Fluorine has seven electrons in its outermost shell. It will most likely try to join with an atom with _____.
seven electrons in its outermost shell
two electrons in its outermost shell
one electron in its outermost shell
eight electrons in its first shell

Answer:

Explanation:Explore this page

About the gas laws calculator

This is an ideal gas law calculator which incorporates the Boyle's law , Charles's law, Avogadro's law and Gay Lussac's law into one easy to use tool you can use as a:

Boyle's Law-

\(\:\:\:\:\:\:\:\:\:\:\:\star\:\sf \underline{ P_1 \: V_1=P_2 \: V_2}\\\)

(Pressure is inversely proportional to the volume)

Where-

As per question, we are given that -

Now that we have all the required values and we are asked to find out that volume which will be occupied if the pressure is adjusted to 80 KPa and the temperature remains unchanged. For that we can put the values and solve for the final volume of helium-

\(\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\star\:\sf \underline{ P_1 \: V_1=P_2 \: V_2}\)

\(\:\:\:\: \:\:\:\:\:\:\longrightarrow \sf 100 \times 160 = 80 \times V_2\\\)

\( \:\:\:\:\:\:\:\:\:\:\longrightarrow \sf V_2 = \dfrac{100 \times 160}{80}\\\)

\( \:\:\:\:\:\:\:\:\:\:\longrightarrow \sf V_2 =100\times \cancel{\dfrac{ 160}{80}}\\\)

\(\:\:\:\: \:\:\:\:\:\:\longrightarrow \sf V_2 = 100 \times 2\\\)

\( \:\:\:\:\:\:\:\:\:\:\longrightarrow \sf \underline{V_2 = 200 \:cm^3 }\\\)

Answer: b. The reactant bonds are broken and the product bonds are formed. The reactants require more energy to break than the product bonds release.

ANSWER

EXPLANATION

Given that;

The number of moles of the gas is 7.7 moles

The pressure of the gas is 0.09 atm

The temperature of the gas is 56 degrees Celcius

Follow the steps below to find the volume of the gas in the container

Step 1; Convert the temperature to degrees Kelvin

Step 2; Apply the ideal gas equation

Therefore, the volume of the container is 2310.58 liters

To determine the answer, we need to calculate the standard free energy change of the reaction using the equation ΔG° = -234.55 kJ/mol.

Enthalpy is a thermodynamic property of a system that expresses the heat energy involved in a process, as well as the work that may be done at a constant pressure. It is represented by the symbol "H" and is usually measured in units of Joules or Calories.

Enthalpy change (ΔH) is often used to describe the difference between the enthalpy of the reactants and the products in a chemical reaction. It can be either positive endothermic or negative exothermic, depending on whether heat is absorbed or released during the reaction.

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Answer:

Mars

Explanation:

Mars is the planet with features that are really similar to the earth. As a matter of fact, Mars and the earth are referred to as "twin planets".

Mars and Earth are believed to have historically had even more similar attributes, however, that of mars was lost due to changes in the solar system.

The two planets are mostly similar because of their relatively similar size and proximity to the sun.

Answer: PbSO4

Explanation: Search on google

Answer:

PbSO4

Explanation:

Answer:

metallic bonds

Explanation:

atoms in a metallic solid loose their outer electrons and form a regular lattice of positive metallic ions.

The chemical bondings are present between the atoms due to the attractive forces. The bond shown in the diagram represents the metallic bonds. Thus, option A is correct.

A metallic bond is a chemical bonding present due to the electrostatic attractive forces present between the delocalized electrons and the ions of the metals.

The metal produces cations that bond with the electrons delocalized around them. This type of bonding accounts for the malleability and conductivity of the metallic species.

The delocalized electrons are shared by the positively charged metal ions. The cations are largely spread in space. It is seen in the elements of aluminum, magnesium, copper, sodium, zinc, calcium, etc.

Therefore, option A. the metallic bond is seen in the diagram.

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Answer:  C

Explanation:

Nuclear reactions involve a change in an atom's nucleus, usually producing a different element. Chemical reactions, on the other hand, involve only a rearrangement of electrons and do not involve changes in the nuclei.

Answer:

This reaction is an example of Hydrohalogenation reaction of alkene.

In this reaction the double bond of alkene acts as nucleophile.

