Give the symbol of the element of lowest atomic number whose ground state has(a) a p electron.(b) four f electrons.(c) a completed d subshell.(d) six s electrons.

According to given question the speed of the arrow as it leaves the bow is 41.32m/sec.

The definition of force in physics is: This push or draw on a massed object changes its velocity. An unseen factor is an agency that has the power to alter the resting or movement condition of a body. It has both a trajectory and a size.

There are several instances of energies in daily life, including: heft and drive (i.e. the weight of something) is force a swing applies to a ball. the pressure that a hair applies to hairs when stroking it. the pressure your foot applies to the pedal whenever you're riding your bike.

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ANSWER:

Light, heat and sound energy.

STEP-BY-STEP EXPLANATION:

When a television is in operation, several different types of energy transformation occur at the same time. The electrical signals leave the base station towards the device itself and the electricity is converted into light, heat and sound energy.

The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)

The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.

To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).

The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).

In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).

Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.

If co > co_critical, the system is considered overdamped (Option E).

If co = co_critical, the system is considered critically damped (Option D).

If co < co_critical, the system is considered underdamped (Option C).

Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.

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Answer:

Teniendo dos tuberías, una hueca y otra sólida, con la misma masa, radio y longitud, ambas poseen la misma rapidez angular, entonces el cuerpo hueco tendrá mayor energía cinética rotacional que la tubería sólida, esto es debido a que el tubo hueco tiene mayor inercia rotacional.

La ecuación de energía rotacional viene dada como:

Er = (1/2)·I·ω

De esta manera tenemos que el tubo hueco tiene mayor inercia rotacional que el tubo sólido, por ende, mayor energía.

Explanation:

Answer:

20 degrees.

Explanation:

this is my answer hope that I will help you

To estimate the energy loss from the pipe per meter of length, we consider the heat transfer through conduction and convection.

The heat transfer through conduction can be calculated using the formula: Q_conduction = (k * A * (T_inner - T_outer)) / d,

Q_conduction = (0.007 W/m°C * π * (0.5 m)² * (30°C - (-12°C))) / 0.05 m.

Next, we need to calculate the heat transfer through convection using the formula:

Q_convection = h * A * (T_inner - T_surrounding),

Q_convection = 9 W/m²°C * π * (0.5 m)² * (30°C - (-12°C)).

Calculating this expression, we find the heat transfer through convection.

Finally, we can find the total energy loss per meter of length by adding the heat transfer through conduction and convection.

Please note that the numerical values provided in the question were not specified, so the final result will depend on the specific values used.

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The high power objective on a microscope is used to provide a higher level of magnification for the detailed examination of specimens.

The high-power objective is one of the multiple objective lenses found on a microscope. It typically has a higher magnification power, often ranging from 40x to 100x or more. When the high-power objective is selected, it brings the specimen into sharp focus at a closer distance. This allows for the observation of finer details and structures that may not be visible with lower magnification objectives. However, higher magnification also means a smaller field of view and reduced depth of field. To compensate for this, a fine adjustment knob is often used to precisely focus the image. The high-power objective is commonly used in advanced biological and medical research, as well as in educational settings where a more detailed examination of microscopic specimens is required.

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If the masses of the hangers are equal, their weight cannot be neglected. Weight is a force that depends on the mass of an object and the acceleration due to gravity.

Even if the masses of the hangers are equal, their weight cannot be neglected because weight is a fundamental force acting on all objects. The weight of an object is determined by multiplying its mass by the acceleration due to gravity.

In everyday situations, the weight of objects is often considered negligible when compared to other forces or when the effects of gravity are insignificant. However, if we want to analyze the forces acting on the hangers accurately, we cannot neglect their weight. The weight of the hangers will contribute to the overall force system, and neglecting it may lead to incomplete or inaccurate analysis.

Therefore, even if the masses of the hangers are equal, their weight should be considered and taken into account when evaluating the forces acting on them.

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Answer:

0.054 kilograms

Explanation:

divide 54 by 1000

so, 54/1000=0.054 kilograms.

Answer:

5.5 m/s^2

Explanation:

I believe this is the answer > using the formula a= v-v0/t

Hope this helps!

Answer:

-1 m/s²

Explanation:

Given:

Δx = 32 m

v₀ = 10 m/s

t = 4 s

Find: a

Δx = v₀ t + ½ at²

32 m = (10 m/s) (4 s) + ½ a (4 s)²

a = -1 m/s²

Answer:

arithmetical multiplier for converting a quantity expressed in one set of units into an equivalent expressed in another.

