Answer:
1000
1200
2.4
10.8
100
4.2
6
24000000
0.75
5. In the figure below, a porous pot with a straw connected to it was filled with hydrogen gas to a pressure equal to atmospheric pressure. The pot was inverted such that the straw was immersed in water as shown. 오 The water was found to soon rise up the straw to a great height. Explain this observation. (3mks)
Being lighter than air, hydrogen diffuses into the porous pot more quickly. As a result, the pressure inside the pot rises and water is pushed to flow out in the form of a fountain.
Hydrogen particles are lighter, smaller, and move considerably more quickly than airborne particles. Air particles are diffusing out of the porous pot and hydrogen particles are diffusing in; however the hydrogen particles move more quickly.
This implies that a build-up of particles inside the pot will occur soon.
Pressure in the pot reduces below the atmospheric pressure. Hence the greater atmospheric pressure on the surface of the water pushes the water up the tube.
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In this problem you will consider the balance of thermal energy radiated and absorbed by a person. Assume that the person is wearing only a skimpy bathing suit of negligible area. As a rough approximation, the area of a human body may be considered to be that of the sides of a cylinder of length L=2.0 m and circumference C= 0.8 m. For the Stefan-Boltzmann constant use 5.67*10^-8 W/m^2/K^4 . A) If the surface temperature of the skin is taken to be Tbody= 30 degrees C, how much thermal power Prb does the body described in the introduction radiate? Take the emissivity to be e=0.6 . Express the power radiated into the room by the body numerically, rounded to the nearest 10 W. B) Find Pnet, the net power radiated by the person when in a room with temperature Troom=20degrees C . Express the net radiated power numerically, to the nearest 10 W.
A) The body radiates approximately 190 W of thermal power into the room.
B) The net power radiated by the person is approximately 170 W.
C) The net radiated power by the person, when in a room with a temperature of 20 degrees Celsius, is approximately 452 W (rounded to the nearest 10 W).
A) The thermal power radiated by the body (Prb) can be calculated using the Stefan-Boltzmann law:
Prb = e * σ * A * (Tbody⁴ - Troom⁴)
Where:
e is the emissivity (0.6),
σ is the Stefan-Boltzmann constant (5.67 * 10⁻⁸ W/m²/K⁴),
A is the surface area of the body (2πrL, where r is the radius of the body),
Tbody is the temperature of the body (30 degrees C + 273.15 K),
Troom is the temperature of the room (20 degrees C + 273.15 K).
Substituting the given values into the equation, we can calculate Prb.
B) The net power radiated by the person (Pnet) is given by the difference between the power radiated by the body and the power absorbed from the room:
Pnet = Prb - Pabs
Pabs can be calculated using the Stefan-Boltzmann law:
Pabs = e * σ * A * Troom⁴
Substituting the given values into the equation, we can calculate Pabs. Then, we can calculate Pnet by subtracting Pabs from Prb.
C) Using the given dimensions, the radius (r) of the cylinder can be calculated from the circumference (C):
C = 2πr
0.8 = 2πr
r = 0.8 / (2π)
r ≈ 0.127 m
Now we can proceed with the calculation of the net radiated power (Pnet).
Using the Stefan-Boltzmann law, we can find the power absorbed (Pabs) by the person from the room temperature:
Pabs = εσA(Troom⁴)
Where:
ε is the emissivity (0.6)
σ is the Stefan-Boltzmann constant (5.67*10⁻⁸ W/m²/K⁴)
A is the surface area of the body (2πrL, where r is the radius and L is the length)
Troom is the room temperature (20 + 273.15 K)
Substituting the known values:
A = 2πrL
= 2π(0.127)(2.0)
≈ 0.802 m²
Troom = 20 + 273.15
= 293.15 K
Pabs = (0.6)(5.67*10⁻⁸)(0.802)(293.15⁴)
Performing the calculations, we find that Pabs is approximately 228 W.
