Guys please help I’m stuck

To draw the Lewis structure for sulfate (SO₄²⁻) with minimized formal charges and determine the total likely resonance structures, follow these steps:

1. Identify the central atom: Sulfur (S) is the central atom in the sulfate ion.
2. Count the total number of valence electrons: Sulfur has 6, each oxygen has 6, and there are 2 extra electrons due to the 2- charge. So, the total number of valence electrons is 6 + 4(6) + 2 = 32.
3. Connect the central atom to the surrounding atoms with single bonds: Connect the sulfur atom to each of the four oxygen atoms using single bonds. This uses up 8 valence electrons (2 for each bond).
4. Distribute the remaining valence electrons to complete the octets of the surrounding atoms: 32 - 8 = 24 valence electrons are left. Distribute them to the four oxygen atoms to complete their octets (6 electrons for each oxygen atom).
5. Check for the need for multiple bonds to satisfy the octet rule for the central atom: Sulfur has 8 electrons around it (1 from each single bond), so the octet rule is satisfied.

Now, the Lewis structure is complete with minimized formal charges. However, there are multiple resonance structures for SO₄²⁻. Since sulfur can form double bonds with any of the four oxygen atoms, there are a total of 4 likely resonance structures for SO₄²⁻, with one double bond in each resonance structure and the remaining oxygen atoms having single bonds.

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Answer:

C) Carla participated in an artistic activity, while Maurice participated in a scientific activity.

Explanation:

Scientific activities involve making observations, which ultimately leads to the series of steps that aims at solving the observed problem or answering a question that arises from the problem. This is the case of Maurice who is observing and recording information about ants in order to solve a curiosity (about what they feed on).

However, on the other hand, Carla is given a pictorial representation of the ants and what they carry. It is not based on curiosity or to answer a question about the ants but rather for decoration or aesthetic purposes, which is what makes her activity artistic.

Answer: As the airplane goes higher, the mechanical energy is changed into gravitational potential energy. While flying, some energy is lost through drag to thermal (heat) energy and sound energy. Some is also lost as the plane makes the air around it move. ... As speed and height decrease, kinetic and potential energy decrease.

Explanation:

Hope this help

Hi Steven!

So yet again, we find ourselves doing math when we thought the class was chemistry!  For this we're going to do a standard conversion that we do a lot in GenChem, converting from grams to moles.

In this case, we're starting with 0.171g N2O.  Let's go ahead and convert that to moles by using the molar mass, which is 44.013 g/mol.

.171 g N2O * (1 mol N2O / 44.013 g N2O) = 0.00389 mol N2O

So we got to moles of dinitrogen monoxide - now we need to know how many moles of nitrogen!  We see that there's a subscript of 2 after the N, meaning there are two moles of N for every mol of N2O.  You can think of it in terms of food -- for every 1 sandwich, there are two pieces of bread.

So let's multiply the number of moles of N2O by 2, to get moles of N!

.00389 mol N2O * ( 2 mol N / 1 mol N2O) = .00778 mol N!

Hope that helps :)

Answer:

- Carbon shares four of its electrons, and each oxygen shares two of its electrons.

Explanation:

Carbon needs 4 electrons to reach a full outer shell while oxygen needs 2 to reach a full outer shell.

Answer:

If earth was 103 miles away from the sun, earth wouldn't be here, it would have burned up. But lets pretend that if earth didn't burn up, it wouldn't be able to support life because of these reasons. The temperature will be 10000 times hotter than it is now. The extreme heat will evaporate any water instantly, which means no water for plants to live in... There will also be no atmosphere because the sun will burn it up, because the sun will be in the atmosphere, so there will also be no oxygen.

Out of the given options, C) crystal violet can be used as an indicator at the lowest pH.

C) Crystal violet changes color from violet to yellow when the pH drops from 0.0 to 1.6. It is a triarylmethane dye that acts as a pH indicator in the acidic range. Crystal violet is often used to stain bacteria and as an indicator in acid-base titrations. Other indicators such as thymol blue, thymolphthalein, and methyl red have a pH range of 8.0-9.6, 9.3-10.5, and 4.4-6.2, respectively. 2,4-dinitrophenol is not a pH indicator, but a protonophore that uncouples oxidative phosphorylation. Therefore, if you need to use an indicator at a very low pH, crystal violet is a suitable option.

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Answer: Fractional distillation is the separation of a mixture into its component parts, or fractions. Chemical compounds are separated by heating them to a temperature at which one or more fractions of the mixture will vaporize. It uses distillation to fractionate.

Explanation:

Based on the Laws of Thermodynamics, when a beaker of isobutyl alcohol is put inside a sealed tank containing isobutyl alcohol gas at 103.