Explanation:

The reference equality is tested using the == operator. True. If obj1 and obj2 refer to same object, then obj1 == obj2 is true. True. A String object cannot be changed.

In programming, a string is a form of data that is used to data type rather than integers. Letters, numbers, symbols, and even spaces can all be found in a string, which is a collection of characters. In order for it to recognized as a string, it needs to be encapsulated in quotation marks.

A string is frequently implemented as just an array data structure of bits (or words) that records a sequence of elements, usually characters, using some text encoding. Typically, a string is considered to be a data type.

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The angular speed when the man walks to a point 1 m from the center is approximately 0.397 rad/s

Angular speed, ω = 0.25 rev/sCylinder radius, r = 2.5 mMan's initial distance from the axis of rotation, r₁ = 2.5 mMan's final distance from the axis of rotation, r₂ = 1 mMass of the cylinder, M = 68 kgMass of the man, m = 80 kgMoment of Inertia of the cylinder, I = 1/2 Mr²First, we'll calculate the angular momentum (L) of the system before and after the man moves closer to the center:

L(before) = (I + mr₁²) ωL(after) = (I + mr₂²) ωWhere

I = 1/2 Mr²L(before)

= (1/2 * 68 * 2.5² + 80 * 2.5²) * 0.25L(before)

= 839 J.sL(after) = (1/2 * 68 * 1² + 80 * 1²) * ω

New angular speed ω can be calculated by equating the two expressions for angular momentum and solving for ω, as follows:

839 = (1/2 * 68 * 1² + 80 * 1²) * ω

ω = 839 / (1/2 * 68 * 1² + 80 * 1²)≈ 0.397 rad/s

Thus, the new angular speed when the man walks to a point 1 m from the center is approximately 0.397 rad/s.

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If the environmental lapse rate (ELR) of the atmosphere surrounding a rising parcel of air is greater than the dry adiabatic rate (DAR) of 10°C/1000m, certain conditions and phenomena can be inferred.

When the ELR is steeper than the DAR, it indicates a condition of instability in the atmosphere.

This means that the surrounding air cools at a faster rate than a rising parcel of air would if it were undergoing adiabatic cooling.

As a result, the parcel of air becomes warmer compared to its surroundings, making it less dense and causing it to continue rising.

The steep ELR exceeding the DAR signifies an environment conducive to the development of convective processes such as thunderstorms, cumulus clouds, and other forms of unstable atmospheric phenomena.

The increased lapse rate creates an environment where the parcel of air continues to rise and can reach higher altitudes, potentially leading to the formation of significant weather events and atmospheric instability.

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Answer:

1 friction produces heat which damages the moving part of a machine

2 a lot of energy is wasted In overcoming the friction before an object starts moving

3 friction produces wear and tear on the contacting surfaces

Answer:

Heloo you there

Explanation:

Answer:

Friction

Explanation:

Because the brake pad is rubbing alongside the wheel to slow the body of the car down

The velocity of the stone after 0.50s is -2.8 m/s.

Since the stone is thrown upwards, we consider the upward direction as positive. The acceleration due to gravity acts in the opposite direction (downward), so it is negative.

We can use the kinematic equation to determine the velocity of the stone after 0.50s:

final velocity = initial velocity + (acceleration * time)

Given:

Initial velocity (u) = 7.0 m/s (upwards)

Time (t) = 0.50s

Acceleration (a) = -9.8 m/s² (due to gravity, acting downwards)

Plugging in the values:

final velocity = 7.0 m/s + (-9.8 m/s² * 0.50s)

final velocity = 7.0 m/s - 4.9 m/s

final velocity = 2.1 m/s (upwards)

The positive value indicates the direction of the velocity is upwards. However, since we took the upward direction as positive, the actual velocity after 0.50s would be in the opposite direction.

Therefore, the velocity of the stone after 0.50s is -2.1 m/s (downwards) or simply -2.8 m/s.

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Complete question here:

A stone is thrown with an initial velocity of 7.0m/s and experience negligible air resistance. If we take upwards as the positive direction, what is the velocity of the stone after 0.50s?

Diagram B,  accurately depicts the directions of the automobile's velocity and acceleration at the moment when it is in the lowest position.