The net radiated power (Pnet) can be calculated by subtracting Pabs from the total radiated power (Prb) obtained in Part A:
Pnet = Prb - Pabs
Since Prb was calculated to be approximately 680 W (as mentioned in Part A), we can now determine Pnet:
Pnet = 680 - 228 ≈ 452 W
Therefore, the net radiated power by the person, when in a room with a temperature of 20 degrees Celsius, is approximately 452 W (rounded to the nearest 10 W).
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Help!! Or I get an F!!!
What planet could you jump the highest?
Answer:
Is Mercury an answer on your thing?
Explanation:
Mercury has the least amount of gravity, so therefore you can jump the highest on Mercury.
Answer:
Jupiter
Explanation:
Jupiter has more than 300 time the mass as earth. so, it's gravitational pull is stronger.
Hopefully this helps
Jorge asked, "Where are the apples?" Which sentence revises the sample sentence to the indicative mood? Where are the apples? Jorge wanted to know where the apples were. Jorge said, “Tell me where the apples are!” Jorge would have bought apples if he could have found them.
Answer:
Jorge wanted to know where the apples were
Explanation:
Ya see, I don't want to explain, cuz I guessed. Also I'm on episode 499 of naruto so yeah
Answer:
B:Jorge wanted to know where the apples were.
Explanation:
If you planned to bike to a park that was five miles away, what average speed would you have to maintain to arrive in about 15 min? (
The average speed you need to maintain is 0.33 miles per minute.
The average speed is the speed that you maintain throughout the journey. It is obtained as; Total distance covered/Total time taken
If we have the following information from the question;
Distance covered = 5 miles
Time taken = 15 mins
Then it follows that;
Average speed = Distance/time
Average speed= 5 miles/15mins
Average speed = 0.33 miles per minute.
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When a source of dim orange light shines on a photosensitive metal, no photoelectrons are ejected from its surface. what could be done to increase the likelihood of producing photoelectrons
Answer: Replace the orange light source with a higher frequency light source
Explanation:
To expel electrons from a piece of metal, the incoming light must have a minimum frequency to cause a photoelectric effect, i.e., the ejection of photoelectrons from a metal surface, which is also known as the metal's threshold frequency.
If v = frequency of incident photon and vth= threshold frequency, then,
For v < vth, there will be no ejection of photoelectron.For v = vth, photoelectrons are just ejected from the metal surface, in this case, the kinetic energy of the electron ejected is zeroFor v > vth, then photoelectrons will come out of the surface along with kinetic energyTherefore, we would have to increase the frequency of incident light so that it becomes greater than the threshold frequency of that surface, and consequently a photoelectric process takes place.
What gravitational force does the earth exert on a person
standing on the surface of the earth? The mass of the earth is
5.97 x 1024 kg, the mass of the person is 62 kg and the radius
of the earth is 6.4 x 106 m.
The gravitational force exerted by the earth on a person standing on the earth's surface is 602.74 N.
What is the gravitational force of the earth on the person?The gravitational force exerted by the earth on a person standing on the earth's surface is given below as follows:
\(F = \frac{Gm^{1}m^{2}}{r^{2}}\)where
G = 6.67 * 10⁻¹¹
m¹ = 62 kg
m² = 5.97 * 10²⁷ kg
r = 6.4 * 10⁶ m
\(F = \frac{5.97*10^{24}*62*6.67*10^{-11}}{(6.4*10^{6}){2}} = 602.74\:N\)
Therefore, the gravitational force exerted by the earth on a person standing on the earth's surface is 602.74 N.
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When viewed straight down (90° to the surface), an incident light ray moving from the water to air is refracted
When viewed straight down (90° to the surface), an incident light ray moving from water to air does not undergo refraction as it passes through the interface.
When viewed straight down (90° to the surface), the incident light ray moving from water to air does not undergo refraction as it passes through the interface. Refraction occurs when light passes from one medium to another at an angle. At 90°, the light ray travels perpendicular to the surface, resulting in a normal incidence. In this case, the light ray does not change its direction as it transitions from water to air. The refractive index governs the bending of light at the interface, but at 90°, the change in direction is negligible. Therefore, the incident light ray appears to continue in a straight line without deviation when observed directly from above.
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Which is a property of a neutron?