This reaction follows Markovnikov's rule i.e. the bromide will add to more substituted carbon atom.

This is because the carbocation intermediate formed during the reaction is is more stable due to its secondary structure.

The final product is called 2-Bromopropane.

Answer:

Not sure sorry :(

Explanation:

Explanation:

the inner core is solid. the outer core is liquid

The concentration of the sucrose solution is:

C = n / V = n / (m / ρ) = (0.0073 mol) / (0.509 g / 1 mL / 1.00 g/cm³) = 0.144 M.

The first step is to calculate the amount of heat released by the combustion of sucrose using the balanced chemical equation:

C12H22O11 + 12O2 → 12CO2 + 11H2O

From the equation, we can see that 1 mole of sucrose produces 12 moles of CO2 and 11 moles of H2O. The molar mass of sucrose is 342.30 g/mol, so the number of moles in 2.5 g is:

n = 2.5 g / 342.30 g/mol = 0.0073 mol

Therefore, the combustion of 2.5 g of sucrose produces:

12 mol CO2 × 0.0073 mol = 0.0876 mol CO2

11 mol H2O × 0.0073 mol = 0.0803 mol H2O

The amount of heat released by the combustion of sucrose can be calculated using the standard enthalpy of combustion ΔH°comb = -5648 kJ/mol:

q = ΔH°comb × n = (-5648 kJ/mol) × 0.0073 mol = -41.23 kJ

This heat is absorbed by the water in the calorimeter, so we can use the equation:

q = mcΔT

where q is the heat absorbed by the water, m is the mass of the water, c is the specific heat of water, and ΔT is the temperature change.

Substituting the given values, we get:

-41.23 kJ = (2190.0 g)(4.184 J/g℃)(25.01 °C - 20.50 °C)

Solving for the mass of water, we get:

m = -41.23 kJ / [(2190.0 g)(4.184 J/g℃)(25.01 °C - 20.50 °C)] = 0.509 g

Therefore, the mass of water is 0.509 g, and the total mass of the solution is:

m = 2.5 g sucrose + 0.509 g water = 3.009 g.

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9. The number of mole of the argon contained in the tank is 2.39 moles

10. The volume (in liters) of H₂O produced from the reaction is 73.5 liters

The number of mole of the argon contained in the tank can be obtained as follow:

PV = nRT

Inputting the given parameters, we have:

9.4 × 6.25 = n × 0.0821 × 299

Divide both sides by (0.0821 × 299)

n = (9.4 × 6.25) / (0.0821 × 299)

n = 2.39 moles

Thus, the number of mole of the argon gas in the tank is 2.39 moles

The volume of H₂O produced can be obtained as shown below:

4NH₃(g) + 5O₂(g) -> 6H₂O(g) + 4NO(g)

From the balanced equation above,

4 liters of NH₃ reacted to produced 6 liters of H₂O

Therefore,

49 liters of NH₃ will react to produce = (49 × 6) / 4 = 73.5 liters of H₂O

Thus, the volume of H₂O produced is 73.5 liters

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Answer:

\(\blue{\boxed{\red{\sf CCl_4 \: will \: dissolve \: in \: gasoline}}}\)

Explanation:

The simple concept that would be applied is

'Like Dissolves Like.'

According to this, the polar solvent will dissolve the polar solutes and the non-polar solvent will dissolve the non-polar solutes.

classification of given compounds as polar or non-polar,

\(\begin{gathered}\boxed{\begin{array}{c|c} \bf Polar & \bf Non-polar \\ \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf NaCl & \sf CCl_4 \\ \\ \sf NaOH & \sf - \\ \\ \sf KCl & \sf - \end{array}} \\ \end{gathered}\)

Also, the given data says water is a polar solvent while gasoline is a non-polar solvent. From all the information we have, we can conclude that CCl4 is the only compound that will dissolve in gasoline.

\(\sf \small \pink{Thanks }\: \green{for} \: \blue{joining} \: \orange{brainly } \: \red{community}!\)

Answer:

\(\huge\boxed{\sf CNH_4}\)

Explanation:

Given compound us,

C₂N₂H₈

= 2 : 2 : 8

= 2 ÷ 2 : 2 ÷ 2 : 8 ÷ 2

= 1 : 1 : 4

So, we can write the formula as:

\(\rule[225]{225}{2}\)

Answer:

2.9 psi

Explanation:

Pressure (mmHg) = 150 mmHg

Pressure (psi) =?

