g what does adding boron impurities do to silicon? what does adding boron impurities do to silicon? boron acts as an acceptor, i.e. electrons are introduced into the conduction band. boron acts as an acceptor, i.e. electrons are introduced into the valence band. boron acts as a donor, i.e. electrons are introduced into the conduction band. boron acts as an acceptor, i.e. holes are introduced into the valence band.

Answer:

Polar covalent.

Explanation:

The covalent bonds are therefore polar, and the oxygen atoms have a slight negative charge (from the presence extra electron share), while the hydrogens are slightly positive (from the extra un-neutralized protons). Opposite charges attract one another.

Answer:

There are three main types of RNA: messenger RNA, ribosomal RNA, and transfer RNA.

Explanation:

Messenger RNA (mRNA), Ribosomal RNA (rRNA), and Transfer RNA (tRNA).

Answer:167.9 g Ag

Explanation: 1 mol Cu + 2 mol AgNO3 = 2 mol Ag + 1 mol Cu(NO3)2

63.55 g Cu —> 2*107.688 g Ag

So 49.1 g Cu —> (49.1/63.55)*2*107.688 = 167.9 g Ag

Answer:

109.94 g/mol

Explanation:

Li is 6.94 and there's 2 of those = 13.88

1 S = 32.06

4 O = 63.996

Add all of those together to get 109.936 round to 109.94

Use Relationship between C and V

Among the compounds you listed, only Al2O3 (aluminum oxide) will form a unit cell similar to K3P (potassium phosphide).

K3P is an ionic compound composed of potassium cations (K+) and phosphide anions (P3-). It crystallizes in a cubic unit cell with a specific arrangement of ions.

Al2O3, also known as alumina, is another ionic compound that forms a crystal lattice structure. It consists of aluminum cations (Al3+) and oxide anions (O2-). Al2O3 can crystallize in different crystal structures, such as the corundum structure or the spinel structure, depending on the conditions.

The other compounds you listed (Na3N, Li2S, Ki, CaBr2) do not have the same ionic composition or structure as K3P. Therefore, their unit cells would be different from K3P.

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Answer:

The temperature will increase or doubled.

Explanation:

In Amonton's Law, it states the pressure of a given amount of gas is directly proportional to its temperature on Kelvin scale when the volume is held constant.

A model helps to explain a physical reality.

A model is a representation of reality. It often serves the  purpose of explanation or prediction. The question is incomplete but I will try to explain what a model is.

There are several kinds of models such as;

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Answer:

Try quizlet, they have everything on there

Explanation:

Answer:

balenced.

Explanation:

An ecosystem where all organisms have niches and habitats will be balanced.

An ecosystem consists of all the organisms and the physical environment with which they interact.

Niche describes the role an organism plays in a community. A species' niche encompasses both the physical and environmental conditions it requires and the interactions it has with other species.

Habitat is the area and resources used by a particular species.

A balanced ecosystem represents a sustainable habitat of interdependent animals, plants, and microorganisms and their environment.

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Answer:is a trace metal of severe toxicity. Its health concerns via consumption of contaminated vegetables have often been overlooked or underestimated

Explanation: Read it carefully and it explains

Using MO theory the diamagnetic species are CN, CN+ the correct answer is (O) 1 and 3 only.

To predict whether a species is diamagnetic or paramagnetic using molecular orbital (MO) theory, we need to determine the number of electrons in the molecular orbitals with spin-up and spin-down. If all the electrons are paired, the species is diamagnetic, while if there are unpaired electrons, the species is paramagnetic.

For CN, we can construct the MO diagram by combining the atomic orbitals of carbon and nitrogen. In this case, there are ten valence electrons (five from carbon and five from nitrogen), which fill the molecular orbitals as follows:

σ2s^2σ*2s^2σ2p^4π2p^2

All the electrons are paired, so CN is diamagnetic.

For CN+, we can use the MO diagram for CN and remove one electron, giving:

σ2s^2σ*2s^2σ2p^4π2p^1

In this case, there is one unpaired electron in the π2p orbital, so CN+ is paramagnetic.

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Answer:

b

Explanation:

The final product will be CH3-CH2-C≡C-CH2CH3. ( Hex-3-yne)

The reaction between CH3-CH2-C≡C:–Na+ and CH3CH2Br is a nucleophilic substitution reaction. The sodium acetylide will act as a nucleophile and attack the electrophilic carbon of the CH3CH2Br molecule. This will result in the formation of a new carbon-carbon bond and the displacement of the bromine atom.

. In this reaction, the negatively charged carbon in the acetylide ion acts as a nucleophile and attacks the electrophilic carbon in ethyl bromide, resulting in the formation of a new carbon-carbon bond. The bromide ion is then released as a leaving group.