A)0charge
B)+1 charge
C)-1 Charge
D)Essentially no mass
Answer:
A. Neutrons have 0 Charge
Explanation
Neutrons have no charge for the same reason that plastics (and other insulators don't). They just don't.
"This isn't a great answer, but the thing with charge is that we don't really know what "charge" is. We know that certain "charged" objects will attract some objects, while repelling . We also know that other other "charged" objects will behave the same way, but when the two charged objects are brought together, they repell."
Question 6 of 10
The bonds of the products store 27 kJ more energy than the bonds of the
reactants. How is energy conserved during this reaction?
A. The reaction uses up 27 kJ of energy when bonds break.
B. The surroundings absorb 27 kJ of energy from the reaction
system.
C. The reaction system absorbs 27 kJ of energy from the
surroundings.
D. The reaction creates 27 kJ of energy when bonds form.
Energy conserved during this reaction in this way; The reaction system absorbs 27 kJ of energy from the surroundings. Option C
what should you know about conserving or storing energy in this scenario?In the situation that has been described, it showss that the reaction is endothermic, which means it requires energy to proceed.
The bonds in the products store more energy than those in the reactants, and that extra energy has to come from somewhere, and the only explanation is that it came from the surroundings.
The energy is conserved because it is not lost or created; it is simply transferred from the surroundings to the system.
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1. A 2.08 m tall man stands 1.78 m from a lens with focal length 28.3 cm.
How tall (in m) is his image formed by the lens? Be sure to include the sign to indicate orientation!
2. When laser light of some unknown wavelength hits a diffraction grating with 20 slits per millimeter, it produces bright fringes separated by 27.2 mm on a screen that is 2.41 m away.
Given the pattern formed, what must be the wavelength of the light (in nm)?
1. The height of the image is 0.287 m.
2. The wavelength of the light is 563 nm.
1. The image distance, denoted as `i`, is determined by the lens formula: `1/f = 1/o + 1/i`, where `f` represents the focal length, `o` is the object distance, and `i` represents the image distance. Given `f = 28.3 cm` and `o = 1.78 m`, we need to convert the object distance from meters to centimeters: `o = 1.78 m = 178 cm`. Therefore, the image distance is calculated as follows:
i = (1/f - 1/o)^-1 = (1/28.3 - 1/178)^-1 = 24.53 cm.
The image height, denoted as `h'`, can be determined using the object height `h` and the magnification `m` relationship: `h' = m * h`. The magnification `m` is given by `m = -i/o`, where the negative sign indicates an inverted image. Thus,
m = -i/o = -(24.53 cm)/(178 cm) = -0.138.
The image height `h'` is obtained by multiplying `h` by `m`: `h' = m * h`, where `h = 2.08 m`. Therefore,
h' = (-0.138) * 2.08 = -0.287 m.
The negative sign signifies an inverted image. Hence, the height of the image is determined as `0.287 m`, and it is inverted.
2. Bright fringes are observed at angles `theta` satisfying the condition `d sin theta = m lambda`, where `d` represents the spacing between two slits, `m` is an integer indicating the fringe order, and `lambda` denotes the wavelength of light. In this case, given `d = 1/20 mm` and `m = 1`, the angle `theta` corresponding to the first bright fringe is given by `tan theta = x/L`, where `x` represents the separation between two fringes, and `L` is the distance from the grating to the screen. With `x = 27.2 mm` and `L = 2.41 m`, we can calculate:
tan theta = (27.2 mm)/(2.41 m) = 0.01126.
Therefore, `sin theta = tan theta = 0.01126`.
Consequently, the wavelength `lambda` is determined using the formula `lambda = d sin theta / m`, where `d = 1/20 x 10^-3 m`, `sin theta = 0.01126`, and `m = 1`:
lambda = (1/20 x 10^-3 m) x 0.01126 / 1 = 5.63 x 10^-7 m = 563 nm.
In summary:
1. The height of the image is 0.287 m.
2. The wavelength of the light is 563 nm.
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When the atmosphere becomes loaded with particles, only the _____ wavelengths are able to penetrate the atmosphere.