The pressure in pound per square inch (psi) can be obtained as follow:

51.715 mmHg = 1 psi

Therefore,

150 mmHg = 150 mmHg × 1 psi / 51.715 mmHg

150 mmHg = 2.9 psi

Thus, pressure in pound per square inch (psi) is 2.9 psi.

The rate of reaction is

1.17*10^5 J/mol

By Arohenius equation, we have

\(.$$\log \left(k_2 k_1\right)=\frac{E_a}{2 \cdot 303 R}\left(\frac{T_2-T_1}{T_1 T_2}\right)$$Given, $k_1=4.85 \times 10^{-5} \mathrm{~L}$ mol.s$$T_1=195^{\circ} \mathrm{C}=(273+195) \mathrm{K}=468 \mathrm{~K}$$$$\begin{aligned}& k_2=8.80 \times 10^{-3} \frac{\mathrm{L}}{\text { mil.s}} \\& T_2=258^{\circ} \mathrm{C}=(273+258) \mathrm{k}=531 \mathrm{~K}\end{aligned}$$\)

\($$\begin{aligned}& \therefore \log \left(\frac{8.80 \times 10^{-3}}{4.85 \times 10^{-5}}\right)=\frac{E a}{2.303 R}\left(\frac{531.468}{488 \times 531}\right) \\& \Rightarrow \log (181.44)=\frac{E_a}{2.303 R}\left(\frac{63}{248,508}\right) \\& \Rightarrow E_a=\log (181.44) \times \frac{248508}{63} \times 2.303 \times 8.314 \\& =170,595.94 \mathrm{~J} / \mathrm{mal} \text {. } \\& =1.71 \times 10^5 \mathrm{~J} / \mathrm{mol} \text { (aru) } \\&\end{aligned}$$\)

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the limiting reagent is nitrogen gas.

steps:

write out balanced equation: 3H2 + N2 = 2NH3

convert to moles to find how much NH3 each yields

find molar mass of each

10 g H2 (1 mol/2.016g) (2NH3/3H2) = 3.31 mol NH3

26g N2 (1mol/28.02g)(2NH3/1N2)=1.86 mol NH3

since N2 yields less NH3, it is the limiting reagent.

There are approximately \(2.76 * 10^{24\) ammonia molecules in the given sample.

To calculate the number of ammonia molecules in the sample, we need to use Avogadro's number and the molar mass of ammonia.

The molar mass of ammonia \((NH_3)\) can be calculated by adding up the atomic masses of nitrogen (N) and hydrogen (H):

Molar mass of \(NH_3\) = (1 x atomic mass of N) + (3 x atomic mass of H)

              = (1 x 14.01 g/mol) + (3 x 1.01 g/mol)

              = 14.01 g/mol + 3.03 g/mol

              = 17.04 g/mol

Now, we can calculate the number of moles of ammonia in the sample using the formula:

Number of moles = Mass of the sample / Molar mass

Number of moles = 78.25 g / 17.04 g/mol

              ≈ 4.5865 mol (rounded to four decimal places)

Finally, we can use Avogadro's number, which represents the number of particles (atoms, molecules, etc.) in one mole of a substance. Avogadro's number is approximately \(6.022 * 10^{23\) particles/mol.

Number of ammonia molecules = Number of moles x Avogadro's number

Number of ammonia molecules ≈ 4.5865 mol x (\(6.022 * 10^{23\) molecules/mol)

                           ≈ \(2.76 * 10^{24\) molecules (rounded to two significant figures)

Therefore, the provided sample contains roughly \(2.76 * 10^{24\) ammonia molecules.

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The number of ammonia molecules in the sample is approximately 2.764 x \(10^{24}\) molecules.

To calculate the number of ammonia molecules in a given sample, we need to use Avogadro's number and the molar mass of ammonia.

The molar mass of ammonia (NH3) is calculated as follows:

Molar mass of N = 14.01 g/mol

Molar mass of H = 1.01 g/mol

Total molar mass of NH3 = 14.01 g/mol + (3 * 1.01 g/mol) = 17.03 g/mol

Now, we can calculate the number of moles of ammonia in the sample:

Number of moles = Mass of sample / Molar mass of NH3

Number of moles = 78.25 g / 17.03 g/mol = 4.594 moles

Next, we use Avogadro's number, which states that there are 6.022 x \(10^{23}\) molecules in one mole of a substance.