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Nitration is the process by which an nitro group (-NO2) is introduced to a chemical compound. Electrophile is a molecule that has a tendency to acquire electrons and hence it is attracted towards the electron-rich centers to neutralize the charge imbalance.

During the nitration of methyl benzoate, the reaction is carried out with nitronium ion (NO2+), which is highly electrophilic and attacks the aromatic ring. The nitration of methyl benzoate occurs in the presence of a mixture of concentrated sulfuric acid and concentrated nitric acid (nitrating mixture).The nitrating mixture is used to prepare the nitronium ion, NO2+. This is the electrophile which carries out the nitration of methyl benzoate.Nitronium ion is formed as follows: HNO3 + H2SO4 → NO2+ + HSO4− + H2OWhen sulfuric acid is added to nitric acid, the acid becomes protonated and undergoes an equilibrium reaction as shown below:HNO3 + H2SO4 ⇌ NO2+ + HSO4− + H2OThe product that is formed is nitronium ion, NO2+. Thus, by adding sulfuric acid, the concentration of NO2+ increases which increases the electrophilicity and leads to the formation of more electrophile. Therefore, the concentration of the nitronium ion can be increased by adding more sulfuric acid to the reaction mixture, which will make the solution more acidic, increasing the amount of nitronium ion, NO2+.

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Carbon buildup can be removed from the metal portion of a pressing comb by immersing it in a solution containing an acid.

When a pressing comb is used for styling hair, it can accumulate carbon buildup over time. This buildup can affect the comb's performance and hinder smooth gliding through the hair.

To remove the carbon buildup, the metal portion of the comb can be immersed in a solution containing an acid. The acid helps to dissolve and break down the carbon deposits, making it easier to clean the comb.

Acids such as vinegar, lemon juice, or citric acid are commonly used for this purpose. These acids have properties that help in dissolving carbon and other residues. The comb should be soaked in the acid solution for a specific period of time, allowing the acid to work on the carbon buildup.

After soaking, the comb can be scrubbed gently with a brush or cloth to remove any remaining residue. Finally, rinsing the comb thoroughly with water and drying it properly completes the process.

Hence, immersing the metal portion of a pressing comb in a solution containing an acid is an effective method to remove carbon buildup and restore the comb's functionality.

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To find the mass of MgCl2 in a 250 ml bottle of 0.200 M MgCl2, we first need to calculate the number of moles of MgCl2 present in the solution.

Molarity (M) is defined as moles of solute per liter of solution. Therefore,
0.200 M = moles of MgCl2 / 0.250 L
moles of MgCl2 = 0.200 x 0.250 = 0.0500 moles mass of MgCl2 = moles of MgCl2 x molar mass of MgCl2 .mass of MgCl2 = 0.0500 moles x 95.21 g/mol = 4.77 g
The mass of MgCl2 is 4.77 g.

1. Convert the volume from milliliters to liters: 250 mL = 0.250 L
2. Use the molarity formula: moles = molarity × volume
  moles of MgCl2 = 0.200 M × 0.250 L = 0.050 moles
3. Find the molar mass of MgCl2: Mg = 24.3 g/mol, Cl = 35.5 g/mol
  molar mass of MgCl2 = 24.3 + 2(35.5) = 95.0 g/mol
4. Calculate the mass of MgCl2: mass = moles × molar mass
  mass of MgCl2 = 0.050 moles × 95.0 g/mol = 4.75 g (rounded to 4.77 g)

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Rounded to the appropriate number of significant figures, the mass of MgCl2 in the 250 ml bottle is approximately 4.78 g.Therefore, the correct answer is b. 4.77 g.

Apologies for the confusion. Let's calculate the mass of MgCl2 in the 250 ml bottle, considering the appropriate significant figures.Rounded to the appropriate number of significant figures, the mass of MgCl2 in the 250 ml bottle is 4.78 g.Apologies for the continued confusion. Let's calculate the mass of MgCl2 in the 250 ml bottle correctly, considering the significant figures Given the continued confusion. Let's calculate the mass of MgCl2 in the 250 ml bottle accurately, considering the significant figures.

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Explanation:

We are given different isotopes and we have to identify the number of protons and neutrons that are in the nuclueus of each atom.

a) Carbon-14:

By definition two isotopes are atoms that have the same atomic number but different mass number. The atomic number of an atom is equal to the number of protons of that atom, and the mass number is equal to the number of protons plus the number of neutrons.

atomic number = n° of protons

mass number = n° of protons + n° of neutrons

n° of protons = atomic number

n° of neutrons = mass number - n° of protons

n° of neutrons = mass number - atomic number

If two isotopes have the same atomic number but different mass number we can say that two isotopes have the same number of protons but different number of neutrons.