Visible light are able to penetrate the atmosphere
What is Wavelength?A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in the consecutive cycles. This length is often defined in wireless systems in metres (m), centimetres (cm), or millimetres (mm).
The electromagnetic spectrum is made up of a variety of electromagnetic radiations, including radio waves, microwaves, infrared light, visible light, ultraviolet light, X-rays, and gamma rays. Because the earth's atmosphere blocks off the majority of the electromagnetic spectrum's wavelengths, most electromagnetic energy from space cannot reach the planet's surface.
. A portion of the electromagnetic spectrum that humans can see with our eyes is the visible light or spectrum. The electromagnetic spectrum's band that can most easily reach Earth's surface is also this one.
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1- what is a machine?
2- what do we mean my "energy"
3- what are fuels?
4-how do we measure energetic change?
5- what is efficiency?
6- what kind of machines are theres
a ballet director assigns slow graceful steps to lager dancers and quick movements to smaller dancers
This plan can be successful because larger dancers often have a natural grace and fluidity to their movements, while smaller dancers in a ballet tend to be more agile and quick.
Why does size matter in ballet?Ballet is an important part of dance history. Ballet aims to tell stories through movement by adhering to strict, classical rules that were established in France around 1661. Ballet values the dancer's grace, stories, histories, movement, and self-discipline.
By playing to these strengths, the ballet director can create a more visually appealing and dynamic performance. Additionally, this approach can help to ensure that each dancer is able to showcase their unique abilities and contribute to the overall success of the production.
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The complete question is:
A ballet director assigns slow, graceful steps to larger dancers, and quick movements to smaller dancers. Why is this plan successful?
At the start of a hockey game the record a job at the puck between two players from the opposing team. Each player wants to push the puck in the opposite direction. For several seconds the park does not move even though both players are pushing on it with the hockey sticks. What forces are acting on the puck, why the park does not move, and how one of the players could get the park to move in a direction they want
Answer:
1) The forces acting on the puck are the forces applied by the two players in their bid to push the puck in the opposite direction
2) The puck does not move because the forces applied by the two players are equal and opposite
3) A player can get the puck to move in the direction they want by increasing the force acting in the direction they want the puck to move
Explanation:
Henry is at the state fair. At one booth he throws a 0.70 kg ball forward with a velocity of 22.0 m/s in order to hit a 0.15 kg bottle sitting on a shelf. When the ball makes contact the bottle goes flying forward at 29.0 m/s. What is the velocity of the ball after it hits the bottle?
The velocity of the ball after it hits the bottle is 15.8 m/s
Let m₁ represent the mass of the ball, m₂ the mass of the bottle, u₁ the velocity of ball before impact, u₂ the velocity of bottle before impact, v₁ the velocity of ball after impact and v₂ the velocity of bottle after impact.
Given that:
m₁ = 0.7 kg, m₂ = 0.15 kg, u₁ = 22 m/s, u₂ = 0, v₂ = 29
momentum before impact = momentum after impact, hence:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
0.7(22) + 0.15(0) = 0.7v₁ + 0.15(29)
0.7v₁ = 11.05
v₁ = 15.8 m/s
Therefore the velocity of the ball after it hits the bottle is 15.8 m/s
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if a request from thread t1 arrives for (0, 4, 2, 0), can the request be granted immediately?
To determine if the request from thread t1, which is (0, 4, 2, 0), can be granted immediately, we need to compare it with the available resources in the system. If the available resources can satisfy all the demands of thread t1, the request can be granted immediately.
The request (0, 4, 2, 0) represents the resource demands of thread t1. To check if the request can be granted immediately, we compare it with the available resources in the system. If the available resources have enough capacity to fulfill all the demands of thread t1, the request can be granted immediately.
The numbers in the request (0, 4, 2, 0) represent the number of resources required in each category, such as CPU, memory, disk space, or any other resource type. To grant the request, we need to ensure that the system has at least 0 units of the first resource, 4 units of the second resource, 2 units of the third resource, and 0 units of the fourth resource available.
If the system has enough available resources to satisfy all these demands, the request can be granted immediately. However, if any of the required resources are currently unavailable or insufficient, the request cannot be granted immediately, and the thread may have to wait until the necessary resources become available.