Number of molecules = Number of moles * Avogadro's number

Number of molecules = 4.594 moles * 6.022 x \(10^{23}\) molecules/mol = 2.764 x \(10^{24}\) molecules

Therefore, there are approximately 2.764 x \(10^{24}\) ammonia molecules in the given sample of 78.25 g.

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Answer:

spinning

Explanation:

Answer:

To prepare 250 ml of 0.15 M KNO3 solution, you will need to follow these steps:

Calculate the amount of KNO3 needed:

Molarity (M) = moles of solute/liters of solution

Rearranging the formula, moles of solute = M x liters of solution

Moles of KNO3 needed = 0.15 M x 0.25 L = 0.0375 moles

Calculate the mass of KNO3 needed:

Mass = moles x molar mass

The molar mass of KNO3 is 101.1 g/mol

Mass of KNO3 needed = 0.0375 moles x 101.1 g/mol = 3.79 g

Dissolve the calculated amount of KNO3 in distilled water:

Weigh out 3.79 g of KNO3 using a digital balance

Add the KNO3 to a clean and dry 250 ml volumetric flask

Add distilled water to the flask until the volume reaches the 250 ml mark

Cap the flask and shake it well to ensure the KNO3 is completely dissolved

Verify the concentration of the solution:

Use a calibrated pH meter or a spectrophotometer to measure the concentration of the solution

Adjust the volume of distilled water or the mass of KNO3 as needed to achieve the desired concentration

It is important to note that KNO3 is a salt that can be hazardous if ingested or inhaled in large quantities. Therefore, it is recommended to handle it with care and wear appropriate personal protective equipment.

Explanation:

Explanation:

try this option (all the details are in the attachment).

H will have the longest wavelength emission line for the transition between the n initial = 2 and n final = 1 levels.

A movement (or leap) of an electron from one energy level to another within an atom or artificial atom is referred to as an atomic electron transition. It seems discontinuous because the electron "jumps" from one quantized energy level to another in a matter of nanoseconds or less.

Electronic transitions occur in atoms and molecules as a result of electromagnetic radiation absorption or emission (typically UV or visible). Planck's equation, E = h, relates the energy change associated with a transition to the frequency of an electromagnetic wave. Transitions between these permitted orbits occur in photon absorption or emission. A photon is released when an electron transitions from a higher-energy orbit to a more stable orbit.

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If 2.54 g of PbS is burned with 1.88 g of O2, approximately 2.20 grams of Pb will be produced.

The balanced equation for the reaction of lead sulfide (PbS) with oxygen (O2) to produce lead (Pb) and sulfur dioxide (SO2) is as follows:

2PbS + 3O2 -> 2Pb + 2SO2

From the balanced equation, we can see that the stoichiometric ratio between PbS and Pb is 2:2 or 1:1. This means that for every 1 mole of PbS, 1 mole of Pb is produced.

To calculate the number of moles of PbS, we need to divide the given mass (2.54 g) by its molar mass:

Molar mass of PbS = 207.2 g/mol (Pb) + 32.07 g/mol (S) = 239.27 g/mol

Moles of PbS = 2.54 g / 239.27 g/mol = 0.0106 mol

Since the stoichiometric ratio between PbS and Pb is 1:1, the number of moles of Pb produced is also 0.0106 mol.

To calculate the mass of Pb, we multiply the number of moles by its molar mass:

Molar mass of Pb = 207.2 g/mol

Mass of Pb = 0.0106 mol x 207.2 g/mol = 2.20 g

This calculation is based on the stoichiometric ratio between PbS and Pb, where 1 mole of PbS produces 1 mole of Pb. By converting the given mass of PbS to moles and then multiplying by the molar mass of Pb, we can determine the mass of Pb produced.

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Answer: Option 2, The ability to do work.

Explanation: Edge

Energy can be defined as:

B. the ability to do work, It can of many forms.

Energy is the capacity of an item to take care of business. It might exist in potential, motor, warm, electrical, substance, atomic, or other different structures. As per the work-energy hypothesis, the work done is put away in the energy of the body.