At the lowest position, the velocity of the automobile will be maximum, while the acceleration will be directed towards the center of the circle. This is because, at the lowest position, the direction of velocity is tangent to the circle while the direction of the acceleration vector is towards the center of the circle. This is shown in the diagram B.

Therefore, the direction of velocity and acceleration vectors of the automobile at the instant that it is at the lowest position is best represented by the diagram B. Hence, the correct answer is option B. 

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The frequency of the electromagnetic wave with a wavelength of 3.40 x \(10^{-6}\) meters is approximately 8.82 x \(10^{13}\) Hz.

The wavelength of the electromagnetic  surge in the presented situation is3.40 x\(10^{-6}\) metres. We may  cipher the  frequence by  fitting  this number into the equation f =  c/. It's 8.82 x 1013 Hz. This indicates that the electromagnetic  surge with a wavelength of3.40 x \(10^{-6}\) metres has a terahertz  frequence.  

Electromagnetic  swells of  colorful wavelengths and  frequentness have different  rates and are employed for a variety of purposes. Radio  swells, for  illustration, have long wavelengths and low  frequentness, making them ideal for carrying data across large distances. X-rays, on the other hand, have short wavelengths and high  frequentness that enable them to access accoutrements  and  give detailed  filmland of the  mortal body.

f = c / λ

f = 3.00 x \(10^{8}\) m/s / 3.40 x \(10^{-6}\) m

f = 8.82 x\(10^{13}\) Hz

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Answer:

The ratio of the potential difference across a metallic conductor to the current in the conductor is known as.

B. Resistance.

Explanation:

According to ohms law   " the current  passing through a conductor is directly proportional to the potential difference between the ends provided the temperature of the wire remains constant".

What is resistance ?

Resistance is a measure of the opposition to current flow in an electrical circuit

what is a resistor ?

a resistor is a n electric conductor which forms resistance to free flow of electric current, the resistance is measured in Ω

The ratio of the potential difference across the conductor to the current is called resistance

It is defined as the ratio of the potential difference across the conductor to the current. The resistance is measured in Ω.

\(R = \dfrac VI\)

Where,

\(R\) - resistance

\(V\)- voltage (Potential difference)

\(I\) - current

Therefore, the ratio of the potential difference across the conductor to the current is called resistance.

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When a force is applied to an object, it can cause a change in the object's motion or state of rest.

If the force is unbalanced, it can cause the object to accelerate or decelerate, resulting in a change in speed or direction. The effect of the applied force depends on the mass and nature of the object, as well as the magnitude and direction of the force. Additionally, the object may experience other effects, such as deformation or compression, depending on the type and direction of the force applied. Understanding the effects of applied forces is crucial in fields such as engineering, physics, and mechanics.

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--The complete question is, When force is Applied  on an object describe effect of action applied. --

Using the theories of gravitation, we got that  3.42×\(10^{11}\)m/sec²  is the free-fall acceleration due to gravity on a a certain planet has equatorial radius about 0.463 times that of the earth, and mass only 0.110 times that of the earth.

We know that acceleration due to gravity on the planet is given by

=Gm/r²

where G is the earth's gravitational constant, m is the mass of the planet and r is the radius of the planet

We are given that mass of the planet is 0.110 times that of the earth.

and radius of the planet is 0.463 times that of the earth.

We know that value of G is 6.67×\(10^{11}\).

So putting the values, we get

Acceleration of planet=[6.67×\(10^{11}\)×0.110 Mass of the earth]/(0.463)² radius of the earth

=>Acceleration of planet=[(6.67×0.110)×    \(10^{11}\)]/(0.463×0.463)

=>Acceleration of planet = (0.7337/0.2143)×\(10^{11}\)

=>Acceleration of planet =3.42×\(10^{11}\)m/sec²

Hence, for a certain planet has equatorial radius about 0.463 times that of the earth, and mass only 0.110 times that of the earth, the free-fall acceleration due to gravity on this planet is 3.42×\(10^{11}\)m/sec².

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(a) Yes, it is possible for a large force to produce only a small or zero torque when the line of action of the force does not create a moment arm or when the force is applied directly through the axis of rotation.

(b) Yes, it is possible for a small force to produce a large torque when the force is applied at a greater distance from the axis of rotation, creating a larger moment arm.

Torque is the rotational equivalent of force and is calculated by multiplying the force by the distance from the axis of rotation. If the line of action of the force passes through the axis of rotation, the moment arm becomes zero, resulting in no torque being generated. This occurs when the force is applied directly on the axis or when the force is balanced by an equal and opposite force that cancels out the rotational effect.

