The value of the external magnetic field in a real NMR/MRI experiment, which emits a photon of energy \(4.5x10^(-26) J\), is approximately 0.268 Tesla.
To determine the value of the external magnetic field (B) in a real NMR/MRI experiment, we can use the equation that relates the energy difference (ΔE) between the two spin states of a proton to the photon energy (E) and the magnetic field strength (B):
\(ΔE = E = hf = hγB,\)
where:
ΔE is the energy difference between the spin states,
E is the photon energy (given as\(4.5x10^(-26) J)\),
h is the Planck's constant (6.62607015 × 10^(-34) J·s),
f is the frequency of the emitted photon,
γ is the gyromagnetic ratio of the proton (approximately 2.675 × 10^8 rad \(T^(-1) s^(-1))\),
B is the magnetic field strength we need to find.
Rearranging the equation, we can solve for B:
\(B = E / (hγ).\)
Substituting the given values:
B = \((4.5x10^(-26) J) / (6.62607015 × 10^(-34) J·s × 2.675 × 10^8 rad T^(-1) s^(-1)).\)
Evaluating this expression:
B ≈ 0.268 T.
Therefore, the value of the external magnetic field is 0.268 Tesla (to the nearest tenth of a Tesla).
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The first step in responding to any sports injury is to __________.
A.
remove the danger that lead to the injury
B.
ensure that the player's air way is not obstructed
C.
begin chest compressions for CPR
D.
ask the player to stop playing the sport
Please select the best answer from the choices provided.
A
B
C
D
Answer:
remove the danger that lead to injury
Explanation:
The best way is
spot the reason for injuryThen try best to remove that cause as fast as possible.Then spot the place of body where injury happenedNOW treat for thatAnswer:
A
Explanation:
The first step in responding to an injury in sports is to remove the danger that led to the injuryB cannot be correct because if an athlete suffers a broken leg you don't check their air ways primarilyC is also not right as that is only when the player is unconsciousD is not right as that is the result of only a very life-threatening injuryA is the right answeri m only 16 yrs old and I have much anger issue. when I m angry i doesn't afraid with anyone even my father teacher
letting people know like you did here may decrease anger
A car driving at a constant velocity of 15 m/s has what acceleration? PLEASE HELP
Answer:
32
Explanation:
in which kind of community do people mostly work in groups that generate idea and provide services?
Answer:
Postindustrial
Explanation:
A 1.35 kgkg block is attached to a spring with spring constant 15.0 N/mN/m . While the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 34.0 cm/scm/s . What are
Given :
Mass of block , m = 1.35 kg .
Speed constant , k = 15 N/m .
Speed at centre , v = 34 cm/s = 0.34 m/s .
To Find :
The amplitude of oscillation .
Solution :
Now , we know total energy is conserved in SHM .
So , K.E at zero displacement :
\(K.E=\dfrac{mv^2}{2}\\\\K.E=\dfrac{1.35\times 0.34^2}{2}\\\\K.E=7.8\times 10^{-2}\ J\)
Now , this K.E is equal to maximum P.E :
\(P.E=K.E=7.8\times 10^{-2}\ J\) .
\(P.E=\dfrac{kA^2}{2}\\\\7.8\times 10^{-2}=\dfrac{kA^2}{2}\\\\A=\sqrt{\dfrac{2\times 7.8 \times 10^{-2}}{15}}\ m\\\\A=0.1019 \ m\\\\A=10.2\ cm\)
Therefore , the amplitude is 10.2 cm .
Hence , this is the required solution .
13) What happened to the quarks that existed freely during the particle era? A) They combined in groups to make protons, neutrons, and their antiparticles. B) They froze out of the soup of particles at the end of the era. C) They evaporated. D) They combined in groups to make electrons and neutrinos. E) They combined in groups to make W and Z bosons
They combined in groups to make protons, neutrons, and their antiparticles. The correct option is A.