Thus, option B is correct.

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The equation C2H4(g) + H2(g) + C2H6(g) → Caco3(s) + Cao(s) + CO2(g) shows an increase in entropy due to the formation of a gas as a product. Option A

In this equation, the reactants on the left-hand side consist of gases (C2H4 and H2), while the products on the right-hand side include a solid (Caco3) and a gas (CO2).

When a reaction involves a change from gaseous to solid or liquid states, there is typically a decrease in entropy because the particles become more ordered and constrained in the solid or liquid phase.

Conversely, when a reaction involves the formation of gases, there is generally an increase in entropy because gases have higher degrees of molecular motion and greater freedom of movement compared to solids or liquids.

In the given equation, the reactants include three gaseous compounds (C2H4, H2, and C2H6), and one of the products is a gas (CO2). Therefore, the overall entropy of the system increases during this reaction.

The equation Fe(s) + S(s) → FeS(s) does not show an increase in entropy. Both the reactants (Fe and S) and the product (FeS) are solids. Since solids have lower entropy compared to gases or liquids, the entropy of the system does not increase in this reaction. Option A

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(a) The hydrogen ion concentration in the solution is [H+] = 1.14x10^-3 M. (b) 0.57%. (c) The ratio of the concentration of propanoate ion to that of propanoic acid in the buffer solution is 2.68.

(a) The balanced equation for the ionization of propanoic acid is:

C2H5COOH + H2O ⇌ C2H5COO- + H3O+

The equilibrium expression for this reaction is:

Ka = [C2H5COO-][H3O+] / [C2H5COOH]

At equilibrium, the concentration of propanoic acid that has ionized to form propanoate ion and hydronium ion is equal to the concentration of propanoic acid that has not ionized, so we can assume that [C2H5COO-] ≈ [H3O+]. Let x be the concentration of hydronium ion in the solution. Then the equilibrium expression becomes:

Ka = x^2 / (0.20 - x)

Solving for x, we get:

x = sqrt(Ka * (0.20 - x)) = sqrt(1.3x10^-5 * 0.20) = 1.14x10^-3 M

Therefore, the hydrogen ion concentration in the solution is [H+] = 1.14x10^-3 M.

(b) The percentage of propanoic acid molecules that are ionized in the solution is given by:

% ionization = [H3O+] / [C2H5COOH] x 100%

% ionization = (1.14x10^-3 / 0.20) x 100% = 0.57%

(c) The pH of a buffer solution can be calculated using the Henderson-Hasselbalch equation:

pH = pKa + log([C2H5COO-] / [C2H5COOH])

At pH 5.20, the hydronium ion concentration is 10^-5.20

= 6.31x10^-6 M.

Using the equilibrium expression for propanoic acid and the fact that [C2H5COO-] + [C2H5COOH] = total buffer concentration,

we can solve for the ratio of the concentrations of propanoate ion to propanoic acid:

Ka = [C2H5COO-][H3O+] / [C2H5COOH]

[C2H5COO-] = Ka[C2H5COOH] / [H3O+]

[C2H5COO-] = (1.3x10^-5)([C2H5COOH]) / (6.31x10^-6)

[C2H5COO-] / [C2H5COOH]

= 2.68

Therefore, the ratio of the concentration of propanoate ion to that of propanoic acid in the buffer solution is 2.68.

(d) When solid NaOH is added to the buffer solution, it reacts with the propanoic acid to form propanoate ion and water:

C2H5COOH + NaOH → C2H5COO- + H2O + Na+

The number of moles of propanoic acid that react with NaOH is equal to the number of moles of NaOH that were added. The new concentration of propanoic acid is:

0.35 M - (0.0040 mol / 0.100 L) = 0.346 M

The new concentration of propanoate ion is:

0.50 M + (0.0040 mol / 0.100 L) = 0.54 M

The new concentration of hydronium ion can be calculated using the equilibrium expression.

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Answer:

the answer should be speed)

Explanation:

hope it helps like the pic by the way

Answer:

B

Explanation:

The scientist had a wrong hypothesis?

Answer:

it would be C.

Explanation:

becuase the scientist would know what to to next time for his next experiment. even if it went wrong, he can try to get it right again.