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if 10.0 kg of ice at 0 o c is added to 2.0 kg of steam at 100 o c, the temperature of the resulting mixture is
If 2.0 kg of steam at 100 o C and 10.0 kilogram of ice at 0 o C are combined, the resulting mixture will be hotter than 50 degrees. In its gaseous state, water is steam.
This might happen as a result of boiling or evaporation, where heat is provided until the water achieves the enthalpy of vaporization. Although wet steam, the visible mist or aerosol of water droplets created as water vapour condenses, is sometimes referred to as "steam," saturated or superheated steam is invisible. The concept of temperature is used to convey quantitatively how hot and cold something is. Using a thermometer, one can gauge temperature. Thermometers are calibrated using a variety of temperature scales, which historically drew on a variety of reference points and thermometric substances.
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how do i multiply 9.6 by 3/2
Solve the given problem as
\(\begin{gathered} x=9.6\times\frac{3}{2} \\ =9.6\times1.5 \\ =14.4 \end{gathered}\)consider the titration of 100.0 ml of 0.200 m acetic acid (ka by 0.100 m koh. calculate the ph of the result- ing solution after the following volumes of koh have been added.
Answer: The pH of the solution after 50.5 mL of 0.100 M KOH has been added is 16.85.
The reaction between acetic acid and potassium hydroxide (KOH) is given by the equation:
CH3COOH + KOH → CH3COOK + H2O.
It can be observed that for every mole of KOH added, one mole of H+ from CH3COOH reacts with one mole of OH- from KOH to produce one mole of H2O. Therefore, after the addition of n moles of KOH, the number of moles of H+ remaining is (0.200 - n) moles (since 0.200 M is the initial concentration of acetic acid). On the other hand, the number of moles of CH3COOK produced is also n moles; thus the final concentration of CH3COOK is n/V (where V is the total volume of the solution).
The reaction produces a salt (CH3COOK), which is neutral. Therefore, the final pH is given by: pH = pKa + log([A-]/[HA]) where A- is CH3COOK and HA is CH3COOH.
To find the pH of the resulting solution after the following volumes of KOH have been added, we need to calculate the number of moles of KOH added, the number of moles of CH3COOK produced, the number of moles of CH3COOH remaining, and the total volume of the solution. Then we can use the Henderson-Hasselbalch equation above to find the pH.
Here are the calculations: Initial number of moles of CH3COOH = M × V = 0.200 × 0.100 = 0.020 moles. For each mole of KOH added, one mole of CH3COOH reacts with one mole of KOH to produce one mole of CH3COOK.Number of moles of KOH added Volume of KOH added (mL)Moles of KOH added0.02 0.00 (initial) 0.000.02 10.10 0.010.02 20.20 0.020.02 30.30 0.030.02 40.40 0.040.02 50.50 0.05Number of moles of CH3COOK produced = number of moles of KOH added = n moles. Concentration of CH3COOK produced = n/V = n/(Vinitial + V added) = n/(0.100 L + V added)
Number of moles of CH3COOH remaining = initial number of moles - number of moles of KOH added = 0.020 - n moles. Total volume of the solution after the addition of KOH = V initial + V added = 0.100 L + V added. We can then use the Henderson-Hasselbalch equation to find the pH: pH = pKa + log([A-]/[HA])where A- is CH3COOK and HA is CH3COOH.pKa of acetic acid = 4.76
Let's tabulate the values of n, [A-], [HA], and pH for each volume of KOH added: Number of moles of KOH added n (moles)Concentration of CH3COOK produced [A-] (M)
Number of moles of CH3COOH remaining [HA] (M)pH0.000.000.020.76 (initial)0.010.010.019.84 0.020.020.018.98 0.030.030.018.20 0.040.040.017.49 0.050.050.016.85.
The pH of the solution after 50.5 mL of 0.100 M KOH has been added is 16.85.
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What should you do every time you exercise?
A.
Warm up
B.
Drink plenty of water
C.
Stretch
D.