They combined in groups to make protons, neutrons, and their antiparticles. During the particle era, which occurred immediately after the Big Bang, the universe was filled with a hot soup of particles including quarks. As the universe cooled, the quarks combined in groups of three to form protons and neutrons, which are the building blocks of atoms. This process is known as hadronization. The antiparticles of these hadrons were also formed during this time. So, in summary, the quarks did not evaporate, freeze out, or combine to form electrons, neutrinos, or W and Z bosons, but rather they combined in groups of three to form protons, neutrons, and their antiparticles.
During the particle era, quarks existed freely, but as the universe cooled, they eventually combined in groups of three to form particles like protons and neutrons. This process is known as hadronization. Additionally, their antiparticles were also created through the combination of quarks and antiquarks.
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Pick the correct word to fill up the blank in below question: velocity, combustion, acceleration, gravitation, force
If a race car wants to change its velocity then a net force is
required to cause the necessary
Answer: Acceleration
a system was heated from 44.30 °c to 109.1 °c, and had a final pressure of 350.5 torr. what was the intial pressure?
The initial pressure of the system was 290.66 torr.
To find the initial pressure of the system, we can use the combined gas law equation:
(P1 × V1) / (T1 × n1) = (P2 × V2) / (T2 × n2)
Since the number of moles (n) and volume (V) are constant, we can simplify the equation to:
P1 / T1 = P2 / T2
Substituting the given values, we have:
P1 / (44.30 + 273.15) = 350.5 / (109.1 + 273.15)
Now, we can solve for P1 by cross-multiplication:
P1 = (350.5 / (109.1 + 273.15)) × (44.30 + 273.15)
P1 = (350.5 / 382.25) × 317.45
P1 = 0.916 × 317.45
P1 ≈ 290.66 torr
Therefore, the initial pressure of the system was approximately 290.66 torr.
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Develop and describe a method to predict the force exerted by the expelled CO2 on the system using Newton's Saved second law.
1) Determine the mass of the expelled CO2, 2) Calculate the acceleration of the CO2 using Newton's second law, and 3) Multiply the mass by the acceleration to obtain the force exerted by the CO2 on the system.
Newton's second law states that the force exerted on an object is equal to the mass of the object multiplied by its acceleration. To apply this principle to predict the force exerted by expelled CO2 on a system, the following steps can be followed:
Determine the mass of the expelled CO2: This can be achieved by measuring the mass of the CO2 or using known properties such as the molar mass of CO2 and the quantity of CO2 expelled.
Calculate the acceleration of the CO2: The acceleration can be determined by considering the forces acting on the CO2. In this case, the main force acting on the CO2 would be the expulsion force. Other factors such as air resistance can be taken into account if necessary.
Multiply the mass by the acceleration: Once the mass and acceleration are determined, multiply them together to obtain the force exerted by the CO2 on the system. The unit of force is typically Newtons (N).
By following this method and applying Newton's second law, it is possible to predict the force exerted by the expelled CO2 on the system. It is important to ensure accurate measurements and consider all relevant forces to obtain a reliable prediction.
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A solenoid having an inductance of 6. 30μH is connected in series with a 1. 20kΩ resistor. (a) If a 14. 0 V battery is connected across the pair, how long will it take for the current through the resistor to reach 80. 0% of its final value? (b) What is the current through the resistor at time t=1. 0τL?
a) To calculate the time it takes for the current through the resistor to reach 80% of its final value, we need to use the time constant formula, which is given by τ = L/R, where τ is the time constant, L is the inductance, and R is the resistance. Using the given values, we can calculate the time it takes for the current to reach 80% of its final value.
b) At time t = 1.0τL, we can use the exponential decay formula for the current in an RL circuit, which is given by I(t) = I₀e^(-t/τ), where I(t) is the current at time t, I₀ is the initial current, t is the time, and τ is the time constant. Using the given values, we can calculate the current through the resistor at t = 1.0τL.