Degree c and 619. torr, the pressure inside the tank will be higher than the pressure in the beaker, causing some of the liquid to evaporate and increase the liquid volume in the beaker. Therefore, after ten minutes, there will be more liquid in the beaker than before.

When a beaker of isobutyl alcohol is put inside a sealed tank containing isobutyl alcohol gas at 103°C and 619 torr, the molecules of isobutyl alcohol gas in the tank will be more energetic due to the increased temperature. As a result, they will move faster and collide with each other more frequently, raising the pressure inside the tank. The higher pressure in the tank will push molecules of isobutyl alcohol gas into the beaker, where they will condense into liquid due to the decrease in pressure.

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In a redox reaction, there are two important things that must be balanced: the number of electrons and the overall charge. Redox reactions involve the transfer of electrons from one reactant to another, and the number of electrons transferred must be equal on both sides of the equation. This ensures that the reaction is balanced and that conservation of mass is maintained. Additionally, the overall charge of the reactants and products must be balanced. This is done by adding electrons or ions to the equation as needed to ensure that the net charge is equal on both sides. Balancing both the number of electrons and the overall charge in a redox reaction is crucial for understanding and predicting chemical reactions.
Hi! In a redox reaction, two things that must be balanced are the number of atoms and the charges. To achieve a balanced redox reaction, you need to follow these steps:

1. Assign oxidation states to all elements involved in the reaction.
2. Identify the elements that undergo oxidation (increase in oxidation state) and reduction (decrease in oxidation state).
3. Write separate half-reactions for oxidation and reduction.
4. Balance the number of atoms for each half-reaction.
5. Balance the charges by adding electrons to the appropriate side of each half-reaction.
6. Adjust the coefficients to make sure the number of electrons gained in the reduction half-reaction equals the number of electrons lost in the oxidation half-reaction.
7. Combine the two half-reactions to form the balanced redox reaction.

By following these steps, you'll ensure both atoms and charges are balanced in your redox reaction.

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When the pressure is changed to 2.76 atm, is approximately 754.19 Kelvin. When the pressure inside the steel bottle is changed to 2.76 atm while containing argon gas at standard temperature and pressure (STP), the final temperature of the gas will increase.

According to the ideal gas law, PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin. Since the volume remains constant in this case, we can rearrange the equation as P₁/T₁ = P₂/T₂, where P₁ and T₁ are the initial pressure and temperature, and P₂ and T₂ are the final pressure and temperature. Given that the initial conditions are at STP, the initial temperature is 273.15 K. If we substitute the values into the equation, we get 1 atm / 273.15 K = 2.76 atm / T₂. Solving for T₂, we find T₂ = (273.15 K) * (2.76 atm / 1 atm) ≈ 754.19 K.Therefore, the final temperature of the argon gas in the steel bottle, when the pressure is changed to 2.76 atm, is approximately 754.19 Kelvin.

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Answer:

d) group 18

Explanation:

Group 18 on the periodic table consists of noble gasses, which do not chemically interact with other elements.

It will improve the accuracy of your Rf value measurement by allowing for better pigment separation.

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In a liquid-liquid extraction (LLE) system with loratadine and pseudoephedrine sulfate, the choice of organic and aqueous phases is crucial for efficient separation.

Loratadine is a non-polar compound, while pseudoephedrine sulfate is more polar due to the presence of a sulfate group. To achieve effective separation, we need to choose a suitable organic phase and aqueous phase.

For the organic phase, a non-polar solvent such as diethyl ether, ethyl acetate, or chloroform can be used. These solvents have good solubility for loratadine. The non-polar organic phase will extract loratadine from the mixture, allowing for separation from the aqueous phase.

As for the aqueous phase, we need to choose a polar solvent that will selectively extract pseudoephedrine sulfate. Aqueous solutions of acids like hydrochloric acid (HCl) or sulfuric acid (H2SO4) can be used. The acidic conditions protonate the pseudoephedrine sulfate, making it more soluble in the aqueous phase.

To perform the extraction, the mixture of loratadine and pseudoephedrine sulfate is added to the LLE system consisting of the organic phase (non-polar solvent) and the aqueous phase (acidic solution). The mixture is then vigorously shaken to ensure thorough mixing and extraction.

After shaking, the phases are allowed to separate, with the more dense aqueous phase settling at the bottom and the less dense organic phase on top. The layers can be carefully separated, and each phase can be further processed to isolate the desired compounds.

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Answer:

6.94 x 10²⁴molecules

Explanation:

Given parameters:

Mass of water  = 207.45g

Unknown:

Number of molecules  = ?