All of the above
Answer:
D. All of the above
Explanation:
Because it's the most logical answer.
he key personal decisions that can influence your personal safety while exercising are __________.A.making sure to replace lost fluids before, during, and after exerciseB.preparing for exercise in extreme temperaturesC.choosing when, where, and how to exerciseD.all of the abovePlease select the best answer from the choices provided.ABCD
The best answer is D. all of the above. Each of the provided options plays a crucial role in influencing personal safety while exercising.
A. Making sure to replace lost fluids before, during, and after exercise is important for maintaining hydration and preventing dehydration. During exercise, the body loses fluids through sweating, and it's essential to replenish those fluids to avoid adverse effects on health and performance. Dehydration can lead to dizziness, fatigue, muscle cramps, and even heat-related illnesses. By prioritizing fluid replacement, individuals can help ensure their personal safety during exercise.
B. Preparing for exercise in extreme temperatures is another important consideration for personal safety. Exercising in extreme heat or cold conditions can pose risks to health. In hot weather, it is crucial to take precautions such as exercising during cooler times of the day, wearing appropriate clothing, staying hydrated, and taking breaks in shaded areas. Similarly, in extremely cold weather, individuals should dress in layers, protect exposed skin, and be aware of the signs of frostbite or hypothermia. By being mindful of extreme temperatures and taking necessary precautions, individuals can safeguard their well-being during exercise.
C. Choosing when, where, and how to exercise is a key personal decision that can impact personal safety. Factors such as the time of day, location, and type of exercise can influence safety levels. For instance, exercising in well-lit areas, avoiding isolated or unsafe neighborhoods, and being aware of one's surroundings can reduce the risk of accidents or encounters with potential hazards. Additionally, selecting appropriate exercise activities that match one's fitness level and considering any pre-existing medical conditions or physical limitations are important for personal safety.
By considering all of the above factors and making informed decisions, individuals can significantly enhance their personal safety while exercising. Each option mentioned is crucial in its own way, addressing different aspects of safety, such as hydration, environmental conditions, and exercise planning. Thus, selecting "D. all of the above" is the most appropriate answer, as it encompasses the key personal decisions that contribute to personal safety during exercise.
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Dos esteras conductoras, cargadas y de igual radio, se apoyan en soportes no conductores. Sus cargas respectivas son-3 C y +7 MC. Si ambas esteras se ponen en contacto y luego son separadas, entonces las cargas respectivas de cada estera son:
A. -Z UC Y +2 MC
В. +1 МС У -3 МС
C. +2 C y +2 MC
D. -1 MC y - 1 MC
The correct option is B. The respective charges on each mat are +1 MC y -3 MC.
Charge refers to a fundamental property of matter that describes how objects interact electromagnetically. The charge can be positive or negative and is measured in Coulombs (C). Objects with the same charge repel each other, while objects with opposite charges attract each other.
Electric charge can be transferred from one object to another through processes such as friction, contact, or induction. The movement of electric charge is the basis for electric current, which is the flow of charge through a conductor.
A charge is also a conserved quantity in physics, meaning that it cannot be created or destroyed, only transferred or redistributed. This conservation of charge is a fundamental principle in many areas of physics, including electromagnetism and quantum mechanics.
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Complete Question:
Two charged conductive mats of equal radius are supported by non-conductive supports. Their respective charges are -3 C and +7 MC. If both mats come into contact and are then separated, then the respective charges on each mat are:
A. -Z UC Y +2 CM
В. +1 MS У -3 MS
C. +2 C and +2 MC
D. -1 MC and - 1 MC
An archer shoots an arrow that goes 210m in 1.5 sec? What is the velocity in m/s?
Answer:
140m/s
Explanation:
divide 210 by 1.5
The kangaroo stops at a lake for a drink of water, then starts hopping again to the south. After 5 seconds, the kangaroo is going 2.5 m/s south. What is the kangaroo’s acceleration?
Answer:
A kangaroo hops 60 m to the east in 5 s. What is the kangaroo's average velocity? ... The kangaroo stops at a lake for a drink of water and then starts hopping again to the south. Each second, the kangaroo's velocity increases 2.5 m/s.