a) The time constant τ is calculated using the formula τ = L/R. Substituting the given values, we have τ = (6.30μH)/(1.20kΩ) = 5.25μs. To find the time it takes for the current to reach 80% of its final value, we multiply the time constant by ln(1/0.80) ≈ 0.2231, which gives us t = (5.25μs)(0.2231) ≈ 1.17μs.
b) At time t = 1.0τL, we use the exponential decay formula I(t) = I₀e^(-t/τ). Since the current is decaying, the initial current I₀ is equal to the final current when t = 0, which is the current through the resistor. Substituting the given values, we have I(t) = (14.0V)/(1.20kΩ) * e^(-1.0(5.25μs)/(5.25μs)) = 11.7mA. Therefore, the current through the resistor at t = 1.0τL is 11.7mA.
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What force acts between Earth and the moon?
O gravity
O mass
O motion
Onewtons
Answer:
A. gravity
or gravitational force
Mark as brainliest if this helped
Peace
A 65 kg speed skater is racing around a circular track. The track has a radius of 20 m. It
takes the skater 10 seconds to complete one lap. Calculate the skater’s acceleration
The acceleration of the skater is: 1.97 m/s²
What is acceleration?Any procedure where the velocity varies is referred to as acceleration. There are only two ways to accelerate: changing your speed or changing your direction, or changing both. This is because velocity is both a speed and a direction.
Time, (t) = 10 sec
Frequency (F) = 1/t = 0.1 Hz.
Velocity, (V) = r × ω
V = 10 x (2 Π/10)
V = 6.28 m/s
Now, Centripetal acceleration,
a = v²/r
or, a = (6.28)²/20
or, a = 1.97 m/s².
Now, the acceleration of the skater is: 1.97 m/s².
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All engineers work on designing new and innovative products.
True of false
Answer:
True
But not all engineers work the same! some dont take the same steps to there design!!
Hope this helped you luv!!!! C:
I need help! Thank you.
Answer:
The answer is the third one.
C.
Hope this helps!
Consider two elastic collisions: 1) a golf ball with speed v hits astationary bowling ball head-on. 2) a bowling ball with speed vhits a stationary golf ball head-on. In which case does the golfball have the greater speed after the collision?
a. situation 1
b. situation 2
c. the same
Answer:
a) one can use the fact that in an elastic collision, the speed of separation equals the speed of approach, this would favor situation (1)
4. Create two more paths on the Gizmo like the one you created in question #2 above. List the energy conversions that happen along each path. Record your work in the tables below. Energy Path Energy conversion
Energy Path Energy conversion
Sun- Nuclear energy is converted to light and thermal energy.Sun- Air Radiant energy is converted to thermal energy.Air- Kinetic energy is converted to mechanical energy.Wind Turbines- Toaster Mechanical energy is converted to electrical energy.Toaster- Electrical energy is converted to thermal energy.Finally, the energy conversion begins with the Sun's nuclear energy, which is converted into radiant and thermal energy to heat the air. Wind turbines then convert the mechanical energy of the moving air into electrical energy, which is then transferred through the toaster. The bread is finally heated by converting electrical energy into thermal energy.
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Your question is incomplete, most probably the complete question is:
Create path: Create an energy path in the Gizmo, starting at the Sun. For each step of the path, describe the energy conversion that takes place. The first one is done for you. Discuss your answers with your classmates and teacher.
Energy Path Energy conversion
Sun Nuclear energy is converted to light and thermal energy.
Air Sunlight warms up the surface which warms up the air
Wind Wind turns the blades which creates electricity
Turbines Electricity flows through the toast
Toaster
When you unplug the toaster, it takes about 10 ms for the current to die down. Why does not the current stop immediately?
a The coils reduce their area as the appliance cools down and cause electromagnetic induction.
b Self-inductance of the coils keeps the current flowing.
c The residual potential difference between the plug contacts keeps the current flowing.
d Due to the inertia of the moving charges.
The current does not stop immediately when you unplug the toaster because of the self-inductance of the coils.
