emits electricity, the electrons circulate from an excited nation to their floor nation and deliver off electricity(radiation).
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............................................................................................................................
Answer:
............................................................................................................................
Explanation:
because ........................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................
JWhat did Rutherford’s model of the atom include that Thomson’s model did not have?
a nucleus
energy levels
electron clouds
smaller particles
Answer:
Rutherford's model of the atom included the nucleus, something lacking in Thomson's model. Rutherford's inclusion of the nucleus came about after his discovery of the nucleus of the atom in 1911. He was testing J.J. Thomson's Plum Pudding model by directing a beam of alpha particles toward a thin sheet of gold foil.
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Read the information in the table below:Which type of reaction is represented by B?
Answer
A. Endothermic reaction
Explanation
The type of reaction represented by B is endothermic reaction.
________ is an atom that gains electrons; it's valence electrons is similar to a noble gas.
ionic bond
covalent bond
anions
cations
melting point
boiling point
conductivity
polyatomic ions
valence electron
Metal
nonmetal
metaloids
Answer:
nonmetal
________ is an atom that gains electrons; it's valence electrons is similar to a noble gas.
Explanation:
Because non metal like chlorine gain one elctron and attain electronic configuration of noble gas Argon
In using the Haber process in the formation of ammonia, what mass of hydrogen is needed to produce 51.0 grams of ammonia? 3 H₂(g) + N2 (g) → 2 NH3(g).
The mass of hydrogen needed to produce 51.0 grams of ammonia is ≈ 9.07 grams.
To determine the mass of hydrogen required to produce 51.0 grams of ammonia (NH3) using the Haber process, we need to calculate the stoichiometric ratio between hydrogen and ammonia.
From the balanced chemical equation:
3 H₂(g) + N₂(g) → 2 NH₃(g)
We can see that for every 3 moles of hydrogen (H₂), we obtain 2 moles of ammonia (NH₃).
First, we need to convert the given mass of ammonia (51.0 grams) to moles. The molar mass of NH₃ is 17.03 g/mol.
Number of moles of NH₃ = Mass / Molar mass
= 51.0 g / 17.03 g/mol
≈ 2.995 moles
Next, using the stoichiometric ratio, we can calculate the moles of hydrogen required.
Moles of H₂ = (Moles of NH₃ × Coefficient of H₂) / Coefficient of NH₃
= (2.995 moles × 3) / 2
≈ 4.493 moles
Finally, we can convert the moles of hydrogen to mass using the molar mass of hydrogen (2.02 g/mol).
Mass of H₂ = Moles × Molar mass
= 4.493 moles × 2.02 g/mol
≈ 9.07 grams
Therefore, approximately 9.07 grams of hydrogen is needed to produce 51.0 grams of ammonia in the Haber process.
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Classify each of the following as an exothermic or endothermic reaction. Drag the appropriate statements to their respective bins. Reset Help The energy level of the reactants is lower than that of the products. The combustion of wood provides energy A reaction releases 101 J. Exothermic Endothermic Submit Request Answer
1. The energy level of the reactants is lower than that of the products. - Endothermic
2. The combustion of wood provides energy - Exothermic
3. A reaction releases 101 J. - Exothermic
What is an Endothermic?
An endothermic process or reaction is a chemical or physical process that absorbs heat from the surroundings. In an endothermic process, energy is required to break the bonds in the reactants and form new bonds in the products. As a result, the temperature of the surroundings decreases, and the process feels cold to the touch. Examples of endothermic processes include melting ice, cooking an egg, and evaporating water.
What is an Exothermic?
An exothermic process or reaction is a chemical or physical process that releases heat into the surroundings. In an exothermic process, energy is released as the bonds in the reactants are broken and new bonds are formed in the products. As a result, the temperature of the surroundings increases, and the process feels warm to the touch. Examples of exothermic processes include burning a candle, combustion reactions, and the reaction between baking soda and vinegar.
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How is dinitrogen (1) oxide distinguished shed from oxygen
Answer:
See Explanation
Explanation:
Both oxygen and dinitrogen (1) oxide are known to rekindle a glowing splint. However, oxygen is an odorless gas while dinitrogen (1) oxide has a faint smell and has an effect on the central nervous system.
Also, the combustion of dinitrogen (1) oxide produces brown fumes of nitrogen IV oxide.
Finally, when dinitrogen (1) oxide and oxgen are both heated with copper, residual nitrogen gas is left with dinitrogen (1) oxide while no residual gas is left with oxygen.
share the imporatant lesson that you have learned in organic chem
We study the reactions that chemists utilise to create bizarre carbon-based structures in organic chemistry.
The study of the makeup, properties, and responses of organic compounds including organic materials, or matter in any of its many forms that contains carbon atoms, is the subject of the branch of science known as organic chemistry. Their structural formula is determined by study of structure.
We will study the reactions that chemists utilise to create bizarre carbon-based structures in organic chemistry, in addition to the analytical techniques used to characterise them. We'll also consider the molecular reaction mechanisms that are driving those reactions.
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Which part of the cell does this illustration represent?
cytoskeleton
endoplasmic membrane system
mitochondria
Calvin cycle center
The answer is:
C.(mitochondria)
I took the test, hope this helps!
1.025 x 0.00034 x 5752.3 =
Which best describes a chemical reaction that follows the law of conservation of matter
A. The reactants have the same mass as the product
B. The reactants have the same density as the product
C. The products conserves all physical properties of the reactant
D. The products conserve all chemical properties of the reactants
Answer:
A
Explanation:
The Law of Conservation of Matter says that the amount of matter (mass) stays the same, even when matter changes its form.