In we pay attention to carbon-14 we can look for its atomic number in the period table: 6. And its mass number is the one that we are given after the name of the element: 14.

n° of protons = atomic number = 6

n° of protons = 6

n° of neutrons = mass number - atomic number = 14 - 6

n° of neutrons = 8

b) Cobalt-60:

atomic number = 27 (from the periodic table)

mass number = 60

n° of protons = atomic number = 27

n° of protons = 27

n° of neutrons = mass number - atomic number = 60 - 27

n° of neutrons = 33

c) Gold-197:

atomic number = 79 (from the periodic table)

mass number = 197

n° of protons = atomic number = 79

n° of protons = 79

n° of neutrons = mass number - atomic number = 197 - 79

n° of neutrons = 118

d) Uranium-235:

atomic number = 92 (from the periodic table)

mass number = 235

n° of protons = atomic number = 92

n° of protons = 92

n° of neutrons = mass number - atomic number = 235 - 92

n° of neutrons = 143

Answer:

a) Carbon-14: n° of protons = 6 n° of neutrons = 8

b) Cobalt-60: n° of protons = 27 n° of neutrons = 33

c) Gold-197: n° of protons = 79 n° of neutrons = 118

d) Uranium-235: n° of protons = 92 n° of neutrons = 143

The pressure required to reduce 50 mL of a gas at standard conditions to 20 mL at a temperature of 23 °C is 10.656 atm. To solve this problem, the ideal gas law is used.

The ideal gas law is a fundamental equation of state that relates the pressure, volume, temperature, and number of moles of an ideal gas. The ideal gas law is expressed mathematically as:

PV = nRT

At standard conditions (STP), the volume of 50 mL of a gas is equivalent to 0.050 L, and the temperature is 273 K. We can use this information to find the initial number of moles of the gas:

n₁ = P*V₁/R*T₁= P(0.050 L)/(0.08206 L·atm/mol·K)(273 K) = P/2.4844

where V₁ = 0.050 L, R = 0.08206 L·atm/mol·K, and T₁ = 273 K.

To reduce the volume to 20 mL (0.020 L) at a temperature of 23°C (296 K), we can rearrange the ideal gas law equation and solve for the required pressure:

P2 = n₁*RT₂/V₂ = (P/2.4844)(0.08206 L·atm/mol·K)(296 K)/(0.020 L) = 10.656P

where T₂ = 296 K and V₂ = 0.020 L.

Therefore, the pressure required to reduce 50 mL of a gas at standard conditions to 20 mL at a temperature of 23°C is:

P₂ = 1 atm × 10.656 = 10.656 atm

Thus, the pressure required to reduce the volume of the gas is 10.656 atm.

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The appearance of ions in solution makes a solution to conduct electricity.

Conductivity refers to the flow of current through a solution.

1) There is an evidence that reaction has occurred because of the formation of a precipitate

2) The conductivity decreases as more H2SO4 was added.

3) The indicator of the number of ions in the solution is the current recorded.

4) This evidence indicates that a reaction has occurred because the formation of a precipitate decreases the current.

5)  Ba(OH)2(s) ---->  Ba^2+(aq) + 3OH^-(aq)

H2SO4(aq) ---> 2H^+(aq) + SO4^2-(aq)

6) When the conductivity is at the minimum, It means that the   Ba(OH)2 is largely undissociated.

7) It does not conduct at a low point because there are no ions in solution.

8) It conducts more before and after this minimum point because of more ions in solution.

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Answer:

17.76 cm x 9.21 cm x 4.45 cm = 727.9 cc. Calculate the weight of the gold bar using the density of gold, which is: 19.3 g/cc. Use the density ...

ΔH rxn = 434.7 kJ

Given

C+O₂⇒CO₂   ΔH=-393.5 (reaction 1)

2CO+O₂⇒2CO₂  ΔH=-566 (reaction 2)

2H₂O⇒2H₂+O₂ ΔH=483.6 (reaction 3)

Required

ΔH rxn

Solution

Reaction 1 : no change

C+O₂⇒CO₂   ΔH=-393.5

Reaction 2 : the reaction is reversed and divided by 2

CO₂⇒ CO+1/2O₂ ΔH=-283

Reaction 3 : divided by 2

H₂O⇒H₂+1/2O₂ ΔH=241.8

-------------------------------------------

C+H₂O⇒CO + H₂ ΔH rxn= -434.7 kJ

Answer:

D. Both are used by radio stations to transmit sound

Explanation:

The main difference between both modulations is that in frequency modulation, the frequency of the carrier wave is modified as per the transmit data, while in amplitude modulation, the carrier wave is modified according to the data. because of this it can NOT be A, B, or C but it CAN be D

PLZ MARK AS BRAINLIEST :)

The amplitude modulation and frequency modulation techniques similar as , Both are used by radio stations to transmit sound.