Solution:

To solve this problem, we must understand:

      1 mole of a substance  contains 6.02 x 10²³ molecules

Now, first find the number of moles of water;

 Number of moles  = \(\frac{mass}{molar mass}\)  

 Molar mass of water  = 2(1) + 16  = 18g/mol

  Number of moles  = \(\frac{207.45}{18}\)   = 11.53moles

So;

          1 mole of a substance  contains 6.02 x 10²³ molecules

       11.53moles of carbon dioxide will contain 11.53 x  6.02 x 10²³

                                                                 = 6.94 x 10²⁴molecules

Answer:

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

From the question

density of metal = 5.78 g/mL

volume = final volume of water - initial volume of water

volume = 24.7 - 22.3 = 2.4 mL

We have

mass = 5.78 × 2.4 = 13.872

We have the final answer as

Hope this helps you

remaining reactant after 120 seconds if the half-life is 60 seconds for a first-order reaction = 25% of [A]₀

half life = 60 seconds

120 seconds = 2 half lives

Amount left = \(\frac{1}{2^n} } [A]_0\\\)

n = 2

Amount left = \(\frac{1}{2^{2} }[A]_{0}\)

= \(\frac{[A]_{0} }{4}\)

Amount left = 25% of [A]₀

The half-life of a reaction is the time expected for a reactant to arrive at one-a portion of its underlying fixation or strain. For a first-request response, the half-life is free of focus and steady after some time.

For a zero order reaction (Half life decreases with decreasing concentration.) For a 1st order reaction (Half life is constant.) For a second order reaction (Half life increases with decreasing concentration.)

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Answer: Copper (I) Carbide

Explanation:

Copper is a polyatomic ion, meaning it has multiple charges. Carbon has an outer shell consisting of 4 valence electrons so it can either add or lose 4 electrons so it’s charge can be -4 or +4. As said Copper has multiple charges but they are positive, so in this case Cu4 would be 4 +1 charges compared to C which would be -4. Therefore this is a 4:1 ratio, meaning Cu4C is Copper (I) Carbide

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The final pressure in the vessel will be three times the initial pressure, or 3P1.

Since the reaction goes essentially to completion, we can assume that all of the CH₃OH(g) will be converted into CO(g) and 2 H₂(g). Therefore, the total number of moles of gas in the vessel will increase from 1 to 3.

Using the ideal gas law, we can calculate the final pressure in the vessel:

P1V1/T1 = nRT/V2

where P1 is the initial pressure, V1 is the initial volume (which we can assume is negligible), T1 is the initial temperature (600 K), n is the initial number of moles (1), R is the gas constant, and V2 is the final volume.

Solving for P2 (the final pressure):

P2 = (n + 2)RT1/V1

Substituting the values we know:

P2 = (1 + 2)RT1/V1

P2 = 3P1

Therefore, the final pressure in the vessel will be three times the initial pressure, or 3P1.

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COMPLETION QUESTION:

CH₃OH(g) —> CO(g) + 2 H₂(g)

DH° = +91 kJ/molrxn

The reaction represented above goes essentially to completion. The reaction takes place in a rigid, insulated vessel that is initially at 600 K A sample of CH3OH(g) is placed in the previously evacuated vessel with a pressure of P1 at 600 K. What is the final pressure in the vessel after the reaction is complete and the contents of the vessel are returned to 600 K?

To change the lengths of the sides of a triangle (7 cm, 4 cm, and 10 cm) so they form a right triangle, we need to modify the length of the longest side. By using the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides, we can determine the new length. In this case, the new length of the longest side, rounded to the nearest tenth, is approximately 10.8 cm.

In a right triangle, the Pythagorean theorem can be used to relate the lengths of the sides. According to the theorem, in a right triangle with sides of lengths a, b, and c (where c is the hypotenuse, the side opposite the right angle), the following equation holds true: a^2 + b^2 = c^2.

In the given triangle, the longest side is 10 cm. To make the lengths form a right triangle, we need to modify the length of the longest side. Let's assume that the new length is x.

Using the Pythagorean theorem, we can set up the equation: 7^2 + 4^2 = x^2.

Simplifying the equation, we have 49 + 16 = x^2, which becomes 65 = x^2.

Taking the square root of both sides, we find that x ≈ 8.06.

Therefore, the new length of the longest side, rounded to the nearest tenth, is approximately 8.1 cm.

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Answer:

Protons

Neutrons

Electrons

Explanation:

The variables of the ideal gas equation and their units of measurement are as follows:

The ideal gas equation is an equation that shows the relationship between the four parameters used in gas measurements.

The four variables are:

The ideal gas equation is given below:

PV = nRT

where:

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A backdraft explosion can occur when there is a lack of oxygen in a partially-burned room. This situation can be exacerbated if a door is opened into the room, introducing a sudden supply of oxygen, which then leads to a rapid combustion of the remaining fuel, causing the explosion. A fire being very smoky may also indicate a lack of oxygen, increasing the risk of a backdraft explosion.