Similarly, even if the force is not directly on the axis of rotation, if the moment arm is very small, the torque produced will also be small. The moment arm is the perpendicular distance between the axis of rotation and the line of action of the force. If the force is applied very close to the axis, the moment arm will be small, resulting in a smaller torque.

If a small force is applied at a considerable distance from the axis of rotation, the moment arm becomes larger, resulting in a larger torque. This is similar to using a wrench or a long lever to apply a small force to loosen a tight bolt. The length of the wrench or lever increases the moment arm, allowing a small force to produce a large torque.

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You have a circuit of four 4.5 v d-cell batteries in series, some wires, and a light bulb, the bulb is lit and the current flowing through the bulb is depends on its resistance.

When four 4.5 V D-cell batteries are connected in series, the total voltage is 18 V. This voltage pushes the current through the light bulb, causing it to light up. The exact amount of current that flows through the bulb depends on its resistance. However, the current flowing through the bulb can be calculated using Ohm's Law.

Ohm's Law states that the current through a conductor between two points is directly proportional to the voltage across the two points. The constant of proportionality is the resistance of the conductor, this means that I = V / R, where I is the current, V is the voltage, and R is the resistance. In this case, since the bulb is lit, we know that there is current flowing through it. However, without knowing the resistance of the bulb, we cannot calculate the exact value of the current. So therefore the bulb is lit and the current flowing through the bulb is depends on its resistance.

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The following calculations in standard notation is 9.13\(e_{1}\), 1.90\(e^{-10}\), 6.14\(e^{8}\).

A standard form of a number in maths is basically mentioned for the representation of large numbers or small numbers. We use exponents to represent such numbers in standard form.

The following calculations and report your answer with three

101,455,348 ÷ 1,111,419 =91.28452

=91.28452 ( in real numbers)

=9.13×\(10^{1}\) (Scientific notation)

=9.13\(e^{1}\)

Therefore, the answer is 9.13\(e_{1}\).

(ii). 0.000000612 × 0.00031119 = 0.000000000190

=0.000000000190 ( in real numbers)

=1.90×\(10^{-10}\) (in scientific notation)

=1.90\(e^{-10}\)

Therefore, the answer is 1.90\(e^{-10}\).

(iii). 297,060 + 0.0004839 =613900000

=613900000 ( in real numbers)

=6.14×\(10^{8}\) (in scientific notation)

=6.14\(e^{8}\)

Therefore, the answer is 6.14\(e^{8}\).

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Answer:

4 ohms

Explanation:

Current = Voltage/resistance

2 = 8/R

2R = 8

R = 4

Answer:

20m

Explanation:

Using the equation s=d/t and re arranging it to solve for distance, d=St, where d=distance, s=speed, ant t=time, we can plug in known variables.

d=4*5

d=20m

there is a distance of 20m traveled

The horizontal distance traveled by the rock is 20 m

For horizontal motion, we use the formula below

⇒ Formula

s = vt.................... equation 1

⇒ Where

From the question,

⇒ Given:

⇒ Substitute these values into equation 1

Hence, The horizontal distance traveled by the rock is 20 m

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Answer:

A) lacks the mass of the object

The expression for ∑fy, representing the sum of the y-components of forces, with upward as the positive y direction, can be written as: ∑fy = F1y + F2y + F3y + ...

In this expression, F1y, F2y, F3y, and so on represent the y-components of individual forces acting on an object. The summation symbol (∑) indicates that we are adding up all the y-components of forces acting on the object. By considering the direction of each force and assigning a positive or negative sign based on whether it acts in the positive y direction (upward) or negative y direction (downward), we can determine the net y-component of the forces (∑fy). The resulting value will indicate the overall effect of the forces on the object in the y-direction.

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Answer: choices a and b

Explanation:

Telescope can be defined as am optical instrument which is designed to observe the distant objects clear and nearer. It comprises of arrangement of lenses which allow the rays of light to be collected. The collected light is focused and the image so produced is magnified in the form of an image. The telescopes are prepared and manufactured on mountains top as this will help in preventing the distortion of light obtain from the star due to the fluctuation of air mass in the atmosphere. The atmospheric distortion affects the resolution, and affects the vision. The atmospheric pressure is low at the mountain tops so it will help in better observation of the sky.