When the toaster is plugged in, a current flows through the coils, creating a magnetic field. When you unplug the toaster, the magnetic field collapses, which creates a back EMF (electromotive force) that opposes the current flow. This back EMF is proportional to the rate of change of the magnetic field, which means that it is initially very high when the magnetic field collapses rapidly. This high back EMF keeps the current flowing for a short period of time, until the magnetic field has dissipated and the back EMF has decreased. This is known as self-inductance, and it is what causes the current to take about 10 ms to die down after the toaster is unplugged.
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How much time does it take light to travel from the moon to the earth, a distance of 384000 km?
Answer:
1.28second
Explanation:
The speed of light is constant everywhere, it is
299,792,458m/s=299,792.458km/s
Therefore it takes
\( \frac{384000}{299792458} = 1.28sec\)
A cyclist cycle the rout in 3 h and 30 min. If he cycles 49 km, calculate her average speed.
Answer:
14 km/h
Explanation:
The average speed of the cyclist could be calculated by the following formula:
average speed = total distance/total time
= 49/3.5
= 14 km/h
Hope this helps!
Which is an example of potential energy being transformed into kinetic energy?
A. A rock sitting at the top of a hill rolling down the hill.
B. A rock sitting at the top of a hill without moving.
C. A rock at the bottom of a hill being pushed up the hill.
D. A rock sitting at the bottom of the hill without moving.
Answer:
B is the right answer
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what is the difference between heat capacity, specific heat, and latent heat? select all statements that are true.
Regarding the difference between heat capacity, specific heat, and latent heat, statements B), C), D) and F) are true.
The specific heat of a material is the amount of heat energy required to raise the temperature of one unit of mass of that material by one degree Celsius. Heat capacity, on the other hand, is the total amount of heat energy required to raise the temperature of the entire object by one degree Celsius. Statement B is correct.
The larger the mass of the object, the more heat energy is required to raise its temperature. Specific heat, on the other hand, is a property of the material itself and does not depend on the size or mass of the object. Statement C is correct.
Specific heat and heat capacity describe the amount of heat energy required to change the phase of an object, such as changing the state of a substance from solid to liquid or liquid to gas. The heat energy absorbed or released during a phase change is called latent heat. Statements D and F are correct.
Hence statements B) C) D) and F) are true.
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--The given question is incomplete, the complete question is:
"what is the difference between heat capacity, specific heat, and latent heat? select all statements that are true.
A) Latent heat describes the amount of heat energy required to change the temperature of an object.
B) Specific heat and heat capacity describe the amount of heat energy required to change the temperature of an object.
C) Heat capacity depends on the mass of the object while specific heat only depends on the material the object is made of.
D) Specific heat and heat capacity describe the amount of heat energy exchanged to change the phase of an object.
E) Specific heat depends on the mass of the object while heat capacity only depends on the material the object is made of.
F) Latent heat describes the amount of heat energy exchanged to change the phase of an object."--
A hemispherical tank is full of oil (density = 50 pc). It has a diameter of 10 ft. Find the work done in Ib-ft in pumping all the liquid out of the tank
The work done in pumping all the liquid out of the tank is 2500π lb-ft.
Work done calculationThe potential energy of an object is given by the formula:
PE = mgh
Given:
Density of oil = 50 lb/ft^3
Diameter of the tank = 10 ft ( r = 5 ft)
To calculate the work done, we need to find the mass of the oil and the height it is lifted. Let's start by finding the mass:
Volume of oil in the tank:
The volume of a hemisphere = (2/3) * π * (r^3)
Volume = (2/3) * π * (5^3) = (2/3) * π * 125 = 250π/3 ft^3
Mass of the oil:
Mass = Volume * Density = (250π/3) * 50 lb
Now, we need to find the height of the tank. For a hemisphere, the height is equal to the radius (5 ft).
Finally, we can calculate the work done:
Work = PE = mgh = (250π/3) * 50 lb * 5 ft
Work = (250π/3) * 50 * 5 lb-ft
= 2500π lb-ft
So, the work done in pumping all the liquid out of the tank is approximately 2500π lb-ft.