So, option D is correct one.

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This problem is providing the total volume of a graduated cylinder, 100 mL with 45.0 mL of water, but when adding a piece of steel, the volume rises to 55.5 mL so the volume of the metal is required and found to be 10.5 mL according to:

In chemistry, density experiments require the use of a well-measured volume of water in order to add the density-unknown object so the difference in the volume lead to the that of the object.

In such a way, since 45.0 mL of water is risen to 55.5 mL upon the addition of the steel, one can calculate the difference in order to get the volume of steel as 55.5 mL comprises both water and the object:

\(V^{steel}=55.5mL-45.0 mL\\\\V^{steel}=10.5 mL\)

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The balanced chemical equation for the acid-base reaction is:

2HCl + Ca(OH)2 → CaCl2 + 2H2O

A balanced chemical equation is a representation of a chemical reaction that shows the relative number of reactant and product molecules involved. It follows the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction. In a balanced equation, the number of atoms of each element on both sides of the equation is equal.

A balanced chemical equation includes chemical formulas of reactants on the left side of the arrow and the chemical formulas of products on the right side. Coefficients are used to balance the equation by adjusting the number of molecules or moles of each substance involved. These coefficients indicate the relative stoichiometric ratios between reactants and products.

According to the equation, for every 1 molecule of CaCl2 that forms, 2 water molecules are produced. Therefore, the correct answer is:

twice as many, 2x

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Answer:

Modification Step

Explanation:

The entire reason why test-marketing exists is to make sure that the product will be well received by the public. Once the test marketing concludes, the data from the test is analyzed. Then the company decides whether or not they will make changes on how the product looks, feels, performs, or even rebranding the product, all to make sure that the final consumer will like the product enough to want to purchase and continuously use the product. Which will in term increase profits for the company.

When slip occurs in a material, the critical resolved shear stress (CRSS) is used to determine the minimum shear stress required to start the slip.

Given that a tensile stress is applied on a nickel crystal along a 1011 direction, and slip occurs on a (111) plane and in a (101) direction, the critical resolved shear stress will be computed as follows: Calculation for g[000] Since the tensile stress is applied along the 1011 direction, g[000] = 0.Calculation for g[1012]:The direction of slip (101) lies in the (1012) plane. Therefore, g[1012] = 1.Calculation for .

From the direction of the applied tensile stress and the direction of the slip plane, we can use the expression given as o = cas-1 [g [000) + 1012 (1210²+1²) (12+0 24 1²) 2 to determine o. Substituting the values of g[000], g[1012], and other parameters gives us.

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When sodium phosphate reacts with sulfuric acid, forming sodium sulfate and phosphoric acid, the stoichiometric coefficient for sulfuric acid in the balanced chemical equation is 3.

In every balanced chemical equation, the total number of individual atoms on the reactant side must be equal to the total number of individual atoms on the product side. The stoichiometric coefficient is the number written in front of each reactants and products that tells how many moles of each are needed in the reaction.

The chemical equation for the given reaction is:

\(Na_{3} PO_{4}\) + \(H_{2} SO_{4}\) = \(Na_{2} SO_{4}\) + \(H_{3} PO_{4}\)

Put the necessary stoichiometric coefficient to balance each element.

Balancing Na:

\(2Na_{3} PO_{4}\) + \(H_{2} SO_{4}\) = \(3Na_{2} SO_{4}\) + \(H_{3} PO_{4}\)

Balancing P:

\(2Na_{3} PO_{4}\) + \(H_{2} SO_{4}\) = \(3Na_{2} SO_{4}\) + \(2H_{3} PO_{4}\)

Balancing S:

\(2Na_{3} PO_{4}\) + \(3H_{2} SO_{4}\) = \(3Na_{2} SO_{4}\) + \(2H_{3} PO_{4}\)

Notice that H and O are already balanced.

Hence, the balanced chemical equation for the reaction is:

\(2Na_{3} PO_{4}\) + \(3H_{2} SO_{4}\) = \(3Na_{2} SO_{4}\) + \(2H_{3} PO_{4}\)

where 3 is the stoichiometric coefficient of sulfuric acid, \(H_{2} SO_{4}\).

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Answer:

To make 250 ml of 0.1 M NaOH, you dissolve 1 gram NaOH in enough water to make a final volume of 250 mls.

Explanation:

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