In a real pully system the work supplied must be _____ the work accomplished and no links plz
What property of sound does a decibel measure
How much heat must be absorbed by 2.50 kg of water to raise the temperature from 10.0° C to 60.0° C? The specific heat of water is 4,184 J/kg°C. A. 732 J B. 104,600 J C. 523,000 J D. 627,600 J
plz
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follow
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Compare and contrast what happens to matter when thermal energy is added to a
substance at its melting and boiling point to any temperature other than its melting
and boiling point.
Can anyone please give me a answer for this pls!
Answer:
When thermal energy is added to a substance at its melting or boiling point, the temperature of the substance remains constant as the added energy is used to break intermolecular bonds and cause a phase change from solid to liquid or from liquid to gas. In contrast, adding thermal energy at any temperature other than the melting or boiling point will cause the temperature of the substance to increase, as the added energy increases the kinetic energy of the particles, causing them to move faster and collide more frequently. At other temperatures, the intermolecular forces between the particles are not strong enough to cause a phase change until the substance reaches its melting or boiling point.
To save fuel, some truck drivers try to maintain a constant speed when possible. A truck traveling at 29.0 km/hr approaches a car stopped at the red light. When the truck is 122.2 meters from the car the light turns green and the car immediately begins to accelerate at 3.7 m/s2.
1. How close does the truck come to the car assuming the truck does not slow down?
2. How far from the stop light has the car travelled when the truck reaches its closest distance?
The distance traveled by the car in that time can be calculated using the formula:S = ut + 1/2 at²whereS = distance covered by the caru = initial velocity = 0t = time taken by the truck to reach the closest point to the cara = acceleration = 3.7 m/s².On substituting the values we get:S = 0 + 1/2 * 3.7 * (15.14)²S = 870.59 m,Therefore, the car has traveled a distance of 870.59 meters from the stop light when the truck reaches its closest distance to the car.
1. How close does the truck come to the car assuming the truck does not slow down?Distance of the truck from the car = 122.2 meters Speed of the truck
= 29 km/hr or 8.06 m/s
The truck is moving towards the car so it has a positive velocity.The car is stationary so it has a velocity of 0.The truck will continue to move towards the car until it reaches its closest point to the car.After the light turns green, the car begins to accelerate at 3.7 m/s^2.The time taken by the truck to reach its closest point to the car can be calculated using the formula:v
= u + at
where v
= final velocity u
= initial velocity a
= acceleration
= time taken by the truck to reach the closest point to the carHere,u
= 8.06 m/st
= ?a = 0 (The truck is not accelerating)We know that the car travels a distance of 122.2 m before the truck reaches its closest point to the car.Distance covered by the truck to reach its closest point to the car can be calculated as follows:S = ut + 1/2 at²whereS
= distance covered by the truck to reach its closest point to the caru
= initial velocity t
= time taken by the truck to reach the closest point to the cara = acceleration = 0 (The truck is not accelerating)On substituting the values we get:S
= 8.06t + 0t²
= 122.2t
= 15.14 s Using the time taken by the truck to reach its closest point to the car, we can calculate the distance traveled by the car from the stop light using the formula:S
= ut + 1/2 at²whereS
= distance covered by the caru
= initial velocity
= 0t
= time taken by the truck to reach the closest point to the cara
= acceleration
= 3.7 m/s²On substituting the values we get:S
= 0 + 1/2 * 3.7 * (15.14)²S
= 870.59 m Therefore, the truck will come closest to the car after a distance of 122.2 meters from the car.2. How far from the stop light has the car traveled when the truck reaches its closest distance.The time taken by the truck to reach its closest point to the car is 15.14 s.The distance traveled by the car in that time can be calculated using the formula:S
= ut + 1/2 at²whereS
= distance covered by the caru
= initial velocity
= 0t
= time taken by the truck to reach the closest point to the cara
= acceleration
= 3.7 m/s²On substituting the values we get:S
= 0 + 1/2 * 3.7 * (15.14)²S
= 870.59 m Therefore, the car has traveled a distance of 870.59 meters from the stop light when the truck reaches its closest distance to the car.
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