A backdraft explosion can occur under certain conditions such as when there is a lack of fuel in a partially-burned room or a lack of oxygen in a partially-burned room. Additionally, if a door is opened into a room instead of opening into a hallway or outside, it can create a draft that can lead to a backdraft explosion. Furthermore, a fire that is very smoky can also lead to a backdraft explosion as the smoke can build up and ignite when oxygen is suddenly introduced. It is important to be aware of these potential dangers and to take necessary precautions to prevent a backdraft explosion from occurring.

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Answer:

5 mol NaOH = 5 mol NaClO

Plantear y balancear reacción: NaOH + HClO ⇒ NaClO + H2O

Como se puede apreciar, los coeficientes estequiométricos son uno por lo tanto, la cantidad de NaClO que se genera será igual a la cantidad de moles que reaccionan de NaOH

c.15gof in25mlof wather

The sugar solution that is the most concentrated is 15 g of sugar in 25 mL of water.

CONCENTRATION:

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The approximate concentration of reaction product in a solution that has an absorbance of 0.7 at ph 6.0 is based on the equation A = εbc given in the passage, the concentration c is the absorbance A divided by the absorptivity ε in a 1 cm path length cell. 0.7 divided by approximately 1400 gives 500 μM.

A = εbc

0.7 = 1400 x c

7/14000 = 1/2000 = 0.0005 = 5x10^-4 = 500 μM

1 μM = 1 x10 ^-6

The concentration of a substance is the amount of solute present in a given volume of solution. Concentration is usually expressed in molarity, defined as the number of solutes in 1 L of solution. Solution concentration is a measure of the amount of solute dissolved in a given amount of solvent or solution.

Concentrated solutions are solutions that contain relatively large amounts of solutes. Dilute solutions are solutions that contain relatively small amounts of solutes. The definition of concentration means the amount of an ingredient or part relative to other ingredients or parts. An example of concentration is the amount of salt to water in a brine solution.

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Answer:

Hey mate.....

Explanation:

This is ur answer.....

An atmosphere is the layers of gases surrounding a planet or other celestial body. Earth's atmosphere is composed of about 78% nitrogen, 21% oxygen, and one percent other gases.

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Answer:

I'm not really sure if you're interested in the electron dot diagram of the potassium and bromine atoms, or of potassium bromide,

KBr, so I'll show you both. You can use this example to find the electron dot diagram of hydrogen bromide, HBr.

Explanation:

If Q is less than Keq, the reaction proceeds to the right. Therefore, the correct option is option A.

The reaction quotient, Q, which is a dimensionless variable in chemical thermodynamics, measures the proportions of products and reactants in a reaction mixture at a given time for a reaction with a known overall stoichiometry.

Taking into account the stoichiometric coefficients of the reaction as exponents of the concentrations, it is mathematically defined as the proportion of the activities (or molar concentrations) for the product species above. If Q is less than Keq, the reaction proceeds to the right.

Therefore, the correct option is option A.

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The vapor pressure of the CCl4-I2 solution at 65°C is 443 mm Hg.

The vapor pressure of the CCl4-I2 solution at 65°C can be calculated by using Raoult's law.

Raoult's law states that the vapor pressure of a solution is equal to the product of the mole fraction of each component in the solution and its vapor pressure as a pure substance.

Mathematically, it is represented as:

Ptotal = ΣP°iXi

where Ptotal is the total vapor pressure of the solution

P°i is the vapor pressure of the pure substance i

Xi is the mole fraction of substance i.

Let us calculate the mole fraction of CCl4 and I2 in the solution.

Mass of pure I2 = 105 g

Molar mass of I2 = 253.8 g/mol

Number of moles of I2 = 105 g/253.8 g/mol

                                       = 0.4147 mol

Mass of CCl4 = 325 g

Molar mass of CCl4 = 153.8 g/mol

Number of moles of CCl4 = 325 g/153.8 g/mol

                                            = 2.11 mol

Total number of moles in the solution = 2.11 + 0.4147

                                                                = 2.525 mol

Mole fraction of CCl4 = 2.11/2.525

                                     = 0.835

Mole fraction of I2 = 0.4147/2.525

                                = 0.165

We are given that the vapor pressure of CCl4 at 65°C is 531 mm Hg.

P°CCl4 = 531 mm Hg

Using Raoult's law:

Ptotal = ΣP°iXi

Ptotal = P°CCl4 x XCCl4

Ptotal = 531 mm Hg x 0.835

Ptotal = 443 mm Hg

Therefore, the vapor pressure of the CCl4-I2 solution at 65°C is 443 mm Hg.

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