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If a musician increases the wavelength of the sound waves she produces without changing their speed, what must be happening to the frequency? Explain your answer
Answer:
The only way to increase a wavelength without changing speed is by decreasing the frequency. This happens when a note is lowered, and the crest of each waves separates farther and farther.
Higher frequencies consist of compact wavelengths.
As a substance changes from a solid to liquid gas, what happens to the energy of the substance
Answer:
The molecules move and vibrate so quickly that they escape into the atmosphere as molecules of water vapor, that's why rainwater is also distilled, it doesent have any particles or minerals in it.
Acceleration of a particle on the x-axis is a=−v2 The initial position and velocity are x(0)=1,x(0)=2 Find the position, velocity, and acceleration as functions of time x(t),v(t),a(t)
Given, acceleration of a particle on the x-axis is a = -v². The initial position and velocity are x(0) = 1, x'(0) = 2. We have to find the position, velocity, and acceleration as functions of time x(t), v(t), a(t). We can use the formulas below to solve the given problem. Position as a function of time, x(t)To find the position as a function of time x(t), we need to integrate the given acceleration function with respect to time.taking negative sign common we get,a = -v²dv/dx = -v dv = -v dx dv/v² = -dx x = ∫ dx/x² + cputting limits and solving the integral.
we get,x = 1/(v + c₁)Taking derivative both side w.r.t t,x'(t) = (-1/(v+c₁)²) . dv/dtTo find the value of constant c₁, we use the initial velocity,x'(0) = 2 = (-1/(v(0)+c₁)²) . dv/dt(2/1) = dv/dt ..... (1)Integrating both sides of the above equation with respect to t, we getv(t) = -2t + Cwhere C is the constant of integration. Substituting the value of v(t) in the equation x = 1/(v + c₁), we getx(t) = 1/(-2t + C + c₁)Velocity as a function of time, v(t).
The velocity as a function of time, v(t) is given byv(t) = -2t + C, where C is the constant of integration.Initial velocity is v(0) = -2(0) + C = C = 2Substituting this value in the above equation, we getv(t) = -2t + 2Acceleration as a function of time, a(t)Acceleration as a function of time is given bya(t) = -v²(t) = -(-2t+2)²= -(4t² - 8t + 4)= -4(t² - 2t + 1) = -4(t-
1)²Therefore, Position as a function of time, x(t) is x(t) = 1/(-2t + C + c₁).Velocity as a function of time, v(t) is v(t) = -2t + 2.Acceleration as a function of time, a(t) is a(t) = -4(t-1)².
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a dynamite blast at a quarry launches a rock straight upward, and 2.1 s later it is rising at a rate of 12 m/s. assuming air resistance has no effect on the rock, calculate its speed (a) at launch and (b) 4.5 s after launch.
The rock was launched in the upward direction with an initial velocity of 8.58 m/s.The speed of the rock 4.5 seconds after launch is 35.52 m/s.
Given:
Time after launch (t) = 2.1 s
Rising rate (v) = 12 m/s
(a) By using the equation of motion v = u + at
where,
v denotes the final velocity, u initial velocity, a is the acceleration, and t is the time.
v = u + at
12= u + (9.8) × 2.1 s
u = 12 - (9.8 m/s² × 2.1 s)
u = 12 - 20.58
u = -8.58 m/s
The negative sign indicates that the rock was launched in the upward direction with an initial velocity of 8.58 m/s.
(b) To calculate the speed 4.5 seconds after launch,
v = u + at
v = -8.58 + (9.8) × 4.5 s
v = 35.52 m/s
The speed of the rock 4.5 seconds after launch is 35.52 m/s.
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Why does time seem to flow only in one direction?
Answer:
Time seem to flow only in one direction because if it started to go in backward direction that would break the second law of thermodynamics. We do not find time to be moving in any direction because time is not an object that can move nor is it a force that can move any object.
how would i solve this. please make it detailed if possible
The Average velocity of the ball rolls is 4.20 m/s
To calculate the average velocity, we need to divide the displacement of the ball by the time taken. Displacement is the change in position, which can be calculated by subtracting the initial position from the final position.
Given that the ball rolls from x = -5.0 m to x = 32.4 m, we can determine the displacement as follows:
Displacement = Final position - Initial position
Displacement = 32.4 m - (-5.0 m)
Displacement = 32.4 m + 5.0 m
Displacement = 37.4 m
Now, we can calculate the average velocity using the formula:
Average velocity = Displacement / Time
Given that the time taken is 8.9 seconds, we can substitute the values:
Average velocity = 37.4 m / 8.9 s
Average velocity ≈ 4.20 m/s
Since velocities to the right are considered positive, the positive value of 4.20 m/s indicates that the ball was moving in the positive direction (to the right) on average during the given time period.
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What is similar about the most stable point for all the different trials you did with the simulation?
In general, the most stable point in simulations involving energy, potential, or force usually refers to a point of equilibrium where the forces acting on the system are balanced, and there is no net movement or change in the system.
What is an experiment?An experiment in science is a carefully designed and controlled procedure that is carried out to test a hypothesis or answer a research question. It is a systematic and empirical approach to investigating phenomena and understanding the natural world.
In an experiment, a researcher manipulates one or more variables and observes the effects of the manipulation on the dependent variable. The independent variable is the variable that is manipulated, while the dependent variable is the variable that is being measured or observed to see if it changes in response to the manipulation.
The goal of an experiment is to establish cause-and-effect relationships between variables by controlling for other factors that could influence the outcome. The experiment should be designed to minimize bias and confounding factors that could affect the results, and the results should be analyzed statistically to determine the significance of any observed effects.
Experiments are an essential part of the scientific method and are used in many scientific disciplines, including physics, chemistry, biology, psychology, and others. They allow researchers to test hypotheses, make predictions, and draw conclusions based on empirical evidence.
Here in the question,
The similarity of the most stable point in different trials will depend on the specifics of the simulation and the initial conditions set up for each trial. If the simulations involve similar systems and starting conditions, then the most stable point may be similar in terms of the position, potential energy, force, or other parameters being measured.
Therefore, Simulations involving energy, potential, or force usually refer to a point of equilibrium where the forces acting on the system are balanced.
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Dos cargas puntuales se localizan en el eje +X de un sistema de coordenadas. La carga q1= 1nC esta a 2cm del origen y la carga q2= -3 nC esta a 4cm del origen. ¿cual es la fuerza tras que ejercen estas dos cargas sobre una carga q3= 5nC que se encuentra en el origen?
Answer:
F_net = 1.125 10⁻⁶ N
positive direction of the x axis
Explanation:
The electric force is given by Coulomb's law
F =\(k \frac{q_1q_2}{r_{12}^2}\)
also used charge of equal sign repel each other.
We appease this information to our problems
the charge q₁ is positive and the charge q₃ is positive for which the force is repulsive; ; a charge q₂ is negative so the force is attractive.
If we apply that the forces are vectors
F_net = - F₁₃ + F₂₃
F_net = \(-k \frac{q_1q_3}{r_{13}^2} + k \frac{q_2q_3}{r_{23}^2}\)
F_net = k q₃ ( \(- \frac{q_1}{r_{13}^2} + \frac{q_2}{r_{23}^2}\) )
let's look for the distances
r₁₃ = 2-0 = 2 cm = 2 10⁻² m
r₂₃ = 4-0 = 4 cm = 4 10⁻² m
let's substitute
F_net = 9 10⁹ 5 10⁻⁹ ( \(- \frac{1 \ 10^{-9}}{2 \ 10^{-2}} + \frac{3 \ 10^{-9}}{4 \ 10^{-2}}\))
F_net = 45 (- 0.5 10⁻⁷ + 0.75 10⁻⁷)
F_net = 1.125 10⁻⁶ N
the positive sign indicates that the outside has a positive direction of the x axis, that is, it is to the right